Answer:
The magnitude of force on the charge at the midpoint is 0.1463N.
Explanation:
Given;
two point charges, q₁ and q₂ = 9μC and 4μC
a positive charge placed at the midpoint between the two charges, q = 5μC
The repulsive force between 9μC and 5μC is calculated by Coulomb's force;
\(f_1 = \frac{kq_1q}{r_1^2}\)
The repulsive force between 4μC and 5μC is calculated by Coulomb's force;
\(f_2 = \frac{kq_2q}{r_2^2}\)
The resultant force on the charge is calculated as;
\(F= f_1 +f_2 = \frac{kq_1q}{r_1^2} = \frac{kq_2q}{r_2^2} \\\\F = \frac{(9\times 10^9)(9\times 10^{-6})(5\times 10^{-6})}{(2)^2} + \frac{(9\times 10^9)(4\times 10^{-6})(5\times 10^{-6})}{(2)^2} \\\\F = 0.1013 \ N \ + \ 0.045 \ N\\\\F = 0.1463 \ N\)
Therefore, the magnitude of force on the charge at the midpoint is 0.1463N.
Name and draw the devices that can convert the analog signal to digital
Answer:
Analog to digital converters
Explanation:
An analog-to-digital converter (ADC) is a device that converts analog signals such as sound into digital signals. Analog information is transmitted by modulating the signal and then amplifying the signal's strength. The conversion from analog to digital involves quantization of the input thereby reducing error or noise. The ADC produces the output data as a series of digital values (0's and 1's) with fixed precision.
Answer:
Analog to digital converter.
Explanation:
Three important type that covert analog signal to digital
1 flash ADC
2 Digital Ramp ADC
3 successive Approximation
Armand is monitoring a large sealed tank by way of a sensor that records the liquid level over time on a graph. He looks at the graph and claims that the sensor indicates there are waves in the liquid in the tank.
In the space provided, answer each of the following.
Part A: Explain how Armand knows that there is a wave in the tank.
Part B: Find the amplitude, in centimeters (cm), and frequency, in number of waves every second/cycle per second (Hz), of the wave.
Answer:
A.) armand probably looked at the graph that the liquid sensor sends information too
Explanation:
the mass of the velociraptor and cage together is 175 kg. What is the gravitational potential energy added when when the velociraptor and cage is lifted from the ground to a height of 9 m?
The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.
What is Potential Energy?
Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.
The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:
GPE = mgh
Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.
Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:
GPE = mgh
GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)
GPE = 15,998.95 J (joules)
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Two students are at the beach studying nature and see a pod of dolphins swimming by. student 1 decides the best way to study them is by diving under the water while student 2 observes from above the water. the two students hear sounds from dolphins that are in the water and jumping above the surface the same distance from the students. based on the information below, which dolphin would the studen hear first?
v=f * A
jumping dolphin frequency: 1200 Hz
wavelength: 0.285 m
swimming dolphin
frequency: 1800 Hz
wavelength: 0.833 m
show the work
which sound reaches the shore first? Use the numbers you have calculated to support your answer.
Answer:
abdulaziz Sharif mamad
e
First, draw a free body diagram for an unknown mass (M) above.
Put your answer to one decimal place, no units.
Example
30.0
String one is at an angle of 33 degrees relative to the horizontal. String two is horizontal and
has a tension of 578 N. Solve for the mass of the object.
59.03 kg is the mass of the object.
T=mgsinθ
m=T/gsinθ
m=578 N/9.8×sin 33
m=578/9.79
m=59.03 kg
In physics, mass is used to express inertia, a property common to all matter. In essence, it is the resistance of a mass of matter to changing its course or speed in response to the application of a force. The more mass a body has, the less of a change an applied force makes. Using Planck's constant, the kilogram, the ISU's unit of mass, is equivalent to 6.62607015 1034 joule seconds (SI). One kilogram is multiplied by one square meter per second to yield one joule. Since the second and the meter have already been defined in terms of other physical constants, the kilogram is determined by precise measurements of Planck's constant.
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pleaseeee help mehhhh
what is the force acting in one direction called?
A net force can act in the same direction as that of the current velocity of the object, in which case it will not change the direction in which the object moves.
Gender inequality in Machenical Engeenering
Gender inequality in mechanical engineering can manifest through biased hiring practices, limited opportunities for women to advance to leadership roles, and a lack of representation in the industry.
Despite efforts to promote gender equality, women are still underrepresented in the field of mechanical engineering. This can be due to a variety of factors, including biased hiring practices, limited opportunities for career advancement, and a lack of representation in the industry.
To address these issues, it is important for companies and organizations to promote diversity and inclusion initiatives, such as actively recruiting women and people of diverse backgrounds, providing mentorship and networking opportunities, and advocating for policies that support work-life balance and equal pay. By creating a more inclusive environment, the field of mechanical engineering can attract and retain more talented individuals and foster innovation and growth.
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--The complete question is, How does gender inequality manifest in the field of mechanical engineering, and what are some potential solutions to address this issue?--
What is formed when 2 or more elements combine chemically
Answer:
compound
Explanation:
a substance made from two or more different elements that have been chemically joined. Examples of compounds include water (H2O), which is made from the elements hydrogen and oxygen, and table salt (NaCl), which is made from the elements sodium and chloride.
A projectile is fired from ground level with an initial speed of 650 m/sec and an angle of elevation of 30 degrees. Use that the acceleration due to gravity is 9.8 m/sec2m/sec2. (a) The range of the projectile is meters. (b) The maximum height of the projectile is meters. (c) The speed with which the projectile hits the ground is 650 m/sec.
Answer:
(a) The range of the projectile is 37,336.3 m
(b) The maximum height of the projectile is 5,389.03 m
Explanation:
Given;
initial velocity of the projectile, u = 650 m/s
angle of projection, θ = 30⁰
(a) The range of the projectile is calculated as;
\(R = \frac{u^2sin 2\theta}{g} \\\\R = \frac{(650^2)Sin (2\times 30^0)}{9.8} \\\\R = 37,336.3 \ m\)
(b) The maximum height of the projectile is calculated as;
\(H = \frac{u^2sin^2\theta}{2g} \\\\H = \frac{(650^2)(Sin \ 30^0)^2}{2\times 9.8} \\\\H = \frac{(650^2)(0.5)^2}{19.6} \\\\H = 5,389.03 \ m\)
In modified PE football, the quarterback can only run with the ball if
A The quarterback has no open receivers
B Time runs out
C Another player on the offense touches the ball before the play starts
D it is 4th down
Answer:
its c i just did the test
Explanation:
a bus is about to leave in exactly 5 seconds. you are 20 meters away. how fast do you need to run to get to the bus? give your answer in m/s. round 2 significant figures
A bus is about to leave in exactly 5 seconds. You are 20 meters away. With a speed of 4 m/sec you will be able to catch the bus on time.
What do you understand by the term Distance, Speed and Time?By dividing the distance traveled by the time required to complete that distance, speed is calculated. For a specific distance, it provides the travel time / distance.
Speed and distance are tightly related, whereas time and distance have an inverse relationship. Speed times the passing of time equals distance.
Distance divided by speed is how time is calculated; as speed rises, time slows down, and vice versa.
What is the calculation for the above problem?Given
Time = 5 secs
Distance = 20 m
On putting the values in the given formula we get,
Speed = Distance / Time
Speed = 20 m / 5 secs
Speed = 4 m/secs
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Which is a chemical property of iron? A. It forms iron oxide (rust) when exposed to moisture and air. B. It is a gray–black metal that is hard to the touch. C. It has a melting point of 2795°F (1536°C). D. It is a good conductor of heat.
Answer:
a
Explanation:
it corrodes after repeated exposure to excess moisture and dry air the rust itself can be turned back into iron after melting it and removing the waste
M ộ t canô xuôi dòng t ừ b ế n A đế n b ế n B v ớ i t ố c độ v 1 = 30km/h; r ồ i ng ượ c dòng t ừ B v ề A v ớ i t ố c độ v 2 =20km/h. Tính t ố c độ trung bình trên l ộ trình đ i – v ề c ủ a canô
Answer:
fslkgndfjlxbndxvb, xn
Explanation:
Select the correct answer from each drop-down menu.
What forms of energy are involved when snow on a mountain breaks loose, resulting in an avalanche?
During an avalanche, the
energy of the snow on the mountain is converted into
energy as the snow cascades down.
Answer:
Gravitational potential energy is converted into kinetic energy
Explanation:
During an avalanche, the gravitational potential
energy of the snow on the mountain is converted into
kinetic energy as the snow cascades down.
The potential energy stored by the snow collected high in the mountain under the gravitational field created by our Earth, breaks loose and as it comes down acquiring velocity, it is converted into kinetic energy due to its accelerated motion
How many significant figures are in the measurement 0.020 km?
a.
1
b.
2
c.
3
d.
4
Please select the best answer from the choices provided
A
B
C
D
Answer:3
Explanation:
Answer:
2
Explanation:
0.020 has two significant figures.
The 2 is significant because all non-zero numbers are signficant.
The second 0 is significant because all zeros at the end of a decimal are significant.
The other zeros are not significant, because they are just place holders.
what exercises most beneficial for your overall health
Answer:
Endurance, or aerobic
Strength, or resistance training
Balance
Flexibility
Explanation:
Answer:
Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).
Help please (View attachment below)
Answer:
To calculate the amount of heat absorbed by the ice, we need to use the equation:
Q = m * ΔHf
where Q is the heat absorbed by the ice, m is the mass of the ice, and ΔHf is the heat of fusion of the ice, which is 334 J/g.
First, we need to calculate the amount of heat lost by the water:
Q = m * c * ΔT
where Q is the heat lost by the water, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the temperature change of the water.
We know that the mass of the water is 100 g, c is 4.18 J/g-°C, and ΔT is 5°C, so:
Q = 100 g * 4.18 J/g-°C * 5°C
Q = 2090 J
This means that the water lost 2090 J of heat, which was absorbed by the ice. Now we can calculate the amount of heat absorbed by the ice:
Q = m * ΔHf
We know that the mass of the ice is 10 g and the heat of fusion of the ice is 334 J/g, so:
Q = 10 g * 334 J/g
Q = 3340 J
Therefore, the amount of heat absorbed by the ice is 3340 J, which is equivalent to 3.34 kJ (kilojoules). The closest answer choice is 2.09 kJ, but that is not the correct answer.
A uniform bar of length 24 m and...
The magnitude of horizontal force, is 33.27 N.
Length of the uniform bar, L = 24 m
Mass of the uniform bar, m = 5 kg
Angle between the cord and the bar, θ₁ = 90°
Angle between the cord and the wall, θ₂ = 50°
For the horizontal equilibrium,
Hₓ = T sinθ₂
Hₓ = T x sin 50
Hₓ = 0.766 T
For the vertical equilibrium,
Hy + T cosθ₂ = mg
Hy + T cos 50 = 5 x 9.8
Hy + 0.642 T = 49 N
For rotational equilibrium,
mg (L/2) = T x L
So,
T = mg/2 = 5 x 9.8/2
T = 24.5 N
Therefore, the magnitude of horizontal force,
Hy = 49 - (0.642 x 24.5)
Hy = 49 - 15.73
Hy = 33.27 N
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An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?
Answer: the radius of the circular path is approximately 1637.58 meters.
Explanation:
The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:
F_c = m * g * tan(banking angle)
Where:
F_c is the centripetal force
m is the mass of the airplane
g is the acceleration due to gravity
tan(banking angle) is the tangent of the banking angle
Now, the centripetal force is also given by the formula:
F_c = (m * v^2) / r
Where:
v is the speed of the airplane
r is the radius of the circular path
Equating the two expressions for F_c, we get:
(m * g * tan(banking angle)) = (m * v^2) / r
Canceling out the mass (m) on both sides of the equation, we have:
g * tan(banking angle) = v^2 / r
Solving for r, we get:
r = (v^2) / (g * tan(banking angle))
Substituting the given values:
v = 400 km/h = 400,000 m/h
g = 9.8 m/s^2
banking angle = 20°
Converting the speed to m/s:
v = 400,000 m/h * (1/3600) h/s = 111.11 m/s
Converting the banking angle to radians:
banking angle = 20° * (π/180) rad/° = 0.3491 rad
Now, substituting the values into the formula:
r = (111.11^2) / (9.8 * tan(0.3491))
r ≈ 1637.58 meters
Therefore, the radius of the circular path is approximately 1637.58 meters.
PLEASE HELP!
I don't even know what Science is I'm so dumb lol XD
Answer:
C
Explanation:
Sled A has more potential energy because it's mass is 100 kg, and it is higher up than Sled B. The more high up the sled is and the lighter it is, the faster it gets, it creates more and more potential energy.
Hope this helps!
An installation consists of a 30-kVA, 3-phase transformer, a 480-volt primary, and a 240-volt secondary. Calculate the largest standard size circuit breaker permitted for primary-only protection to be used without applying Note 1 of Table 450.3(B).
Answer: 45 A
Explanation:
Primary only protection 3-phase
I = 3 phase kVA / ( 1.723 * V)
I = 30000 / ( 1.732 * 480 ) = 36.085 A
Table 450.3(B)
Currents of 9A or more column
primary only protection = 125%
Max OCPD pri = 125% of I = 1.25 * 36.085 = 45.11 A
Table 450.3(B) Note 1 does not apply, use next smaller Table 240.6(A)
Next smaller = 45 A
A charged particle ( 7.58 x 10⁻⁶ kg and -6.9 x 10⁻⁹ C ) accelerates in a uniform electric field: (see 2nd image)
Assuming that the only force acting on the particle is due to the electric field, calculate the acceleration of the particle in m/s², taking the direction of the field as the positive direction (see 3rd image). Remember that F=ma.
Round to the nearest hundreth.
Will give brainliest if correct. Please show method/explaination down below.
Answer:
-9.20 m/s²
Explanation:
We can calculate the acceleration of the particle using the equation F = ma. We know that the force acting on the particle is given by the equation F = qE, where q is the charge of the particle and E is the electric field. So we can write:
ma = qE
We know the mass of the particle, the charge of the particle, and the electric field. We can substitute these values into the equation to find the acceleration:
a = qE/m = (-6.9 x 10⁻⁹ C)(3.5 x 10⁵ N/C) / (7.58 x 10⁻⁶ kg) = -9.20 m/s²
So the acceleration of the particle is -9.20 m/s². It is acting in the opposite direction of the electric field.
Tried My Best Hope This Helps :)
A football player kicks a ball with the force of 50N. Find the impulse on the ball if his foot stays in contact with the football for 0.01s
Answer:
Impulse = 0.5Ns
Explanation:
F = 50N
t = 0.01s
Impulse = ?
Impulse = Force * t,
Impulse = 50N * 0.01s = 0.5Ns
The small spherical planet called "Glob" has a mass of 7.88×10^18 kg and a radius of 6.32×10^4 m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 1.44×10^3 m, above the surface of the planet, before it falls back down.
1. What was the initial speed of the rock as it left the astronaut's hand? (Glob has no atmosphere, so no energy is lost to air friction. G = 6.67×10^-11 Nm2/kg2.)
2. A 36.0 kg satellite is in a circular orbit with a radius of 1.45×10^5 m around the planet Glob. Calculate the speed of the satellite.
Answer: The small spherical planet called "Glob" has a mass of 7.88×1018 kg and a radius of 6.32×104 m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 1.44×103 m, above the surface of the planet, before it falls back down.
1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.
2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.
Explanation: To find the answer, we need to know about the different equations of planetary motion.
How to find the initial speed of the rock as it left the astronaut's hand?We have the expression for the initial velocity as,\(v=\sqrt{2gh}\)
Thus, to find v, we have to find the acceleration due to gravity of glob. For this, we have,\(g_g=\frac{GM}{r^2} =\frac{6.67*10^{-11}*7.88*10^{18}}{(6.32*10^4)^2}= 0.132\)
Now, the velocity will become,\(v=\sqrt{2*0.132*1.44*10^3} =19.46 m/s\)
How to find the speed of the satellite?As we know that, by equating both centripetal force and the gravitational force, we get the equation of speed of a satellite as,\(v=\sqrt{\frac{GM}{r} } =\sqrt{\frac{6.67*10^{-11}*7.88*10^{18}}{1.45*10^5} } =3.624km/s\)
Thus, we can conclude that,
1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.
2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.
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The tiny planet known as "Glob" has a radius of 6.32× 10^4 meters and a mass of 7.88× 10^18 kg. On Glob's surface, an astronaut launches a rock straight upward. Before falling back down, the rock rises to a maximum height of 1.44×10^3 m above the planet's surface.
1) The rock was moving at 19.46 m/s when it first left the astronaut's palm.
2) A 36.0 kg spacecraft is orbiting the planet Glob in a sphere with a radius of 1.45 105 meters. The satellite is moving at 3.624 km/s at that point.
Understanding the planetary motion equations is necessary in order to determine the solution.
How to determine the rock's original speed when it left the astronaut's hand?The starting velocity's expression is as follows:\(V=\sqrt{2gh}\)
So, in order to determine v, we must determine the acceleration of glob caused by gravity. We already have,\(a=\frac{GM}{r^2} =\frac{6.67*10^{-11}*7.88*10^{18}}{(6.32*10^4)^2} \\a=0.132m/s^2\)
The velocity will now change to,\(V=\sqrt{2*0.132*1.44*10^3} =19.46m/s\)
How can I determine the satellite's speed?As we are aware, the centripetal force and gravitational force are equivalent, and thus leads to the following satellite speed equation:\(v=\sqrt{\frac{GM}{r} } =3,624km/s\\where,\\M=7.88*10^{18}kg\)
Consequently, we can say that
1) The rock was moving at 19.46 m/s when it first left the astronaut's palm.
2) A 36.0 kg spacecraft is orbiting the planet Glob in a sphere with a radius of 1.45 105 meters. The satellite is moving at 3.624 km/s at that point.
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how often the earth magnetism change
Write the differences between rest and motion
Answer:
Depends on position
Explanation:
Rest:
A body is said to be at rest, if it does not change its position with respect to its surroundings.
Motion:
A body is said to be in motion, if it changes its position with respect to its surroundings.
The state of rest and motion is relative
Two bumper car in an amusement park ride collide elastically as on approaches the other directly from the rear. Car A has a mass of 450kg and car B 550kg, owing to differences in passenger mass. If car A approaches at 4.5m/s and car B is moving at 3.7m/s, calculate (a) their velocities after collision, and (b) the change in momentum of each.
Answer:
VA = 3.62 m/s
VB = 4.42 m /s
Change of momentum of A = -396 kgm/s
Change of momentum of B = 396 kgm/s
Explanation:
Asuming A and B move to the right after the collision
pbefore = pafter
4.5*450 + 3.7*550 = 450VA + 550VB
In a elastis collition, the coefficient of restitution is 1
1 = (VB - VA)/(4.5 - 3.7)
VB - VA = 0.8
VB = 4.42 m/s
VA = 3.62
Change of momentum of A = 450*(3.62-4.5) = -396 kgm/s
Change of momentum of B = 550*(4.42-3.7) = 396 kgm/s
A 9.00 kg bomb mass is sitting stationary. The bomb explodes and M1 (3kg) moving to the left with a velocity of
140 ms (v₁). The remaining portion flys to the right. Determine the v2 (velocity) it flys off with
A 9 kg explosive detonates into two fragments, each weighing 3 kg and 6 kg. The kinetic energy of mass 6 kg is 1.92 J, and the velocity of mass 3 kg is 1.6 m/s.
What is meant by velocity?The rate at which an object's position changes as perceived from a particular point of view and as measured by a certain unit of time is determined by its velocity, which can be expressed as, for instance, 60 km/h northbound. Quickness of motion or activity is known as velocity. Speed is a shorter term and a synonym for celerity. The term "velocity" in physics especially refers to the measurement of an object's rate and direction of positional change.The vector quantity velocity (v), denoted by the equation v = Δs/Δt, quantifies displacement (or change in position, s), over change in time (t).Therefore,
The total momentum of the bomb is unchanged before and after the explosion thanks to the conservation of linear momentum.
0 = 3 × 1.6 + 6v
v = 0.8 m/s
Kinetic energy of mass 6 kg is:
1/2 mv² = 1/2 × 6 × 0.8²
= 1.92 J
Hence, the correct option is c) 1.92J
The complete question is:
A bomb of mass 9kg explodes into 2 pieces of mass 3kg and 6kg. The velocity of mass 3kg is 1.6m/s, the kinetic energy of mass 6kg is :
A) 3.84J
B) 9.6J
C) 1.92J
D) 2.92J
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what is 5.02 Properties of Light Lab Report
Answer:
I Don't know
Explanation:
Because I'm 5 grade student