Two people push a 2,000-kg car to get it started. An acceleration of at least 5.0 m/s? is required to start
the car. Assuming both people apply the same magnitude force, how much force will each need to
apply if friction between the car and the road is 300 N? (5150N)
Answers
This question deals with the concepts of NEWTON'S SECOND LAW OF MOTION and frictional force.
The magnitude of force required by each person will be "5150 N".
Applying Newton's Second law formula to get the total force required to produce given acceleration.
F = ma
where,
F = required force = ?
m = mass of the car = 2000 kg
a = acceleration = 5 m/s²
Therefore,
F = (2000 kg)(5 m/s²)
F = 10000 N
Now, the friction force will be added to this required force. Because to get the car starting to move, the friction force first needs to be overcome.
F = 10000 N + frictional force = 10000 N + 300 N
F = 10300 N
Now, this is the force that both people need to apply. In order to find the force applied by the single individual, we can simply divide this force into two.
F = \(\frac{10300\ N}{2}\)
F = 5150 N
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The attached picture explains the concept of Newton's Second Law.
Related Questions
Explain how to identify a starting position on a line.
Answers
Answer:
We can easily find out the beginning point of the line by using dot representation.
When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system.
The vector is a straight line that has a certain end which is fixed to its body.
The other end is linked with a moving point that tells an accurate position of that specific point.
Answer:
Pick a reference point on the line to be the zero position. Determine the direction and measure the distance from zero in standard units.
Explanation:
6th grade science I mark as brainliest.
Answers
Answer:
2m 13\(\frac{1}{3}\)s
Explanation:
1.5m = 1s
200m = \(\frac{200}{1.5}\) × 1s
= 133\(\frac{1}{3}\)s
= 2m 13\(\frac{1}{3}\)s
a tourist takes his 24.5 w, 120 v ac razor to europe, finds a special adapter, and plugs it into 210 v ac. assuming constant resistance, what power does the razor consume as it is ruined?
Answers
The power consumed by the razor as it is ruined is 56.4 watts.
We can use the formula
P = V² / R
to calculate the power consumed by the razor.
Given that the razor operates at 120 V AC and has a resistance that remains constant, we can find the value of resistance by using the formula P = V² / R, where P is the power consumed, V is the voltage and R is the resistance. Thus, R = V² / P.
If the razor consumes 24.5 W of power at 120 V AC, then its resistance can be calculated as R = 120² / 24.5 = 587.76 ohms.
When the razor is plugged into 210 V AC, the voltage is increased, but the resistance remains the same. Therefore, using the same formula, we can calculate the power consumed by the razor as P = 210² / 587.76 = 75.24 W.
However, this power consumption is too high for the razor to handle, and it gets ruined. Therefore, we need to calculate the power consumed at which the razor gets ruined.
Typically, the maximum power rating for a 24.5 W razor is around 30 W. Therefore, assuming that the razor can handle a maximum power consumption of 30 W, we can use the formula P = V² / R to find the voltage at which the razor will consume 30 W of power.
Thus, 30 = V^2 / 587.76, which gives us V = 95.36 V. This means that when the voltage exceeds 95.36 V, the razor will consume more than 30 W of power and get ruined.
Therefore, when the tourist plugs his 24.5 W, 120 V AC razor into 210 V AC in Europe, the razor will consume 75.24 W of power, which is more than its maximum power rating. As a result, it will get ruined.
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Two packing crates of masses m1 = 10.0 kg and m2 = 5.00 kg are connected by a light string that passes over a frictionless pulley.The 5.00 kg crate lies on a smooth incline of angle 43.0°. Find the acceleration of the 5.00 kg crate and the tension in the string
Answers
The acceleration of the 5.00 kg crate is 4.22 m/s² and the tension in the string is 46.9 N.
To find the acceleration of the 5.00 kg crate and the tension in the string, we need to apply Newton's second law and consider the forces acting on the system.
The gravitational force acting on the 5.00 kg crate can be resolved into two components: one perpendicular to the incline (mg*cos(43.0°)) and one parallel to the incline (mg*sin(43.0°)).
The tension in the string is in the same direction as the force parallel to the incline.
Since the system is connected by a light string, the tension in the string is the same on both sides. Therefore, the tension in the string can be considered as the force accelerating the 5.00 kg crate.
Using Newton's second law, we can set up equations for the acceleration of the system and the tension in the string. Considering the net force along the incline, we have: m2*g*sin(43.0°) - T = m2*a.
Considering the net force perpendicular to the incline, we have: m2*g*cos(43.0°) = m2*g.
By solving these equations simultaneously, we can find the values of acceleration (a) and tension (T). Plugging in the given values, we find that the acceleration of the 5.00 kg crate is 4.22 m/s² and the tension in the string is 46.9 N.
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The density of oil is 0.8 g/cm^3. What is the mass of 36 cm^3 of oil? + (1 Point) O 0.29 N O 28.09 28.8 g O 36.89
Answers
Answer:
density = mass/volume
density=0.8
volume=36
mass=?
0.8=mass/36
mass = 36x0.8=28.8g
Question 1 of 10
2 Points
A piece of ice absorbs heat and melts. Which statement best describes the
changes in the ice as it melts?
A. The kinetic energy of the particles increases as the temperature
increases.
B. The potential energy of the particles increases as intermolecular
forces are overcome.
C. The potential energy of the particles increases as the temperature
increases.
D. The kinetic energy of the particles increases as intermolecular
forces are overcome.
Answers
option A is correct✔✔☑
An ideal gas at temperature To is slowly compressed at constant pressure of 2 atm from a volume of 10 liters to a volume of 2 liters. Then the volume of the gas is held constant while heat is added, raising the gas temperature back to To. Calculate the work done ON the gas. 1 atm = 1.0x 105 Pascals and 1 liter = 0.001 m³.
1. -800 J
2. -400 J
3. +800 J
4. +400 J
5. +1600 J
6. -1600 J
Calculate the heat flow INTO the gas
1. +1600 J
2. -400 J
3. -800 J
4. +400 J
5. +800 J
6. -1600 J
Answers
Work done on the gas = -1600 J, and Heat flow into the gas = -1600 J . The correct option for both questions is (option 6).
To solve this problem, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:
ΔU = Q - W
where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system. Since the volume of the gas is held constant during the second part of the process, no work is done on or by the gas, so W = 0.
For the first part of the process, the pressure is constant, so we can use the equation:
W = PΔV
where P is the pressure, and ΔV is the change in volume. We can convert the volumes to cubic meters, and the pressure to Pascals:
P = 2 atm = 2 x 1.0 x 10^5 Pa
V1 = 10 L = 0.01 m³
V2 = 2 L = 0.002 m³
ΔV = V2 - V1 = -0.008 m³ (since the gas is being compressed)
W = PΔV = (2 x 1.0 x 10^5 Pa) x (-0.008 m³) = -1600 J
So, the work done on the gas during the compression is -1600 J.
To find the heat flow into the gas during the second part of the process, we can use the equation:
ΔU = Q - W
Since the internal energy of an ideal gas depends only on its temperature, and the temperature is the same at the beginning and end of the process, ΔU = 0. Therefore:
0 = Q - W
Q = W = -1600 J
So, the heat flow into the gas during the second part of the process is -1600 J.
Therefore, the answers to the questions are Work done on the gas = -1600 J (option 6), and Heat flow into the gas = -1600 J (option 6).
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1. A race car accelerates uniformly from 19.5 m/s to 50.1 m/s in
2.47 seconds. Determine the acceleration of the car.
The acceleration of the car is 79.8.
Answers
Answer:
12.39m/s²
Explanation:
use the formula a=v-u
t
Describe two physical environmental factors in your environment at the moment
Answers
Answer:
The factors in the physical environment that are important to health include harmful substances, such as air pollution or proximity to toxic sites the focus of classic environmental epidemiology access to various health-related resources e.g. healthy or unhealthy foods, recreational resources, medical care.
A sports car starts from rest it covers a distance of 900 m to attain a speed of 80m s determine the acceleration of the car and the time required to reach this speed
Answers
The acceleration of the car and the time required to reach this speed will be 8 m/s² and 10 sec.
What is acceleration?The rate of velocity change concerning time is known as acceleration.
Given data;
Initial velocity, u=0 m/s
Final velocity, v= 80 m/sec
Distance travelled,s =900m
From Newton's third equation of motion;
v²=u²+2as
a =(v²-u²)/2s
Substitute the given values;
a = (80²-0)/2 ×900
a = 6400/1800
a=8 m/s²
The time required to reach this speed is found in Newton's first equation of motion as;
v = u+at
Substitute the given values;
80 = 0 + 8t
t=80/8
t = 10 sec
Hence, the acceleration of the car and the time required to reach this speed will be 8 m/s² and 10 sec.
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An object travels a distance of 56 meters to the right in 7 seconds. What is the object's velocity?
Answers
Explanation:
Distance travelled (d) = 56 metres
Time taken (t) = 7 seconds
velocity of the object (V)
= d / t
= 56 / 7
= 8 m/s
The velocity of the object is 8 m/s.
Hope it will help :)
outside temperature over a day can be modelled as a sinusoidal function. suppose you know the high temperature for the day is 66 degrees and the low temperature of 34 degrees occurs at 6 am. assuming t is the number of hours since midnight, find an equation for the temperature, d, in terms of t.
Answers
Temperature equation: d = 16sin((π/12)(t-6)) + 50.
Find temperature equation?To model the outside temperature over a day as a sinusoidal function, we can use the sine function. Here's how you can find an equation for the temperature, d, in terms of t:
Let's consider a 24-hour period from midnight (t = 0) to midnight (t = 24). The temperature starts at 34 degrees at 6 am (t = 6) and reaches its highest point of 66 degrees at some time during the day.To create a sinusoidal function, we need to determine the amplitude, period, phase shift, and vertical shift.Amplitude (A): The amplitude is half the difference between the high and low temperatures, which is (66 - 34)/2 = 16 degrees. Therefore, A = 16.
Period (P): The period is the duration of one complete cycle of the sine function. Since it represents a full day, the period is 24 hours. Therefore, P = 24.
Phase shift (C): The phase shift is the horizontal displacement of the sinusoidal function. It represents the time when the temperature reaches its lowest point. In this case, it occurs at 6 am (t = 6), which is a 6-hour delay from midnight. Therefore, C = 6.
Vertical shift (D): The vertical shift represents the average temperature over the day. Since the average of the high and low temperatures is (66 + 34)/2 = 50 degrees, D = 50.
Now, we can write the equation for the temperature, d, in terms of t:d = A * sin((2π/P) * (t - C)) + D
Substituting the values we found earlier, the equation becomes:
d = 16 * sin((2π/24) * (t - 6)) + 50
Therefore, the equation for the temperature, d, in terms of t is:
d = 16 * sin((π/12) * (t - 6)) + 50
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a rock is tossed straight up from a height of 1.20 m above the ground with an initial speed of 7.54 m/s. how many seconds later does the rock hit the ground?
Answers
A rock is tossed straight up from a height of 1.20 m above the ground with an initial speed of 7.54 m/s. It will take 0.15 seconds to hit the rock ground
height = displacement = 1.20 m
initial speed = u = 7.54 m/s
final speed = v = 0
time = ?
Using kinematic equation
s = u*t + 1/2 * g * \(t^{2}\)
1.20 = 7.54 t + 1/2 * 9.8 * \(t^{2}\)
= 4.9 \(t^{2}\) + 7.54 t - 1.20
t = 0.15 seconds
It will take 0.15 seconds to hit the rock ground
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An object is moving with uniform speed in a circle of radius r. Calculate the distance and displacement
(a) When it completes half the circle,
(b) When it completes full circle,
(c) What type of motion does the object possess ?
Answers
Answer and Explanation:
distance will be 2×3.14 (pie)×r
displacement will be 2r (diameter)
the motion is uniform circular motion as the object is moving in a circular path with uniform motion
Answer:
distance= pi*r=π×r²
displacement=2r
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The image I've attached holds the question.What is the satellite’s speed?Answer in units of m/s.What is the period of the satellite’s orbit?Answer in units of h.
Answers
Given:
The gravitational constant, G=6.67259×10⁻¹¹ N·m²/kg⁻²
The mass of the moon, M=7.36×10²² kg
The radius of the orbit of the satellite, R=955.2 km=955.2×10³ m
To find:
1. Satellite's speed.
2. The period of satellite.
3. The acceleration of the satellite.
Explanation:
1.
The gravitational force applied by the moon on the satellite provides the satellite with the centripetal force that is neccessary for the satellite to orbit the moon.
Thus,
\(\begin{gathered} F_c=F_g \\ \frac{mv^2}{R}=\frac{GMm}{R^2} \\ v=\sqrt{\frac{GM}{R}} \end{gathered}\)Where F_c is the centripetal force, F_g is the gravitational force, and v is the orbital velocity of the satellite.
On substituting the known values,
\(\begin{gathered} v=\sqrt{\frac{6.67259\times10^{-11}\times7.36\times10^{22}}{955.2\times10^3}} \\ =2267.46\text{ m/s} \end{gathered}\)2.
The orbital period of the satellite in seconds is given by,
\(T=\frac{2\pi R}{v}\)Thus the period of the satellite in hours is given by,
\(T=\frac{2\pi R}{v\times3600}\)On substituting the known values,
\(\begin{gathered} T=\frac{2\pi\times955.2\times10^3}{2267.46\times3600} \\ =0.74\text{ hr} \end{gathered}\)3.
The acceleration of the satellite is given by,
\(a=\frac{v^2}{R}\)On substituting the known values,
\(\begin{gathered} a=\frac{2267.46^2}{955.2\times10^3} \\ =5.38\text{ m/s}^2 \end{gathered}\)Final answer:
1. The orbital velocity of the satellite is 23267.46 m/s
2. The period of the satellite is 0.74 hr
3. The acceleration of the satellite is 5.38 m/s²
The diagram shows a state of matter in a closed system before and after undergoing a
change.
System before change
System after change
SEE
Which statement best explains the change in the system?
Particle motion decreases when thermal energy is added to the system
O Particle motion increases when solid particles are added to the system.
O Particle motion increases when thermal energy is added to the system.
O Particle motion decreases when gas particles are added to the system.
Answers
Answer:
the second one
Explanation:
Particle motion increases when solid particles are added to the system.
Aluminum is often melted down for recycling purposes. Assuming 1 kg of aluminum is at room temperature, what is the minimum amount of heat needed to melt it to a liquid? The specific heat capacity of aluminum is 899 J/kg°C, the melting point is 660°C, and the latent heat of fusion is 3.97 x 105 J/kg.
60 points
Answers
The minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.
What is enthalpy of fusion?The minimum amount of heat needed to melt it to a liquid is known as the enthalpy of fusion.
The formula for the enthalpy of the fusion is;
\(\rm L_f=Q/m \\\\ L_f=mCdt/m \\\\ L_f= Cdt \\\\ L_f= 899 J/kg^0C \times (660^0-27^0) \\\\ L_f= 569,067 \ J \\\\\ L_f=569.067 \ kJ\)
Hence, the minimum amount of heat needed to melt it to a liquid will be 569.067 kJ.
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If you weigh 38 kilograms on your bathroom scale, your weight in space will be ________.
38 kilograms
more than 38 kilograms
less than 38 kilograms
38 kilograms minus your clothes
Answers
Answer:
Less than 36kilo's
Explanation:
Use Newton's second law of motion and a free-body diagram to...
1. ...calculate the normal force acting upon a 50-kg passenger who accelerates upward at a rate of 3.0 m/s/s.
2. ...calculate the normal force acting upon a 50-kg passenger who accelerates downward at a rate of 3.0 m/s/s.
Please don't put any links or I will report you.
Answers
F = m*a
F = 50*3
F = 150 N
A marble is launched 8.00 m/s horizontally from a height of 1.60 m. How long does it take the marble to hit the ground?
Answers
It take the marble 0.57 second to hit the ground.
What is velocity?
A body's velocity is the rate at which its displacement alters with respect to time. A vector quantity with both magnitude and direction is velocity. The meter/second unit of measurement for velocity.
Given that the horizontal velocity of the marble is: u = 8.00 m/s.
Height of the place: H = 1.60 m.
As their has no initial vertical component of velocity; time taken by the marble to reach the ground: t = √(2H/g)
= √(2×1.60/9.8) second
= 0.57 second.
Hence, time taken to reach ground is 0.57 second.
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How to integrate 1/ 1 + x2
Answers
The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.
Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.
Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:
∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du
The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.
Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.
Let us work through the steps:
Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x
Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du
Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.
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Consider three widely separated galaxies in an expanding universe. Imagine that you are located in galaxy 1 and observe that both galaxies 2 and 3 are moving away from you. If you asked an observer in galaxy 3 to describe how galaxy 2 appears to move, what would he or she say?
Answers
Answer:
The observer will say that galaxy 2 is moving away from galaxy 3 where he stands.
Explanation:
Since the galaxies are expanding, each one would move away from the others. Observers on all three galaxies have their frame of reference fixed on their own galaxies. Judging from their own galaxies, each observer will perceive the other galaxies moving away from his/or galaxy.
The observer at galaxy 3 will talk about galaxy 2 by doing is; he will say that galaxy 2 is moving far from him.
We are told that the universe is expanding and as such, the galaxies would be expanding and moving away from each other.
Since the galaxies are expanding, it means that they will be moving away from each other.
From time dilation principle, an observer at galaxy 3 will say that galaxy 2 is moving far from him.
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*A ceiling fan has an angular acceleration of 62 rad/s2 when acted on
by a force of 8.3 N.m. What is the moment of inertia of the fan?
Answers
we can estimate it by assuming that the radius is 1 meter. In that case, the moment of inertia would be I = 8.3 N.m * 1 meter / 62 rad/s2 ≈ 0.13 kg·m2.
What is radius ?Radius is a line segment that connects two points on the circumference of a circle, with one endpoint at the centre of the circle and the other endpoint at any point on the circumference. Radius is also the length of this line segment. It is an important concept in geometry, trigonometry, and calculus, and is used to measure the size and shape of circles, as well as other curved figures. Radius is typically represented by the letter ‘r’, and the length of a radius is half the circumference of the circle.
The moment of inertia of a ceiling fan is calculated using the equation I = F * radius / angular acceleration, where F is the applied force, radius is the distance from the center of the fan to the point where the force is applied, and angular acceleration is the angular acceleration of the fan.
In this case, the moment of inertia is calculated as I = 8.3 N.m * radius / 62 rad/s2. Since the radius is not given, we cannot calculate the exact moment of inertia.
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9. A bicyclist is moving down a hill. Her position on the hill gives her 720 J of potential energy, and her
movement gives her 680 J of kinetic energy. What is her total mechanical energy?
A. 260 J
B. 1400 J
C. 2648 J
D. 2.86×105 J
Answers
The total mechanical energy of the bicyclist is 1400 J, obtained by adding her potential energy of 720 J and kinetic energy of 680 J. The correct answer is option B.
The total mechanical energy of a moving object is the sum of its kinetic energy and potential energy. Kinetic energy is defined as the energy an object has due to its motion, whereas potential energy is the energy an object has due to its position or configuration.Therefore, the total mechanical energy of the bicyclist is calculated by adding her kinetic energy and potential energy. According to the question, the bicyclist has 720 J of potential energy and 680 J of kinetic energy.Total mechanical energy = Potential energy + Kinetic energy = 720 J + 680 J = 1400 JTherefore, the total mechanical energy of the bicyclist is 1400 J. Therefore, the correct answer is option B.For more questions on mechanical energy
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(a) A novelty clock has a 0.0100-kg-mass object bouncing on a spring that has a force constant of 1.25 N/ m. What is the maximum velocity of the object if the object bounces 3.00 cm above and below its equilibrium position
Answers
Answer:
0.3354 m/s
Explanation:
Using the general equation of a wave,
x(t) = Acos(ωt+Φ)....................... Equation 1
Where x(t) = distance of the wave at an instantaneous time t, A = maximum displacement of the wave, ω = angular velocity, t = time, Φ = phase angle.
Note: v(t) = x(t)/t, and this is the differentiation of x(t)
V(t) = -Aω sin(ωt+Φ)............. Equation 2
From the equation above,
V(max) = Aω............... Equation 3
But,
ω = √(k/m)................ Equation 4
Where k = force constant of the spring, m = mass of the object.
Given: k = 1.25 N/m, m = 0.01 kg
Substitute these values into equation 4.
ω = √(1.25/0.01)
ω = √125
ω = 11.18 rad/s
Also given: A = 3.00 cm = 0.03 m
Substitute into equation 3
V(max) = 11.18(0.03)
V(max) = 0.3354 m/s
When resting, a person has a metabolic rate of about 4.70x10^5 joules per hour. The person is submerged neck deep into a tub containing no 812kg of water at 23.07 degrees Celsius. If the heat from the person goes only into the water, by how much will the water temperature temperature increase after 43 minutes of immersion?
Answers
Given
Rate of metabolic rate,
\(Q=4.70\times\frac{10^5J}{hr}\)Mass of water,
\(m=812kg\)The initial temperature,
\(T=23.07^oC\)Explanation
The heat transferred in 43 minutes is given by
\(\begin{gathered} Q\times\frac{43}{60}=mc(T_f-T_i) \\ \Rightarrow4.70\times10^5\times\frac{43}{60}=812\times4180(T_f-28) \\ \Rightarrow T_f=28.099^oC \end{gathered}\)Conclusion
The temperature increase to 28.099 degC
How much work input is required to lower (not drop) a 120-pound weight from the top of a 3-foot table to the floor?
A. 40 foot-pounds.
B. 360 foot-pounds.
C. 120 pounds of force.
Answers
The work input required to lower a 120-pound weight from the top of a 3-foot table to the floor is 360 foot-pounds. The correct answer is option B.
The work done to lower an object is calculated by multiplying the force exerted on the object by the distance over which the force is applied. In this case, the force exerted is the weight of the object, which is 120 pounds.
The distance over which the force is applied is the vertical distance from the table's top to the floor, which is 3 feet.
To calculate the work input, we use the formula W = F × d, where W is the work, F is the force, and d is the distance.
Substituting the given values, we have W = 120 pounds × 3 feet = 360 foot-pounds.
Therefore, the work input required to lower the 120-pound weight from the top of the 3-foot table to the floor is 360 foot-pounds.
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Question 6
Marks: 1
A ______ is a dimensionless unit to express physical intensity or sound pressure levels.
Choose one answer.
a. noise level
b. decibel
c. hertz
d. sound pressure level (SPL)
Answers
A decibel is a dimensionless unit to express physical intensity or sound pressure levels.
A decibel is a dimensionless unit to express physical intensity or sound pressure levels. The decibel, in turn, measures the power of the sound, its energy, and the stronger or weaker it is emitted. Measures the volume of the sound. It is a logarithmic scale that quantifies the relative loudness or softness of a sound compared to a reference level. The decibel scale is based on powers of 10, where an increase of 10 dB represents a tenfold increase in sound intensity. The reference level for the decibel scale varies depending on the context. In the field of acoustics, the commonly used reference level is 0 dB, which corresponds to the threshold of human hearing. Positive decibel values indicate increasing sound levels, while negative values indicate decreasing sound levels or the absence of sound.
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technician a says the charging system is needed to keep the battery fully charged and recharge the battery after starting. technician b say the charging system supplies all the vehicle's electrical current needs after the engine starts. who is correct?
Answers
Answer:
Technician A is correct
Explanation:
The statement "charging system is needed to keep the battery fully charged and recharge the battery after starting" is correct
from technician's B point of view, that the charging system supplies electrical current needs after engine start is incorrect.
In-fact the charging system is dedicated to the battery alone, the electrical needs of the system is gotten from the battery.
A student named Bob is on a bike and the mass is 50 kg. The force causes the student to accelerate at 3 m/s to the power of 2. Calculate the net force that causes this acceleration.???
Answers
Answer:
150 N
Explanation:
Force is equal to mass times acceleration. 50 kg accelerating at a mass of 3m/3² is undergoing a force of 150 m/s², or 150 Newtons