Two people are trying to decide whether a die is fair. The correct test for analyzing the fairness of the die with the given data is the chi-square \(X^2\) test, not the z-test.
The z-test is used for analyzing data when we have known population parameters, such as the mean and standard deviation. However, in this case, we are dealing with categorical data (the frequencies of each face of the die), and we want to determine if the observed frequencies significantly differ from the expected frequencies.
To perform the chi-square test, we first need to calculate the expected frequency for each face of the die. The expected frequency is calculated by multiplying the total number of rolls (100) by the probability of each face (1/6, assuming a fair die). Each face of the die is expected to occur approximately 16.67 times (100/6 = 16.67).
Next, we calculate the degrees of freedom (df) for the chi-square test. For a fair die with 6 faces, the df is (number of categories - 1), which is 5 in this case.
Then, we calculate the chi-square statistic\((X^2)\) by summing the squared differences between the observed and expected frequencies, divided by the expected frequencies. The \(X^2\) value is used to assess the goodness-of-fit between the observed and expected frequencies.
Finally, we determine the p-value associated with the calculated \(X^2\)value using the chi-square distribution and the degrees of freedom. The p-value indicates the likelihood of observing the data if the die is fair.
To provide the specific values for the expected frequency, degrees of freedom, \(X^2\), and p-value, the actual calculations based on the given data are required.
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During gym , your "friend" is standing 5 meters from you and throws a ball at your face. It hits you in approximately 1. 2 seconds. What is the velocity of the ball?
The velocity of the ball thrown by your friend is approximately 4.17 meters per second.
To ascertain the speed of the ball, we want to utilize the condition of movement that relates distance, time, and speed increase. For this situation, we expect that the ball goes in an orderly fashion, and its speed increase is because of the power applied by your companion's toss. We can utilize the recipe:
distance = speed x time
We realize that the distance among you and your companion is 5 meters, and the time taken for the ball to travel that distance is 1.2 seconds. Hence, we can revise the equation to tackle for the speed:
speed = distance/time
Subbing the qualities, we get:
speed = 5/1.2 = 4.17 meters each second (approx.)
So the speed of the ball tossed by your companion is around 4.17 meters each second.
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Select the correct answer.
Which equation represents a function?
Answer:
C
Step-by-step explanation:
'x=' create vertical lines which are not functions whereas
'y=' create horizontal lines which are functions
simplify
a)6+[12-5 multiply by 2 +{2+ small bracket 8 divided by 4 -2 small bracket curley bracket ]
make a meaningful question and solve this
only for math legends who are the dad of albert einstein
Answer:
8
Step-by-step explanation:
\(6 + 12 - 5 \times 2 + 2(8 \div 4 - 2)\)
\(6 + 12 - 10 + 2(2 - 2)\)
\(6 + 12 - 10 + 2 \times 0\)
\(6 + 12 - 10 + 0\)
\( = 8\)
Indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5). Enter your answer into the blank equation box. (Do not use spaces.)
Equation of a line is \(x+3y =-3\).
What is a perpendicular bisector of the line segment?A perpendicular bisector is a line that cuts a line segment connecting two points exactly in half at a 90 degree angle. To find the perpendicular bisector of two points, all you need to do is find their midpoint and negative reciprocal, and plug these answers into the equation for a line in slope-intercept form.
Given that,
Endpoints of the line segment are (\(x_{1},y_{1}\)) = (4, 1) and (\(x_{2},y_{2}\)) = (2, -5).
First find the midpoints of the given line segment.
M = \(\left(\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2}\Right)\)
= \(\left(\frac{4+2 }{2},\frac{1-5 }{2}\Right)\)
M = \((3,-2)\)
Now, Find the slope of the line :
It is perpendicular to the line with (4,1) and (2,-5)
Slope between (\(x_{1},y_{1}\)) and (\(x_{2},y_{2}\)) = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
so,
the slope between (4,1) and (2,-5) = \(\frac{-5-1 }{2-4 }\)
= 3
perpendicular lines have slopes the multiply to get -1
3 times m=-1
m= \(\frac{-1}{3}\)
The equation of a line that has a slope of m and passes through the midpoints M(3,-2) is
\(y-y_{1} =m(x-x_{1} )\)
\(y-(-2) =\frac{-1}{3} (x-3 )\)
\((y+2) =\frac{-1}{3} (x-3 )\)
if we want slope intercept form
\((y+2) =\frac{-1}{3} x+1\)
\(y= \frac{-1}{3} x-1\)
If we want standard form
\(\frac{1}{3} x+y = -1\)
\(x+3y =-3\)
Hence, Equation of a line is \(x+3y =-3\).
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In your opinion, which is better. Pancakes, or waffels?
(1 point) The weight of a lake trout as a function of age satisfies the formula W(t) = 25.5(1 - -0.181)3, where W is in kg and t is in years. a. Differentiate this weight function. W'(t) = Find its second derivative. W"(t) = Give both the t and W values for any points of inflection (t > 0). t = yr. W(t) = kg. The trout is gaining weight most rapidly at this point of inflection. Find this most rapid rate of growth. W'(t) = kg/yr.
a. Differentiating the weight function with respect to t, we get:
W'(t) = 25.5(3)(-0.181)(1 - 0.181)2(-0.181')
Simplifying, we get:
W'(t) = -13.92(1 - 0.181)2(0.181')
b. Taking the second derivative of W(t) with respect to t, we get:
W''(t) = -13.92(1 - 0.181)2(0.181'')
Simplifying, we get:
W''(t) = 8.38(0.181'')
c. To find the points of inflection, we need to find the values of t for which W''(t) = 0. Since 0.181'' is always positive, W''(t) will only be zero when t = 0.
To find the corresponding W value, we can use the original weight function:
W(0) = 25.5(1 - 0.181)3 = 25.5(0.819)3 = 15.99 kg
Therefore, the point of inflection is (t, W) = (0, 15.99) years, kg.
d. To find the most rapid rate of growth, we need to find the maximum value of W'(t). We can do this by setting W'(t) = 0 and solving for t:
0 = -13.92(1 - 0.181)2(0.181')
Differentiating , we get:
0.181' = 0.181/3 = 0.06033
Substituting this value back into the expression for W'(t), we get:
W'(t) = -13.92(1 - 0.181)2(0.06033) ≈ -0.229 kg/yr
Therefore, the trout is gaining weight most rapidly at the point of inflection, and the most rapid rate of growth is approximately -0.229 kg/yr.
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Find the measure of each missing angle.
Answer:
m< 3 = 180 - 93
m< 3 = 87 degrees
m< 4 = 180 - 87 - 49
m< 4 = 44 degrees
m< 2 is vertically opposite to the 49 degree angle given
m< 2 = 49 degrees
m< 1 = 180- 68 - 49
m< 1 = 63 degrees
The measure of each missing angle are; m< 1 = 63, m< 2 = 49, m< 3 = 87 and m< 4 = 44 degrees
What are vertically opposite angles?The vertically opposite angles are those angles that are opposite one another at a specific vertex and are created by two straight intersecting lines.
We can determine angle 3 as;
m< 3 = 180 - 93
m< 3 = 87 degrees
Also,
m< 4 = 180 - 87 - 49
m< 4 = 44 degrees
We can see that m< 2 is equal to 49-degree angle by a vertically opposite angle.
m< 2 = 49 degrees
m< 1 = 180- 68 - 49
m< 1 = 63 degrees
Hence, the measure of each missing angle are; m< 1 = 63, m< 2 = 49, m< 3 = 87 and m< 4 = 44 degrees
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Greg and terry are buying a $340,750 home. They are approved for an APR of 9.1%, 30 year loan. They made a 25% down payment and will be closing on July 11th. How much is the prepaid interest and what is the monthly payment?
Answer:
wow man this is a tough question
-3
-2
- 1
2.
3
4
-2
-3
-4
-5
The equation of the line in this graph is y =
Answer:
please ask proper question or repost it
g Fisher's Exact Test is used when there are ______samples of categorical data. Group of answer choices two independent two paired more than two independent none of the above
Fisher's Exact Test is used when there are two independent samples of categorical data, and it is a valuable tool for analyzing small sample sizes where other tests may not be appropriate.
Fisher's Exact Test is used when there are two independent samples of categorical data. This test is specifically designed to determine if there is a significant association between two categorical variables in a 2x2 contingency table.
It is commonly used when the sample size is small, which can cause issues with other statistical tests such as the chi-square test.
The two independent samples refer to two different groups or populations that are being compared. For example, we might be interested in comparing the success rates of a new drug treatment versus a placebo in a clinical trial, where success and failure are the two categories being considered.
Fisher's Exact Test calculates the probability of observing the data given the null hypothesis of no association between the variables. It does this by considering all possible arrangements of the data that have the same marginal totals. If the calculated probability is very small (typically less than 0.05), we reject the null hypothesis and conclude that there is a significant association between the variables.
In summary, Fisher's Exact Test is used when there are two independent samples of categorical data, and it is a valuable tool for analyzing small sample sizes where other tests may not be appropriate.
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Numbers of the jerseys of 5 randamty selected Carolina Panthers Quantitative discrete Quantitative continuous. Gualitative
The numbers of the jerseys of 5 randomly selected Carolina Panthers would fall under the category of quantitative discrete data.
Quantitative data are numerical measurements or counts that can be added, subtracted, averaged, or otherwise subjected to arithmetic operations. Discrete data, on the other hand, can only take on specific, whole number values, as opposed to continuous data which can take on any value within a range.
Qualitative data, on the other hand, are non-numerical data that cannot be measured or counted numerically. Examples include colors, names, opinions, and preferences. Since the numbers of the jerseys are specific numerical values, they are considered quantitative data.
Since they can only take on specific, whole number values (i.e. the jersey numbers are not continuous values like weights or heights), they are considered discrete data. Therefore, the correct option for the given question is option "quantitative discrete".
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let d be the region in the first quadrant of the xy-plane given by 1 < x^2 + y^2 < 4(a) Sketch the region D, and say whether it is type z, type y, both, or neither. (b) Set up, but do not evaluate, a double integral or sum of double integrals to integrate f(x, y) = y over the region D.
a) Here is a sketch of the region D:
|\
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| \
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| \
| \
_________|________\_________
| \
| \
| \
| \
| \
| \
b) Possible way to set up this integral is:
∫[0,2π] ∫[1,2] y r dr dθ
Write down brief solution to both parts of the question?(a) The region D is an annulus (a ring-shaped region) with inner radius 1 and outer radius 2. It is neither a type z nor a type y region.
Here is a sketch of the region D:
|\
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| \
| \
| \
| \
| \
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_________|________\_________
| \
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(b) The integral to find the volume under the surface z = y over the region D is:
∬D y dA
where D is the region given by 1 < x² + y² < 4. One possible way to set up this integral is:
∫[0,2π] ∫[1,2] y r dr dθ
where we integrate first with respect to r, the radial variable, and then with respect to θ, the angular variable. Note that the limits of integration for θ are 0 to 2π, the full range of angles, and the limits of integration for r are the radii of the annulus
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Mr. Zuro finds the mean height of all students in his statistics class to be inches. Just as mr. Zuro finishes explaining how to get the mean, danielle walks in late. Danielle is inches tall. What is the mean height of the students in the class?.
Mean height of the students in the class = 65.7 inches
The mean height of all 12 students in the class is 66.0 inches.
So the Total height of 12 students in the class = 66 × 12
= 792 inches
As Danielle's height = 62.1 inches
So the total height of 13 students = 792 + 62.1
= 854.1 inches
Mean of all 13 students in the class = 854.1 / 13
= 65.7 inches
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The complete question:
Mr. Zuro finds the mean height of all 12 students in his class to be 66.0 inches. Just as Mr. Zuro finishes explaining how to get the mean, Danielle walks in late. Danielle is 62.1 inches tall. What is the mean of the 13 students in the class?
Ashlee is placing a rug in the middle of her bedroom. The length of the rug is two feet more than the width.
What is the area of the bedroom?
Answer:
A=16
Step-by-step explanation:
formula is 2l+2w=A
Harry fills up his Jeep with gasoline and notes that the odometer reading is 23,408.1 miles. The next time he fills up his Jeep, he pays for 15.5 gallons of gasoline. He notes his odometer reading is 23,684 miles. How many miles per gallon did he get? (Round the answer to the nearest tenth, if necessary.)
First let's find how many kilometers the jeep traveled, by subtracting the odometer readings:
\(23684-23408.1=275.9\)Now, to find the miles per gallon, we just need to divide the kilometers by the amount of gallons of gasoline:
\(\frac{275.9}{15.5}=17.8\)So Harry got 17.8 miles per gallon with the Jeep.
write the parametric equations of the line l passing through point a(5,-8,4) and perpendicular with the plane p described by the equation
The parametric equations of the line l passing through the given point and perpendicular with the plane p is x = 5 - 3t, y = -8 - 3t, and z = 4 - t.
To find the parametric equations of the line passing through point a (5,-8,4) and perpendicular to the plane p described by the equation 1x - 3y + 3z = 6, we need to first find the direction vector of the line.
The normal vector of the plane p is (1,-3,3), since the coefficients of x, y, and z in the plane equation represent the components of the normal vector.
To find the direction vector of the line, we take the cross product of the normal vector of the plane p and any vector that lies on the line. We can choose the vector (1,0,0) as lying on the line, since it is perpendicular to the normal vector of the plane.
Thus, the direction vector of the line is:
(1,0,0) x (1,-3,3) = (-3,-3,-1)
Now we can write the parametric equations of the line in vector form:
r = a + t*d
where r is the position vector of any point on the line, t is a parameter, a is the position vector of the known point on the line (5,-8,4), and d is the direction vector of the line (-3,-3,-1).
So the parametric equations of the line passing through point a (5,-8,4) and perpendicular to the plane p described by the equation 1x - 3y + 3z = 6 are:
x = 5 - 3t
y = -8 - 3t
z = 4 - t
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First method: Multiply the equation for bouquet A by , and add it to the equation for bouquet C. Then multiply the equation for bouquet B by , and add it to the equation for bouquet C. Second method: Rewrite the equation for bouquet B by subtracting from both sides of the equation. Then divide both sides by , and substitute the expression for in the equations for bouquets A and C.
Answer:
looking at anwser now
Step-by-step explanation:
Round these numbers to the nearest tenth.
a) 74.3472
b) 98.759
Answer:
a) 74.3
b) 98.8
Step-by-step explanation:
The tenth decimal place is the first place immediately to the right of the decimal point. When rounding, you first need to look at the number to the right of the place you wish to find. If the number in this spot is 5 - 9, round the number in the tenth decimal place up one unit. If the number is 0 - 4, keep the number in the tenth decimal place the same. Finally, remove all of the numbers to the right of the tenth decimal place.
a) 74.3472
^ tenth
The next number to the right (4) is not big enough to round up
a) 74.3
b) 98.759
^ tenth
The next number to the right (5) is big enough to round up
b) 98.8
Answer:
a) 74.3
b) 98.8
Step-by-step explanation:
Go to the tenths place, and check the hundredths spot. If the number in the hundredths is less than five, leave the tenths place alone. If it is greater than five, round the tenths place up.
A triangle has sides with lengths of 16 meters, 7 meters, and 12 meters. Is it a right triangle?
Find the Area of the triangle, Is it In or In2
Answer:
15 In²
Step-by-step explanation:
Area of triangle = 1/2 × base × height
1/2 × 6 × 5 = 15
Find the work done by vector field F(x, y, z) = xi + 15xyj − (x + z)k on a particle moving along a line segment that goes from (1, 4, 2) to (0, 5, 1).
The work done by the vector field F(x, y, z) = xi + 15xyj − (x + z)k on a particle moving along a line segment from (1, 4, 2) to (0, 5, 1) can be found by evaluating the line integral of F along the line segment.
To calculate the work done, we start by parametrizing the line segment as r(t) = (1 - t)i + (4 + t)j + (2 - t)k, where t varies from 0 to 1. Then, we express the line integral of F along the line segment using the dot product of F and the differential of the position vector dr.
After substituting the parametric equations for x, y, and z into the line integral, we simplify the expression and integrate it with respect to t over the interval [0, 1]. The integral involves evaluating terms such as x, xt, and constants. By performing the integration, we obtain the numerical value of the work done by vector field F on the given line segment.
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in the united states, 44% of adults have type O blood. You will choose 32 US adults at random until you find one with type O blood. What is the probability. a It takes 4 people to find one with type O blood
The probability that it takes 4 people to find one with type O blood is approximately 0.0938 or 9.38%.
What are the three kinds of probability?Probability is classified into three types:
Classical: (equally probable outcomes) (equally probable outcomes).Definition of Relative Frequency.Probability that is subjective.A randomly selected US adult has a 44% chance of having type O blood. This probability is denoted by the letter p.
The likelihood that the first person you choose does not have type O blood is 1-p (or 56% in this case).
To calculate the probability that it takes exactly four people to find one with type O blood, multiply the odds of the first three people not having type O blood (1-p) by the odds of the fourth person having type O blood (p).
As a result, the likelihood is:
(1-p) * (1-p) * (1-p) * p
= (0.56) * (0.56) * (0.56) * (0.44) (0.44)
= 0.0938
As a result, the probability of finding someone with type O blood is approximately 0.0938, or 9.38%.
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Please help !!
Select the correct answer.
Factor the expression.
(49x^2 - 16) | (Choices in the picture.)
Answer:
B.
Step-by-step explanaBtion:
The answer would be B
(7x+4)(7x-4)
you can tell because when you expand it e.g.
49x^2 +28x - 28x -16
simplify
49x^2 - 16
equals the expression
Answer:
The answer would be B: (7x+4)(7x-4)
Cual es la Raíz cuadrada de 32
Answer:
5.66
Step-by-step explanation:
\(\sqrt{32}\)=5.65685
Find the vilume of the cylinder. Round your andwer to the nearest tenth
A. 87.9 mm3^
B. 175.8 mm3^
C. 153.9 mm3^
D. 615.4 mm3^
Dont answer randomly please and thank you
Answer:
could be wrong. but I belive its B
Step-by-step explanation:
7 X 2 = 14 x pi (3.14) = gives us 43.96. since its 4 tall. you would muiliply 43.96 x 4. it would give you 175.84.
here is the formula because I want you to understand this.
R = radius
D = 2 x radius
Pi = 3.14
C = circumference
C = Pi x (radius x 2)
Find m/STR.
186
T
m/STR=
112
R
degrees
The $600.00 earned at the back sale was shared by 3 groups. The band got 1/2.The chess club got 1/3 of what was left. The rest went to the environment club.How much did each group get?? (fractions) (this is due tomorrow)
The band got $300, the chess club got $100, and the environment club got $200.
What are fractions?
A fraction represents a numerical value, which defines the parts of a whole.
The band got 1/2 of the $600, which is:
1/2 x $600 = $300
So, there's $300 left to be shared between the chess club and the environment club.
The chess club got 1/3 of what was left, which is:
1/3 x $300 = $100
So, the environment club got the remaining amount:
$300 - $100 = $200
Therefore, the band got $300, the chess club got $100, and the environment club got $200.
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The scale factor of two similar polygons is given. Find the ratio of their perimeters and the ratios of their areas.
1) 3:1
2) 7/4
The ratios of their perimeters and the ratios of their areas are 1) 3:1 and 9:1 and 2) 7:4 and 49:16.
Given the scale factor of two similar polygons, we need to find the ratio of their perimeters and the ratios of their areas,
To find the ratio of the perimeters of two similar polygons, we can simply write the scale factor as it is because the ratio of the perimeter is equal to the ration of the corresponding lengths.
1) So, perimeter = 3:1
The ratio of areas between two similar polygons is equal to the square of the scale factor.
Since the scale factor is 3:1, the ratio of their areas is:
(Ratio of areas) = (Scale factor)² = 9/1 = 9:1
Similarly,
2) Perimeter = 7:4
Area = 49/16
Hence the ratios of their perimeters and the ratios of their areas are 1) 3:1 and 9:1 and 2) 7:4 and 49:16.
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Urgent!!!! help how do I calculate the area of this parallelogram, due in 20 minutes!!!
0. the population mean annual salary for acme corporation is $63,500. what is the probability that the mean salary of a person selected at random will have a salary that is less than $61,000? assume ????
To find the probability that the mean salary of a person selected at random from Acme Corporation is less than 61,000, we can use the Z-score formula.
First, we need to calculate the Z-score, which measures the number of standard deviations a value is away from the mean. The formula for the Z-score is:
Z = (X - μ) / (σ / √n)
Where:
- X is the value we are interested in (in this case, $61,000)
- μ is the population mean annual salary for Acme Corporation ($63,500)
- σ is the population standard deviation (unknown in this case)
- n is the sample size (unknown in this case)
Since we don't have the population standard deviation or sample size, we cannot calculate the exact Z-score. Therefore, we cannot find the exact probability.
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Based on the assumption of a sample standard deviation of $5,000, the probability that the mean salary of a person selected at random will be less than $61,000 is approximately 30.85%.
The probability of a person selected at random having a salary less than $61,000 can be determined using the z-score and the standard normal distribution.
To calculate the z-score, we need to know the population standard deviation. Since it is not provided, we cannot calculate the exact probability. However, we can use the assumption that the population standard deviation is the same as the sample standard deviation.
Let's assume the sample standard deviation is $5,000.
First, we calculate the z-score:
\(z = (x - \mu) / (\sigma / \sqrt n)\)
=> z = (61000 - 63500) / (5000 / √1)
=> z = -2500 / 5000
=> z = -0.5
Next, we find the corresponding area under the standard normal curve using a z-table or a calculator. The area to the left of -0.5 is approximately 0.3085.
Therefore, the probability that a person selected at random will have a salary less than $61,000 is approximately 0.3085 or 30.85%.
In conclusion, based on the assumption of a sample standard deviation of $5,000, the probability that the mean salary of a person selected at random will be less than $61,000 is approximately 30.85%.
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