The final temperature of both objects will be less than 35°C. Hence, the correct option is less than. The specific heat capacity of a substance refers to the quantity of energy needed to raise the temperature of a unit mass of that substance by one degree Celsius.
Heat is transferred from one object to another when two objects are in thermal contact. When two objects are brought into thermal contact with each other, heat will flow from the hotter object to the cooler object until the temperatures of both objects are equal.
The specific heat capacity of a substance is directly related to its ability to retain heat. A substance with a high specific heat capacity would require more heat to raise its temperature by one degree Celsius than a substance with a low specific heat capacity. Object a will require more heat to raise its temperature than object b.
Therefore, when the two objects are brought into thermal contact with each other, heat will flow from object b to object a until the temperatures of both objects are equal. Since object b is hotter than object a, heat will flow from object b to object a, raising the temperature of object a and lowering the temperature of object b.
Thus, the final temperature of both objects will be less than 35°C. Hence, the correct option is less than.
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Two dimensions. In Figure 13-34, three point particles are fixed in place in an xy plane. Particle A has mass mA = 3 g, particle B has mass 2.00mA, and particle C has mass 3.00mA. A fourth particle D, with mass 4.00mA, is to be placed near the other three particles. What (a) x coordinate and (b) y coordinate should particle D be placed so that the net gravitational force on particle A from particles B, C, and D is zero (d = 22 cm)?
To make the net gravitational force on particle A from particles B, C, and D zero, particle D should be placed at the x coordinate of -11 cm and the y coordinate of 0 cm.
The net gravitational force on particle A from particles B, C, and D can be calculated using the formula for gravitational force:
F = G * (m₁ * m₂) / r²
Where F is the gravitational force, G is the gravitational constant, m₁ and m₂ are the masses of the two particles, and r is the distance between them.
Since the net gravitational force on particle A should be zero, we can set up an equation:
FAB + FAC + FAD = 0
Using the given information that the distance d is 22 cm and the masses of particles B, C, and D are known in terms of mA, we can calculate the x and y coordinates for particle D.
By applying the principle of superposition, we can calculate the net gravitational force on particle A from particles B, C, and D at the x coordinate and y coordinate of particle D. By adjusting the position of particle D, we can find the coordinates that result in a net gravitational force of zero on particle A.
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A machinist wishes to insert an iron rod with a diameter of 6 mm into a hole with a diameter of 5.995 mm. By how much would the machinist have to lower the temperature (in °C) of the rod to make it fit the hole?
The machinist should be careful not to cool the rod too much, as this could cause it to become brittle and difficult to work with.
The diameter of the rod is 6 mm. The diameter of the hole is 5.995 mm. The diameter of the rod is greater than the diameter of the hole by 0.005 mm.
To calculate the change in temperature needed to fit the rod into the hole, use the formula:
ΔL = αLΔT
where ΔL = change in length of the rodα
= coefficient of linear expansion
L = length of the rod
ΔT = change in temperature
Rearranging this equation gives:
ΔT = ΔL / (αL)
The change in length needed to fit the rod into the hole is half the difference in diameters
ΔL = (diameter of the rod - diameter of the hole) / 2
= (6 - 5.995) / 2
= 0.0025 mm
Substituting into the formula above:
ΔT = (0.0025 x 10^-3 m) / (11 x 10^-6 K^-1 x 1 m)
≈ 0.23 °C
Therefore, the machinist would have to lower the temperature of the iron rod by approximately 0.23 °C to make it fit the hole.
This change is relatively small, so the machinist may be able to achieve it by cooling the rod in a refrigerator or freezer for a short period of time.
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The radium isotope 223Ra, an alpha emitter, has a half-life of 11. 43 days. You happen to have a 1. 0 g cube of 223Ra, so you decide to use it to boil water for tea. You fill a well-insulated container with 460 mL of water at 16∘ and drop in the cube of radium.
How long will it take the water to boil?
Express your answer with the appropriate units
It will take about 11.8 days for the water to boil.
The first step is to find the decay constant (λ) of the radium isotope using the half-life equation:
t1/2 = 0.693/λ
where t1/2 is the half-life.
So, rearranging the equation, we get:
λ = 0.693/t1/2
= 0.693/11.43 days
= 0.0605 day⁻¹
Next, we need to calculate the number of radium atoms in the 1.0 g cube using Avogadro's number and the molar mass of 223Ra:
Number of atoms \(= (1.0 g)/(223 g/mol) * (6.022 * 10^{23} atoms/mol)\)
= 2.7 x 10²⁰ atoms
Since each radium atom emits an alpha particle during decay, we can calculate the activity of the radium sample:
Activity = (2.7 x 10²⁰ atoms) x (1 decay/atom) x (1 alpha particle/decay)
= 2.7 x 10²⁰ alpha particles per second
Now, we need to calculate the energy released per alpha particle. The energy (E) released per alpha particle can be calculated using the equation:
E = (Q/m) x Na
where
Q is the energy released per decay,
m is the mass of the radionuclide per decay, and
Na is Avogadro's number.
For 223Ra,
Q = 5.69 MeV,
m = 223/2 = 111.5 g/mol, and
Na = 6.022 x 10^23 atoms/mol.
Therefore,
E = (5.69 MeV/decay)/(111.5 g/mol) x (6.022 x 10²³ atoms/mol)
= 3.84 x 10⁻¹³ J/alpha particle
Finally, we can calculate the rate of energy transfer to the water by multiplying the activity of the radium sample by the energy released per alpha particle:
Rate of energy transfer = (2.7 x 10²⁰ alpha particles/s) x (3.84 x 10⁻¹³ J/alpha particle)
= 1.04 W
To boil the water, we need to transfer enough energy to raise its temperature from 16°C to 100°C and to vaporize it.
The specific heat capacity of water is 4.18 J/g°C, and the heat of vaporization of water is 40.7 kJ/mol, or 2257 J/g. The mass of the water is 460 g, so the total energy required is:
Energy required = (460 g) x (4.18 J/g°C) x (100°C - 16°C) + (460 g) x (2257 J/g)
= 1.06 x 10⁶ J
Finally, we can calculate the time required to transfer this amount of energy to the water using the formula:
Energy transferred = Rate of energy transfer x time
Solving for time, we get:
time = Energy required/Rate of energy transfer
= (1.06 x 10⁶ J)/(1.04 W)
= 1.02 x 10⁶ s
= 11.8 days
Therefore, it will take about 11.8 days for the water to boil.
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3. A class took a field trip to a music studio. The students watched through thick glass as the musicians played
music inside the studio. The students could only hear the music when the studio door was open. The less
separating the musicians from the students is made with two layers of thick glass. The space between the glass
Layers has had all the air removed, creating a vacuum.
Which statement best explains why the students were able to see the musicians even while they were unable to
hear them?
Answer:
Sound can't travel in a vaccum.
Explanation:
Sound waves need a medium in order to travel (e.g. air, water, glass)
Since there was a vaccum between the glass the sound couldn't travel since vaccum's contain a very small amount of atoms.
______________ controls the flow of electric current.
Answer!!!
Please
Answer:
Explanation:
Its resistor
NEED HELP PLEASE ASAP
The energy output of a fan is 36 kWh. The fan is 75% efficient.
How much energy is lost to the surroundings?
12 kWh
36 kWh
48 kWh
84 kWh
Answer:
The energy output of a blender is 1.4 kWh. If the blender is 85% efficient, how much energy is lost to the surroundings?
⇒ 0.25 kWh
when the voltage on each side of the charge indicator lamp is equal (between the lamp and the diode trio), there is no current flow through the lamp and the lamp is turned off
true
false
When the voltage on each side of the charge indicator lamp is equal (between the lamp and the diode trio), there is no current flow through the lamp and the lamp is turned off. The answer is true.
When the voltage on each side of the charge indicator lamp is equal, this means there is no potential difference across the lamp. As a result, no current flows through the lamp, and the lamp remains turned off. In this case, according to Ohm's Law (V = IR), if the voltage is zero, the current flowing through the lamp would also be zero (I = 0), and the lamp would be turned off. The equal voltage on both sides of the lamp ensures that there is no potential gradient to drive any current through it, resulting in the lamp remaining inactive.
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Two stars are in a binary system. One is known to have a mass of 0.800 solar masses. If the system has an orbital period of 28.7 years, and a semi-major axis of 2.39E+9 km, what is the mass of the other star?
The mass of the other star in the binary system is approximately 0.592 solar masses.
To determine the mass of the other star, we can use Kepler's Third Law of Planetary Motion, which can be applied to binary star systems. The law states that the square of the orbital period (\(T\)) is proportional to the cube of the semi-major axis (\(a\)) of the orbit. Mathematically, this can be expressed as\(\(T^2 = \frac{4\pi^2}{G(M_1 + M_2)}a^3\)\), where \(\(M_1\)\) and \(\(M_2\)\) are the masses of the stars, G is the gravitational constant, and other variables have their usual meanings.
Given that one star has a mass of 0.800 solar masses, we can substitute the known values into the equation and solve for \(\(M_2\)\). Rearranging the equation, we have\(\(M_2 = \frac{4\pi^2}{G}(\frac{a^3}{T^2}) - M_1\)\).
Plugging in the values for \(\(a\) (2.39E+9 km)\) and\(\(T\) (28.7 years\)), and using the appropriate unit conversions, we can calculate the mass of the other star, \(\(M_2\)\), to be approximately 0.592 solar masses.
Therefore, the mass of the other star in the binary system is approximately 0.592 solar masses.
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Two copper spheres are currently 1.2 meters apart.One sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4 C .what is the force between the charged spheres is the force attractive or repulsive
Two copper spheres are currently 1.2 meters apart. One sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4 C, then the the force between the charged spheres is the force attractive.
What is Coulomb's law?Coulomb's law can be expressed as that the electrical force between two charged bodies is directly proportional to the product of the quantity of charge on the bodies and inversely proportional to the square of the separation distance between the two bodies.
As given in the problem two copper spheres are currently 1.2 meters apart.One sphere has a charge of +2.2•10-4 C and the other has a charge of - 8.9•10-4 C.
As per coulomb's law, opposite charges attract each other.
Thus, If one sphere has a charge of +2.2•10-4 C and the other has a charge of -8.9•10-4 C, then the the force between the charged spheres is the force attractive.
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Write the relation between:
1) applied force and pressure.
2) surface area of contact and pressure.
realtion between applied force.and pressure is more force exerts more pressure whereas less force exerts less pressure
confused in another one
Answer:
See below
Explanation:
1) Applied Force and Pressure
Pressure = Force / Area
This shows that Applied force and pressure are in direct relationship. This means that If the Applied force is more, the Pressure is also More and vice versa.
2) Surface Area of Contact and Pressure
Pressure = Force / Surface Area of Contact
This shows that Pressure and Surface area of contact are inversely related. This means that if pressure is increased on an object, the surface area of contact decreases and vice versa.
A rock is thrown at an angle of 35.0° to the horizontal with a speed of 11.5 m/s. how far does it travel?
Answer:
The distance covered by the projectile is 12.68 m
Explanation:
Given;
angle of projection, θ = 35.0°
speed of projectile, v = 11.5 m/s
The distance covered by the projectile is given by the range of the projection;
R = vt
\(R = \frac{v^2sin2\theta}{g} \\\\R = \frac{(11.5)^2 sin (2*35)}{9.8} \\\\R = 12.68 \ m\)
Therefore, the distance covered by the projectile is 12.68 m.
Definition of molecular machine
A 7.77 kg pumpkin falls from a height of 12.3 m. It hits the ground and comes to an abrupt stop in about 444 ms. What is the average force imparted by the ground on the pumpkin
Given data-Mass of the pumpkin, m = 7.77 kgHeight from which pumpkin falls, h = 12.3 mTime taken by pumpkin to come to rest, t = 444 ms = 0.444 s. Average force imparted by the ground on the pumpkin = F, Here, we need to calculate the average force exerted by the ground on the pumpkin.
We can calculate the same using the work-energy principle. According to the work-energy principle, the work done on an object is equal to the change in its kinetic energy. Mathematically, W = ΔKE Total work done on the pumpkin is equal to the work done by the gravitational force of the earth on the pumpkin when it falls from a height of h. So, W = mghHere, g = 9.81 m/s² is the acceleration due to gravity. Work done by the ground on the pumpkin when it comes to rest = -1/2 mv². By the work-energy principle, W = work done by the ground + work done by gravity on the pumpkin= -1/2 mv² - mghHere, the final velocity of the pumpkin, v = 0 as it comes to rest. Therefore, W = -mghAs we know, W = Fd, where d is the distance through which the force is applied. Here, d = h.Hence, F = -mgThe negative sign indicates that the direction of the force exerted by the ground is opposite to the direction of motion of the pumpkin (i.e., upward direction). So, substituting the given values,m = 7.77 kg, g = 9.81 m/s², h = 12.3 mF = - (7.77 kg) × (9.81 m/s²) × (12.3 m) = -907.1961 N (upward)Therefore, the average force imparted by the ground on the pumpkin is 907.1961 N (upward).
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whats ur funniest thing u have ever done in ur life mine was me sending a picture of me and my friend at the beach to my principle
which one is more important in science, qualitative or quantitative
Answer:
quantitative
Explanation: quantitative research is better for scientist.
What speed would a fly with a mass of 0.638 g need in order to have 74354.5 j of kinetic energy
Answer:
v = 15,267 m/s
Explanation:
Kinetic Energy
Is the type of energy of an object due to its state of motion. It's proportional to the square of the speed.
The formula to calculate the kinetic energy is:
\(\displaystyle K=\frac{1}{2}mv^2\)
Where:
m = mass
v = speed
The kinetic energy is often expressed in Joules (J)
We are given the mass of a fly m=0.638 g and we need to calculate its speed in order to have a kinetic energy of 74354.5 J.
Converting:
m=0.638 g /1000 = 0.000638 kg
To find the speed, we solve the formula for v:
\(\displaystyle v=\sqrt{\frac{2K}{m}}\)
\(\displaystyle v=\sqrt{\frac{2K}{m}}\)
Substituting:
\(\displaystyle v=\sqrt{\frac{2*74354.5}{0.000638}}\)
v = 15,267 m/s
(The fly should move faster than a rocket)
A 4.28 m deep well acts as a Closed pipe. When wind blows across the top. what is the fundamental frequency it creates? (Speed of sound = 343 m/s) (Unit = H2)
Answer:
F = v / λ
= 343 / 4.28
= 80.1 Hz
Explanation:
The formula connecting wavelength, frequency and speed is F = v / λ, where frequency is represented by F, speed represented by v and wavelength represented by λ. This applies to mechanical waves, which include both sound waves and electromagnetic waves.
There is a long seesaw in the schoolyard James school. James likes to play on the seesaw with his friend Martin. The seats are in the schoolyard is long enough that I went James site is in the air, his feet RSI up as other children said. What forces James when he uses the seesaw 
The force that affects James when he uses the seesaw is force of gravity. Option C.
What is force of gravity about?Gravity may be a constrain that exists between any two objects within the universe that have mass. It is an appealing constrain, meaning it pulls objects towards each other. The size of the gravitational constrain depends on the mass of the objects and the separate between them. The bigger the masses of the objects and the closer they are to each other, the more grounded the gravitational drive between them.
Hence, gravity is the force that pulls James down towards the center of the Soil. This drive is dependable for keeping James situated on the teeter-totter and making him move up and down as he plays. The other alternatives, power, contact, and attractive drive, are not pertinent in this situation and don't play a part within the functioning of the teeter-totter.
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Which statement best describes the difference between acceleration and velocity?
A. acceleration only shows a change in direction, but velocity shows a change in speed.
B .acceleration depends on direction, but velocity does not.
C. acceleration is a change in velocity, but velocity is speed in a given direction.
D. acceleration only shows change in speed, but velocity only shows a change in direction.
Answer:
C
Explanation:
acceleration is a change in velocity which means a time rate change in velocity but velocity is the time rate change in displacement
What does it mean when we say: momentum is conserved? (Law of Conservation of Momentum)
We say that momentum is conserved, we mean that the total momentum of a system remains constant.
This means that in any interaction or collision, the total amount of momentum before and after the collision is the same. This is due to the law of conservation of momentum, which states that the total momentum of a closed system (meaning that no external forces are acting on it) is constant. This means that the total momentum before and after an interaction must be the same, as the momentum of the system cannot be changed unless an external force acts on the system. Whether an elastic or non-elastic collision occurs, momentum is always conserved. Kinetic energy, however, is not conserved in a non-elastic collision; instead, it is transformed into heat energy, potential energy, etc.
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A student drops a bag of mass m onto a cart of mass M that is sliding with speed vo along a horizontal track with negligible friction. Immediately after the bag lands in the cart, the cart-bag system moves with speed uf. Which of the following statements correctly relates the two speeds and gives a correct reason for this relationship?
A. vf
B. Uf 00, because the kinetic energy of the bag decreases.
C. Uf > Vo, because the linear momentum of the bag is added to the linear momentum of the cart.
D. Uf = vo, because the bag is moving perpendicular to the cart.
When the bag lands on the cart, it follows that vf < vo given the fact that some mechanical energy is now lost by the system.
What is friction?The term friction refers to the force that opposes motion. The direction of the frictional force is opposite to the force that causes motion.
When the bag lands on the cart, it follows that vf < vo given the fact that some mechanical energy is now lost by the system. Note that the potential energy of the bag is converted to kinetic energy.
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Which of the following epidermal layers is made of cells that are constantly dividing?
a. stratum corneum
c. stratum spinosum
b. stratum granulosum
d. stratum basale
epidermal layer is made of basal cell layer that are consulting dividing
A dog pulls on a pillow with a force of 5.6 N at an angle of 39 degrees above the horizontal. Assume the x-axis of a reference frame is along the horizontal and the y-axis is along the vertical. Find the x and y components of the force.
1. The x component of the force is 4.4 N
2. The y component of the force is 3.5 N
How do I determine the components of the force?The following data were obtained from the question:
Force applied (F) = 5.6 NAngle (θ) = 39 degreesx component =?y component =?1. How to determine the x component
Force applied (F) = 5.6 NAngle (θ) = 39 degreesx component =?x component = FCosθ
x component = 5.6 × Cos 39
x component = 4.4 N
2. How to determine the y component
Force applied (F) = 5.6 NAngle (θ) = 39 degreesy component =?y component = FSineθ
y component = 5.6 × Sine 39
y component = 3.5 N
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You push downward on a box at an angle 25° below the horizontal with a force of 750 N. If the box is on a flat horizontal surface for which the coefficient of static friction with the box is 0.76, what is the mass of the heaviest box you will be able to move? 59 kg 68 kg 82 kg 54 kg
To determine the mass of the heaviest box you will be able to move, we need to consider the maximum static friction force that can be exerted on the box without it moving. The maximum static friction force can be calculated using the equation:
F_static_max = μ_s * N
where F_static_max is the maximum static friction force, μ_s is the coefficient of static friction, and N is the normal force.
In this case, the normal force is equal to the weight of the box, which is given by:
N = m * g
where m is the mass of the box and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Given:
Angle below the horizontal: 25°
Force applied: 750 N
Coefficient of static friction: 0.76
To calculate the mass of the heaviest box, we need to find the maximum static friction force that can be exerted and set it equal to the applied force:
F_static_max = F_applied
μ_s * N = F_applied
μ_s * m * g = F_applied
μ_s * m * g = 750 N
Solving for m:
m = 750 N / (μ_s * g)
m = 750 N / (0.76 * 9.8 m/\(s^2\))
m ≈ 96.38 kg
Therefore, the mass of the heaviest box you will be able to move is approximately 96.38 kg. Since none of the given answer choices match this value, it seems there might be a calculation error or the correct answer is not provided.
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how much does a change in mass affect the kinetic energy of two balls of comparable diameter?
Answer:
Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.
In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.
what would happen to the orange liquid in the lava lamp if heat did not conduct out of the top of the lava lamp? what would happen to the orange liquid in the lava lamp if heat did not conduct out of the top of the lava lamp? the orange liquid would stay near the bottom of the lava lamp. the orange liquid would rise toward the top of the lava lamp. the orange liquid would stay near the top of the lava lamp. the orange liquid would sink toward the bottom of the lava lamp.
The orange liquid would stay near the top of the lava lamp if the heat did not conduct out of the top of the lava lamp.
Lava lamp - A lava lamp is a decorative lamp, It consists of a bolus of a special coloured wax mixture inside a glass vessel, the remainder of which contains clear or translucent liquid.
The lava lamp contains two liquids with different densities that do not mix and that expand at different rates when heated.
We observe that in the lava lamp experiment, the density of oil is much lower than that of water. Although the water and oil layers separate due to the densities the food couriering has the same density as that of water.
So, If heat did not conduct out of the top of the lava lamp, the orange liquid would stay near the top of the lava lamp
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A skater with a mass of 50 kg is moving at a speed of 5 m/s. Away is their kinetic energy?
q8. a car with a mass of 1500kg is being towed at a steady speed by a rope held at 20degrees angle from the horizontal. a friction force of 320n opposes the car's motion. what is the tension in the rope?
The tension in the rope is 340 N
The x component of the tension triangle is equal to the friction force, 320 N, BUT the tension is not equal to this.
Use Cos 20 degrees = a/H
Where a is 320 N and H will be the tension
If something is at an angle, don't assume it is equivalent to the thing on the other side because of the angle
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A 3. 2 kg cannon ball at rest is fired from a cannon. The cannon ball leaves the cannon with a speed of 6. 0 m/s. Determine the force provided by the cannon if it
takes 0. 55 seconds to launch the cannon ball
0 10,6 N
0 27,8 N
0 34 9 N
0 159 N
The force provided by the cannon to launch a 3.2 kg cannonball at rest with a speed of 6.0 m/s in 0.55 seconds is 34.88 N.
To determine the force, we'll first need to find the acceleration of the cannonball using the formula:
final velocity (vf) = initial velocity (vi) + acceleration (a) * time (t).
Then, we'll use Newton's second law of motion (F = m * a) to find the force.
Step 1: Calculate the acceleration.
Given: vi = 0 m/s (cannonball at rest), vf = 6.0 m/s, t = 0.55 seconds
Formula: vf = vi + a * t
Rearranging the formula: a = (vf - vi) / t
Step 2: Plug in the given values.
a = (6.0 m/s - 0 m/s) / 0.55 seconds
a = 6.0 m/s / 0.55 seconds
a ≈ 10.9 m/s²
Step 3: Calculate the force using Newton's second law of motion.
Given: mass (m) = 3.2 kg, acceleration (a) ≈ 10.9 m/s²
Formula: F = m * a
Step 4: Plug in the given values.
F = 3.2 kg * 10.9 m/s²
F ≈ 34.88N
Thus, the force provided by the cannon is approximately 34.88 N.
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why does fiberglass insulation used in walls of houses often layered with shiny aluminum foil on one side
Answer:
Foil insulation can prevent radiant heat loss all year round. In summer, it can prevent heat from entering by reflecting sunlight. In winter, it can reflect heat back inside a room, keeping it warmer.