Two metal alloys are nearly identical, except Alloy A has 2% impurity content and Alloy B has 8% impurity content. Assuming lattice resistance is nearly zero for both alloys, what do you predict the difference in yield strength (sigma)y to be for these two materials?

Answer:

i) Heat rejection =  1.0288 KJ

  Network production = 1.212 kJ

ii) Thermal efficiency = 54.08%

   mean effective pressure = 353.5 kPa

Explanation:

Given data :

Compression ratio ( r )  = 7

P1 ( initial pressure ) = 90 kPa,

T1 ( initial temperature ) = 27°C + 273 = 300 K

V1 = 0.004 m^3

Max cycle Temperature = 1127°C for each repetition of the cycle

i) Determine the heat rejection and net work production

considering that process 1-2 is an Isentropic compression

Find ; T2 = T1 ( r )^1.4-1

      T2 = 300 ( 7 )^0.4  = 653.371 K

    P2 = P1( r )^k

          = 90 ( 7 )^1.4  = 1372.081 kPa

considering that process 3-4 is an Isentropic expansion

T4 = T3 / r^k-1

    = 1400 / 7^(1.4 -1 ) = 642.82 K

Next ; Calculate the value of m

m = P1V1 / RT1   = 90(0.004) / 0.287 ( 300 )

                      m = 4.18 * 10^-3 kg

Finally :

amount of heat rejected = mCv ( T4 - T1 )

                                          = 4.18 * 10^-3 ( 0.718 ) ( 642.82 - 300 )

                                    Qout  = 1.0288 KJ

amount of heat added ( Qin ) =  mCv ( T3 - T2 )

                                                = 4.18 * 10^-3 ( 0.718 ) ( 1400 - 653.371 )

                   hence           Qin  = 2.2408 kJ

Network production( Wnet) = Qin - Qout

                                  = 2.2408 - 1.0288 ) KJ

                                  = 1.212 kJ

ii) Determine the thermal efficiency and mean effective pressure of the cycle

Thermal efficiency = 1 - Qout / Qin

                               = 1 - ( 1.0288 / 2.2408 )  = 54.08%

mean effective pressure = Wnet / V1 ( 1 - 1/r )

                                         = 1.212 / 0.004 ( 1 - 1/7 )

                                         = 353.5 kPa

Answer:

  a) up

  b) down

Explanation:

When the cube is less dense than water, it will tend to float (move upward). When it is more dense, it will sink (move downward).

a) 160.2 kg/m^3 < 1000 kg/m^3. The cube will move up.

__

b) 7849 kg/m^3 > 1000 kg/m^3. The cube will move down.

Answer:

Not seeing any other information, the best answer I can give is 2m.

Explanation:

M = magnitude

You see, if they have an equal charge, and you add them, it'd be 2 * m, or 2m.

The algorithm helps Billy make a list of the first meat-based pizza order numbers displayed on the screen each time an order is written below.

A process for solving a problem or completing a computation is referred to as an algorithm.

The store's display screen is always displaying Kout of Borders (meat and vegan). The pizza shop is well-known and frequently receives orders.

Program Details

Make a class for a bank account with two attributes:

Owner and Balance,

and two methods:

Deposit and Withdraw.

Note: Withdrawals may not exceed the available balance.

Therefore, the algorithm is written above.

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Explanation:

Remember, to say a product is incorporated with aesthetic design implies that its overall appearance is designed to look beautiful to the eyes of the user/buyer. For example, a clothing company whose target market is mainly focused on women's clothing would need to take into consideration that certain colors like pink, blue, etc are attractive to women more than men. So they'll have to ensure the colors of their clothing are suitable to the needs of their target market.

The Universal Design process involves building products that can be used by a wide range of users at ease. For example, you may ask yourself: Is my product/service easily accesible to those with disabilities?

Other processes include;

Answer:

50421.6 m³

Explanation:

The river has an average rate of water flow of 59.6 m³/s.

Tributary B accounts for 47% of the rate of water flow. Therefore the rate of water flow through tributary B is:

Flow rate of water through tributary B = 47% of 59.6 m³/s = 0.47 * 59.6 m³/s = 28.012 m³/s

The volume of water that has been discharged through tributary B = Flow rate of water through tributary B * time taken

time = 30 minutes = 30 minutes * 60 seconds / minute = 1800 seconds

The volume of water that has been discharged through tributary B in 30 seconds = 28.012 m³/s * 1800 seconds = 50421.6 m³

Answer:

Typically, diesel trucks cost more than those with gas engines, especially when you're first buying them, as diesel is usually featured as an add-on for gas-powered cars. Diesel add-ons can cost over $5,000 for midsize trucks and around $10,000 for heavy-duty trucks.

Explanation:

Make me brain pls

If a one piece parallel joint driveline arrangement with 2 universal joints is used the  working angles of its two U- joints of its angles must be equal and opposite.

The truck driveline is known to be a form of a a less-known and it is one that is known to be a vital aspect of the engine where or which is seen in heavy-duty diesel trucks.

Note that It's a system is made up of all the gears and axles needed to make sure that a truck can move more faster and efficiently.

Hence, If a one piece parallel joint driveline arrangement with 2 universal joints is used the  working angles of its two U- joints of its angles must be equal and opposite.

See full question below

When a one-piece, parallel-joint driveline arrangement with 2 universal joints is used,which of its angles must be equal and opposite?

A) working angles of its two U- joints

B) angles of both mating yokes

C) angle of the transmission output shaft and the axle pinion shaft

D) all of the above

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It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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Creativity and Innovation.

Communication, Innovativeness, knowledge, quality of the product, and motivation...

Given the following data:

Mass of astronaut = 150-lbm.

Acceleration due to gravity on Moon = 5.48 ft/s².

Weight can be defined as the force acting on an object or a physical body due to the effect of gravity. Also, the weight of a physical object (body) is typically measured in Newton or ounces.

Mathematically, the weight force on a physical body can be calculated by using this formula:

W = mg

Where:

Substituting the given parameters into the formula, we have;

Weight = 150 × 1/32.2 × 5.48

Weight = 25.5 lbf.

A beam scale is a measuring instrument that is designed and developed to compare the masses of a physical body and as such, it's not affected by the variations in acceleration due to gravity. Therefore, the beam scale would read 150-lbf as it read on earth.

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Answer:

b. American Society of Mechanical Engineers

Explanation:

The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.

The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.

Answer:

20% of the critical value. Determine (a) the damping factor, (b) the

Explanation:

Complete Question

Complete Question is attached below

Answer:

Option A

Explanation:

From the question we are told that:

inner Diameter of pipe \(d_i=100^c\)

Thickness \(t=50mm\)

Outer diameter of pipe \(d_o=1.1m\)

Length \(l=5m\)

Temperature \(T_i=130^oC\)

Generally the equation for Heat Balance is mathematically given by

\(q*\pi d_oL=mC_p(T_i-T_o)\)

Therefore

\(T_o=T_i+\frac{q*\pi d_oL}{mC_p}\)

\(T_o=130+\frac{100*3.142 *1.1*5}{0.5*4000}\)

\(T_o=129.136^oC\)

Therefore the exit temperature of the water.is \(T_o=129.136^oC\)

Option A

The rate at which steam is produced is equal to 701 kg/hour.

A Boiler may be characterized as a type of device or instrument that significantly transforms water into steam. There are two types of boiler are found. They are water tube boilers and fire tube boilers.

According to the question,

The power generated by combustion, W = 813kW.

The efficiency of the boiler, η = 65% = 0.65.

Temperature, To = 650°C.

Water enters the boiler tubes as a liquid, T1 = 20°C.

Water leaves the tubes as saturated steam, P2 = 20 bar.

The enthalpy of water at 20°C, \(h_1\) = 83.9kJ/kg.

The enthalpy of water at 20 bar pressure, \(h_2\) = 2797.29kJ/kg.

Enthalpy change can be calculated by ΔH = \(h_2-h_1\)

= 2797.29kJ/kg - 83.9kJ/kg = 2713.3 kJ/kg.

The total energy that can be developed can be calculated by the formula:

The mass of the flow rate of the rate at which steam is produced is calculated by the following formula:

             = 528.45 kW/2713.3 kJ/kg.

             = \(\frac{528.45kW }{2713.3kJ/kg} *\frac{3600kJ/h}{1kW}\) = 701 kg/hour.

Therefore, the rate at which steam is produced is equal to 701 kg/hour.

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Answer:

Efficiency is defined as any performance that uses the fewest number of inputs to produce the greatest number of outputs. Simply put, you're efficient if you get more out of less.

Explanation:

Answer:

yes

Explanation:

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When approaching a railroad crossing where the barriers are open, a driver must follow these guidelines:

1. Approach with caution: Even if the barriers are open, it is essential to approach the railroad crossing with caution. Always be prepared for a train to be approaching.

2. Look and listen for trains: Check for any approaching trains by looking both ways along the tracks. Listen for any sounds of an approaching train, such as horns or whistles.

3. Observe warning signs and signals: Pay attention to any warning signs, signals, or flashing lights at the railroad crossing. Follow their instructions and be prepared to stop if necessary.

4. Yield to trains: If a train is approaching or crossing the tracks, always yield the right-of-way to the train. Never try to beat a train or cross the tracks if a train is approaching.

5. Do not stop on the tracks: Make sure not to stop your vehicle on the tracks or too close to the tracks, even if the barriers are open. Leave enough space to ensure your vehicle is clear of the tracks in case the barriers close suddenly.

6. Proceed with caution: If there are no trains approaching and it is safe to do so, proceed across the railroad crossing with caution. Continue to observe for any approaching trains until you have completely cleared the tracks.

Remember, railroad crossings can be dangerous, and it is crucial to exercise caution and follow all safety procedures when approaching and crossing them, regardless of whether the barriers are open or closed.

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When approaching a railroad crossing with open barriers, a driver must exercise caution and be prepared to stop if necessary. They should look for any oncoming trains and proceed only when it is safe to do so.

When approaching a railroad crossing with open barriers, a driver must exercise caution and be prepared to stop if necessary. Even though the barriers are open, it does not guarantee that a train is not approaching. The driver should look both ways for any oncoming trains and only proceed if it is safe to do so.

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The given question is incomplete, the complete question is as follows:

Our text describes a trade-off that we must make as engineers between our confidence in the value of a parameter versus the precision with which we know the value of that parameter. That trade-off might be affected by whether we are looking at a two-sided or bounded (one-sided) interval.

Question: Discuss your interpretation of the confidence-precision trade-off, and provide a few examples of how you might make a choice in one direction or the other in an engineering situation.

Answer: A balancing point is required to be reached to obtain a better confidence level in the predicted values.

Explanation:

The confidence interval and precision are the two terms that aims at providing the accurate estimation of the measurability of an object. If the precision increases, we can compromise on the confidence level and if the confidence level increases, then the precision of the predicted value also dilutes.

Thus a balance point is required to be reached between these two variables so that we get better confidence in the values being predicted without losing the correct estimation on precision. Ensuring that both the confidence and precision are maintained.

The stress at elastic limit is 1.27 N/mm^2, the Young's modulus is 254 N/mm^2, the percentage elongation is 57.5%, the percentage reduction in area is 97.44%, and the ultimate tensile stress is 696.67 N/mm^2.

Stress = Force / Area

Young's modulus = Stress / Strain

Percentage elongation = (extension / gauge length) x 100%

Percentage reduction in area = [(original area - area at neck) / original area] x 100%

Ultimate tensile stress = Maximum load / Area

Diameter of specimen = 100 mm

Gauge length = 100 mm

Extension at 70 KN load = 0.50 mm

Load at elastic limit = 10 KN

Maximum load = 140 KN

Total extension at fracture = 58 mm

Diameter at neck = 16 mm

We can calculate the area of the specimen as follows:

Area = π/4 x d^2

Area = π/4 x (100 mm)^2

Area = 7853.98 mm^2

The stress at elastic limit can be calculated as:

Stress = Load / Area

Stress = 10 KN / 7853.98 mm^2

Stress = 1.27 N/mm^2

The Young's modulus can be calculated as:

Strain = Extension / Gauge length

Strain = 0.50 mm / 100 mm

Strain = 0.005

Stress = Load / Area

Load = Stress x Area

Load = 1.27 N/mm^2 x 7853.98 mm^2

Load = 9982.16 N

Young's modulus = Stress / Strain

Young's modulus = 1.27 N/mm^2 / 0.005

Young's modulus = 254 N/mm^2

The percentage elongation can be calculated as:

Percentage elongation = (extension / gauge length) x 100%

Percentage elongation = (58 mm - 0.50 mm) / 100 mm x 100%

Percentage elongation = 57.5%

The percentage reduction in area can be calculated as:

Original area = π/4 x (100 mm)^2 = 7853.98 mm^2

Area at neck = π/4 x (16 mm)^2 = 201.06 mm^2

Percentage reduction in area = [(original area - area at neck) / original area] x 100%

Percentage reduction in area = [(7853.98 mm^2 - 201.06 mm^2) / 7853.98 mm^2] x 100%

Percentage reduction in area = 97.44%

The ultimate tensile stress can be calculated as:

Area at neck = π/4 x (16 mm)^2 = 201.06 mm^2

Ultimate tensile stress = Maximum load / Area

Ultimate tensile stress = 140 KN / 201.06 mm^2

Ultimate tensile stress = 696.67 N/mm^2

Therefore, the stress at elastic limit is 1.27 N/mm^2, the Young's modulus is 254 N/mm^2, the percentage elongation is 57.5%, the percentage reduction in area is 97.44%, and the ultimate tensile stress is 696.67 N/mm^2.

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1. (a) The combinational circuit to convert a 4-bit binary number to gray code can be designed using standard logic gates, a decoder, an 8-to-1 multiplexer, or a 4-to-1 multiplexer.

2. The Boolean expression of the output of an 8-to-1 multiplexer with inputs connected as described is to be determined.

3. An 8-bit magnitude comparator can be designed using 4-bit comparators and other gates.

4. The Boolean function F(A, B, C, D) = (1, 3, 4, 11, 12, 13, 15) can be implemented using a decoder and external gates or an 8-to-1 multiplexer and external gates.

1. (a) The 4-bit binary to gray code conversion can be achieved by using standard logic gates, which include AND, XOR, and NOT gates, to manipulate the input bits according to the gray code conversion algorithm. Alternatively, a decoder can be used to decode the 4-bit binary input and then a combination of XOR and AND gates can be used to convert the decoded outputs into gray code. Another approach is to use an 8-to-1 multiplexer, where the binary input is connected to the data inputs of the multiplexer and the selection lines are connected to a gray code table. Similarly, a 4-to-1 multiplexer can be used with appropriate connections to convert the binary number to gray code.

2. The Boolean expression of the output of the 8-to-1 multiplexer can be determined based on the given connections. The selection lines S₂, S₁, and So correspond to inputs A, B, and C, respectively. The data inputs I₁, I₂, 17, 13, 15, 10, 14, and l6 correspond to the values 0, 1, 1, 0, 1, D, D, and D' respectively. By analyzing these connections, the Boolean expression of the MUX output can be derived.

3. To design an 8-bit magnitude comparator, we can use 4-bit comparators to compare each corresponding pair of bits in the two 8-bit numbers. The outputs of the 4-bit comparators can then be combined using additional logic gates to obtain the final result, which indicates whether the two 8-bit numbers are equal, greater than, or less than each other.

4. The Boolean function F(A, B, C, D) = (1, 3, 4, 11, 12, 13, 15) can be implemented using a decoder and external gates. The inputs A, B, C, and D can be connected to the inputs of the decoder, and the outputs of the decoder corresponding to the given function values can be connected to the external gates to obtain the desired function. Alternatively, the function can be implemented using an 8-to-1 multiplexer, where the inputs A, B, C, and D are connected to the selection lines of the multiplexer, and the data inputs of the multiplexer are set according to the given function values. The output of the multiplexer will then represent the Boolean function.

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Answer:

Beam of 25" depth and 12" width is sufficient.

I've attached a detailed section of the beam.

Explanation:

We are given;

Beam Span; L = 20 ft

Dead load; DL = 0.50 k/ft

Live load; LL = 0.65 k/ft.

Beam width; b = 12 inches

From ACI code, ultimate load is given as;

W_u = 1.2DL + 1.6LL

Thus;

W_u = 1.2(0.5) + 1.6(0.65)

W_u = 1.64 k/ft

Now, ultimate moment is given by the formula;

M_u = (W_u × L²)/8

M_u = (1.64 × 20²)/8

M_u = 82 k-ft

Since span is 20 ft, it's a bit larger than the average span beams, thus, let's try a depth of d = 25 inches.

Effective depth of a beam is given by the formula;

d_eff = d - clear cover - stirrup diameter - ½Main bar diameter

Now, let's adopt the following;

Clear cover = 1.5"

Stirrup diameter = 0.5"

Main bar diameter = 1"

Thus;

d_eff = 25" - 1.5" - 0.5" - ½(1")

d_eff = 22.5"

Now, let's find steel ratio(ρ) ;

ρ = Total A_s/(b × d_eff)

Now, A_s = ½ × area of main diameter bar

Thus, A_s = ½ × π × 1² = 0.785 in²

Let's use Nominal number of 3 bars as our main diameter bars.

Thus, total A_s = 3 × 0.785

Total A_s = 2.355 in²

Hence;

ρ = 2.355/(22.5 × 12)

ρ = 0.008722

Design moment Capacity is given;

M_n = Φ * ρ * Fy * b * d²[1 – (0.59ρfy/fc’)]/12

Φ is 0.9

f’c = 4,000 psi = 4 kpsi

fy = 60,000 psi = 60 kpsi

M_n = 0.9 × 0.008722 × 60 × 12 × 22.5²[1 - (0.59 × 0.008722 × 60/4)]/12

M_n = 220.03 k-ft

Thus: M_n > M_u

Thus, the beam of 25" depth and 12" width is sufficient.

it is undesirable that all of the points should fall extremely near, or exactly on, the centerline of the control chart Because:

If a data point falls is said to outside the control limits, we can say that the process is said to be out of one's control and it is good that an investigation is done to ascertain and remove the cause or causes.

So, it is undesirable that all of the points should fall extremely near, or exactly on, the centerline of the control chart Because:

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Answer:

Hello your question is incomplete attached below is the complete question

answer :

I) P = t/R * 492.85

II) The final equation : PR / t  + 4M/πR3 =  б e

Explanation:

attached below is a detailed solution to the given problem

i) P = t/R * 492.85

ii) Final equation : PR / t  + 4M/πR3 = б e

The most common type of virtual private network (VPN) is the remote access VPN.

This type of VPN is commonly used by employees who need to access their company's network from a remote location. It is also popular among individuals who want to access content that is restricted in their region or country. Remote access VPNs use encryption and authentication protocols to ensure data privacy and security.

A remote access VPN allows individual users to establish secure connections with a remote computer network. Users can access the network as if they were directly connected to the network's servers. This type of VPN is commonly used by businesses to allow employees to access corporate resources securely from remote locations.

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The following statement of the document is false.

What do you mean by document?

A document is a written, drawn, presented, or documented statement of ideas that frequently includes both non-fictional and fictitious content. The term comes from the Latin Documentum, which means "teaching" or "lesson": the verb doce means "to teach." Historically, the term was used to refer to written proof that may be used as evidence of a truth or reality. "Document" in the computer age usually refers to a mostly textual computer file, including its structure and format, such as fonts, colours, and graphics. Given the existence of electronic documents, the term "document" is no longer defined by its transmission medium, such as paper.

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Answer:

A.) Time = 17.13 seconds

B.) Distance = 31.9 m

C.) V = 11.18 m/s

D.) V = 7.1 m/s

Explanation:

The initial velocity U of the automobile is 15.65 m/s.

 At the instant that the two vehicles are abreast of each other, the police car starts to pursue the automobile with initial velocity U = 0 at a constant acceleration of 1.96 m/s². Because the police is starting from rest.

For the automobile, let us use first equation of motion

V = U - at.

Acceleration a is negative since it is decelerating with a = 3.05 m/s² . And

V = 0.

Substitute U and a into the formula

0 = 15.65 - 3.05t

15.65 = 3.05t

t = 15.65/3.05

t = 5.13 seconds

But the motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s².

The total time required for the police car to overtake the automobile will be

12 + 5.13 = 17.13 seconds.

b.) Using the third equation of motion formula for the police car at V = 11.18 m/s and a = 1.96 m/s²

V^2 = U^2 + 2aS

Where S = distance travelled.

Substitute V and a into the formula

11.18^2 = 0 + 2 × 1.96 ×S

124.99 = 3.92S

S = 124.99/3.92

S = 31.88 m

c.) The speed of the police car at the time it overtakes the automobile will be in line with the speed zone which is 11.18 m/s

d.) That will be the final velocity V of the automobile car.

We will use third equation of motion to solve that.

V^2 = U^2 + 2as

V^2 = 15.65^2 - 2 × 3.05 × 31.88

V^2 = 244.9225 - 194.468

V = sqrt( 50.4545)

V = 7.1 m/s

In Excel, to build a dashboard we need to add a tab and label it as Dashboard. Then, we set a gray background and copy-paste the three pivot charts we have built in the previous steps. Also, we insert slicers for Employee Last Name and Region.

We ensure these slicers dynamically interact with all three charts by selecting each slicer, right mouse clicking, choosing report connections, and selecting the appropriate check boxes. Finally, we test the dashboard to ensure that all of the charts interact with the slicers and when we drill down into the region and employee last names we see the corresponding pivot tables dynamically update as well.The steps to build a dashboard in Excel are as follows:

Step 1: Add a tab and label it as Dashboard

Step 2: Set the gray background

Step 3: Copy-paste the three pivot charts we have built in the previous steps

Step 4: Insert slicers for Employee Last Name and Region

Step 5: Ensure these slicers dynamically interact with all three charts by selecting each slicer, right mouse clicking, choosing report connections and selecting the appropriate check boxes

Step 6: Test the dashboard to ensure that all of the charts interact with the slicers

Step 7: When we drill down into the region and employee last names we see the corresponding pivot tables dynamically update as well.To create a dynamic dashboard, it is important to choose the correct chart types, slicers, and chart sizes and locations. Slicers are used to filter the data in the pivot tables and charts. Charts in Excel can be easily resized, formatted, and customized to make it more attractive and informative to users.To ensure that all of the charts interact with the slicers, we should select each slicer and check if the charts are changing accordingly. Finally, we need to test the dashboard to ensure that it is working as expected.

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