The equation for the magnitude of the angular acceleration α is α = rF / (3mR^2) where r represents the radius of the spheres, F is the applied force, m is the mass of each sphere, and R is the distance between the center of the cylinder and the center of each sphere.
This equation is derived from the rotational dynamics of the system. The torque τ exerted by the force F is given by τ = rF, where r is the lever arm or radius at which the force is applied. The moment of inertia I of the system is given by I = 2mR^2, considering the two spheres of mass m and distance R.
Using Newton's second law for rotational motion, τ = Iα, and substituting the values, we get rF = 2mR^2 α. Solving for α, we find α = rF / (2mR^2). However, since there are two spheres, we divide by 2 to obtain α = rF / (3mR^2), as stated in the given equation.
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According to the lab manual, what information does the computer need to determine the ball’s speed at the laser gate? a. the time the laser gate is blocked by the ball b. the time between pressing "d" and the ball passing through the gate c. the diameter of the ball d. Answers a and c. 10.
The main answer is that the computer needs two pieces of information in order to determine the ball’s speed at the laser gate: the time the laser gate is blocked by the ball and the diameter of the ball. (D)
This is due to the fact that the speed of the ball is directly proportional to the time it takes for the ball to pass through the laser gate, and inversely proportional to the diameter of the ball. In other words, the smaller the diameter of the ball, the faster it will travel in a given time interval.
Thus, by measuring the time it takes for the ball to pass through the laser gate and its diameter, the computer can accurately calculate the speed of the ball.
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A man does 4,335 J of work in the process of pushing his 2.80 103 kg truck from rest to a speed of v, over a distance of 27.5 m. Neglecting friction between truck and road, determine the following. (a) the speed v m/s (b) the horizontal force exerted on the truck N
The speed of the truck is approximately 8.42 m/s. The horizontal force exerted on the truck is approximately 157.64 N.
(a) The work-energy principle relates the work done on an object to its change in kinetic energy. Since the truck starts from rest, the work done on it equals its final kinetic energy:
W = \((1/2)mv^2\)
Solving for v, we get:
v = \(sqrt(2W/m) = sqrt(2(4,335 J)/(2.80 x 10^3 kg)) ≈ 8.42 m/s\)
Therefore, the speed of the truck is approximately 8.42 m/s.
(b) The horizontal force exerted on the truck can be found using the formula for work:
W = Fx
where F is the force exerted on the truck and x is the distance over which the force is applied. Rearranging this equation, we get:
F = W/x = (4,335 J)/(27.5 m) ≈ 157.64 N
Therefore, the horizontal force exerted on the truck is approximately 157.64 N.
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in 1923, the united states army (there was no united states air force at that time) set a record for in-flight refueling of airplanes. using two refueling planes, an airco dh-4b biplane was able to remain in flight for 37 h37 h . during the flight, the refueling planes were able to air-transfer a total of 687687 gallons of fuel to the plane in 99 refueling transfers. assume that the refueling nozzle had a diameter of 1.75 in1.75 in and each refueling took 2.41 min 2.41 min to perform. calculate the velocity of the fuel through the nozzle. assume that the fuel filled the entire cross-sectional area of the nozzle.
The velocity of fuel through the nozzle is "1.09 m/s".
The flow speed of fuel can be found using the formula for the volume flow rate of fuel:
V/t = Av
V = Avt
v = At/V
where,
v = volume flow speed = ?
A = cross-sectional area = π(radius)² = π(1.75/2 in)² = 2.40 m²
t = time taken for refueling = (9)(2.41 min) = 21.69 min = 1301 s
V = Volume of fuel transferred = (687 gallons) = 2.6 m³
Therefore,
we can find the velocity of volume flow by
v= (2.40 * 1301)/2.6
v= 3122.4/2.6
v = 1200.9
velocity of volume flow = 1200.9 m/s
Therefore, the velocity of the volume flow of fuel through the entire cross-sectional area of the nozzle is 1200.9 m/s.
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hey pls help with this HDJSJDH im rlly bad at this kinda stuff :,) i'll mark the correct answer brainliest
Answer:
A. Cue, White Ball, Blue Ball
Explanation:
Visualize in which order things are being hit
determine the overall charge on each complex ion. tetrachloridocuprate(ii) ion:
The overall charge on the tetrachloridocuprate(II) ion is 2-.
In different wording: What is the net charge on the tetrachloridocuprate(II) ion?The tetrachloridocuprate(II) ion, also known as CuCl4^2-, consists of a central copper atom (Cu) coordinated to four chloride ions (Cl-) in a tetrahedral arrangement. Each chloride ion carries a charge of -1, resulting in a total negative charge of -4 contributed by the chloride ligands. Since the overall charge of the tetrachloridocuprate(II) ion is 2-, it means the copper ion must have a charge of +2 to balance the negative charges from the chloride ions. This indicates that the copper ion has lost two electrons to achieve stability and form the complex ion.
Complex ions: Complex ions are formed when a central metal atom or ion is surrounded by ligands, which are usually ions or molecules that donate electrons to the metal. The overall charge on a complex ion is determined by balancing the charges of the ligands with the charge of the central metal atom or ion.
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How does a balanced Chemical Equation Satisfy the Law of Conservation of Mass?
A. During a chemical reaction, the total amount of matter stays the same.
b. During a chemical reaction, matter is destroyed.
c. During a Chemical reaction, one ore more new substances formed.
d. During a chemical reaction, the total number of atoms increases.
Please help I'll mark brainliest
a body dropped from a height reaches a velocity of 13m/s just before touching the ground. What is the initial height of the ball and the time of height
Hi there!
We can use the following (derived) equation to solve for the final velocity given height:
vf = √2gh
We can rearrange to solve for height:
vf² = 2gh
vf²/2g = h
Plug in the given values (g = 9.81 m/s²)
(13)²/2(9.81) = 8.614 m
We can calculate time using the equation:
vf = vi + at, where:
vi = initial velocity (since dropped from rest, = 0 m/s)
a = acceleration (in this instance, due to gravity)
Plug in values:
13 = at
13/a = t
13/9.81 = 1.325 sec
3.
The drawing shows a collision between two pucks on an air-hockey table. Puck A has a
mass of 0.025 kg and is moving along the x axis with a velocity of +5.5 m/s. It makes a
collision with puck B, which has a mass of 0.050 kg and is initially at rest. The collision is
not head-on. After the collision the two pucks fly apart with the angles shown in the
drawing. Find the final speed of (a) puck A and (b) puck B. (Cutnell 7.30) 3.4 m/s, 2.6 m/s
+5.50
The final speed of puck A is 1.8 m/s and the final speed of puck B is 3.7 m/s.
Conservation of linear momentum
The final speed of the pucks is determined by applying the principle of conservation of linear momentum.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.025(5.5) + 0.05(0) = 0.025v₁ + 0.05v₂
0.1375 = 0.025v₁ + 0.05v₂
One direction linear velocityu₁ + v₁ = u₂ + v₂
5.5 + v₁ = 0 + v₂
v₁ = v₂ - 5.5
0.1375 = 0.025(v₂ - 5.5) + 0.05v₂
0.1375 = 0.025v₂ - 0.1375 + 0.05v₂
0.275 = 0.075v₂
v₂ = 0.275/0.075
v₂ = 3.7 m/s
v₁ = 3.7 - 5.5
v₁ = -1.8 m/s
Thus, the final speed of puck A is 1.8 m/s and the final speed of puck B is 3.7 m/s.
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in which of the following galaxies would you expect to find old stars and no young stars? (1) large magellanic cloud (2) andromeda galaxy (m31) (3) m87 group of answer choices (1) and (2) only (2) only (1) only (3) only (1), (2), and (3)
Answer: You would expect to find old stars and no young stars in the M87 galaxy, as it is a giant elliptical galaxy that is known to have a population of old stars. Therefore, the correct answer is (3) only M87.
The Large Magellanic Cloud (LMC) and Andromeda Galaxy (M31) are both spiral galaxies that are actively forming new stars, so you would expect to find a mixture of old and young stars in these galaxies.
3x+5=40 solve for x to get the answer.
This is question isnt real i just need to talk
with someone
Explanation:
3x=40-5
3x=35
x=35/3
x=11.66 or x=11 2/3
An ideal gas expands isothermally performing 4.30 x 10³ of work in the process. Calculate (a)
the change in internal energy of the gas, and (b) the heat absorbed during this expansion.
Answer:
The solution of the given query is explained below in the explanation portion.
Explanation:
Given value is:
Work,
⇒ \(W=4.30\times 10^3 \ J\)
(a)
The change in the internal energy will be:
⇒ \(\Delta V=\frac{3}{2}nR(\Delta T)\)
Throughout the isothermal procedure, The temperature will be constant "ΔT = 0".
then,
⇒ \(\Delta V = \frac{3}{2}nR(0)\)
⇒ \(\Delta V = 0 \ J\)
(b)
As we know,
⇒ \(\Delta V = Q-W\)
On substituting the value, we get
⇒ \(0=Q-W\)
On adding W both sides, we get
⇒ \(W=Q-W+W\)
⇒ \(W=Q\)
On substituting the given value of "W", we get
⇒ \(Q=4.30\times 10^3 \ J\)
If 60 Joules are used to raise a 15 N object, how high is the object raised?
Please help
Answer:
W = 60 J
F = 15 N
s = ?
W = Fs
s = W / F
s = 60 / 15
s = 4 m
When the height of the cylinder increased by a factor of 5, from 100 m to 500 m, what happened to the cylinder’s gravitational potential energy?
Answer: It increased by a factor of 5
Explanation:
Gravitational potential energy is given by the following formula:
during a sunrise the sun appears to rise up from the horzion why does this happen
It doesn't rise and set. But it appears to rise and set because of the Earth's rotation on its axis. As the Earth rotates toward the east, it looks like the sun is moving west. As the Earth rotates, different locations on Earth pass through the sun's light.
It doesn't rise and set. But it appears to rise and set because of the Earth's rotation on its axis. ... As the Earth rotates toward the east, it looks like the sun is moving west. As the Earth rotates, different locations on Earth pass through the sun's light
Which of the following statements helps support the endosymbiotic theory?
Choose 1 answer:
(Choice A) A The Golgi body is a membrane-bound organelle within eukaryotes that was once a free-living prokaryote.
(Choice B) B If isolated from a eukaryotic cell, mitochondria can survive and reproduce on their own.
(Choice C) C Both mitochondria and chloroplasts have their own DNA that is different from the nuclear DNA of the larger host cell.
(Choice D) D The lysosome is a membrane-bound organelle within eukaryotes that was once a free-living prokaryote.
Answer:
C
Explanation:
Both mitochondria and chloroplasts have their own DNA that is different from the nuclear DNA of the larger host cell.
Mitochondrial DNA (mtDNA) and chloroplast DNA (cpDNA) actually more closely resemble the structure of prokaryotic DNA (circular) as compared to the structure of eukaryotic DNA (linear).
The endosymbiotic theory proposes that mitochondria and chloroplast were once independent prokaryotic organisms that survived endocytosis by an early eukaryotic cell.
The statement "both mitochondria and chloroplasts have their own DNA that is different from the nuclear DNA of the larger host cell" helps support the endosymbiotic theory (Option C).The lines of evidence that support the endosymbiotic theory include:
Both mitochondria and chloroplasts have their own circular DNA and divide by binary fission.Both mitochondria and chloroplasts have their own bacteria-like ribosomes (70 S).Both mitochondria and chloroplasts have a similar size as prokaryotic cells.In conclusion, the statement "both mitochondria and chloroplasts have their own DNA that is different from the nuclear DNA of the larger host cell" helps support the endosymbiotic theory (Option C).
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A barber wants to set up a salon in a room measuring length 3m by 3m he has a simple wooden chair,three large mirrors & a bulb. Using the knowledge of shadows & reflection advise the barber on how to arrenge a good saloon using the only items he has
Here are some ideas for setting up the barber's salon based on the size of the space and the products available: The wooden chair should be positioned in the middle of the space, facing a wall.
The barber's workspace will be this. The room's other three walls should be covered with the three enormous mirrors. This will give the impression that there is more space present and enlarge the room. The mirrors should be angled to reflect both the client in the chair and the barber's work area. Over the chair, suspend the lightbulb from the ceiling. The barber salon will be able to operate in enough lighting thanks to this.The wooden chair should be positioned in the middle of the space, The barber can set up a white sheet or a reflecting surface to improve illumination even further.
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What type of adaptations involve chemical changes in body systems?
Answer:
Physiological adaptations are biochemical and metabolic changes in the cells of an organism, such as the development of poison in some plant species that protect the plant from environmental predators. Behavioral adaptations are adaptations in the behavior of an organism.
anyone know the answer?
Answer:
closed
Explanation:
sorry if I'm wrong
Write three laws of refraction by a lens.
Answer:
1.The incident Ray,the refracted Ray and the normal at the point of incidence,all three lies in the same plane
2.the ratio of sine of angle of incidence to the sine of angle of refraction is constant for a pair
16. Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10^24 kg, the mass of Jupiter is 1898.6 x 10^24 kg and the closest distance is abou
The gravitational force of attraction between the Earth and Jupiter is approximately 1.32 x 10²⁸ N.
The gravitational force of attraction between two objects can be calculated using Newton's law of universal gravitation, which states that the force (F) is proportional to the product of their masses (m₁ and m₂) and inversely proportional to the square of the distance (r) between their centers. Mathematically, the formula is expressed as:
F = (G * m₁ * m₂) / r²
where G is the gravitational constant.
m₁ = 6 x 10²⁴ kg (mass of Earth)
m₂ = 1898.6 x 10²⁴ kg (mass of Jupiter)
r = 5.88 x 10¹¹ m (distance between Earth and Jupiter)
Plugging in the values into the formula, we have:
F = (6.67 x 10⁻¹¹ N m²/kg²) * (6 x 10²⁴ kg) * (1898.6 x 10²⁴ kg) / (5.88 x 10¹¹ m)²
Calculating the expression, we find:
F ≈ 1.32 x 10²⁸ N
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THE COMPLETE QUESTION IS:
Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10²⁴ kg the mass of Jupiter is 1898.6 x 10²⁴ kg and the closest distance is about 5.88 x 10¹¹
A car covers 72 kilometers in the first hour of its journey. In the next hour, it covers 90 kilometers. What is the amount of work done by the car? The total mass of the car, including its passengers, is 2. 5 Ă— 103 kilograms. A. 2. 8 Ă— 105 joules B. 4. 0 Ă— 105 joules C. 5. 1 Ă— 105 joules D. 2. 8 Ă— 106 joules E. 2. 8 Ă— 107 joules.
The work done by the car at the given mass and speed is \(3.1 \times 10^5 \ J\)
The given parameters;
First distance traveled by the car, s = 72 kmSecond distance traveled, = 90 kmTotal time of motion, t = 2 hoursTotal mass = 2.5 x 10³ kgThe initial velocity of the car, u = 72 km/h = 20 m/s
The final velocity of the car, v = 90 km/h = 25 m/s
The acceleration of the car is calculated as follows;
\(a = \frac{\Delta v}{\Delta t} \\\\a = \frac{v- u}{t_2 - t_1} \\\\\)
the initial time of motion, t₁ = 1 hour = 3600 s
the second time of motion, t₂ = 1 hour + 1 hour = 2 hours = 7200 s
\(a = \frac{25-20}{7200 - 3600} \\\\a = 0.00138 \ m/s^2\)
The force exerted by the car is calculated as follows;
\(F = ma\\\\F = (2.5 \times 10^3) \times 0.00138 \\\\F = 3.45 \ N\)
The work done by the car is calculated as follows;
\(W = F\times s\)
where;
s is the displacement of the car\(s = (72 - 0) \ k m \ + \ (90 - 72) \ km\\\\s = 90 \ km = 90,000 \ m\)
\(W = 3.45 \times 90,000 \\\\W = 3.1 \times 10^5 \ J\)
Thus, the work done by the car at the given mass and speed is \(3.1 \times 10^5 \ J\).
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How deep is the floor of the ocean if a sonar sound takes 7 seconds to return back to the ship?
What are three ways in which people use microwaves?
Answer:
Sample Response: They are used to transmit data, TV signals, and telephone signals. They are also used in ovens and radar.
Explanation:
Which statement should he place in the region marked X?
Explanation:
The answer is Electrons move between objects.
After Punch Taut travels to Pentune, what actually happens to his mass and his weight?
After Punch Taut travels to Pentune, his mass remains the same as it is a measure of the amount of matter in his body which does not change with a change in location.
However, his weight will change as it is the measure of the gravitational force acting on his mass. The weight of Punch Taut will be different on Pentune compared to his weight on his previous location due to differences in the gravitational pull of the two locations. However, his weight changes because weight depends on both mass and the gravitational force acting on the object. If Pentune has a different gravitational force than Punch Taut's previous location, his weight will be affected accordingly.
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According to current scientific understanding, the idea that the milky way galaxy might be home to a civilization millions of years more advanced than ours is.
According to contemporary scientific understanding, the thought that the Milky Way Galaxy energy is home to a civilization millions of years more developed than ours is. one reasonable solution to Fermi's paradox.
What is the milky way galaxy?Our Milky Way galaxy is simply one of the billions of galaxies in the universe. Within it, there are at smallest 100 billion stars, and on moderate, each star contains at least one planet circling it. This means there are potentially thousands of planetary procedures like our solar system within the galaxy!The Milky Way gets its name from a Greek myth about the goddess Hera who sprayed milk across the sky. In other parts of the world, our galaxy goes by different names.The Milky Way is about we look. Up, down, left, right, that is the Milky Way. From Earth, it can be noticed as a hazy form of stars in the evening sky that the stripped eye can barely notice. You can visit the Milky Way all year, no matter where you are on the earth.To learn more about Milky Way galaxy, refer to:
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Consider a bullet of mass \( 10 \mathrm{~g} \) travelling with \( 100 \mathrm{~m} / \mathrm{s} \) which hits a ballistic pendulum of mass \( 990 \mathrm{~g} \). In the aftermath, approximately how hig
The ballistic pendulum reaches a maximum height of approximately 0.102 m after the collision.
The bullet of mass 10 g and velocity 100 m/s collides with the ballistic pendulum of mass 990 g.
To find the maximum height the pendulum reaches after the collision, we can use the principle of conservation of momentum and conservation of energy.
First, we need to find the velocity of the bullet and pendulum after the collision. Using conservation of momentum, we can write:
\(\( m cot bullet}} + m_{\text{pendulum}} \cdot v_{\text{pendulum}} = (m_{\text{bullet}} + m_{\text{pendulum}}) \cdot v_{\text{after}} \)\)
Substituting the given values, we have:
\(\( 0.01 \, \text{kg} \cdot 100 \, \text{m/s} + 0.99 \, \text{kg} \cdot 0 \, \text{m/s} = (0.01 \, \text{kg} + 0.99 \, \text{kg}) \cdot v_{\text{after}} \)\)
Simplifying, we find that the velocity of the bullet and pendulum after the collision is \( 1 \, \text{m/s} \).
Next, we can use the conservation of energy to find the maximum height the pendulum reaches. The initial kinetic energy of the system is equal to the potential energy at maximum height.
Since the system is initially at rest, the initial kinetic energy is zero. The potential energy at maximum height can be written as:
\(\( m_{\text{pendulum}} \cdot g \cdot h = 0.99 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 \cdot h \)\)
Setting this equal to zero, we can solve for the maximum height h.
Simplifying, we find that the maximum height is approximately 0.102m
In conclusion, the ballistic pendulum reaches a maximum height of approximately 0.102 m after the collision.
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who coined the term psychophysics
The term "psychophysics" was coined by German psychologist and philosopher Gustav Fechner in the mid-19th century.
He introduced the concept in the mid-19th century as a way to quantify and study the relationship between physical stimuli and their psychological effects. Fechner is considered to be the founder of psychophysics, and his work laid the foundation for the development of this field of study. Psychophysics aims to understand the perception of stimuli and how it is related to the physical properties of the stimuli, such as their intensity, duration, and frequency. Psychophysics is a subfield of psychology that deals with the relationship between physical stimuli and their psychological effects. It aims to quantify the relationship between the physical properties of stimuli, such as intensity, duration, and frequency, and the subjective experiences of those stimuli, such as sensation, perception, and response.
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a ball is shot from the ground straight up into the air with initial velocity of 46 46 ft/sec. assuming that the air resistance can be ignored, how high does it go?
The ball may fly up to a height of 27.56 feet. A ball is thrown up into the air, yet although though it rises into the air, the direction and velocity of the ball are actually downward.
As it rises, the ball's speed slows until the very apex of its motion, where it briefly pauses. At the peak, it accelerates at -9.8 m/s2.
the settings provided.
initial ball velocity (u) = 42 ft/s initial ball acceleration (a) = 32 ft/s2
The following formula is used to determine the ball's highest possible height:
v² = u²- 2gh
where;
When the ball is at its highest point, its velocity is zero.
0 = u² - 2gh
2gh = u²
The ball can therefore go a maximum height of 27.56 feet.
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