Two magnets are held apart. Once released, the south pole of one magnet moves toward the north pole of another magnet until the magnets collide. How does the graph reflect the changes in energy that occur?

(1 point)

Kinetic energy is at its peak when the magnets are first released, then it decreases steadily. Energy stored in the magnetic field becomes zero.

The kinetic energy of the system is derived from the thermal energy created by increased velocity. Energy stored in the magnetic field does not change.

Answer:

kinetic energy = 1/2 x mass x velocty^2

1/2(12)(10^2)

600 N

hope that answers your question

Explanation:

The suitcase is dragged for 2.10 meters before it is riding smoothly on the belt.

To calculate the distance the suitcase is dragged before it is riding smoothly on the belt, we can use the equations of motion and the coefficients of static and kinetic friction. The force of friction acting on the suitcase can be found by multiplying the coefficient of static friction by the weight of the suitcase (F_s = μ_s * m * g). The maximum force of static friction that can act on the suitcase before it starts moving can be found by multiplying the coefficient of static friction by the normal force (F_s ,max = μ_s * m * g). Since the force of gravity acting on the suitcase is balanced by the normal force, we can equate the maximum force of static friction with the force of gravity (F_ s, max = F_ g). Once the suitcase starts moving, the force of friction becomes kinetic and is given by F_ k = μ_k * m * g. Using the equations of motion and the given parameters, we can find that the distance the suitcase is dragged before it is riding smoothly on the belt is 2.10 meters.

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The force of attraction between two bodies is 6.67×10⁻⁷N. This force will remain same for the two bodies whether they are on the earth or on the moon.

Given that,

mass of two bodies each= 100kg

distance between them= 1m

We know that,

\(F= G\)×\(\frac{M1 M2}{R^{2} }\)

Where, F=force

M1= mass of one body

M2= mass of another body

G= gravitational force [6.67×10⁻¹¹]

R= distance between the two bodies

Substituting the given values, we have

F= 6.67×10⁻¹¹×\(\frac{10000}{1^{2} }\)N

 = 6.67×10⁻⁷N

As per Newton's law of gravitation, the force of attraction between two bodies is proportional to the product of the individual masses of the two bodies and inversely proportional to the square of the distance between them. This force will remain same for the two bodies whether they are on the earth or on the moon.

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Answer:

the force is very strong between

You'll See After You Have an Answer!

Explanation:

For instance, on my answer, you'll see a button presenting the words "Mark Brainliest"

Answer: 14 centimeters

Explanation: she walks 4 units east, 6 units up, then 4 units west. If each unit is 1 centimeter that is 16 centimeters.

OPTION  B IS THE ANSWER

Answer:

The real answer is A 2023 answer -_-

Explanation:

Answer: A raindrop

Explanation:

It would be a raindrop depending on if the ship is moving or not. If the ship is not moving, then the raindrop would have more momentum. But, if the ship were moving, then it would have more momentum. Because momentum equals mass times velocity.

Answer:

A

Explanation:

magnifying = enlarging something or making it seem bigger

Answer:

Approximately \(33\; {\rm m\cdot s^{-2}}\).

Approximately \(55\; {\rm m\cdot s^{-2}}\).

(Assume that the table is level, and that the \(60\; {\rm N}\) force is horizontal.)

Explanation:

Consider all three blocks as one object of mass \(m = (1 + 4 + 6)\; {\rm kg} = 11\; {\rm kg}\). Among all the forces that are in action, the only unbalanced external force on this \(m = 11\; {\rm kg}\) object will be the \(60\; {\rm N}\) force. Hence, the resultant force of this combined object of mass \(m = 11\; {\rm kg}\) will be \(F_{\text{net}} = 60\; {\rm N}\).

Acceleration \(a\) of this combined object will be:
\(\begin{aligned}a &= \frac{F_{\text{net}}}{m} \\ &= \frac{60\; {\rm N}}{11\; {\rm kg}} \\ &= \frac{60}{11}\; {\rm m\cdot s^{-2}}\end{aligned}\).

Since the three crate blocks are moving together, each will have the same acceleration, \(a = (60/11)\; {\rm m\cdot s^{-2}}\).

Resultant force on each of the crate blocks will be:

Assume that the \(60\; {\rm N}\) external force on the \(1\; {\rm kg}\) block points to the right.

When the crates are considered individually, external forces on the \(1\; {\rm kg}\) crate will include:

Since these two forces are in opposite directions, the resultant force on this \(1\; {\rm kg}\) block will be \((60\; {\rm N} - x\; {\rm N})\). However, since the actual resultant force on this block (calculated from acceleration) is \((60 / 11)\; {\rm N}\):

\(\displaystyle 60\; {\rm N} - x\; {\rm N} = \frac{60}{11}\; {\rm N}\).

Therefore, the force that the \(4\; {\rm kg}\) block exerts on the \(1\; {\rm kg}\) block will be

\(\displaystyle 60\; {\rm N} - \frac{60}{11}\; {\rm N} = \frac{600}{11}\; {\rm N} \approx 55\; {\rm N}\).

When considered individually, the only unbalanced external force on the \(m = 6\; {\rm kg}\) block is the normal force from the \(4\; {\rm kg}\) block. Hence, this force will be equal to the resultant force on the \(m = 6\; {\rm kg}\) block, \((360 / 11)\; {\rm N} \approx 33\; {\rm N}\).

The direction of the magnetic force on a charged particle moving through a magnetic field is given by the right-hand rule.

If we point the fingers of our right hand in the direction of the particle's velocity (ty-direction), and then curl them toward the direction of the magnetic field (+x-direction) so that they are perpendicular to both the velocity and the field, then our thumb will point in the direction of the magnetic force.

In this case, if the proton is moving in the ty-direction (i.e., the positive y-direction), and the magnetic field is pointing in the +x-direction (i.e., the positive x-direction), then the magnetic force will be directed in the -z-direction (i.e., the negative z-direction).

Therefore, the direction of the magnetic force on the proton is in the negative z-direction.

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(1) The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is 8,000 m/s² east.

(2) The magnitude of the average force the Bat exerts on the ball while they are in contact is 1,120 N.

The given parameters:

The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is calculated as follows:

\(a = \frac{v- u}{t} \\\\a = \frac{35 - (-45)}{0.01} \\\\a = \frac{80}{0.01} \\\\a = 8,000 \ m/s^2\)

The magnitude of the average force the Bat exerts on the ball while they are in contact is calculated as follows;

\(F = ma\\\\F = 0.14 \times 8,000\\\\F = 1,120 \ N\)

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The moment of inertia of this combination about an axis perpendicular to the bar and through one of the balls is 5.71 kgm².

The moment of inertia is a measure of how resistant an object is to changes in its rotational motion.

The moment of inertia of any object is obtained from the product of mass and square of radius of the object.

Mathematically, the moment of inertia of the rod and the points masses is calculated by apply the following equation.

I = ¹/₁₂ML²  +  2m(L/₂)²

where;

The moment of inertia of this combination about an axis perpendicular to the bar and through one of the balls is calculated as follows;

I = ¹/₁₂(2.6)(3.5)²  +  2(0.5)(3.5/₂)²

I = 2.65 + 3.0625

I = 5.71 kgm²

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Answer:

1.5024

Explanation:

Draw a diagram. Put the two cells in series. Now draw 3 resistors. Two of them equal 0.26 ohms each. The third one is the lightbulb which is 12 ohms.

R = 0.26 + 0.26 + 12 = 12.52

The bulb has a voltage of 2.88 volts across it. You can get the current from that.

i = E / R

i = 2.88 / 12 =

i = 0.24 amps.

Now you can get the voltage drop across the two cells.

E = ?

R = 0.26

i = 0.24 amps

E = 0.26 * 0.24

E = 0. 0624

Finally divide the 2.88 by 2 to get 1.44

Each cell has an emf of 1.44 + 0.0624 = 1.5024

Answer:

alpha particles carry a positive charge, beta particles carry a negative charge, and gamma rays are neutral

Explanation:

Alpha rays have poor penetration power. They can cause little harm from outside. The outer layer of dead skin in humans, a thick sheet of paper, or a layer of clothes can resist alpha penetration.

However, alpha particles also have the greatest mass, which implies that they have the greatest ionizing power. If an alpha particle somehow gets into the system through inhaling or swallowing, they become the most dangerous.

Chances of alpha particles getting inside the system occur only in situations of a nuclear accident or explosion. Once inside, alpha particles can cause maximum damage to the tissues of humans and other living organisms.

Beta particles are smaller and have less tissue-damaging power when inside an organism. However, they have greater penetrative power. From the outside, beta particles can burn human skin. It would be similar to a severe sunburn.

Gamma rays have the highest penetration power. A living organism such as a human being exposed to gamma rays faces a high risk of having bone marrow and internal organs damaged.

Gamma rays can pass through a body, damaging tissue and DNA in the process. Scientists consider gamma rays to be the most dangerous form of radiation.

Also:

Alpha particles are positive, heavy, and slower in its movement in comparison to other kinds of nuclear radiation. The travel speed of alpha particles is 5-7% of the speed of light.

Radiotherapy in cancer treatment uses alpha particles to kill the cancerous cells. Because of their low penetration power, they cannot damage the healthy cells surrounding the cancerous part.

One-thousandth of the mass of a proton is the mass of a beta particle. Beta particles carry either one negative charge – an electron, or one single positive charge – a positron. Because of their small mass, beta particles can travel almost at the speed of light.

Beta particles get used as tracers for medical imaging. They also have therapeutic uses in bone and eye cancer treatment. Smoke detectors also use beta particles. Sometimes, beta particles are used for quality control. Checking the thickness of paper, for instance.

Gamma has no mass and no electrical charge. It can travel at the speed of light. There is some application of gamma rays in oncology, and for sterilizing medical instruments

Beta particles have a negative charge, alpha particles have a positive charge, and gamma rays are neutral.

Energy that emanates from a source and moves through space at the speed of light is referred to as radiation. This energy has wave-like qualities and is accompanied by an electric field and a magnetic field. Radiation may also be referred to as electromagnetic waves.

Ionizing radiation and non-ionizing radiation are the two types of radiation. Non-ionizing radiation has sufficient energy to cause molecules' atoms to vibrate or move about, but not enough to deplete them of their electrons.

Gamma rays are neutral, alpha particles are positively charged, while beta particles are negatively charged.

An alpha particle is made up of two protons and two neutrons. Beta particles are thought to be highly energetic electrons. Photons are electromagnetic energy waves, and they are what gamma rays are.

Thus, this is the difference between the properties of alpha, beta and gamma radiations.

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Strong x-ray beams can be produced when cathode rays strike a metal anode.

This process is known as the production of bremsstrahlung radiation. When high-speed electrons, also called cathode rays, are accelerated and then collide with a metal target, they are abruptly decelerated, and the kinetic energy lost is converted into X-ray photons.

The resulting X-ray beam produced can be strong and intense, and its properties depend on the energy of the incident electrons and the material of the target.

Gamma rays moving through a magnetic field, alpha rays passing through a thin metal foil, or beta rays being absorbed by bones do not directly produce strong X-ray beams.

In summary, the correct answer is A) cathode rays striking a metal anode can produce strong X-ray beams.

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The smallest lifetime that this nuclear-excited state can have is 5.26 x 10^-14 seconds.

The uncertainty in energy, represented by the symbol ΔE, is related to the lifetime of a state, represented by the symbol τ, by the formula ΔEΔt ≥ ħ/2, where ħ is the reduced Planck constant. For a nuclear state with uncertainty ΔE = 2.5 eV, we can rearrange the formula to solve for the smallest lifetime:

Δt ≥ ħ/2ΔE

Plugging in the values, we get:

Δt ≥ (6.626 x 10^-34 J s)/(2 x 2.5 eV x 1.602 x 10^-19 J/eV)

Simplifying, we get:

Δt ≥ 5.26 x 10^-14 s

Therefore, the smallest lifetime that this nuclear-excited state can have is 5.26 x 10^-14 seconds.

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Answer:

It has 11 electrons 23_11=11

Answer:

Explanation:

Nichrome wire is generally used as a heating element in heating appliances because it has the following features: It offers a very large resistance. So a large amount of electric energy is converted into a large amount of heat energy. It has a high melting point such that it can be heated till red hot without melting.

Answer:

a

Explanation:

the river over time will eroded the rock

Answer:

Hello There!!

Explanation:

The answer is O False.

hope this helps,have a great day!!

~Pinky~

Answer:

i would say a bus because it has to speed up after the turn

Answer:

The bus

Explanation:

when the bus turns it has a change in direction and since velocity is a vector based on speed and direction the velocity is considered changed and since acceleration is a change in velocity the bus is an example of acceleration

Answer:

The president is permitted to veto specific legislative acts, but Congress has ... and judicial appointments and on the approval for ratification of treaties. ... State shall have the Qualifications requisite for Electors of the most numerous Branch of the State Legislature. ... No Bill of Attainder or ex post facto Law shall be passed.

Explanation:

To determine the force exerted by the seat on the passenger at the top of the loop, we can analyze the energy changes.

At the bottom of the loop, the car has kinetic energy given by KE = 1/2 * mass * velocity^2. At the top of the loop, this kinetic energy is converted to gravitational potential energy (GPE). Equating these energies, we have 1/2 * mass * velocity^2 = mass * g * height, where g is the acceleration due to gravity. Solving for height, we find h = (velocity^2) / (2 * g).

Now, at the top of the loop, the net force acting on the passenger is the sum of the gravitational force (mass * g) and the normal force exerted by the seat (N). The net force points downward, so we can write the equation as N - mass * g = mass * v^2 / r, where r is the radius of the loop. Plugging in the given values, we can calculate the force exerted by the seat on the passenger.

The force exerted by the seat on the passenger at the top of the loop, we equate the kinetic energy at the bottom of the loop to the gravitational potential energy at the top. Solving for height, we substitute it into the equation for net force. By plugging in the given values, we can determine the force exerted by the seat.

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The speed of the water flow through the hole in the figure is 2.97 m/s.

The speed of the water flow through the hole in the figure is calculated by applying the principle of conservation of energy as shown below.

change in kinetic energy = change in potential

ΔK.E = ΔP.E

where;

¹/₂mv² - ¹/₂mu² = mgh₁ - mgh₂

where;

¹/₂m(v² -u²) = mg(h₁ -h₂)

¹/₂(v² -u²) = g(h₁ -h₂)

¹/₂(v² -0) = g(h₁ -h₂)

v² = 2g(h₁ -h₂)

v = √(2g(h₁ -h₂))

v = √(2 x 9.8(0.5 - 0.05))

v = 2.97 m/s

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Einstein’s equation means that a small amount of mass can be converted into a large amount of energy.

The Einstein’s equation shows the relationship between the mass and energy of matter. According to his theory, mass and energy are interconvertible. The “c^2” in Einstein’s equation means that a small amount of mass can be converted into a large amount of energy.

In a nuclear reactor, energy is one of the products, the energy produced ina nuclear reactor is vented as small amount of mass can be converted into a large amount of energy.  Nuclear fusion involves the joining of to nuclei, this process occurs naturally  in the Sun and other stars.

We know that;

E = mc^2

E = 3 * 10^-3 * (3×108 m/s)^2 = 2.7×10^14 J

Again;

E = mc^2

m= E/c^2

m = 1012 J/(3×108 m/s)^2 = 1.1 * 10^-14 Kg

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Answer:

1. A small amount of mass can be converted into a large amount of energy.

2. heat

3. in the Sun and other stars

4. 2.7×1014 J

5. 1.1×10−5 kg

100% correct

The time period of the simple pendulum is 2.4 seconds.

Given the data in the question;

Period is the time needed for a complete cycle of vibration to pass a given point.

Period of a pendulum is the of time needed for it to complete one full back-and-forth motion. It is the time required to for the pendulum to swing from leftmost point to rightmost point and back to leftmost point.

Now, if it took the pendulum \(1.2s\) to swing from leftmost point to rightmost point, it will also take the pendulum \(1.2s\) to swing back to its original position( leftmost point )

Hence,

\(T\) = time taken to swing from leftmost to rightmost + time taken to swing from rightmost point to leftmost point.

\(T = 1.2s + 1.2s\\\\T = 2.4s\)

Therefore, the time period of the simple pendulum is 2.4 seconds.

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The frequency of electromagnetic radiation at which very pure silicon, at 300 K, should become transparent according to the Drude theory is 1.1 × 10¹⁶ Hz.

Drude theory is a physical model that describes the behavior of electrons in a solid. This model was proposed by Paul Drude in 1900. Drude theory assumes that electrons in a solid are free to move within the solid and interact with the lattice structure of the solid. Drude theory was the first model to successfully explain the electrical and thermal conductivity of solids.

The frequency of electromagnetic radiation at which very pure silicon, at 300 K, should become transparent according to the Drude theory is given by the expression below:

ωp² = \(\frac{n e^{2}} {e^ {0} m^*}\)

Here,ωp is the plasma frequency n is the number density of electrons e is the electron charge e⁰ is the permittivity of free space m* is the effective mass of the electron.

Substituting the given values, we get:

ωp2 = \(\frac{1.5*10^{22} * 1.6*10^{-19}*2}{8.85* 10^{-12}*9.1*10^{-31}}\)

ωp2 = 3.29 × 10²⁷ s⁻²

Therefore,ωp = 1.81 × 10¹³ s⁻¹. The critical frequency at which silicon becomes transparent is given by:

ν0 = ωp ÷ (2π)ν⁰ = 1.1 × 10¹⁶ Hz

Therefore, the frequency of electromagnetic radiation at which very pure silicon, at 300 K, should become transparent according to the Drude theory is 1.1 × 10¹⁶ Hz.

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Scientists have observational evidence of black holes through indirect methods, such as studying the effects of their strong gravitational pull on surrounding matter, detecting X-rays emitted from accretion disks.

Black holes, by definition, cannot be observed directly since no light or information can escape their gravitational pull. However, scientists have gathered compelling evidence for their existence through indirect observations. One such method involves studying the effects of black holes on surrounding matter. As matter falls into a black hole's gravitational field, it forms an accretion disk that emits X-rays detectable by space telescopes. Additionally, the detection of gravitational waves, ripples in spacetime caused by the acceleration of massive objects, provides strong evidence for the existence of black holes. Advanced detectors like LIGO and Virgo have successfully observed gravitational waves generated by black hole mergers, confirming their presence in the universe.

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The back EMF of the motor when it is operating normally is 179 V.

The starting current of the motor would be 107.5 A.

A series resistance of 0.402 ohm would be required to limit the starting current to 30.0 A.

Back EMF calculation:

The back EMF of a DC motor can be calculated using the formula:

EMF = V - I*R

Where:

EMF = back electromotive force

V = supply voltage

I = armature current

R = armature resistance

Given:

V = 215 V

I = 18.0 A

R = 2.00 ohm

Substituting the values in the formula, we get:

EMF = 215 V - 18.0 A * 2.00 ohm

EMF = 215 V - 36 V

EMF = 179 V

Starting current calculation:

The starting current can be calculated using the formula:

Istart = (V/R)

Where:

Istart = starting current

V = supply voltage

R = armature resistance

Given:

V = 215 V

R = 2.00 ohm

Substituting the values in the formula, we get:

Istart = (215 V) / (2.00 ohm)

Istart = 107.5 A

Series resistance calculation:

To limit the starting current to 30.0 A, we need to add a series resistance to the armature circuit. The resistance required can be calculated using the formula:

Rseries = (V - EMF) / Istart - Iload

Where:

Rseries = series resistance

V = supply voltage

EMF = back electromotive force

Istart = starting current

Iload = operating current

Given:

V = 215 V

EMF = 179 V

Istart = 107.5 A

Iload = 18.0 A (given in the problem)

Substituting the values in the formula, we get:

Rseries = (215 V - 179 V) / (107.5 A - 18.0 A)

Rseries = 36 V / 89.5 A

Rseries = 0.402 ohm

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