Two fun-loving otters are sliding toward each other on a muddy (and hence frictionless) horizontal surface. One of them, of mass 8.00 kg , is sliding to the left at 5.50 m/s , while the other, of mass 5.65 kg , is slipping to the right at 5.50 m/s . They hold fast to each other after they collide. Part A Find the magnitude of the velocity of these free-spirited otters right after they collide.
Answers
Answer:
Explanation:
Applying the law of collision:
Sum of momentum before collision = sum of momentum after collision
Both object move with the same velocity after collision
Momentum = mass × velocity
Sum of momentum before collision;
= 5.65(5.4)+(8)(-5.5)
= 30.51-44
= -13.49kgm/s
Sum of momentum after collision
= (8.0+5.65)v
= 13.65v
Equate;
-13.49 = 13.65v
v = -13.49/13.65
v = -0.988m/s
Hence the velocity of the otter after collision is 0.988m/s ( both moving towards the left)
Related Questions
Priscilla is driving her car on a busy street and Harvey passes her on his motorcycle. What will happen to the sound from his motorcycle after it passes her car?
A.
The frequency of the sound will decrease.
B.
The amplitude of the sound will increase.
C.
The intensity of the sound will increase.
D.
The wavelength of the sound will decrease.
E.
The velocity of the sound will increase.
Answers
Answer:
the correct answer is A
Explanation:
This is a doppler effect exercise which is the change in frequency due to the relative movement of the sound source and the observer.
\(f' = f_o \ \frac{v+v_o}{v-v_s}\)
where v₀ is the speed of the observer and v_s the speed of the source, the signs correspond when the two are closing in
with this expression let's analyze the different answers
A) True. The observed change is in the frequency, in this case the two are moving away, so the expression that describes the phenomenon is
\(f'= f_o \ \frac {v-v_o}{ v+v_s}\)
In this case, the speed of the source is greater than the speed of the observer, so when the denominator increases faster than the numerator, consequently the frequency must decrease
B) False. The amplitude does not depend on the relative velocity
C) False. The intensity depends on the distance, by or which when increasing the distance the intensity should decrease
D) False. The speed of sound is a constant, if the frequency decreases the wavelength must increase to maintain equality
E) False. The speed of sound depends on the properties of the propagating medium, not on the relative speed of the source and the observer.
Consequently the correct answer is A
An 8.0 Kg mass is placed at = 3 where should a 10 Kg mass be placed along the − so that the center of mass will be located ay = 4.5?
Answers
Answer:
Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.
Explanation:
To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.
Given:
m1 = 8 kg
x1 = 3 m
x_cm = unknown (to be found)
m2 = 10 kg
y_cm = 4.5 m
Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.
To solve for x2, we can rearrange the formula as follows:
x2 = (x_cm * (m1 + m2) - m1 * x1) / m2
Substituting the given values:
x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg
Simplifying:
x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg
Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:
4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)
Simplifying:
4.5 m = (24 kg + 10 kg * x2) / 18 kg
Multiplying both sides by 18 kg:
81 kg*m = 24 kg + 10 kg * x2
Subtracting 24 kg from both sides:
10 kg * x2 = 81 kg*m - 24 kg
Dividing both sides by 10 kg:
x2 = (81 kg*m - 24 kg) / 10 kg
Simplifying:
x2 = 8.1 m - 2.4 m
x2 = 5.7 m
(brainlest?) ples:(
Answer:
the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.
Explanation:
To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.
The center of mass of a system is given by the equation:
x_cm = (m1x1 + m2x2) / (m1 + m2),
where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.
Given:
m1 = 8 kg,
x1 = 3 m,
m2 = 10 kg,
y_cm = 4.5 m.
To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:
y_cm = (m1y1 + m2y2) / (m1 + m2),
where y1 and y2 are the positions along the y-axis.
Rearranging the equation and substituting the given values:
4.5 = (83 + 10y2) / (8 + 10).
Simplifying the equation:
4.5 = (24 + 10*y2) / 18.
Multiplying both sides by 18:
81 = 24 + 10*y2.
Rearranging the equation:
10*y2 = 81 - 24,
10*y2 = 57.
Dividing both sides by 10:
y2 = 5.7.
Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.
To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:
x_cm = (m1x1 + m2x2) / (m1 + m2).
Substituting the given values:
x_cm = (83 + 10x2) / (8 + 10).
Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:
0 = (83 + 10x2) / (8 + 10).
Rearranging the equation:
83 + 10x2 = 0.
24 + 10*x2 = 0.
10*x2 = -24.
Dividing both sides by 10:
x2 = -2.4.
6.
least 2 m. If the same car is moving with the speed 80K/h,what is the minimum stopping distance?
A car moving with a speed of 40 km/h can be stopped by applying the brakes after at-
Answers
The minimum stopping distance of the car is determined as 8 m.
What is the minimum stopping distance?The minimum stopping distance of the car is calculated as follows;
d = (u²)/(2a)
where;
d is the minimum stopping distanceu is the initial velocitya is the acceleration of the carwhen the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s
2 = (11.11²)/(2a)
a = (11.11²)/(2 x 2)
a = 30.86 m/s²
when the speed becomes 80 km/h, the minimum stopping distance is calculated as;
u = 80 km/h = 22.22 m/s
d = (22.22² )/ (2 x 30.86)
d = 8 m
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to the pleasure of the air show crowd, a 75.2 kg pilot makes a series of loop the loops. at the bottom of a 192 meter diameter circle loop, the pilot is flying with a speed of 63.1 m/s. determining all numerical values of f norm, a, f grav, f net
Answers
The lift required for the pilot to complete the loop is provided by the net force, which has a negative magnitude and is acting in the opposite direction of the centripetal force.
Calculation-f_grav = m * g
f_grav = 75.2 kg * 9.8 m/s^2 = 736.36 N
f_norm = -f_grav
f_norm = -736.36 N
The centripetal force acting on the pilot can be calculated using the equation:
f_cent = m * v^2 / r
f_cent = 75.2 kg * 63.1 m/s^2 / 96 m = 607.71 N
f_net = f_norm + f_cent = -736.36 N + 607.71 N = -128.65 N
So, the numerical values are:
f_norm = -736.36 N
a = 9.8 m/s^2
f_grav = 736.36 N
f_net = -128.65 N
What causes a roller coaster's centripetal force?Whether a roller coaster moves uphill, downhill, or in a loop, gravity exerts a constant downward force on the vehicle and its passengers. The centripetal force required to maintain the cars on the arching course as they pass through the loop is provided by the solid steel tracks in conjunction with gravity.
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The lift required for the pilot to complete the loop is provided by the net force, which has a negative magnitude and is acting in the opposite direction of the centripetal force.
What causes a roller coaster's centripetal force?Whether a roller coaster moves uphill, downhill, or in a loop, gravity exerts a constant downward force on the vehicle and its passengers. The centripetal force required to maintain the cars on the arching course as they pass through the loop is provided by the solid steel tracks in conjunction with gravity.
\(f_{grav} = m times g \\f_grav = 75.2 kg \times 9.8 m/s^2 = 736.36 N\\f_{norm} = -f_{grav}\\f_{norm} = -736.36 N\)
The centripetal force acting on the pilot can be calculated using the equation:
\(f_{cent} = m \times v^2 / r\\f_{cent} = 75.2 kg \times 63.1 m/s^2 / 96 m = 607.71 N\\f_{net} = f_{norm} + f_{cent} = -736.36 N + 607.71 N = -128.65 N\)
So, the numerical values are:
\(f_{norm} = -736.36 N\\a = 9.8 m/s^2\\f_{grav} = 736.36 N\\f_{net} = -128.65 N\)
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In a study, participants watched two teams pass a basketball among teammates. One team was wearing white shirts, and the other was wearing black shirts. Participants were told to count how many times the team wearing the white shirts passed the basketball, thereby directing their attention to the white shirts and ignoring the black shirts. Interestingly, half of the study participants failed to notice when a man wearing a black gorilla suit walked through the swirl of players, even though the gorilla paused to thump its chest. This phenomenon is known as
Answers
Interestingly, half of the study participants failed to notice when a man wearing a black gorilla suit walked through the swirl of players, even though the gorilla paused to thump its chest. This phenomenon is known as called inattentional blindness.
What is inattentional blindness?In psychology, inattentional blindness is defined as the inability of an individual to observe an object as a result of not paying attention to it's existence rather than being blind.From the excerpt, the instructions given to the participants directed their attention to the white shirts while ignoring the black shirts.
Because they lacked the attention, at the end of the study, half of the study participants failed to notice when a man wearing a black gorilla suit walked through the swirl of players due to inattentional blindness.
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If two runners are running in a 500 meter dash and runner #1 finishes in 25 seconds and runner #2 finishes in 27 seconds. What are the speeds of both runners? Which one is faster
Answers
For two runners running in a 500 meter dash and runner, the speeds of both runners is mathematically given as
v1=25m/s
v2=20m/s
and the first runner is faster
What are the speeds of both runners?Generally, the equation for the speed is mathematically given as
v=d/t
Therefore, for first runner
v=500/20
v1=25m/s
For 2nd runner
v=500/25
v2=20m/s
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An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
Answers
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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Need help please answer
Answers
Answer:
8 + 6 = 14 miles north
Explanation:
A rocket is fired from the earth to the moon at a speed of 0.930c. Let two events be "rocket leaves earth" and "rocket hits moon"
A. In the earth's reference frame, calculate Δx for these events.
B. In the earth's reference frame, calculate Δt for these events.
C. In the earth's reference frame, calculate the spacetime interval s for these events.
D. In the earth's reference frame, calculate Δx' for these events.
E. In the earth's reference frame, calculate Δt' for these events.
F. In the earth's reference frame, calculate the spacetime interval s' for these events.
G. In the earth's reference frame, calculate Δx if a rocket is replaced with a laser beam.
H. In the earth's reference frame, calculate Δt if a rocket is replaced with a laser beam.
I. In the earth's reference frame, calculate the spacetime interval s if a rocket is replaced with a laser beam.
Express ALL parts with appropriate units
Answers
A. Δx = 384,400 km (distance between Earth and Moon)
How to solveB. Δt = 384,400 km / (0.930 * 299,792 km/s) ≈ 1.421 s
C. s² ≈ (-2.781 * 10^10) km² (imaginary number, time-like separated events)
D, E, F. Cannot answer without specified primed frame.
G. Δx for laser beam = 384,400 km
H. Δt for laser beam = 384,400 km / 299,792 km/s ≈ 1.282 s
I. s² for laser beam ≈ 0 km² (light-like separated events)
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Nativism was rejected in the late 1600’s and early 1700’s by a group, of philosophers called:
Answers
Answer:
Nativism was rejected in the late 1600’s and early 1700’s by a group, of philosophers called?
Empiricists Is the Correct Answer!
xXxAnimexXx
Happy Labor day!
what are
the the ten disadvantages of friction
Answers
These are some frictional disadvantages: Overheating caused by friction consumes energy. Money is spent on both reducing resistance and
What does friction mean?
A force called friction keeps two objects from slamming into or rolling over one another. While friction force, such the traction needed to walk without slipping, may be helpful, they can also present a sizable degree of impediment to motion.
Why does Friction arise?
Friction is caused by flaws on the surfaces that are in touch. Even for the finest materials include minute imperfections, and these flaws produce friction when two surfaces come into contact. As the defects get worse, the friction gets worse.
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how come I can't find where the last one goes and everytime I do I have to click on it to go on the next question but it disappears?
Answers
answer yuo do not have it
determine the resultant force that water exerts on the overhang sea wall along abc. the wall is 2 m wide.
Answers
The resultant force that water exerts on the overhang sea wall along abc is 179 kN.
What is force?Force is a physical quantity that describes the interaction between two objects, such as a push or a pull. It is defined as any influence that causes an object to undergo a change in motion or deformation. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction.
Component that is horizontal. Because AB is horizontal, there is no horizontal component. The horizontal component of BC's force is.
(Fbc)h =γwhˉA=(1000kg/m3)(9.81m/s2)(1.5m+21(2m))(2m(2m))=98.1(103)N.
Component that is vertical. The weight of the water contained in blocks Abefa and Bcdeb (shown shaded in Fig. a) is equal to the force on AB and the vertical component of the force on BC. Here,
Aabefa=1.5m(2.5m)=3.75m2and
2Abcdeb=(3.5m)(2m)–4π(2m)2=(7–p)m2. Then,
Fab=γwVabefa=(1000kg/m3)(9.81m/s2)[(3.75m2)(2m)] =73.575(103)N=73.6N (FBC)v=γwVbcdeb=(1000kg/m3)(9.81m/s2)[(7–π)m2(2m)] =75.702(103)N
Therefore,
Fbc=(Fbc)²h2+(Fbc)²v2=√[98.1(10³)N]²+[75.702(10³)N]²=123.91(10³)N=124KN
FR² =(Fbc)²H2+[Fab+(Fbc)v]²
==[98.1(10³)N]² + [(73.6(10³)N)²+75.702(10³)N²]
=178.6(10³)N = 179 kN.
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A hamster eats a carrot before using its hamster wheel. The hamster wheel is connected to a generator which powers a light bulb.
Mechanical → Chemical → Radiant → Electrical
Chemical → Mechanical → Electrical → Radiant
Chemical → Mechanical → Thermal → Electrical
Mechanical → Electrical → Thermal → Radiant
Answers
Answer: Chemical → Mechanical → Electrical → Radiant
Explanation:
First, the Hamster eats the carrot, then the hamster is getting chemical energy.
Now the hamster starts using his wheel, then he "transforms" the chemical energy into mechanical energy.
Now the mechanical energy is connected to a generator, this means that the mechanical energy (the rotation of the wheel) is being converted into electrical energy.
And we know that there is a light bulb powered by this electrical energy, then we have electrical energy being transformed into radiant energy.
Then the correct option is:
Chemical → Mechanical → Electrical → Radiant
In hiking, what fitness component is required of you
Answers
Using Newton's 2nd Law of Motion Formula (F=MA) answer the following.
the net force on a vehicle that is accelerating at a rate of 1.5m/s^2 is 1,800 newtons. what is the mass of the vehicle to the nearest kilogram?
Answers
Explanation:
1200 is your answer for this question
Question 10 (1 point)
A water wave in a 17 m long pool takes 3 seconds to travel to one end of the pool.
What is the speed of the wave?
Answers
Answer:
5.67 m/s
Explanation:
The speed of a wave can be calculated as the distance traveled by the wave divided by the time taken:
Speed = Distance/Time
In this case, the distance traveled by the wave is the length of the pool, which is 17 m. The time taken by the wave to travel this distance is 3 seconds.
So, the speed of the wave can be calculated as:
Speed = 17 m/3 s
Speed = 5.67 m/s
Therefore, the speed of the water wave in the 17 m long pool is 5.67 m/s.
What is the velocity of a freely falling object 6 seconds after being dropped? After 10 seconds?
Answers
The speed of an object under free fall that starts at rest can be found using the formula:
\(v=gt\)Where g is the gravitational acceleration:
\(g=9.8\frac{m}{s^2}\)Remember that the velocity is a vector quantity. While the speed can be found using the given formula, a free falling object that starts at rest will get a velocity directed to the downward direction.
Substitute the value of g and the different values of t (6 seconds and 10 seconds) to find the velocity of the object at those moments:
\(v_1=(9.8\frac{m}{s^2})(6s)=58.8\frac{m}{s}\)\(v_2=(9.8\frac{m}{s^2})(10s)=98\frac{m}{s}\)Therefore, the velocity of a freely falling object 6 seconds after being dropped is 58.8m/s downwards.
The velocity of a freely falling object 10 seconds after being dropped is 98m/s downwards.
How has Physics improved
or affected our society?
Answers
By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life
From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.
The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.
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how to calculate the magnitude and direction of vector A-vectorB
A-B
Answers
Answer:
Let vector C(x,y) be A-B.
Explanation:
Now the direction is given by: tan-1(y/x)
Use the correct angle on the basis in which quadrant the vector C lies.
Magnitude = sqrt(x^2 + y^2)
When a glass rod is rubbed with silk, it becomes positive and the silk becomes negative—yet both attract dust. Does the dust have a third type of charge that is attracted to both positive and negative? Explain. g
Answers
Answer:
The dust does have any third charge.
Explanation:
In the context, the glass rod gets positively charged and so it induces a negative charge on the dust particles which are neutral. Thus the face of the dust particle which is near to the rod becomes negative charge and the opposite face of the dust gets equal positive charge and hence it ensures the neutrality of the dust particle but still being attracted to the glass rod.
And in the case of the negatively charged silk, the silk induces or gives positive charge to the dust particle which is neutral in charge. The face which is near to the silk gets positive charge and the other face becomes negative charge, again ensuring its neutrality and being attracted to the glass rod.
This shows how both positive charged rod and negatively charged silk attracts the neutral dust particle.
A girl of mass m1=60.0 kilograms springs from a trampoline with an initial upward velocity of vi=8.00 meters per second. At height h=2.00 meters above the trampoline, the girl grabs a box of mass m2=15.0 kilograms. (Figure 1)
For this problem, use g=9.80 meters per second per second for the magnitude of the acceleration due to gravity.
What is the speed vbefore of the girl immediately before she grabs the box?
Express your answer numerically in meters per second.
What is the speed vafter of the girl immediately after she grabs the box?
Express your answer numerically in meters per second.
What is the maximum height hmax that the girl (with box) reaches? Measure hmax with respect to the top of the trampoline.
Answers
The conservation of momentum and energy allows to shorten the results for the movement of the girl on the trampoline holding the box are:
a) the girl's speed is v = 4.98 m / s
b) The speed of the girl + box system is: v_f = 0.996 m / s
c) the maximum height is: y = 2.05 m
Kinematics studies the movement of bodies, looking for relationships between the position, velocity and acceleration of bodies.
The momentum is defined by the product of mass and the velocity, when a system is isolated the momentum is conserved.
The mechanical energy is the sum of the kinetic energy plus the potential energies, when there is no friction in the system the mechanical energy is conserved.
Let's solve this exercise in parts:
a) Let's use kinematics to find the speed of the girl before she grabs the box
v² = v₀² - 2 g y₁
v² = 8² - 2 9.8 2.00
v = R 24.8 = 4.98 m / s
b) Let's use momentum conservation for when the speed of the girl and the box together. Let's write the moment in two moments.
Initial instant. Just before you grab the box.
p₀ = M v + 0
Final moment. Right after taking the box
\(p_f\) = (m + M) \(v_f\)
In system this form by the girl and the box therefore it is an isolated system and the momentum is conserved.
\(p_o = p_f\)
mv = (m + M) \(v_f\)
\(v_f = \frac{m}{m+M} \ v\)
Let's calculate
\(v_f = \frac{15}{15+ 60} \ 4.98\)
\(v_f\) = 0.996 m / s
c) Now we use conservation of energy after the girl has the box.
Starting point. When the girl has the box
Em₀ = K + U
Em₀ = ½ (m + M) v² + (m + M) g y₁
Final point. At the highest point of the trajectory
\(Em_f\) = U
\(Em_f\) = (m + M) g y₁
As there is no friction, the energy is conserved.
\(Em_o = Em_f\)
½ (m + M) v² + (m + M) g y₁ = (m + M) g y
y = \(\frac{v^2}{2g} + y_1\)
Let's calculate
y = \(\frac{0.996^2}{2 \ 9.8} + 2.0\)
y = 2.05 m
In conclusion using the conservation of momentum and energy we can shorten the results for the movement of the girl on the trampoline holding the box are:
a) the girl's speed is v = 4.98 m / s
b) The speed of the girl + box system is: v_f = 0.996 m / s
c) the maximum height is: y = 2.05 m
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Answer:
Vbefore = 4.98 m/s
Vafter = 3.98 m/s
Hmax = 2.81 m
What is velocity gradient?
Answers
Answer:
Explanation:
What Is Velocity Gradient? According to the definition of velocity gradient, the difference in velocity between the layers of the fluid is known as the velocity gradient. It is represented by v/x, where v stands for velocity and x stands for the distance between the adjacent layers of the fluid.
The half-life of Silver-105 is 3.57 x 106 seconds. A sample contains 5.78 x 1017 nuclei. What is the decay constant for this decay?
Answers
Answer:
The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:
16:42
λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.
Explanation:
Name at 2 areas of physics that make video games possible
Answers
Answer:
projectiles
electromagnetic
Answer:
Explanation:
física cuántica y Quantum Moves
a car is moving 5.82 m/s when it accelerates at 2.35 m/s2 for 3.25, what is its final velocity
Answers
The final velocity of the car can be calculated using the formula: final velocity = initial velocity + acceleration * time. Plugging in the values you provided, we get: final velocity = 5.82 m/s + 2.35 m/s² * 3.25 s = 13.44 m/s.
A 2 m long wire carrying 2 A of current pointing to the right is placed in a magnetic field of 4 T directed away from you.
How big is the force acting on the wire?
A. 4 N
B. 8 N
C. 12 N
D. 16 N
Answers
Answer:16
Explanation:
as F=BIL so by placing value's B is magnetic field 4 and i is current 2A and l is length that js 2 m so answer is
Given: i=10A,B=0.15 T,θ=45
∘
and l=2 m
Force on a current carrying wire of finite length =
F
=l(
i
×
B
)
Hence, magnitude of force, F=Bilsinθ
=0.15×10×2×sin45
∘
=
2
3
N
The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat of Aluminum is double the specific heat of iron. If the temperature of the Aluminum's mass changes by /\T, what is the change in the Iron's mass temperature?
Answers
Answer:
it is double the temperature change of iron
A 3m plank AB of mass 20kg has a center of gravity 2m from end A and rests on supports R1 and R2 both 0,5m from either end. It also carries a 10kg block at end A. Calculate the reactions at R1 and R2
Answers
Answer:
130.7 N
Explanation:
Suppose the width of your fist is 5.3 inches and the length of your arm is 26.0 inches. Based on these measurements, what will be the angular width (in degrees) of your fist held at arm’s length?
Answers
Answer:
the suppose the widtge frist is 6.5 inches and the lenth of your arm is 320 and 500