two examples of decomposers
Answers
Fungi and bacteria-- mushrooms, bacteria, mold...
Answer:
The two examples of decomposers is bacteria and fungi
Related Questions
2 moles of NO, was placed in an empty I dm' bottle and allowed to reach equilibrium according to the equation:
At equilibrium, 1.2 moles of N,O, dissociated. Calculate the value of the equilibrium constant for the reaction at that
temperature.
Answers
2NO(g) ⇌ N2(g) + O2(g)
According to the problem statement, 2 moles of NO were placed in a 1 dm^3 bottle and allowed to reach equilibrium, and at equilibrium, 1.2 moles of NO had dissociated. This means that the initial concentration of NO was:
[NO]initial = 2 mol / 1 dm^3 = 2 M
And the concentration of NO at equilibrium is:
[NO]equilibrium = (2 - 1.2) mol / 1 dm^3 = 0.8 M
Since the stoichiometry of the balanced equation is 2:1:1 for NO, N2, and O2, respectively, the equilibrium concentrations of N2 and O2 will also be 0.6 M.
The equilibrium constant (Kc) can be calculated using the equilibrium concentrations of the reactants and products, raised to the power of their stoichiometric coefficients. Therefore:
Kc = ([N2][O2]) / ([NO]^2)
Substituting the equilibrium concentrations into the equation, we get:
Kc = (0.6 M x 0.6 M) / (0.8 M x 0.8 M)
Kc = 0.5625
Therefore, the value of the equilibrium constant for the reaction at that temperature is 0.5625. Note that the units of Kc depend on the stoichiometry of the balanced equation. Since the stoichiometric coefficients are all 1, the units of Kc in this case are M^-1
Convert 96.3g of calcium sulfate,CaSO4 into moles
Answers
Answer:
0.7073569530323789
Explanation:
They prob want it rounded tho so 0.71
Which will most likely happen to her soup?
Carlotta adds too much salt to her soup. She recalls that
evaporation can be used to separate salt from salt water,
so she plans to leave the soup on the stove on low heat
until the soup is less salty.
O The soup will become saltier because evaporation
removes the water and leaves the salt behind.
O The procedure will make the soup less salty because
the salt will evaporate and leave the pot.
The saltiness of the soup will not change because
both salt and water will evaporate.
O The heat will cause the soup to become more salty
because more salt dissolves in hotter water.
Answers
Answer: A! The soup will become saltier because evaporation removes the water and leaves the salt behind.
Explanation:
Just finished the test and got a 90%! <3
Answer:
A
Explanation:
COMO HA CONTRIBUIDO JUNTO A LA MOLALIDAD Y LA NORMALIDAD, CON EL DESARROLLO TECNOLOGICO Y DE LA HUMANIDAD.
Answers
Answer:
La molalidad y la normalidad son definiciones empleadas en aplicaciones de concentración bastante útiles para lograr proporciones óptimas en soluciones sólido-líquido y líquido-líquido, asimismo permite un criterio cuantitativo para aplicar un control de calidad en insumos productos a cualquier escala, así como garantizar unos mínimos de seguridad en materia de cuidado ecológico y de la salud humana, evitando desastres ecológicos, así como enfermedades y muertes asociadas a intoxicaciones.
Explanation:
La molalidad y la normalidad son definiciones empleadas en aplicaciones de concentración bastante útiles para lograr proporciones óptimas en soluciones sólido-líquido y líquido-líquido, asimismo permite un criterio cuantitativo para aplicar un control de calidad en insumos productos a cualquier escala, así como garantizar unos mínimos de seguridad en materia de cuidado ecológico y de la salud humana, evitando desastres ecológicos, así como enfermedades y muertes asociadas a intoxicaciones.
Assume air is 21% oxygen on a mole percent basis and the remainder is nitrogen. Calculate the weighted average heat capacity and then use that to find the energy that would need to be removed from 10 mol of the mixture to go from 500 K to 300 K.
Answers
Approximately 8,880 J of energy would need to be removed from 10 mol of the mixture to go from 500 K to 300 K.
The weighted average heat capacity of the air mixture is approximately 29.6 J/(mol·K). Therefore, to go from 500 K to 300 K, approximately 8,880 J of energy would need to be removed from 10 mol of the mixture.
To calculate the weighted average heat capacity, we consider the mole fraction of each component and their respective heat capacities. Given that air is 21% oxygen (O₂) and 79% nitrogen (N₂) on a mole percent basis, we can calculate the mole fraction of each component. The mole fraction of oxygen is 0.21, and the mole fraction of nitrogen is 0.79.
The heat capacity of oxygen is 29.3 J/(mol·K), and the heat capacity of nitrogen is 29.1 J/(mol·K). To find the weighted average heat capacity, we multiply the mole fraction of each component by its respective heat capacity, and then sum the results:
Weighted average heat capacity = (0.21 * 29.3 J/(mol·K)) + (0.79 * 29.1 J/(mol·K))
= 6.153 J/(mol·K) + 22.989 J/(mol·K)
= 29.142 J/(mol·K) ≈ 29.6 J/(mol·K)
Now, to find the energy that needs to be removed from 10 mol of the mixture to go from 500 K to 300 K, we can use the formula:
Energy = n * ΔT * C
Where:
n is the number of moles (10 mol),
ΔT is the change in temperature (500 K - 300 K = 200 K),
C is the weighted average heat capacity (29.6 J/(mol·K)).
Plugging in these values, we have:
Energy = 10 mol * 200 K * 29.6 J/(mol·K)
= 59,200 J ≈ 8,880 J
Therefore, approximately 8,880 J of energy would need to be removed from 10 mol of the mixture to go from 500 K to 300 K.
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When treated with excess of silver nitrate, which of the following three solutions will yield the largest mass of silve halide precipitate per liter of solution? c ha narrect answer helow: Select the correct answer below: O one molar solution of KCI O one molar solution of KBr O one molar solution of KI O All three solutions will yield the same mass of precipitate.
Answers
All three solutions will yield the same mass of precipitate.
The reactions are as follows:
\(KCl + AgNO_{3}\)→\(AgCl + KNO_{3}\)
\(KBr + AgNO_{3}\)→\(AgBr + KNO_{3}\)
\(KI + AgNO_{3}\)→\(AgI + KNO_{3}\)
To make a precipitate, we must combine two solutions: one containing silver ions and the other containing halide ions. Silver ion precipitates as white silver(I) chloride in soluble chlorides such as hydrochloric acid. The precipitate starts out white but quickly turns yellow. It can be fused, and when cool, it has an intense yellow color. Silver bromide is very light sensitive, but the color it produces when exposed to light is very different from that of chloride.
Eosin is adsorbed on the surface of silver halide precipitate, coloring it. In the presence of the dye eosin, the white precipitate of silver halide turns colored.
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what effect do concentration changes have on the reaction rate
Answers
Changes in concentration of reactants can affect the reaction rate by altering the frequency of collisions between particles.
Changes in the concentration of reactants can have a significant effect on the rate of a chemical reaction. In general, increasing the concentration of reactants leads to an increase in the reaction rate, while decreasing the concentration slows down the reaction.
The concentration of reactants determines the frequency of collisions between particles, which is a crucial factor in reaction kinetics. By increasing the concentration, there are more reactant particles available, leading to a higher probability of successful collisions and more frequent formation of product molecules. This results in an overall increase in the reaction rate.
Conversely, decreasing the concentration reduces the number of available reactant particles, leading to a decrease in collision frequency and slower reaction rate.
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concentration changes in a chemical reaction have a significant effect on the reaction rate. Increasing the concentration of reactants increases the frequency of collisions, leading to a faster reaction rate. Conversely, decreasing the concentration of reactants decreases the collision frequency and slows down the reaction rate. Concentration changes can also shift the equilibrium position, favoring the forward reaction and resulting in a faster reaction rate.
concentration changes in a chemical reaction can have a significant effect on the reaction rate. According to the collision theory, for a reaction to occur, reactant particles must collide with sufficient energy and proper orientation. When the concentration of reactants is increased, there are more particles per unit volume, leading to a higher frequency of collisions. This increased collision frequency increases the likelihood of successful collisions, resulting in a faster reaction rate.
On the other hand, decreasing the concentration of reactants decreases the number of particles available for collisions, leading to a lower collision frequency and a slower reaction rate. Therefore, concentration changes directly impact the reaction rate by influencing the frequency of collisions.
Additionally, concentration changes can also affect the reaction rate by altering the equilibrium position of the reaction. In some cases, increasing the concentration of reactants can shift the equilibrium towards the product side, favoring the forward reaction and resulting in a faster reaction rate.
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The diagram below shows a box with
two forces acting upon it.
20 N
20 N
Based on the diagram, which of the
following is most likely true?
A The box will move downward.
B The box will move toward the left.
C The box will move toward the
right.
D The box will not move or change
direction.
Answers
What food item will provide c in the least mass? What is that mass?
Answers
Answer:
Honey but Cheerios pls follow
Determine physiological temperature, 98.6 F in degree C
Answers
Answer:
37
Explanation:
( 98.6 - 32 ) × 5(100c) ÷ 9(180f) = 37
how do you balance _KCIO3 + __P4 → _P4010 + ___KCI
Answers
Information about calcium carbonate
What is calcium carbonate?
Answers
Answer:
Calcium carbonate is a dietary supplement used when the amount of calcium taken in the diet is not enough. Calcium is needed by the body for healthy bones, muscles, nervous system, and heart. Calcium carbonate also is used as an antacid to relieve heartburn, acid indigestion etc.
... yes I copied this from the internet, but hope it helps !
Select the step(s) that will compose rationale for the cation Ag+ being absent in an unknown (but Pb+2 is present}: Select one or more: - A whlte precipitate did not form step 2-B. - A lack of dark blue colored solution after addition of 15 M NH3- A yellow precipitate did not form when K2CrO4 was added in step 1-C - All of the white precipitate from step 1-A dissolved in hot water. - A reddish brown precipitate did not form after adding KFe(CN}6.- The white solid did not turn black upon addition of NaOH and SnCl2- The white precipitate from step dissolved in 6M NH3 and then reformed when 6 M HNO3 was added- No white precIpitate formed when 6 M HCI was added t0 the unknown solution In step 1-A - The presence of a Ilght blue decantate in step
Answers
The step(s) that compose rationale for the cation Ag+ being absent in an unknown (but Pb+2 is present) are:
A lack of dark blue colored solution after the addition of 15 M NH3 (step 2-B)A yellow precipitate did not form when K2CrO4 was added in step 1-CA reddish-brown precipitate did not form after adding KFe(CN)6The white solid did not turn black upon the addition of NaOH and SnCl2The white precipitate from step 1-A dissolved in hot water, indicating it is not AgCl, which is insoluble in water.The white precipitate from step 1-A dissolved in 6M NH3 and then reformed when 6M HNO3 was added, indicating it is not AgCl, which would not dissolve in NH3.No white precipitate formed when 6 M HCl was added to the unknown solution in step 1-A, indicating it is not AgCl, which would precipitate with HCl.The presence of a light blue decantate in step 1-B is consistent with the presence of Pb2+ but not Ag+.Step 1 involves adding KCl and HCl to the unknown solution, which should result in the formation of white precipitates of AgCl and PbCl2 if Ag+ and Pb+2 are present.
The absence of a white precipitate in step 1-A suggests that Ag+ may not be present, and this is supported by the fact that the precipitate dissolves in hot water, indicating it is not AgCl, which is insoluble in water.
In step 1-B, the addition of H2S produces a black precipitate of PbS, indicating the presence of Pb+2. The absence of a black precipitate in step 1-B also suggests that Ag+ may not be present.
Step 1-C involves adding K2CrO4 to the unknown solution to test for the presence of Pb+2, which should result in the formation of a yellow precipitate of PbCrO4. The absence of a yellow precipitate indicates that Pb+2 may not be present.
Step 2-B involves adding NH3 to the unknown solution, which should result in the formation of a dark blue solution if Ag+ is present. The absence of a dark blue color suggests that Ag+ may not be present.
The remaining steps (4, 5, 6, 7) involve the use of additional reagents to further differentiate between Ag+ and Pb+2. For example, the addition of KFe(CN)6 to the unknown solution should result in the formation of a reddish-brown precipitate if Ag+ is present, but not if Pb+2 is present.
Overall, by observing the results of these specific reactions with various reagents, it is possible to determine the presence or absence of specific cations in the unknown solution. In this case, the results suggest that Pb+2 is present, but Ag+ is not.
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If an object weighs 2,354 N on Earth, what is the objects mass?
Answers
Answer:
4.0 kg
Explanation:
M = W/g = 39.2/9.8 = 4.0 kg
sorry if its wrong-
a chemical reaction wherein two molecules combine to form one larger product is called _______. a. condensation b. absorption c. peristalsis d. segmentation e. hydrolysis
Answers
A chemical reaction wherein two molecules combine to form one larger product is called a condensation reaction.
The process of joining two or more atoms or molecules to form a single product is known as a chemical reaction. These reactions can be divided into two categories: combination and decomposition reactions.
During the process of condensation reaction a small molecule is eliminated as a byproduct, such as water or alcohol.
The condensation reaction can be utilized to create a variety of polymers by joining smaller monomers together into more complex molecules.
This reaction can be utilized to create peptide bonds between amino acids in proteins, ester bonds between carboxylic acids and alcohols, and glycosidic bonds between sugars, for example.
In addition to the condensation reaction, there are other types of chemical reactions.
For example, Hydrolysis, decomposition, single displacement, double displacement, acid-base, redox, and oxidation reactions are all examples of different types of chemical reactions.
In summary, a chemical reaction wherein two molecules combine to form one larger product is called a condensation reaction.
This process is used to create a variety of polymers by joining smaller monomers together into more complex molecules.
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Que características deben tener los modelos científicas
Answers
Answer:
Los modelos deben basarse en principios científicos sólidos.
Explanation:
Espero que esto ayude!
Which substance is the BEST example of a compound?
Orange Juice
Salt Water
Hydrogen
Water
Answers
Answer:
I think hydrogen because Hydrogen combined with one atom with oxygen and in hydrogen peroxide. It has two atoms of hydrogen and 2 atoms of oxygen. Therfore it should be a compound.
Which of the following are products of combustion?
liquid and solid water
newly discovered elements
additional atoms
heat and light
Answers
The answer option which are products of combustion is: D. Heat and light.
In Chemistry, there are five (5) main types of chemical reaction and these include;
Combination reaction.Double-replacement reaction.Decomposition reaction.Single-replacement reaction.Combustion reaction.A combustion reaction can be defined as an exothermic chemical reaction between physical substances, usually in the presence of oxygen and hydrocarbons to produce heat, light and carbon.
An example of a combustion reaction is the burning of forest trees and plants.
In conclusion, the products of combustion are heat and light.
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Answer:
heat and light
Explanation:
write a balanced equation for the precipitation reaction. c2h6 7 which product in the above reaction is the precipitate?
Answers
The balanced equation for the precipitation reaction is
C2H6 + 7O2 + 4H2O → 2CO2 + 7H2O .
A precipitation reaction is a chemical reaction occurring in an aqueous solution where two ionic bonds combine, resulting in the formation of an insoluble salt which is called the precipitate. A precipitate is a solid that forms out of a solution.
The balanced equation for the precipitation reaction of C2H6 and which product is the precipitate is as follows:
C2H6 + 7O2 + 4H2O → 2CO2 + 7H2O
In this reaction, the product that is the precipitate is not specified as there is no indication of any other reactant involved in the reaction that can form a precipitate.
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mass is the amount of
Answers
Answer:
Mass is a measure of the amount of matter in a substance or an object
Explanation:
we learned about this on school
The Lewis structure of carbon monoxide is given below. The hybridizations of the carbon and oxygen atoms in carbon monoxide are ________ and ________, respectively.
Answers
The hybridization of the carbon atom in carbon monoxide is sp, and the hybridization of the oxygen atom is sp.
To determine the hybridization of an atom, we need to consider the number of sigma bonds and lone pairs of electrons around that atom. In the Lewis structure of carbon monoxide (CO), we have a triple bond between carbon and oxygen, indicating the presence of one sigma bond and two pi bonds.
The carbon atom in carbon monoxide forms a triple bond with the oxygen atom, meaning it shares three electron pairs. In order to accommodate these three electron pairs, the carbon atom requires three atomic orbitals to hybridize.
One of these orbitals is an s orbital, and the other two are p orbitals. Therefore, the hybridization of the carbon atom is sp.
On the other hand, the oxygen atom in carbon monoxide forms a single bond with carbon, sharing one electron pair. It also has two lone pairs of electrons.
Considering these electron pairs, the oxygen atom requires three orbitals to hybridize. One of these orbitals is an s orbital, and the other two are p orbitals. Therefore, the hybridization of the oxygen atom is sp.
In conclusion, the carbon atom in carbon monoxide has sp hybridization, and the oxygen atom has sp hybridization. This hybridization allows both atoms to achieve the required geometry for their bonding and lone pairs of electrons.
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Indicate a procedure to solve the following recrystallization problems: a) lack of crystal formation, b) presence of colored impurities.
Answers
a) lack of crystal formation,
Seed crystals (a small amount of the pure solid) can be added to jump start the recrystalization process, or scratching the side of the glass can help.b) presence of colored impurities,
Using activated carbon "decolorizing carbon" which has a high affinity to colored impurities. Then filter mixture using gravity filtration.What is the recrystallizationIn the absence of crystals forming:
Make sure to use a good liquid that dissolves well.Make the solution dissolve better by heating it and stirring it.Cool the solution slowly so that crystals can form.Use little crystals if you have to.Remove impurities, clean, remove moisture, and gather the solid particles.b) Presence of Colored Impurities: This means that there are substances that are not the usual color in the mixture.
Select a liquid that can dissolve both the main substance and any unwanted substances effectively.Use hot filtration to remove substances that cannot dissolve in the liquid.Put activated carbon in to absorb colored dirt.Remove the activated carbon from the solution by using a filter.Make the solution colder so that crystals start to form.Clean, rinse, remove moisture, and gather the clean crystals.Read more about recrystallization here:
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Calculate the concentration 3.8g of copper sulfate, CuSO4 dissolved in 250cm4 of water
Answers
Answer:
Molarity = 0.08 M
Explanation:
Given data:
Mass of copper sulfate = 3.8 g
Volume of water = 250 cm³ (250/1000 = 0.25 L)
Concentration of solution = ?
Solution:
Number of moles of copper sulfate:
Number of moles = mass/molar mass
Number of moles = 3.8 g/ 159.6 g/mol
Number of moles = 0.02 mol
Concentration:
Molarity = Number of moles / volume in L
By putting values,
Molarity = 0.02 mol / 0.25 L
Molarity = 0.08 mol/L
Molarity = 0.08 M
write all the laws of thermodynamics.
Answers
Enthalpy In Thermodynamics: Thermal Energy Definition
What Is Planck's Constant: Entropy Definition Thermodynamics
Zeroth Law Of Thermodynamics Examples: Applications Of Newton's Laws Of Motion
What 2 main factors drive the water cycle? view attachment
Answers
Answer:
sun and ocean. I had this last week
In the circular flow diagram, what do firms provide to product markets?(1 point)
Answers
Answer:
Firms produce goods and services,which they sell to households in return for revenue.
Answer: Goods and Services
Explanation:
chemistry image below
Answers
A very reactive metal is image D
What is a reactive metal?A reactive metal is a metal that readily reacts with other substances in its environment, particularly with non-metals such as oxygen, chlorine, sulfur, and nitrogen. The reactivity of a metal depends on the ease with which it can lose electrons to form positive ions. These metals are often used in chemical reactions because of their reactivity
The metal that has been shown in the image that is attached in option D is sodium which is known to loose electron easily hence it is a reactive metal.
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"No matter what phase water
is in, the water molecules
stay the same; they just move
differently."
1: explain why this evidence matters
Answers
Answer:
Yes, water molecules remain the same despite the phase
Explanation:
When water is in the form of ice, it molecules remain the same only the distance between the molecule. This distance is higher than that of the inter molecular distance between liquid water molecules. Due to this reason ice is lighter than water.
Now in gaseous phase, the intermolecular distance increases thereby making it lighter than solid ice and liquid water.
Determine the mass of 10g of CaCO3
Answers
Answer:
= 100u. Hence 10 g = 0.1 mole. Hope it's helpful to u
If 4.0 mL of a 3.0 M HCl solution is exactly neutralized by a 3.0 mL sample of NaOH, then what is the concentration of the NaOH solution?
Answers
Answer:
B. 4.0
Explanation: