Answers
Answer:
6.00 x 10⁻⁸N
Explanation:
Given parameters:
Mass of each dump trucks = 1500kg
Distance between them = 50m
Unknown:
New gravitational force between them = ?
Solution:
From Newton's law of universal gravitation,
F = \(\frac{G m1 m2}{r^{2} }\)
F is the gravitational force
G is the universal gravitation constant
m is the mass
r is the distance
F = \(\frac{6.67 x 10^{-11} x 1500 x 1500}{50^{2} }\) = 6.00 x 10⁻⁸N
Related Questions
No idea which one is correct..
Answers
What is energy anything that takes up space and has mass a change in the position of an object a push or pull the ability to cause change in matter
Answers
Energy is that which has the ability to cause change in matter.
What is energy?Energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light. Energy is a conserved quantity—the law of conservation of energy states that energy can be converted in form, but not created or destroyed.
So in simple definition we can say that energy is that which has the ability to cause change in matter.
Based on the given statements we can classify them as;
anything that takes up space and has mass - matter.cause a change in the position of an object through push or pull - forcethe ability to cause change in matter - energy.Learn more about energy here: https://brainly.com/question/13881533
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progress of science has not caused any ill effect true or false?
Answers
A solid metal sphere of radius 4.00 m carries a total charge of -5.20 μC . a What is the magnitude of the electric field at a distance from the sphere's center of 0.300mb What is the magnitude of the electric field at a distance from the sphere's center of 3.85mc What is the magnitude of the electric field at a distance from the sphere's center of 4.10md What is the magnitude of the electric field at a distance from the sphere's center of 6.00m
Answers
a. In a metal sphere, all the charge resides on the surface of the sphere, such that the electric field anywhere in the bulk of the metal sphere is 0, i.e. electric field inside the radius of the metal sphere is 0.
Hence,
\(\vec{E}(r=0.300m)=\vec{0}\)b. By same argument,
\(\vec{E}(r=3.85m)=\vec{0}\)c. But outside the metal sphere, the electric field will be,
\(\vec{E}(r)=\frac{1}{4\pi\epsilon_0}\frac{Q}{r^2}\hat{r}\)here Q = -5.20×10^(-6) C, r = 4.10m,
\(E(r=4.10m)=9\times10^9\times\frac{(5.20\cdot10^{-6})}{(4.10)^2}=2784.06\text{ N/C}\)d. Again outside the sphere,
\(E(r=6.00m)=9\times10^9\times\frac{(5.20\times10^{-6})}{(6.00)^2}=1300\text{ N/C}\)Result: a. 0, b. 0, c. 2784.06 N/C, d. 1300 N/C.In case of solid nonconductor uniformly charged, the electric field won't be 0 inside,
\(E(r)=\frac{\rho r}{3\epsilon_0}\)where rho is the charge density.
a.
\(E(r=0.300m)=\frac{1}{4\pi\epsilon_0}\frac{Qr}{R^3}=9\times10^9\times\frac{(5.2\times10^{-6})(0.300)}{(4.00)^3}=219.375\text{ N/C}\)b.
\(E(r=3.85m)=9\times10^9\times\frac{(5.2\times10^{-6})(3.85)}{(4.00)^3}=2815.3125\text{ N/C}\)Two resistors, A and B, are connected in parallel across a 6.0-V battery. The current through B is found to be 2.0 A. When the two resistors are connected in series to the 6.0- V battery, a voltmeter connected across resistor A measures a voltage of 4.0 V. Find the resistances of A and B
Answers
Answer:
The resistance of A is 6 ohms and the resistance of B is 3 ohms
Explanation:
Step 1: For the first connection (parallel connection), the resistance of B will be calculated.
Note: in a parallel connection, the voltage through each resistor is the same.
\(V = I_AR_A = I_BR_B\\\\R_B = \frac{V}{I_B} = \frac{6}{2} = 3 \ ohms\)
Step 2: The resistance of A will be calculated from the second connection (series connection)
Note: in series connection, the current flowing in each resistor is the same
\(V = V_A + V_B\\\\V = IR_A + IR_B\\\\The \ voltage \ drop \ in \ B; \ V_B = V- V_A\\\\V_B = 6 - 4 = 2 \ V\\\\IR_B = 2\ V\\\\I = \frac{2 \ V}{R_B}= \frac{2}{3} \ A\\\\The \ resistance \ of \ A \ is \ calculated \ as ;\\\\IR_A = 4 \ V\\\\R_A = \frac{4}{I} = \frac{4 \times 3}{2} = 6 \ ohms\)
22 4 points
What is the mechanical advantage of a hydraulic system that has a small piston diameter of 6.5 inches and a large piston diameter of 20 inches?
A.8.84
B.15.35
C.9.47
D.3.7
Answers
This is 20 plus 6.5 squared, which equals.Nearly nine 478 is what this equates to.This system therefore has a 9.47 mechanical advantage.
What mechanical benefit does this hydraulic system offer? This is 20 plus 6.5 squared, which equals.Nearly nine 478 is what this equates to.This system therefore has a 9.47 mechanical advantage.In a hydraulic system, the fluid's capacity to convey pressure evenly accounts for the significant mechanical advantage.It enables you to apply a tiny amount of force to the small piston in order to generate a bigger amount of force on the large piston.The output force minus the input force is equal to the mechanical advantage.The ratio of the large piston area to the tiny piston area is the mechanical advantage of a hydraulic lift that is optimal.
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if the mass of an object were doubled, its weight would be
Answers
Weight of a body is defined as the force with which it is attached to the earth.
mass is the total quantity of matter present.
the weight of something is given as mass * acceleration
weight of an object is directly proportional to the mass of the object. so, if mass doubles, weight will also double.
hope this helps :)
- jeron
. Acceleration is the rate at which/what hap-
pens?
Answers
On April 13, 2029 (Friday the 13th!), the asteroid 99942 mi Apophis will pass within 18600 mi of the earth-about 1/13 the distance to the moon! It has a density of 2600 kg/m^3, can be modeled as a sphere 320 m in diameter, and will be traveling at 12.6 km/s.
1)If, due to a small disturbance in its orbit, the asteroid were to hit the earth, how much kinetic energy would it deliver?
2)The largest nuclear bomb ever tested by the United States was the "Castle/Bravo" bomb, having a yield of 15 megatons of TNT. (A megaton of TNT releases 4.184x10^15 J of energy.) How many Castle/Bravo bombs would be equivalent to the energy of Apophis?
Answers
Answer:
Explanation:
Volume of asteroid = 4/3 x π x 160³
= 17.15 x 10⁶
mass = volume x density
= 17.15 x 10⁶ x 2600
= 445.9 x 10⁸ kg
kinetic energy
= 1/2 x 445.9 x 10⁸ x( 12.6 )² x 10⁶
= 35.4 x 10¹⁷ J .
2 )
energy of 15 megaton
= 4.184 x 10¹⁵ x 15 J
= 62.76 x 10¹⁵ J
No of bombs required
= 35.4 x 10¹⁷ / 62.76 x 10¹⁵
= 56.4 Bombs .
A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
Answers
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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The volume of a cylinder is calculated with the following equation: V=πr2h (where r is the radius and h is the height of the cylinder). If the height of the cylinder is 0.188ft and the radius is 0.0443inches what is the volume in cm3. [1ft=0.3048m] [2.2inches=0.0558m]
Answers
The volume of the cylinder would be 0.2278 cm³.
What is the volume of a cylinder?The volume of a cylinder is calculated with the formula
V = πr²h
where V is the volume of the cylinder
r is the radius of the cylinder
h is the height of the cylinder
As given in the problem If the height of the cylinder is 0.188ft and the radius is 0.0443inches
h = 0.188 ft
= 0.188× 0.3048 m
= 0.0573 m
r = 0.0443inches
=0.00112522 m
V = πr²h
= 3.14 ×0.00112522²×0.0573
=2.278 ×10⁻⁷ m³
=0.2278 cm³
Thus, the volume of the cylinder would be 0.2278 cm³.
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An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?
Answers
Answer: the radius of the circular path is approximately 1637.58 meters.
Explanation:
The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:
F_c = m * g * tan(banking angle)
Where:
F_c is the centripetal force
m is the mass of the airplane
g is the acceleration due to gravity
tan(banking angle) is the tangent of the banking angle
Now, the centripetal force is also given by the formula:
F_c = (m * v^2) / r
Where:
v is the speed of the airplane
r is the radius of the circular path
Equating the two expressions for F_c, we get:
(m * g * tan(banking angle)) = (m * v^2) / r
Canceling out the mass (m) on both sides of the equation, we have:
g * tan(banking angle) = v^2 / r
Solving for r, we get:
r = (v^2) / (g * tan(banking angle))
Substituting the given values:
v = 400 km/h = 400,000 m/h
g = 9.8 m/s^2
banking angle = 20°
Converting the speed to m/s:
v = 400,000 m/h * (1/3600) h/s = 111.11 m/s
Converting the banking angle to radians:
banking angle = 20° * (π/180) rad/° = 0.3491 rad
Now, substituting the values into the formula:
r = (111.11^2) / (9.8 * tan(0.3491))
r ≈ 1637.58 meters
Therefore, the radius of the circular path is approximately 1637.58 meters.
Weight is best defined as _____. A the amount of space an object takes up B the speed of an object C the force of gravity on an object D the amount of energy in an object
Answers
Weight is best defined as C) the force of gravity on an object.
1.00 kg of ice at -24.0°C is placed
in contact with a 1.00 kg block of a
metal at 5.00°C. They come to
equilibrium at -8.88°C. What is
the specific heat of the metal?
Answers
1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.
We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.
The heat lost by the metal is given by
Q1 = m1c1ΔT1
Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.
The heat gained by the ice is given by
Q2 = m2c2ΔT2
Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.
Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2
m1c1ΔT1 = m2c2ΔT2
Solving for c1, we get
c1 = m2c2ΔT2 / (m1ΔT1)
By putting these values we get
c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]
c1 = 0.902 kJ/kg·K
Hence, the specific heat of the metal is 0.902 kJ/kg·K.
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does the stirling engine follow the law of conservation energy
Answers
Answer:
Conservation of Energy: Like all things, Stirling Engines follow the conservation of energy principle (all the energy input is accounted for in the output in one form or another). ... The hot one supplies all of the energy QH, while the cold one removes energy QC (a necessary part of the cycle).
Explanation:
Answer: Yes
Explanation: All the energy input is accounted for in the output in one form or another
A small heat engine has an energy input of 1,176 joules, and does 201 joules of work. What is the efficiency of the engine? (round your answer to the nearest whole number percent, but leave off the % symbol)
so, if you calculate it is 13.3%, enter your number as 13.
Answers
The efficiency of the engine is 17%.
Given the following data:
Energy input = 1,176 JoulesEnergy output = 201 JoulesTo find the efficiency of the engine:
Mathematically, the efficiency of an engine is calculated by using the formula:
\(Efficiency = \frac{E_O}{E_I}\) × \(100\)
Where:
Eo is the energy output.Ei is the energy input.Substituting the given parameters into the formula, we have;
\(Efficiency = \frac{201}{1176}\) × \(100\)
\(Efficiency = 0.171\) × \(100\)
Efficiency = 17%
Therefore, the efficiency of the engine is 17%.
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What is the acceleration of a 7 kg object if a force of 63 N is applied?
Answers
Answer:
9m/s^2
Explanation:
F=ma
a=F/m
a=63/7
a=9m/s^2
Excess ______________ and _______________ run-off into the lake causing algae to “________.” The subsequent decomposition of the algae sucks up ___________ gas suffocating other organism and blocks _____________ for other producers.
Answers
Excess phosphorus and nitrogen run-off into the lake causing algae to “overgrow” The subsequent decomposition of the algae sucks up oxygen gas suffocating other organisms and blocks sunlight for other producers.
How overflow of nitrogen runoff causes overgrowth of algaeIt is not an uncommon fact that an undersecretary, oversecretion, excess flow, little flow of substances creates a negative impact on living organisms.
From the task given above, when there is too much nitrogen supply to the plant algae, it leads to the overstimulation of the organisms in terms of overgrowth which them to be suffocated of certain gases and hinder light energy to penetrate into the deep part of water.
So therefore, we can deduce that an overflow of phosphorus and other nutrients is not healthy for algae life.
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A 2.50-W beam of light of wavelength 124 nm falls on a metal surface. You observe that the maximum kinetic energy of the ejected electrons is 4.16 eV. Assume that each photon in the beam ejects a photoelectron. (a) What is the work function (in electron volts) of this metal
Answers
Answer:
φ = 13.43 x 10⁻¹⁹ J = 8.4 eV
Explanation:
Using the Einstein's Photoelectric equation:
Energy of Photon = Work Function + Kinetic Energy of Electron
\(\frac{hc}{\lambda} = \phi + K.E\)
where,
h = Plank's Constant = 6.625 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength = 124 nm = 1.24 x 10⁻⁷ m
φ = work function = ?
K.E = Kinetic Energy of Electrons = (4.16 eV)(\(\frac{1.6\ x\ 10^{-19}\ J}{1\ eV}\)) = 2.6 x 10⁻¹⁹ J
Therefore,
\(\frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{1.24\ x\ 10^{-7}\ m} = \phi + 2.6\ x\ 10^{-19}\\\\\phi=16.03\ x\ 10^{-19}\ J - 2.6\ x\ 10^{-19}\ J\)
φ = 13.43 x 10⁻¹⁹ J = 8.4 eV
A 200N lamp is suspended from three cables as shown in the figure below. Find the tensions in each of the three cables.
Answers
Answer:
66.6N
Explanation:
Step one;
given data
the mass of the lamp = 200N
we are told that it is suspended by 3 cables.
Now we know that the weight will be distributed equally on the cables
Step two:
so, let the tension in each cable be T
T+T+T= 200
3T=200
T=200/3
T=66.6N
The tenion on each cable is 66.6N
A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?
Answers
The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s
What is Speed ?Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s
Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.
The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.
Let us first calculate the time by using the formula
h = ut + 1/2gt²
Where
h = 52 mu = 0Range R = 35 mg = 9.8 m/s²Substitute all the necessary parameters into the formula
52 = 0 + 1/2 × 9.8 × t²
52 = 4.9t²
t² = 52/4.9
t² = 10.6
t = √10.6
t = 3.26 s
The speed at which the rock was initially kicked can be found by
R = Ut
35 = U × 3.26
U = 35/3.26
U = 10.7 m/s
Therefore, rock was initially kicked at a speed of 10.7 m/s
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what kind of soil is most likely found in the desert
Answers
NEED THIS ASAP
1. What type of graph did John use to display his data?
2. What is the dependent variable in John’s graph?
3. What is the independent variable in John’s graph?
4. On which day of the week did the greatest number of leaves fall?
5. On what days of the week did the number of leaves that fell remain constant?
6. On what other type of graph could this data be shown?
Directions: Convert the following.
7. 200 m = ____________ km
8. 1.2 L = ____________ mL
9. 0 K = ____________ °C
10. 12 cm3 = ____________ mL
11. 10°C = ____________ K
12. 1 L = ____________ cm3
13. 124 mm = ____________ cm
14. 12,000 mg = ____________ g
Answers
2- Number of leaves that fell
3- Days of week
4- Friday
5- Monday, Tuesday, Wednesday
6- Bar graph
7- 200 m = 0.2 km
8- 1.2 L = 1200 mL
9- 0k = -273 ‘C
10 - 12 cm3 = 12 mL
11- 10 ‘C = 283 K
12- 1 L = 1000 cm3
13- 124 mm= 1,24 cm
14 - 12.000 mg = 12.0 g
Hope it helps you.
From the graph attached below the dependent variables are located on the Y axis of the graph while the independent variables are located on the x-axis of the graph.
Independent variables have direct effect on dependent variables in an experiment when manipulated. also independent variables have direct effect on dependent variables even when not manipulated.
Data involving the comparison of the effect of independent variables on dependent variables can be represented with a bar graph or line graph .
Hence we can conclude that the answers to your questions are as listed above.
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A motor has a rotor (with armature) of moment of inertia ????m . The rotor is attached to a gear box of gear ratio G > 1. The output of the gearbox is attached to a mass whose moment of inertia is ????. What will be the moment of inertia ‘felt’ by the motor? What will be the moment of inertial ‘felt’ by someone who is rotating the mass ???? by hand, to turn the motor? Which of the two is large
Answers
Answer:
hello your question is incomplete attached below is the complete question
answer : The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor i.e. J > Jm
Explanation:
Gear ratio G > 1
a) Determine the moment of inertia felt by the motor
moment of inertia felt by Motor = moment of Inertia at the armature
b) Determine the moment of inertial felt by someone who is rotating the mass by hand
moment of inertia felt by someone is = J
The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor
attached below is a detailed solution
The cycling of the air is a natural phenomenon as shown above is the result of
Answers
Answer:
natural convection
............
A circular loop of wire with radius 10.0 cm is located in the xy-plane in a region of uniform magnetic field. A field of 2 T is directed in the z-direction, which is upward. (a) What is the magnetic flux through the loop
Answers
Answer:
\(\phi=628.3\)
Explanation:
From the question we are told that
Radius \(r=10.0 cm\)
Magnetic field\(B=2T\)
Generally the equation for area of circular path is mathematically given by
\(Area=\pi r^2\)
\(A=\pi 10^2\)
\(A=314.15m^2\)
Generally the equation for Magnetic flux is mathematically given by
\(\phi=BA\)
\(\phi=2*314.15\)
\(\phi=628.3\)
A man is standing away from the School
Building at a distance of
300m . He claps his hands and hears an echo calculate the time interval of him hearing his echo
Answers
The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
What do you mean by echo?An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.
The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.
To calculate the time interval, we can use the following formula:
time = distance / speed
where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.
distance = 2 x 300m = 600m
speed = 343 m/s
time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)
Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
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Type the name or address of your current location in the address field and select the location provided. Write the exact latitude and longitude coordinates (degrees, minutes, and seconds) that are provided in the answer space. How do these coordinates compare to your estimate from part C?
The coordinates should be written in the following format:
Lat: N 33°34’ 40”
Lon: W 99°29’ 31”
Answers
My location coordinates are Lat: N 38.89'76", Lon: W: -77.03'66"
What are geographic coordinates?Geographic coordinates are a term to refer to the terrestrial reference system that allows a location to be specified by means of a series of numbers, letters or symbols.
The basic and best known geographic coordinate system worldwide specifies the following data:
North or South latitude, degrees, minutes and seconds.East and west longitude, degrees, minutes and seconds.To establish the geographical location of a point, the imaginary Greenwich meridian reference lines (longitude) and the equator line (latitude) must be taken into account.
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a 260 g ball is dropped from a height of 2.4 m , bounces on a hard floor, and rebounds to a height of 1.9 m . (figure 1) shows the impulse received from the floor.
Answers
The impulse received from the floor is -118 g m/s when a 260 g ball is dropped from a height of 2.4 m, bounces on a hard floor, and rebounds to a height of 1.9 m.
The impulse received by the floor is equal to the change in momentum of the ball. The momentum of the ball can be calculated as the product of its mass and velocity.
Before the ball hits the floor, its momentum is given by:
= p1
= m x v1
= 260 g x (2.4 m/s)
= 624 g m/s
After the ball hits the floor and rebounds, its momentum is given by:
= p2
= m x v2
= 260 g x (-1.9 m/s)
= -494 g m/s
The change in momentum of the ball is equal to the difference between p2 and p1:
= Δp
= p2 - p1
= -494 g m/s - 624 g m/s
= -118 g m/s
Therefore, the impulse received by the floor is equal to -118 g m/s. Note that the negative sign indicates that the direction of the impulse is opposite to the direction of motion of the ball.
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Calculating Displacement under Constant Acceleration
Use the information from the graph to answer the
question.
Velocity (m/s)
40
30
20
10
0
Velocity vs. Time
0 5
10
15
Time (s)
20
25
What is the total displacement of the object?
I
m
Answers
Answer:
1 km
Explanation:
displacement =velocity ×time
displacement =40m/s ×25s
displacement =1000m equivalent to 1km