Two bumper cars collide into each other and each car jolts backwards this is an example of which of newtons laws?

Answers

Answer 1

When two bumper cars collide into each other and each car jolts backwards, this is an example of: Newton's Third Law of Motion also known as the law of action and reaction.

Newton's Third Law states that for every action, there is an equal and opposite reaction. In the case of the bumper cars, when they collide, the force exerted by Car A on Car B (the action) is equal in magnitude and opposite in direction to the force exerted by Car B on Car A (the reaction).

This is why both cars experience a jolt in opposite directions after the collision.

To recap, the situation you described with the two bumper cars colliding and jolting backwards is an example of Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction.

This law helps us understand the behavior of objects during collisions and interactions, and it plays a crucial role in understanding the principles of physics.

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Related Questions

A sprinter runs a 100 m dash in 12.0 s. She starts from rest with a constant acceleration ax for 2.0 s and then runs with constant speed for the remainder of the race.

Answers

the value of ax, given the data from the question is 4.55 m/s²

Data obtained from the queston

From the question given above, the following data were obtained:

Total distance travelled = 100 mTotal time = 12 sTime for acceleration (t) = 2Acceleration (a) = ax =?

How to determine the distance travelled in the first 2 sInitial velocity = 0 m/sAcceleration (a) = axTime (t) = 2 sDistance (s) for the first 2 s = ?

s = ½at²

s = ½ × ax × 2²

s = 2ax

How to determine the velocity in the first 2 sAcceleration (a) = axTime for acceleration (t) = 2 sVelocity for the first 2 s (v) = ?

v = at

v = ax × 2

v = 2ax

How to determine the value of ax

Remaining distance = velocity × remaining time

Remaining time = 12 - 2 = 10

Remaining distance = 2ax × 10

Remaining distance = 20ax

Total distance = Distance for first 2 s + Remainng distance

100 = 2ax + 20ax

100 = 22ax

Divide both sides by 22

ax = 100 / 22

ax = 4.55 m/s²

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If there was a flood that caused damage to your car, what kind of coverage must you have in order for the insurance company to help cover the cost of repairs?

Answers

Comprehensive coverage?

In order for the insurance company to help cover the cost of repairs, you must have comprehensive auto coverage.

What is flood?

An overflow of water causing the destruction beyond its limits is called flood.

In the situation of car damage due to flood, comprehensive auto coverage from the insurance company will pay for the damage to your flooded vehicle. So, it helps in covering the cost of damages to vehicle when damage is not caused by a collision.

Thus, In order for the insurance company to help cover the cost of repairs, you must have comprehensive auto coverage.

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Which of the following is an example of light energy being changed to chemical energy?

Group of answer choices
A flashlight with rechargeable batteries
A solar panel that charges a battery
Food that is eaten to provide mechanical energy

Answers

Answer:

A solar panel

Explanation:

Against the park ranger's advice, a visitor at a national park throws a stone horizontally off the edge of a 83 m high cliff and it lands a distance of 93 m from the edge of the cliff, narrowly missing a visitor below.
What was the initial horizontal velocity of the rock, in m/s? You can round your answer to the hundredths place and use g ≈ 10 m/s2.

Answers

the answer it would be 164 m

Why is the less massive star in Algol a red giant already, but the more massive star is still on the main sequence

Answers

Algol is a binary star system consisting of two stars orbiting around their common center of mass.

The more massive star, Algol A, is still on the main sequence, while the less massive star, Algol B, has evolved into a red giant.

This difference in evolutionary stage can be explained by their initial masses and the difference in their ages.

The more massive a star is, the faster it consumes its nuclear fuel and progresses through its evolutionary stages. In the case of Algol, Algol A is more massive than Algol B, which means that it burns its nuclear fuel at a higher rate.

Algol B, being less massive, has a lower rate of energy production and a longer lifespan. As it exhausts the hydrogen fuel in its core, it expands and enters the red giant phase.

This expansion occurs as the core contracts and the outer layers of the star expand, causing it to become larger and cooler, leading to its classification as a red giant.

On the other hand, Algol A, being more massive, continues to burn hydrogen in its core at a faster rate, maintaining its high core temperature and pressure. As a result, it remains on the main sequence, where stars primarily burn hydrogen into helium through nuclear fusion.

The difference in evolutionary stage between the two stars in Algol is primarily determined by their masses and their different rates of energy production and consumption.

The more massive star progresses faster through its life cycle, while the less massive star evolves more slowly, leading to the difference in their evolutionary stages observed in the Algol binary system.

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An electrical appliance of 1.5 kw is used for 4hour each day. The electrical energy consumed in 60 days is :

a)6kwh

b)360kwh

c)2250kwh

please help me!!

I want the correct answers ​

Answers

Answer:

c

Explanation:

c

Your answer would be C.


C is the best answer.

What is the magnitude of a force? (1 point)
O the type of force
O the amount of force
O the motion of the force
O the direction of the force

Answers

Answer:

the amount of the force i learned it from my teacher

The amount of force is referred to as the magnitude of a force. Hence, option B is correct.

What is Force?

A force is an action that has the ability to alter an object's motion. An object can be caused by a force, which can also accelerate an item. To describe force, a push or a pull, makes intuitive sense. Forces have had both direction and magnitude, since they are vector quantities. It is measured in newtons that use the SI system (N). The symbol for force is the letter F.

An entity's net force equals the rate at which its momentum is changing over time, according to the original formulation of Newton's second law.

Objects' velocities can be changed by the concepts of push, drag, and torque. Thrust causes an item to move faster, whereas torque allows an object to move slower. Each part of an extended body typically exerts forces on its adjacent sections; the internal mechanical stress in the body is the result of the distribution of these forces.

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One forecasting model was used to forecast demand for a product. The forecasts and the demand are shown in the table below. B Actual Forecast 11 40 41 35 38 3 38 35 33 30 IX Calculate Moan Absolute Deviation (MAD) and Mean Squared Error (MSE). Show all details and use 1 decimal in your answer For the toolbar, press ALT+F10 (PC) or ALT+FN-F10 (Mac). BI V S Paragraph Arial 14px V QUESTION 1 The department manager is using a combination of methods to forecast sales of tonsters at a local department store. The demanders shown in the be Week Actu Demand 11 24 bo 2 bas x III A Using trend projection, calculate foresting values for week and week & Show details of your answer For the toolbar, pro ALT.F10 PC) O ALT.FN.F10 Mac BIS Paragraph Arial 14 Focus Chile we state

Answers

The estimated demand for Week 4 is 36.3

MAD(Mean Absolute Deviation) is used to calculate the average difference between forecast values and actual values. It calculates the deviation by taking the absolute value of the difference between actual and forecasted demand. The formula to calculate Mean Absolute Deviation is:

MAD= Sum of| Actual demand - Forecast demand | / number of periods

In the given table, the Actual demand is shown as B and the forecast demand is shown as F.

B Actual Forecast 11 40 41 35 38 3 38 35 33 30

Calculation of MAD:

Actual (B) Forecast (F) |B-F|11 40 29.041 35 5.043 38 0.053 3 35.054 38 3.055 35 0.056 33 3.057 30 3.058 0.0 30.0Total 103.0

The number of periods is 9 as shown in the table.

MAD= 103/9MAD= 11.44

Mean Squared Error (MSE) measures the average squared difference between the actual and forecasted values. The formula for MSE is:

MSE= Sum of (Actual demand - Forecast demand)^2 / number of periods.

Calculation of MSE:

Actual (B) Forecast (F) (B-F)^2 11 40 841 35 25 625 38 0 0 3 35 484 38 0 0 35 33 4 30 0 900Total 2854

The number of periods is 9 as shown in the table.

MSE= 2854/9MSE= 317.1

Therefore, the calculated MAD is 11.44 and MSE is 317.1.

Trend Projection formula is given by:

Y = a + bx

where Y is the estimated demand for a particular period.

a is the Y-intercept

b is the slope of the regression line x is the period number

In the given table, the Week number is shown as X and the Actual demand is shown as Y.

Week number Actual Demand 11 24 22 29

Using trend projection for Week 3, we can calculate the demand as follows:

Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*22 - 1*24)/(2*3 - 1*1) = 20/5 = 4

Intercept (a) = Σy/n - b(Σx/n) =(24+22)/2 - 4(2/2) = 23Y = a + bx = 23 + 4(3) = 35

Therefore, the estimated demand for Week 3 is 35.

Using trend projection for Week 4, we can calculate the demand as follows:

Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*29 - 1*24)/(2*5 - 1*1) = 34/9 = 3.78

Intercept (a) = Σy/n - b(Σx/n) =(24+22+29)/3 - 3.78(2.0) = 21.5Y = a + bx = 21.5 + 3.78(4) = 36.3

Therefore, the estimated demand for Week 4 is 36.3.

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a 40 kg boy dives horizontally off a 600 kg raft. if the boy's speed at the moment he is leaving the raft is 4.0 m/s, what is the raft's speed? group of answer choices 0.56 m/s 0.60 m/s 0.26 m/s 4.0 m/s

Answers

The speed of the raft when the 40 kg boy dives horizontally off it at a speed of 4.0 m/s is 0.60 m/s.

According to the law of conservation of momentum, the total momentum before the boy jumps off the raft is equal to the total momentum after he jumps off. The momentum of an object is given by the product of its mass and velocity.

Let the initial velocity of the raft be v (which is what we need to find), and the final velocity of the boy be v_boy = 4.0 m/s. The mass of the boy is 40 kg, and the mass of the raft is 600 kg.

Before the boy jumps off, the total momentum is the sum of the momentum of the boy and the momentum of the raft. After the boy jumps off, the momentum of the boy becomes zero, and only the momentum of the raft remains.

The initial momentum is given by the product of the mass and velocity of the boy: momentum_initial = 40 kg * 4.0 m/s.

The final momentum is the product of the mass and velocity of the raft: momentum_final = 600 kg * v.

Since momentum is conserved, we can equate the initial momentum to the final momentum: momentum_initial = momentum_final.

40 kg * 4.0 m/s = 600 kg * v.

Simplifying the equation, we find: v = (40 kg * 4.0 m/s) / 600 kg.

Calculating this, we get v ≈ 0.2667 m/s, which can be rounded to 0.26 m/s.

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In which direction does an applied force move an object?

Question 1 options:

independent of the force


in the opposite direction of the force


in the same direction as the force


perpendicular to the force

Answers

Answer:

in the opposite direction of the force

Answer:

The force applied moves the object in the direction of the force. Suppose if the force is applied to the moving object in that case object moves in the direction of the stronger force. Thus, according to the given question the applied force moves the object in its direction.

that means it's the 2nd option( in the opposite direction of the force

i need help please

The temperature at Houston is around 76ºF (24ºC). at Austin, about 200 km to the west-northwest, the temperature is 36ºF(2ºC). The temperature at the midway point is 50ºF(10ºC) and the wind is blowing at 10 ms-1 from the west-northwest. If the temperature advection remains constant, what will the temperature at your station be in 2 hours in Houston?

Answers

Based on the given information, the temperature at your station in Houston is likely to decrease in the next 2 hours due to the constant temperature advection and is estimated to be 63.04ºF (16.8ºC).

Given the wind speed of 10 m/s from the west-northwest, we can use the concept of wind advection to adjust the temperature gradient based on the speed and direction of the wind.

First, we need to convert the wind speed from meters per second to kilometers per hour, as the temperature gradient is typically expressed in degrees per kilometer.

10 m/s is equivalent to 36 kilometers per hour (10 m/s * 3.6 km/h).

Next, we can adjust the temperature gradient based on the wind speed. The temperature change due to advection is typically estimated using a rule of thumb, which suggests that for each 10 kilometers per hour of wind speed, the temperature change is approximately 1 degree Celsius (or 1.8 degrees Fahrenheit) over a distance of 100 kilometers.

In this case, with a wind speed of 36 kilometers per hour, the adjusted temperature change due to advection would be approximately 3.6 degrees Celsius (or 6.48 degrees Fahrenheit) over a distance of 100 kilometers.

Now, let's calculate the temperature change at your station in Houston after 2 hours using the adjusted temperature gradient.

Temperature change = Adjusted temperature gradient × Distance × Time

Temperature change = 3.6°C/200 km * 200 km * 2 hours

Calculating the result, the temperature at your station in Houston is estimated to decrease by 7.2 degrees Celsius (or 12.96 degrees Fahrenheit) after 2 hours.

To find the final temperature at your station, subtract this temperature change from the initial temperature of 76ºF (24ºC):

Final temperature = Initial temperature - Temperature change

Final temperature = 76ºF (24ºC) - 12.96ºF (7.2ºC)

The estimated final temperature at your station in Houston after 2 hours is approximately 63.04ºF (16.8ºC).

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Two 10.-ohm resistors have an equivalent resistance of 5.0 ohms when connected in an electric circuit with a source of potential difference. Using circuit symbols found below, draw a diagram of this
circuit.

Two 10.-ohm resistors have an equivalent resistance of 5.0 ohms when connected in an electric circuit

Answers

The resistors are connected in parallel between the terminals of a battery.

Note: If those resistors are connected in parallel, then their equivalent resistance is already 5 ohms, even if they're still in the drawer or in a box on the shelf. They don't have to be connected to a source of voltage for that to happen.

A uniform solid cylinder I = 0.5MR2 with radius R = 0.250 m and mass M = 5.00 kg starts from rest and spins up to 52.4 rad/s in 30.0 s. Assuming a constant angular acceleration, the net torque is a. 3.13 mN b.5.79 mN c. 0.273 m d. 9.19 m e. 1.25 mN

Answers

The net torque is closest to option (d) 9.19 mN. To solve this problem, we can use the equation for rotational motion: θ = θ0 + ω0t + 1/2αt²

θ is the final angular displacement, θ0 is the initial angular displacement (which is zero in this case), ω0 is the initial angular velocity (also zero), t is the time elapsed, and α is the angular acceleration.

We can rearrange this equation to solve for α:

α = 2(θ - θ0 - ω0t) / t²

In this problem, θ is the final angular displacement, which is 52.4 radians. θ0 and ω0 are both zero. t is 30 seconds. Plugging in these values, we get:

α = 2(52.4 - 0 - 0) / (30)² = 0.038 rad/s²

Now we can use the equation for torque:

τ = Iα

where τ is the net torque, I is the moment of inertia (which is given as 0.5MR² for a uniform solid cylinder), and α is the angular acceleration we just calculated.

Plugging in the values, we get:

τ = (0.5MR²)(0.038) = (0.5)(5.00 kg)(0.250 m)^2(0.038) = 0.4625 Nm

We can convert this to millinewton-meters (mN) by multiplying by 1000:

τ = 462.5 mN

Therefore, the net torque is closest to option (d) 9.19 mN.

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An alpha particle (a He nucleus, containing two protons and two neutrons and having a mass of 6.64x10-27 kg) traveling horizontally at 35.6 km/s enters a uniform, vertical, 1.20 T magnetic field. Part A: what is the diameter of the path followed by this alpha particle (3 significant figures)
Part C: what is the magnitude of the acceleration of the alpha particle while it is in the magnetic field?

Answers

Part A: The diameter of the path followed by the alpha particle is approximately 0.285 meters (to 3 significant figures).

The path followed by a charged particle in a magnetic field can be determined using the formula for the radius of the circular path: r = (m*v) / (q*B), where r is the radius, m is the mass of the particle, v is its velocity, q is its charge, and B is the magnetic field strength.

Given the mass of the alpha particle (m = 6.64x10^(-27) kg), its velocity (v = 35.6 km/s = 35.6x10^3 m/s), the charge of an alpha particle (q = 2 times the charge of an electron), and the magnetic field strength (B = 1.20 T), we can calculate the radius of the path.

Plugging in the values into the formula, we have: r = (6.64x10^(-27) kg * 35.6x10^3 m/s) / (2 * 1.60x10^(-19) C * 1.20 T) = 0.285 meters.

Therefore, the diameter of the path followed by the alpha particle is approximately 0.285 meters.

Part C: The magnitude of the acceleration of the alpha particle while it is in the magnetic field is 8.92x10^12 m/s^2 (to 3 significant figures).

The acceleration of a charged particle moving in a magnetic field is given by the formula: a = (q * v * B) / m, where a is the acceleration, q is the charge of the particle, v is its velocity, B is the magnetic field strength, and m is its mass.

Using the given values, we can calculate the acceleration: a = (2 * 1.60x10^(-19) C * 35.6x10^3 m/s * 1.20 T) / 6.64x10^(-27) kg = 8.92x10^12 m/s^2.

Therefore, the magnitude of the acceleration of the alpha particle while it is in the magnetic field is approximately 8.92x10^12 m/s^2.

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Using a cable with a tension of 1350 N , a tow truck pulls a car 5.00 km alond a horizontal roadway. (a) how much work does the cable do on the car if it puls horizontally ? if it pulls at 35.0 degrees above the horizontal ? (b) how much work does the cable do on the tow truck in both cases of part (a)? (c) how much work does gravity do on the car in part (a)?

Answers

Using a cable with a tension of 1350 N , a tow truck pulls a car 5.00 km alone a horizontal roadway. Therefore,

(a) Cable work: 6,750,000 J horizontally.

(b) Cable work: 6,308,250 J at 35.0° above horizontal.

(c) No work by gravity.

To calculate the work done by the cable in each scenario, we need to consider the angle between the direction of the force applied and the displacement.

(a) If the cable pulls horizontally (0° above the horizontal):

In this case, the angle between the force and the displacement is 0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(0°)

Work = 1350 N * 5000 m * 1

Work = 6,750,000 J

The cable does 6,750,000 Joules of work on the car when it pulls horizontally.

(b) If the cable pulls at 35.0 degrees above the horizontal:

In this case, the angle between the force and the displacement is 35.0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(35.0°)

Work = 1350 N * 5000 m * 0.819

Work = 6,308,250 J

The cable does approximately 6,308,250 Joules of work on the car when it pulls at 35.0 degrees above the horizontal.

(c) The work done by gravity on the car is zero because gravity acts vertically downward, perpendicular to the displacement along the horizontal roadway. Therefore, the gravitational force does not contribute to the work done on the car in this scenario.

In both cases (a) and (b), the cable does the same amount of work on the tow truck as on the car since they are connected by the cable. So the work done by the cable on the tow truck would be equal to the values calculated above: 6,750,000 J in case (a) and 6,308,250 J in case (b).

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Science and technology are

Answers

Answer:  Science encompasses the systematic study of the structure and behaviour of the physical and natural world through observation and experiment, and technology is the application of scientific knowledge for practical purposes.

Explanation: this should help

Which of the following is NOT an application of laser light?Select one:a.cutting materialb.precision surgeryc.satellite communication d.calibration of telescopes

Answers

Given:

The uses of LASER light

To find:

Which is not an application of LASER light

Explanation:

When cutting stainless steel or aluminium, LASER beams are used.

To remove warts, moles, sunspots, and tattoos in human bodies LASER lights are used.

LASER is used in communication also. Laser communication in space is the use of free-space optical communication in outer space.

One of the most important uses for lasers in astronomy is to reduce distortion on images taken with ground-based telescopes. So directly we cannot say that LASER is used for the calibration of telescopes.

Hence, calibration of telescopes is not an application of LASER light.

What is the net force in this image?


a
8000 N right
b
5000 N right
c
4000 N right
d
4000 N left
e
5000 N left
f
8000 N left

What is the net force in this image? a8000 N right b5000 N right c4000 N right d4000 N left e5000 N left

Answers

Answer:

4000N left

Explanation:

6000N-1000N-1000N

6000N-2000N

8000N

What are the si units

Answers

Answer:

The uniy which is accepted all over the world is called SI unit.

Explanation:

The system of measurement that is agreed by the international convention if scientists that is held in paris of France to adopt an international unit is called SI unit unit.

During the spin cycle the wash machine that cloths stick to the outer wall the barrel as it spins at a rate as high as 1950 rpm the radius of the barrel inside the wash machine is 0.5 m what is the speed of the clothes as a spin in the barrel?

Answers

The linear speed of the clothes as a spin in the barrel is 102.1 m/s.

What is the linear speed of the clothes?

The linear speed of the clothes is the measure of the change of displacement of the clothes with time.

Mathematically, the formula for linear speed is given as;

v = ωr

where;

v is the linear speed of the clothesω is the angular speed of the clothesr is the radius of the barrel

The angular speed of the wash machine is given as;

ω = 1950 rpm = 1950 rev/min x 2π rad/rev x 1 min/60 s = 204.2 rad/s

v = 204.2 rad/s x 0.5 m

v = 102.1 m/s

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Which term is defined as the amount of charge stored per volt?
A. capacitance
B. potential difference
C. potential energy
D. electric potential

Answers

The answer is A capacitance

An object that is moving in a circle experiences centripetal acceleration, this acceleration affects which aspect of the object's velocity vector?


A: MASS

B: VELOCITY

C: DIRECTION

D: MAGNITUDE

Answers

Centripetal acceleration is the acceleration experienced by an object moving in a circular path toward the center of the circle. This acceleration affects the direction of the object's velocity vector, which is always tangent to the circle.

As the object moves in a circle, its direction of motion changes continuously, and hence the direction of the velocity vector also changes. However, the magnitude of the velocity vector remains constant, assuming that the speed of the object is constant. So, centripetal acceleration affects the direction of the object's velocity vector, but not its magnitude or mass. An object moving in a circle experiences centripetal acceleration, which affects the direction (C) aspect of the object's velocity vector. This acceleration causes the object to continuously change its direction while maintaining a constant speed, allowing it to move in a circular path.

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How many kcalories are provided by a food that contains 25 g carbohydrate, 6 g protein, and 5 g fat?

Answers

169 Kcalories are provided by a portion of food that has 25 grams of carbs, 6 grams of protein, and 5 grams of fat.

Kcalories mean kilo-calories. Basically, kilo-calorie or kcal refers to 1,000 calories. To get the Kcalories of food, you have to add the kcal of carbohydrates, protein, and fat.

Get the product by multiplying the number of grams of carbohydrate, protein, and fat by 4,4, and 9, respectively. So if you want to get the energy or Kcal available from a meal, you must then combine the outcomes.

Simply put it, take note of the following conversions:

1 gram of carbohydrate is 4kcal1 gram of protein is also 4kcalThough, 1 gram of fat is 9kcal

So here's how to compute the Kcalories of food that contains 25g carbs, 6g protein, and 5g fat.

1.    25g x 4kcal/g = 100kcal

2.    6g x 4kcal/g = 24kcal

3.    5g x 9kcal/g = 45kcal

4.    100kcal + 24kcal + 45kcal = 169kcal!


Therefore, the food contains 169 kilo-calories!

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How many kcalories are provided by a food that contains 25 g carbohydrate, 6 g protein, and 5 g fat?

14.a box of mass 40kg has a base of area 10m2 .calculate the pressure exerted by it on the ground (use 1kg-f=10n).

Answers

The pressure exerted by a box on the ground can be calculated by dividing the force exerted by the box on the ground by the area of the base of the box.

The force exerted by the box can be calculated using Newton's second law, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a). In this case, the mass of the box is given as 40 kg. Since the box is at rest on the ground, the acceleration is 0. Therefore, the force exerted by the box is 0 N.

To calculate pressure, we need to convert the force from newtons to kilogram-force. Since 1 kg-f = 10 N, the force can be expressed as 0 N / 10 = 0 kg-f.

The pressure exerted by the box on the ground is calculated by dividing the force by the area of the base of the box. The area is given as 10 m^2. Therefore, the pressure exerted by the box on the ground is 0 kg-f / 10 m^2 = 0 kg-f/m^2.

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a. What is the overall displacement Δx of the particle?b. What is the average velocity vav of the particle over the time interval Δt=50.0s ?c. What is the instantaneous velocity v of the particle at t=10.0s?

Answers

a. The overall displacement Δx of the particle is 75 m to the east.

b. The average velocity vav of the particle over the time interval Δt=50.0s is 1.5 m/s to the east.

c. To find the instantaneous velocity v of the particle at t=10.0s, we can calculate the derivative of the position function x(t) with respect to time t at t=10.0s.

From the given position function x(t) = 0.25t³ - 1.5t² + 3t, we can find the velocity function v(t) by taking the derivative: v(t) = dx/dt = 0.75t² - 3t + 3. At t=10.0s, the instantaneous velocity v of the particle is v(10.0) = 57.0 m/s to the east.

The displacement of the particle can be found by subtracting its initial position from its final position, which gives Δx = x(60.0s) - x(10.0s) = 3000 m - 2925 m = 75 m to the east. The average velocity of the particle over the time interval is given by the formula vav = Δx/Δt = 75 m/50.0 s = 1.5 m/s to the east.

Finally, the instantaneous velocity of the particle at t=10.0s can be found by taking the derivative of the position function x(t) with respect to time t and evaluating it at t=10.0s, giving the value of the velocity at that instant.

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Final answer:

Calculations of displacement, average velocity, and instantaneous velocity require specific information about the motion of the particle. Each of these calculations can be performed using calculus when the motion of the particle is defined as a function of time.

Explanation:

The questions are about the interpretation of the motion and the velocity of a particle. However, the actual values, for displacement Δx, average velocity vav, and instantaneous velocity v, could not be directly calculated without additional specific information about the motion of the particle. But here's a general method:

a. The overall displacement, Δx, of the particle can be calculated by integrating the velocity function, v(t), over the time interval.

b. The average velocity, vav, of a particle over a time interval, Δt, can be found by dividing the total displacement, Δx, by the total time, Δt.

c. The instantaneous velocity, v, of a particle at a specific time, t, can be calculated by taking the derivative of the position function, x(t), at that time.

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a. l1 =20 A and l2 =24 A
B. l1 = 20A and l2 = 12 A
C. l1 = 26 A and l2 = 12 A
D. l1 = 24 A and l2 = 8 A

a. l1 =20 A and l2 =24 AB. l1 = 20A and l2 = 12 AC. l1 = 26 A and l2 = 12 AD. l1 = 24 A and l2 = 8 A

Answers

Answer:

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Find the total distance a car would travel if it moves 5 km East and then turns and travels 48 km West.

Answers

Answer:

53km

Explanation:

The total distance covered by the car will be the sum total of the distance moved during the journey.

Distance moved towards east = 5 km

Distance moved towards west = 48km

Total distance covered = Distance moved towards east+Distance moved towards east

Total distance covered  = 5km+48km

Total distance covered  = 53km

Hence the total distance a car would travel if it moves 5 km East and then turns and travels 48 km West is 53km

a ball is swung in a vertical circle such that at one point along its circular path the forces exerted on the ball can be represented by the free body diagram. the magnitude of the tension force exerted on the ball, t, is twice that of the force due to gravity exerted on the ball from earth, fg. what is the location of the ball, and what is the magnitude of the centripetal acceleration of the ball?

Answers

Location of the ball is top of the circle and acceleration is 3g.

Since tension force is more, surely ball is having net force upward and hence, the location of the ball in this case is top of the circle.

Any object that moves in a circle has an acceleration vector towards the center of that circle. This is known as Centripetal acceleration.

total force/ net force when ball is top of the circle is sum of tension force and gravity force.

\(F_{net\) = T + mg

Because of this net force, there is centripetal acceleration towards the center.

so, T + mg = ma

2mg + mg = ma

3mg = ma

a = 3 × force of gravity

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a loaf of bread is removed from an oven at350° f and cooled in a room whose temperature is70° f. ifthe bread cools to210° f in 20 minutes,how much longer will it take the bread to cool to140° f.

Answers

It will take the bread an additional 54.8 minutes to cool from 210° F to 140° F.

The rate of cooling of the bread is directly proportional to the difference between the temperature of the bread and the surrounding temperature. Therefore, we can use the formula:
T(t) = T_s + (T_0 - T_s) e^(-kt)
where T(t) is the temperature of the bread at time t, T_0 is the initial temperature of the bread (350° F), T_s is the surrounding temperature (70° F), and k is a constant that depends on the properties of the bread and the room. We can use the fact that the bread cools to 210° F in 20 minutes to find k:
210 = 70 + (350 - 70) e^(-k*20)
Simplifying and solving for k, we get k = 0.0441 min^-1. Now we can use the same formula to find how long it will take for the bread to cool to 140° F:
140 = 70 + (350 - 70) e^(-0.0441t)
Solving for t, we get t = 54.8 minutes. Therefore, it will take the bread an additional 54.8 minutes to cool from 210° F to 140° F.

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what is the height of the image of a person on the screen who is 3.0 cm tall on the display? express your answer with the appropriate units.

Answers

The height of the image of a person formed by a plane mirror is equal to the height of the person.

The height of the image of a person formed by a plane mirror is equal to the height of the person itself. When an object, such as a person, is placed in front of a plane mirror, the mirror creates a virtual image that appears to be behind the mirror.

The virtual image has the same size as the object and is located at the same distance behind the mirror as the object is in front of it.

Since a plane mirror does not introduce any magnification or distortion, the height of the image will be identical to the height of the person. The mirror simply reflects the light rays in a way that creates the illusion of an image, maintaining the proportions and size of the object.

Therefore, the height of the image of a person formed by a plane mirror is equal to the height of the person.

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The correct question would be as

What is the height of the image of a person formed by a plane mirror?

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