Twenty points question

Answer:

\(l\leq 46.75\)

Step-by-step explanation:

Put the closed endpoint at 46.75 with the arrow pointing left.

Answer:  \(\ell \le 46.75\)  (fourth choice)

Graph has a closed endpoint at 46.75 and the ray pointing to the left (i.e. shading is to the left).

Check out the diagram below.

==================================================

Explanation:

The phrasing "at most" means that's the highest ceiling possible. The longest the cape can be is 46.75 inches. So it could be this length or shorter.

If \(\ell\) is this length, then either \(\ell = 46.75\) or \(\ell < 46.75\)

We can combine those two statements into the final answer of \(\ell \le 46.75\)

The graph involves a closed point at this marker to include the endpoint (in contrast an open hole would leave the endpoint out). The shading is to the left to include every value smaller than 46.75

Realistically the smallest \(\ell\) can get is \(\ell = 0\), but we don't have to worry too much about this. This is because zero isn't anywhere near these shown values on the number line.

Answer:

Step-by-step explanation:

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The probability of the baseball player getting exactly 4 hits out of 10 times at bat is approximately 0.161, or 16.1%.

To calculate the probability of a baseball player getting exactly 4 hits out of 10 times he was up at bat, we need to use the binomial probability formula.

The binomial probability formula is given by:P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

Where:

P(X = k) is the probability of getting exactly k hits

n is the total number of trials (in this case, the player's 10 times at bat)

k is the number of successful trials (in this case, 4 hits)

p is the probability of success in a single trial (in this case, the player's batting average, 0.298)

(1 - p) is the probability of failure in a single trial

Plugging in the values:

P(X = 4) = C(10, 4) * (0.298)^4 * (1 - 0.298)^(10 - 4)

Using the combination formula C(n, k) = n! / (k! * (n - k)!):

P(X = 4) = 10! / (4! * (10 - 4)!) * (0.298)^4 * (1 - 0.298)^(10 - 4)

Calculating the values:

P(X = 4) ≈ 0.161

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instantaneous rate of change of the search length 0.1667 seconds per

We need to take the derivative of the function S(n) with respect to n and evaluate it at n=12 in order to determine the instantaneous rate of change of the search length for a set of 12 articles.

Taking the derivative of S(n) with respect to n using the chain rule, we get:

S'(n) = 1.6 * (1/(0.8n)) * 0.8 = 2/n

Evaluating this expression at n=12, we get:

S'(12) = 2/12 = 0.1667 seconds per article

This indicates that the search time will increase by approximately 0.1667 seconds per article if the set contains 12 articles by one unit. Alternately, the search time per article will decrease by approximately 0.1667 seconds if the set's number of articles decreases by one unit from 12.

Therefore, the units for the instantaneous rate of change are "seconds per article", indicating the change in search time for each additional or fewer article in the set.

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From both the table and the graph, it can be concluded that the points given in the table lies on the parabola y =  x²  

What is graph of a function ?

At first it is important to know about function.

A function from A to B is a rule that assigns to each element of A a unique element of B. A is called the domain of the function and B is called the codomain of the function.

There are different operations on functions like addition, subtraction, multiplication, division and composition of functions.

Graph of a function f(x) is the collection of points of the form (x, f(x))

x           x²                 (x, y)

-3        9                   (-3, 9)

-2        4                   (-2, 4)

-1         1                    (-1, 1)

0        0                   (0, 0)

1         1                     (1, 1)

2        4                    (2, 4)

3         9                   (3, 9)

The graph has been attached

From both the table and the graph, it can be concluded that the points given in the table lies on the parabola y =  x²  

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Answer:

D

Step-by-step explanation:

You dont know what the number is, so replace that with the variable X. Now, more than is a reversal term and it means to add. So, the equation will be

x + 44

Hope this helps you!!  :)

Answer:

Yes

Step-by-step explanation:

Answer: 19 months

Step-by-step explanation:

given data:

amount paid initially when joining the club = $50.

monthly payments made = $10.

total amount paid since joining the club = $240.

Solution:

= 10X + 50 = 240

collect like terms

= 10X = 240 – 50

10X = 190

divide both sides by 10

10X/10 = 190/10

X = 19

isabella has been a member of the club for 19 months.

Answer:

1,500 square feet

Step-by-step explanation:

you have to convert yards to feet and multiply

Answer:

2.685 + 2.685 + 2.685 + 2.685 + 2.685 + 2.685. . . . . 102 times.

Step-by-step explanation:

Think of this as 102 times of 2.685.

So you would add 2.685 together 102 times.

(I didn't want to type out 2.685 that many times)

Hope I helped :)

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Answer:

richard is 22 and teo is 9

Step-by-step explanation:

The total amount the man had = 52,200 rupees. Out of this, he gave 21,750 rupees to his son, 13,050 rupees to his daughter, and 17,400 rupees to his wife , the total amount given away by the man = 21,750 + 13,050 + 17,400 = 52,200 rupees.

A man gave 5/12 of his money to his son, 3/7 of the remainder to his daughter, and the remaining to his wife. If his wife gets Rs. 8,700, what is the total amount?

The given problem can be solved using the concept of ratios and fractions. Let us solve the problem step-by-step.Assume the man had x rupees with him.The man gave 5/12 of his money to his son.

The remaining amount left with the man = x - 5x/12= (12x/12) - (5x/12) = (7x/12)The man gave 3/7 of the remainder to his daughter.'

Amount left with the man after giving it to his son = (7x/12)The amount given to the daughter = (3/7) x (7x/12)= (3x/4)The remaining amount left with the man = (7x/12) - (3x/4)= (7x/12) - (9x/12) = - (2x/12) = - (x/6) (As the man has given more money than what he had with him).

Therefore, the daughter's amount is (3x/4) and the remaining amount left with the man is (x/6).The man gave all the remaining amount to his wife.

Therefore, the amount given to the wife is (x/6) = 8700Let us find the value of x.x/6 = 8700 x = 6 x 8700 = 52,200

Therefore, the man had 52,200 rupees with him.He gave 5/12 of his money to his son. Therefore, the amount given to his son is (5/12) x 52,200 = 21,750 rupees.

The remaining amount left with the man = (7/12) x 52,200 = 30,450 rupees.He gave 3/7 of the remainder to his daughter. Therefore, the amount given to his daughter is (3/7) x 30,450 = 13,050 rupees.

The amount left with the man = (4/7) x 30,450 = 17,400 rupees.The man gave 17,400 rupees to his wife.
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For the  trigonometric identity

11. If cos 27° = x, then the value of tan 63° interims of "x" is  x/√1 - x²

12. If Θ be an acute angle and 7sin²Θ + 3 cos²Θ= 4, then tan Θ is  1/√3

13. The value of tan 80° × tan 10° + sin² 70° + sin² 20° is 2

14. The value of (sin 47°/cos 43°)² + (cos 43°/sin 47°) -  4 cos²45° is 0

15. If 2 (cos²Θ - sin²Θ) = 1, Θ is a positive acute angle them the value of Θ is  30°

16. If 5 tan Θ = 4, then (5 sin Θ - 3 cos Θ)/(5 sin Θ + 2 cos Θ) is equal to 1/6

17. If sin(x + 20)° = cos (x + 10)° then the value of "x" is  30°

18. The value of (sin 65°)/ (cos 25°) is 1

To solve the various   trigonometric identity;

11. Given: cos 27° = x

We know that cos (90 - θ) = sin θ

So, cos 63° = sin 27°

And sin 63° = √1 - cos²27°

Substituting cos 27° = x, we get

sin 63° = √1 - x²

Therefore, Therefore, tan 63° = sin 63° / cos 63° = cos 27° / cos 63° = x / cos 63°.

= x/√1 - x²

12. Given: Θ is an acute angle and 7sin²Θ + 3 cos²Θ= 4

Since Θ is an acute angle, sin²Θ + cos²Θ = 1

Substituting sin²Θ + cos²Θ = 1 into the equation 7sin²Θ + 3 cos²Θ= 4, we get

7 (sin²Θ/ cos²Θ) + 3 = 4/cos²Θ - 4 sec²Θ

⇒ 7tan²Θ + 3 = 4(1 + tan²Θ)

⇒ 7tan²Θ + 3 = 4 + 4 tan²Θ

⇒3 tan²Θ = 1

⇒ tan²Θ = 1/3

⇒ tanΘ = 1/√3

13. For tan 80° × tan 10° + sin² 70° + sin² 20°

⇒ tan 80° = cot (90 - 80)° = cot 10°

⇒  sin 70° = cos (90 - 70) = cos 20°

⇒ cot 10° × tan 10° +  cos 20° + sin² 20°

= 1 + 1 = 2

14. (sin 47°/cos 43°)² + (cos 43°/sin 47°) - 4 cos²45°

= (sin 47°/cos43°)² + (cos 43°/sin 47°)² - 4(1/√2)²

= (sin (90° - 43°)/cos43°)² +  (cos (90° - 47°)/sin)²  = 4(1/2)

= (cos 43°/cos 43°)² + (sin 47°/ sin   47°)² - 2

= 1 + 1 - 2 = 0

15. 2 (cos²Θ - sin²Θ) = 1

cos²Θ - sin²Θ = 1/2

Since Θ is an acute angle, sin²Θ + cos²Θ = 1

Substituting sin²Θ + cos²Θ = 1 into the equation cos²Θ - sin²Θ = 1/2, we get

cos²Θ - (1 - cos²Θ) = 1/2

2cos²Θ = 3/2

cos Θ = √3/2(cos 30° = (√3)/2

= 30°

16. Given: 5 tan Θ = 4

We know that tan Θ = sin Θ / cos Θ

So, 5 sin Θ / cos Θ = 4

5 sin Θ = 4 cos Θ

Dividing both sides of the equation by 5, we get

sin Θ / cos Θ = 4/5

∴ sin Θ = 4/5 cos Θ

given that the expression is (5 sin Θ - 3 cos Θ)/(5 sin Θ + 2 cos Θ)

we substitute sin Θ = 4/5 cos Θ  into the equation

⇒(5 × 4/5 cos Θ  - 3 cos Θ)/(5 × 4/5 cos Θ  + 2 cos Θ)

= (4-3)/(4 + 2) = 1/6

17. Given: sin(x + 20)° = cos (x + 10)°

We know that sin(90 - θ) = cos θ

So, sin(x - 20)° = sin(90 - (3x + 10))°

⇒ (x - 20)° = (90 - (3x + 10))°

⇒ x - 20° = 90° - 3x + 10

⇒ 4 x = 120°

⇒ x = 120°/4

⇒ x = 30°

18. To find the value of (sin 65°) / (cos 25°), we can use the trigonometric identity:

To solve this, we can use the following trigonometric identities:

sin(90 - θ) = cos θ

cos(90 - θ) = sin θ

We can also use the fact that sin²θ + cos²θ = 1.

Rewrite sin (65°) / cos (25°)

⇒ sin (65°) = cos (25°)

∴ cos (25°)/ cos (25°) = 1

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★ Volume of cylinder :-

Here,

We have :

Substituting the values :

> V = π (2 × 2) × 7

> V = 4π × 7

> V = 28π

★ Volume of cone :-

We have :

Substituting the values :

> V = ⅓ × π × (2 × 2) × 6

> V = ⅓ × π × 4 × 6

> V = ⅓ × π × 24

> V = 8π

★ According to the question :-

Adding them together,

> Total Volume = 8π + 28π

> Total Volume = 36π

\(Total \: \: \: Volume = (88+176) {cm}^{2} \\ \\ = 264 {cm}^{2} .\)

Answer:

260,000

15,000*6 = 90,000

350,000 - 90,000 = 260,000

Step-by-step explanation:

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Answer:

The answer is 12. Please please like.

Answer:

Step-by-step explanation:

Let's factor the trinomial:

x + 4 is between the answer options

Correct option is D.

y=-2x+5 is the slope-intercept equation for a line that goes through the point (4,-3) and 5 is the value of b.

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

We have to find the slope-intercept equation for a line that goes through the point (4,-3)--with a slope of -2

m=-2

Now let us find the y intercept

-3=-2(4)+b

-3=-8+b

-3+8=b

5=b

Hence, y=-2x+5 is the slope-intercept equation for a line that goes through the point (4,-3) and 5 is the value of b.

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Answer:

\(Q(-2,3) \longrightarrow Q'(-1/3, 1/2) \\ \\ R(-3,1) \longrightarrow R'(-1/2, 1/6) \\ \\ T(2,-1) \longrightarrow T'(1/3, -1/6) \\ \\ W(2,4) \longrightarrow W'(1/3, 2/3)\)

Step-by-step explanation:

For a dilation at the origin, multiply each of the coordinates by the scale factor.

\(Q(-2,3) \longrightarrow Q'(-1/3, 1/2) \\ \\ R(-3,1) \longrightarrow R'(-1/2, 1/6) \\ \\ T(2,-1) \longrightarrow T'(1/3, -1/6) \\ \\ W(2,4) \longrightarrow W'(1/3, 2/3)\)

From greatest to least5.25, 1, 3/4 (or 0.75), -5/2 (or -2.5), -8.345

To sort these numbers from largest to smallest, we must establish a consistent format for swift comparison.

Among the various numbers included are whole figures, fractions and decimals, causing us to mix them uniformly first so that they match— in decimals.

-5/2 = -2.5

5.25 = 5.25 (no alteration required)

1 = 1.0 (to simplify analysis, only adding decimal points)

3/4 = 0.75

-8.345 = -8.345 (essentially unchanged)

At this point, we can effortlessly contrast and compare the numbers.

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The required probability of giving class period run between 51.5 and 51.75 is 0.125.

The lengths of her classes are uniformly distributed between 50 and 52 minutes.

Probability, can be define as the ratio of favorable events to the n number of total events.

since,

\(p(r) = \frac{51.75-51.5}{52-50}\)

p(r) = 0.125

Thus, the required probability of class period runs between 51.5 and 51.75 is given by 0.125

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well, the profit is clearly just 490 - 350 = 140.

Now, if we take 350(origin amount) to be the 100%, what is 140 off of it in percentage?

\(\begin{array}{ccll} Amount&\%\\ \cline{1-2} 350 & 100\\ 140& x \end{array} \implies \cfrac{350}{140}~~=~~\cfrac{100}{x} \\\\\\ \cfrac{5}{2} ~~=~~ \cfrac{100}{x}\implies 5x=200\implies x=\cfrac{200}{5}\implies x=40\)

Answer:

D) Graph Z

Step-by-step explanation:

Convert from point-slope to slope-intercept form

\(y-6=4(x-4)\\\\y-6=4x-16\\\\y=4x-10\)

This tells us that the line intersects the y-axis at (0,-10) and that our slope is 4. Therefore, the best choice given the options is D, graph Z.

The linear equation y = 4x - 10 represents the graph z. Then the correct option is D.

A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

The linear equation is given below.

y - 6 = 4(x - 4)

Convert the equation into slope-intercept form. Then we have

y - 6 = 4(x - 4)

y - 6 = 4x - 16

y = 4x - 16 + 6

y = 4x - 10

The slope of the line is 4 and the y-intercept of the line is negative 10. Then the equation represents the graph z, then option D is correct.

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Answer:

4a^3

Step-by-step explanation:

Please check the attached photo.

The fractions on the number line are 1/8, 2/8, 3/8, 4/8, 5/8, 6/8, 7/8

The range of the number line is given as:

Range = 1/8 to 7/8

Using an increment of 1/8, the fractions on the number line are:

1/8, 2/8, 3/8, 4/8, 5/8, 6/8, 7/8

Next, we plot the number line where the above fractions are placed on the number line

See attachment for the required number line.

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