The statement suggests that there are 24 specific objects that transmit complex radio codes, including time signals traveling at the speed of light. It also states that you can contact at least 4 of these objects at any time of day or night.
Based on this information, it seems like the objects being referred to are satellites. Satellites are objects that orbit the Earth and can transmit signals for various purposes, including time synchronization.
One example of such satellites is the Global Positioning System (GPS) satellites.
The GPS system consists of a network of satellites that transmit signals to GPS receivers on Earth, enabling us to determine our precise location and time.
In conclusion, the main answer to the question is that the 24 specific objects mentioned are likely satellites, such as GPS satellites, that transmit complex radio codes, including time signals. You can contact at least 4 of these objects at any time of day or night.
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how much fluid a pump can move in one revolution is referred to as ____.
Hi! The term you're looking for is "displacement." Displacement refers to the amount of fluid a pump can move in one revolution. This is an important characteristic to consider when selecting a pump for a specific application, as it helps determine the overall efficiency and performance of the pump.
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Two forces are applied to a 2. 0 kg block on a frictionless horizontal surface. F1 = 8. ON is applied to the left while F2 = 3. 0 N is applied to the right. What is the
acceleration of the block?
A. ) 2. 5 m/s^2 to the left
B. ) 1. 5 m/s^2 to the right
C. ) 4. 0 m/s^2 to the left
D. ) 2. 5 m/s^2 to the right
The string of a violin A vibrates 12 times in 4 seconds while string of violin B vibrates 18
times in 6 seconds. Compare the frequencies of both.
Because the string of a violin A vibrates 12 times in 4 seconds and the string of a violin B vibrates 18 times in 6 seconds, their frequencies are equal; that is, the string of a violin A and the string of a violin B have the same frequency of 3 Hz.
What is the calculation of the frequency of the violin?The frequency of a string = number of complete cycles of vibration per unit time, and the calculation is given below,
For string A, the frequency is,
frequency = number of vibrations / time frequency
frequency = 12 vibrations / 4 sec= 3 Hz
For string B, the frequency is,
frequency = number of vibrations / time frequency
frequency = 18 vibrations / 6 sec = 3 Hz
Hence, because the string of a violin A vibrates 12 times in 4 seconds and the string of a violin B vibrates 18 times in 6 seconds, their frequencies are equal; that is, the string of a violin A and the string of a violin B have the same frequency of 3 Hz.
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A barrel of oil contains roughly 6.1×109 J. How many kW-hr is this? Answer in units of kW-hr
Answer: 1.6958*10^3 kW-hr
Explanation:
The barrel of oil contains around 6.1*10^9 J of energy.
We want this energy expressed in kW-hr.
We know that:
1J = 2.78*10^(-7) kW-hr
Then 6.1*10^9 J will be equal to 6.1*10^9 times the above amount.
This is:
E = (6.1*10^9)*(2.78*10^(-7) kW-hr) = (6.1*2.78)*(10^9*10^(-7)) kW-hr
= 16.958*10^(9 - 7) kW-hr
= 16.958*10^2 kW-hr
= 1.6958*10^3 kW-hr
Energy is the ability to do work. There are a few types of energy, these types are as follows:-
Heat enegyWind energyLight energyThe barrel of oil contains around 6.1*10^9 J of energy. We want this energy expressed in kW-hr.
One joule of energy has 1J = 2.78*10^(-7) kW-hr .
Therefore, the \(6.1*10^9\)J will be equal to \(6.1*10^9\) times the above amount.
Hence, the energy will be
E = \((6.1*10^9)*(2.78*10^7 )\)
=\(16.958*10^9-7\)
= \(1.6958*10^3 kW-hr\)
Hence, the correct option is \(1.6958*10^3 kW-hr\)
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A fully loaded tractor-trailer traveling at 65 mph under ideal conditions takes a minimum of: A) 3 seconds to stop
B) 6 seconds to stop C) 9 seconds to stop D) 12 seconds to stop
A fully loaded tractor-trailer traveling at 65 mph under ideal conditions takes a minimum of B) 6 seconds to stop.
The stopping distance of a vehicle depends on many factors such as the speed, the weight of the vehicle, the condition of the brakes and the road surface. Assuming ideal conditions, it can be estimated that a fully loaded tractor-trailer traveling at 65 mph takes at least 6 seconds to stop. This estimate is based on the recommended following distance of at least one car length for every 10 mph of speed.
At 65 mph, the recommended following distance would be about 390 feet. It would take approximately 6 seconds to cover this distance at a constant speed, assuming no braking. However, in reality, it would take longer than 6 seconds to stop a fully loaded tractor-trailer, as braking distance increases with speed and weight.
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What is the potential energy of a 3.00 kg object at the bottom of a well 10.0 m deep as measured from ground level ? Explain the sign of the answer. (b) How much qirk is required to lift a 3.00 kg object from the bottom of the well 10.0 m deep
The potencial energy is given by the following formula:
\(E_P=\text{mgh}\)Where "m" is the mass, "g" is the acceleration of gravity, and "h" is the height. Since the height is below the reference point it has a negative sign. Replacing we get:
\(E_P=(3kg)(9.8\frac{m}{s^2})(-10m)\)Solving the operation:
\(E_P=-294J\)The negative sign indicates that the object is below the zero point.
b. Since the work is equivalent to:
\(W=Fd\)The force that acts on the object is equivalent to its weight and the distance the height, therefore:
\(W=\text{mgh}\)Replacing:
\(\begin{gathered} W=(3\operatorname{kg})(9.8\frac{m}{s^2})(10m) \\ W=294J \end{gathered}\)
A force of 29.40 N is applied tangentially to a wheel of radius 0.340 m and gives rise to an angular acceleration of 1.20 rad/s2. Calculate the rotational inertia of the wheel.
a) 12.50 kg⋅m2
b) 10.41 kg⋅m2
c) 6.25 kg⋅m2
d) 8.33 kg⋅m2
The rotational inertia of the wheel is approximately d) 8.333 kg·m².
To calculate the rotational inertia of the wheel, we can use the equation:
The torque acting on an object is equal to the product of its rotational inertia and angular acceleration.
The torque (τ) can be calculated by multiplying the force (F) by the radius (r) of the wheel:
τ = F * r
Substituting the given values:
τ = 29.40 N * 0.340 m
Now we can rearrange the equation to solve for the rotational inertia (I):
I = τ / α
Substituting the values of torque (τ) and angular acceleration (α):
I = (29.40 N * 0.340 m) / 1.20 rad/s²
Calculating the result:
I ≈ 8.333 kg·m²
Therefore, the rotational inertia of the wheel is approximately 8.333 kg·m².
The correct answer is d) 8.33 kg·m².
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A 1. 18 kg gold cube hangs at the end of a 4. 00 m long string. Rhogold = 19. 3 × 103 kg/m3; rhomercury = 13. 6 × 103 kg/m3. When the gold cube is immersed in mercury, the tension in the string, in n, is
When the gold cube is immersed in mercury, the tension in the string in Newtons is 3.142N.
What is tension?Tension is the force acting on the linear object like string, chain or rope due to pulling.
Volume of gold V = mass / density
V = 1.18 /19.3x 10³ =61.1 x 10⁻⁶ m³
Tension in the string after immersing will be
T = [ρ(Gold) -ρ(Hg)] g. V
T =[ 19.3x 10³ - 13.6 x 10³] x 9.81 x 61.1 x 10⁻⁶
T =3.416 N
Thus, the tension in the string is 3.42 N.
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The voltage waveform in the given figure is applied across a 55-μf capacitor
Answer:
Explanation:
A capacitor is an electronic component that stores and releases electrical energy. It consists of two conductive plates separated by an insulating material called a dielectric. When a voltage is applied across the plates, charge accumulates on them, creating an electric field between the plates.
The capacitance of a capacitor is a measure of its ability to store charge. It is typically represented by the symbol 'C' and is measured in farads (F). In your case, you mentioned a 55-μF (microfarad) capacitor, indicating its capacitance value.
When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The rate at which the capacitor charges and discharges depends on the capacitance and the resistance in the circuit
Since there is no figure provided in the text, I am unable to reference it for the specific details of the voltage waveform. However, I can explain the general behavior of a capacitor when a voltage waveform is applied.
When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The behavior of the capacitor is determined by its capacitance, which is given as 55 μF in this case.
As the voltage waveform varies, the capacitor stores and releases electrical charge. During the rising portion of the waveform, the capacitor charges and accumulates energy. During the falling portion, the capacitor discharges and releases the stored energy.
The exact behavior and characteristics of the voltage waveform and the charging/discharging process depend on the specific shape and frequency of the waveform. Without the specific details of the voltage waveform provided in the figure, it is challenging to provide a more detailed analysis.
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Two small point charges are charged by transferring a number of electrons from Q to q. The charges on the two points are equal and opposite, and the point charges are separated by 12.7 mm in air. Calculate the charge on Q and q if there is an attractive force of 22.5 µN between them. Use k = 8.99 x 10⁹ Nm²c-².
Two point charges of +2.00 μC and -2.00 μC are 0.100 m apart. What is the electric field at the point midway between the two charges?Group of answer choices2.88 x 107 N/C1.44 x 107 N/C7.19 x 106 N/C0 N/C
Take into account that the magnitude of electric field at point P, produced by a charge q is given by:
\(E=k\frac{q}{r^2}\)where k (9*10^9 N/m^2C^2) is the Coulomb's constant, r is the distance from the charge to the point P and q is the magnitude of the charge.
An illustration of the given situation is shown below:
As you can notice, at point P the electric fields generated by each charge point to the negative charge. The signs of the charge determine the direction of the electric field.
The magnitude of each electric field is the same, due to the distance to each charge is the same and the magnitude of the charge is equal. Then, The magnitude of the total electric field is:
\(\begin{gathered} E=E_1+E_2=2(9\cdot10^9\frac{N}{m^2C^2})(\frac{2.00\cdot10^{-6}C}{(0.05m)^2}) \\ E\approx1.44\cdot10^7\frac{N}{C} \end{gathered}\)Hence, the electric field at a point midway the given charges is approximately 1.44*10^7N/C
An object spun around in a circular motion such That’s is frequency is 24Hz . What is the period of its rotation?
Answer:
It would spin ifintely
Explanation:
ssm what is the spring constant of a spring that stores 25 j of elastic potential energy when compressed by 7.5 cm?
The spring constant for a spring that can store 25J of elastic potential energy when compressed by 7.5 cm is 8.9*10³ N/m.
given,
energy stored in the spring = E = 25J
compressed distance = x = 7.5cm = 0.075m
E = 1/2 * kx²
K = 2E/x²
= 8.9*10³ N/m
The energy that an item retains due to its position in relation to other objects, internal tensions, electric charge, or other reasons is known as potential energy in physics.
Potential energy can take many different forms. Some examples are an object's gravitational potential energy, the elastic potential energy of a stretched spring, and the electric potential energy of an electric charge in an electric field. The joule, denoted by the letter J in the International System of Units (SI), is the unit of energy.
Although it has connections to the Greek philosopher Aristotle's concept of potentiality, the word "potential energy" was first used in the 19th century by the Scottish engineer and scientist William Rankine.
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what is the speed of a 11 g bullet that, when fired into a 12 kg stationary wood block, causes the block to slide 5.2 cm across a wood table? assume that μk = 0.20.
The speed of an 11 g bullet that, when fired into a 12 kg stationary wood block, causes the block to slide 5.2 cm across a wood table is 574.7 m/s.
According to the principle of conservation of momentum, the momentum of the bullet before collision equals the sum of momentum of bullet and block after the collision. Thus: mv = (m + M)V; Here, m = 11 g = 0.011 kg (mass of bullet), M = 12 kg (mass of block), V = velocity of block and bullet after collision. v = velocity of bullet before collision.
Substituting the given values in the above equation and solving for V: 0.011v = (12 × V) - 0.20 × (12 × 9.81 × 0.052)V
0.011v / 12 - (0.20 × 12 × 9.81 × 0.052) / 12V
v / 1090.1 - 0.1017V
v / 1090.1.
The distance traveled by the block after collision is 5.2 cm or 0.052 m. Thus, V² - u² = 2as
= 2 × 0.20 × 9.81 × 0.052V² - (v / 1090.1)²
= 0.02152V² = (v / 1090.1)² + 0.02152V²
= 0.0000121 + 0.02152V²
= 0.0215321V = √0.0215321V
= 0.1466.
Thus, v = 0.1466 × 1090.1 = 574.7 m/s.
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The intensity of the radiation emitted by the oxygen sensor is directly proportional to the:
A.propagation speed of the radiation.
B.wavelength of the radiation.
C.polarization of photons emitted.
D.number of photons emitted.
The intensity of the radiation emitted by the oxygen sensor is directly proportional to the D. number of photons emitted.
The intensity of radiation refers to the amount of energy per unit time per unit area of the radiation. It is related to the number of photons emitted by the source of radiation, which is a measure of the amount of energy being released.
The propagation speed of the radiation, wavelength of the radiation, and polarization of photons emitted are not directly related to the intensity of the radiation emitted by the oxygen sensor.
Propagation speed refers to the speed at which the radiation moves through space, which is important for determining the distance traveled by the radiation.
Wavelength refers to the distance between the crests of two adjacent waves of radiation, which is important for determining the energy and frequency of the radiation.
Polarization refers to the orientation of the electric field vector of the photons emitted by the oxygen sensor, which is important for determining how the radiation interacts with matter.
In summary, the intensity of the radiation emitted by the oxygen sensor is directly proportional to the number of photons emitted.
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What 4 pieces of information should be included any time you give a written
description of motion?
Answer:
In physics, motion is the phenomenon in which an object changes its position over time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and time. ... One can also speak of motion of images, shapes, and boundaries.
Explanation:
What is technology ?
What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45. 0° when it passes through a diffraction grating that has 500. 0 lines per mm?.
Answer:
1414.21 nm
Explanation:
diffraction grating equation is
d sin θ = nλ
were looking for λ
d is the distance between the slits = 1/500 mm = .002 mm = 2000 nm
θ is diffraction angle = 45
λ is the wavelength of the light (what were looking for)
n is the order of diffraction = "first-order bright band" = 1
λ = wavelength
θ = 45°
Plug in
2000sin(45°) = (1)λ
=> λ = 1414.21 nm
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What is the answer for the first part of a? In kN
We are asked to determine the magnitude of the force that acts parallel to the nail. To do that we will add the torque that acts on the point of contact. First, we draw a free-body diagram of the situation:
We have decomposed the force of the nail into its horizontal and vertical components. The horizontal component does no torque since there is no distance parallel to the force to the point of contact.
Now, we add the torques. We consider counterclockwise as positive:
\(\Sigma T=-(30cm)F+(5cm)(R_y)\)Since we consider the moment before there is no angular acceleration the sum of torques adds up to zero:
\(-(30cm)F+(5cm)(R_y)=0\)Now, we determine the value of Ry as a function of "R" using the trigonometric function cosine:
\(\cos \theta=\frac{R_y}{R}\)Now, we multiply both sides by "R":
\(R\cos \theta=R_y\)Now, we substitute in the sum of torques:
\(-(30cm)F+(5cm)(R\cos \theta_{})=0\)Now, we solve for "R". First, we add "30F" to both sides:
\((5cm)(R\cos \theta)=(30cm)F\)Now, we divide both sides by 5cm:
\((R\cos \theta)=\frac{(30cm)F}{5cm}\)Now, we divide both sides by cosine:
\(R=\frac{(30cm)F}{5cm\cos \theta}\)Now, we substitute the values:
\(R=\frac{(30cm)(155N)}{(5cm)\cos 26.9}\)Solving the operations:
\(R=1042.8N\)Therefore, the force on the nail is 1042.8 Newtons.
What is the mass of an object that is accelerating at a rate of 25 m/s² and is using 15 N of force?
Saint Petersburg, Russia and Alexandria, Egypt lie approximately on the same meridian. Saint Petersburg has a latitude of 60° N and Alexandria 32° N. Find the distance (in whole miles) between these two cities if the radius of the earth is about 3960 miles.
The distance between Saint Petersburg, Russia, and Alexandria, Egypt, along the same meridian is approximately 9686 miles.
To find the distance between Saint Petersburg, Russia (latitude 60° N) and Alexandria, Egypt (latitude 32° N) along the same meridian, we can use the concept of the great circle distance.
The great circle distance is the shortest path between two points on the surface of a sphere, and it follows a circle that shares the same center as the sphere. In this case, the sphere represents the Earth, and the two cities lie along the same meridian, which means they have the same longitude.
To calculate the great circle distance, we can use the formula:
Distance = Radius of the Earth × Arc Length
Arc Length = Latitude Difference × (2π × Radius of the Earth) / 360
Given that the radius of the Earth is approximately 3960 miles and the latitude difference is 60° - 32° = 28°, we can substitute these values into the formula:
Arc Length = 28° × (2π × 3960 miles) / 360 = 3080π miles
To obtain the distance in whole miles, we can multiply 3080π by the numerical value of π, which is approximately 3.14159:
Distance = 3080π × 3.14159 ≈ 9685.877 miles
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What is a scientific law?
Answer:
In general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory. It is a misconception that theories turn into laws with enough research.
Explanation:
hope you get it right
:)
Answer: Found this in google. Statement based on repeated experiments or observations, that describe or predict a range of natural phenomena. Hope this helps!
Explanation:
A high diver wants to make sure that she does not move any faster than 32 m/s when she enters the water from a dive. If she leaves the diving board from rest, what is the maximum height the diving board can be above the water (in meters) so that she does not go any faster than 32 m/s
The maximum height the diving board can be above the water is 52.5m, so that she does not go any faster than 32 m/s when she enters the water.
How do you determine the maximum height ?To determine the maximum height the diving board can be above the water, we can use the equation of motion for a freely falling object:
v^2 = u^2 + 2as
where
v = final velocity (32 m/s)
u = initial velocity (0 m/s)
a = acceleration due to gravity (-9.8 m/s^2)
s = distance fallen (height of diving board above water)
We can rearrange the equation to find the distance fallen (s)
s = v^2/(-2a) - u^2/2a
substituting the values
s = 32^2/(-2*(-9.8)) = 32^2/19.6 = (1024/19.6) = 52.5 m
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I NEED THIS ANSWERED ASAP NO LINKS !!!
I need a answer that is 100% ACCURATE
Answer:
1. Not a noun phrase
2. Noun phrase
3. Noun prase
4. Not a noun phrase
Explanation:
A crate is pulled with a force of 165 N at an angle 30 ° northwest. What is the resultant horizontal force on the crate?
Answer:
Resultant horizontal force = 143 N
Explanation:
Since the a gle is 30° northwest, then it means the resultant force will be horizontal and as such;
Resultant horizontal force = 165 * cos 30
Resultant horizontal force = 142.89
Approximating to a whole number gives;
Resultant horizontal force = 143 N
A student builds an electromagnet as shown. Will the compass needle move when brought near the electromagnet and why
Answer:
See below
Explanation:
You didn't show the e-magnet construction diagram....but:
If the e-magnet is built properly and has current flowing through the coils, it will affect the compass.....also note that a compass is a magnet, so if the e-magnet is ferrous (iron-containng) material it will affect the compass ....current flowing or not !
A massive light hangs over the table in Jeremy's dining room. The light is supported by four strong chains which make an angle of 72° with the horizontal. The force in each chain is 36.4 N. Determine the mass of the light in kilograms (kg). Use the approximation g ≈ 10 m/s^2.
Given
A massive light hangs over the table in Jeremy's dining room. The light is supported by four strong chains which make an angle of 72° with the horizontal.
The force in each chain is F=36.4 N.
To find
The mass of the light in kg
Explanation
Let the mass of the light be m
The weight of the light acts downwards.
To balance thisi force the force on the string vertically upward is considered
In equillibrium
\(\begin{gathered} mg=4Fsin72^o \\ \Rightarrow10m=4\times36.4\times sin72^o \\ \Rightarrow m=13.84\text{ kg} \end{gathered}\)Conclusion
The mass of the light is 13.84 kg
If a 15 kg object has a 22 n friction force acting on it. What is the friction coefficient?.
The coefficient of friction is the ratio of frictional force to the normal force. The normal force acting on 15 Kg object is 147 N and the coefficient of friction is 0.149.
What is friction?Friction is a kind of resistive force acting on a body that resist it from motion. Thus, frictional force will be always opposite to the applied force for the displacement of an object.
The normal force acting on a body of mass m is mg. Where, g is the acceleration due to gravity. Normal force acting on 15 kg object is :
N = mg
= 15 × 9.8 m/s²
= 147 N.
The coefficient of friction = Normal force / frictional force
= 22 N/147 N
= 0.149
Therefore, the coefficient of friction for an object with 15 kg and 22 N frictional force is 0.149.
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Which of the following statements from Dalton's atomic theory is no longer true, according to modern atomic theory?
the statement from Dalton's atomic theory that is no longer true is "Atoms are indivisible and cannot be divided into smaller particles."
Dalton's atomic theory, proposed in the early 19th century, stated that atoms were indivisible and indestructible particles, meaning they could not be further divided into smaller particles. However, with advancements in scientific understanding and the development of subatomic particle physics, it has been discovered that atoms are not indivisible. Atoms are composed of subatomic particles, namely protons, neutrons, and electrons. Protons and neutrons reside in the nucleus at the center of the atom, while electrons orbit around the nucleus. Furthermore, scientists have identified even smaller particles within the nucleus, such as quarks and gluons. Hence, the concept of atoms being indivisible, as proposed in Dalton's atomic theory, is no longer valid based on modern atomic theory.
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Which of the following statements from Dalton's atomic theory is no longer true, according to modern atomic theory?
A) All atoms of a given element are identical.
B) Atoms are not created or destroyed in chemical reactions.
C) Elements are made up of tiny particles called atoms.
D) Atoms are indivisible and cannot be divided into smaller particles.
If two bowling balls are resting on a horizontal surface about one meter apart, what can be done to decrease the gravitational attraction between the two bowling balls
However, by implementing these measures, you can decrease the gravitational attraction between the two bowling balls to some extent. To decrease the gravitational attraction between the two bowling balls, you can do the following:
1. Increase the distance between the bowling balls: Gravitational attraction decreases with increasing distance. By moving the bowling balls farther apart, you can decrease the gravitational force between them.
2. Decrease the mass of the bowling balls: Gravitational attraction is directly proportional to the masses of the objects involved. If you can reduce the mass of the bowling balls, the gravitational force between them will also decrease.
3. Place a barrier or object between the bowling balls: Introducing another object between the bowling balls can disrupt the gravitational field between them and reduce the attraction. This can be done by placing a physical barrier or object that acts as a shield between the balls.
It's important to note that the gravitational force is a fundamental force of nature, and it cannot be eliminated entirely However, by implementing these measures, you can decrease the gravitational attraction between the two bowling balls to some extent.
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