true/false. flaws in the research design are a more serious limitation to the credibility of results than are gaps in the literature review.

By substituting the given time values into the equation il = 150 mA(1 - e⁻(t/15 ms)) and solving for il, the current at those time points and the corresponding time when il reaches specific values can be calculated.

The given equation describes the current (il) as a function of time (t) using the formula il = 150 mA(1 -e⁻(t/15 ms)).

a) To find il at t = 1.5 ms, substitute t = 1.5 ms into the equation and calculate il.

b) To find il at t = 150 ms, substitute t = 150 ms into the equation and calculate il.

c) To find the time t when il equals 75 mA, set il = 75 mA in the equation and solve for t.

d) To find the time t when il equals 149 mA, set il = 149 mA in the equation and solve for t.

These calculations will provide the specific values of il at different time points and determine the corresponding time when il reaches a specific current value.

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Answer:

whatsthe question choices

Answer:

Explanation:

The only vertical force that can be applied at joint D is that of link CD. Since joint D is stationary, there must be no vertical force. Hence the force in link CD must be zero, as must the force in link DE.

At joint E, the only horizontal force is that applied by link EF, so it, too, must be zero.

Then link CE has 15 N tension.

The downward force in CE must be balanced by an upward force in CF. Of that force, only 1/√2 of it will be vertical, so the force in CF is a compression of 15√2 N.

In order for the horizontal forces at C to be balanced the 15 N horizontal compression in CF must be balanced by a 15 N tension in BC.

At joint F, the 15 N horizontal compression in CF must be balanced by a 15 N compression in FA. CF contributes a downward force of 15 N at joint F. Together with the external load of 10 N, the total downward force at F is 25 N. Then the tension in BF must be 25 N to balance that.

At joint B, the 25 N downward vertical force in BF must be balanced by the vertical component of the compressive force in AB. That component is 2/√5 of the total force in AB, which must be a compression of 25√5/2 N.

The horizontal forces at joint B include the 15 N tension in BC and the 25/2 N compression in AB. These are balanced by a (25/2+15) N = 55/2 N tension in BG.

In summary, the link forces are ...

_____

Note that the forces at the pins of G and A are in accordance with those that give a net torque about those point of 0, serving as a check on the above calculations.

For a dislocation density of 10^4 mm^-2, the chain would extend 1.24 miles. For a density of 10^10 mm^-2, the chain would extend 124,274 miles.

1. Calculate total dislocations: Dislocation density x Volume = 10^4 mm^-2 x 1000 mm^3 = 10^7 dislocations
2. Estimate the length of one dislocation: Consider 1 mm as an average dislocation length
3. Calculate total length of dislocations: 10^7 dislocations x 1 mm/dislocation = 10^7 mm
4. Convert length to miles: 10^7 mm x (1 m/1000 mm) x (1 km/1000 m) x (1 mile/1.609 km) ≈ 1.24 miles
5. Repeat steps 1-4 for a density of 10^10 mm^-2: 10^10 mm^-2 x 1000 mm^3 = 10^13 dislocations, total length ≈ 124,274 miles.

Therefore the chain would extend 1.24 miles.

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Answer:

Cave-ins

Explanation:

The term excavation means any form of cuts, depression or trench by removing the surface of the earth. This process is intended primarily for the purpose of construction and maintenance or exploration. In this process there are many hurdles that pose danger to both human life and earth. The excavation workers face the great threat because of cave-ins. The collapsing of the earth's surface and random accidents prove to be very dangerous for the workers.

Answer:

10

Explanation:

Answer:

Alvaro designs machinery and equipment for ships. His job title is best described as Marine Engineer.

Jeanette draws maps and plans for freeway projects. Her job title is best described as Civil Drafter.

Joseph designs a new airport. His job title is best described as Transportation Engineer.

Geraldine designs imaging systems that use light. Her job title is best described as Photonics Engineer.

Hope this helps sorry I am late to respond, but anyone else who needs the answer it is here.

Based on the above, Alvaro is a Marine Engineer;

Machinery and Equipment are known to be a type of industrial tools, devices, and items that aids facilities.

Conclusively, They are said to be tangible personal property that are used as a tool for repair parts, etc. Professions in ship jobs includes, Marine Engineer, Photonics Engineer, etc.

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The probability that the patient's specimen will be flagged as "unusually high" if the reported value is the mean of three independent assays is approximately 0.0668 or 6.68%.

To discover the likelihood that a patient's specimen will be flagged as "unusually high" given the detailed value as the mean of three free tests, we got to calculate the likelihood of getting a mean ALT concentration of 40 or more.

The cruel of three free measures takes after a ordinary dispersion with the same cruel as the person tests but a diminished standard deviation. Since the standard deviation of each person test is 4 U/l, the standard deviation of the cruel of three measures can be calculated as takes after:

Standard deviation of the cruel = Standard deviation of person measures / sqrt(Number of measures)

= 4 U/l / sqrt(3)

Presently, we will calculate the z-score for the detailed esteem of 40 U/l utilizing the patient's genuine ALT concentration of 35 U/l and the standard deviation of the cruel of three measures:

z-score = (detailed esteem - genuine esteem) / standard deviation of the cruel

= (40 - 35) / (4 / sqrt(3))

Calculating the z-score:

z-score = 5 / (4 / sqrt(3))

= 5 * sqrt(3) / 4

Following, we have to be find the likelihood of getting a z-score greater than or rise to to the calculated z-score. This could be done by looking up the comparing aggregate likelihood within the standard typical dissemination table or by employing a calculator or computer program.

Let's accept we utilize a standard typical conveyance table. Looking up the esteem of z-score = 5 * sqrt(3) / 4 within the table, we discover that it is around 0.9332.

Be that as it may, we require the likelihood of getting a z-score more noteworthy than or break even with to the calculated z-score, so we subtract this esteem from 1:

Likelihood = 1 - 0.9332

= 0.0668

Hence, the likelihood that the patient's example will be hailed as "curiously tall" in the event that the detailed esteem is the cruel of three free tests is around 0.0668 or 6.68%.

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Answer:

Explanation:

a. calculations / markings. An essential component of the electrical profession is the manufacture of conduits. When done well, it can resemble a piece of art.

When carried out improperly, it may be against construction codes, result in equipment failures, and endanger the integrity of the entire electrical system. A conduit installed incorrectly may potentially prevent the passage of wire, rendering the entire system unusable.

All sizes and varieties of electrical conduits must be installed correctly and effectively, and this expectation extends to our apprentices and journeymen. Conduits can be bent using a wide variety of methods and equipment.

Both in the classroom and on the job, our apprentices receive training. We invest a lot of time learning and perfecting the skill of conduit manufacture and installation in order to prepare our apprentices.

To ensure that our employees are the best in the business, we have spent tens of thousands of dollars on the newest tools and equipment.

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all conduit fabrication jobs begin with accurate measurements, ? , and ? . select one: a. calculations / markings b. calculations / proper bending tools c. investigation / material estimate d. markings / proper bending tools. explain.

The exercise of using a black box (obs-certain) with a marble inside to understand its construction typically requires the following:

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As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.

Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.

It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.

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Answer:

Yes, the forging can be completed

Explanation:

Given h = 100 mm, ε = ㏑(450/100) = 1.504

\(Y_f = 230 \times 1.504^{0.15} = 244.52\)

V = π·D²·L/4 = π × 50²×450/4 = 883,572.93 mm³

At h = 100 mm, A = V/h = 883,572.93 /100 = 8835.73 mm²

D = √(4·A/π) = 106.07 mm

\(K_f\) = 1 + 0.4 × 0.1 × 106.07/100 = 1.042

F = 1.042 × 244.52 × 8835.73 = 2252199.386 N =2.25 MN

Hence the required force = 2.25 MN is less than the available force = 3 MN therefore, the forging can be completed.

Answer:

A=16+j12…'B=6+j10.4

Explanation:

add the following vector given in

The flashing arrow panels are not used just at night but are used even during the day time. These are necessary to give the directional information to the drivers. Thus, the given statement is false.

The safety instructions are necessary for the drivers as absence of these would lead to increased number of accidents which could lead to death of a number of people. The flashing arrow panels is one of these instructions.

Flashing arrow panels are used during the day as well as at the night to give advance warning and directional information to the drivers where it is required to move to the right or to the left into another lane.

Some of the safety systems used at level crossings include amber and red warning lights on majority of roads, people should stop when the amber lights come on, unless vehicle has already crossed the stop line.

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This graph traversal, depth first, visits a vertex, then a neighbor of the vertex, a neighbor of the neighbor, and so on, and advancing as far as possible from the original vertex. The correct option is:
d. depth first

This is because the Depth First Traversal explores as far as possible along a branch before backtracking to explore other branches. Depth-first traversal is a technique used to traverse or explore a tree or graph data structure in a depthward motion, visiting nodes or vertices as deep as possible before backtracking. It starts at a designated node and explores as far as possible along each branch before backtracking.

The basic idea behind depth-first traversal is to visit a node and then recursively explore all the adjacent nodes or children of that node until there are no more unvisited nodes. Once all the adjacent nodes have been visited, it backtracks to the previous node and continues exploring any unvisited adjacent nodes from there. This process continues until all nodes in the tree or graph have been visited.

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The mean kinetic energy of the N₂ molecules at 25 °C is 3593.519 joules per mole.

Let suppose that the gas sample behaves ideally. The Graham's law establishes a connection between the ideal gas model and the kinetic theory of gases.

In this question we need to use this law to estimate the average kinetic energy (Kₐ), in joules per mole, of a diatomic gas (N₂), which is defined by the following expression:

\(K_{a} = \frac{3}{2}\cdot R_{u}\cdot T\)   (1)

Where:

If we know that \(R_{u} = 8.314\,\frac{J}{mol\cdot K}\) and \(T = 288.15\,K\), then the average kinetic energy is:

\(K_{a} = \frac{3}{2}\cdot \left(8.314\,\frac{J}{mol\cdot K} \right) \cdot (288.15\,K)\)

\(K_{a} = 3593.519\,\frac{J}{mol}\)

The mean kinetic energy of the N₂ molecules at 25 °C is 3593.519 joules per mole. \(\blacksquare\)

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Answer:

the amount of bleed steam required to heat 1 kg of feedwater in this unit is 0.078 kg/s

Explanation:

Given that:

Pressure of the feed water = 7000 kPa

Temperature of the closed feedwater heater = 260 ° C

Pressure of of the turbine = 6000 kPa

Temperature of the turbine = 325 ° C

The  objective is to calculate the amount of bleed steam required to heat 1 kg of feedwater in this unit.

From the table A-4 of saturated water temperature table at temperature  260° C at state 1 ;

Enthalpies:

\(h_1 = h_f = 1134.8 \ kJ/kg\)

From table A-6 superheated water at state 3 ; the value of the enthalpy relating to the pressure of the turbine at 6000 kPa and temperature of 325° C  is obtained by the interpolating the temperature between 300 ° C and 350 ° C

At 300° C; enthalpy = 2885.6 kJ/kg

At 325° C. enthalpy = 3043.9 kJ/kg

Thus;

\(\dfrac{325-300}{350-300}=\dfrac{h_{325^0}-{h_{300^0}}}{{h_{350^0}}- {h_{300^0}}}\)

\(\dfrac{325-300}{350-300}=\dfrac{h_{325^0}-2885.6}{3043.9-2885.6 }}\)

\(\dfrac{25}{50}=\dfrac{h_{325^0}-2885.6}{3043.9-2885.6 }}\)

\(h_{325^0} = 2885.6 + \dfrac{25}{50}({3043.9-2885.6 )\)

\(h_{325^0} = 2885.6 + 0.5({3043.9-2885.6 )\)

\(h_{325^0} =2964.75 \ kJ/kg\)

At pressure  of 7000 kPa at state 6; we obtain the enthalpies corresponding to the pressure at table A-5 of the saturated water pressure tables.

\(h_6 = h_f = 1267.5 \ kJ/kg\)

From state 4 ;we obtain the specific volume corresponding to the pressure of 6000 kPa at table A-5 of the saturated water pressure tables.

\(v_4 = v_f = 0.001319\ m^3 /kg\)

However; the specific work pump can be determined by using the formula;

\(W_p = v_4 (P_5-P_4)\)

where;

\(P_4\) = pressure at state 4

\(P_5\) = pressure at state 5

\(W_p = 0.001319 (7000-6000)\)

\(W_p = 0.001319 (1000)\)

\(W_p =1.319 \ kJ/kg\)

Using the energy balance equation of the closed feedwater heater to calculate the amount of bleed steam required to heat 1 kg of feed water ; we have:

\(E_{in} = E_{out} \\ \\ m_1h_1 +m_3h_3 + m_3W_p = (m_1+m_3)h_6\)

where;

\(m_1 = 1 \ kg\)

Replacing our other value as derived above into the energy balance equation ; we have:

\(1 \times 1134.8 +m_3 \times 2964.75 + m_3 \times 1.319 = (1+m_3)\times 1267.5\)

\(1134.8 + 2966.069 \ m_3 = 1267.5 + 1267.5m_3\)

Collect like terms

\(2966.069 \ m_3- 1267.5m_3 = 1267.5-1134.8\)

\(1698.569 \ m_3 =132.7\)

\(\ m_3 = \dfrac{132.7}{1698.569}\)

\(\mathbf{ m_3 = 0.078 \ kg/s}\)

Hence; the amount of bleed steam required to heat 1 kg of feedwater in this unit is 0.078 kg/s

Answer:

30 lbs

Explanation:

Answer:

The answer above is correct.  30lbs

Explanation:

Answer:

True.

Explanation:

The process of dismantling and inspecting a competitor's product to understand its design and functionality, and to discover opportunities for improvement or innovation is called "reverse engineering." It is a common practice in many industries, such as electronics, software, and automotive, to gain a competitive advantage or to understand the market.

Answer:

B: Team has the ball near center line

Explanation:

i guessed so...

A stepped uniaxial bar is subjected to forces. The length and area of cross-sections of the two elements are asked to be written. The stiffness matrix of the given information is to be calculated.

Consider a stepped uniaxial bar subjected to forces as shown in the below diagram. The above bar has two different areas of cross-section and lengths. Hence, the bar can be divided into two elements with different areas and lengths.

Let us consider Element 1:

Here, \(l_1\) = Length of element 1

\(A_1\) = Area of cross-section of element 1

Let \(P_1\) and \(P_2\) be the forces applied on Element 1 and Element 2 respectively.

In general, the element stiffness matrix can be written as \(k = AE / Le\), where A is the area of the cross-section, E is the modulus of elasticity, and Le is the length of the element.

Let us calculate the stiffness matrix for Element 1. The stiffness matrix of Element 1, \(k_1\) is given by: 

\(k_1 = (A_1E_1 / l_1) * [1, -1; -1, 1]\)

Let us consider Element 2:

Here, \(l_2\) = Length of element 2

\(A_2\) = Area of cross-section of element 2

The stiffness matrix of Element 2, \(k_2\) is given by:

\(k_2 = (A_2E_2 / l_2) * [1, -1; -1, 1]\)

Now, we need to find the stiffness matrix of the complete bar. Let us consider k as the stiffness matrix of the complete bar. Then, \(k = [k_1 + k_2]\) is the stiffness matrix of the complete bar.

The complete stiffness matrix of the given problem is given by: \(k = [A_1E_1/l_1 + A_2E_2/l_2] * [1, -1; -1, 1]\)

Hence, the stiffness matrix of the given problem is given by \([A_1E_1/l_1 + A_2E_2/l_2] * [1, -1; -1, 1].\)

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The term that matches the definition is "high-level programming language."

In a high-level programming language, the instructions and syntax are designed to be close to everyday English, making it easier for programmers to read, write, and understand the code. High-level programming languages abstract away many low-level details and complexities of computer hardware, providing a more intuitive and human-friendly approach to programming.

These languages utilize a vocabulary and syntax that resemble natural language, with keywords and constructs that align with common concepts and actions.

For example, high-level languages may use keywords such as "if," "while," and "for" to represent conditional statements, loops, and iteration. Variables and functions are often named using descriptive words or phrases, allowing for more expressive and self-explanatory code.

By using a high-level programming language, developers can focus on the logical aspects of their programs rather than getting lost in intricate machine-level details. This abstraction enables faster development, better code readability, and increased productivity.

Examples of high-level programming languages include Python, Java, C++, and JavaScript. These languages provide extensive libraries, frameworks, and tools that simplify complex tasks and provide a wide range of functionalities. The use of natural language-like syntax in these languages enhances the programmer's ability to communicate intentions and ideas effectively.

In contrast, low-level programming languages, such as assembly or machine code, use instructions that directly correspond to the underlying hardware architecture, offering more control but requiring a deep understanding of computer internals. High-level languages bridge this gap and make programming more accessible and user-friendly for developers.

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When the SR flip-flop circuit transitions from SR=00 to SR=11 with an initial state Q=1, it can result in a critical race due to the uncertain behavior of the outputs.

The SR flip-flop (Set-Reset) is a basic sequential circuit with two inputs (S and R) and two outputs (Q and Q'). Using a Karnaugh map (K-map) for analysis, we can determine the behavior of the circuit under different input conditions. A critical race occurs when two or more input changes lead to an unpredictable output state.

For SR=00 (no change), Q maintains its initial state, Q=1. When transitioning to SR=11 (invalid input), both S and R are activated simultaneously, which creates an ambiguous state, leading to a possible critical race.

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Point E has a total internal loading of -3 kN. At point F, there is a +3 kN internal loading overall.

In mathematics and physics, a cross-sectional area is the non-empty intersection of a solid body in three dimensions with a plane, or its equivalent in higher dimensions. An item can be divided into several parallel cross-sections when it is chopped into pieces. The boundary of a three-dimensional cross-section that is parallel to the plane created by these axes and equal to two of the directions is also referred to as a contour line. Point E has a total internal loading of -3 kN. At point F, there is a +3 kN internal loading overall. The internal loadings acting on the cross section at E are mathematically given as, according to what we have. M e=-2400lbft. Typically, the mathematical equation for the equilibrium moment about b is written as

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