True or False
ATP energy is used to move muscles and build protein in your body

Answers

Answer 1
True. ATP is released when using your muscles, and it helps break down food giving you protein

Related Questions

A group of a similar search that proform a particular function is called

Answers

Answer:

Explanation: Tissue if I'm not mistaken

A group of a similar cells that perform a particular function is called a tissue.

What is a Tissue?

This is the aggregation of cells which have the same type of structure and therefore performs the same type of function through what is referred to as cell specialization.

The organ is also formed from the aggregation of tissues and is necessary so as to ensure that biochemical activities in the body are performed optimally.

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Question 4 (1 point)

If the decomposition of (NH4)2(CO3) is a first-order process with a rate constant of
0.196 s-1, how much ammonium carbonate would remain after 39.0 s, starting from
a concentration of 0.957 M?

Your Answer in units:

Answers

The final concentration of the reactant of a first order reaction can be determined from the rate constant equation. The concentration of ammonium carbonate after 39 s will be 0.003 M.

What is rate constant?

Rate constant of a reaction is the rate of reaction when one molar concentration of the reactant is involved in the reaction. The expression for the rate constant k for first order reaction is :

k = 1/t ln (C0/Ct)

Where C0 be the initial concentration and Ct be the concentration after t seconds.

Given that C0 of ammonium nitrate = 0.957 M

rate constant = 0.196 /s

t = 39 s.

The concentration after 39 seconds is calculated as follows:

0.196 /s = 1/39s ln (0.957 M / Ct)

Ct = 0.957 / (ln⁻¹ (0.196 × 39))

    = 0.003 M.

Therefore, the concentration of ammonium carbonate after 39 seconds will be 0.003 M.

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True or False: Air can be made to vibrate.

Answers

Answer

False

Explanation:

Which of the following processes is used to test for drunk driving and also to break down alcohol in the body?
a. transesterification
b. E1 elimination
c. alcohol oxidation
d. ketone reduction

Answers

Answer:

c. alcohol oxidation

Explanation:

The police often use a device called a breathalyzer to test drivers suspected of being drunk. The chemical basis of this device is a redox reaction. A sample of the driver’s breath is drawn into the breathalyzer, where it is treated with an acidic solution of potassium dichromate. The alcohol (ethanol) in the breath is  converted to acetic acid as shown in the following equation:

3 CH₃CH₂OH + 2 K₂Cr₂O₇ + 8H₂SO₄   → 3 CH₃COOH + 2 Cr₂(SO₄)₃ + 2 K₂SO₄ +1 11H₂O

ethanol + potassium dichromate (orange yellow)  + sulfuric acid → acetic acid +  chromium(III) sulfate (green) + potassium sulfate + water

In this reaction, the ethanol is oxidized to acetic acid and the chromium(VI) in the orange-yellow dichromate ion is reduced to the green chromium(III) ion. The driver's blood alcohol level can be determined readily by measuring the degree of this color change (read from a calibrated meter on the instrument).

Which of the following processes is used to test for drunk driving and also to break down alcohol in

A particular reaction has an enthalpy and entropy of reaction of ∆H = +33 kJ/mol and ∆S = +0.15 kJ/mol⋅K. At the three indicated temperatures, determine if either reactants or products are favored?

Answers

Answer:

Explanation:  check my paage

A car is traveling 1289 miles north and the time of travel is 2.34 hours. Calculate the velocity of the car.

Answers

Answer:

529.59

Explanation:

Velocity= Distance over time

1289 miles /2.34 hours=

529.59

or 529.487179487

What is the equilibrium constant for the reaction
SO2(g) + NO2(9) = SO3(g) + NO(g)?

А. Keq: [S03)(S02]
[NO][NO2]

B. Keq: [SO2)(NO2]
[SO3)(NO]

C. Keq: [SO3)3(NO]
[SO2)2(NO2)2

D. Keq: [SO3)(NO]
[SO2]NO2]

Answers

Answer:

D. Keq: [SO3][NO] /[SO2]NO2]

Explanation:

Hello!

In this case, according to the process to set up equilibrium expressions for chemical reactions at equilibrium, we realize we need to write up the concentration of products on top and that of reactants on bottom; thus, for there chemical reaction herein specified, we obtain:

\(Keq=\frac{[SO_3][NO]}{[SO_2][NO_2]}\)

Thereby, the answer is D. Keq: [SO3][NO] /[SO2]NO2].

Best regards!

Answer:

D

Explanation:

The half-life of Po-210 is 140 days. If the initial mass of the sample is 5 kg, how much will remain after 280 days.

Answers

The half-life of Po-210 is 140 days. If the initial mass of the sample is 5 kg, 3.5g will remain after 280 days.

What is chemical kinetics?

Chemical kinetics is a subfield of physical chemistry that studies the speeds of chemical processes. The rate of the reaction may be used to classify it as quick, moderate, or sluggish. Reaction mechanism also enables us to study the effects of temperature and catalyst on reaction rate and rate constant. It informs us about reaction processes and enables us to apply particular rate constants to certain mechanistic stages.

The rate law for first order kinetics is

K=(2.303/T)×log(a/a-x)

half life=0.693/K

Where

k - rate constant

t - time passed by the sample

a - initial amount of the reactant

a-x - amount left after the decay process

K=0.693/half life

K=0.693/140

=0.086

0.086=(2.303/ 280)×log( 5 /a-x)

0.086=0.07×log( 136/a-x)

1.22=log( 136/a-x)

136/a-x=16.5

a-x=3.5g

Therefore, 3.5g will be left after 280 days.

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A galvanic cell is powered by the following redox reaction:
2Zn2+(aq) + N2H4(aq) 4OH-zn2+ right arrow(aq) 2Zn(s) + N2(g) + 4H2O(I)
1. Write a balanced equation for the half-reaction that takes place at the cathode.
2. Write a balanced equation for the half-reaction that takes place at the anode.
3. Calculate the cell voltage under standard conditions.

Answers

if you could apply a picture with the question that would help.

8.5ml of a sample of sea water solution was added to a 44.317g evaporating dish the combination weighted 52.987g after evaporating the dish and content weighed 44.599g

Answers

Answer:  There is no question, but we can calculate a couple of items:

Density of sea water sample = (52.987g-44.317g)/8.5ml

Inorganic content of sample (mostly salts) = (44.599g-44.317g)/(52.987g-44.317g) x 100% = percent inorganics in water sample

Explanation:

How did the experiment with the iron fillings and sulfur compare with experiment in which copper sulfate pentahydrate was heated?

Answers

Answer:

Both resulted in gas formation. Both resulted in color change.

Explanation:

Follow me!

Answer:

statement second and third are both corect

Explanation:

When iron(grey) reacts with sulfur(yellow) chemical change takes place in which iron sulfide is formed which black in color.

Fe(s) + S(s)\rightarrow FeS(s)Fe(s)+S(s)→ FeS(s)

When we heat copper sulfate-pentahydrate(blue) ,water molecule present in its crystal will get evaporated and it will become an anhydrous copper sulfate which will be white in color.

CuSO_{4}.5H_{2}O(s)\overset{heat}{\rightarrow} CuSO_{4}(s)+5H_2O(g)CuSO

4

.5H

2

O(s)

heat

CuSO

4

(s)+5H

2

O(g)

So, in both the reactions chang

request:

set as brainiest

please help me i need this asp

please help me i need this asp

Answers

It’s an “ionic bond” with the formula name “NaCl”

The concentration of H3AsO3 in a solution is determined by titrating it with a 0.1741 M Ce4+ solution. The balanced net ionic equation for the reaction is: 2Ce4+(aq) + H3AsO3(aq) + 5H2O(l) 2Ce3+(aq) + H3AsO4(aq) + 2H3O+(aq) In one experiment, 18.68 mL of the 0.1741-M Ce4+ solution is required to react completely with 30.00 mL of the H3AsO3 solution.
Calculate the concentration of the H3AsO3 solution.

Answers

Answer:

0.0542 M

Explanation:

Let;

CA = concentration of Ce4+ solution = 0.1741 M

VA = volume of Ce4+ solution = 18.68 mL

CB = concentration of H3AsO3 = ?

VB  = volume of H3AsO3 = 30.00 mL

NA = Number of moles of Ce4+ solution = 2

NB = Number of moles of H3AsO3  = 1

From;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB = CAVANB/VBNA

CB = 0.1741 * 18.68 * 1/30.00 * 2

CB = 0.0542 M

A 20.0-L nickel container was charged with 0.833 atm of xenon gas and 1.28 atm of fluorine gas at 400°C. The xenon and fluorine react to form xenon tetrafluoride. What mass (g) of xenon tetrafluoride can be produced assuming 100% yield?

Answers

Answer:

A 20.0 L

20.0

L

nickel container was charged with 0.500 atm

0.500

a

t

m

of xenon gas and 1.50 atm

1.50

a

t

m

of fluorine gas at 400 ∘C

400

C

. The xenon and fluorine react to form xenon tetrafluoride. What mass of xenon tetrafluoride can be produced assuming 100%

100

%

yield?

Explanation:

Match the density to the object

- The object at the bottom of the yellow layer
- The object at the bottom of the blue layer
- The nut in the red layer
- The object at the top of the yellow layer

● 6 g/mL
● 1.5 g/mL
● 3 g/mL
● 0.5 g/mL​

Answers

Answer:

The object at the bottom of the yellow layer: 6 g/mL

The object at the bottom of the blue layer: 1.5 g/mL

The nut in the red layer: 3 g/mL

The object at the top of the yellow layer: 0.5 g/mL

What is a hypothesis?

Answers

Answer: a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.

Explanation: definition

i need help with this

i need help with this

Answers

Answer:

hope it helps you.......

i need help with this

A pizza is an example of a heterogeneous mixture. Explain why it is classified as such?​

Answers

Answer:

Hi!

So, a homogeneous mixture is when the parts that make up the mixture are all mixed in perfectly evenly, so they're only appearing as one uniform substance.

In a heterogeneous mixture, the pieces are not evenly mixed. A pizza has separate parts, like the crust and toppings, so it's a heterogeneous mixture.    

Carbon-14 is used in radiocarbon dating.

The half-life of carbon-14 is 5.73E3 years. If a sample of carbon-14 has an activity of 0.350 Ci, what is the difference in activities between this sample and the same sample after 1.719E4 years?

Answers

Answer:

0.30625 Ci

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 5.73E3 years

Original activity (Nₒ) = 0.350 Ci

Time (t) = 1.719E4 years

Difference in activities =?

Next, we shall determine number of half-lives that has elapse. This can be obtained as follow:

Half-life (t½) = 5.73E3 years = 5.73×10³ years

Time (t) = 1.719E4 years = 1.719×10⁴ years

Number of half-lives (n) =?

n = t / t(½)

n = 1.719×10⁴ / 5.73×10³

n = 3

Thus, 3 half-lives has elapsed.

Next, we shall determine the activity after 1.719E4 years. This can be obtained as follow:

Original activity (Nₒ) = 0.350 Ci

Number of half-lives (n) = 3

Activity remaining (N) =?

N = 1/2ⁿ × Nₒ

N = 1/2³ × 0.350

N = 1/8 × 0.350

N = 0.125 × 0.350

N = 0.04375 Ci

Finally, we shall determine the difference in activities. This can be obtained as follow:

Original activity (Nₒ) = 0.350 Ci

Activity remaining (N) = 0.04375 Ci

Difference in activities =?

Difference in activities = Nₒ – N

Difference in activities = 0.350 – 0.04375

Difference in activities = 0.30625 Ci.

what are interstitial compounds?​

Answers

Answer:

1. An interstitial compound or alloy is a compound that is formed when small atoms like hydrogen, boron, carbon or nitrogen are trapped in the interstitial holes in a metal lattice. 2. They are usually non-stoichiometric compounds. 3. Transition metals form a number of interstitial compounds such as TiC, ZrH1.92 , Mn4N etc. 4. The elements that occupy the metal lattice provide them new properties. They are hard and show electrical and thermal conductivity They have high melting points higher than those of pure metals Transition metal hydrides are used as powerful reducing agents Metallic carbides are chemically inert

Interstitial compounds are formed when small atoms such as H, C or N are trapped inside the crystal lattices of metals. They are usually nonstoichiometric and are neither typically ionic nor covalent

production associates are not allowed to view the process safety management documents.They are only for supervisors and upper management?

Answers

The given statement "production associates are not allowed to view the process safety management documents. They are only for supervisors and upper management" is true.

Why are the production associates not allowed?

These documents are typically intended for supervisors and upper management, as they contain information related to the management of hazards and risks associated with specific processes or operations. This is to ensure that the management team has the necessary information to make informed decisions about process safety and to ensure that appropriate safety measures are in place to protect workers and the surrounding community.

Hence, It is important to note that access to PSM documents should be based on an individual's specific job responsibilities and the level of access needed to perform their duties. Some production associates may have access to certain PSM documents if their job responsibilities require it.

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See full question below

production associates are not allowed to view the process safety management documents.They are only for supervisors and upper management? true or false.

12. 5.6g of solid copper was heated with 476.2 J at room temperature (25°C). Given that
copper has a C of 0.38 J/g°C, what would its final temperature be?

Answers

Answer:

The final temperature of the copper would be 311.3°C.

I hope this helps you

A sample of a certain lead compound contains 12.92 g of lead for 2 g of oxygen. A second sample has mass of 34.27 g and contains 14.39 g of oxygen. Are the two compound the same

Answers

The two chemical compounds are not the same, because their ratio is not equal. In both samples the composition of lead and oxygen is different.

What is a chemical compound?

A chemical compound is a substance made of numerous similar molecules (or molecular entities) joined by chemical bonds and comprising atoms from various chemical elements. Therefore, a molecule made up of only one type of atom is not a compound. Chemical reactions, which may entail interactions with other molecules, can change a compound into a distinct substance. Atomic bonds may be broken or new ones created during this process.

What are the calculations?

sample 1 = mass of lead / mass of oxygen = 12.92g/2g = 6.46 .

sample 2 = mass of lead/ mass of oxygen = 34.27 - 14.39/14.39 = 1.38 .

so, the ratios are not the same.

Hence, the two chemical compounds are not the same, because their ratio is not equal. In both samples the composition of lead and oxygen is different.

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If 2.45 g of iron are placed in 1,5 L of 0.25M HCl, how many grams of FeCl2 are obtained? Identify the limiting and excess reactants in this single replacement reaction. Fe + 2HCl = FeCl2 + H2

Answers

Answer:

\(m_{FeCl_2}=0.652gFeCl_2\)

Explanation:

Hello there!

In this case, according to the given information and the chemical reaction, whereby iron and hydrochloric acid react in a 1:2 mole ratio, it is firstly necessary to calculate the moles of iron (II) chloride from each reactant in order to figure out the limiting reactant:

\(n_{FeCl_2}=2.45gFe*\frac{1molFe}{55.845gFe}*\frac{1molFeCl_2}{1molFe}=0.0439molFeCl_2\\\\ n_{FeCl_2}=1.5L*0.25\frac{molHCl}{L} *\frac{1molHCl}{36.46gHCl}*\frac{1molFeCl_2}{2molHCl}=0.00514molFeCl_2\)

In such a way, we infer the maximum moles of FeCl2 product are yielded by HCl, for which it is the limiting reactant. Finally, we calculate the grams of product by using its molar mass as shown below:

\(m_{FeCl_2}=0.00514molFeCl_2*\frac{126.75gFeCl_2}{1molFeCl_2} \\\\m_{FeCl_2}=0.652gFeCl_2\)

Regards!

HELP ASAP PLEASEEEEE!!!!! (serious answers only or i’ll report)




Mg(s)+2HCl(aq)—>MgCl2(aq) + H2(g)

what is the order of the reaction between magnesium and hydrochloric acid, with respect to magnesium?

Answers

Answer:

1st order

Explanation:

because magnesium has a coefficient of 1, it is first order

hydrochloric acid has a coefficient of 2, so it is second order

overall the reaction is third order (1+2)

4. A balloon filled with 2 L of air is at 313 K. Suppose the temperature increases to 600 K. Calculatewhat happens to the volume of the balloon.

Answers

According to Charle's law, a balloon at 600 K has a volume of 3.83 L.

Describe Charles's law.

Charles' law states that, under constant pressure, the volume a given amount of gas fills is directly proportional to its absolute temperature. For instance, when the temperature drops during the winter, a basketball placed outside in the ground would contract.

Mathematically, Charles' law can be written as V1/T1 = V2/T2, where V1 denotes the volume at the beginning, T1 the temperature at that point, and V2 the volume at the end with T2 the temperature at that point.

The following examples of how Charles' law is applied in real life:

Helium balloons shrink when it's cold outside.

From Charles' law, V/T = constant

V₁/T₁ = V₂/T₂

or, 2/313 = V₂/600

or, V₂ = (2x600)/313

          = 3.83

Hence, form Charles' law we conclude the volume of balloon at 600 K is 3.83 L.

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A student measures the mass and volume of a small cube made of an unknown metal. The mass of the cube is 25.0 g, and the volume of the cube is 3.19 cm³. The student is told that the cube is a sample of one of the four materials listed in the table. based on the Data given, the unknown material is most likely A gold Density 19.39, B iron Density 7.85, C silver Density 10.50 D tin density 7.28

Answers

The unknown material with a mass of 25.0g, and the volume is 3.19 cm³ is iron with a density of 7.85g/cm³.

DENSITY:

The density of a substance can be calculated by dividing the mass of the substance by its volume. That is;

Density (g/cm³) = mass (g) ÷ volume (cm³)

According to this question, the mass of the cube is 25.0g, and the volume of the cube is 3.19cm³. The density can be calculated as follows:

Density = 25.0g ÷ 3.19g/cm³

Density = 7.84g/cm³

Therefore, the unknown material with a mass of 25.0g, and the volume is 3.19 cm³ is iron with a density of 7.85g/cm³.

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The density of 70.5 wt% aqueous perchloric acid is 1.67 g/mL. a. How many grams of solution are in 1.000 L? b. How many grams of HClO4 are in 1.000 L? c. How many moles of HClO4 are in 1.000 L?

Answers

There would be 1670 g of solution in 1.000 L and  1,177.35 gram of HClO₄ are in 1.000 L. There are  11.72 moles of HClO₄ in 1 L.

There are 1000 mL in a liter, hence density indicates the amount of grams per mL.

Density =1.67 g / 1 mL   =   1670 g / 1000 mL = 1670 g/ 1.0 L

so there would be 1670 g of solution in 1.000 L

We got aqueous perchloric acid 70.5 wt%, it means the amount of perchloric acid in 100 grams of solution is 70.5 grams. so mass of HClO₄ are in 1.000 L will be

mass of HClO₄  = 70.5% x1670 g/ 1.0 L = 1,177.35 gram

Moles of HClO₄ = mass / mass molar

Moles of HClO₄ = 1,177.35 gram/ 100.46 g/mol = 11.72 moles

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what is the freezing point in C of a 0.325 m aqueous solution of Na2SO3 give your answer to the thousandths place

what is the freezing point in C of a 0.325 m aqueous solution of Na2SO3 give your answer to the thousandths

Answers

Answer:

Explanation:

The freezing point of a 0.325 m aqueous solution of Na₂SO₃ is equal to -1/814 °C

Stephan’s mother cuts a twig from a rose bush and plants it in the soil. After a few days, Stephan observes a new plant growing. Which characteristic does the growth of the new plant depict?

Answers

The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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