True or false:
A small wire can conduct an infinite amount of current.

Answer:

The answer is approximately 350.4J to 1d.p

Explanation:

W=F×S

F=F cosø

W=Fcosø×S

W=71.5cos27×5.5

W=63.7×5.5

W=350.35J

W≈350.4J

It is essential to remember that the materials utilised, the kind of block, and the charge circumstances all affect how well these approaches work. To prevent breaking the blocks or hurting oneself, it's crucial to handle the blocks cautiously.

Rub the L block with a substance that has a strong propensity to give up electrons, such wool or silk, as one way to do this. The L block acquires electrons from the substance when it is rubbed against it, leaving the block with a net positive charge. Similar to this, you may rub the R block with anything that has a strong propensity to draw electrons, such hair or rubber. The R block will then receive electrons from the substance, leaving the block with a net negative charge as a result.

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The scale will read a weight of 463.5 N during the elevator's acceleration.

To calculate the weight that the scale reads during the elevator's acceleration, we need to consider the forces acting on the child.

Weight is a force caused by the gravitational pull of the Earth on an object. It is given by the formula:

Weight = mass × gravitational acceleration

The mass of the child is given as 45.0 kg. The gravitational acceleration is approximately 9.8 m/s² on the surface of the Earth.

However, during the elevator's acceleration, there will be an additional force acting on the child due to the acceleration. This force is given by Newton's second law:

Force = mass × acceleration

In this case, the acceleration is the difference in velocity divided by the time taken, which is (3.0 m/s - 1.0 m/s) / 4.00 s = 0.5 m/s².

So, the additional force acting on the child during the acceleration is:

Additional Force = mass × acceleration = 45.0 kg × 0.5 m/s² = 22.5 N

Now, we can calculate the total force acting on the child, which includes both the weight and the additional force:

Total Force = Weight + Additional Force

Since the weight is equal to mass × gravitational acceleration, we can rewrite the equation as:

Total Force = mass × gravitational acceleration + Additional Force

Total Force = (45.0 kg × 9.8 m/s²) + 22.5 N

Total Force = 441 N + 22.5 N

Total Force = 463.5 N

Therefore, the scale will read a weight of 463.5 N during the elevator's acceleration.

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Two objects are held close together. When they are released, they move toward one another. The conclusion is supported by this evidence is  the objects have opposite charges.

An electric charge is a physical property that causes matter to experience a force when in close proximity to other electrically charged matter. There are two types of electric charges: positive and negative. Protons, which are positively charged, and electrons, which are negatively charged, are subatomic particles that make up matter.

In general, the protons and neutrons in the nucleus of an atom have a net positive charge, while electrons, which orbit the nucleus, have a net negative charge. The charges of these subatomic particles are indicated by the symbols "p" for proton, "n" for neutron, and "e" for electron.

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For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

Answer:10.03

Explanation:acellus

Answer:

A

Explanation:

彼が好きな男のような話は妻と関係があったのでそう

Explanation:これが難しい場合はコメントで教えてくださいが何でも

lol okay

from: a random person :)

Answer: Iron

Explanation: Gradpoint

Answer:

inversely proportional to

Answer:

The 25-year flood occurs on average once every 25 years and has an exceedance probability of 1 over 25, or 4 percent, in any given year

The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

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Answer:

B. Boats need to float.

The maximum velocity is 48π m/s.

The equation: can be used to determine the maximum velocity of a particle in simple harmonic motion.

Vmax = ω * A

Where

The following formula can be used to get the angular frequency:

ω = 2π / T

Where

T is the motion's period.

Given that the period is π/2 seconds (T = π/2) and the amplitude is 12 m (A = 12), we can find the angular frequency:

ω = 2π / (π/2) = 4π rad/s

Now we can calculate the maximum velocity:

Vmax = ω * A = (4π rad/s) * (12 m) = 48π m/s

Therefore, the maximum velocity is 48π m/s.

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Answer:

(D) parasite........................

The mass of the rule is 3.36 kg and the weight of the rule is 33.6 N.

The butt of the blade is designed to balance the majority of fine chef's knives. This is due to the fact that a pinch grip is used in both Western and Eastern cutting styles for improved control. Therefore it makes sense that you'd want your knife to be balanced where you'll be holding it.

To balance the meter rule, Assume the mass of the rule "M".

It is possible to determine the rule's magnitude and weight, which act downward:

weight of rule = M * g

where g = acceleration due to gravity.

weight of rule * (50 cm) = (20 g) * (100 cm - 58 cm)

M * g * (50 cm) = (20 g) * (42 cm)

M = (20 g * 42 cm) / (50 cm * g)

M = 33.6 g / g

M = 33.6 g / 10 m/s^{2}

M = 3.36 kg

(ii) The weight of the rule:

weight of rule = M * g

weight of rule = 3.36 kg * 10 m/s^{2}

weight of rule = 33.6 N

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Answer: B

Explanation: i learned it last year

Pedometer is a small portable device that counts every step taken throughout the day. The correct option is (B).

A pedometer is a small portable device that counts the number of steps taken by an individual throughout the day. It is typically worn on the waist or carried in a pocket and uses a mechanism to detect body motion and count each step.

Pedometers are commonly used for tracking physical activity and encouraging individuals to achieve daily step goals as part of their fitness routines.

Therefore, Pedometer is a small portable device that counts every step taken throughout the day. Choose the option (B).

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.

A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.

If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.

In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.

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Answer:

4.8 watts

Explanation:

power = voltage * current = 12.0 * 0.40 = 4.8 watts

As the spring moves up to be compressed by only 0.30 m, the change in elastic potential energy will be 0.045 k J.

Elastic potential energy is the potential energy stored by stretching or compressing an elastic object by an external force such as the stretching of a spring.

Given,

The spring moves up to be compressed by a displacement = 0.30 m

And the elastic potential energy (U) for a spring can be calculated as:

\(U = \frac{1}{2} k x^{2}\)

Where k = spring constant and is measure in N/m

and x = change in length of the spring or the displacement of the spring

\(U = \frac{1}{2} k (0.30)^{2}\)

\(=\frac{1}{2} k (0.09)\)

\(=0.045 k\) J

Hence, the change in elastic potential energy is 0.045 k J.

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Answer:

Speed of the spacecraft right before the collision: \(\displaystyle \sqrt{\frac{2\, G\cdot M_\text{e}}{R\text{e}}}\).

Assumption: the earth is exactly spherical with a uniform density.

Explanation:

This question could be solved using the conservation of energy.

The mechanical energy of this spacecraft is the sum of:

Let \(m\) denote the mass of this spacecraft. At a distance of \(R\) from the center of the earth (with mass \(M_\text{e}\)), the gravitational potential energy (\(\mathrm{GPE}\)) of this spacecraft would be:

\(\displaystyle \text{GPE} = -\frac{G \cdot M_\text{e}\cdot m}{R}\).

Initially, \(R\) (the denominator of this fraction) is infinitely large. Therefore, the initial value of \(\mathrm{GPE}\) will be infinitely close to zero.

On the other hand, the question states that the initial kinetic energy (\(\rm KE\)) of this spacecraft is also zero. Therefore, the initial mechanical energy of this spacecraft would be zero.

Right before the collision, the spacecraft would be very close to the surface of the earth. The distance \(R\) between the spacecraft and the center of the earth would be approximately equal to \(R_\text{e}\), the radius of the earth.

The \(\mathrm{GPE}\) of the spacecraft at that moment would be:

\(\displaystyle \text{GPE} = -\frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\).

Subtract this value from zero to find the loss in the \(\rm GPE\) of this spacecraft:

\(\begin{aligned}\text{GPE change} &= \text{Initial GPE} - \text{Final GPE} \\ &= 0 - \left(-\frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\right) = \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}} \end{aligned}\)

Assume that gravitational pull is the only force on the spacecraft. The size of the loss in the \(\rm GPE\) of this spacecraft would be equal to the size of the gain in its \(\rm KE\).

Therefore, right before collision, the \(\rm KE\) of this spacecraft would be:

\(\begin{aligned}& \text{Initial KE} + \text{KE change} \\ &= \text{Initial KE} + (-\text{GPE change}) \\ &= 0 + \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}} \\ &= \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\end{aligned}\).

On the other hand, let \(v\) denote the speed of this spacecraft. The following equation that relates \(v\!\) and \(m\) to \(\rm KE\):

\(\displaystyle \text{KE} = \frac{1}{2}\, m \cdot v^2\).

Rearrange this equation to find an equation for \(v\):

\(\displaystyle v = \sqrt{\frac{2\, \text{KE}}{m}}\).

It is already found that right before the collision, \(\displaystyle \text{KE} = \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\). Make use of this equation to find \(v\) at that moment:

\(\begin{aligned}v &= \sqrt{\frac{2\, \text{KE}}{m}} \\ &= \sqrt{\frac{2\, G\cdot M_\text{e} \cdot m}{R_\text{e}\cdot m}} = \sqrt{\frac{2\, G\cdot M_\text{e}}{R_\text{e}}}\end{aligned}\).

Answer:

18 m/s

Explanation:

1.8 meters / 0.1 seconds = 18 m/s

Answer:

Some of them

Explanation:

Some pelagic Birds can stay aloft for days or weeks at a time, and will even sleep in flight. in many Cases, true pelagic birds only return to land to nest and breed

Answer:

the c is in the cycle lab where they were created and then it cycles then it reoves it to the right.

Explanation:

The pressure exerted when a force of 1000 N acts on an area of 0.25 cm² is 40,000,000 Pa or 40,000,000 N/m².

To calculate the pressure exerted, we can use the formula:

Pressure = Force / Area

Given that the force is 1000 N and the area is 0.25 cm², we need to convert the area to square meters to match the unit of force (Newtons per square meter or Pascal).

1 cm² = 0.0001 m² (conversion factor)

0.25 cm² = 0.25 * 0.0001 m² = 0.000025 m²

Now we can calculate the pressure:

Pressure = 1000 N / 0.000025 m²

Pressure = 40,000,000 N/m² or 40,000,000 Pascal (Pa)

Therefore, the pressure exerted when a force of 1000 N acts on an area of 0.25 cm² is 40,000,000 Pa or 40,000,000 N/m².

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Answer:

Explanation:

Whats the entire question?