A crossbow is fired horizontally off a cliff with an initial velocity of 15 m/s. If the arrow takes 4s to hit the ground, what is the range of the projectile?
Answer:
The range of the projectile is 60 m
Explanation:
Horizontal Motion
When an object is thrown horizontally with a speed vo from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:
\(v_x=v_o\)
The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:
\(v_y=g.t\)
The horizontal distance is calculated as a constant speed motion:
\(x = v_x.t\)
Knowing the crossbow is fired horizontally at vo=vx=15 m/s and it takes t=4 s to hit the ground, thus the range of the projectile is:
x = 15*4 = 60
The range of the projectile is 60 m
an ice skater is moving across a flat and level skating rink and is speeding up. which one of the following statement is true of the ice skater
Answer:
where are the statements
Explanation:
Help.. mee..
;-;
Dont answer if you dont know I dont want to fail this
Answer:
It would be B because the warm air heats up and then burns the marshmallow. And the heat and the marshmallow were touching each other
Explanation:
Answer:
its B because both objects are touching, every other option the heat moves through the air
Which type of heat transfer takes place in gases by the movement of particles through a medium?
Answer: Convention
Explanation: Convention is pretty well known for being a process that transmits heat from one place to another place with the movements of heated particles. I got this answer from my notebook during my chemistry class.
Hope this answer helps!
When light travels through a small hole, it appears to be an observer that the light spreads out, blurring the outline of the hole. Does this observation support the theory of light as a wave, or light being made of particles? Explain.
Answer:
support lights as a wave
Explanation:
In the model of light as a particle, the experimenter would expect to see one small hole of light emerging on the wall. However, as the light spreads out, it behaves much like a wave that diffracts when going through a small hole.
In 7.5 s, 4200 waves pass a given point. What is the frequency of the waves?
In 7.5 s, 4200 waves will pass a given point. Then, the frequency of the waves is 560 Hz.
Frequency is the number of cycles or oscillations of a wave that occur in one second, measured in Hertz (Hz). It is the rate at which a wave completes a full cycle, which is usually measured as the number of wavelengths that pass a fixed point in a unit of time.
The formula for frequency is;
frequency = waves/time
Where "waves" is the number of waves that pass a given point and "time" is the time it takes for those waves to pass.
In this case, we know that 4200 waves pass a given point in 7.5 seconds, so we can plug those values into the formula;
frequency = 4200/7.5
Simplifying;
frequency = 560
Therefore, the frequency of the waves is 560 Hz.
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Which is an SI base unit that makes up part of the unit of energy?
candela
ampere
kelvin
kilogram
The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D
What is a unit of measurement?A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.
The base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole
The unit of energy is Joules which is equivalent in mks unit as Kg m²s⁻²
Thus, The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D
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a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.
When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.
This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.
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The known values are given in the table below them. Find the missing values.
The value of the missing resistance, R₃ = 10.35 ohms.
The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.
The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.
What is the value of missing component of the circuit?The values of the missing component of the circuit is calculated by applying the following formula.
The total resistance of the circuit;
For R₂, R₃, 1/R = 1/R₂ + 1/R₃
1/R = 1/12 + 1/R₃
1/R = (R₃ + 1)/(12R₃)
R = 12R₃ / (R₃ + 1)
For, R₁, R₂ and R₃, total resistance;
R = 12R₃ / (R₃ + 1) + R₁
R = [12R₃ / (R₃ + 1)] + 2
R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)
R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)
R = (14R₃ + 2 ) / (R₃ + 1)
The total current in circuit is calculated as;
I = V/R
I = 30 / R
I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)
I = (30R₃ + 30) / (14R₃ + 2) ------- (1)
The voltage in parallel circuit is the same
V₂ = V₃ = 24 V
V₃ = IR₃
24 = IR₃
I = 24/R₃ --------- (2)
Solve (1) and (2) together as follows;
24/R₃ = (30R₃ + 30) / (14R₃ + 2)
30R₃² - 306R - 48 = 0
Solve the quadratic equation, using formula method.
R₃ = 10.35 ohms
I₃ = V₃/R₃
I₃ = 24 V / 10.35
I₃ = 2.32 A
If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V
The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A
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For your assignment this week, research an athlete who has used steroids or some other performance enhancer in his/her career.
One notable athlete who has been associated with the use of performance-enhancing drugs (PEDs) is the American professional cyclist Lance Armstrong.
Armstrong gained worldwide recognition for his unprecedented seven consecutive victories in the Tour de France from 1999 to 2005. However, his remarkable achievements were tarnished when it was revealed that he had engaged in systematic doping throughout his career.
In 2012, after years of denial, Armstrong finally admitted to using banned substances, including erythropoietin (EPO), testosterone, corticosteroids, and blood transfusions, to enhance his performance. These substances boosted his endurance and oxygen-carrying capacity, providing him with an unfair advantage over his competitors. Armstrong's confession came after substantial evidence, including testimonies from teammates and extensive investigations, exposed his involvement in one of the most elaborate and sophisticated doping schemes in sports history.
Following his admission, Armstrong was stripped of his Tour de France titles and received a lifetime ban from professional cycling. The revelations surrounding his drug use had a profound impact on the sport, shaking its credibility and raising concerns about the prevalence of doping in cycling.
Armstrong's story serves as a cautionary tale, highlighting the ethical and moral dilemmas associated with doping in sports. His case underscores the importance of maintaining the integrity of athletic competition, the significance of stringent anti-doping measures, and the need for education and awareness regarding the risks and consequences of performance-enhancing substances.
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A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. What is the beaver’s mass?
A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy, then the mass is approximately 1.74 kg, and this can be calculated by using the kinetic energy (KE) of an object that is KE = (1/2) ×m × \(v^2\).
KE = (1/2) ×m × \(v^2\).
where m= mass of the object, v=its velocity.
The beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. Substituting these values into the above equation
45 J = (1/2) ×m × \((2.0 m/s)^2\)
Simplifying this equation:
45 J = (1/2) × m × 4.0\(m^2/s^2\)
45 J = 2 m × 2 \(m^2/s^2\)
45 J = 4 \(m^3/s^2\)
\(m^3\) = 45 J / 4 \(s^2\)
\(m^3\) = 11.25 kg×\(m^2/s^2\)
Taking the cube root of both sides to solve for mass,
m = (11.25 kg×\(m^2/s^2)^(^1^/^3^)\)
m = 1.74 kg (rounded to two decimal places)
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If you know the position vectors of a particle at two points along its path and also know the time it took to move from one point to the other, can you determine the particles instantenious velocity? its average velocity? explain.
We need the position vectors of a particle at two points along its path and also know the time it took to move from one point to the other to find the instantaneous velocity but not the average velocity.
What is the velocity?We need to take a moment to be able to explain to ourselves again the meaning of the term velocity. Let us recall that the term velocity would have to do with the change in the position of an object with time.
We know that the velocity is a vector quantity and as such we must have to look at the direction in which the distance that has been covered has passed through and this is something that we must keep in mind as we work through this question.
Now, we know that the velocity is the change in position as such we need the two positions of the object and the approximate time taken to make the change.
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Solar radiation at the surface of the earth is about 700 W/m2. How much solar energy is incident on a roof of dimensions 8.83 m by 13.67 m in 4.43 hours?
Given:
The solar power per unit surface of the earth is: P = 700 W/m²
The dimensions of the roof are: A = 8.83 m × 13.67 m
The time for which the solar radiation is incident on the roof is: t = 4.43 h
To find:
The energy incident on the roof.
Explanation:
The area A of the roof is:
\(A=8.83\text{ m}\times13.67\text{ m}=120.7061\text{ m}^2\)The time t can be converted into seconds as:
\(t=4.43\text{ h}=4.43\times60\text{ min}=4.43\times60\times60\text{ s}=15.948\times10^3\text{ s}\)The energy incident on the given surface area in the given time is calculated as:
\(E=P\times A\times t\)Substituting the values in the above equation, we get:
\(\begin{gathered} E=700\text{ W/m}^2\times120.7061\text{ m}^2\times15.948\times10^3\text{ s} \\ \\ E=84.494\times10^3\times15.948\times10^3\text{ s} \\ \\ E=1347.51\times10^6\text{ W.s} \\ \\ E=1347.51\times10^6\text{ J} \\ \\ E=1347.51\text{ M.J} \end{gathered}\)Final answer:
The amount of solar energy incident on the roof is 1347.51 Mega Joules (M.J)
A lead block is suspended by means of a string from the underside of a 8.00 kg block of wood of density of 696 kg/m3. If the upper surface of the wood is just level with the water, what is the tension in the string?(The density of lead is 11340 kg/m3)
Answer:
Tension of rope T = 35.16 N
Explanation:
Given:
Mass of block = 8 kg
Wood of density = 696 kg/m³
Density of lead = 11,340 kg/m³
Find:
Tension in the string
Computation:
Volume of wood = Mass of block / Wood of density
Volume of wood = 8 / 696
Using Archimedes law
Mw + M = (Vw + V) 1,000
8/1,000 + 11,340v = (Vw + V) 1,000
V = 3.47 x 10⁻⁴
Tension of rope T
T = v (11,340 - 1,000)9.8 N
T = (3.47 x 10⁻⁴)(11,340 - 1,000)9.8 N
Tension of rope T = 35.16 N
If the upper surface of the wood is just level with the water, the tension in the string is 34.2 Newton.
Mass of block of wood; \(m_w = 8.00kg\)
Density of wood; \(\delta _w = 696 kg/m^3\)
Density of lead; \(\delta _{Ld} = 11340 kg/m^3\)
Density of water; \(\delta _{water} = 1000kg/m^3\)
First we determine the volume of wood:
\(v_w = \frac{mass}{density} = \frac{m_w}{\delta w} = \frac{8.00kg}{696kg/m^3}\\\\v_w = 0.01149m^3\)
Now, using Archimedes principle:
Buoyancy force is determined using the equation:
\(F_b = V * \delta * g\)
Where:
\(F_b\) is the buoyancy force acting on the objectV is the submerged volume of the object\(\delta\) is the density of the fluid the object is submerged in( Density of water; \(\delta _{water} = 1000kg/m^3\))g is the force of gravity( \(9.8m/s^2\))We substitute our values into the equation
\(F_b = 0.01149m^3\ *\ 1000kg/m^3 * 9.8m/s^2\\\\F_b = 112.602 kg.m/s^2\\\\F_b = 112.602N\)
Now, buoyancy force \(F_b\) = Weight + Tension
\(F_b = mg + T\\\\T = F_b - mg\)
We substitute in our values
\(T = 112.602N - ( 8kg * 9.8m/s^2)\\\\T = 112.602N - 78.4kgm/s^2\\\\T = 112.602N - 78.4N\\\\T = 34.2N\)
Therefore, if the upper surface of the wood is just level with the water, the tension in the string is 34.2 Newton.
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A 39.4 kg beam is attached to a wall with a link and its far end is supported by a cable such that the angle between the beam and the cable is 90 degrees. If the beam is inclined at an angle of theta = 33.1 degrees with respect to horizontal, what is the magnitude of the horizontal component of the force exerted by the link on the beam?
Answer:
192.6N
Explanation:
Let's consider the forces acting on the beam:
Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.
Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.
Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.
Let's break down the forces acting on the beam:
Vertical forces:
W (weight of the beam) - T (vertical component of tension) = 0
T = W
Horizontal forces:
F_link (horizontal component of the force exerted by the link) = ?
To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.
Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:
F_link = W * sin(θ)
Let's substitute the given values:
W = 39.4 kg * 9.8 m/s^2
θ = 33.1 degrees
F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)
Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.
Assume that the body's muscle mechanism can be approximated by a spring with a uniform continuous mass distribution that follows Hooke's law. Concerning this,
A) find the effective mass of the spring with mass m.
Then, estimate the potential energy which can be mechanically stored in B) the muscles of each arm, and
C) the muscles of each leg,
and estimate the spring constant of
D) each arm muscles, and
E) each leg muscle.
F) Now, could estimate the speed of a runner by using these results?
Based on Hooke's law, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.
What is the spring constant?The spring constant or stiffness constant of an elastic spring is constant which describes the extent a bit forceapplied to an elastic spring will extend it.
Spring constant, K = force/extensionAssuming, a body's muscle mechanism is a spring obeying Hooke's law, the effective mass of the spring with mass m is 1/3 of the mass of the spring = m/3
The potential energy that can be stored = ke^2 / 2
where K is spring constant and e is the extension produced.
Therefore, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.
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Work-Energy Theorem & Power
A 0.5 kg mass sitting on smooth ice is accelerated from rest by a force until is
acquires a speed of 8 m/s. The force acts while the mass moves through a
displacement of 2 m.
A. Calculate the kinetic energy of the mass after the force acts.
B. Calculate the work done by the force.
C. Calculate the magnitude of the force that accelerated the mass.
Answer:
A. 16 J
B. 16 J
C. 8 N
Explanation:
A. Determination of the kinetic energy.
Mass (m) = 0.5 Kg
Velocity (v) =. 8 m/s
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 0.5 × 8²
KE = ½ × 0.5 × 64
KE = 0.5 × 32
KE = 16 J
B. Determination of the Workdone by the force.
Kinetic energy (KE) = 16 J
Workdone =.?
Workdone and kinetic energy has the same unit of measurement. Thus,
Workdone = kinetic energy
Workdone = 16 J
C. Determination of the force.
Workdone (Wd) = 16 J
Displacement (s) = 2 m
Force (F) =?
Wd = F × s
16 = F × 2
Divide both side by 2
F = 16 / 2
F = 8 N
A crowbar of 200 cm long is pivoted about to its other end to displace a load of 600 N. 0.5 m Calculate MA, VR and efficiency of the crowbar.
The mechanical advantage of the crow bar is 3 while the velocity ratio is 4. The efficiency of the machine is 75%.
What is the efficiency of the crow bar?We know that a machine is any device that can be used to make work a lot much easier. Thus, the machine is the object that could make less effort to be applied in making a greater work to be done as we can see in this case we have here.
From the question, the pieces of information that we can get are;
Distance moved by Effort = 200 cm
Distance moved by load = 0.5 m or 50 cm
Velocity ratio = Distance moved by Effort/Distance moved by load
= 200 cm /50 cm
= 4
Mechanical advantage is found to be; Load/Effort
= 600 N/200 N
= 3
Efficiency = Mechanical advantage/ Velocity ratio * 100/1
= 6/4 * 100/1
=3/4 * 100/1
= 75%
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Using the same cost and time estimates, consider any trade-offs that Drehex Corporation may have to make to complete the project. Camilla John Nora Oracio Cost per Hour $40 $30 $20 $15 Time to Complete Job 20 hours 30 hours 40 hours 50 hours Ideally, the process of technological design should be cost-effective and time-effective. However, sometimes this is simply not possible and trade-offs are necessary. Explain the trade-offs Drehex Corporation may have to make to complete the project.
Drehex Corporation may need to make trade-offs between cost and time to complete the project, considering the hourly rates and time estimates of their team members.
Corporation may have to make several trade-offs to complete the project based on the cost and time estimates provided. Here are some possible trade-offs they may need to consider:
Cost vs. Time: The corporation may need to decide whether to prioritize completing the project quickly or keeping the costs low. If they want to minimize costs, they might opt for a longer completion time by choosing a team member with a lower cost per hour. Conversely, if time is crucial, they might choose a team member with a higher cost per hour to expedite the process.Expertise vs. Cost: The team members have different levels of expertise, as indicated by their respective costs per hour. Drehex Corporation may need to evaluate the trade-off between the level of expertise required for the project and the associated cost. They might decide to invest more in a highly skilled team member to ensure the quality and efficiency of the project, even if it means incurring higher costs.Resource Allocation: The corporation will need to allocate resources effectively among the team members to ensure a balanced workload. They may need to assign tasks and responsibilities based on individual strengths and expertise, considering the trade-off between utilizing the most capable team members and maintaining a fair distribution of work.Quality vs. Time/Cost: The trade-off between project quality and time/cost is a common consideration. If Drehex Corporation wants to deliver a high-quality output, they might need to allocate more time and resources to ensure thoroughness and attention to detail. Conversely, if time or cost constraints are significant factors, they may need to compromise on certain aspects of quality to meet project deadlines or budget limitations.Ultimately, the trade-offs Drehex Corporation makes will depend on their specific project goals, budget, timeline, and the importance they place on factors such as cost-effectiveness, timeliness, expertise, and quality. Balancing these trade-offs effectively is crucial for successful project completion.
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Answer:
Sample Response: Oracio is the most cost-effective choice because he would cost the least to complete the project. However, he would also take the longest amount of time. Camilla could complete the job the fastest, but she costs more than Oracio. Drehex Corporation will have to decide if it is more important to save money or complete the work quickly to meet the deadline.
Explanation:
What kind of force draws certain types of metal together?
O A. Friction
O B. Nuclear
O C. Magnetic
O D. Weight
A magnetic force is the answer
I attempted to answer and got 0m, please explain how to get to the answer.
A cannonball is fired straight up with an initial velocity of 150 m/s. How high will it get before it stops moving upward (it comes to a temporary stop before falling back down)?
The maximum height to which the ball attain before falling back down is 1147.96 m
Data obtained from the questionThe following data were obtained from the question:
Initial velocity (u) = 150 m/sFinal velocity (v) = 0 m/s (at maximum height) Acceleration due to gravity (g) = 9.8 m/s²Maximum height (h) =?How to determine the maximum heightThe maximum height reached by the ball can be obtained as illustrated below:
v² = u² – 2gh (since the ball is going against gravity)
0² = 150² – (2 × 9.8 × h)
0 = 22500 – 19.6h
Collect like terms
0 – 22500 = –19.6h
–22500 = –19.6h
Divide both side by –19.6
h = –22500 / –19.6
h = 1147.96 m
Thus, the maximum height reached by the ball is 1147.96 m
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If you walk 5 meters north, 2 meters west, 4 meters south, and 7 meters east....what is your displacement?
If you walk 5 meters north, 2 meters west, 4 meters south, and 7 meters east....then the displacement is \(\sqrt{26}\).
What is Displacement?A displacement is a vector whose length is the shortest distance from the initial to the final position of a point P undergoing motion.
Solution:
As per the given statement when you walk 5 meters north, 2 meters west, 4 meters south, and 7 meters east... then you will be resulting in forming a right angled triangle from origin to ending point.
That right angled triangle will have
base=5m
perpendicular=1cm
hypotenuse=?
to find hypotenuse we use Pythagoras theorem:
\(h^{2}\)=\(b^{2}+ p^{2}\)
On putting values we get
\(h^{2}\)=\(b^{2}+ p^{2}\)
h=\(\sqrt{25+1}\)
h=\(\sqrt{26}\)
Hence, the displacement is \(\sqrt{26}\).
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If you measure the properties of an unknown material and find that it has a density of 3.13 g/cm3 (+/- 0.1 g/cm3) and boils at 1415 °C (+/- 5 ºC), which material would it most likely be?
A) Potassium iodide
B) Sulfur
C) Iodine
D) Lead nitrate
E) Copper chloride
F) Sodium chloride
G) Copper nitrate
Answer:
The correct option is A
Explanation:
For a substance to boil at 1415 °C shows the substance is an electrovalent/ionic substance (hence the elements are not the answer). Electrovalent/ionic substances are characterized by high melting and boiling points. Also, with a density of 3.13 g/cm³ (with a +/- 0.1 g/cm³), the correct answer is potassium iodide. This is because potassium iodide has a density of 3.12 g/cm³ (which is - 0.1 g/cm³). It should also be noted that pure potassium iodide boils at 1,330 °C, however the presence of impurities could increase the boiling point of the salt, thus an impure potassium iodide could have a density of 3.12 g/cm³ and a temperature around 1415 °C
"Potassium iodide" would it most likely be. A further explanation is provided below.
Given values are:
Density,
3.13 g/cm³Boiling point,
1415 CDensity can be change by,
+/-0.1 g/cm³Uncertainty in temperature,
+/-5°CWe can take the value of density from:
3.03 (3.13-0.1) to,3.23 (3.13+0.1)We can take the value of temperature from:
1410 C (1415-5) to,1420 C (1415+5)After checking the ranges, we find "Potassium iodide" have density as well as temperature in our range.
Thus the above answer is right.
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A plank AB 3m long weighing 20kg and with center of gravity 2m from the end A carries a load of mass 10kg at the end A it rests on two supports CandD.
1, compute the values of the reaction forces R1 and R2 at C and D.
2, how far from D and on which side of it must a mass of 24kg be placed on the plank so as to make the reactions equal? What are their values.
3,without this 24kg what vertical force applied at B will just lift the plank clear of D? What is then the reaction at C.
The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.
1) R1 and R2 at C and D respectively are given by the equation R2 = (m1 + m2)g - R1, where m1 and m2 are the masses of the plank and load, respectively, and g is the acceleration due to gravity. Hence, substituting values R2 = (20 + 10) × 9.81 - R1 = 294.3 - R1. Now, taking moments about D, the following equation can be obtained: (20 × 1 + 10 × 3)g = R1 × 2 + R2 × 3 = 2R1 + 3 × (294.3 - R1) = 882.9 - R1, from which R1 = 343.7 N and R2 = 294.3 - 343.7 = -49.4 N. Since the support at D can only push the plank upwards and cannot pull it downwards, a negative value for R2 implies that the plank is actually being pulled downwards by an external force. Therefore, the value of R2 is not relevant. 2) The total weight of the plank and the load acting at the end A is 20 + 10 = 30 kg. For the reactions at C and D to be equal, the 24 kg mass must be placed at a distance x from D such that x × 30 = 24 × 6, from which x = 12/5 = 2.4 m. Since the 24 kg mass is being placed to the left of the plank, it will cause the reaction at C to decrease and that at D to increase. Thus, if R is the vertical force applied at B, then taking moments about D gives 20g × 1 - 10g × 3 + R × 6 = 0, from which R = 90 N. Taking moments about C gives R × 3 - 10g × 2 = 0, from which R = 66.3 N. 3) The vertical force applied at B that will just lift the plank clear of D is the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D. The weight of the plank and the load acting at the end A is 20 + 10 = 30 kg, and the weight of the part of the plank that is to the right of D is 24 × 1.6 = 38.4 kg. Therefore, the vertical force applied at B that will just lift the plank clear of D is (20 + 10 + 38.4)g = 686.4 N. The reaction at C is zero because the plank is not being supported there anymore. The reaction at D is the same as the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D, which is 20 + 10 + 24 × 1.6 = 61.4 kg.For more questions on acceleration
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On land, the most massive concrete block you can carry is 25 kg. Given concrete’s 2200‐ kg/m3 density, how massive a block could you carry underwater
Answer:
46kg approx.Explanation:
Given data
Density of concrete ρ_c=2200kg/m3
Mass of concrete m_c= 25kg
In water
\(F_{P2} + F_{app}-m_{cg}=0\)
\(F_{app}=m_{cg}-F_{P2}\)
Max Fapp = 25*g
Buoyancy force
\(F_{P2} = \rho WgV_c= \rho Wg\frac{\rho_c}{m_c}\\\\F_{ p2}= \rho Wg\frac{\rho_c}{m_c}\)
\(25*g=m_cg- \rho W g\frac{mW}{\rho_c}= m_cg(1- \frac{\rho W}{\rho_c} )\)
\(m_c=25( \frac{\rho_c}{\rho_c- \rho W} )\)
substitute
\(m_c=25( \frac{2200}{2200- 1000} )\\\\m_c=25*1.833\\\\m_c=45.8\)
=46kg approx.
Question 81 point)
Ms. Vetter has not worked out in a long time. She is trying to lift her pet bunny cage off the ground to put into her car for their trip to Bunnyville
to visit some of her pet bunnies ancestors. If Ms. Vetter does not have enough _____ _____ she can use a simple machine to help her lift the cage off the ground and into her car.
A.craft supplies
B.big muscles
C.mechanical force
D.mechanical advantage
Answer:
(C) Mechanical Force
Explanation:
a motor that does 2400j of work in two minutes.
The power of the motor can be calculated by dividing the work done (2400J) by the time taken (2 minutes). Therefore, the power of the motor is 2400J/120s = 20W.
What is motor?Motor is a mechanical or electrical device that converts energy into motion. Motors are used in a variety of applications, including industrial, commercial, and residential. Examples of motors include electric motors, steam engines, and internal combustion engines. Electric motors use electrical energy to produce rotational mechanical energy, while steam engines produce rotational mechanical energy through the use of steam pressure. Internal combustion engines produce rotational mechanical energy through the combustion of fuel. Motors are used in a variety of applications, ranging from powering household appliances to running industrial machinery. In addition, motors are used to power various types of transportation, such as cars and boats. Motors are also used to power robotics in a variety of industries, including manufacturing and healthcare.
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The speed of light is 3×10^8 meters per second, which means that light can travel 300 million meters in just one second. How far can light travel in one minute?
Answer:
(1.8 × 10^9) meters in one minute
Explanation:
To determine how far light can travel in one minute, we need to multiply its speed by the number of seconds in a minute.
The speed of light is 3 × 10^8 meters per second.
There are 60 seconds in a minute.
Therefore, the distance light can travel in one minute is:
Distance = Speed × Time
Distance = (3 × 10^8 meters per second) × (60 seconds)
Calculating this, we get:
Distance = 3 × 10^8 meters/second × 60 seconds
Distance = 18 × 10^8 meters
Distance = 1.8 × 10^9 meters
So, light can travel approximately 1.8 billion (1.8 × 10^9) meters in one minute.
Convert 4 centimeters to meters using dimensional analysis and scientific notation. Please go step by step as I am having difficulty with this subject.
Answer:
\(thank \: you\)
If you were to subtract the net force from the weight of the falling object, what would you be solving for?
Answer: Air resistance
Explanation: If you subtract the net force from the weight of a falling object, you would be solving for a force that is not being balanced from the other forces.
The net force (with no external forces) on the falling object would just be the force of gravity. So, any force that unbalances the force of gravity would be what you are solving for. This can be air resistance, friction (if the object is sliding against a wall), or applied forces (pushing the object while it falls).