Trapezoid QRST with vertices Q(2,1) R(2,5) S(4,5) and T(8,1) 90 degree clockwise

Answer:

27 minutes

Step-by-step explanation:

Answer:

Step-by-step explanation:

If 11 flights were sampled with an 85% on-time arrival rate, the number of flights from the sample that arrived on time would be estimated to be 9.35, which would round to 9 flights.

This can be solved by:

(0.85x11)= 9.35

Since there can't be .35 of a flight, we would round to the nearest whole number, which would just be 9.

The final answer= 9 flights

Answer:

b. 5 meters

Step-by-step explanation:

1 meter = 1000 millimeters

5 meter = 5000 millimeters

Which is longer 5 meters or 400 millimeters?

5000 > 400

So, the answer is b. 5 meters.

Answer:

There are 250 adult tickets.  

There are 325 Student tickets.  

Step-by-step explanation:

Let a = the number of adult tickets

Let s = the number of student tickets

a + s = 575

a + 75 = s  Substitute a + 75 for s in the first equation'

a + a + 75 = 575  Combine like terms

2a + 75 = 575  Subtract 75 from both sides

2a = 500  Divide both sides by 2

a = 250

There are 250 adult tickets.  

Substitute 250 for a in the first equation

a + s = 575

250 + s = 575  Subtract 250 from both sides

s = 325

There are 325 Student tickets.  

Answer:

---------------------

Formula for area of a rectangle with dimensions l and w is:

Substitute 10 for l and 4 for w:

The results of operations between vectors are, respectively:

Case A: u + w = <- 3, - 1>

Case B: - 6 · v = <6, 6>

Case C: 3 · v - 6 · w = <- 21, - 15>

Case D: 4 · w + 3 · v - 5 · u = <39, 4>

Case E: |w - v| = √(4² + 3²) = 5

In this problem we must determine the operations between vectors, this can be done by following definitions:

Vector addition

v + u = (x, y) + (x', y') = (x + x', y + y')

Scalar multiplication

α · v = α · (x, y) = (α · x, α · y)

Norm of a vector

|u| = √(x² + y²)

Now we proceed to determine the result of each operation:

Case A:

u + w = <- 6, - 3> + <3, 2>

u + w = <- 3, - 1>

Case B:

- 6 · v = - 6 · <- 1, - 1>

- 6 · v = <6, 6>

Case C:

3 · v - 6 · w = 3 · <- 1, - 1> - 6 · <3, 2>

3 · v - 6 · w = <- 3, - 3> + <- 18, - 12>

3 · v - 6 · w = <- 21, - 15>

Case D:

4 · w + 3 · v - 5 · u = 4 · <3, - 2> + 3 · <- 1, - 1> - 5 · <- 6, - 3>

4 · w + 3 · v - 5 · u = <12, - 8> + <- 3, - 3> + <30, 15>

4 · w + 3 · v - 5 · u = <39, 4>

Case E:

|w - v| = |<3, 2> - <- 1, - 1>|

|w - v| = |<4, 3>|

|w - v| = √(4² + 3²) = 5

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Answer:

(0,-2) (3,-4) (6,-6)

Step-by-step explanation:

I think you start at (0,-2) then go over 3 to the right and down 2 since it's negative each time

Answer:

1+-1=0 I would assume that would be sufficient unless Im underthinking it.

An equation to model the sum of the situation will be +1 - 1 = 0.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that "A hydrogen atom has a zero charge because it has been negatively charged electron and one positively charged proton."

The expression for the given situation will be written as below:-

+1 - 1 = 0

Therefore, the equation to model the sum of the situation will be +1 - 1 = 0.

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Answer:

\(a_5 = 21\)

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms is always the same, and this difference is called common difference.

The nth term of an arithmetic sequence is given by:

\(a_n = a_1 + d(n-1)\)

In which \(a_1\) is the first term and d is the common difference.

In this question:

\(a_1 = 5, d = 4\). So

\(a_n = a_1 + d(n-1)\)

\(a_n = 5 + 4(n-1)\)

Find the value of a_5

\(a_n = 5 + 4(n-1)\)

\(a_5 = 5 + 4(5-1) = 5 + 16 = 21\)

So

\(a_5 = 21\)

The \(a_{5}\) term of an arithmetic sequence is 21.

An arithmetic sequence is a sequence of numbers where the difference between consecutive terms is constant, and this difference is called the common difference.

The nth term of the sequence is given by

\(\rm a_{n} =a_{1} + (n-1)d\\\)

\(a_{1}\)= the first term of the sequence and d is a common difference.

\(\rm a_{1} = 5, d=4\\\rm a_{n} =a_{1} + (n-1)d\\\rm a_{n} = 5 + 4(n-1)\\\rm a_{5} = 5 + 4(5-1)\\\rm a_{5} = 21\)

Therefore, The \(a_{5}\) term of an arithmetic sequence is 21.

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Part A: 5 out 25 lobsters have dangerous levels of mercury

Part B: the 95% confidence interval is given by (4.45, 5.65)

since everything is given all I had to do is find the critical value which can be found from the resource packet = 2.064

Using the formula we find 5.05+-2.064*1.45/5 = ( 4.45,5.65)

For this case, we have 95% of confidence that the true mean for the average number of lobsters with dangerous levels of mercury is between 4.45,5.65

Answer:

The margin of error is of 20, option B.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the subtraction between the bounds, divided by 2.

In this question:

Lower bound: 200

Upper bound: 240

Margin of error:

(240 - 200)/2 = 40/2 = 20

The margin of error is of 20, option B.

Answer:

Step-by-step explanation:

Chloe has finished 60% of her test. She has answered

18 questions. How many questions are on the test?

18 = 60%

so

18 : 60 * 100 = 30

Answer: k-a=y

Step-by-step explanation:

Since we are solving for y, we have to subtract a from both sides a-a cancels out and subtract a from k. This leaves us with the equation k-a= y since a is no longer on the other side.

The cost of one hosta is approximately $7 and the cost of one geranium is approximately $4.

To find the cost of one hosta and one geranium, we can set up a system of equations based on the given information.

Let's assume the cost of one hosta is represented by 'h' and the cost of one geranium is represented by 'g'.

From the information given, we can set up the following equations:

Eugene's spending:

18h + 6g = $150

Jessica's spending:

7h + 16g = $113

We can now solve this system of equations to find the values of 'h' and 'g'.

Multiplying the first equation by 2 and the second equation by 3 to eliminate 'g', we get:

36h + 12g = $300

21h + 48g = $339

Now, we can subtract the second equation from the first to eliminate 'h':

(36h + 12g) - (21h + 48g) = $300 - $339

36h - 21h + 12g - 48g = -$39

15h - 36g = -$39

Simplifying further, we have:

15h - 36g = -$39

Now we can solve this equation for 'h' and substitute the value back into any of the original equations to find 'g'.

Let's solve for 'h':

15h = 36g - $39

h = (36g - $39) / 15

Substituting this value of 'h' into Eugene's equation:

18[(36g - $39) / 15] + 6g = $150

(648g - $702) / 15 + 6g = $150

648g - $702 + 90g = $150 * 15

738g - $702 = $2250

738g = $2250 + $702

738g = $2952

g = $2952 / 738

g ≈ $4

Now, substituting the value of 'g' back into Eugene's equation:

18h + 6($4) = $150

18h + $24 = $150

18h = $150 - $24

18h = $126

h = $126 / 18

h ≈ $7

Therefore, the cost of one hosta is approximately $7 and the cost of one geranium is approximately $4.

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Answer:

Step-by-step explanation:

Answer:

0-4-9 = -13 or -4-9 = -13

Explanation:

Basically it starts at 0, then it moves to the left of the number line meaning it subtracts. It moves to the left by 4, so it is subtracting 4 from 0. Then it moves to the left again by 9, so you subtract 9 from 0-4

In the end, it is 0-4-9 or you can remove the 0 and be -4-9

Hope this was helpful :)

Answer:

Step-by-step explanation:

you ok bud? dont be sad its ok :D

Answer:

the two numbers are x = -81 - 81*sqrt(7) and y = (-1 - sqrt(7)) / 2.

Step-by-step explanation:

To find the two numbers, we can use the formula for the sum of two numbers:

x + y = z

Where x and y are the two numbers and z is their sum.

In this case, we know that the difference between the two numbers is 9, so we can set x to be the larger of the two numbers and y to be the smaller number:

x - y = 9

We can also use the fact that the product of the two numbers is 162 to set up an equation:

xy = 162

Now we can solve for x and y by substituting the second equation into the first and solving for x:

x = 162/y

Substituting this expression for x into the first equation gives us the following:

(162/y) - y = 9

We can simplify this equation to:

162 - y^2 = 9

We can solve for y by completing the square:

y^2 - y + 4.5 = 0

We can use the quadratic formula to find the solutions for y:

y = (1 +/- sqrt(1 - 414.5)) / (2*1)

This simplifies to:

y = (-1 +/- sqrt(7)) / 2

Since y is the smaller number, we need to choose the negative solution:

y = (-1 - sqrt(7)) / 2

We can use this value of y to find the value of x:

x = 162/y = 162/(-1 - sqrt(7))/2

This simplifies to:

x = (-81 - 81*sqrt(7))/2

So the two numbers are x = -81 - 81*sqrt(7) and y = (-1 - sqrt(7)) / 2.

Answer:

9, 18

Step-by-step explanation:

lets say the smaller number is x, then the larger number is x+9

we know x * (x+9) = 162.

expand to get x^2 + 9x - 162 = 0, factor or use the quadratic formula to get x^2 + 9x -162 = (x + 18) (x - 9) = 0, so x = 9 or -18.

I'm assuming the two numbers must be positive, so x = 9, and the larger number is 9+9 = 18.

Answer:

y = 3x - 11

Step-by-step explanation:

(3, -2) and (5, 4)

m = 4+2/5-3

m = 6/2

m = 3

y = 3x + b

4 = 3(5) + b

4 = 15 + b

b = -11

y = 3x - 11

Answer:

4 lollipops and 3 penicls in each bag, so 50 bags

Step-by-step explanation:

I've had to do this one before

The system A has no solution.

The system B has the solution y=( 3-x )/3

What is the solution to an equation?

In order to make the equation's equality true, the unknown variables must be given values as a solution. In other words, the definition of a solution is a value or set of values (one for each unknown) that, when used as a replacement for the unknowns, transforms the equation into equality.

System A:

x+3y=9..........(1)

-x-3y=9 ..........(2)

(1) => x=9-3y........(3)

Substitute (3) into (2)

(2) = >  - ( 9-3y ) - 3y = 9

          -9 + 3y - 3y = 9

          -9 =9

This is false.

So, the system has no solution.

System B:

-x-3y=-3..........(1)

x+3y=3..........(2)

(2) => x=3-3y........(3)

Substitute (3) into (1)

-(3-3y)-3y=-3

-3+3y-3y= -3

-3=-3

This is true,

So, the solution is:

x=3-3y

=> 3y= 3-x

=> y=( 3-x )/3

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Answer:

a) 1/3

b)45

Step-by-step explanation:

Answer:

a) 1/3

b)45

have a good day/night

Based on the equation given, the value of the string will be $10.50.

It should be noted that 1 yard = 36 inches.

Therefore, 108 inches = 3 yards

Since the string is on sale for $3.50 a yard, the cost of 3 yards will be:

= $3.50 × 3

= $10.50

In conclusion,the answer is $10.50.

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Answer:

Step-by-step explanation:

answer: the original number is 62.

Given :

Units digits is thrice the tens digit

The digits interchange when - 36 is added

To find :

The number

Solution :

✯

Let the digits be -

   Units place as 3y

   Tens place as 10(y)

⇒ 10(y) + 3y

⇒ 10y + 3y

⇒ 13y --------- (Orignal Number)

✯

Let the digits be -

   Units place as y

   Tens place as 10(3y)

⇒ 10(3y) + y

⇒ 30y + y

⇒ 31y --------- (Number with reversed digits)

✯

The number gets reversed when 36 is added to it.

⇒ 13y + 36 = 31y

⇒ 13y - 31y = - 36

⇒ 18y = 36

⇒ y = 36/18

⇒ y = 2

✯

⇒ 13y

⇒ 13(2)

⇒ 26

✯

The units place should be thrice of the tens place,

⇒ 2 × 3 = 6

Units place is 6

Reversed digits are 62,

⇒ 26 + 36 = 62

⇒ 62 = 62

The Orignal Number is 62.

The given question requires that we get the number of men

We have the ratio of men to women to be

we are given the number of women to be 595

Thus, to get the numbers of men, we can represent the number of men to be m, and then we can set up the relationship:

We can get the value of m by cross multiplying

We will have

The  length of the hypotenuse of the triangle whose other two sides are of the length 5√2 units is given by: Option B: 10 units.

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

\(|AC|^2 = |AB|^2 + |BC|^2\)

where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).

For this case, consider the figure attached below.

Then, we are given the facts that:

Using the Pythagoras theorem, we get:

\(|AC|^2 = |AB|^2 + |BC|^2\\\\h^2 = (5\sqrt{2})^2 + (5\sqrt{2})^2 \\\\h^2 = 2(5\sqrt{2}))^2\)

Taking root, we get:

\(h = \sqrt{2 (5\sqrt{2})^2}\) (only positive root since h is denoting length, which is a non-negative quantity).

Thus, we get:

\(h = \sqrt{2 (5\sqrt{2})^2} = \sqrt{(5\sqrt{2})^2} \times \sqrt{2} = (5\sqrt{2}) \times \sqrt{2} = 5 \times (\sqrt{2})^2 = 5 \times 2 \\\\h= 10 \: \rm units\)

(square cancelled the square root).

Thus, the  length of the hypotenuse of the triangle whose other two sides are of the length 5√2 units is given by: Option B: 10 units.

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Answer:

10 units.

Step-by-step explanation:

just took the quiz

Write z = -8 in polar form:

\(z = -8 = 8e^{i\pi}\)

Then the cube roots of z are

\(z^{1/3} = 8^{1/3} e^{i\left(\frac{\pi+2n\pi}3\right)\)

where n ∈ {0, 1, 2}, or

\(z^{1/3} \in \left\{8^{1/3} e^{i\pi/3}, 8^{1/3} e^{i\pi}, 8^{1/3} e^{i\,5\pi/3}\right\} \\\\ z^{1/3} \in \left\{2 \left(\dfrac12 + i\dfrac{\sqrt3}2\right), -2, 2 \left(\dfrac12-i\dfrac{\sqrt3}2\right)\right\} \\\\ \boxed{z^{1/3} \in \left\{1+i\sqrt3, -2, 1-i\sqrt3\right\}}\)