the accelaration is 0.009027.
what is accelaration?
accelaration is the eate of the change of thr velocity of an object with respect by time.
Resulting torque = (ryFz - rzFy) i +(rzFx - rxFz) j+(rxFy - ryFx) k
(b) Magnitude of resulting torque = = 3.99 Nm
(c) angular acceleration = = 0.009027 rad/s²
Given Data;
I = 442 kg˙m2
rx = 0.76 m,
ry = 0.035 m,
rz = 0.015 m,
Fx = 3.6 N,
Fy = -2.8 N,
Fz = 4.4 N
F = Fx i + Fy j + Fz ------------------------------1
r = rx i + ry j + rz k ------------------------------2
(a) Torgue is given by the formula;
T = r * F ------------------------------------3
Putting equation 1 and 2 into equation 3, we have;
Torque= r x F
= (rx i +ry j +rz k) x (Fx i + Fy j +Fz k )
= (ryFz - rzFy) i +(rzFx - rxFz) j+(rxFy - ryFx) k
Therefore,
Resulting torque = (ryFz - rzFy) i +(rzFx - rxFz) j+(rxFy - ryFx) k
b)
Putting given values into the above expression, we have torque = (ryFz - rzFy) i +(rzFx - rxFz) j+(rxFy - ryFx) k
=(0.035*4.4 - (0.015*-2.8))i +(0.015*3.6 - 0.76*4.4)j+(0.76* -2.8 - 0.035*3.6)k
= (0.154 +0.041) i + (0.054 - 3.344) j + (-2.128 -0.126) k
= (0.196) i - (3.29) j + (-2.254) k
Magnitude of resulting torque = √(0.196² + 3.29² +2.254²
=√15.943031
= 3.99 Nm
c) Angular acceleration is given by the formula;
angular acceleration =in torque/moment of inertia
= 3.99/ 442
= 0.009027 rad/s²
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Explain the interactions the model shows between earths systems
The Earth has four main interconnected systems: the atmosphere, the hydrosphere, the lithosphere, and the biosphere.
The model shows how all four systems interact with each other and influence each other. The atmosphere is responsible for controlling the climate and transferring energy through air currents and radiation. The hydrosphere includes all water on Earth, both frozen and liquid, and it is responsible for transporting water and energy. The lithosphere is made up of rocks, soil, and minerals, and it helps regulate and moderate the Earth's temperature. Finally, the biosphere is made up of all living things, and it influences and is influenced by all of the other systems.
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A naval navigator is using sonar to look for sunken cargo. The waves he is using have a frequency of 120
kHz and a wavelength of 3 mm. How far away is the cargo if the sound wave is emitted at exactly 9:24 a.m.
and returns to hit the ship's sensor 3 seconds later?
Answer should be in meters
With the use of wave speed and echo formula, the distance is 540 m
What is Echo ?Echo can simply be defined as a reflection of sound wave. Where as, Sound wave is longitudinal wave.
Given that a naval navigator is using sonar to look for sunken cargo. The waves he is using have a frequency of 120 kHz and a wavelength of 3 mm.
The wave speed V = Fλ
Where
V = ?F = 120 KHz = 120,000λ = 3 mm = 0.003 mV = 120000 × 0.003
V = 360 m/s
How far away is the cargo if the sound wave is emitted at exactly 9:24 a.m. and returns to hit the ship's sensor 3 seconds later?
Speed V = 2S/t
where
S = distance ?t = time taken = 3 s360 = (2 × S)/3
360 × 3 = 2S
S = 1080/2
S = 540 m
Therefore, the cargo is 540 m away
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Write a summary paragraph discussing this experiment and the results. Use the following questions and topics to help guide the content of your paragraph.
According to your data, was your hypothesis correct? (Be sure to refer to your data when answering this question.)
Summarize the conclusions that you can draw from this experiment. Use the questions above to guide your ideas.
Summarize any difficulties or problems you had in performing the experiment that might have affected the results. Describe how you might change the procedure to avoid these problems.
Give at least three examples from everyday life where an inclined plane is used to reduce the effort force needed to accomplish a task.
In this experiment, you will determine the IMA, AMA, and efficiency.
The materials for this experiment are:
a smooth board
smooth block or other object to drag up a plane
a spring scale (calibrated in newtons)
string
books or blocks to support the inclined plane
and a meter stick.
Your job is to observe the experiment and collect your own data from this demonstration.
Be ready to record your observations and data.
You will be pulling an object up an inclined plane at different inclines.
Make and record a hypothesis about how changine the slope of inclined plane will affect the efficiency.
Measure the height and length of the plane, record the measurements.
Measure the mass of the object, and record. Convert the mass from grams to newtons by dividing by 102, and record.
Now slowly and steadily pull the object up the incline with the spring scale and string kept parallel to the incline.
Record the readout on the scale.
This will be the effort force.
Now increase the slope of the incline by increasing the height.
Measure the height of the new incline.
The length of the incline remains constant.
Slowly and steadily pull the object up the incline, record the readout from the scale.
You are now ready to complete the rest of this assignment.
Answer:
LOL i belive its 200 because i did this exact same thing yesterday for homework and got it right bcs i got it lol, yw btw! hahaha! good luck also, subscribe to my channel!
Explanation:
TRUE OR FALSE!!!!!
PLEASE HELP
Igneous rock is formed by volcanoes releasing magma from the mantle, the rock cools and piles up forming a mountain. Rivers direct water to cool magma underground forming metamorphic rock under lake beds.
Answer:
true
Explanation:
this is true, igneous rocks are formed from molten lava when it cools
Answer: True
Explanation:
Shows three layers of soil in a tube 100 mm times 100 mm in cross section. Water is supplied to maintain constant head difference of 300 mm across the sample. The hydraulic conductivity of the soils in the direction of flow through them are as follows: Find the rate of water supply in cm^3/hr.
The rate of water supply (in \(cm^3/hr\)) is equal to the Q × 3600 cm³/hr.
Given data:
Cross-sectional area of the tube = 100 mm × 100 mm
Water head difference (Δh) = 300 mm
Hydraulic conductivity of the three soils = K₁, K₂, K₃
Let's assume that the length of the soil sample is "L" mm. To find the rate of water supply, we need to calculate the discharge through the soil sample.
So, the formula to calculate the discharge (Q) is given by:
Q = (A × Δh × K) / L
Where, A = Cross-sectional area of the tube
Δh = Water head difference across the soil sample
K = Hydraulic conductivity of the soil
L = Length of the soil sample
Substituting the values in the above formula, we get,
\(Q = (100 mm * 100 mm * 300 mm * (K_1 + K_2 + K_3)) / L\)
So, the rate of water supply = Q × 3600 cm³/hr (1 hour = 3600 seconds)
Therefore, the required rate of water supply is given by, \(Q = (100 mm * 100 mm * 300 mm * (K_1 + K_2 + K_3)) / L\) cm³/sec
Now, let's understand the answer step by step. The given cross-sectional area of the tube is 100 mm × 100 mm.
Hence, the area of the tube is A = 100 mm × 100 mm = 10,000 mm²
The water head difference across the soil sample is given as 300 mm.Δh = 300 mm
Let's consider that the length of the soil sample is "L" mm. L = L mm The hydraulic conductivity of the three soils is given by K₁, K₂, and K₃.K₁, K₂, and K₃ are given in terms of the direction of flow through them.
The formula to calculate the discharge (Q) is given by: \(Q = (A * \Delta h * K) / L\)
Now, we can substitute the given values in the above formula. \(Q = (100 mm * 100 mm * 300 mm * (K_1 + K_2 + K_3)) / L\)
This gives us the value of the discharge through the soil sample. Now, we need to calculate the rate of water supply, which is given by Q × 3600 cm³/hr.
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A wave has a wavelength of 4 m and a frequency of 85 Hz. What is the speed of this wave?
The speed of wave with a wavelength of 4 m and a frequency of 85 Hz is 340m/s
The speed of a wave is the product of the frequency of the wave and its wavelength. Mathematically, it is expressed as:
\(v = f \lambda\) where:
f is the frequency
\(\lambda\) is the wavelength
Given the following:
f =85Hz
\(\lambda\) = 4 m
Substitute the given parameter into the formula:
v = 85 × 4
v = 340m/s
Hence the speed of wave with a wavelength of 4 m and a frequency of 85 Hz is 340m/s
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A 5. 69x10^-2kg tennis ball moves at a speed of 13m/s. Then the ball is struck by a racket, causing it to rebound in the opposite direction at a speed of 18m/s. What is the change in the ball's momentum
Explanation:
The change in an object's momentum is equal to the final momentum minus the initial momentum.
The momentum of an object is given by the product of its mass and velocity:
Initial momentum = mass * initial velocity
Final momentum = mass * final velocity
Given:
Mass of the tennis ball = 5.69x10^-2 kg
Initial velocity = 13 m/s
Final velocity = -18 m/s (opposite direction)
Let's calculate the initial momentum and final momentum:
Initial momentum = (5.69x10^-2 kg) * (13 m/s)
Final momentum = (5.69x10^-2 kg) * (-18 m/s)
Now, let's calculate the change in momentum:
Change in momentum = Final momentum - Initial momentum
Plugging in the values:
Change in momentum = [(5.69x10^-2 kg) * (-18 m/s)] - [(5.69x10^-2 kg) * (13 m/s)]
Performing the calculation will give you the change in the ball's momentum.
Hope I helped
Pressure of 76cm of mercury column is pa
The pressure of 76 cm of mercury column is 10132.5 Pa.
Pressure, in the physical sciences, the perpendicular force per unit area, or the stress at a point within a confined fluid.
The pressure of 76 cm of mercury column can be converted to Pascals (Pa) using the following conversion factor:
1 atm = 101325 Pa
760 mmHg = 1 atm
Therefore,
76 cm Hg = (76/760) atm = 0.1 atm
Now, we can convert this pressure in atm to Pascals using the following conversion factor:
1 atm = 101325 Pa
Therefore,
0.1 atm = 0.1 * 101325 Pa = 10132.5 Pa
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--The complete question is, Pressure of 76cm of mercury column is ______ pa.--
Which of the above would double the wavelength of the fundamental resonant mode on the string? Select the correct answer A. None of these options would double the wavelength of the fundamental mode. B. Decrease the linear mass density by a factor of 2C. Decrease the linear mass density by a factor of 4D. Increase the linear mass density by a factor of 2E. Increase the linear mass density by a factor of 4
E. Increase the linear mass density by a factor of 4 would double the wavelength of the fundamental resonant mode on the string.
To double the wavelength of the fundamental resonant mode on the string, we need to increase the length of the string or decrease the tension on the string or increase the linear mass density of the string. Option A states that none of the given options would double the wavelength of the fundamental mode, which is incorrect. Option B suggests decreasing the linear mass density by a factor of 2, which would result in a higher frequency and a shorter wavelength. Therefore, option B is incorrect as well. Option C suggests decreasing the linear mass density by a factor of 4, which would result in a higher frequency and a shorter wavelength. Thus, option C is also incorrect.
Options D and E suggest increasing the linear mass density of the string. Option D suggests increasing it by a factor of 2, which would decrease the frequency and increase the wavelength. However, to double the wavelength, we need to increase the length or decrease the tension. So, option D is also incorrect. Therefore, the correct answer is option E, which suggests increasing the linear mass density by a factor of 4. This would decrease the frequency and double the wavelength of the fundamental resonant mode on the string.
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A school bus has a mass of 18,200 kg k g . The bus moves at 15.5 m/s m / s .
Answer:
whatttt
Explanation:
what do u ask boy? just ask.
What is the mass of a skateboard that is accelerating at 7 m/s when it is pushed with 49N?
Pls
Answer:
m = 7 kg
Explanation:
F = m × a
49 = m × 7
7m = 49
m = 49/7
m = 7 kg
According to the article Alien Antimatter Crashes into Earth e: More than 60 years ago, future Nobel laureate Sheldon Glashow predicted that if an antineutrino - the antimatter answer to the nearly massless neutrino - collided with an electron, it could produce a cascade of other particles. The "Glashow resonance e" phenomenon is hard to detect, in large part because the antineutrino needs about 1,000 times more energy than what's produced in the most powerful colliders on Earth. Let's compare this event to an ordinary baseball with a mass of 146 g. Please use three significant figures in your calculations. Question 1 2 pts What is the threshold antineutrino energy for the Glashow resonance in peta electronvolts (PeV)? Question 2 2 pts What is this threshold energy in units of joules? dance Question 3 2 pts Now consider a baseball with the same kinetic energy as that of the Glashow resonance. What speed in m/s would correspond to this energy? Question 4 2 pts What is this rate in units of inches/second? Question 5 3 pts Compare and contrast IceCube e to Ice Cube e. How are they the same? How are they different? Edit View Insert Format Tools Table 12pt Paragraph BIU A ev T²v
FULL SOLUTION BELOW THE PIC.
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Name at least four factors involved in performing a good throw.
Answer:
You need to have a good stance, release, power, speed, body, movement, and aim. You should be able to throw an effective pass or throw by using your body and having the correct amount of balance and form
A 2.0 kg rock is dropped from a height of 125 m. What is the momentum of the object just before it strikes the ground (Use g=10 m/s2)?
Answer:
100Ns
Explanation:
find velocity and then plug into momentum formula momentum=(velocity)(mass)
Answer:
5,000 kg-m/s going south
Explanation:
Since you're only given mass and height, not velocity. You have to find velocity first. The equation for velocity is v=2gh. We know gravity is 10 since it's given & height is also given which is 125m. After doing the math, it's 2,500. Now that you have velocity, you can plug velocity into the formula for momentum which is p=mv. 2.0 times 2,500 = 5,000 kg-m/s going south.
The figure below shows a shooting competition, where air rifles fire soft metal at distant targets
Answer:
where is the figure?
Explanation:
2. What is the distance to a star, in parsecs, if its measured parallax (p) is 1/30 of an
arc second (use equation below)? What is its distance in light years? Show your
work!
Dist. (in pc) = 1/ Parallax (in arc sec)
The distance to the star, in parsecs, is 30 pc.
The distance to the star, in light years, can be calculated using the conversion factor of 3.26 light years per parsec. Therefore, the distance to the star in light years is approximately 97.8 light years.
The distance to a star can be determined using its measured parallax angle. Parallax is the apparent shift in the position of an object when viewed from two different points. It is measured in units of arc seconds.
The formula to calculate the distance to a star in parsecs is:
Distance (in pc) = 1 / Parallax (in arc sec)
Given that the measured parallax is 1/30 of an arc second, we can substitute this value into the formula:
Distance (in pc) = 1 / (1/30) = 30 pc
This gives us the distance to the star in parsecs.
To convert the distance to light years, we use the conversion factor of 3.26 light years per parsec. Multiplying the distance in parsecs by this conversion factor gives us the distance in light years:
Distance (in light years) = 30 pc × 3.26 light years/pc = 97.8 light years
Therefore, the distance to the star is approximately 30 parsecs or 97.8 light years.
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List between six and eight student organizations either offered by your school or offered
at other schools. Use online research if necessary. Explain how these organizations
encourage growth and what you can learn from being involved in them. Discuss the
skills you can learn from certain organizations, and other benefits of being involved.
Examples of student-led organizations are:
Academic and educational organizationsCommunity service organizationMedia and publications organizationsPolitical or multicultural organizationsRecreation and sports organizationsStudent government organizationsReligious and Spiritual organizations
The benefits of getting involved in any of these are many. They include but are not limited to:
It helps one to learn more about oneselfIt is a great place to develop leadership skillsIt offers the opportunity for people to build life-long networks
Skills learned in class can be practiced and honed in these organizationsSoft skills such as team-intellignce, and social intelligence can be learned in these organizationsValuable experiences that count in real-life jobs can be learned hereIt is also an opportunity to give back to the community and to have fun
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explain how energy carried by a light and sound wave varies with amplitude and frequency properties brainly WILL GIVE 100 POINTS
Answer:
A sound is a form of energy, just like electricity, heat, or light. When you strike a bell, it makes a loud ringing noise. Now instead of just listening to the bell, put your finger on the bell after you have struck it. Can you feel it shaking? This movement or shaking, i.e. the to and fro motion of the body is termed as Vibration.
The sound moves through a medium by alternately contracting and expanding parts of the medium it is travelling through. This compression and expansion create a minute pressure difference that we perceive as sound. Let’s discuss the characteristics of sound waves like amplitude, frequency, wavelength, and timbre.
Explanation:
The amount of energy carried by them is proportional to their frequency and amplitude. The greater the frequency, the greater the energy, and the greater the amplitude, the greater the energy.
What is frequency?The frequency of a repeating event is the number of occurrences per unit of time. It is also known as temporal frequency to distinguish it from spatial frequency and ordinary frequency to distinguish it from angular frequency.
In physics, frequency is the number of waves that pass through a fixed point in one unit of time; it is also the number of cycles or vibrations that a body in periodic motion undergoes in one unit of time.
Their energy carrying capacity is proportional to their frequency and amplitude. The more frequency there is, the more energy there is, and the more amplitude there is, the more energy there is.
Thus, this way, energy carried by a light and sound wave varies with amplitude and frequency properties.
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Water (density = 1 ´ 103 kg/m3) flows at 15 m/s through a pipe with radius 0. 040 m. The pipe goes up to the second floor of the building, 3. 0 m higher, and the pressure remains unchanged. What is the speed of the water flow in the pipe on the second floor?
The is that the velocity of water flow in the pipe on the second floor is 13.6 m/s.
To calculate the velocity of water flow on the second floor, we can use Bernoulli’s principle which states that the pressure and speed of a fluid are inversely proportional to each other. Pressure + (1/2) * Density * Velocity^2 + Density * g * Height
= Constant (where g = acceleration due to gravity)In this problem, since the pressure remains unchanged, we can eliminate the first term on both sides of the equation for both positions. Using Bernoulli’s principle for position 1 and 2 as:
(1/2) * Density * Velocity1^2 + Density * g * H1 = ConstantPosition 2:
(1/2) * Density * Velocity2^2 + Density * g * H2
= ConstantConstant
= (1/2) * Density * Velocity1^2 + Density * g *
H1Taking the difference of the above equations we get:1/2 * ρ * (V2^2 - V1^2)
= -ρghV2^2 - V1^2
= -2ghV2^2 = V1^2 - 2ghV2
= √(V1^2 - 2gh)
The negative sign is ignored as it represents the direction of flow. Putting the values we get:
V2 = √(15^2 - 2 × 9.81 × 3)
= 13.6 m/s
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Which of these is a chemical property of aluminum?
A. Aluminum has a density of 2.70 g • cm^-3
B. Aluminum is silvery white in color
C. Aluminum is highly reactive
D. Aluminum is a soft metal
A large pendulum swings in the lobby of the United Nations building in New York City. The pendulum has a 91-kg gold-plated bob and a length of 22.9 m. Assume g = 9.81 m/s2.
Part A
How much time does it take for the bob to swing from its maximum displacement to its equilibrium position?
Express your answer to three significant figures and include the appropriate units.
Answer:
t = 2.40 s
Explanation:
It just told me
Which equation should be used to calculate the speed of a wave?
speed = frequency x wavelength
speed = frequency x hertz
speed = period x wavelength
speed = period x hertz
The equation should be used to calculate the speed of a wave is speed = frequency x wavelength.
What is the formula for wave speed?The speed of a wave is calculated by the equations: V = λ . f or V = λ/T, and the unit of measurement is m/s. This speed depends on the medium: in gaseous media, the speed is lower than in solid media.
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The equation should be used to calculate the speed of a wave is speed = frequency x wavelength.
What is Speed of wave?Wave speed is the movement of a progressive wave, which is an energy-moving disturbance that takes the shape of an oscillation and moves from one place to another.
The wavelength and frequency of a wave both affect its speed. A wave's speed is a crucial factor because it enables us to estimate how quickly the wave will disperse in the medium, which is the substance or material that will carry it.
This is the water in the case of ocean waves and the air in the case of sound waves. The kind of wave and the physical properties of the medium in which it is flowing also affect a wave's velocity.
Therefore, The equation should be used to calculate the speed of a wave is speed = frequency x wavelength.
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A massless rod is fixed to a wall on one end. A cable is attached to the wall and the center of the rod. The cable makes an angle of 60° to the wall. If the maximum tension of the cable is 10 n, what is the maximum amount of weight that can hang from the end of the rod?.
The most extreme sum of weight that can hang from the conclusion of the pole is 8.66 N.
The most extreme sum of weight that can hang from the conclusion of the bar is calculated as follows.
Apply the equation for pressure utilizing Newton's moment law of movement.
Newton's moment law of movement states that the constrain experienced by a question is specifically relative to the item of the mass and speeding up of the question.
T sinθ = W
Where T is maximum tension in cable
θ is angle of inclination of cable
W is weight of cable
10 sin (60) = W
8.66 N = W
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Two objects (39.0 and 18.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley hangs from the ceiling. Find the acceleration of the objects.
The acceleration of the objects can be determined by applying Newton's second law and considering the tension in the string. The acceleration is found to be approximately 2.31 m/s², directed towards the heavier object.
To find the acceleration of the objects, we can consider the forces acting on each object. Let's assume the 39.0 kg object is hanging vertically, and the 18.0 kg object is on the horizontal surface. The tension in the string will be the same for both objects.
For the 39.0 kg object:
The gravitational force acting on it is given by F₁ = m₁g, where m₁ is the mass of the object and g is the acceleration due to gravity. As the object is accelerating downwards, there is a net force acting on it in the downward direction. The tension in the string is directed upwards. So, we have T - F₁ = m₁a, where a is the acceleration of the system. Therefore, T = m₁(g + a).
For the 18.0 kg object:
The gravitational force acting on it is F₂ = m₂g, where m₂ is the mass of the object. As the object is on a horizontal surface, the net force acting on it is given by T - F₂ = m₂a. Since the object is moving towards the right, the acceleration is directed towards the right.
Since the tension in the string is the same for both objects, we can equate the two expressions for T: m₁(g + a) = T = m₂g - m₂a. Solving this equation for a, we get a = (m₂g) / (m₁ + m₂) - (m₁g) / (m₁ + m₂). Substituting the given values, we find a = 2.31 m/s². The negative sign indicates that the acceleration is towards the heavier object.
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The distance between two consecutive crests is 2. 5 meters. Which characteristic of the wave does this distance represent? A. Amplitude B. Frequency C. Period D. Wavelength E. Phase.
D. Wavelength. The distance between two consecutive crests represents the wavelength of a wave. Wavelength is defined as the distance between two corresponding points on a wave, such as two crests or two troughs.
It is typically measured in meters and determines the spatial extent of one complete cycle of the wave. In this case, the distance of 2.5 meters between the crests indicates the length of one full wavelength in the wave. The characteristic of the wave represented by the given distance is the wavelength (D). Wavelength is the distance between two consecutive points with the same phase, such as two crests or two troughs. It is a measure of the spatial extent of one complete cycle of the wave. In this case, the distance of 2.5 meters represents the length of one complete wavelength. Amplitude (A) refers to the maximum displacement of the wave from its equilibrium position, frequency (B) is the number of complete cycles of the wave occurring in one second, period (C) is the time taken for one complete cycle of the wave, and phase (E) represents the position of the wave at a particular point in time.
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what is the pressure exerted on the ground by a 5-kg box that has a width of 5 m and a length of 10 m?
The pressure exerted on the ground by the box of mass 5 kg is 0.98 N/m².
What is pressure:Pressure is defined to be the amount of force exerted per area acting on the surface of a body.
To calculate the preesure exerted on the ground, we use the formula below.
Formula:
P = mg/lw............... Equation 1Where:
P = Pressure exerted on the groundm = Mass of the boxg = Acceleration due to gravityl = Length of the boxw = Width of boxFrom the question,
Given:
m = 5 kgg = 9.8 m/s²l = 10 mw = 5 mSubstitute these values into equation 1
P = (5×9.8)/(5×10)P = 49/50P = 0.98 N/m²Hence, the pressure exerted on the ground is 0.98 N/m².
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Explain how the law of conservation of energy applied to the energy transformations that occur from the outlet charger to the ringing phone
Answer: ELECTRICAL ENERGY to CHEMICAL ENERGY to SOUND ENERGY.
Explanation:
There are laws governing the conservation of energy in physics. The first law of thermodynamics states that in a closed system, energy can neither be created nor destroyed during transformation. With this, the total energy of a given system always remains constant.
This first law of thermodynamics which arouse from special relativity, says that changes in the energy of systems will also coincide with changes in a measure of its energy content.
The ELECTRICAL energy from the outlet charger is transformed and stored as CHEMICAL energy in the battery of the phone. This in turn is converted to SOUND energy when the phone rings.
DESPERATE WILL GIVE BRAINLIST AND THANKS
The Cenozoic Era was the “age of the dinosaurs.”
Question 2 options:
True
False
Answer:
false
Explanation:
Answer:
false
Explanation:
The Cenozoic Era is the current Era it's also called the new life era. Dinosaurs appeared in the Triassic era.
1. Helen's car ran out of gas and stalled 100 meters from a gas station. Helen knew she could push the car to the gas station. She put her car in neutral and pushed with a force of 40 N. How much work (in Newton meters) did Helen do to get her car to the gas station?
The amount of work (in Newton meters) that Helen did to get her car to the gas station is 4000 Newton meters
How do i determine the amount of work (in Newton meters)?Work done is defined as illustrated by the formula given below:
Work done = force (F) × distance (d)
From the question given above, we were told that:
Force applied (F)= 40 NewtonDistance to gas station (d) = 100 metersWorkdone =?The work done by Helen can be obtained as shown below:
Work done = force (F) × distance (d)
Work done = 40 × 100
Work done = 4000 Newton meters
Thus, it is evident that the work done is 4000 Newton meters
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Instructions:Draw a speed graph in the box that matches thefollowing scenario:A runner jogged 40m at a slow pace for 40seconds. She then stopped for 40 seconds to gea drink of water. After that, she sped up and ran60m more in 20 seconds.Tip:y axis - total of 100 mx axis - total of 100 s
Given data:
1) Runner jogged 40 m at a slow pace for 40 sec.
2) Stopped for 40 sec.
3) Again funs for 60 m in 20 sec.