To prevent a piece of iron from rusting, which one of the following metals will provide the best coating?A) Zinc
B) Copper
C) Aluminium
D) Lead

Answer: 15910 meters

Explanation:

1 kilometer = 1000 meters

15.91 kilometers * 1000 meters/1 kilometer =

15.91 * 1000/1=

15.91*1000=15910 meters

Answer:

Boiling B.

Explanation:

Answer:

ion know figure it out its you who learning ab it

Explanation:

Answer:

♡ ..This sounds like a "you" problem.. ♡

Nah I'm k i d d i n g I actually don't know .

Explanation

Answer:

Copper (II) acetate, which is also referred to as cupric acetate

Explanation:

Answer:

humidity

Explanation:

The research sponsored by the National Institutes of Health (NIH) on rare diseases is aimed at finding treatments and solutions for these conditions. The research outcomes are intended to benefit individuals affected by rare diseases and improve their health outcomes.

The National Institutes of Health (NIH) plays a significant role in funding and supporting research related to various medical conditions, including rare diseases. Through its sponsorship of medical foundations, the NIH provides resources and financial support to conduct research specifically focused on rare diseases. This research aims to advance the understanding of these diseases, identify potential treatments, and develop interventions that can improve the lives of individuals affected by these conditions.

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Answer:

122.904 21(1)

Explanation:

The mailing cylinder for posters, with dimensions of 12 inches in length and 8 inches in diameter, can hold an approximate volume. By using the formula for the volume of a cylinder and substituting the given values, the volume can be calculated.

The volume of a cylinder can be calculated using the formula V = πr²h, where V represents the volume, π is approximately 3.14, r is the radius, and h is the height or length of the cylinder. In this case, the diameter is given as 8 inches, so the radius (r) can be calculated by dividing the diameter by 2, resulting in r = 8/2 = 4 inches. The height or length (h) is given as 12 inches. Substituting these values into the volume formula, we have V = 3.14 × (4 inches)² × 12 inches. Simplifying the equation further, we get V = 3.14 × 16 square inches × 12 inches, which evaluates to approximately 602.88 cubic inches.

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The process of photosynthesis requires water and air in addition to grow ,obtain their energy from the sun  and supply oxygen to the environment .

It is defined as a process by which plants and other photosynthetic organisms convert the light energy in to chemical energy  through the process of cellular respiration.

Some of the energy which is converted  is stored in molecules of carbohydrates like sugar and starches  which are made up of from carbon dioxide and water . Photosynthetic organisms which can perform photosynthesis  are algae and cyanobacteria. Photosynthesis is largely responsible for producing and maintaining the content of oxygen in earth's atmosphere.

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The formula for the transition metal cation in test tube M is Fe2+.

Step 1:

The presence of the Co2+ ions is confirmed by adding potassium nitrite acidified with acetic acid to the mixture of the four cations. A precipitate is formed, which is identified as Co(NO2)2.

The net ionic equation for this reaction is:

Co2+(aq) + 2NO2^-(aq) → Co(NO2)2(s)

Step 2:

Aqueous ammonia is added to the solution in test tube 12 until the solution is basic. A precipitate is formed, which is identified as Cu(OH)2. The net ionic equation for this reaction is:

Cu2+(aq) + 2OH^-(aq) → Cu(OH)2(s)

Step 3:

An ethanol solution of dimethylglyoxime is added to the solution in test tube 13. A precipitate is formed, which is identified as Ni(C4H7O2N2)2. The net ionic equation for this reaction is:

Ni2+(aq) + 2C4H6O2N2^-(aq) → Ni(C4H7O2N2)2(s)

Step 4:

To check that there is a final transition metal cation in the solution in test tube M, another sample of the original mixture of all four cations is tested with aqueous potassium iodide. A precipitate is formed, which is identified as FeIIs. The net ionic equation for this reaction is:

Fe2+(aq) + 2I^-(aq) → FeI2(s)

Thus, the formula for the precipitate in test tube 11 is Co(NO2)2, the formula for the precipitate in test tube 12 is Cu(OH)2, the formula for the precipitate in test tube 13 is Ni(C4H7O2N2)2, and the formula for the precipitate in the confirming test tube is FeI2.

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Answer:

2 Fe + 3 (H2SO4) = Fe2(SO4)3 + 3H2

Explanation:

Hello, always remember that balancing equations is having one side(the reactants) equal to the same amount as the other side(the products). In this example you would like to look on each side and see what has more of what and how you can equal it.

1. First add a 2 Coefficient to Fe because there is 2 Fe on the product side due to Fe2(SO4)3

2. In Fe2(SO4)3 we can see the 3 at the very end that is distributed to the Sulfur and Oxygen. This means we have to go to the other side due to SO4 only being distributed by nothing, there is no 3 so that is why we put a 3 coefficient in front of H2SO4.

3. Because we put that 3 in front of H2SO4, this cause the hydrogen on the product sign to be imbalanced so we put a 3 coefficient infront of the H2 on the product side.

*Always remember to multiply the coefficient and/or subscripts.

The structures of the compounds are:

(1) 2-methylbutan-2-ol
(2) 2-methyl-2-propanol
(3) 3-methyl-2-butanone
(4) 3-methylbutanoic acid

The 1H NMR data provided for each compound corresponds to their specific molecular structure. In compound (1), the doublet at 1.09 δ and singlet at 2.12 δ are indicative of a methyl group near a chiral carbon, while the septet at 2.58 δ suggests a CH group attached to two different carbons.

Compound (2) exhibits a singlet at 2.24 δ due to a hydroxyl group, while the triplet at 0.91 δ and singlet at 1.19 δ indicate methyl groups. In compound (3), the multiplet at 1.76 δ and doublet at 3.38 δ show the presence of a carbonyl group, and the doublet at 0.90 δ implies two methyl groups.

Lastly, compound (4) has a doublet at 1.21 δ representing two methyl groups, a septet at 2.59 δ suggesting a CH group, and a singlet at 11.38 δ due to the carboxylic acid proton.

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ANSWER

The mass of Na2SO4 is 874g

EXPLANATION

Given that;

The number of moles of HCl is 12.3 mol

Follow the steps below to find the mass of sodium sulfate produced

Step 1; Write a balanced equation for the reaction

In the reaction above, 2 moles of NaCl react with 1 mole of H2SO4 to give 2 moles of HCl and 1 mole of Na2SO4

Let the number of moles of Na2SO4 be x

The number of moles of Na2SO4 is 6.15 moles

Step 3; Find the mass of Na2SO4 using the below formula

Recall, that the molar mass of Na2SO4 is 142.04 g/mol

Therefore, the mass of Na2SO4 is 874g

Answer

1.0 mol

Explanation

Given:

Volume, V = 5.0 L

Temperature, T = 215 K

Pressure, P = 342 kPa

The gas constant, R = 8.31 L kPa/mol K

What to find:

The number of moles of the gas sample.

Step-step-solution:

The number of moles of the gas can be determine using the ideal gas equation formula:

Put the given values into the formula and calculate for n:

The number of moles of the gas sample is 1.0 mol.

Answer:

110 °C

Explanation:

The following data were obtained from the question:

Initial pressure (P1) = 0.538 atm

Initial temperature (T1) = 256 °C

Initial volume (V1) = 437 mL.

Final pressure (P2) = constant = 0.538 atm

Final volume (V2) = 316 mL

Final temperature (T2) =?

Next we shall convert 256 °C to Kelvin temperature. This Can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T1) = 256 °C

Initial temperature (T1) = 256 °C + 273 = 529 K

Next, we shall determine the new temperature of the gas as illustrated below:

Pressure = constant

Initial temperature (T1) = 529 K

Initial volume (V1) = 437 mL.

Final volume (V2) = 316 mL

Final temperature (T2) =?

Applying the Charles' law equation, we have:

V1 /T1 = V2 /T2

437/529 = 316/T2

Cross multiply

437 × T2 = 529 × 316

437 × T2 = 167164

Divide both side by 437

T2 = 167164 / 437

T2 = 382.5 ≈ 383 K

Finally, we shall convert 383 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 383 K

T(°C) = 383 – 273

T(°C) = 110 °C

Therefore, the new temperature of the gas is 110 °C

Answer:

Yes, it is a fact that saturated fats contain more gross energy due to higher H+ concentration. However, unsaturated fats are more digestible and have higher absorption rate, and therefore the metabolizable energy that unsaturated fats provide is higher than that provided by saturated fats.

Explanation:

Answer:

the answer is 9.6853

Explanation:

I got it right

Explanation:

\((.0000360 gAu} )\frac{1molAu}{196.96gAu}= ? mol Au\)

Answer:

About $5.65x10^15 or $5,650,000,000,000,000

Explanation:

Given:

Volume of seawater: 2.3 mL

Grams of gold: 4.0 x 10^-10

Total volume of the ocean: 1.5 x 10^21

Price of gold: $21.66/g

Need:

1000 mL = 1 L

Find:

Dollar worth of all the gold in the world's oceans

Steps:

1. We know that there is 4.0 x 10^10 g of gold in 2.3 mL of seawater, therefore we can write it like this:

2. In order to find the amount of gold in the entire ocean we need to cancel out the 2.3 mL of seawater on the bottom. To do this we will use the volume of the entire ocean (1.5 x 10^21 L). Before we plug it into the equation, we have to match the units of the mL and the L. We will use the 1000mL = 1 L to accomplish this. The formula should now look like this:

\(\frac{4.0*10^{-10}g }{2.3mL} \frac{1000mL}{1L} \frac{1.5*10^{21}L}{1}\)

3. Solve the equation to find the amount of gold in all the oceans:

\(\frac{4.0*10^{-10}g }{2.3mL} \frac{1000mL}{1L} \frac{1.5*10^{21}L}{1} = 2.61 x 10^{14} g\)

4. Now since we found the amount of gold in all the oceans we can use this to find the total worth of all of it. We can do this by multiplying all the grams of the gold by the price of gold per gram. It can be represented like this:

\(\frac{21.66 dollars}{1 gram} \frac{2.61*10^{14}g }{1}\)

5. Get the answer:

\(\frac{21.66 dollars}{1 gram} \frac{2.61*10^{14}g }{1} = 5.65 x 10 ^ {15}dollars\)

There ya go!

b. The temperature of the equilibrium mixture is increased at constant volume. The number of moles of CO (g) in the container will increase when the temperature is increased. The equation given is an exothermic reaction, so increasing the temperature favors the reaction to the right, releasing heat energy and producing more moles of CO (g).

The given equilibrium equation is CO (g) + H2(g) <--> C(s) + H2O (g) ∆H˚ = -131 kJ. The question asked to determine whether the number of moles of CO (g) in the container will increase, decrease or stay the same for different disturbances.

b. The temperature of the equilibrium mixture is increased at constant volume. When the temperature is increased at constant volume, the equilibrium will shift towards the product side in order to counteract the increase in temperature. Since CO (g) is a reactant, the number of moles of CO (g) will decrease after the disturbance is applied, so the correct answer is "decrease."

c. The volume of the container is decreased at constant temperature.

When the volume of the container is decreased at constant temperature, the pressure inside the container will increase, which will cause the equilibrium to shift towards the side with fewer gas moles to counteract the increase in pressure. CO (g) has one gas mole, and H2O (g) and H2 (g) have two gas moles. Therefore, the equilibrium will shift towards the side with fewer gas moles, which is the product side. This means that the number of moles of CO (g) will decrease, so the correct answer is "decrease."

d. The graphite pellets are pulverized. When the graphite pellets are pulverized, the surface area of C(s) will increase. This will increase the rate of reaction from the reactant side to the product side. The reaction will continue until the equilibrium is reestablished, but the number of moles of CO (g) will not change, so the correct answer is "stay the same." Therefore, the correct answer is b. The temperature of the equilibrium mixture is increased at constant volume.

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Answer:

The new volume is 5.0L

Explanation:

Given:

Initial pressure (P₁) = 1.4 atm

Initial volume (V₁) = 2.3 L

Final pressure (P₂) = 0.65 atm

We'll use Boyle's Law:

P₁V₁ = P₂V₂

Substituting the given values:

(1.4 atm)(2.3 L) = (0.65 atm)(V₂)

Now, let's solve for V₂:

V₂ = (1.4 atm * 2.3 L) / 0.65 atm

Calculating this expression step-by-step:

V₂ = (3.22 atm·L) / 0.65 atm

V₂ ≈ 4.953 L

Rounded to one decimal place, the new volume is approximately 5.0 L.

A) F2 and C2H5OH (Heterogeneous mixture)B) H2O and CH3OH (Homogeneous mixture)C) LiCl and C10H20 (Heterogeneous mixture)D) CH4 and C2H5OH (Heterogeneous mixture).

The pair of substances that are most likely to form a homogeneous solution is B. H2O and CH3OH. A homogeneous mixture is one in which the components are evenly distributed throughout the mixture. These types of solutions have uniform properties and the same composition throughout.A heterogeneous mixture is one in which the components are not evenly distributed. This means that the mixture has distinct regions or phases that are visibly different from one another. The following are the most likely pairs of substances to form a homogeneous solution:A) F2 and C2H5OH (Heterogeneous mixture)B) H2O and CH3OH (Homogeneous mixture)C) LiCl and C10H20 (Heterogeneous mixture)D) CH4 and C2H5OH (Heterogeneous mixture).

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The assertions many of these chemicals feature a benzene ring as a structural unit, they are very stable compounds, and they are unsaturated compounds are all accurate descriptions of aromatic hydrocarbons.

Arenes are aromatic organic compounds consisting completely of carbon and hydrogen, also referred to as aromatic hydrocarbons. The configuration of six carbon atoms in aromatic compounds is known as a "benzene ring," named after the basic aromatic molecule benzene, or a "phenyl group" when it is a component of a larger structure. Aromatic hydrocarbons are hydrocarbons that have delocalized pi electrons and sigma bonds between their carbon atoms in a ring. Benzene is one illustration. They are referred to as aromatic because of their odor.

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Answer:

yes when ammonium(NH4) react with chlorine then will we get ammonium chloride

Explanation:

Pure chlorine gas may react vigorously with ammonia gas. An excessive mix of the two gases in air can produce hazardous compounds such as the explosive nitrogen trichloride. ... Chlorine reacts readily with ammonium hydroxide to form ammonium chloride, a relatively harmless compound.

Answer:

12.736 grams of hydrogen peroxide

Explanation:

Answer:

pH is an index of how many protons, or hydrogen ions (H+) are dissolved and free in a solution. The pH scale goes from 0 to 14. A fluid with a pH of 7 is neutral. Below 7, it is acidic; above 7, it is alkaline.

The more below or above 7 a solution is, the more acidic or alkaline it is. The scale is not linear—a drop from pH 8.2 to 8.1 indicates a 30 percent increase in acidity, or concentration of hydrogen ions; a drop from 8.1 to 7.9 indicates a 150 percent increase in acidity. Bottom line: Small-sounding changes in ocean pH are actually quite large and definitely in the direction of becoming less alkaline, which is the same as becoming more acidic.

If you think about it, we use descriptive words like this all the time. A person who stands 5’5” tall and weighs 300 pounds isn’t thin. If he loses 100 pounds, he still won’t be thin, but he will be thinner than he was before he went on the diet. (And we are more likely to comment that he’s looking trimmer than to say he’s not as fat as he used to be.)

Nitrate ions are endothermic, yet the process is spontaneous because the entropy of the solution is changing.

Ammonium nitrate dissolves spontaneously in water by an endothermic reaction. The system experiences a drop in entropy, which makes it spontaneous. At 25 °C, ammonium nitrate (NH4NO3) dissolves spontaneously in water. The temperature of the water drops as it disintegrates. The dissolution of ammonium nitrate in solution is an endothermic reaction. The environment becomes colder as the ammonium nitrate dissolves because heat energy from the surroundings is absorbed. For the disintegration process to be spontaneous, there must be a rise in entropy. Diluting a solution raises its entropy, which causes the reaction to be spontaneous.

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Answer:

the answer is option B it is a proton acceptor

Among the given options, the element that represents X in the transmutation is 49Be (option a).

In the given transmutation, X represents the element that undergoes the nuclear reaction.

Looking at the reaction:

\($X + 2^4He \rightarrow 6^{12}C + 0^1n$\)

We can identify the elements involved in the reaction:

From the given options, the element X can be determined by balancing the atomic and mass numbers on both sides of the reaction.

Comparing the atomic numbers, we have:

X: Z

2⁴ He: 2 (helium)

6¹²C: 6 (carbon)

0¹n: 0 (neutron)

To balance the atomic number on the left side (X + 2^4He), it should equal the atomic number on the right side (6^12C):

Z + 2 = 6

Z = 4

Therefore, the element X has an atomic number of 4, which corresponds to the element beryllium (Be).

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