To prepare for a bake-off, Kent used 560 grams of flour each day for 2 weeks. How many kilograms did Kent use in those 2 weeks?

Given:

Mean= 5.7.

Standard deviation= 0.4

For the normal distribution,

i) The probability that the plants would you expect to be between 5.3 and 6.1 inches tall is,

Answer:

Less than 3,

9/4

Step-by-step explanation:

A scatter plot, because it would show the association, or relationship, between the two variables

From the question, we have the following parameters that can be used in our computation:

The table of values

To show the relationship and association between data values, the data values are best represented on a scatter plot

using the above as a guide, we have the following:

The most appropriate to construct for the data is (b)

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The total weight of Rice that Mark buys is given as follows:

2.5 pounds.

The total weight of Rice that Mark buys is obtained applying the proportions in the context of the problem.

The weight of each bag is given as follows:

5/8 pounds = 0.625 pounds.

The number of bags is given as follows:

4 bags.

Hence the total weight of Rice that Mark buys is given as follows:

4 x 0.625 = 2.5 pounds.

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For a company that charges $5.10 plus 5.747 cents per kilowatt-hour (kWh) for customers using up to 1300 kWh, and charges 5.788 cents per kilowatt-hour (kWh) for the extra kWh used after the first 1300 kWh, if more than 1300 kWh are used, the total charge for 1,300 kWh is $79.811.

The total charge is the product of the multiplication of the unit rate by the total kilowatt-hours used by the customer plus the fixed rate.

Multiplication operation is one of the four basic mathematical operations, including addition, subtraction, and division.

Multiplication involves the multiplicand, the multiplier, and the product.

Fixed charge = $5.10

Variable charge per kilowatt-hour = 5.747 cents ($0.05747)

Total usage  = 1,300 kWh

The total charge = $79.811 ($5.10 + $0.05747 x 1,300)

Thus, the total charge for 1,300 kWh for the nonextreme weather month is $79.811.

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Answer:

166,000(1 + 0.085)^t ; $195,000 ; $230,000

Step-by-step explanation:

Given that :

Rate of increase = 8.5% = 0.085 per year

Initial value ; price in 2011 (A) = $166,000

Formula to predict the median price t years after 2011 ;

At a continous rate :

Median price, P:

P = initial price (1 + rate)^t

P = 166,000(1 + 0.085)^t

t = time since 2011 ;

Median price of home in 2013:

t = 2013 - 2011 = 2

P = 166,000(1 + 0.085)^2

P = 166000(1.085)^2

P = 166000(1.177225)

P = 195419.35

P = $195,000 ( nearest $1000)

Median price of home in 2013:

t = 2015 - 2011 = 4

P = 166,000(1 + 0.085)^4

P = 166000(1.085)^4

P = 166000(1.385858700625)

P = 230052.54430375

P = $230,000 ( nearest $1000)

Answer:

(0,-4)

Step-by-step explanation:

The plot for x intercept is at -4,0 and the y intercept is at 0,5

type it in as (0,-4), some require the (#,#) format

Answer:

The middle term is \(-160x^{3}\)

Step-by-step explanation:

Given

\((\frac{2}{x} - x^2)^6\)

Required

Determine the middle term

This can be expanded using binomial expansion

i.e.

\((a + b)^n = a^n + ^nC_1a^{n-1}b^1 + ^nC_2a^{n-2}b^2 +....+b^n\)

When n = 6;

\((a + b)^6 = a^6 + ^6C_1a^{6-1}b^1 + ^6C_2a^{6-2}b^2 + ^6C_3a^{6-3}b^3+ ^6C_4a^{6-4}b^4+ ^6C_5a^{6-5}b^5+b^n\)

\((a + b)^6 = a^6 + ^6C_1a^{5}b^1 + ^6C_2a^{4}b^2 + ^6C_3a^{3}b^3+ ^6C_4a^{2}b^4+ ^6C_5a^{1}b^5+b^6\)

\((a + b)^6 = a^6 + ^6C_1a^{5}b + ^6C_2a^{4}b^2 + ^6C_3a^{3}b^3+ ^6C_4a^{2}b^4+ ^6C_5ab^5+b^6\)

The middle term here is given as:

\((a + b)^6 = ^6C_3a^{3}b^3\)

In \((\frac{2}{x} - x^2)^6\)

\(a = \frac{2}{x}\) and \(b = -x^2\)

This gives:

\((\frac{2}{x} - x^2)^6 = ^6C_3(\frac{2}{x})^{3}(-x^2)^3\)

\((\frac{2}{x} - x^2)^6 = 20*(\frac{2}{x})^{3}(-x^2)^3\)

Solve all exponents

\((\frac{2}{x} - x^2)^6 = 20*\frac{8}{x^3}*(-x^6)\)

\((\frac{2}{x} - x^2)^6 = -\frac{20*8*x^6}{x^3}\)

\((\frac{2}{x} - x^2)^6 = -160*x^{6-3}\)

\((\frac{2}{x} - x^2)^6 = -160*x^{3}\)

\((\frac{2}{x} - x^2)^6 = -160x^{3}\)

Hence, the middle term is \(-160x^{3}\)

To test the hypotheses h0: p1 = p2 and Ha: p1 ≠ p2, we can use a two-sample proportion test. This test compares the proportion of success (no longer being late to school) in the control group (p1) to the proportion of success in the treatment group (p2) to determine if there is a statistically significant difference between the two proportions.

Here are the steps to perform the test:

State the hypotheses:

h0: p1 = p2 (the proportion of success in the control group is equal to the proportion of success in the treatment group)

Ha: p1 ≠ p2 (the proportion of success in the control group is not equal to the proportion of success in the treatment group)

Select a significance level (alpha): usually, it is set as 0.05

Calculate the test statistic:

p = (p1n1 + p2n2) / (n1 + n2)

z = (p1 - p2) / sqrt(p*(1-p)*((1/n1)+(1/n2)))

Find the p-value:

Using the z-score, look up the probability in a standard normal table.

Make a decision:

Compare the p-value to the significance level. If the p-value is less than or equal to the significance level, then reject the null hypothesis. If the p-value is greater than the significance level, then fail to reject the null hypothesis.

Conclusion:

Interpret the results in terms of the research question. If the null hypothesis is rejected, then the results suggest that there is a statistically significant difference in the proportion of success between the control group and the treatment group

The question is incomplete, the complete question is:

__"'A researcher wants to conduct a study to determine whether a newly developed anti-tardy program is successful. Two random groups of 100 students each, identified as control and treatment groups, are formed from 200 students who are repeatedly late to school. Both groups receive a set of anti-tardy reading materials and a lecture from a teacher and a tardy-reformed student about the negative impacts of being late. In addition, the treatment group also receives materials from the newly developed program. Thirty-three of the 100 students in the control and 35 of the 100 students in the treatment group are no longer late to school is recorded 6 months later.

Use the results to test the hypotheses H0: p1 = p2 and Ha: p1 ≠ p2 where p1 represents the proportion of students who succeed in the control program and p2 represents the proportion of students who succeed in the newly developed program.

What can you conclude using the significance level α = 0.05?""__

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Colombian gold production was reported at 47,830,000 kg in December 2020. This represents an increase from 36,676,000 kg in December 2019. Colombia Gold production data is updated annually and averaged 35,783 kg from December 1990 to 2020 with 31 observations.

Colombia's largest gold mine is set to start operations in Britica, in the province of Antioquia. There are frequent conflicts between potential mining activities and indigenous communities in the country, particularly in the sparsely populated eastern provinces of Vichada, Guanía, Guaviare and Vaupés.

As of 2021, Gran Colombia Gold Segovia Subcrustal Colombia is the largest gold and other precious metals mining company in Colombia, with which revenues increases of approximately 1.42 trillion Colombian pesos. It was followed by Continental Gold Limited Sucursal Colombia with a turnover of 1.36 trillion pesos.

Complete Question:

Show the full Series Graph about Gold Production in Colombia

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Answer:

C. A=[1,3,5,7,9] thats the answer

Answer:

? = 130

Step-by-step explanation:

I'm letting ? be x

Since the triangles are similar, larger outer and smaller inner, then the ratios of corresponding sides are equal.

If x is the length of side of larger then x - 70 is corresponding length of smaller.

Then

\(\frac{x}{x-70}\) = \(\frac{78}{36}\) ( cross- multiply )

78(x - 70) = 36x ← distribute left side

78x - 5460 = 36x ( subtract 36x from both sides )

42x - 5460 = 0 ( add 5460 to both sides )

42x = 5460 ( divide both sides by 42 )

x = 130

The sample size needed to be 99​% confident that the sample proportion will not differ from the true proportion by more than ​4% is given as follows:

n = 1037.

A confidence interval of proportions has the bounds given by the rule presented as follows:

\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)

In which the variables used to calculated these bounds are listed as follows:

The margin of error is given as follows:

\(M = z\sqrt{\frac{\pi(1-\pi)}{n}}\)

The confidence level is of 99%, hence the critical value z is the value of Z that has a p-value of \(\frac{1+0.99}{2} = 0.995\), so the critical value is z = 2.575.

As we have no estimate, the parameter is given as follows:

\(\pi = 0.5\)

Then the sample size for M = 0.04 is obtained as follows:

\(M = z\sqrt{\frac{\pi(1-\pi)}{n}}\)

\(0.04 = 2.575\sqrt{\frac{0.5(0.5)}{n}}\)

\(0.04\sqrt{n} = 2.575 \times 0.5\)

\(\sqrt{n} = \frac{2.575 \times 0.5}{0.04}\)

\((\sqrt{n})^2 = \left(\frac{2.575 \times 0.5}{0.04}\right)^2\)

n = 1037.

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Answer:

Step-by-step explanation:

12=666

It is given that tanA = 5/6 and tan B = 1/6

We need to solve for the tan(A+B)

From the expression of trigometric ratio for the tan(A+B).

Substitute the value of tan A =5/6 and tan B = 1/6 in the expression.

Answer: tan(A+B) = 36/31

The final answer is (f o g)(x) = x^4 - 16x^2 + 72

(g o f)(x) = x^4 + 16x^2 + 56

(f o g)(2) = 24

To find the composite functions (f o g)(x) and (g o f)(x), we need to substitute one function into the other.

(f o g)(x):

To find (f o g)(x), we substitute g(x) into f(x):

(f o g)(x) = f(g(x))

Let's substitute g(x) = x^2 - 8 into f(x) = x^2 + 8:

(f o g)(x) = f(g(x)) = f(x^2 - 8)

Now we replace x in f(x^2 - 8) with x^2 - 8:

(f o g)(x) = (x^2 - 8)^2 + 8

Simplifying further:

(f o g)(x) = x^4 - 16x^2 + 64 + 8

(f o g)(x) = x^4 - 16x^2 + 72

Therefore, (f o g)(x) = x^4 - 16x^2 + 72.

(g o f)(x):

To find (g o f)(x), we substitute f(x) into g(x):

(g o f)(x) = g(f(x))

Let's substitute f(x) = x^2 + 8 into g(x) = x^2 - 8:

(g o f)(x) = g(f(x)) = g(x^2 + 8)

Now we replace x in g(x^2 + 8) with x^2 + 8:

(g o f)(x) = (x^2 + 8)^2 - 8

Simplifying further:

(g o f)(x) = x^4 + 16x^2 + 64 - 8

(g o f)(x) = x^4 + 16x^2 + 56

Therefore, (g o f)(x) = x^4 + 16x^2 + 56.

(f o g)(2):

To find (f o g)(2), we substitute x = 2 into the expression (f o g)(x) = x^4 - 16x^2 + 72:

(f o g)(2) = 2^4 - 16(2)^2 + 72

(f o g)(2) = 16 - 64 + 72

(f o g)(2) = 24

Therefore, (f o g)(2) = 24.

In summary:

(f o g)(x) = x^4 - 16x^2 + 72

(g o f)(x) = x^4 + 16x^2 + 56

(f o g)(2) = 24

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Answer:

The blue dot is -19

Step-by-step explanation:

Since every 2 ticks are worth 6 (|-10|-|-4|=6), then one tick is worth 3.

We are going backward, so we can count backward.

We have to go down 3 ticks, so -10-3=-13; -13-3=-16; -16-3=-19.

The blue dot is -19

Answer: The blue dot equals to -19.

Step-by-step explanation:

On the number line, there are the numbers -10 & -4.

-7 would fit in the middle of them. That means the number line goes by minus 3.

Count -10 , -13, -16, then you get on the the blue dot which is -19.

Therefore, -19 is the answer.

Answer:

He will have 2 cups :)

Answer:

he would have 2 cups in it cause 1 pint = 2 cups

Answer:

i hop you will know the answer soon

Step-by-step explanation:

sorry i dont know

Answer:

5.44 meters

Step-by-step explanation:

We Know

0.3048 meter = 1 ft

How many ft makes a height of 1.66m?

We Take

1.66 ÷ 0.3048 ≈ 5.44 meters

So, the answer is 5.44 meters.

So According to me the answer is

10(f-4)

Because it says the product and product means multiply and brackets also means multiply so the product if 10 AND f-4

Answer:

Step-by-step explanation:

ask ur teacher

Answer: x = 3

Step-by-step explanation: -7 + 9 = 8 - 6

Answer:

Answer will be 55898.

Step-by-step explanation:

The vertical angles from the attached image will be; 1 and 4; 2 and 3; 5 and 8; 6 and 7.

The Linear pair angles would be: 1 and 3; 2 and 4; 5 and 7; 6 and 8; 1 and 2; 3 and 4; 5 and 6; 7 and 8

A) From the attached image, the side roads resemble 2 parallel lines cut by a transversal.

Now, if we consider the roads to be very fat lines, then it means that the main road is the transversal while the two side roads are parallel to each other.

B) Vertical angles are defined as angles that are opposite of each other The vertical angles from the attached image will be; 1 and 4; 2 and 3; 5 and 8; 6 and 7.

The Linear pair angles would be: 1 and 3; 2 and 4; 5 and 7; 6 and 8; 1 and 2; 3 and 4; 5 and 6; 7 and 8when two lines cross

The supplementary angles would be: 3 and 5; 4 and 6

C) If a fourth road is constructed, it will be perpendicular to the main road, or perpendicular to the two side roads, and it will form a right triangle.

Thus, the acute angles of the triangles will be complementary because their sum will be 90°

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Answer:

if you are asking for true or false it would be false

Step-by-step explanation:

For the fractions, the calculation of 3/5 of 2/3 of 3/4 of 560 is equal to 168.

To calculate 3/5 of 2/3 of 3/4 of 560, break it down step by step:

Step 1: Calculate 3/4 of 560:

3/4 × 560 = (3 × 560) / 4 = 1680 / 4 = 420

Step 2: Calculate 2/3 of the result from Step 1:

2/3 × 420 = (2 × 420) / 3 = 840 / 3 = 280

Step 3: Calculate 3/5 of the result from Step 2:

3/5 × 280 = (3 × 280) / 5 = 840 / 5 = 168

Therefore, 3/5 of 2/3 of 3/4 of 560 is equal to 168.

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The mean should be calculated for data sets A, B, C, and D.

It is useful to take into account the nature of the data and any potential outliers when deciding whether to choose the mean or the median as the measure of center in a data set.

When the data is symmetrically distributed with no major outliers, the mean is usually a better choice. It affects extreme values and gives an indication of the average value.

The median, on the other hand, is often preferred when the data is skewed or contains outliers. It represents the middle value when the data is ordered, and it is less affected by extreme values.

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