To find the distance across a river, a forester sets up stakes at A, B,C and D so that
stakes D and B are in line with a larger tree T, on the opposite bank. Calculate the
width of the river using the measurements given. (Upload a Picture of your solution)

Solution:

Given:

From the table,

Therefore, the answer is 20.

Answer:

35 minutes.

Step-by-step explanation:

Just multiply 7 minutes by 5 miles.

Answer:

It will take Carmen 35 minuets to run 5 miles.

Answer:

-6384

Step-by-step explanation:

= (10^2 + 2 x 8^2)(10^2-2 x 8^2)

= (100 + 2 x 8^2) (10^2-2 x 8^2)

= (100 + 2 x 64) (10^2-2 x 8^2)

= (100 + 128) (10^2-2 x 8^2)

= 228 (10^2-2 x 8^2)

= 228 (100 - 2 x 64)

= 228 (100 - 128)

= 228 (-28)

= -6384

PEDMAS

Parentheses

Exponents

Division

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Addition

Subtraction

The height of the flagpole if 1212 yards away flagpole's top lines up with the curb of a street 2020 yards away when looking from a height of 1515 yards is 606 yards.

Let us represent the position Carla is as A, top of flagpole as B, curb of street as C, bottom of flagpole as D and bottom of apartment as E. Therefore, AE = 1515 yards, CE = 2020 yards and DE = 1212 yards.

Now consider ΔACE and ΔBCD,

∠ACE = ∠BCD   same angle

∠CEA = ∠CDB = 90°

Therefore ΔACE is similar to ΔBCD by AA similar criterion of triangles.

In similar triangles, ratio of corresponding sides are equal. Therefore as ΔACE is similar to ΔBCD,

BD/ AE = CD/CE

BD = CD/CE × AE

BD = ( CE - DE )/CE × AE

BD = (2020 - 1212)/ 2020 × 1515

BD = 606

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Answer:

X = 12

Step-by-step explanation:

Just add 8 to both sides to set the equation balanced. I hope this helps :)

Can you even understand my writing here ?

anyway this is the process i think is the right one ...

let me know if its incorrect

the dimensions of the lot is 100 yards by 400 yards. In this problem, a parking lot has a rectangular area of 40,000 square yards, and the length is 200 yards more than twice the width.

Determining the dimensions of a rectangular area, such as a parking lot, can be a useful task for many purposes, such as planning and designing a new lot or estimating the amount of space available for parking.

Let's call the width of the parking lot "w". Then, the length of the parking lot can be represented as 2w + 200.

The total area of the parking lot is 40,000 square yards, so we can set up an equation to solve for w: w * (2w + 200) = 40,000.

Solving for w, we get w = 100. This means that the width of the parking lot is 100 yards and the length is 2 * 100 + 200 = 400 yards.

The dimensions of the parking lot are 100 yards by 400 yards.

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Part (c) is the correct option i.e. The total dealer's cost is $16588.36.

What is Percentage ?

Percentage, which is a relative figure used to denote hundredths of any quantity. Since one percent (symbolised as 1%) is equal to one hundredth of something, 100 percent stands for everything, and 200 percent refers to twice the amount specified.

Given, Cost paid for car's options = 82 % $3,098 = $2540.36

           Cost paid for base price = 85 % $15,480 = $13158.

           Destination charge = $890

∴ The total dealer's cost will be :

 = Cost paid for car's options +  Cost paid for base price +  Destination charge

=  $2540.36 + $13158 + $890

= $16588.36.

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Major challenges for managers to ensure that they treat their employees fairly and equitably includes recognizing Biases and Inclusivity

Major challenges for managers to ensure that they treat their employees fairly and equitably includes recognizing biases and promoting inclusivity.

1:Biases: Managers must recognize and address their own biases,  the biases that may exist within the organization. Biases can be conscious or unconscious, and  lead to unfair treatment and favoritism. Managers need to be aware of these biases and actively work to mitigate their impact on decision-making processes such as promotions, assignments, and evaluations.

2:Inclusivity: Managers need to promote inclusivity by creating a work environment where all employees feel valued, respected, and included. This involves acknowledging and appreciating diversity in terms of race, gender, age, sexual orientation, ethnicity, and other dimensions of identity. Managers should ensure that opportunities for growth and advancement are accessible to all employees, and that discriminatory practices or behaviors are not tolerated.

Biases and promoting inclusivity, managers can foster a fair and equitable workplace where all employees have equal opportunities to succeed and contribute to the organization's goals.

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Answer:

Are you sure thats all you are given?

The amount of rice harvested this year from 690 acres of farmland was 5211570 bushels

An equation is an expression used to show the relationship between two or more numbers and variables.

This year, a large farm harvested rice from 690 acres of farmland. The crop yield was 7,553 bushels per acre.

Hence:

Amount of rice harvested =  7,553 bushels per acre * 690 acres = 5211570 bushels

The amount of rice harvested this year from 690 acres of farmland was 5211570 bushels

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Answer: B

Step-by-step explanation:

if on edg just took the quiz

If Buddy the Elf throws 55 snowballs in 30 seconds during a snowball fight with the mean boys, he would throw an estimated 4,730 snowballs throughout the school day from 7:50 am to 2:40 pm.

To calculate the number of snowballs Buddy would throw during the school day, we need to determine the total number of 30-second intervals in the given time period. From 7:50 am to 2:40 pm, there are approximately 6 hours and 50 minutes, or 410 minutes, in total. Each minute contains two 30-second intervals, so there are 820 intervals in the given time frame.

Since Buddy throws 55 snowballs in 30 seconds, we can multiply this rate by the total number of intervals. Multiplying 55 by 820 gives us an estimated 45,100 snowballs. Therefore, if Buddy were to maintain the same pace he had during the snowball fight, he would throw approximately 45,100 snowballs throughout the school day from 7:50 am to 2:40 pm.

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Answer: The correct is 114

Step-by-step explanation: Hope this helps

Answer:

Step-by-step explanation:

The radius of the outside of the pipe is 6 inches and the radius of the inside of the pipe

is 5.75 inches

Determine the volume of metal used to build the pipe.

Answer:

well religion does not work here sorry

Step-by-step explanation:not everyone prays im sorry

Answer:

im confused

Step-by-step explanation:

dont delete this

\(:\implies\sf\:2-\dfrac{x}{3}=6-x\)

Taking LCM in left side, we obtain

\(:\implies\sf\:\dfrac{6-x}{3}=6-x\)

\(:\implies\sf\:6-x=3(6-x)\)

\(:\implies\sf\:6-x=18-3x\)

\(:\implies\sf\:-x+3x=18-6\)

\(:\implies\sf\:2x=12\)

\(:\implies\sf\:x=\dfrac{12}{2}\)

\(:\implies\boxed{\bf{\orange{x=6}}}\)

Answer:

Step-by-step explanation:

C looks good

a. The probability that a flaw is detected by the end of the second fixation is given by the formula: P(flaw is detected by the end of the second fixation) = 1 - P(flaw is not detected in first fixation) * P(flaw is not detected in second fixation).

b. Similarly, the probability that a flaw will be detected by the end of the nth fixation is given by the formula: P(flaw is detected by the nth fixation) = 1 - P(flaw is not detected in first fixation) * P(flaw is not detected in second fixation) * ... * P(flaw is not detected in n-th fixation).

c. To calculate the probability that a flawed item will pass inspection, we can use the formula: P(B'|A), where A is the event that an item has a flaw and B is the event that the item passes inspection. Thus, P(B'|A) is the probability that the item passes inspection given that it has a flaw. Since the item is passed if a flaw is not detected in the first three fixations, and the probability that a flaw is not detected in any one fixation is 1 - p, we have P(B'|A) = P(flaw is not detected in first fixation) * P(flaw is not detected in second fixation) * P(flaw is not detected in third fixation) = (1 - p)³.

d. To find the probability that an item is chosen at random and passes inspection, we can use the formula: P(C) = P(item is not flawed and passes inspection) + P(item is flawed and passes inspection). We can calculate this as (1 - 0.1) * 1 + 0.1 * P(B|A'), where A' is the complement of A. Since P(B|A') = P(flaw is not detected in first fixation) * P(flaw is not detected in second fixation) * P(flaw is not detected in third fixation) = (1 - p)³, we have P(C) = 0.91 + 0.1 * (1 - p)³.

e. It's important to note that all of these formulas assume certain conditions about the inspection process, such as the number of fixations and the probability of detecting a flaw in each fixation. These assumptions may not hold in all situations, so the results obtained from these formulas should be interpreted with caution.

The given problem deals with calculating the probability that an item is flawed given that it has passed inspection. Let us define the events, where D denotes the event that an item has passed inspection, and E denotes the event that the item is flawed.

Using Bayes’ theorem, we can calculate the probability that an item is flawed given that it has passed inspection. That is, P(E|D) = P(D|E) * P(E) / P(D). Here, P(D|E) is the probability that an item has passed inspection given that it is flawed. P(E) is the probability that an item is flawed. And, P(D) is the probability that an item has passed inspection.

Since the item is passed if a flaw is not detected in the first three fixations, we can find P(D|E) = (1 - p)³. Also, given that 10% of all items contain a flaw, we have P(E) = 0.1.

Now, to find P(D), we can use the law of total probability. P(D) = P(item is not flawed and passes inspection) + P(item is flawed and passes inspection). This is further simplified to (1 - 0.1) * 1 + 0.1 * (1 - p)³.

Finally, we have P(E|D) = (1 - p)³ * 0.1 / [(1 - 0.1) * 1 + 0.1 * (1 - p)³], where p = 0.5. Therefore, we can use this formula to calculate the probability that an item is flawed given that it has passed inspection.

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Answer: 6^4

Step-by-step explanation:

You have 6^5 / 6 which is basically 6^5 / 6^1

When you are dividing exponents with the same base, you can subtract the exponent from each other.

When you do this, you get 6^4

Given two predictor variables with a correlation of 0.32879, we should expect there to be multicollinearity between them.

In a data set with a, b, c, d, e, and f numeric variables, given there is a strong correlation of these pairs (f, a), (f, c), (d, e), (a, d), we can set up a regression model as

Of-a + c Of-a + b + c + d + e Of-a + C + d + e Of-a + C + e.

Given two predictor variables with a correlation of 0.32879, we should expect there is multicollinearity between them.

The statement that is true regarding the given two predictor variables with a correlation of 0.32879 is:

we should expect there to be multicollinearity between them.

Multicollinearity is a situation in which two or more predictor variables in a multiple regression model are highly correlated with one another. Multicollinearity complicates the understanding of which predictor variables are significant in the regression model's estimation.

Therefore, given two predictor variables with a correlation of 0.32879, we should expect there to be multicollinearity between them.

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Answer:

The answer to your problem is, 63

Step-by-step explanation:

So we know that he has 2,835 comic books. He is also going to put them in boxes to ship it in a book store.

1 Box = 45 Comic Books

So in order to solve the problem we need to divide:

The expression includes:

2,835 ÷ 45 = 63

Thus the answer to your problem is, 63

Answer:

75°/360° = 5/24

Area of sector = (5/24)(π)(10^2)

= 125π/6 square inches

= 65.4 square inches

Length of arc = (5/24)(2π)(10)

= 25π/6 inches

= 13.1 inches

Answer:

A.

Step-by-step explanation:

Qualitative data is a type of data that describes information. Examples of qualitative data include sex (male or female), name, state of origin, citizenship, etc.

Answer:

22

Step-by-step explanation:

The 309.3333 is the base amount of seniors that graduate each year, the x is the number of years, so the 21.8571 is the number of students they increase by. This answer is 100% I took the final and got it right. Hope this helps!!  :)

Answer:

22

Step-by-step explanation:

Simplification form of 1/5 raised to the power minus 1 is 5.

To simplify simply means to make anything easier. In mathematics, simplifying an equation, fraction, or problem means taking it and making it simpler. Calculations and problem-solving techniques simplify the issue.

If a fraction's top and bottom share only one additional common factor, it is said to be in its simplest form. In other words, the top and bottom cannot be divided further and remain full numbers. Simplest form is also referred to as "lowest words."

The reduced form of a fraction is another name for its most basic form. For instance, the simplest representation of a fraction with a common component of 1 is 34 The simplest form, however, is not 2/4 because 12 is a further simplification of 2/4 that can be written.

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the probability that a randomly selected passenger car gets more than 35 mpg is approximately 0.3665.

the probability that the average mpg of four randomly selected passenger cars is more than 35 mpg is approximately 0.087

the probability that all of the passenger cars get more than 35 mpg is approximately 0.015.

We need to find \(P(X > 35),\) where X is the mpg rating of a randomly selected passenger car.

The standard normal distribution and Table 1, we have:

\(z = (35 - 33.8) / 3.5 = 0.34\)

\(P(X > 35) = P(Z > 0.34) = 0.3665\)

\(P(\bar X > 35)\), were \(\bar X\) is the sample mean mpg rating of four randomly selected passenger cars.

The population standard deviation, we use the t-distribution with \(n-1\) degrees of freedom (were \(n = 4\)) and Table 1. We have:

\(t = (35 - 33.8) / (3.5 / \sqrt(4)) = 1.83\)

Using Table 1 with 3 degrees of freedom (\(n-1 = 4-1\)), we find:

\(P(T > 1.83) = 0.087\)

We need to find \(P(X1 > 35\) and \(X2 > 35\) and \(X3 > 35\) and \(X4 > 35\)), where X1, X2, X3, and X4 are the mpg ratings of four randomly selected passenger cars.

Since the mpg ratings of the four cars are independent and identically distributed, we have:

\(P(X1 > 35\)and\(X2 > 35\) and \(X3 > 35\) and \(X4 > 35\)) =\(P(X > 35)^4\)

From part (a), we know that\(P(X > 35) = 0.3665.\)

\(P(X1 > 35\)and \(X2 > 35\) and\(X3 > 35\) and \(X4 > 35) = 0.3665^4 \approx 0.015\)

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Answer: answer is 72 you can  get it by either multiplying the height and the base by two and following the formula for area of a triangle or you can divide 36 by two and multiply that by 4

Step-by-step explanation:

Answer:

72 meters

Step-by-step explanation:

Working on 1 triangle at a time

How to find the area of a triangle: Base x Height divided by 2

So: 6 x 6 = 36

36 divided by 2 = 18

Each triangle is 18 meters

18 x 4 triangles = 72 meters

Answer:

$226.57

Step-by-step explanation: