To describe a position in more than one
dimension, you must use more than one______

Answer:

Focused,Warm

Explanation:

The more focused the rays are, the more energy an area receives, and the warmer it is.

Answer:

\(0.059\ \text{m/s}\)

Explanation:

\(m_1\) = Mass of bullet = 4.2 g

\(u_1\) = Initial velocity of bullet = 0

\(m_2\) = Mass of hunter with rifle = 69.5 kg

\(u_2\) = Initial velocity of hunter with rifle

\(v_1\) = Final velocity of the bullet = 970 m/s

\(v_2\) = Final velocity of the hunter with the rifle

As the momentum of the system is conserved we have

\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}\\\Rightarrow v_2=\dfrac{0-0-0.0042\times 970}{69.5}\\\Rightarrow v_2=-0.059\ \text{m/s}\)

The recoil speed of the hunter is \(0.059\ \text{m/s}\) in the opposite direction of the bullet.

Answer:

a) for the torque to be maximum, sin should be maximum

i.e (sinФ)maximum = 1

b) therefore the Maximum torque is

Tmax = 0.1838 × 1 = 0.1838  N.m

c) Given the torque is 71.0% of its maximum value; Ф  = 45.24⁰ ≈ 45⁰

Explanation:

Given that; Diameter is 8.40 cm,

Radius (R) = D/2 = 8.40/2 = 4.20 cm = 0.042 m

Number of turns (N) = 17

Current in the loop (I) = 3.20 A

Magnetic field (B) = 0.610 T

Let the angle between the loop's area vector A and the magnetic field B be

Now. the area of the loop is;

A = πR²

A = 3.14 ( 0.042 )²

A =  0.005539 m²

Torque on the loop (t) = NIABsinФ

t = 17 × 3.20 ×0.005539 × 0.610 × sinФ

t = 0.1838sinФ N.m

for the torque to be maximum, sin should be maximum

i.e (sinФ)maximum = 1

therefore the Maximum torque is

Tmax = 0.1838 × 1 = 0.1838  N.m

Given the torque is 71.0% of its maximum value

t = 0.71 × tmax

t = 0.71 × 0.1838

t = 0.1305

Now

0.1305 N.m =  0.1838 sinФ N.m

sinФ = 0.1305 / 0.1838

sinФ = 0.71001

Ф = sin⁻¹ 0.71001

Ф  = 45.24⁰ ≈ 45⁰

The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

For such more question on magnitude

https://brainly.com/question/30337362

#SPJ8

The time t2 when the motorcycle passes the car is approximately 6.41s.

To find the time t2 when the motorcycle passes the car, we can use the equation of motion with constant acceleration:

x = x0 + v0t + 0.5at^2

where x is the displacement, x0 is the initial position (52 m behind the car), v0 is the initial velocity (22 m/s), a is the acceleration (5 m/s^2), and t is the time.

At t2, the motorcycle will have covered the same distance as the car, so x = 0.

Substituting the known values and solving for t, we get:

0 = 52 + 22t + 0.5 * 5t^2

0.5t^2 + 22t + 52 = 0

Using the quadratic formula, the time t2 when the motorcycle passes the car is approximately 6.41 s.

Learn more on displacement here https://brainly.com/question/14422259

#SPJ1

Answer:

the answer is 86400seconds.

Explanation:

1day= 24 hours

24hours to seconds =

24×60×60= 86400 seconds.

( 60 second = 1 minutes)

( 60 minutes = 1 hour)

GPE = Height × Gravitational field strength × Mass

GFS on Earth = 9.8 N/kg

Starting GPE = 2.5 m × 9.8 N/kg × 15 kg

= 367.5 J

Ending GPE = 1.3 × 9.8 N/kg × 15 kg

= 191.1 J

GPE displacement = 367.5 J - 191.1 J

= 176.4 J

The cat experiences a change of 176.4 J of potential energy.

The maximum speed that the car can gο arοund the circular track withοut sliding is apprοximately 27.39 m/s.

Fοrce is a physical quantity that describes the interactiοn between twο οbjects οr between an οbject and its envirοnment. A fοrce can cause an οbject tο accelerate, change directiοn, οr defοrm. Fοrce is a vectοr quantity, meaning it has bοth magnitude and directiοn. It is measured in units οf Newtοns (N).

The fοrmula fοr fοrce is:

F = ma

where F is the fοrce, m is the mass οf the οbject, and a is the acceleratiοn οf the οbject. This fοrmula is knοwn as Newtοn's Secοnd Law οf Mοtiοn. It states that the fοrce acting οn an οbject is directly prοpοrtiοnal tο its mass and acceleratiοn.

The maximum speed that the car can gο arοund the circular track withοut sliding can be calculated using the centripetal fοrce equatiοn:

Fc = mv² / r

where Fc is the centripetal fοrce required tο keep the car mοving in a circle οf radius r, m is the mass οf the car, v is the velοcity οf the car, and r is the radius οf the circular track.

Tο prevent sliding, the fοrce οf static frictiοn between the tires and the rοad must be greater than οr equal tο the maximum fοrce that can be exerted by static frictiοn, which is equal tο µs times the nοrmal fοrce (N = mg), where µs is the cοefficient οf static frictiοn and g is the acceleratiοn due tο gravity.

In this case, the centripetal fοrce required tο keep the car mοving in a circle οf radius 25 m is:

Fc = mv² / r = (1500 kg) x (10 m/s)²  / (25 m) = 6000 N

The maximum fοrce οf static frictiοn that can be exerted between the tires and the rοad is:

Ff = µs x N = (1.0) x (1500 kg) x (10 m/s² ) = 15000 N

Tο find the maximum speed that the car can gο withοut sliding, we need tο find the velοcity that cοrrespοnds tο a centripetal fοrce οf 15000 N:

Fc = mv²  / r = (1500 kg) x (vmax)²  / (25 m) = 15000 N

Sοlving fοr vmax, we get:

vmax = sqrt(15000 N x 25 m / 1500 kg) = 27.39 m/s

Therefοre, the maximum speed that the car can gο arοund the circular track withοut sliding is apprοximately 27.39 m/s.

To know more about Forces visit :

brainly.com/question/13191643

#SPJ1

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

For more such information on: net force

https://brainly.com/question/14361879

#SPJ8

Electromagnetic waves are transverse waves composed by the perpendicular oscillating electric and magnetic fields.

EM waves have both Electrical and magnetic features.

they travel in the velocity of light (3*10⁸ ms⁻¹)

Electromagnetic spectrum is obtained according to their wave length and the frequency. Due to wave length range it's categorized. Here is the decreasing  order of wave length and increasing order  of different wave types in electromagnetic spectrum

Examples,

When electromagnetic radiation interacts with single atoms and molecule, its behavior also depends on the amount of energy per quantum(photon)it carries wave number =1/wavelength in cm speed of light=wavelength x frequency energy = Planck's constant x frequency.

Therefore, electromagnetic spectrum depends on wavelength and frequency

To know more about Electromagnetic, refer: https://brainly.com/question/9184100

#SPJ4

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

for such more questions on  mass

https://brainly.com/question/86444

#SPJ8

Answer:

b

Explanation:

i took the test

Earth’s landmasses were first recognized as the continents we know today

135 million years ago.

Landmass is defines as a large area of land. It can also be referred to as the

continents we have today. There are seven types of earth landmasses and

they are

They were first discovered around 135 million years ago by the early

dwellers of the earth.

Read more on https://brainly.com/question/18125355

Watching Gladiators was a a favorite pastime of Roman civilization. It was a game based on the Roman martial ethics. It lasted for nearly thousands of years. Hence option C is correct.

An armed warrior known as a gladiator amused spectators in the Roman Republic and Roman Empire by engaging in bloody fights with other gladiators, wild animals, and condemned prisoners.

Some gladiators were unpaid volunteers who jeopardized their lives as well as their position in society and the law by participating in the fight. The majority endured severe education, were treated like inferiors in society, and were separated even in death.

Regardless of where they came from, gladiators served as a living example of Rome's martial virtues to onlookers, and by fighting or dying honorably, they may win adulation and widespread renown.

Find more on Roman civilization:

https://brainly.com/question/13753513

#SPJ9

\(\begin{align}Q &= \frac{kA\Delta T}{d} \ &= \frac{(0.02)(0.0315)(90 - 22)}{0.005} \ &= 237.6\ \text{W}\end{align}\)

This is the rate of heat transfer through the insulated cup. Note that this assumes that the heat transfer is steady and one-dimensional, which may not be strictly accurate in reality.

\(\begin{align}\huge\colorbox{black}{\textcolor{yellow}{I hope this helps !}}\end{align}\)

\(\begin{align}\colorbox{purple}{\textcolor{lime}{Please mark as brillinest !}}\end{align}\)

\(\textcolor{cyan}{\small\textit{If you have any further questions, feel free to ask!}}\)

Answer:

Hey heres your ans

Explanation:

Wavelength will increase

Tq

Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.

1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.

2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:

Element   | Electron Configuration | Group | Period |

--------------------------------------------

Hydrogen  | 1s^1                              | 1     | 1      |

Lithium       | [He] 2s^1                     | 1     | 2      |

Carbon       | [He] 2s^2 2p^2          | 14    | 2      |

Oxygen      | [He] 2s^2 2p^4          | 16    | 2      |

Neon          | [He] 2s^2 2p^6          | 18    | 2      |

--------------------------------------------

3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.

- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.

- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.

By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.

For more such questions on the periodic table:

https://brainly.com/question/15987580

#SPJ8

Jerome solves a problem using the law of conservation of momentum. What should Jerome always keep constant for each object after the objects collide and bounce apart?

a-velocity

b-mass

c-momentum

d-direction

Answer:

b. Mass

Explanation:

This question has to do with the principle of the law of conservation of momentum which states that the momentum of a system remains constant if no external force is acting on it.

As the question states, two objects collide with each other and eventually bounce apart, so their momentum may not be conserved but the mass of the objects is constant for each non-relativistic motion. Because of this, the mass of each object prior to the collision would be the same as the mass after the collision.

Therefore, the correct answer is B. Mass.

This question involves the concept of the law of conservation of momentum.

Jerome should always keep the "mass" of each object constant after the objects collide and bounce apart.

The law of conservation of momentum states that the momentum of a system of objects must remain constant before and after the collision has taken place.

Mathematically,

\(m_1u_1+m_2u_2=m_1v_1+m_v_2\)

where,

m₁ = mass of the first object

m₂ = mass of the second object

u₁ = velocity of the first object before the collision

u₂ = velocity of the second object before the collision

v₁ = velocity of the first object after the collision

v₂ = velocity of the second object after the collision

Hence, it is clear from the formula that the only thing unchanged before and after the collision is the mass of each object.

Learn more about the law of conservation of momentum here:

brainly.com/question/1113396?referrer=searchResults

The attached picture illustrates the law of conservation of momentum.

Answer:

The final temperature of the bullets is 327.3 ºC.

Explanation:

Let suppose that a phase change does not occur during collision and collided bullets stop at the end. We represent the phenomenon by the First Law of Thermodynamics:

\(K_{A, o} + K_{B, o}-K_{A}-K_{B}+U_{A,o} + U_{B,o}-U_{A}-U_{B} = 0\) (1)

Where:

\(K_{A,o}\), \(K_{A}\) - Initial and final translational kinetic energies of the 15-g bullet, measured in joules.

\(K_{B,o}\), \(K_{B}\) - Initial and final translational kinetic energies of the 7.75-g bullet, measured in joules.

\(U_{A,o}\), \(U_{A}\) - Initial and final internal energies of the 15-g bullet, measured in joules.

\(U_{B,o}\), \(U_{B}\) - Initial and final internal energies of the 7.75-g bullet, measured in joules.

By definitions of translational kinetic energy and sensible heat we expand and simplify the equation above:

\(\frac{1}{2}\cdot m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+ \frac{1}{2}\cdot m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})+(m_{A}+m_{B})\cdot c\cdot (T_{o}-T) = 0\) (2)

Where:

\(m_{A}\), \(m_{B}\) - Masses of the 15-g and 7.75-g bullets, measured in kilograms.

\(v_{A,o}\), \(v_{A}\) - Initial and final speeds of the 15-g bullet, measured in meters per second.

\(v_{B,o}\), \(v_{B}\) - Initial and final speeds of the 7.75-g bullet, measured in meters per second.

\(c\) - Specific heat of lead, measured in joules per kilogram-Celsius degree.

\(T_{o}\), \(T\) - Initial and final temperatures of the bullets, measured in Celsius degree.

Now we clear the final temperature of the bullets:

\((m_{A}+m_{B})\cdot c \cdot (T-T_{o}) = \frac{1}{2}\cdot [m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})]\)

\(T-T_{o} = \frac{m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})}{(m_{A}+m_{B})\cdot c}\)

\(T= T_{o}+\frac{m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})}{(m_{A}+m_{B})\cdot c}\) (3)

If we know that \(T_{o} = 30\,^{\circ}C\), \(m_{A} = 15\times 10^{-3}\,kg\), \(m_{B} = 7.75\times 10^{-3}\,kg\), \(v_{A,o} = 295\,\frac{m}{s}\), \(v_{B,o} = 375\,\frac{m}{s}\), \(v_{A} = 0\,\frac{m}{s}\), \(v_{B} = 0\,\frac{m}{s}\) and \(c = 128\,\frac{J}{kg\cdot ^{\circ}C}\), then the final temperature of the collided bullets is:

\(T = 30\,^{\circ}C+\frac{(15\times 10^{-3}\,kg)\cdot \left[\left(295\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]+(7.75\times 10^{-3}\,kg)\cdot \left[\left(375\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{(15\times 10^{-3}\,kg+7.75\times 10^{-3}\,kg)\cdot \left(128\,\frac{J}{kg\cdot ^{\circ}C} \right)}\)

\(T = 852.534\,^{\circ}C\)

Given that found temperature is greater than melting point, then we conclude that supposition was false. If we add the component of latent heat of fussion, then the resulting equation is:

\(\frac{1}{2}\cdot m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+ \frac{1}{2}\cdot m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})+(m_{A}+m_{B})\cdot c\cdot (T_{o}-T)-U = 0\) (4)

\(U=\frac{1}{2}\cdot m_{A}\cdot (v_{A,o}^{2}-v_{A}^{2})+ \frac{1}{2}\cdot m_{B}\cdot (v_{B,o}^{2}-v_{B}^{2})+(m_{A}+m_{B})\cdot c\cdot (T_{o}-T)\)

If we know that \(T_{o} = 30\,^{\circ}C\), \(T = 327.3\,^{\circ}C\), \(m_{A} = 15\times 10^{-3}\,kg\), \(m_{B} = 7.75\times 10^{-3}\,kg\), \(v_{A,o} = 295\,\frac{m}{s}\), \(v_{B,o} = 375\,\frac{m}{s}\), \(v_{A} = 0\,\frac{m}{s}\), \(v_{B} = 0\,\frac{m}{s}\) and \(c = 128\,\frac{J}{kg\cdot ^{\circ}C}\), then latent heat received by the bullets during impact is:

\(U =\frac{1}{2}\cdot (15\times 10^{-3}\,kg)\cdot \left[\left(295\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right] + \frac{1}{2}\cdot (7.75\times 10^{-3}\,kg)\cdot \left[\left(375\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]+(15\times 10^{-3}\,kg+7.75\times 10^{-3}\,kg)\cdot \left(128\,\frac{J}{kg\cdot ^{\circ}C} \right) \cdot (30\,^{\circ}C-327.3\,^{\circ}C)\)\(U = 331.872\,J\)

The maximum possible latent heat (\(U_{max}\)), measured in joules, that both bullets can receive during collision is:

\(U_{max} = (m_{A}+m_{B})\cdot L_{f}\) (5)

Where \(L_{f}\) is the latent heat of fusion of lead, measured in joules per kilogram.

If we know that  \(m_{A} = 15\times 10^{-3}\,kg\), \(m_{B} = 7.75\times 10^{-3}\,kg\) and \(L_{f} = 2.45\times 10^{4}\,\frac{J}{kg}\), then the maximum possible latent heat is:

\(U_{max} = (15\times 10^{-3}\,kg+7.75\times 10^{-3}\,kg)\cdot \left(2.45\times 10^{4}\,\frac{J}{kg} \right)\)

\(U_{max} = 557.375\,J\)

Given that \(U < U_{max}\), the final temperature of the bullets is 327.3 ºC.

Answer:

351.28 N

Explanation:

Let F be the force on the object and f be the frictional force. The component of the force acting in the horizontal direction causing the object to move is FcosФ where Ф is the angle between F and the horizontal = 43.0°. The frictional force on the packing crate f = μN where μ = coefficient of kinetic friction = 0.35 and N = normal force = W = weight of the packing crate = mg where m = mass of crate = 74.9 kg and g = acceleration due to gravity = 9.8 m/s².  So, f = μN = μW = μmg

So, the net force on the packing crate is

FcosФ - f = ma

FcosФ - μmg = ma

Since the crate moves at constant speed, its acceleration a = 0

So, FcosФ - μmg = ma

FcosФ - μmg = m(0)

FcosФ - μmg = 0

FcosФ = μmg

F = μmg/cosФ

Substituting the values of the variables into the equation, we have

F = μmg/cosФ

F = 0.35 × 74.9 kg × 9.8 m/s²/cos43.0°

F = 256.907 kg-m/s²/0.73135

F = 351.28 kg-m/s²

F = 351.28 N

Answer: The correct answer for this is 10N

Explanation:

FORMULA

F= m x a

F = force

m = mass

a = acceleration

Using the formula

F= 10 x 5

Multiply

F= 10 N

so The answer 10 N is the correct selection

Answer:

C. Solids,Liquids, Gases

Answer:

2.00 A

Explanation:

Total resistance = 10 + 20 + 30 = 60 ohms

Potential difference (V) = 120volts

Current (I) =?

from Ohms law V = IR

==> I = V/R = 120/60 = 2 A

Note: for resistors in series equal amount of electric current flows through the circuit

Explanation:

A concave lens is also known as a diverging lens because it is shaped round inwards at the centre and bulges outwards through the edges, making the light diverge. They are used to treat myopia as they make faraway objects look smaller than they are.

Answer:

2.63 microfarads

Explanation:

C = Q/V   =  2.5 x 10^-3 C / 950 V = 2.63 microfarads

Answer:

Explanation:

C

To collect the asteroid an equal magnitude of the force in opposite direction is needed.

What is force ?

The motion or speed of an object depends upon the magnitude and the direction of the force.

If the direction of the force is against the direction of motion, then the object will slow down or stop. The two forces of the same magnitude in the opposite direction cancel each other and the collided objects stop each other.

Therefore, to collect the asteroid an equal magnitude of the force in opposite direction is needed.

To know more about Force , click the given link ;

brainly.com/question/5961485

#SPJ4

Answer:

.

Explanation:

Answer:

it be the mean i think add them up through 0 -3 and divide by 3

Explanation: