To decrease the risk of rear wheel traction loss:
Answers
To decrease the risk of rear wheel traction loss, there are a few things you can do. First, make sure your tires are properly inflated and have good tread. This will ensure that they have the best possible grip on the road. Second, avoid sudden or aggressive acceleration, as this can cause the rear wheels to spin and lose traction.
To decrease the risk of rear wheel traction loss, you should:
1. Maintain a steady speed: Avoid sudden accelerations or decelerations, as these can cause the rear wheels to lose traction.
2. Keep a safe following distance: This allows you more time to react to any potential hazards and decreases the chances of sudden braking, which could lead to traction loss.
3. Drive smoothly: Make gradual and smooth turns, avoiding sharp or abrupt movements that could cause the rear wheels to lose grip.
4. Use appropriate tires: Ensure your tires are well-maintained, with sufficient tread depth and proper inflation, to provide optimal traction in various road conditions.
5. Adjust your driving to road conditions: Be aware of wet, icy, or slippery surfaces and adjust your speed, following distance, and braking accordingly to minimize the risk of traction loss.
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Related Questions
a minimum set of requirements for plumbing installations in a municipality, city, county, or state is a(n)
Answers
A minimum set of requirements for plumbing installations in a municipality, city, county, or state is a plumbing code.
A plumbing code is a set of minimum standards and regulations that dictate the design, installation, and maintenance of plumbing systems. The code is typically enforced by local or state authorities and serves to protect public health and safety by ensuring that plumbing systems are safe, functional, and sanitary. Plumbing codes cover a wide range of requirements, including the size and type of pipes and fittings, fixture installation and location, drainage and venting, water supply, and backflow prevention. Plumbing codes are updated periodically to reflect advances in technology, changes in building materials, and new safety and environmental concerns. Compliance with the plumbing code is mandatory, and failure to meet the code requirements can result in fines, penalties, or legal action.
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Air is compressed from 20 psia and 70°F to 150 psia in a compressor. The compressor is operated such that the air temperature remains constant. Calculate the change in the specific volume of air as it passes through this compressor.
Answers
Answer: -8.51 ft^3/lbm
Explanation:
In this question, to find the change in volume, we will use the ideal gas law.
\(\begin{aligned}&n_{1}=1 \text { mole }\\&\mathrm{P}_{1}=20 \mathrm{psia}\\&\mathrm{T}_{1}=70^{\circ} \mathrm{F}\\&T_{1}=(70+460)^{0} \mathrm{R}\\&v_{1}=\frac{\left(0.3704 \frac{psia \cdot_{\text { } ft^{3}}}{l \mathrm{lbm} \cdot R}\right)(70+460)^{0} \mathrm{R}}{20 \mathrm{psi}}\\&v_{1}=9.816 \frac{\mathrm{ft}^{3}}{\mathrm{lbm}}\end{aligned}\)
\(\begin{aligned}&\mathrm{n}_{2}=1 \text { mole } \\&\mathrm{P}_{2}=150 \mathrm{psia} \\&\mathrm{T}_{1}=\mathrm{T}_{2}=70^{0} \mathrm{~F} \\&\mathrm{~T}_{1}=\mathrm{T}_{2}=(70+460)^{0} \mathrm{R} \\&v_{2}=\frac{\left(0.3704 \frac{\text { psia} \cdot \mathrm{ft}^{3}}{\mathrm{lbm} \cdot R}\right)(70+460)^{0} \mathrm{R}}{150 \mathrm{psi}} \\&v_{2}=1.309 \frac{\mathrm{ft}{ }^{3}}{\mathrm{lbm}}\end{aligned}\)
\($$The change in volume is,$$\begin{aligned}&\Delta v=v_{2}-v_{1} \\&\Delta v=1.309-9.816 \\&\Delta v=-8.51 \frac{\mathrm{ft}^{3}}{\mathrm{lbm}}\end{aligned}\text{The negative sign shows that the gas was compressed during this process}\)
URGENT NEED HELP BY AN HOUR
C++ ONLY
Given a line of text as input: (1) output the number of characters excluding the three characters commonly used for end-of-sentence punctuation( period, exclamation point, and question mark), (2) then output the number of end-of-sentence punctuation characters that were found. You can just do (1) to pass the first few test cases for partial credit, then do (2) for full credit.
Ex: If the input is "Listen, Sam! Calm down. Please.", the output is:
28
3
Ex: If the input is "What time is it? Time to get a watch! O.K., bye now.", the output is:
43
5
Answers
Using the knowledge in computational language in python it is possible to write a code that output the number of characters excluding the three characters commonly used for end-of-sentence punctuation.
Writting the code:import re
def check_sentence(text):
result = re.search(r"^[A-Z][A-Za-z\s]*[\.\?!]$", text)
return result != None
print(check_sentence("Is this is a sentence?")) # True
print(check_sentence("is this is a sentence?")) # False
print(check_sentence("Hello")) # False
print(check_sentence("1-2-3-GO!")) # False
print(check_sentence("A star is born.")) # True
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Re armature of a 4 pole DC generator is required to generate an emf of 520v on open circuit when revolving at a speed of 660rpm. Calculate the magnetic flux per pole required if the armature has 144 slots with 2 coil sides per slot each coil consisting of 3 turns. The armature is wave wound.
Answers
Since the armature is wave wound, the magnetic flux per pole is 0.0274 Weber.
Given the following data:
Emf = 520 VoltsSpeed = 660 r.p.mNumber of armature conductors = 144 slotsNumber of poles = 4 polesNumber of parallel paths = 2To find the magnetic flux per pole:
Mathematically, the emf generated by a DC generator is given by the formula;
\(E = \frac{\theta ZN}{60}\) × \(\frac{P}{A}\)
Where:
E is the electromotive force in the DC generator.Z is the total number of armature conductors.N is the speed or armature rotation in r.p.m.P is the number of poles.A is the number of parallel paths in armature.Ф is the magnetic flux.First of all, we would determine the total number of armature conductors:
\(Z = 144\) × \(2\) × \(3\)
Z = 864
Substituting the given parameters into the formula, we have;
\(520 = \frac{\theta (864)(660)}{60}\) × \(\frac{4}{2}\)
\(520 = \theta (864)(11)\) × \(2\)
\(520 = 19008 \theta \\\\\Theta = \frac{520}{19008}\)
Magnetic flux = 0.0274 Weber.
Therefore, the magnetic flux per pole is 0.0274 Weber.
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if a technician inspects the interior of a combustion chamber and finds large quantities of unburned oil, he would correctly conclude that th
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Large quantities of unburned oil in the combustion chamber indicate an issue with incomplete combustion.
What does the presence of excessive unburned oil in the combustion chamber suggest?When a technician inspects the interior of a combustion chamber and discovers significant amounts of unburned oil, it is a clear indication of incomplete combustion. In a properly functioning combustion process, the fuel should be completely burned, leaving little to no residue behind. However, the presence of unburned oil points to a problem with the combustion process.
Incomplete combustion can be caused by various factors, such as improper fuel-air mixture, clogged fuel injectors, malfunctioning ignition system, or worn-out components like piston rings or valves. These issues can result in the accumulation of unburned oil, which can lead to reduced engine performance, increased emissions, and potential damage to the combustion chamber and other engine parts.
To address this problem, the technician would need to diagnose the specific cause of the incomplete combustion and perform necessary repairs or adjustments. This may involve cleaning or replacing fuel injectors, checking and adjusting the air-fuel mixture, inspecting the ignition system, or conducting a comprehensive engine tune-up.
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Two wooden members of uniform rectangular cross section are joined using a simple glued scarf splice. The maximum allowable shearing stress and maximum allowable normal stress in the glued splice is 50 MPa and 100 MPa, respectively. The cross-section area of the glued member is 400 mm2. (a) What should the value of the angle be to achieve maximum load Fmax? (b) What is the magnitude of the maximum load Fmax?
Answers
Answer:
a). α = 26.57
b). Maximum load is 50 .kN
Explanation:
a).
The normal force is given by
N = σ A cosec β
where, σ is the normal stress
A is the cross sectional area
Similarly, shear force is given by
S= τ A cosec β
where, τ is the shearing stress
Now from the figure,
tan β = S/N
= τ/σ
Therefore, \($\beta = \tan^{-1}(2)$\) = 63.43
α = 90 - β = 26.57
b).
The normal force is given by
\($N=(100\times 10^6)(400\times 10^{-6}) \text{ cosec}\ 63.43$\)
\($N=44.78\times 10^3$\) N
We have
\($\Sigma F_y=0$\)
∴ N - F sin β = 0
⇒ F = N / sin β
= \($\frac{44.72\times 10^3}{\sin(63.43)} = 50\times 10^3 N$\)
Similarly,
The shear force is given by
S = τ A cosec β
= \($(50\times 10^6)(400\times 10^{-6}) \text{ cosec}\ 63.43 = 22.36\times 10^3 N$\)
\($\Sigma F_x=0$\)
∴ S - F cos β = 0
⇒ F = S / cos β
\($\frac{22.36\times 10^3}{\cos(63.43)} = 49.99\times 10^3 N$\)
Therefore, force is 50 kN.
A 75-kg piano is hosted on a crane and delivered throughout the window of a 6th story apartment (20 meters above ground). What is the potential energy of the piano?
Answers
Answer:
14,700 J
Explanation:
PE = Mgh = (75 kg)(9.8 m/s²)(20 m) = 14,700 J
with a digital system, if you have measured incorrectly and use too low of a kvp for adequate penetration, what do you need to do with the next exposure
Answers
The x-ray beam's penetrating power is regulated by kVp (beam quality). Every time an exposure is conducted, the x-rays need to be powerful (enough) to sufficiently penetrate through the target area.
How does kVp impact the exposure to digital receptors?The radiation's penetration power and exposure to the image receptor both increase as the kVp value is raised.
Exposure to the image receptor is enhanced with an increase in kVp, right?Due to an increase in photon quantity and penetrability, exposure at the image receptor rises by a factor of five of the change in kVp, doubling the intensity at the detector with a 15% change in kVp.
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Water flows without friction through a horizontal pipe and enters a section where the cross sectional area is smaller. The velocity profile is uniform at sections 1 and 2.
Water flows without friction through a horizontal
The correct statement about the static pressure p2 relative to p1 and the velocity V2 relative to V1 along the streamline down the center of the pipe is?
(A) p2 < p1 and V2 < V1
(B) p2 < p1 and V2 > V1
(C) p2 > p1 and V2 < V1
(D) p2 > p1 and V2 > V1
(E) The relation between p2 and p1 is indeterminate
Answers
Option C. The correct statement about the static pressure p₂ relative to p₁ and the velocity V₂ relative to V₁ along the streamline down the center of the pipe is p₂ > p₁ and V₂ < V₁.
When fluid flows without friction through a horizontal pipe and enters a section where the cross-sectional area is smaller, the static pressure at the smaller area decreases relative to the static pressure at the larger area, whereas the velocity increases. Therefore, the correct statement about the static pressure p₂ relative to p₁ and the velocity V₂ relative to V₁ along the streamline down the center of the pipe is p₂ > p₁ and V₂ < V₁.
This is because the mass flow rate is conserved across any cross-section of the pipe, and this leads to an increase in fluid speed as the cross-sectional area decreases (and vice versa). As a result, the fluid experiences an increase in velocity head and a decrease in pressure head as it moves from the larger area to the smaller area.
Therefore the correct option is C.
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the 1.000 cm mark on a steel ruler is accurate at a temperature of 20.22°c. at what temperature will the 1.000 cm mark be too long by 0.16%? the linear coefficient of expansion for steel is a
Answers
The 1.000 cm mark on the steel ruler will be too long by 0.16% at a temperature of approximately 1096.25°C.
To determine the temperature at which the 1.000 cm mark on the steel ruler will be too long by 0.16%, we need to consider the linear coefficient of expansion for steel. The linear coefficient of expansion represents how much a material expands or contracts with a change in temperature.
The given information states that the 1.000 cm mark on the ruler is accurate at a temperature of 20.22°C. We can assume this is the reference temperature. The ruler will expand as the temperature increases.
To find the temperature at which the 1.000 cm mark becomes too long by 0.16%, we can use the formula for linear expansion: ΔL = α * L * ΔT, where ΔL is the change in length, α is the linear coefficient of expansion, L is the original length, and ΔT is the change in temperature.
In this case, we want to find the temperature at which ΔL/L equals 0.16%. Since ΔL/L can be approximated by ΔT * α, we can set up the equation: ΔT * α = 0.0016, where α is the linear coefficient of expansion for steel.
By rearranging the equation and substituting the given values, we can solve for ΔT, which represents the change in temperature. ΔT = 0.0016 / α.
Given that the linear coefficient of expansion for steel (α) is not provided, it is not possible to calculate the exact temperature. However, if the value of α is known, we can substitute it into the equation to find the change in temperature.
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Fast fourier transforms (FFT) are algorithms that speed up the computation of fourier coefficients compared to the traditional direct form discuss how the speed up is achieved
Answers
Answer:
Fast Fourier ( FFT ) algorithms speed up computation of Fourier coefficients by simply reducing the the computing time of a traditional direct form Fourier series. it achieves this by breaking complex DFTS into smaller DFTS to reduce its complexity and in turn reduce its computing time
Explanation:
Fast Fourier ( FFT ) algorithms speed up computation of Fourier coefficients by simply reducing the the computing time of a traditional direct form Fourier series. it achieves this by breaking complex DFTS into smaller DFTS to reduce its complexity and in turn reduce its computing time. an example of such FFT is Cooley-Tukey algorithm
the leading cause of death for those aged between 8 and 14 is:
Answers
The leading cause of death for those aged between 8 and 14 is accidents. The primary causes of accidents in children are pedestrian accidents, bicycle accidents, and motor vehicle accidents.
However, there are several other factors that contribute to accidents, including poor judgment, risk-taking behavior, and a lack of experience in decision-making and problem-solving skills.
Most of these accidents are preventable, and education is the most effective way to reduce the rate of accidents. Parents, educators, and community leaders can work together to promote safety and prevent accidents
Accidents are the leading cause of death for children aged 8-14. Pedestrian, bicycle, and motor vehicle accidents are the primary causes of accidents in children.
However, there are several other factors that contribute to accidents, including poor judgment, risk-taking behavior, and a lack of experience in decision-making and problem-solving skills.
Many of these accidents are preventable, and education is the most effective way to reduce the rate of accidents. Parents, educators, and community leaders can work together to promote safety and prevent accidents.
According to the Centers for Disease Control and Prevention (CDC), in 2018, approximately 2,500 children aged 1-14 years died due to unintentional injuries, and 12,000 were hospitalized for non-fatal injuries.
Motor vehicle accidents were responsible for the most deaths and injuries in this age group.
Drowning, burns, falls, and poisoning are some other causes of accidents in children that result in injuries or death. These injuries can have a significant impact on children's health and well-being.
In conclusion, accidents are the leading cause of death for children aged 8-14. Pedestrian, bicycle, and motor vehicle accidents are the primary causes of accidents in children. Many of these accidents are preventable, and education is the most effective way to reduce the rate of accidents. Parents, educators, and community leaders can work together to promote safety and prevent accidents.
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What is the primary damage control telephone circuit for
Damage Control Central?
A) 2JZ/NET 80
B) 7JZ/NET 86
C) 5JZ/NET 82
D) 4JZ/NET 81
Answers
2JZ/net 80 is the primary damage control cellphone circuit for damage control central
2JZ/net 80 is utilized by Pri DC & Stab Ctrl; DCC & all R/Ls damage manipulate imperative (DCC) is the hub of the deliver's harm control efforts. it's far organised to coordinate manipulate of all damage the deliver can also sufferin warfare, and it keeps the commanding officer suggested of the capabilities of the deliver after every casualty. It trains repair events to perform and control damage as independent devices.DCC employees take a look at all damage reviews and the corrective motion being taken. DCC issues direction when repairs are now not progressing satisfactorily,damage is past the talents of the personnel worried, recommendation is asked, or corrective motion in progress is incorrect
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Water is the working fluid in an ideal Rankine cycle. Superheatedvapor enters the turbine at 10MPa, 480°C, and the condenser pressure is6 kPa. Isentropic efficiencies of the turbine and pump are 80% and 75%,respectively. Determine for the cyclea.the actual heat transfer to the working fluid passing through thesteam generator, in kJ per kg of steam flowing.b.the thermal efficiency.c.the actual heat transfer from the working fluid passing through thecondenser to the cooling water, in kJ per kg of steam flowing
Answers
Answer:
Explanation:
Given that:
Superheated vapor enters the turbine at 10 MPa, 480°C,
From the tables of superheated steam tables; the following values are obtained
\(h_1 = 3322.02 \ kJ/kg\\\\ s_1 = 6.52846 \ kJ/kg.K\)
Also; from the system, the isentropic line is 1-2 in which s_2 is in wet state
\(s_2 = s_{f \ 6 kpa} +xs_{fg \ 6 kpa}\)
\(s_2 =0.51624 + x(7.82)\)
\(s_2 =0.51624 + 7.82x\)
From the values obtained;
\(s_1 =s_2= 6.52846 \ kJ/kg.K\)
Therefore;
6.52846 = 0.51624+7.82x
6.52846 - 0.51624 = 7.82 x
6.01222 = 7.82 x
x = 6.01222/7.82
x = 0.7688
The enthalpy for this process at state (s_2) can be determined as follows:
\(h_2 = h _f +xh_{fg} \\ \\ h_2 = 150.15 +(0.77 \times 2415.92) \\ \\ h_2 =150.15 +( 1629.2584 ) \\ \\ h_2 =2010.4084 \ kJ/kg\)
The actual enthalpy at s_2 by using the isentropic efficiency of the turbine can determined by using the expression:
\(n_T = \dfrac{h_1-h_{2a}}{h_1-h_2}\)
\(0.8 = \dfrac{3322.02-h_{2a}}{3322.02-2010.4084}\)
\(0.8 = \dfrac{3322.02-h_{2a}}{1311.6116}\)
\(0.8 * {1311.6116}= {3322.02-h_{2a}\)
\(1049.28928= {3322.02-h_{2a}\)
\(h_{2a}= {3322.02- 1049.28928\)
\(h_{2a}= 2272.73072\) kJ/kg
The work pump is calculated by applying the formula:
\(w_p = v_{f \ 6 kpa} (p_4-p_3)\)
\(w_p = 0.0010062 * (10000-6)\)
\(w_p = 0.0010062 *9994\)
\(w_p = 10.0559628 \ kJ/kg\)
However;
\(w_p = h_4 -h_3\)
From the process;
\(h_3 = h_{f(6 kpa)} = 150.15 \ kJ/kg\)
\(10.0559628 = h_4 - 150.15\)
\(10.0559628+ 150.15 = h_4\)
\(160.2059628= h_4\)
\(h_4= 160.2059628 \ kJ/kg\)
The actual enthalpy at s_4 by using the isentropic efficiency of the turbine can determined by using the expression:
\(n_P = \dfrac{h_4-h_{3}}{h_{4a}-h_3}\)
-0-1"
-0
-20
-15
-10
0
-5
Answers
75743366
Explanation:
Consider an isothermal CSTR with first order reaction with a rate constant k. Let V, v are the volume of liquid in the tank, and volumetric flow rate of the liquid to the tank. Ca, Cai are the concentration of species A in the tank, and in the inlet fluid. Sketch and label. The volumetric flow rate is always constant but the inlet concentration may change. Write a balance for component A, and convert to deviation variables. For deviation variables, you can use hats. Obtain a relationship between cA(s), cAi(s). Represent as a block diagram. Identify the time constant and process gain.
Answers
Consider an isothermal CSTR with a first-order reaction having a rate constant k. Let V be the volume of liquid in the tank, v be the volumetric flow rate of liquid to the tank. Ca, Cai are the concentration of species A in the tank and inlet fluid respectively.
A sketch of the system is shown below.Inlet Concentration may change:Since the volumetric flow rate is always constant, the inlet concentration may vary.
Therefore, the inlet flow rate multiplied by the inlet concentration must be equal to the outlet flow rate multiplied by the outlet concentration.Balance equation:For component A, balance equation is;In deviation variables, the equation is;Relationship between cA(s), cAi(s):Applying Laplace transform to the differential equation, we have:Block Diagram:From the block diagram, we can see that the transfer function is;Therefore, the time constant is equal to V/v and process gain is equal to -v/(kV).
Thus, the transfer function is given by Y(s)/U(s) = -v/(kV + sV)
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if a person is injured at the hospital during a natural disaster a correct action to take is
Answers
That’s what I learnt sooo..
Which organization would provide business and leadership training to a high school hospitality student?
Answers
Answer:
Future Business Leaders of America
Explanation:
what is the purpose of a cnc machining center? machining centers enable a single machine to tolinmg u
Answers
CNC machining equipment allows companies to manufacture complex parts with a user-friendly, single-setup machining process. This structure offers significant productivity advantages — cutting labor costs, increasing part quality, and reducing work time.
Two numbers, A and B, are stored in one byte floating point notation using the least significant (rightmost) 3 bits for the exponent. Both parts of each number are in 2's complement. If the A and B are 00110111 and 11011000, then A+B in the same notation as the operands is (select all correct answers)
a) 10000010
b) Any of the numerical answers
c) 11110000
d) None of the numerical answers
e) 11100111
f) 11000110
Answers
Floating point numbers are used to represent noninteger fractional numbers and are used in most engineering and technical calculations, for example, 3.256, 2.1, and 0.0036.
Which data is stored using a floating point representation?As detailed in this book, a binary floating point number has the structure
with p being the number of significant bits, emin n emax being the exponent range, and d1 0 being the first significant bit.
The biggest magnitude for a floating point number using this notation is and the smallest magnitude for a non-zero floating point number is. The sign bit is the leftmost bit internally, 0 denotes nonnegative and 1 denotes negative. Using e bits, the exponent is given after. A bias of 2e 1 1 is added to the genuine exponent to avoid having to express negative exponents. For instance, the bias is 127 if the exponent is represented by 8 bits. The cached exponent is 18 + 127 = 109 if the true exponent is 18.
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The hard drive (HDD) you are installing in a pc is the boot drive with the operating system on it. you want to make sure that the bios recognize this hdd as the boot drive without the need to configure it as the boot drive in bios. which of the following should you do to make sure the hdd is recognized as the boot drive automatically?
a. Verify that the power supply and SATA cables can reach the HDD.
b. Connect the HDD to the lowest numbered SATA connector on the motherboard.
c. The HDD needs to be partitioned and formatted with a file system.
Answers
Installing the operating system on the HDD and making sure that the partition on the HDD is identified as "active" are the best ways to guarantee that the HDD is immediately recognised as the boot drive.
Why is Windows unable to identify my HDD in BIOS?Why Does My Hard Disk Appear in the BIOS But Not Windows. Most causes would result in this mistake. The operating system's driver is probably incompatible with the drive if it is identified in the BIOS but not in the OS. Moreover, it's conceivable for one drive to support AHCI while the other only supports traditional IDE.
What will you do if an HDD is not found when installing the OS?In the BIOS, look at the Hard Disk. If not, spend some time checking the BIOS to see if the hard drive is detected, especially if you're installing an operating system from a bootable USB drive or CD/DVD disc. You may access BIOS settings by holding down F2 while pressing. Check to see if the hard drive appears there.
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An electrical contractor employs 16 people. Five people earn $15 per hour, four people earn $17 per hour, and the remaining people earn $16 per hour. What is the total hourly wage earned by all 16 people
Answers
$255 per hour
Explanation:Total number of employed people = 16
(i) 5 people earn $15 per hour
That means that the total amount earned by those 5 is;
5 x $15 = $75 per hour
(ii) 4 people earn $17 per hour
That means that the total amount earned by those 4 is;
4 x $17 = $68 per hour
(iii) The remaining people earn $16 per hour.
There are 7 people remaining. i.e
16 - 5 - 4 = 7
That means that the total amount earned by those remaining (7) is;
7 x $16 = $112 per hour
The total hourly wage is therefore the sum of all the results in i, ii and iii. i.e
Total = $75 + $68 + $112
Total = $255
Therefore, the total hourly wage earned by all 16 people is $255
The steady-state data listed below are claimed for a power cycle operating between hot and cold reservoirs at 1200 K and 400 K, respectively. For each case, evaluate the net power developed by the cycle, in kW, and the thermal efficiency. Also in each case apply the equation below on a time-rate basis to determine whether the cycle operates reversibly, operates irreversibly, or is impossible.
(a) Qh(dot)=600 kW, Qc(dot)=400 kW
(b) Qh(dot)=600 kW, Qc(dot)=0 kW
(c) Qh(dot)=600 kW, Qc(dot)=200 kW
∮ (δQ/T)_b = -σ_cycle
Answers
Answer:
(a) Qh(dot)=600 kW, Qc(dot)=400 kW is an irreversible process.
(b) Qh(dot)=600 kW, Qc(dot)=0 kW is an impossible process.
(c) Qh(dot)=600 kW, Qc(dot)=200 kW is a reversible process.
Explanation:
T(hot) = 1200k, T(cold) = 400
efficiency n = (Th - Tc ) / Tc
n = (1200 - 400) / 1200 = 0.667 (this will be the comparison base)
(a)
Qh = 600 kW, Qc = 400 kW
n = (Qh - Qc) / Qh ⇒ (600 - 400) / 600
n = 0.33
0.33 is less than efficiency value from temperature 0.67
∴ it is irreversible process
(b)
Qh = 600 kW, Qc = 0
n = (Qh - Qc) / Qh ⇒ (600 - 0) / 600 = 1
efficiency in any power cycle can never be equal to one.
∴ it is an impossible process.
(c)
Qh = 600 kW, Qc = 200 kW
n = (Qh - Qc) / Qh = (600 - 200) / 600
n = 0.67 (it is equal to efficiency value from temperature)
∴ it is a reversible process
Tech A says that radial ply tires have much more flexible sidewalls than bias-ply tires because of their construction. Tech B says that bias-ply tires have a more durable construction than radial tires. Who is correct?
Answers
Answer:
Tech A and Tech B are correct
Explanation:
Tech A is correct because radial ply tires have more flexible sidewalls than radial tires due to the fact that radial tires make use of two or more layers of casing piles and are thus not much flexible.
Also, tech B is correct because bias-ply tires typically have more durable construction than radial tires
Three charges of 2 nC, -5 nC, and 0.2 nC are situated at P(2, 7/2,"/4), S(1, π, "/2), and Q(5, "/3,2/3), respectively. Find the force acting on the 2 nC charge at point P. Is this a force of attraction or repulsion?
Answers
Answer:htthrhtrhtrrtrth
Explanation:
trtrhtr
_____ occur when warm, dry wind flows down a slope, whereas _____ occur when cold, dense air flows down a slope.
Answers
Chinook winds occur when warm, dry wind flows down a slope, whereas katabatic winds occur when cold, dense air flows down a slope.
What are Chinook winds?Chinook winds, sometimes known as 'Chinooks,' are two types of predominantly warm, mainly westerly winds in western North America: coastal Chinooks and inland Chinooks. The coastal Chinooks are rainy, southwesterly winds that come in from the ocean on a seasonal basis.
On the other hand, a katabatic wind is a draining wind, which transports high-density air from a higher height down a slope using gravity. Such winds are sometimes known as autumn winds; the term catabatic winds is often used.
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Prove that the center of pressure of a completely sub-merged plane surface is always below the center of gravity of the sub-merged surface or at most coincide with the center of gravity when the plane surface is horizontal.
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The location at which the joined forces of a pressure distribution on a wholly submerged plane surface counteracts is determined by its shape, orientation, and furthermore the pressure composition.
How to show this?To exemplify, when a plane surface displays an evenly distributed pressure around its center of gravity, then the center of pressure will be found beneath the center of gravity when the surface inclines.
Yet, if the same plane surface remains horizontal, the pressure arrangement will remain homogenous and thus the two centers merge. Generally speaking, the center of pressure stands below, or at most level with, the center of gravity when the plane surface is straight.
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Explain any five applications of computer modeling in beams.
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Answer:
Explain any five applications of computer modeling in beams.
Explanation:
2. A collection of "free" electrons in one place creates a(n)
OA. magnetic field
OB. conductance
OC. electrostatic force
OD. inverse voltage
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(1) What are the available methods for crop establishments in the field?
(2) Give a conceptual sketch for a seeder to establish soybean seeds in an
agricultural field of dry zone in Sri Lanka (Use software where
necessary/or a hand sketch with detail).
(3) Discuss the advantages of the seed dibbling mechanism and list the
crops that can be used dibbler.
A
(4) Discuss the key points to enhance agricultural productivity using the
fertilizer applicators.
(5) Calculations: Calibration of a seed drill
Number of furrows = 5
Spacing between the furrows = 8 cm
Diameter of the ground wheel = 0.65 m
Number of rotations of the ground wheel = 300
Weight of seed collected = 20 kg
Calculate the seed rate in kg/ha
The average number of seeds dropped per one revelation =6
Calculate the
(1) seed rate and
(ii)
hole to hole spacing
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Answer:
1) Therefore it was so much more than one answer my head