TIME SENSITIVE! please help !

Consider the word PENCIL. If all the letters are used, and the first letter can’t be N or L, how many ways can the letters be arranged?

A) 720

B) 480

C) 360

D) 96

The horizontal force exerted on the skater 1170 N.

The diameter of the semicircular portion of the track is 16 m.

Therefore its radius is

r = 8 m.

The tangential velocity of the skater is 12 m/s.

Therefore the angular speed is

ω = v/r = (12 m/s)/(8 m) = 1.5 rad/s

The horizontal force on the skater is due to centripetal acceleration of

a = r*ω² = (8 m)*(1.5 rad/s)² = 18 m/s².

The force acting on the 65-kg skater is

F = m*a = (65 kg)*(18 m/s²) = 1170 N

Therefore, the horizontal force exerted on the skater 1170 N. The correct answer is 1170 N.

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Answer: The distance between two points with coordinates

(9,-4),(-4,-1)  is:

9.85 units

(results are in decimal form, rounded to the nearest 100th)

Step-by-step explanation: hope this helps

Answer:

2.5 dB/100 ft

Explanation:

If 5 dB was lost after 200 ft of cable and 100 ft is half of 200 ft, then the rate of loss should be 2.5 dB per 100 ft.

Step-by-step explanation:

The total loss is 9 dB

Since we have 250 ft of cable that has a loss rate of 3.6 dB per 100 ft, we need to find the total loss of the 250 ft of cable.

To find this total loss, we multiply the loss rate by the total length of cable.

So, the total loss for the 250 ft of cable, L = loss rate × length of cable.

Since loss rate = 3.6 dB per 100 ft and the length of cable = 250 ft, substituting the values of the variables into the equation, we have

L = loss rate × length of cable.

L =  3.6 dB/100 ft × 250 ft.

L = 3.6 dB/10  × 25.

L = 3.6 × 25/10 dB

L = 3.6 × 2.5 dB

L = 9 dB

So, the total loss is 9 dB

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Answer:

\(( {7a}^{2} \times {a}^{4} ) + ({7a}^{2} \times {5a}^{3}) + ( {7a}^{2} \times 4) = {7a}^{6} + {35a}^{5} + {28a}^{2} \)

Answer: is not / is one x-value

Step-by-step explanation:

The relation is not a function because there is one x-value corresponding to multiple y-values.

For a function, each point on the domain is mapped into only one point on the range.

In this relation we can see the points:

(1, 4), (3, -1), (-1, -2), and (1, -3).

Then we can see that the element of the domain "1" is being mapped into two different elements of the range (4, and -3).

Then the relation is not a function because there is one x-value corresponding to multiple y-values.

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A function f such that f '(x) = 3x^3 and the line 81x + y = 0 is tangent to the graph of f is f(x) = 3x^4/4 + 729/4.

In the given question, we have to find a function f such that f'(x) = 3x^3 and the line 81x + y = 0 is tangent to the graph of f.

The given function is f'(x) = 3x^3.

No integrating on both side,

f(x) = \(\int3x^3dx\) + C

f(x) = 3x^4/4 + C

As given, the line 81x + y = 0 is tangent to the graph of f.

So, slope at point of tangent; f'(x) = -81

So, 3x^3 = -81

Divide by 3 on both side, we get

x^3 = -27

Taking cube root on both side, we get

x = -3

So putting the value of x in 81x + y = 0, we get

y = 243

Thus, f(x) passes through (-3, 243).

So, 243 = 3/4(81) + C

Multiply by 4 on both side, we get

972 = 243 + 4C

Subtract 243 on both side, we get

4C = 729

Divide by 4 on both side, we get

C = 729/4

So, f(x) = 3x^4/4 + 729/4

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0.1199 %  is the probability that at least four boys are chosen.

Definition of probability

Using the hypergeometric distribution, it is found that there is a 0.1199 = 11.99% probability that at least four boys are chosen.

The students are chosen without replacement, which is the reason why the hypergeometric distribution is used.

Hypergeometric distribution-

\(P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N - k, n-x } }{C_{N,n} }\)

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this problem:

16 + 19 = 35 students, thus N = 35

16 are boys, thus k = 16

Five are chosen, thus n = 5

The probability that at least four are boys is:

P(x ≥ 4 ) = P(X = 4 ) + P ( X = 5)

In which

P(X = x) = h(x ,N, n, k) = \(\frac{C_{k,x } C_{N - k , n-k} }{C_{N,n} }\)

\(P(x = 4) = h (4,35,5,16) = \frac{C_{16,4}C_{10,1} }{C_{35,5} } = 0.1065\)

\(P( X= 5 ) = h (5,35,5,16) = \frac{C_{16,5} C_{19,0} }{C_{35,5} } = 0.0134\)

Then-

P( X ≥ 4) = P(X = 4) + P( X = 5 ) = 0.1065 + 0.0134 = 0.1199

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An interval variable is a type of quantitative variable, where the difference between two values of the variable is meaningful and the values can be ordered.

Examples of interval variables include temperature (in Celsius or Fahrenheit), time (in seconds, minutes, hours, etc.), and dates. You can calculate the difference in temperature between two points, the length of time between two events, or the number of days between two dates. For example, let's say that the temperature outside is 25°C at noon and 29°C at 4 pm. The interval variable is the temperature, and the difference between the two temperatures is 4°C (29°C - 25°C = 4°C). Another example is the length of time between two events. Let's say that Event A began at 1 pm and Event B began at 2 pm. The interval variable is the length of time between the two events and the difference between the two times is 1 hour (2 pm - 1 pm = 1 hour). Finally, let's say that Date A is January 1, 2020 and Date B is January 10, 2020. The interval variable is the number of days between the two dates, and the difference between the two dates is 9 days (January 10,)An interval variable is a type of quantitative variable, where the difference between two values of the variable is meaningful and the values can be ordered.

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Inequality stating that there are 8000 sq. m. of land available: Let B be the number of units of house B and C be the number of units of house C.

Therefore,B+C ≤ 8000/200 [Reason: House C requires 200 sq. m. of land]⇒B+C ≤ 40b. Inequality that the engineer has at most 6400 man-hour available for construction:

160B + 256C ≤ 6400c

Inequality stating that the engineer has at least 12 million pesos to spend for materials:

600B + 800C ≤ 12000d

. Let us write down a table to calculate the cost, income and profit as follows:Units of house BLabor Hours per unit of house BUnits of house CLabor Hours per unit of house CTotal Labor HoursMaterial Cost per unit of house BMaterial Cost per unit of house CTotal Material CostIncome per unit of house BIncome per unit of house C

Total IncomeTotal ProfitBC=8000/200-B160CB+256C600000800000+256C12,000,0003,500,0004,000,0003,500,000B+C ≤ 40 160B + 256C ≤ 6400 600B + 800C ≤ 12000 Units of house B requires 160 man-hour and a unit of house C requires 256 man-hour.

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Answer:

7 lbs. or option B.

Step-by-step explanation:

To figure out how much the chairs weigh to then divide them, you first need to subtract 36 from 92.

92 - 36 = 56

Now, we have to divide 56 by the number of chairs we have because we need to find out how much a single chair weighs.

56 ÷ 8 = 7

So, each chair weighs 7 lbs.

Answer:

B) 7 lbs

Step-by-step explanation:

To find how much the chairs weigh, you must subtract 36 from 92.

92 - 36 = 56

We have to divide 56 by 8 or the number of chairs.

56 ÷ 8 = 7

B) 7 lbs

sixty-two thousandths ​ : 0.62

Answer :

The class that lost the most pencils overall based on the data displayed is D. Mr. Johnson's class; it has a wide spread in the data

The answer is Mr. Johnson's class. The median is the middle value in a set of data. In Mr. Johnson's class, the median is 11 pencils. This means that half of the students in his class lost 11 or fewer pencils, and half of the students lost 11 or more pencils.

In Mr. Simpson's class, the median is 14.5 pencils. This means that half of the students in his class lost 14.5 or fewer pencils, and half of the students lost 14.5 or more pencils.

Since the median for Mr. Johnson's class is lower than the median for Mr. Simpson's class, we can conclude that Mr. Johnson's class lost more pencils overall.

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Kindness is a fundamental virtue that fosters empathy, compassion, and understanding, leading to healthier and more harmonious relationships within society. It has the power to positively impact both the giver and the receiver, promoting a sense of connection and well-being. When we engage in acts of kindness, we not only contribute to the happiness and welfare of others but also experience a sense of fulfillment and purpose in our own lives.

In line with Friedman's assertion, finding meaning in our lives through providing value to others is crucial for experiencing life satisfaction. When we use our talents, skills, and resources to make a positive difference in the lives of others, it gives our existence a deeper sense of purpose and fulfillment. Knowing that our actions have a meaningful impact on others cultivates a sense of significance and contributes to our overall well-being.

By embracing kindness and finding meaning through helping others, we can create a more compassionate and fulfilling world. It is through acts of kindness and the pursuit of meaningful connections that we can find true happiness and fulfillment in our lives.

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Answer:

(-2,-4)

Step-by-step explanation:

Cant explain but its that one.

Answer:

\(3^{0} =1\)

Step-by-step explanation:

Answer:

\({:}\longrightarrow\)\(\sf 3x+y=-7 \)

\({:}\longrightarrow\)\(\sf y=-7-3x \)

\(\boxed{\begin{array}{|c|c|c|c|} x & 1 & (-1) & 0 \\ y & -10 & (-4) & -7 \end{array}}\)

Hence the intercepts are

\(\therefore\)\(\sf A (1,-10),B(-1,-4),C(0,-7)\)

Answer:

X=0

Step-by-step explanation:

Answer:

958.99

Step-by-step explanation:

Since the nine is bigger than four, you'd make the eight a nine.

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Answer:

28.27 m

Step-by-step explanation:

C=2πr

Answer:

28.26m

Step-by-step explanation:

C=2 3.14 r

2*3.14=6.28*4.5=28.26

Answer:

35 in total

Step-by-step explanation:

The slopes of perpendicular lines are opposite reciprocals

The true statement is that segments FG and HJ are perpendicular

The coordinates of the points are given as:

F = (3,1)

G = (5,2)

H = (2,4)

J = (1,6)

Start by calculating the slopes of FG and HJ using the following slope formula

\(m = \frac{y_2 -y_1}{x_2 -x_1}\)

So, we have:

\(FG = \frac{2 -1}{5 -3}\)

\(FG = \frac{1}{2}\)

Also, we have:

\(HJ = \frac{6 - 4}{1 - 2}\)

\(HJ = \frac{2}{-1}\)

\(HJ = -2\)

To determine the relationship, we make use of the following highlights

From the computation above, we have:

Hence, segment FG and HJ are perpendicular

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It would take approximately 9.4 years to triple your investment with a 14% return, assuming compound interest.

To determine how long it would take to triple your investment with a 14% return, we can use the compound interest formula

Future Value = Present Value × (1 + Interest Rate)ⁿ

In this case, the Future Value is three times the Present Value, the Interest Rate is 14% (or 0.14), and we want to solve for Time.

Let's denote the Present Value as P and the Time as n:

3P = P × (1 + 0.14)ⁿ

Now, we can simplify the equation:

3 = (1.14)ⁿ

To solve for n, we need to take the logarithm of both sides of the equation. Let's use the natural logarithm (ln) for this calculation:

ln(3) = ln((1.14)ⁿ)

Using the logarithmic property, we can bring down the exponent:

ln(3) = n × ln(1.14)

Now, we can solve for t by dividing both sides of the equation by ln(1.14):

n = ln(3) / ln(1.14)

we can find the value of t:

n ≈ 9.4

Therefore, it would take approximately 9.4 years to triple your investment with a 14% return, assuming compound interest.

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Answer:

B. Different of Squares

Step-by-step explanation:

Based on the text, the primary source of primate endangerment today is habitat destruction.

Habitat destruction is considered the primary source of primate endangerment based on various factors mentioned in the text. Primates, like many other species, heavily rely on their natural habitats for survival, including food, shelter, and breeding. However, human activities such as deforestation, urbanization, and land conversion for agriculture or infrastructure development have significantly reduced and fragmented primate habitats.

Habitat destruction leads to the loss of critical resources and disrupts the ecological balance necessary for primate populations to thrive. As their habitats shrink, primates face increased competition for limited resources, reduced access to food and water sources, and decreased opportunities for successful reproduction and rearing of offspring. This loss of habitat also exposes primates to increased vulnerability to predation, disease transmission, and human-wildlife conflicts.

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The correct answer is d. 1, 3. Both paralleling and bite-wing techniques use the same principles of horizontal angulation.

Horizontal angulation refers to the angle at which the X-ray beam is directed from the X-ray tube towards the film or sensor, perpendicular to the long axis of the teeth. Correct horizontal angulation is crucial for obtaining accurate and clear radiographic images.
In the paralleling technique, the film or sensor is placed parallel to the long axis of the teeth, and the X-ray beam is directed perpendicular to both the teeth and the film/sensor. This technique reduces distortion and provides a more accurate representation of the teeth and surrounding structures.
The bite-wing technique is primarily used for interproximal (between teeth) radiography, capturing images of the crowns of the upper and lower teeth and the alveolar bone in a single exposure. The film or sensor is placed in the mouth with a tab or holder, and the patient bites down to stabilize it. The X-ray beam is directed at the same horizontal angle as in the paralleling technique, ensuring proper alignment with the teeth and film/sensor.
Although the bisecting technique also involves angulation, it uses a different principle known as the bisector angle. In this method, the film or sensor is positioned closer to the teeth, and the X-ray beam is directed at an angle between the long axis of the teeth and the film/sensor, creating a theoretical bisector. This technique may result in some image distortion compared to the paralleling and bite-wing techniques.

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The techniques Paralleling, Bisecting, and Bite-wing all use the principles of horizontal angulation in Dentistry. This angulation refers to the direction of the x-ray beam, which is adjusted in each of these methods to produce the optimal dental image.

The techniques that use the principles of horizontal angulation are Paralleling, Bisecting, and Bite-wing. This means the correct answer is 1, 2, 3 (option a). Horizontal angulation refers to the angle in which the beam of the x-ray is projected. In Dentistry, it signifies the movement of the x-ray tube head in a horizontal plane. For all three techniques, the x-ray beam's angulation is adjusted horizontally in order to attain the desired image.

Paralleling technique requires the dental film, tooth, and x-ray beam to be parallel to each other. Bisecting involves angulating the x-ray beam to correctly intercept the angle formed by the film and tooth. Bite-wing method also uses horizontal angulation by aligning the x-ray beam perpendicular to the curvature of the arch and the film.

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Answer: X = 16

Step-by-step explanation:

so 6^(X-4) = 6^12

X = ?

we can rewrite it as X - 4 = 12 since the bases are the same

now solve for X

X = 12 + 4

X = 16

The z-score for a raw score of 6 is 0.5.A z-score indicates how many standard deviations a raw score is away from the mean.

To calculate the z-score for a raw score of 6 given a mean of 4 and a standard deviation of 4, we can use the formula:

z = (raw score - mean) / standard deviation

Substituting the values into the formula, we get:

z = (6 - 4) / 4

z = 0.5

Therefore, the z-score for a raw score of 6 is 0.5.

In this case, a z-score of 0.5 indicates that the raw score of 6 is half a standard deviation above the mean of 4.

Z-scores are useful because they allow us to compare scores from different distributions. For example, if we have two sets of data with different means and standard deviations, we can convert them into z-scores to compare them directly. A positive z-score means that the raw score is above the mean, while a negative z-score means that the raw score is below the mean. The magnitude of the z-score indicates how far the raw score is from the mean in terms of standard deviations.

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The ticket price that would maximize revenue is $3.70.

Let's first determine the equation of the line that represents this relationship. We can use the point-slope form of a linear equation:

y - y₁ = m(x - x₁)

Where:

   • y is the attendance

   • x is the ticket price

   • (x₁, y₁) is a point on the line

Using the given information, we can choose two points on the line: (12, 9,200) and (11, 11,200).

Using the point-slope form, we have:

9200 - y₁ = m(12 - x₁) ...(1) 11200 - y₁ = m(11 - x₁) ...(2)

Now, let's solve these two equations simultaneously to find the values of m and y₁:

9200 - y₁ = m(12 - x₁) 11200 - y₁ = m(11 - x₁)

Rearranging equation (1), we get: 9200 - y₁ = 12m - mx₁ ...(3)

Rearranging equation (2), we get: 11200 - y₁ = 11m - mx₁ ...(4)

By subtracting equation (3) from equation (4), we can eliminate y₁ and find the value of m:

11200 - y₁ - (9200 - y₁) = 11m - mx₁ - (12m - mx₁) 2000 = -m

Dividing both sides by -1, we have: m = -2000

Now, substituting the value of m into equation (3), we can solve for y₁:

9200 - y₁ = 12(-2000) - (-2000x₁)

9200 - y₁ = -24000 + 2000x₁

y₁ = 2000x₁ - 14800 ...(5)

Equation (5) represents the linear relationship between attendance (y) and ticket price (x).

To find the ticket price that maximizes revenue, we need to consider the revenue formula:

Revenue = Ticket Price × Attendance

Let's denote revenue as R. Substituting the value of attendance (y) from equation (5), we have:

R = x(2000x₁ - 14800) R = 2000x² - 14800x ...(6)

Equation (6) represents the revenue as a function of ticket price. To find the maximum revenue, we can use various techniques like differentiation or graph plotting. Let's use differentiation here.

Differentiating equation (6) with respect to x, we get:

dR/dx = 4000x - 14800

To find the maximum revenue, we set dR/dx equal to zero:

4000x - 14800 = 0

Solving for x, we find:

4000x = 14800 x = 3.7

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Answer:

Step-by-step explanation:

Look at the image