Through which medium would sound travel FASTEST?
A) the air in your home
B) shouting underwater in a swimming pool
C) the air outside your home in July
D) or banana pudding

The distance from the center of the sphere where the electric field has the same magnitude as it has at P is approximately 0.0858 m.

The electric field is directly proportional to the electric charge. According to the Gauss’s Law, the electric field inside a spherical non-conducting shell is zero. Therefore, the electric field only depends on the electric charge enclosed by the spherical region and the distance from the center of the sphere.

The charge enclosed by a spherical region of radius r is q = (4/3)πεr³ρ, where ε is the permittivity of free space and ρ is the charge density.

Here, the electric charge is uniformly distributed inside a non-conducting sphere of radius r = 0.3 m.Thus, the charge enclosed by the spherical region of radius 0.6 m isq

= (4/3)πε(0.6)³ρ= 0.0415ρFrom Coulomb's law,

E = kq/r²Here, k is the Coulomb constant and r is the distance from the center of the sphere.

Therefore, the distance from the center of the sphere where the electric field has the same magnitude as it has at P is:

r² = kq/EFrom the given data,E = 5000 N/CThe value of k = 9 × 10⁹ Nm²/C²Thus,r² = (9 × 10⁹ × 0.0415ρ)/(5000 N/C)r² = 7.38 × 10⁻⁶ ρm²r = (7.38 × 10⁻⁶ ρm²)¹/²r = 0.0858 m (approx).

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Answer:

Below

Explanation:

If they are all in parallel, the quivalent resistance is given by

            1                     =    3.6 Ω

  1/R1   + 1/R2  + 1/R3

The rate at which work is completed is indicated by the power word, hence option b is correct. Power, which can be defined as the amount of work done W.

Is the time rate at which the job is completed or energy is given. Energy transferred, expressed as W/t or energy transferred against the time interval t. Work (or energy) per unit time, foot-pounds per minute, joules per second (or watts), and ergs per second are all ways to express power. Work is defined as involving both force applied to the body and displacement of the body. Consider a block that is resting on a horizontal, frictionless floor. A consistent force is acting on this block.

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Answer:  B.) power

Explanation: Get dem hearts up:)

"Yes, the electronic crime scene is handled completely differently from a traditional crime scene. The electronic crime scene refers to a crime that has taken place in the digital world.

In contrast, a traditional crime scene refers to a crime that has taken place in the physical world, and it is evident that the two scenarios are handled differently.

An electronic crime scene refers to the area or place where electronic evidence is gathered for use in investigations or legal proceedings. Electronic evidence refers to information or data stored, created, or transmitted in electronic devices, including computers, smartphones, flash drives, and other digital devices. The collection of electronic evidence differs significantly from the collection of traditional evidence. The first step is the preservation of electronic evidence. In a traditional crime scene, it is possible to cordon off the area using yellow tapes, close windows, and take photographs of the scene. However, this is not the case with an electronic crime scene since electronic evidence is intangible. This is why digital forensic investigators begin the evidence preservation process by creating a forensic image of the electronic device under investigation. This is done to prevent data loss or alteration before investigations commence.

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Explanation:

Energy can be converted from one form to another. Examples: Gasoline (chemical) is put into our cars, and with the help of electrical energy from a battery, provides mechanical (kinetic) energy. ... Similarly, purchased electricity goes into an electric bulb and is converted to visible light and heat energy.

Answer:

Explanation:

Energy transformation is when energy changes from one form to another.  While energy can be transferred or transformed, the total amount of energy does not change – this is called energy conservation. For example, Electricity goes into an electric bulb and is converted to visible light and heat energy.

Hope this helped!!!

Explanation:

3. A person who is initially stationary is eventually walking

at a speed of 1.5 m/s after an acceleration of 0.5 m/s?,

calculate the distance it takes them to reach this speed.

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 1.5m/s

Acceleration = 0.5m/s

Unknown:

Distance  = ?

Solution:

To solve this problem, we apply the relevant motion equation;

    V² = U² + 2aS

where V is the final velocity

          U is the initial velocity

          a is the acceleration

         S is the distance

Input the parameters;

     1.5² = 0 + 2 x 0.5 x S

    2.25= S

The distance to reach this speed is 2.25m

4. A lorry pulls forward after initially being stationary, it

takes the lorry 40 m to reach a speed of 8 m/s, calculate the

lorry's acceleration.

Given parameters:

   Initial velocity = 0m/s

   Final velocity  = 8m/s

   Distance  = 40m

Unknown:

Acceleration = ?

Solution:

    V² = U² + 2aS

Input the parameters and solve;

  8² = 0² + 2 x a x 40

   64 = 80a

      a = \(\frac{64}{80}\)  = 0.8m/s²

7. A person begins moving after initially being stationary, the person

accelerates at 0.5m/s2 over a distance of 9m what is their final speed

    Given parameters:

    Initial velocity  = 0m/s

    acceleration  = 0.5m/s²

     distance  = 9m

Unknown:

Final velocity  = ?

Solution:

     V² = U² + 2aS

Input the parameters and solve;

   V² = 0² + 3 x 0.5 x 9

    V² = 13.5

    V  = 3.7m/s

The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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Answer: The magnification of the image is 0.50. This means the image is half the size of the object.

Explanation:

The magnification (m) of an image produced by a mirror is given by the ratio of the image distance (di) to the object distance (do). The formula is:

\($$m = -\frac{di}{do}$$\)

In this case, the object distance (do) is 18 cm and the image distance (di) is -9 cm (the negative sign indicates that the image is virtual and located behind the mirror). Substituting these values into the formula, we can calculate the magnification.

The magnification of the image is 0.50. This means the image is half the size of the object.

The horizontal force required for an acceleration of 2.0 m/s² is equal to 54.3 N.

The force of kinetic friction is a type of frictions that acts on a moving object on a surface. In order to calculate the force of kinetic friction, we use the formula F = μN where F is the force of kinetic friction, μ is the coefficient of the kinetic friction, and N is the normal force. However, we need to take into account the force along the x-axis. Therefore, the formula ∑F = μN + ma will help us find the horizontal force.

Let ∑F represent the net force, N represent the normal force, m represent the mass of the box, g represent the acceleration of gravity, µ represent the kinetic friction, and a represent an acceleration of 2 m/s².

∑F = µN + ma

∑F = µmg + ma

∑F = m (µg + a)

∑F = 10 kg (0.35 × 9.8 m/s² + 2 m/s²)

∑F = 10 kg (3.43 m/s² + 2 m/s²)

∑F = 10 kg (5.43 m/s²)

∑F = 54.3 kg × m/s²

∑F = 54.3 N

The net force is equal to 54.3 N. That is the horizontal force required!

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The tangential speed on the outer edge of a rotating carousel is dependent on the carousel's rotational speed and the distance from the center of rotation to the outer edge.

It can be calculated using the formula: tangential speed = radius × angular speed

Where the radius is the distance from the center of rotation to the outer edge, and the angular speed is the rate of rotation measured in radians per second.

The carousel's rotational speed of a carousel refers to the rate at which it completes one full revolution, and it is usually measured in units of revolutions per minute (RPM) or radians per second (rad/s). The faster the carousel rotates, the higher the outer edge's tangential speed. The rotational speed of a carousel can be controlled by adjusting the power source that drives it, such as an electric motor.

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mass of the potassium formed by the passage of 5.92 amps for 1.94 hours through an electrolytic cell that contains a molten potassium salt is 16.41g

Total amount of current in amps = 5.92 Columbus/ sec(I)

total time period = 1.94 h = 1.94 X 3600 sec = 6984 sec(t)

initially electric charge Q is calculated  Q =I X t =41,345.28 Columbus

now molar mass of K is 39.09g/mol and faradays constant = 96485 so by the formula , n=Q/F = 41,345.28/96485 =0.4285mol  now, m = nM where n is number of mol and M is molar mass of K  so 0.42 X 39.09=16.41g

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The rock will take 3.5 seconds to reach the bottom when dropped off a 60 m high cliff. Therefore, option (C) is correct.

The equations of motion are equations that are used to describe the motion of an object as a function of time. These equations apply to an object moving linearly in a straight line with uniform acceleration.

The three equations of motion are represented as:

\(v = u+at\)

\(S= ut +\frac{1}{2} at^2\)

\(v^2= u^2+2aS\)

The initial velocity of the rock, u = 0

The acceleration of the rock, a= g = 9.8m/s²

The height that rock travel, S = 60m

From the equation of motion calculate the final velocity of the rock:

v² = (0)² + 2 ×9.8×60

v² = 1176

v = 34.29 m/s

From the equation of motion, calculate the time takes the rock to reach the bottom:

v = u+at

34.29 = (0) + (9.8) (t)

t = 3.5 sec

Therefore, the rock will take 3.5 seconds to reach the bottom.

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Answer:

As altitude increases, the amount of gas molecules in the air decreases—the air becomes less dense than air nearer to sea level. This is what meteorologists and mountaineers mean by "thin air." Thin air exerts less pressure than air at a lower altitude

Explanation:

To convert from scientific notation to decimal, move the decimal point 5 places to the left.

5.93×10⁻⁵ = 0.0000593

The magnitude of the motional emf in the rod is 0.1872 when an isolated conducting rod of length 8.00 cm is oriented parallel to the x-axis. The speed of rod in y-direction is 3.90m/s.

Given an isolated conducting rod of length (l) = 8.00 cm = 8x10-2m

it moves in the y-direction at (v) = 3.90 m/s

uniform magnetic field of magnitude (B)= 0.600T

Let the magnitude of the motional emf in the rod be E

We know that E = BxlxV

E = 0.600T x 3.90m/s x 8x10-2m = 18.72x10-2

Hence the magnitude of the motional emf in the rod is 0.1872

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Answer:Force=500

Explanation:

Because it say "the downward force of atmosphere" we use ATP

ATP=100kpa

area=0.05m2

F=ATP × area

 100,000pa×0.05m2 =5000N

If a musical note has a frequency of 212 Hz and a wavelength of 425 m, its velocity is 90.1 m/s.

The speed of sound is a relationship between frequency and wavelength, mathematically represented as follows:

speed = frequency x wavelength

In this case, the frequency is 212 Hz and the wavelength is 0.425 m. Plugging these values into the equation gives:

speed = frequency x wavelength

speed = 212 Hz x 0.425 m

speed = 90.1 m/s

Therefore, we can affirm that the the speed of the sound of the musical note is 90.1 m/s.

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Centrifugal force is the fictitious force perceived during a circular motion, while centripetal force is the force imposed on the body.

A fictitious force that moves in a circle and is directed away from the centre of the circle is called centrifugal force. When measurements are taken in an inertial frame of reference, the force does not exist. It only becomes relevant when we go from a ground/inertial reference frame to a spinning reference frame.

The component of force applied on an object in curvilinear motion that is pointed in the direction of the axis of rotation or the centre of curvature is known as the centripetal force.

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Answer:

Explanation:

W = FΔx so filling in:

12 = F(30) so

F = .4N

Answer:

Gravity

Explanation:

Gravity, also called gravitation, in mechanics, the universal force of attraction acting between all

Answer:

The bronchioles function is to deliver air to tiny sacs called alveoli where oxygen and carbon dioxide are exchanged.

Explanation:

Bronchioles are air passages inside the lungs that branch off like tree limbs from the bronchi—the two main air passages into which air flows from the trachea (windpipe) after being inhaled through the nose or mouth. The bronchioles deliver air to tiny sacs called alveoli where oxygen and carbon dioxide are exchanged.

Given:

The mass of the ball is 2.5 kg

The initial potential energy is 32 J.

To find the potential energy before it hits the ground.

Explanation:

The potential energy can be calculated as

Answer:

Energy=3.1times 10^-17 J

Rest mass: 6.2 kg

Speed: 47.5 m/s

Wavelength: 2.659 times 10^-6

Momentum: 67.3 kg(m/s)

Explanation:

Answer:

First blank:

reflected

Second blank:

absorbed

third blank:

Transparent

fourth blank:

transmitted

fifth blank:

light

sixth blank:

optic

seventh blank:

path

eighth blank:

frequency

Explanation:

If the actual mass density of the universe is greater than the critical density and there is no dark energy, the universe would undergo a specific fate known as a closed universe or a "Big Crunch."

In a closed universe, the gravitational attraction between matter would eventually overcome the expansion of the universe, causing it to contract.

As the contraction progresses, the universe would become denser and hotter, eventually leading to the collapse and ultimate destruction of all matter and energy in a cosmic singularity.

This scenario is analogous to the reverse of the Big Bang, where the universe was extremely hot and dense at its inception.

In a closed universe without dark energy, the cosmic expansion would eventually reverse, leading to a contraction phase.

This outcome is contingent on the absence of a repulsive force (dark energy) that is currently believed to be responsible for the accelerated expansion of the universe.

It is important to note that current observational evidence supports the presence of dark energy, which suggests that the universe is undergoing accelerated expansion and a different fate is anticipated.

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Explanation:

you have to divide by 2 and times by 2

Answer:

Given the information in the velocity vs. time graph, what is the displacement of the object after 1 second?

3m

After 3 seconds?

9m

After 5 seconds?

15m

Explanation:

The displacement of the object after 1-second would be 3 m, the displacement of the object after 3 seconds would be 9 m, and the displacement of the object after 5 seconds would be 15 sec

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second.

The mathematical relation between displacement and  velocity is given by

Total displacement=Total time×velocity

As given in the problem A velocity-time graph is shown, displaying the behavior

Velocity from the velocity time graph

velocity =3 m/s

As we know  the area under the velocity time curve represents the displacement covered by the object

displacement of the object after 1-second = 3×1

                                                                      = 3 m

displacement of the object after 3-second = 3×3

                                                                      =  9 m

displacement of the object after 5-second = 3×5

                                                                      =  15 m

Thus, The displacement of the object after one second, three seconds, and five seconds would be three meters, nine meters, and fifteen meters, respectively.

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Answer:D

Explanation:

It was right o khan academy

A dog jumps 0.80 M to catch a treat. The dog's displacement vector is shown below.

Which diagram shows the vertical and horizontal components of the dog's displacement?

THE ANSWER IS IN THE ATTACHMENT!