three resistors with values of 5 ohms, 7 ohms, and 9 ohms are connected in parallel to a 12v battery. what is the equivalent resistance of the circuit? sketch the circuit.

The density of a metal block having a mass of 10 cg and sides equaling 10, 15, and 20 centimeters is 3.33 × 10-⁵g/cm³.

The density of a substance can be calculated by dividing the mass of the substance by its volume.

That is;

Density = mass ÷ volume

According to this question, a metal block has a mass of 10 cg and sides equaling 10, 15, and 20 centimeters.

Volume of the metal block = 15 × 20 × 10 = 3000cm³

Mass of metal block in grams = 0.1g

Density of metal block = 0.1g ÷ 3000cm³

Density = 3.33 × 10-⁵g/cm³

Therefore, the density of a metal block having a mass of 10 cg and sides equaling 10, 15, and 20 centimeters is 3.33 × 10-⁵g/cm³.

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Answer:

D)evaluating a solution

Explanation:

In this scenario, the next logical step would be evaluating a solution. This is because Jasper and Samantha have already identified the problem/need which is that the robot needs to be able to move a 10-gram weight at least 2 meters and turn in a circle. They also designed and implemented a solution because they have already built the robot. Therefore the only step missing is to evaluate and make sure that the robot they built is able to complete the requirements.

The sample will move very slowly in the opposite direction of the applied magnetic field, but it will eventually come to a stop when it reaches equilibrium.

Diamagnetic materials, unlike ferromagnetic or paramagnetic materials, do not possess any permanent magnetic moment or net magnetic dipole moment. The magnetic force acting on the diamagnetic material is perpendicular to its velocity, and hence it cannot accelerate the material along the direction of the magnetic field.

Since the sample is made of diamagnetic material, it will have a very weak and temporary magnetic moment induced in it when placed in a magnetic field. This induced magnetic moment will be in the opposite direction to the applied magnetic field. Therefore, the sample will experience a force in the direction opposite to the applied magnetic field. However, this force will be very weak since the diamagnetic material has a weak magnetic susceptibility.

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Answer:

I think it's this A resource that is replenished at a rate slower than it is used

Any resource that exists in finite quantities (there is only a certain amount)

Answer:

A resource that is difficult to recover.

Answer:

Popular graph types include line graphs, bar graphs, pie charts, scatter plots and histograms. Graphs are a great way to visualize data and display statistics. For example, a bar graph or chart is used to display numerical data that is independent of one another.

Graphs are a useful tool for scientists to visualize and compare different measurements. Here are some examples of measurements that scientists can compare using graphs: Time-series data, Relationships between variables, Proportions, Distribution of data and Comparing groups.

Before the establishment of contemporary scientific fields, the responsibilities of "scientists" and their forerunners underwent significant change over time. The social norms, ethical principles, and epistemic virtues that have been associated with scientists—and what has been expected of them—over time have also changed. This is true of scientists of different eras as well as of the natural philosophers, mathematicians, historians, theologians, and engineers who preceded them and contributed to the development of science. Consequently, depending on whatever aspects of contemporary science are seen to be crucial, a wide range of historical personalities might be classified as early scientists.

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Electric field intensity

\(\\ \tt\hookrightarrow \dfrac{V}{l}\)

\(\\ \tt\hookrightarrow \dfrac{100}{l}\)

\(\\ \tt\hookrightarrow 100N/C\)

The electric field intensity across the wire depends upon the voltage and its length. The electric field intensity across the wire is 100 V/m.

The electric field intensity is defined as the force experienced by the unit positive charge placed at that point.

Given that the voltage is 100 V. If the length of the wire is 1m, then the electric field intensity across the wire is given as below.

\(E = \dfrac {V}{d}\)

Where E is the electric field intensity, V is the voltage across the wire and d is the length of the wire.

\(E = \dfrac {100}{1}\)

\(E = 100 \;\rm V/m\)

Hence we can conclude that the electric field intensity across the wire is 100 V/m.

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Astronomers use rotation curves to measure the masses of individual spiral galaxies based on the speed at which stars orbit the galactic center.

The original assumption that all matter interacts with electromagnetic radiation was proven incorrect for the Milky Way galaxy. To further understand the behavior of matter in other galaxies, scientists are now focused on investigating whether this assumption still holds true in different galactic contexts. To accomplish this, they require a method to calculate the masses of individual galaxies and galaxy clusters, which can then be compared with the observed luminous matter.

Astronomers utilize rotation curves as a means to determine the masses of spiral galaxies. These curves provide insights into the speed at which stars orbit around the central region of a galaxy. The underlying principle is that the more mass there is between the stars and the galactic center, the faster the stars will orbit. By analyzing these rotation curves, scientists can estimate the amount of mass present within the galaxy, including both visible matter and potential invisible components such as dark matter.

This approach allows researchers to study the distribution of mass within galaxies and evaluate whether the observed luminous matter alone can account for the gravitational forces that govern the observed motions. By comparing the calculated masses derived from the rotation curves with the masses inferred from the observed luminosity, scientists can gain valuable insights into the existence and properties of dark matter in galaxies.

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With a mass of 540 kg and a height of 20 m at the starting position, the maximum potential energy of the coaster is 105,840 Joules.

To calculate the maximum potential energy of the coaster, we need to determine the height at which the maximum potential energy occurs. Given the positions:

- Starting position: 20 m

- Displacement: 15 m

- End position: 10 m

The maximum potential energy of the coaster will be at the starting position since it has the highest height among the given locations.

To calculate the potential energy, we can use the formula:

Potential Energy (PE) = mass (m) * acceleration due to gravity (g) * height (h)

Given:

Mass of the coaster (m) = 540 kg

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 20 m

Substituting the values into the formula, we can calculate the maximum potential energy:

PE = 540 kg * 9.8 m/s² * 20 m

PE = 105,840 J (Joules)

Please note that potential energy depends on the height and not on the displacement or the end position. In this case, the starting position, with a height of 20 m, corresponds to the location with the maximum potential energy.

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Answer:

6 seconds

Explanation:

\(d=v_ot+\dfrac{1}{2}at^2\)

Since the object is being dropped out of the window, it has no initial velocity.

\(176.4=\dfrac{1}{2}(9.8)t^2 \\\\t^2=36 \\\\t=6\text{ seconds}\)

Hope this helps!

Answer:

6 seconds

Explanation:

The formula for free fall is:

h = 1/2gt^2

We know that the height is 176.4 meters. We also know that on Earth, gravity is 9.8 m/s^2.

h=176.4

g=9.8

Substitute these values into the formula.

176.4=1/2(9.8)*t^2

Multiply 9.8 and 1/2

176.4=4.9*t^2

t^2 and 4.9 are being multiplied. The opposite of multiplication is division. Divide both sides by 4.9

176.4/4.9=4.9*t^2/4.9

176.4/4.9=t^2

36=t^2

t is being squared. The opposite of squared is the square root. Take the square root of both sides.

√36=√t^2

√36=t

6=t

t=6 seconds

It will take 6 seconds for the object to fall 176.4 meters.

The distance to Vega is ( 25.05 ) light years or ( 147,257,919,657,004 ) miles. Therefore, the number of miles to Vega in scientific notation with only 3 significant figures is ( 1.47₆ 10¹⁴ ).

To write the number of miles to Vega in scientific notation with only 3 significant figures, we can use the following steps:

Write the number in scientific notation with all significant figures: ( 1.47257919657004 \times 10¹⁴ ).

Round the number to 3 significant figures: ( 1.47 \times 10¹⁴ ).

Therefore, the number of miles to Vega in scientific notation with only 3 significant figures is ( 1.47₆ 10¹⁴ ).

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The main differences between sound waves and light waves are their medium of propagation, speed of propagation, and nature of interaction. Sound waves require a medium and travel at slower speeds compared to light waves.

Medium of Propagation:

Sound waves require a medium, such as air, water, or solids, to propagate. They are mechanical waves that travel through the vibration of particles in the medium. On the other hand, light waves can propagate through vacuum or empty space and do not require a medium. They are electromagnetic waves that consist of oscillating electric and magnetic fields.

Speed of Propagation:

Sound waves travel at a much slower speed compared to light waves. The speed of sound depends on the medium it travels through, with an approximate speed of 343 meters per second (m/s) in air at room temperature. In contrast, light waves travel at a constant speed of approximately 299,792,458 meters per second (m/s) in a vacuum, which is often rounded to 3.00 x 10^8 m/s for simplicity.

Nature of Interaction:

Sound waves interact differently with objects compared to light waves. Sound waves can be diffracted, reflected, refracted, and absorbed by objects in their path. They can bend around obstacles and travel through materials of different densities. In contrast, light waves can exhibit properties such as reflection, refraction, diffraction, interference, and polarization. They can be reflected off surfaces, refracted through lenses, diffracted around edges, and exhibit interference patterns.

Medium of Propagation:

Sound waves require a medium for their propagation because they rely on the mechanical vibrations of particles in the medium to transmit energy. When an object vibrates, it compresses and rarefies the surrounding particles, creating regions of higher and lower pressure. These pressure variations travel through the medium as a wave. For example, in air, sound waves propagate as compression waves, where particles compress together in regions of high pressure and spread apart in regions of low pressure.

Light waves, on the other hand, are electromagnetic waves that consist of oscillating electric and magnetic fields. They do not require a medium to propagate because the electric and magnetic fields can self-sustain and travel through empty space. This property allows light waves to travel through vacuum, making them capable of reaching us from distant stars and galaxies.

The main differences between sound waves and light waves are their medium of propagation, speed of propagation, and nature of interaction. Sound waves require a medium and travel at slower speeds compared to light waves. They interact differently with objects, while light waves exhibit properties such as reflection, refraction, diffraction, interference, and polarization. These distinctions arise from the fundamental differences in the nature of sound waves as mechanical waves and light waves as electromagnetic waves.

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Answer:

The answer is A and C.

Explanation:

Only two factors are relevant when dealing with the gravitational force between two objects - their mass and their distance apart from one another. Gravity's force is proportional to the product of the masses of the two objects and is inversely proportional to the square of the distance between them.

Answer:

C. 2m to the right of the rollerblader

Explanation:

The turtle is 2m to the LEFT of the rollerblader, so its the only option not describing the position of the turtle:)

Hope this helps, have a great day;)

Answer:

Protostars

Explanation:

Answer:

c

Explanation:

Answer:

1200J

Explanation:

m=3,h=40 while g= 10m/s^2

P.E=mgh

= 3 x 40 x10

=1200J

The point on the x-axis where the electric field is zero is 1.6667 * C / r1² = C / r2².

We would need additional information such as the distances of the charges from the point on the x-axis.  We cannot determine the exact point on the x-axis where the electric field is zero.

To find the point on the x-axis where the electric field is equal to zero, we need to consider the electric fields created by each charge individually and then determine the point where the net electric field cancels out.

Let's calculate the electric field created by each charge separately using Coulomb's law:

For the charge at the origin:

E1 = k * |q1| / r1²

For the charge on the x-axis at x = 1.00 m:

E2 = k * |q2| / r2²

where:

E1 and E2 are the electric fields created by the charges q1 and q2, respectively

k is the electrostatic constant (k ≈ 9 × 10⁹ N m²/C²)

|q1| and |q2| are the magnitudes of the charges

r1 and r2 are the distances from the charges to the point on the x-axis where we want to find the electric field

To cancel out the net electric field, the magnitudes of E1 and E2 must be equal. Therefore, we can set up the equation:

E1 = E2

k * |q1| / r1² = k * |q2| / r2²

Substituting the given values:

15x10⁻⁶ C / r1² = 9x10⁻⁶ C / r2²

1.6667 * C / r1² = C / r2²

To find the point on the x-axis where the electric field is zero, we need to find the values of r1 and r2 that satisfy this equation.

However, we don't have enough information to determine the specific values of r1 and r2 from the given information. We would need additional information such as the distances of the charges from the point on the x-axis.

Therefore, without further information, we cannot determine the exact point on the x-axis where the electric field is zero.

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Answer:

Below

Explanation:

Possibly.... it would depend on the weights of the vehicles and the coefficient of static friction of each of the configurations for the vehicles .

Different tires have different coeff static friction

When a lens is masked so that light can pass through only the bottom half of the lens, the image formed will be distorted compared to the image formed before masking.

The image formed by the lens is a result of the bending of light by the lens, which is known as refraction. The amount of bending of light depends on the curvature of the lens and the wavelength of the light. When the lens is masked so that only the bottom half of the lens is allowed to pass light, the top half of the lens is not able to refract light. Therefore, the image formed by the lens will bez distorted, as the light passing through the bottom half of the lens will be bent differently than the light passing through the top half of the lens. Additionally, the image formed will be dimmer because only half of the lens is available to form the image. In general, masking a lens in such a way that not all of it is allowed to pass light will result in a distorted and or dimmer image.

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Answer:

87kg

Explanation:

2244.6kg divided by 25.8 m = 87 kg

Answer:

87kg

Explanation:

momentum formula= p=mv

rearrange the formula ==> m=p/v

2244.6/25.8= 87kg

a) The tangential speed of the ball is 1.26 m/s

b) The centripetal acceleration of the ball is 1.99 m/s^2.

We need to use the formulas for tangential speed and centripetal acceleration:

Tangential speed = radius x angular speed

Centripetal acceleration = (tangential speed)^2 / radius

Given:

Mass of the ball, m = 5.00 kg

Radius of the circle, r = 0.800 m

Angular speed, ω = 0.500 rev/s

We need to convert the angular speed from revolutions per second to radians per second:

ω = 0.500 rev/s x 2π rad/rev = 1.57 rad/s

(a) Tangential speed of the ball:

v = rω = 0.800 m x 1.57 rad/s = 1.26 m/s

(b) Centripetal acceleration of the ball:

a = v^2 / r = (1.26 m/s)^2 / 0.800 m = 1.99 m/s^2

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Answer:

C

Explanation:

because cooling down makes your blood flow through your body much easier and fatser.

Answer:

C.It keeps your blood flowing evenly.

Explanation:

Answer:

3 meters

Explanation:

Velocity = displacement/time

Displacement=velocity×time

As, time from 7 to 8 is 1 sec. And velocity increases from 0 to 3 m/s

So, Displacement = 3×1

=3m

Please give me brainlist.

The image is located 1.43 cm behind the concave mirror when the object is moved to a distance of 15 cm from the mirror.

To solve this problem, we can use the mirror formula:

1/f = 1/do + 1/di

where f is the focal length of the mirror, do is the object distance, and di is the image distance.

We know that the mirror is concave, so its focal length is negative.  We also know that the image produced is virtual, so di is negative.

Using the given information for the first case:

do = 6 cm

di = -7.5 cm

f = ?

1/f = 1/do + 1/di

1/f = 1/6 + (-1/7.5)

1/f = -0.0333

f = -30 cm

Now, we can use the mirror formula again to find the image distance when the object is moved to a new position:

do = 15 cm

di = ?

f = -30 cm

1/f = 1/do + 1/di

1/-30 = 1/15 + 1/di

-1/30 = 1/di - 1/15

-1/30 = (15 - di)/15di

di(-1/30) = (15 - di)/15

-1.5 + 0.05di = di

1.05di = 1.5

di = 1.43 cm

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Answer:

Speed, V = 4.95m/s

Explanation:

Given the following data;

Mass, M1 = 14.7kg

Mass, M2 = 3.2kg

Velocity, V1 = 6.7m/s

Velocity, V2 = 3.1m/s

To find the final speed;

Mathematically, inelastic collision is given by the formula;

\( V = \frac{(M_{1}V_{1}+M_{2}V_{2})}{(M_{1}+M_{2})}\)

Where;

V is the final velocity in m/s.

M1 is the mass of the first object in kgs.

M2 is the mass of the second object in kgs.

V1 is the initial velocity of the first object in m/s.

V2 is the initial velocity of the second object in m/s.

Substituting into the equation, we have;

\( V = \frac{(14.7*6.7) - (3.2*3.1)}{14.7 + 3.2}\)

\( V = \frac{98.49 - 9.92}{17.9}\)

\( V = \frac{88.57}{17.9}\)

Speed, V = 4.95m/s

The value of ax is |a| and the value of ay is 0. These values make sense.

To reshape the vector so that it is completely horizontal and starts at the point (0,0), we can use the following equation:

|a|cos(θ) = ax
|a|sin(θ) = ay

Since the vector is horizontal and starts at (0,0), this means that the angle θ is 0 degrees. We also know that |a| is the magnitude of the vector. So, we have:
ax = |a|cos(0) = |a|
ay = |a|sin(0) = 0
θ = 0 degrees
|a| = magnitude of the vector

These values make sense, since the x-component of the vector is |a|, and the y-component is 0, which is what we would expect when the vector is horizontal.

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Answer:

I think it is 50 j, I am not sure and also please let me know if I am wrong.

Answer: hey

Explanation:

We can contrast distant galaxies with nearby galaxies.

Although scientists are unsure of the universe's actual age, we estimate that it is somewhere between 13 and 14 billion years old. In order to determine the age of the universe, astronomers use two different methods: (a) searching for the earliest stars; and (b) measuring the universe's rate of expansion and projecting it back to the Big Bang.

The amount of time it took for the galaxies to get to their current distances is therefore t=D/v. However, we know that v=H0D because to Hubble's Law. Therefore, t=D/v=D/(H0D)=1/H0. Thus, 1/H0 can be used as a rough estimate for the  age of the Universe.

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The magnitude of the vector with components -14.0 units in the x-direction and 5 units in the y-direction can be calculated using the Pythagorean theorem.

The magnitude of a vector represents its length or size. In the xy plane, the magnitude of a vector with components in the x-direction (horizontal) and y-direction (vertical) can be found using the Pythagorean theorem. The theorem states that the square of the magnitude of a vector is equal to the sum of the squares of its components.

For the given vector with components -14.0 units in the x-direction and 5 units in the y-direction, we can calculate its magnitude as follows:

Magnitude = sqrt(\(14^{2} } +5^{2}\))

Magnitude = sqrt(196 + 25)

Magnitude = sqrt(221)

Magnitude ≈ 14.87 units

Therefore, the magnitude of the vector is approximately 14.87 units. This represents the length or size of the vector in the xy plane, taking into account its components in the x and y directions.

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