Three of the following statements about mechanical weathering are true. One is false. Which
statement is incorrect?
A) Mechanical weathering does not affect metamorphic rocks.
B) Mechanical weathering produces smaller pieces.
C) Mechanical weathering does not change the rock's mineral composition.
D) Mechanical weathering adds to the effectiveness of chemical weathering

Golf cart is moving 8 metre in 1 second

so, in 10 seconds it moves 8 × 10 = 80 m

a) velocity = 80/10 = 8 m/s

b) acceleration = v - u / t

= 8 - 0 / 10

= 0.8 m/s²

c) the displacement of the graph is increasing

I hope this answer is correct and helpful to you

Answer:

r = 1.999m

Explanation:

E = kq/r²

10 = 9*10^9*q/1²

q = 10/9*10^9

q = 1.11*10^-9

then at what distance

r² = kq/E

r² = 9*10^9*1.11*10^-9/2.5

r² = 9.99/2.5

r² = 3.996

r = √3.996

r = 1.999m

The direction of revolution in the plane of the Solar System was determined by the direction of rotation of the original cloud. The correct option is c.

The solar system was created from a cloud of gas and dust. According to the nebular hypothesis, the sun and planets were formed from a single rotating cloud of dust and gas. The sun was created at the center of the cloud, while the planets were created in orbit around it.

The plane of the solar system's planets is determined by the rotation of the original cloud. The original cloud that formed the solar system was spinning in a specific direction, which determined the direction of revolution in the plane of the solar system. Therefore, the answer is option c. the direction of rotation of the original cloud.

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Answer:

this statement is true because I looked it up

Answer:

35 m/s = v KE= 1/2 m x v^2. 89= m x 1224

89 J = KE 89 = 1/2 (m) x (35)^2. m = 0.15 kg.

Answer:

he Kuiper Belt shouldn't be confused with the Oort Cloud, which is a much more distant region of icy, comet-like bodies that surrounds the solar system

Explanation:

:)

(a) The initial temperature is 373.95 K.

(b) The final temperature is 546.15 K.

(c) The total internal energy change of the fluid during this process is 515.4 kJ.

(d) The process can be represented as an isochoric heating process on the P-v diagram and as an isobaric expansion process on the T-v diagram.

(a) To find the initial temperature, we can use the saturated steam tables. At a pressure of 200 kPa, the corresponding saturation temperature is 373.95 K.

(b) Since the volume doubles, the process is an isochoric (constant volume) heating process. Using the ideal gas law, we can determine the final temperature. The initial and final volumes are related by the equation V_final = 2V_initial. Since the mass remains constant, the specific volume (v) is inversely proportional to the density (ρ). Therefore, ρ_final = ρ_initial/2. Using the ideal gas law, we can calculate the final temperature to be 546.15 K.

(c) The total internal energy change can be calculated using the equation ΔU = mC_vΔT, where m is the mass of the fluid and C_v is the specific heat at constant volume. Given the mass as 0.5 kg, the specific heat of water at constant volume, and the temperature change, we can find that the total internal energy change is 515.4 kJ.

(d) On the P-v diagram, the process is represented as a vertical line at 200 kPa, indicating constant pressure. On the T-v diagram, the process is shown as an upward-sloping line, indicating an isobaric expansion process. The initial state is represented as a point on the left, and the final state is represented as a point on the right. The path between the initial and final states is a straight line connecting these two points.

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ANSWER

EXPLANATION

The speed of a wave is given by the formula:

where λ = wavelength

f = frequency

Hence, the wavelength of the wave is:

Therefore, the wavelength of the sound wave is:

The answer is option B.

The forces in members gh, gb, and bc are given below.

Force is an influence that can cause a change in an object's motion, direction, shape, or energy state. It is a vector quantity, meaning that it has both magnitude and direction.

Member gh: The force in member gh is in compression. This is because it is part of a truss system where two other members are connected to it, forming a triangle. Since the two other members will both be pushing inwards towards member gh, it will be in compression.

Member gb: The force in member gb is in tension. This is because it is part of a truss system where two other members are connected to it, forming a triangle. Since the two other members will both be pulling on member gb, it will be in tension.

Member bc: The force in member bc is in tension. This is because it is part of a truss system where two other members are connected to it, forming a triangle. Since the two other members will both be pulling on member bc, it will be in tension.

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The Earth orbits around the sun because the gravitational force that the sun

exerts on the Earth:

O A. causes Earth's acceleration toward the sun.

O B. is very small because the sun is so far from the Earth.

O c. is smaller than the force the Earth exerts on the sun.

O D. pushes the Earth away from the sun.

O A. causes Earth's acceleration toward the sun.

I hope this helps, have a nice time ahead!

Answer:

88N

Explanation:

m = 9kg

a = 9.8m/s²

F = ma = 9 × 9.8

F = 88N

Answer:

It's C

Since the vast majority of an atom’s mass is found its protons and neutrons, subtracting the number of protons (i.e. the atomic number) from the atomic mass will give you the calculated number of neutrons in the atom.

Answer:

rotational kinetic energy

angular momentum

the mechanical energy of frictionless systems

Explanation:

The quantities that are conserved in a movement are extremely useful for the simple resolution of different situations, in addition to the linear movement in the angular movement, some quantities are also conserved.

rotational kinetic energy

angular momentum

the mechanical energy of frictionless systems

Answer:

1. speed is the distance travelled by an object in unit time

2. velocity is the displacement of a body in in unit time

3. formula of speed =total distance (d)÷ total elapsed time

All particles have energy, and the energy varies depending on the temperature the sample of matter is in, which determines if the substance is a solid, liquid, or gas. Solid particles have the least amount of energy, and gas particles have the greatest amount of energy

Answer:

A. amplitude

Explanation:

please vote me brainliest?? thanks:)

Answer:

Are similar in pattern

Explanation:

edge 2021

Answer:

vertical axis

Explanation:

Duff is a breakdancer whose signature move is spinning around on his head while his body is upside down. It means that the center of axis lies at the center of head. it means that Duff is rotating at vertical axis.

Hence, the correct option is (b) "vertical axis"

Answer:

verticalaxis

Explanation:

Answer:

B

Explanation:

The time interval where the rotational kinetic energy increases is when fmotor is greater than 0.4n and decreases is when fmotor is less than 0.4n.

What is rotational kinetic energy?

Rotational kinetic energy is the kinetic energy associated with the rotation of an object. It is equal to the work done in rotating an object (a moment of force multiplied by the angular displacement) and is equal to one-half the moment of inertia of the object multiplied by the angular velocity squared.

The rotational kinetic energy of the wheel is given by the equation:

K.E. = 1/2 Iω2

where I is the moment of inertia and ω is the angular velocity.

The moment of inertia is given by I = mr2, where m is the mass of the wheel and r is the radius of the wheel.

The angular velocity is given by ω = v/r, where v is the linear velocity of the wheel.

The linear velocity of the wheel is given by v = 2πfr, where f is the frequency of rotation.

The frequency of rotation is given by f = (fmotor - 0.4n)/(2πr).

The rotational kinetic energy can therefore be written as:

K.E. = 1/2 m(2πfr)2r2

Time interval where the rotational kinetic energy increases:

The rotational kinetic energy increases when the linear velocity of the wheel (v) increases. This happens when the frequency of rotation (f) increases. This is when fmotor is greater than 0.4n.

Hence, the time interval where the rotational kinetic energy increases is when fmotor is greater than 0.4n.

Time interval where the rotational kinetic energy decreases:

The rotational kinetic energy decreases when the linear velocity of the wheel (v) decreases. This happens when the frequency of rotation (f) decreases. This is when fmotor is less than 0.4n.

hence, the time interval where the rotational kinetic energy decreases is when fmotor is less than 0.4n.

Therefore, The time interval where the rotational kinetic energy increases is when fmotor is greater than 0.4n and decreases is when fmotor is less than 0.4n.

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The magnitude of the average force on the bumper is approximately 13,632.2 N. The negative sign indicates that the force is directed opposite to the initial motion of the car.

To calculate the magnitude of the average force on the bumper, we can use Newton's second law of motion, which states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a). In this case, the acceleration can be determined using the equation:

a = (v\(_{f}\) - v\(_{i}\)) / t

where v\(_{f}\) is the final velocity (0 m/s), v\(_{i}\) is the initial velocity (2.0 m/s), and t is the time taken to come to rest.

Since the bumper collapses over a distance (d) of 0.255 m, we can calculate the time taken using the equation:

t = d / v\(_{i}\)

Substituting the given values:

t = 0.255 m / 2.0 m/s

t = 0.1275 s

Now, we can calculate the acceleration:

a = (0 m/s - 2.0 m/s) / 0.1275 s

a = -15.6863 m/s²

Since the car comes to rest, the force exerted on it is equal to the force applied by the bumper. Thus, we can calculate the magnitude of the average force using:

F = m × a

Substituting the mass of the car (m = 870 kg) and the acceleration (a = -15.6863 m/s²):

F = 870 kg × (-15.6863 m/s²)

F ≈ -13,632.2 N

The negative sign indicates that the force is directed opposite to the initial motion of the car. Therefore, the magnitude of the average force on the bumper is approximately 13,632.2 N.

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The correct answer is option E, which is eastward with a magnitude of 1.8 x 10^5 m/s^2.

A negatively charged particle is placed in a uniform electric field directed West. What are the magnitude and direction of the particle's acceleration if its charge is q= -6 μC, its mass m = 2 grams, and the value of electric field E is 6 x10 N/C?The magnitude of the force experienced by the charged particle (q) is F=qE.From Newton's second law, we know that acceleration is given by:F = maTherefore, we can find the magnitude of acceleration asa = F/mSubstituting the values given in the problem,a = F/m = qE/m = (-6x10^-6 C)(6x10^5 N/C) / 0.002 kg= -1.8x10^3 m/s^2Since the charge of the particle is negative, the force is opposite to the direction of the electric field. Therefore, the force and acceleration both point towards the east.

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The sum of the kinetic and potential energies of particles in an object called mechanical energy.

Mechanical energy is the energy possessed by an object due to its motion or due to its position. This energy is derived from the work done on an object.

It can be in the form of kinetic energy, the energy of motion; or in the form of potential energy, the energy an object has due to its position or shape.

Mechanical energy can be converted between the two forms, and is often converted into other forms, such as electrical energy or thermal energy.

Mechanical energy is used to power machines and devices, and is an important source of energy in the modern world.

Therefore, The sum of the kinetic and potential energies of particles in an object called mechanical energy.

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Answer:

2H₂S + SO₂ —> 2H₂O + 3S

Explanation:

From the question given above, the following equation were obtained:

H₂S + SO₂ —> H₂O + S

The equation can be balance as illustrated below:

H₂S + SO₂ —> H₂O + S

There are 2 atoms of O on the left side and 1 atom on the right side it can be balance by writing 2 before H₂O as shown below:

H₂S + SO₂ —> 2H₂O + S

There are 2 atoms of H on the left side and 4 atoms on the right side. It can be balance by writing 2 before H₂S as shown below:

2H₂S + SO₂ —> 2H₂O + S

There are 3 atoms of S on the left side and 1 atom on the right side. It can be balance by writing 3 before S as shown below:

2H₂S + SO₂ —> 2H₂O + 3S

Now, the equation is balanced.!

Explanation:

Hey there!

Given;

Mass of one object (m1) = 250kg

Mass of another object (m2) = 400 kg

Distance (d) = 100 m

Gravitational constant (g) = 6.67*10^-11

Now;

\(f = \frac{g.m1.m2}{ {d}^{2} } \)

Keep all values;

\(f = \frac{6.67 \times {10}^{ - 11} \times 250 \times 400}{ {(100)}^{2} } \)

Simplify

\(f = \frac{6.67 \times {10}^{ - 11} {10}^{5} }{10000} \)

\(f = \frac{6.67 \times {10}^{ - 6} }{10000} \)

Therefore, gravitational force is 6.67*10^-10.

Hope it helps!

Kisses' power is approximately 490.13 Watts.

Power (P) is defined as the rate at which work is done. The formula to calculate power is:

P = W / t

P is the power,

W is the work done,

t is the time taken.

The work done (W) can be calculated as the product of force (F) and distance (d):

W = F * d

In this case, the force is the weight of Kisses, which can be calculated using the formula:

F = m * g

m is the mass of Kisses,

g is the acceleration due to gravity (approximately 9.8 m/s^2).

m = 57 kg

d = 28 m

t = 32 seconds

g = 9.8 m/s^2

First, calculate the work done:

W = F * d

W = (m * g) * d

Next, calculate the power:

P = W / t

Substituting the given values:

W = (57 kg * 9.8 m/s^2) * 28 m

W ≈ 15684.24 J

P = 15684.24 J / 32 s

P ≈ 490.13 W

Therefore, Kisses' power is approximately 490.13 Watts.

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The photon's wavelength emitted during the transition from n = 2 to n = 3 is approximately 256 nm. The photon's wavelength emitted during the transition from n = 1 to n = 3 is about 160 nm. The width of the box is approximately 0.622 nm.

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

Let's assume the wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h² / (8× m × L²)) ×(9 - 4)

ΔE = (h²/ (8 × m × L²)) × 5

The energy difference is proportional to the frequency of the emitted photon:

ΔE = h × c / λ

where c is the speed of light.

We can equate the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

Plugging in the given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L² = 0.00047765 m²

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

Following the same steps,

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Simplifying and solving for λ:

λ = (m × L² × c) / h

Plugging in the given values:

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Therefore, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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The wavelength of the photon released during the change from n = 2 to n = 3 is roughly 256 nm. About 160 nm is the wavelength of the photon that is released when n = 1 changes to n = 3. The box has a width of about 0.622 nm.

Given values:

m = mass of the electron = 9.11 x 10⁻³¹ kg

L = width of the box (to be determined)

c = speed of light = 3 x 10⁸ m/s

The energy levels of a particle in a one-dimensional box:

Eₙ = (n² ×h²) / (8 × m × L²)

where:

Eₙ: energy level of the particle

n: quantum number of the energy level

h: Planck's constant

m: mass of the particle

L: width of the box.

Transition from n = 2 to n = 3:

The wavelength of the photon emitted during this transition is λ.

ΔE = E₃ - E₂

ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))

ΔE = (h²/ (8 × m × L²)) × 5

The frequency of the photon that was released directly correlates with the energy difference:

ΔE = h × c / λ

,c is the speed of light.

Evaluating the two expressions for ΔE:

(h² / (8 × m × L²)) × 5 = h × c / λ

λ = (8 × m × L² ×c) / (5 × h)

λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))

Solving for L

L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))

L ≈ 0.021847 m

The wavelength of the photon is given by:

λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))

λ ≈ 256 nm

Transition from n = 1 to n = 3:

ΔE = E₃ - E₁

ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))

ΔE = (h² / (m × L²))

Using ΔE = h × c / λ:

(h² / (m × L²)) = h ×c / λ

Solving for λ:

λ = (m × L² × c) / h

λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)

λ ≈ 160 nm

Width of the box (L):

From the above equations,

L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))

L ≈ 0.000622 m or 160 nm

Thus, the answers are 256 nm, 160 nm, and 0.622 nm respectively.

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