This question concerns the photoelectric effect in a cosmic context. Ultraviolet radiation striking dust grains composed of the moon's dominant rock type, feldspar (with work function 4.5 eV), leaves them with a small electric charge. Smaller grains levitate due to the resulting electrostatic repulsion, giving the surface a diffuse dust halo. What sign of charge do the dust grains have? Negative Positive O Some grains are negative, some are positive.

It takes the boat 10 seconds to reach the opposite side of the river.

The boat's velocity with respect to the shore can be found by using vector addition. Let's break down the velocities involved:

- The boat's velocity relative to the water: 40.0 m/s

- The water's velocity relative to the shore: 8.0 m/s

To find the boat's velocity with respect to the shore, we need to add these two velocities together. Since the velocities are in opposite directions, we subtract the magnitude of the water's velocity from the magnitude of the boat's velocity:

Boat's velocity with respect to the shore = Boat's velocity relative to the water - Water's velocity relative to the shore

                                            = 40.0 m/s - 8.0 m/s

                                            = 32.0 m/s

Therefore, the boat's velocity with respect to the shore is 32.0 m/s.

To find the time it takes for the boat to reach the opposite side of the river, we can use the formula:

time = distance / velocity

Given that the distance is 320 m and the velocity with respect to the shore is 32.0 m/s, we can substitute these values into the formula:

time = 320 m / 32.0 m/s

      = 10 s

Therefore, it takes the boat 10 seconds to reach the opposite side of the river.

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Answer:

P= 720 watt

Explanation:

P= IV

P= (6)(120)

P= 720 watt

Answer:

metamorpic rock

Explanation:

the rock stay near the ocen

Answer:

Mercury is a good conductor of heat. That makes it better at recording higher temperatures than other elements.

Explanation:

hope this helps

The lighter one travel with the speed of 0.574 m/sec. Force is defined as the product of mass and acceleration. Its unit is Newton.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The two skaters push off against each other on frictionless ice, then torque act by the one skater on the other is equal.

P₁₂=P₂₁

F₁₂V₁ =F₂₁V₂

625 ×V₁= 725 N×  1.5 m/s

V₁=0.574 m/sec

Hence, the lighter one travel with the speed of 0.574 m/sec.

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Answer:

1.74 m/s

Explanation:

use the formula

     \(F_{1} v_{1} = F_{2}v_{2}\)

the heavier skater being \(F_{1}\) and the lighter skater being \(F_{2}\)

    (725 N)(1.5 m/s) = (625 N) \(v_{2}\)

solve for \(v_{2}\)

  \(v_{2} =\) 1.74 m/s

The peak effective friction angle for the sand is approximately 35.9°, which is closest to option B) 38.0°.

The peak effective friction angle, φ, can be calculated using the following formula:

tan φ = (Aoult - Ao peak)/(2oc)

Substituting the given values, we get:

tan φ = (96.1 - 128.7)/(2 x 30.0) = -0.727

Taking the inverse tangent, we get:

\(φ = tan^-1(-0.727) = -35.9°\)

However, since the effective friction angle cannot be negative, we need to add 180° to the angle:

φ = 180 - 35.9 = 144.1°

Since this angle is greater than 90°, we need to subtract it from 180° to get the peak effective friction angle:

φ = 180 - 144.1 = 35.9°

Therefore, the peak effective friction angle for the sand is approximately 35.9°, which is closest to option B) 38.0°.

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Answer:

a

Explanation:

i took the test

Answer:

It is 100% B

Explanation:

I just took the test and it was right I promise

The landform that was most affected by erosion and experienced the highest amount of sediment displacement is the riverbed. This is due to the constant flow of water, which exerts a significant force on the riverbed.

Among various landforms, rivers are particularly susceptible to erosion and sediment displacement. The continuous flow of water in rivers exerts hydraulic pressure, which plays a crucial role in erosion. As water moves downstream, it carries sediments and debris along with it. The force of the flowing water can dislodge rocks, soil, and other loose materials from the riverbed, resulting in erosion.

Additionally, the velocity and volume of water in rivers can vary significantly, especially during heavy rainfalls or floods, further increasing the erosive power. This continuous erosion and transport of sediment contribute to the formation and reshaping of river valleys, as well as the deposition of sediment in delta regions and floodplains. Consequently, the riverbed stands out as the landform most affected by erosion and the one with the highest amount of sediment displaced.

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Science does not  work when every one does the same thing, some creative thinking will be major breakthroughs for an invention. Therefore, option B is correct.

So how do researchers come up with those particular questions to look into ! It may come as a shock to learn how much imagination is required for the procedure.

Peter Medawar, a Nobel Prize-winning biologist, once described scientific inquiry as "the art of the soluble"  In order to succeed in science, one must first identify the questions that may be answered by scientific study and then determine the answers to those questions, according to Medawar.

Because of how intricate the natural world is, it is frequently impossible to directly address the really intriguing, significant scientific topics

The art of science includes repeatedly re-imagining these complex issues, mentally dividing them into more manageable components, and then guessing as to which of these more manageable components might hold the answer to solving the larger issue.

Therefore, all the discoveries and inventions are resulted from the creative ideas and thoughts of scientists. Therefore, creativity is the only way to make a controlled experiment.

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In this scenario, the 1000-kg car and 2000-kg truck are colliding and the resulting wreckage has a combined mass of 3000 kg, the velocity of the wreckage just after impact is 11.67 m/s.  

The combined velocity of the two vehicles after the collision can be calculated by applying the law of conservation of momentum.

The law of conservation of momentum states that the momentum of a system remains constant if there are no external forces acting upon it.

Momentum (p) is equal to the mass (m) multiplied by velocity (v), so p = mv.

The momentum of the 1000-kg car traveling north at 15 m/s is 15000 kg m/s, and the momentum of the 2000-kg truck traveling east at 10 m/s is 20000 kg m/s.

After the collision, the momentum of the combined wreckage is the sum of the two vehicles' momentums, or 35000 kg m/s.

As the combined mass of the wreckage is 3000 kg, the velocity of the wreckage just after impact is

35000/3000

= 11.67 m/s.

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400N  magnitude of the friction acting on the crate.

work done by gravity

\([w=mg sin \theta \cdotS],[w=mgh=],[w=800 \cdot2=w=1600]\)

Then was done by friction  external work - wask done by gravity

\([f_S \cdot S=3200-1600],[f_S \cdot4=1600],[f_S=400 N]\)

Thus the crate is not moving with constant speed then we can say that the value of friction Force is less then 400 N

So Friction Force is not zero but less then the 400N

The resistance present at the contact surface at the point of contact when two or more objects move over one another can be referred to as friction force. The direction of friction force is always perpendicular to the object's motion.

The amount of friction is influenced by the surface's roughness and outside pressures. The force of friction works more strongly on a surface the rougher it is. The same is true of outside factors.

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An optical fiber uses flint glass surrounded by a crown glass cladding.The critical angle for total internal reflection in this optical fiber configuration is approximately 53.13 degrees.

To find the critical angle for total internal reflection in an optical fiber, we need to know the refractive indices of the materials involved. The critical angle can be calculated using the formula:

θc = arcsin(n2/n1)

where θc is the critical angle, n1 is the refractive index of the first medium (in this case, the core material), and n2 is the refractive index of the second medium (in this case, the cladding material).

For flint glass (core material), the refractive index is typically around 1.6-1.7, and for crown glass (cladding material), the refractive index is around 1.5-1.6.

Let's assume n1 = 1.7 (refractive index of flint glass) and n2 = 1.5 (refractive index of crown glass). Substituting these values into the formula:

θc = arcsin(1.5/1.7)

Using a calculator, the arcsin of (1.5/1.7) is approximately 53.13 degrees.

Therefore, the critical angle for total internal reflection in this optical fiber configuration is approximately 53.13 degrees.

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Here the focal length of the convex mirror as -12 cm, a light bulb with a diameter of 6 cm is placed 60 cm from the mirror. Hence, the image distance is -60 cm, and the image height is 6 cm.

To find the image distance and height, we will use the mirror formula for a convex mirror, which is given as follows;1/f = 1/v + 1/u. Where, f = focal length of the convex mirror;

v = the image distance;

u = the object distance

If the object distance is positive, it means the object is placed in front of the mirror, and if it is negative, it means the object is placed behind the mirror. The focal length of a convex mirror is always negative, as given above.

Therefore, u = -60 cm and f = -12 cm.

Plugging in the values in the mirror formula, we get:1/-12 = 1/v + 1/-60=> -5/60 = 1/v - (1/60) => -5/60 = (60 - v)/60=> v = -300/5= -60 cm

The image distance is -60 cm, which means the image is virtual and erect. The negative sign indicates that the image is formed behind the mirror.

To find the image height, we use the magnification formula:

m = -v/u= -(-60)/(-60)= 1

The magnification is 1, which means the image is of the same size as the object. The height of the light bulb is 6 cm, so the height of the image will also be 6 cm.

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The name of the substance is silver based on the specific heat capacity value.

The specific heat capacity of the substance is calculated by applying the following formula for heat capacity.

Q = mcΔθ

where;

c = Q / mΔθ

The specific heat capacity of the substance is calculated as;

c = (5875 J ) / ( 500 g x 50 )

c = 0.235 J/kgK

The substance that has the same specific heat capacity calculated above is silver.

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This type of system is a third class lever. FEL where fulcrum, effort and load comes in an arrangement.

Lever  is a simple machine in which the fixed arms are arranged at a fixed point known as fulcrum. There are three types of lever system: first class Lever system, second class lever system and third class lever system. In the first class lever system there is an arrangement like the see saw. In this arrangement the fulcrum is in center and both the arms are like a seesaw. In the second class lever system, output force was between input force and fulcrum. In the third class lever system input force is between output force and fulcrum. 

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Answer:

v = 4.4 m / s

Explanation:

Unfortunately, the exercise scheme does not appear. Let's analyze the problem the marble leaves point A with an initial velocity, goes down and then rises to a given height where its velocity is zero, in the whole trajectory they tell us that the resistance is zero, so we can use the conservation relations of the enegy.

Starting point. Point A

          Em₀ = K + U = ½ m v2 + mg y_a

point B.

          Em_f = U = m g y

the energy is conserved

         Em₀ = Em_f

         ½ m v² + mg y_a = m g y

        ½ m v² = m g (y -y_a)

         v = \(\sqrt {2g ( y - y_a)}\)

         In the exercise the diagram is not seen, but the height of point A must be known, suppose that y_a = 4 m

       v = \(\sqrt{ 2 \ 9.8 ( 5 -4)}\)

       v = 4.4 m / s

Answer:

I believe the answer is 45

Answer: hello the terms are missing but I have provided the answer ( the terms and matched them properly

answer :

Explanation:

This body wave is a compressional wave  : P WAVES

This body wave is a shear wave :  S  WAVES

This surface wave moves from side to side : L WAVES

This surface wave moves up and down. : R WAVES

A body wave is a type of wave that passes through the interior of the earth and they are classified as ; P and S waves while surface waves are seismic waves that travel near the earth's surface

The magnitude of the electric field between the plates is 1.25 x × 10⁴ N/C.

Electric field - Every point in space where a charge, in any form, is present has an electric property that is called an electric field.

The magnitude of the electric field strength is given as :

E = F/q

where

E = electric field

F = electrostatic force

q = charge

electron experiences a force of as it accelerates between two metal plates =  2 x 10⁻¹⁵ N

Charge of the electron,

q = 1.6 × 10⁻¹⁹ C

Then

E = (2 x 10⁻¹⁵ N)÷(1.6 × 10⁻¹⁹ C)

E = 1.25 x × 10⁴ N/C.

The magnitude of the electric field between the plates is 1.25 x × 10⁴ N/C.

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Explanation:

san po ung pagpipilian ?

To find the error in Rob's simplification of a radical expression, it is necessary to understand the process of simplifying radicals. This involves breaking down the radicand into its prime factors and simplifying each factor separately.

To identify and correct Rob's error in simplifying the radical expression, we need to understand the steps involved in simplifying radicals. First, we factorize the radicand (the number inside the square root) into its prime factors. For example, if we have the expression √72, we factorize 72 as 2 × 2 × 2 × 3 × 3.

Next, we pair up the prime factors into groups of two, taking one factor from each pair outside the square root sign. For our example, we have √(2 × 2) × √(2 × 3 × 3). Now, we simplify each square root separately. The square root of 2 × 2 simplifies to 2, and the square root of 2 × 3 × 3 simplifies to 3√2. Combining these results, we get 2√2 × 3√2.

Finally, we multiply the coefficients (numbers outside the square root) and combine like terms. In this case, the coefficients are 2 and 3, so the final simplified expression is 6√2. By following these steps, we can determine the correct simplification and identify and correct any errors made by Rob in the process.

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After watching the Ted Talk, there were still a few questions that I had about supermassive black holes. Firstly, I wanted to know more about the event horizon and what it exactly entails. Although the speaker briefly touched upon this subject, I would have appreciated a more in-depth explanation. Additionally, I would have liked to know more about the role of supermassive black holes in the universe.

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When a dielectric material is inserted between the plates of a charged capacitor, the free charge on the surface of the plates will remain unchanged, while the total charge (free and bound) on the surface of the plates will decrease.

A dielectric material is an insulating material that can store electrical energy in an electric field. In other words, it is a material that has a high resistance to the flow of electric current and does not conduct electricity.

Dielectric materials are commonly used as insulators in capacitors, which are electronic components that store electrical energy in an electric field. When a dielectric material is placed between the plates of a capacitor, it increases the capacitance of the capacitor, allowing it to store more electrical energy.

Examples of dielectric materials include air, glass, ceramics, and certain plastics. The properties of a dielectric material, such as its dielectric constant, determine how effective it is at storing electrical energy in an electric field.

Overall, dielectric materials play an important role in many electrical and electronic devices, including capacitors, transformers, and other components that use electric fields to store and transfer electrical energy.

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The horizontal displacement from the firing position to the point of impact is approximately 2,425 meters. The projectile hits the ground with a speed of approximately 230.4 meters/second.

To calculate the horizontal displacement of the projectile, we need to find the time of flight and then multiply it by the horizontal component of the initial velocity.

Step 1: Find the time of flight

Using the given initial muzzle speed and launch angle, we can find the time of flight. The vertical component of the initial velocity can be determined by multiplying the initial speed by the sine of the launch angle. Since the projectile is launched from a height of 4 meters, the time it takes for the projectile to reach the ground can be calculated using the equation h = ut + (1/2)gt^2, where h is the height, u is the initial vertical velocity, g is the acceleration due to gravity, and t is the time of flight. Plugging in the known values, we get 4 = (370 * sin(40))t - (1/2)(9.8)t^2. Solving this equation yields t ≈ 7.28 seconds.

Step 2: Calculate the horizontal displacement

The horizontal component of the initial velocity can be found by multiplying the initial speed by the cosine of the launch angle. The horizontal displacement is then given by multiplying the horizontal component of the initial velocity by the time of flight. Therefore, the horizontal displacement is approximately 370 * cos(40) * 7.28 ≈ 2,425 meters.

Step 3: Determine the speed at impact

To find the speed at which the projectile hits the ground, we need to calculate the vertical component of the velocity at the time of impact. The vertical component of the velocity can be determined by multiplying the initial speed by the sine of the launch angle and subtracting the product of the acceleration due to gravity and the time of flight.

Thus, the vertical component of the velocity at impact is given by 370 * sin(40) - 9.8 * 7.28 ≈ -230.4 meters/second. The negative sign indicates that the velocity is directed downwards. Therefore, the speed at which the projectile hits the ground is approximately 230.4 meters/second.

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The work needed if a force of 3N is used to move a table 25 metres is 75Nm (joules).

Work is a measure of energy expended in moving an object. This means that no work is done if the object does not move.

Force is a physical quantity that denotes the ability to push, pull, twist or accelerate a body and which has a direction and is measured in Newtons.

Work done on an object can be calculated by multiplying the force applied to move the object by the distance the object moves as follows:

Work done = Force (N) × distance (m)

According to this question, a force of 3 Newtons is used to move a table over a distance of 25 meters. The work done on the table can be calculated as follows;

W = 3N × 25metres

W = 75Nm

Therefore, 75Nm is the work done on the table.

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Answer:

definition of matter is that matter takes up space and has mass

The amount of power needed to draw the sled 1.00 km in 20.0 minutes at a tension of 100.0 N is roughly 83.3 watts.

Energy is referred to as the ability to perform the work, whereas work is defined as the displacement of an object when a force (push or pull) is applied to it. It can be found in a variety of forms, including potential, kinetic, chemical, thermal, nuclear, electrical, and so forth.

We can apply the power equation:

Power is defined as the product of work, the quantity of energy needed to move the sled, and time, the length of the sled's motion.

Finding the work completed on the For work, we can apply the following formula:

work = force x distance

distance = 1.00 km x 1000 m/km = 1000 m

time = 20.0 min x 60 s/min = 1200 s

work = force x distance = 100.0 N x 1000 m = 100000 J

Finally, we can calculate the power required to move the sled:

power = work / time = 100000 J / 1200 s = 83.3 W.

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