This is the case study of a young man named Josh. Josh is a 27 year-old male who recently
moved back in with his parents after his fiancé was killed by a drunk driver. His fiancee, a
beautiful young woman he'd been dating for the past four years, was walking across a busy
intersection to meet him for lunch one day. He still vividly remembers the horrific scene as
the drunk driver ran the red light, plowing down his fiancé right before his eyes. He raced
to her side, embracing her crumpled, bloody body as she died in his arms in the middle of
the crosswalk. No matter how hard he tried to forget, he frequently finds himself reliving
the entire incident as if it was happening all over.
Since the accident, Josh has been plagued with nightmares about the accident almost
every night. He had to quit his job because his office was located in the building right next
to the little cafe where he was meeting his fiancé for lunch the day she died. The few times
he attempted to return to work were unbearable for him. He has since avoided that entire
area of town.
Normally an outgoing, fun-loving guy, Josh has become increasingly withdrawn, "jumpy",
and irritable since his fiancé's death. He's stopped working out, playing his guitar, or play-
ing basketball with his friends - all activities he once really enjoyed. His parents worry
about how detached and emotionally flat he's become.

Answers

Answer 1
Interesting drabble. But what does this have to do with physics friend?

Related Questions

1.How are elements arranged on the periodic table in terms of valence electrons?

2. Show some evidence using data tables


3. Explain how the evidence supports your claim. Explain how the evidence from your data table shows the trends for valence electrons for both groups and periods on the periodic table.

Answers

Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.

1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.

2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:

Element   | Electron Configuration | Group | Period |

--------------------------------------------

Hydrogen  | 1s^1                              | 1     | 1      |

Lithium       | [He] 2s^1                     | 1     | 2      |

Carbon       | [He] 2s^2 2p^2          | 14    | 2      |

Oxygen      | [He] 2s^2 2p^4          | 16    | 2      |

Neon          | [He] 2s^2 2p^6          | 18    | 2      |

--------------------------------------------

3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.

- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.

- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.

By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.

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Instead of moving back and forth, a conical pendulum moves in a circle at constant speed as its string traces out a cone (see figure below). One such pendulum is constructed with a string of length
L =10.7 cm and bob of mass 0.344 kg. The string makes an angle = 5.58° with the vertical.

(a) What is the radial acceleration of the bob?
magnitude


(b) What are the horizontal and vertical components of the tension force exerted by the string on the bob? (Assume radially inward to be the positive x axis and vertically upward to be the
positive y axis. Express your answer in vector form.)
T= N

Answers

Answer:

a

The  radial acceleration is  \(a_c = 0.9574 m/s^2\)

b

The horizontal Tension is  \(T_x = 0.3294 i \ N\)

The vertical Tension is  \(T_y =3.3712 j \ N\)

Explanation:

The diagram illustrating this is shown on the first uploaded

From the question we are told that

   The length of the string is  \(L = 10.7 \ cm = 0.107 \ m\)

     The mass of the bob is  \(m = 0.344 \ kg\)

     The angle made  by the string is  \(\theta = 5.58^o\)

The centripetal force acting on the bob is mathematically represented as

         \(F = \frac{mv^2}{r}\)

Now From the diagram we see that this force is equivalent to

     \(F = Tsin \theta\) where T is the tension on the rope  and v is the linear velocity  

     So

          \(Tsin \theta = \frac{mv^2}{r}\)

Now the downward normal force acting on the bob is  mathematically represented as

          \(Tcos \theta = mg\)

So

       \(\frac{Tsin \ttheta }{Tcos \theta } = \frac{\frac{mv^2}{r} }{mg}\)

=>    \(tan \theta = \frac{v^2}{rg}\)

=>   \(g tan \theta = \frac{v^2}{r}\)

The centripetal acceleration which the same as the radial acceleration  of the bob is mathematically represented as

      \(a_c = \frac{v^2}{r}\)

=>  \(a_c = gtan \theta\)

substituting values

     \(a_c = 9.8 * tan (5.58)\)

     \(a_c = 0.9574 m/s^2\)

The horizontal component is mathematically represented as

     \(T_x = Tsin \theta = ma_c\)

substituting value

   \(T_x = 0.344 * 0.9574\)

    \(T_x = 0.3294 \ N\)

The vertical component of  tension is  

    \(T_y = T \ cos \theta = mg\)

substituting value

     \(T_ y = 0.344 * 9.8\)

      \(T_ y = 3.2712 \ N\)

The vector representation of the T in term is of the tension on the horizontal and the tension on the vertical is  

         

       \(T = T_x i + T_y j\)

substituting value  

      \(T = [(0.3294) i + (3.3712)j ] \ N\)

         

Instead of moving back and forth, a conical pendulum moves in a circle at constant speed as its string

The radical acceleration of the bob is 0.9575 m/s². The horizontal and vertical components of the tension force exerted by the string on the bob are 0.329 N and 3.37 N respectively.

Taking the vertical component of the tension where the weight mass is balanced, then:

T sin θ = mg

\(\mathbf{T = \dfrac{mg}{sin \theta}}\)

However, the centripetal force of the system is given by the horizontal component of the tension which can be expressed as:

T cos θ = m\(\mathbf{a_r}\)

Making \(\mathbf{a_r}\) the subject, we have:

\(\mathbf{a_r = \dfrac{Tcos \theta }{m}}\)

replacing the value of tension (T), we have:

\(\mathbf{a_r = \dfrac{ \dfrac{mg}{sin \theta}cos \theta }{m}}\)

\(\mathbf{a_r=g tan \theta}\)

where;

angle  θ = 5.58°

\(\mathbf{a_r=9.8 m/s^2 \times tan 5.58}\)

\(\mathbf{a_r=9.8 m/s^2 \times 0.0977}\)

\(\mathbf{a_r=0.9575 \ m/s^2}\)

Thus, the radical acceleration of the bob is 0.9577 m/s²

On the positive x-axis, the horizontal component of the tension force is:

\(\mathbf{T_x =Tcos \theta}\)

\(\mathbf{T_x =ma_r}\)

\(\mathbf{T_x =0.344 \ kg \times 0.9575 \ m/s^2}\)

\(\mathbf{T_x =0.329 \ N}\)

On the positive y-axis, the vertical component of the tension force is:

\(\mathbf{T_y =Tsin \theta}\)

\(\mathbf{T_y =mg}\)

\(\mathbf{T_y=0.344 \ kg \times 9.8 \ m/s^2}\)

\(\mathbf{T_x =3.37 \ N}\)

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What is the displacement of the iguana between 0s and 6s

Answers

Answer: Displacement between 0s and 6s = 2

Explanation:0+2=2

Select the correct answer.
What is the force that can cause two pieces of iron to attract each other?
A.
gravitational force
B.
magnetic force
C.
elastic force
D.
electrostatic force

Answers

Answer:

A. gravitational force always true.

B, C and D could be true under the correct conditions

HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?

Answers

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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A Hunter points his gun at a squirrel on a branch of a tree away from him. Assume he lies on the ground and that the moment he fires his gun the squirrel drops off the branch. Show that the squirrel should not have dropped if it was to avoid being shot.(neglect air resistance).​

Answers

Answer:

well if it wasn't shot then it shouldn't have been affected

Explanation:

A gas expands from I to F in the figure. The energy added to the gas by heat is 465 J when the gas goes from I to F along the diagonal path. What is the change in internal energy of the gas?

Answers

The gas's internal energy that expands from I to F changes by 1015 J.

How to determine internal energy?

Since the gas is expanding and energy is added to it by heat, the change in internal energy of the gas can be calculated using the first law of thermodynamics, which states that:

ΔU = Q - W

where ΔU = change in internal energy,

Q = heat added to the system, 465 J and

W = work done by the system.

Assuming that the process is quasi-static use approximation known as the "staircase approximation."

By adding up the work done in each step, find that the total work done by the gas is approximately -550 J. The negative sign indicates that work is done on the gas.

Therefore, using the first law of thermodynamics, we can calculate the change in internal energy of the gas as:

ΔU = Q - W

ΔU = 465 J - (-550 J)

ΔU = 1015 J

Therefore, the change in internal energy of the gas is 1015 J.

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PLEASE ANSWER FAST
Select the statement(s) that accurately illustrate examples of energy transfer by radiation.
Heat emitted from a candle
Ocean waves on the surface of the sea Microwaves from a microwave oven
Radio waves transmitted between towers Sound waves from a car radio​

Answers

Heat emitted from a candle, Microwaves from a microwave oven, Radio waves transmitted between towers, Sound waves from a car radio.

Illustrate examples of energy transfer by radiation?The examples of energy transfer by radiation mentioned above are heat, microwaves, radio waves, and sound waves. Heat is the transfer of thermal energy from one object to another, usually through the process of convection, conduction, or radiation. Heat emitted from a candle is an example of energy transfer by radiation.Microwaves are electromagnetic waves that are used to heat food in a microwave oven. The microwaves are generated by an oscillating electric current and then radiated into the oven, where they are absorbed by the food. This energy is then converted into heat, which cooks the food. Radio waves are used to transmit information between towers, such as those used for cellular phone communication. The towers emit radio waves, which travel through the air, and the information they contain is then picked up by the towers on the other end. Sound waves are also a form of energy transfer by radiation. When a car radio is playing, sound waves are emitted from the radio, which then travel through the air to your ears. The process of energy transfer by radiation is called electromagnetic radiation. This is the process by which energy is transferred from one place to another in the form of electromagnetic waves. Examples of electromagnetic radiation include visible light, infrared radiation, ultraviolet radiation, x-rays, and gamma rays.

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In the arrangement described in Sample Problem B, how much would the water’s internal energy increase if the mass fell 6.69 m?

Answers

If a mass fell into water, the water's internal energy would increase due to the conversion of the kinetic energy of the falling mass into thermal energy.

How to explain the information

When the mass hits the water, it will experience a force from the water, and this force will cause the mass to decelerate and eventually come to a stop. During this process, the kinetic energy of the mass is converted into thermal energy of the water, which increases the water's internal energy.

The amount by which the water's internal energy increases will depend on several factors, including the mass of the falling object, its velocity, and the properties of the water, such as its specific heat capacity and temperature. Additionally, the temperature of the water may rise due to the energy transfer from the falling object, which would further increase its internal energy.

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Violet light has a frequency of 7.26 × 1014 Hz and travels at a speed of 3.00 × 108 m/s.

Answers

Answer:

what's the question

........

In 7.5 s, 4200 waves pass a given point. What is the frequency of the waves?

Answers

In 7.5 s, 4200 waves will pass a given point. Then, the frequency of the waves is 560 Hz.

Frequency is the number of cycles or oscillations of a wave that occur in one second, measured in Hertz (Hz). It is the rate at which a wave completes a full cycle, which is usually measured as the number of wavelengths that pass a fixed point in a unit of time.

The formula for frequency is;

frequency = waves/time

Where "waves" is the number of waves that pass a given point and "time" is the time it takes for those waves to pass.

In this case, we know that 4200 waves pass a given point in 7.5 seconds, so we can plug those values into the formula;

frequency = 4200/7.5

Simplifying;

frequency = 560

Therefore, the frequency of the waves is 560 Hz.

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Particles q1= -66.3 μC, q2 = +108 μC, and q3 = -43.2 μC are in a line. Particles q1 and q2 are separated by 0.550 m and particles q2 and q3 are separated by 0.550 m. What is the net force on particle q2?

Remember:
Negative forces (-F) will point Left
Positive forces (+F) will point Right

Will mark brainliest IF answer is correct.

Particles q1= -66.3 C, q2 = +108 C, and q3 = -43.2 C are in a line. Particles q1 and q2 are separated

Answers

To calculate the net force on particle q2, we need to calculate the individual forces exerted by q1 and q3 on q2, considering their charges and separation distances.

Using Coulomb's Law, the force between two charged particles can be calculated as:

\(F = (k * |q1 * q2|) / r^2\)

where F is the force, k is Coulomb's constant (8.99 x 10^9 N m²/C²), q1 and q2 are the charges of the particles, and r is the separation distance between them.

For q1 and q2:

F1 = (8.99 x 10^9 N m²/C²) * (|-66.3 x 10^-6 C * 108 x 10^-6 C|) / (0.550 m)²

For q2 and q3:

F2 = (8.99 x 10^9 N m²/C²) * (|108 x 10^-6 C * -43.2 x 10^-6 C|) / (0.550 m)²

The net force on q2 is the vector sum of F1 and F2:

Net Force = F1 + F2

By calculating these values and performing the addition, we can determine the net force acting on particle q2.

Therefore, To calculate the net force on particle q2, we need to calculate the individual forces exerted by q1 and q3 on q2, considering their charges and separation distances.

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Which of the following is NOT true about the mass of an object?

A)
Mass is measured in kilograms.
B)
Mass is a measurement of force.
C)
Mass is a measurement of the amount of matter in an object.
D)
Mass does not change based on your location.

Answers

Answer:

B) Mass is a measurement of force

Explanation:

Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.

When measuring espresso for a drink, which instrument would give the
greatest precision?

When measuring espresso for a drink, which instrument would give thegreatest precision?

Answers

How many mL is an espresso?

One shot of espresso is generally about 30–50 ml (1–1.75 oz), and contains about 63 mg of caffeine (3). Important point: The “golden ratio” for espresso is this: a single shot is 30 to 44 mL (1 to 1.5 ounces) of water and 7 grams of coffee

please help me with questions 3and 4​

please help me with questions 3and 4

Answers

q3 - I am not sure, sorry:(

q 4 - Alcoholism is a disease because it not only causes people to become addicted to alcohol, which has many harmful consequences such as heart disease, but it also causes people to relapse when they say they will stop drinking. However, some people who were addicted to alcohol realised during that time that life has a purpose and that being addicted to alcohol will not solve problems. This person's alcoholism inspired them to change their lives and mindsets, as well as to work on their goals, which has led them to accomplish many things in life.For example, celebrity Daniel Radcliffe, 29, acknowledged to using alcohol to cope with the immediate popularity he'd achieved as the lead of the Harry Potter films. Despite enjoying his work, the English actor claims he isolated himself from the public to avoid the constant attention. Radcliffe attributes his ability to get therapy and create new, better coping techniques to his close pals.

Draw the Free- Body diagram of the 37 kilogram glass falling to the floor in a vacuum.



Then, use Newton’s Second Law to calculate how much force the glass hits the floor with.

Answers

Answer:

362.6 N

Explanation:

\(F_{g}=mg\)

\(F_{g}=37\cdot9.8\)

\(F_{g}=362.6\ N\)

Therefore, the force that the glass hits the floor with is 362.6 N

A 67 kg high jumper leaves the ground with a
vertical velocity of 6.4 m/s.
How high can he jump? The acceleration
of gravity is 9.8 m/s².
Answer in units of m. Answer in units of m.

Answers

The height of the jump having a mass of 67kg with the vertical velocity of 6.4m/s is 2.089m.

What is Kinetic and Potential energy?

Potential energy is defined as the energy stored in an object or system by virtue of its position or arrangement of parts while kinetic energy is defined as the energy of the moving particles of an object or system.

Potential energy is represented as :

P.E.= mgh

Kinetic energy  is represented as :

\(K.E.= 1/2mv^2\)

where, m = mass of the object

h= height

v= velocity

g= acceleration due to gravity which is \(9.8m/s^2\)

For above given example,

m= 67kg, v= 6.4m/s

we first find out Kinetic energy,

K.E.=\(\frac{1}{2} 67* (6.4)^2\)= 2744.32/2= 1372.16 J

As we know, K.E.= P.E.

So, P.E.= 1372.16J = mgh

1372.16= 67* 9.8* h

height= 2.089 m

Thus, the height of the jump having a mass of 67kg with the vertical velocity of 6.4m/s is 2.089m.

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Which of the following relationships is correct?
2 points
1 N = 1 kg
1 N = 1 kg·m
1 N = 1 kg·m/s
1 N = 1 kg·m/s2

Answers

1 N = 1 kg•m is the answer

In a velocity selector having electric field E and magnetic field B, the velocity selected for positively charged particles is v= E/B. The formula is the same for a negatively charged particles.

a. True
b. False

Answers

Answer:

True or False

Explanation:

Because.....

easy 50% chance you are right

PLEASE HELP !!!!!! As seen in the lesson video, solar photovoltaic technologies help provide clean electrical energy. Using the video animation as a guide, diagram and label the absorption of photons and production of electrons (photoelectric effect) used in solar PV systems. Include a screenshot or picture of your diagram below.

Answers

We can see here that the diagram that reveals the absorption of photons and production of electrons (photoelectric effect) used in solar PV systems is seen below.

What is photon?

A photon is a fundamental particle or quantum of light.

It is the smallest indivisible unit of electromagnetic radiation, which also includes radio waves, microwaves, X-rays, visible light, ultraviolet light, and infrared radiation. In scientific calculations, photons are represented by the symbol "c" and move at the speed of light in a vacuum while carrying energy.

Wave-particle duality is the idea that photons are both particles and have wave-like characteristics. This means that they can exhibit wave-like properties like interference and diffraction as well as discrete particle behavior, each with a distinct energy and momentum.

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PLEASE HELP !!!!!! As seen in the lesson video, solar photovoltaic technologies help provide clean electrical

two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then what is the magnitude and the direction of the resultant force
what is its acceleration of x and y component
what is the magnitude of acceleration of the object

Answers

Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then  the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

The acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

The magnitude of the acceleration of the object is 3  \(m/s^{2}\).

To find the magnitude and direction of the resultant force, we need to add the two given forces together.

Given:

f1 = (8i + 3j) N

f2 = (4i + 6j) N

To find the resultant force (\(F_res\)), we simply add the corresponding components:

\(F_res\) = f1 + f2

= (8i + 3j) + (4i + 6j)

= (8 + 4)i + (3 + 6)j

= 12i + 9j

The magnitude of the resultant force (\(|F_res|\)) can be found using the Pythagorean theorem:

\(|F_res|\)= \(\sqrt{(12^2) + (9^2)}\)

= \(\sqrt{144 + 81}\)

= \(\sqrt{225}\)

= 15 N

So, the magnitude of the resultant force is 15 N.

To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:

θ = arctan(9/12)

= arctan(3/4)

≈ 36.87 degrees

Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:

F = ma

For the x-component:

\(F_x\)= 12 N

m = 5 kg

Using  \(F_x\)= \(ma_x\), we can solve for \(a_x\):

12 N = 5 kg * \(a_x\)

\(a_x\)= 12 N / 5 kg

\(a_x\) = 2.4 \(m/s^{2}\)

For the y-component:

\(F_y\) = 9 N

m = 5 kg

Using \(F_y\) = \(ma_y\), we can solve for \(a_y\):

9 N = 5 kg * \(a_y\)

\(a_y\) = 9 N / 5 kg

\(a_y\)= 1.8  \(m/s^{2}\)

So, the acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:

|a| = \(\sqrt{(a_x^2) + (a_y^2)}\)

= \(\sqrt{(2.4^2) + (1.8^2}\)

= \(\sqrt{5.76 + 3.24}\)

= \(\sqrt{9}\)

= 3  \(m/s^{2}\)

Therefore, the magnitude of the acceleration of the object is 3  \(m/s^{2}\)

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A candle is sitting in front of a concave mirror at a distance of 18.0 cm. It is found that an image of the ca
25.0 cm. What is the focal length of the mirror?
03.52 cm
07.50 cm
O 10.4 cm
022.1 cm

Answers

Answer:

The focal length of the mirror is 10.4 cm.

Explanation:

The object distance ( d₀ )  ( distance of the candle from the mirror) is -18 cm.The Image distance ( dᵢ  ) ( distance of the image from the mirror) is -25.0 cm.The mirror equation is  1/f = 1/d₀ + 1/dᵢ.

So substitute the values of object distance and image distance in the mirror equation,

1/f = 1/(-18cm) + 1/(-25.0cm)

1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)

1/f = ( -25cm - 18cm)/(18cm x 25cm)

1/f = -43.0/450.0

f = -10.4651 cm.

The focal length of the mirror is approximately -10.4 cm.

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1. Which of the choices will make a brass band?
A. Angklung
B. Bumbong, Kalatok, Tongatong
C. Bamboo, woodwind instrument
D. Woodwind, percussion, brass wind

2. Which is a woodwind instrument?
A. Bass Drum
B. Cymbals
C. Flute
D. Snared Drum

3. Which is a percussion instrument?
A. Bass Drum
B. Flute
C. Sousaphone
D. Trombone​

Answers

Explanation:

1.

C. Bamboo woodwind instrument

2.

C. Flute

3.

A. Bass Drum

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?

Answers

Answer: τy = 2τx

Given: graph of L vs t
Ly = 20 at t = 5
Lx = 10 at t = 5
All L = 0 at t = 0
So change in angular momentum of y is 20 and x is 10

Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy


Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X

water pressurized to 450000 pa is flowing at 5.0m/s in a horizontal pipe which contracts to 1/3 its former area. what are the pressure and velocity of the water after the contraction?

Answers

the pressure of the water after the contraction is -50000 Pa (or 50 kPa below atmospheric pressure), and the velocity of the water after the contraction is 15.0 m/s.

The continuity equation states that the product of the cross-sectional area and the velocity of an incompressible fluid is constant along a pipe, so we can use it to relate the pressure and velocity before and after the contraction:

A₁v₁ = A₂v₂

where A₁ and v₁ are the area and velocity of the pipe before the contraction, and A₂ and v₂ are the area and velocity of the pipe after the contraction.

We can also use the Bernoulli equation, which relates the pressure and velocity of a fluid along a streamline:

P₁ + 1/2 ρv₁² = P₂ + 1/2 ρv₂²

where P₁ and v₁ are the pressure and velocity of the fluid before the contraction, and P₂ and v₂ are the pressure and velocity of the fluid after the contraction, and ρ is the density of the fluid, which we assume to be constant.

Solving for the pressure and velocity after the contraction, we can use the continuity equation to express v₁ in terms of v₂ and substitute it into the Bernoulli equation:

A₁v₁ = A₂v₂

v₁ = (A₂/A₁) v₂

P₁ + 1/2 ρ((A₂/A₁) v₂)² = P₂ + 1/2 ρv₂²

Simplifying and solving for P₂, we get:

P₂ = P₁ + 1/2 ρ(v₁² - v₂²)

Substituting the given values, we get:

A₂ = (1/3) A₁

v₁ = 5.0 m/s

P₁ = 450000 Pa

ρ = 1000 kg/m³

Using the continuity equation, we can find the value of v₂:

A₁v₁ = A₂v₂

v₂ = (A₁/A₂) v₁

v₂ = 3 × 5.0 m/s

v₂ = 15.0 m/s

Substituting this value into the Bernoulli equation, we can find the pressure P₂:

P₂ = P₁ + 1/2 ρ(v₁² - v₂²)

P₂ = 450000 Pa + 1/2 × 1000 kg/m³ × (5.0 m/s)² - (15.0 m/s)²

P₂ = 450000 Pa - 500000 Pa

P₂ = -50000 Pa

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Can someone please explain why the answer to this net torque question is +115 Nm

Can someone please explain why the answer to this net torque question is +115 Nm

Answers

Answer:

Net torque in positive direction:

Fz = -450 * cos 30 deg * 1.5 = -585 N-M

Fz = 200 * 3.5 = 700 N-M

Net F = 115 N-M

Torque is generally defined as L = R X F

X cross Y = Z     normal coordinate system

Note that Z will be out of the page giving the positive value for the torque.

The mass of an empty density bottle is 2 g. Its mass when filled with water is 4.0 g and 6.0 g when filled with liquid X. Calculate the density of liquid X if the density of water is 1,000 kgm-3.​

Answers

Answer:

density of liquid x = 2000kg/m3

Explanation:

mass of water = mass of bottle with water - mass of bottle

mass of water = 4g - 2g

mass of water = 2g

mass of liquid x = mass of bottle with liquid x - mass of bottle

mass of liquid x = 6g - 2g

mass of liquid x = 4g

since the mass of liquid x is double the mass of the water and the volume of the bottle is the same, the density is doubled

density of liquid x = 1000kg/m3 • 2

density of liquid x = 2000kg/m3

The following three appliances are connected to a 120 volt house circuit: (i) a toaster, 1200 Watts, (ii) a coffee pot, 750 Watts, and (iii) a microwave, 600 Watt. If all operate at the same time, what total current would they draw

Answers

Answer:

They would draw a total of 21.25 amperes

Explanation:

The total power consumed is

1200 W+ 750 W + 600 W= 2550 Watts

The formula relating the power consumed, the voltage and the current is given as

\(P=IV\)---------------1

given that the voltage supply is 120V

\(2550=I*120\\\I=\frac{2550}{120} \\\\I= 21.25amps\)

a fluid that becomes more dense will sink or rise?

Answers

It depends on the liquid the fluid is being put in. If the liquid is more dense than the fluid then it will sink but if the fluid is denser than the liquid then it will float.

if the fluid becomes more dense as it is put in the liquid it can sink as long as it reaches a high spenough density to be denser than this liquid it is in.

The following are four electrical components.
A. A component which obeys ohm's law
B. Another component which obeys ohm's law
but which has higher resistance than A
A filament lamp
C.
D. A component, other than a filament lamp,
which does not obey ohm's law.
a. For each of these components, sketch current-
voltage characteristics, plotting current on the
vertical axis, and showing both positive and
negative values. Use one set of axes for A and
B, and separate sets of axes for C and for D.
label your graphs clearly.
b.
Explain the shape of the characteristic for C
c. Name the component you have chosen for D.

Answers

For the following are four electrical components:

a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.

For the following are four electrical components:

a. Sketches of current-voltage characteristics:

For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

  Current (I)

     ^

     |          B

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

     Current (I)

     ^

     |          A

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.

For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.

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