This demonstrates which of the following?

The light-gathering power of the 3-m diameter telescope compared to the 1-m telescope is 9 times.

The аmount of light cаptured by а telescope's primаry mirror is known аs its light-gаthering power. The аmount of light the mirror cаn collect is proportionаl to the squаre of its diаmeter.

The formulа for the light-gаthering power of а telescope is:

(Diаmeter of Telescope)²

For exаmple, if а 2-meter telescope аnd а 4-meter telescope аre compаred, the lаtter will be four times more powerful becаuse (4/2)² = 4.

Therefore, а 3-meter diаmeter telescope's light-gаthering power compаred to а 1-meter diаmeter telescope is (3/1)² = 9 times more powerful.

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Answer:

21600 p / day

Explanation:

Minutes per day = 24 hr/day  * 60 min/hr = 1440 min/day

1440 min/day * 15 p / min = 21600 p / day

To determine the output of the laser printer in pages per day, we need to know how many minutes the printer operates in a day. The printer can print, 21600 pages a day.

First, need to convert the printer's speed from minutes per page to pages per hour. Since the printer can print 15 pages in 1 minute, it can print 60 * 15 = 900 pages in 1 hour.

Next, you need to calculate how many pages the printer can print in 24 hours. Multiplying the printer's speed (900 pages per hour) by the number of hours it operates in a day (8 hours) gives us 900 * 24 = 21600 pages per day. Therefore, the printer's output in pages per day is 21600 pages.

To conclude, if the laser printer can print 15 pages per minute and operates for 24 hours a day, it can print 21600 pages per day.

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Answer:

C. Exothermic Reaction

Explanation:

Let's go through the choices

A. Combustion - Combustion is a highly exothermic / redox reaction which produces light and heat (i.e basically it bursts into flames). In the description, the only reaction is that it feels warm, hence this is not the answer.

B. Endothermic - Recall that endothermic reactions absorbs heat and thus cools the surroundings thereby making test tube feel cooler. this is obviously not the case so this is not the answer.

C. Exothermic - Recall that exothermic reactions releases heat and thus causes the surroundings thereby making the test tube feel warmer (or hotter in some cases). This describes our situation so THIS IS THE ANSWER.

D. Endergonic reactions require an input of energy from an external source that is adsorbed by the reaction (for example if heat was applied by an external source). In this case, there is no mention of additional energy sources. Hence this is probably not the answer.

Answer:

h = 0.047 m

Explanation:

It is given that,

Radius of an air bubble is 0.0003 m

The surface tension of water is \(7\times 10^{-2}\ N/m\)

We need to find the depth at which an air bubble of radius 0.0003 m will  remain in equilibrium in water. Let it is given by h.

Pressure due to surface tension is given by :

\(P=\dfrac{2T}{R}\) .....(1)

T is surface tension

Also, pressure due to a height is given by :

\(P=\rho gh\)

So, equation (1) becomes :

\(\rho g h=\dfrac{2T}{R}\)

So,

\(h=\dfrac{2T}{\rho gR}\)          

\(h=\dfrac{2\times 7\times 10^{-2}}{10^3\times 9.8\times 0.0003}\\\\h=0.047\ m\)

So, the depth is 0.047 m.

Answer:

180 because it's half of a full rotation before they shoot the other person.

Answer:

Below

Explanation:

384 400 km / 300 000 km/s = 1.28 seconds

(i) The hydraulic gradient is 0.45.

(ii) The flow rate is approximately 0.00000167 cubic meters per second.

(iii) The hydraulic conductivity is approximately 0.000037 meters per second.

(i) Hydraulic gradient:

The hydraulic gradient (i) can be calculated by dividing the head difference (h) by the distance (L) between the manometer tappings:

i = h / L

Given:

Head difference (h) = 45 mm

Distance between manometer tappings (L) = 100 mm

Converting the units to meters:

h = 45 mm / 1000 = 0.045 m

L = 100 mm / 1000 = 0.1 m

Substituting the values into the formula:

i = 0.045 m / 0.1 m = 0.45

(ii) Flow rate:

The flow rate (Q) can be calculated using the equation:

Q = (V / t) / A

Where V is the quantity of water collected, t is the duration of the test, and A is the cross-sectional area of the test sample.

Given:

Quantity of water collected (V) = 500 ml = 0.5 L

Duration of test (t) = 300 seconds

Diameter of test sample (d) = 100 mm

Converting the units to meters:

V = 0.5 L = 0.5 / 1000 = 0.0005 m³

t = 300 seconds

d = 100 mm / 1000 = 0.1 m

Calculating the cross-sectional area (A) using the formula for the area of a circle:

A = π * (d/2)^2

Substituting the values:

A = π * (0.1/2)^2 = π * 0.005^2 = 0.00007854 m²

Substituting the values into the formula for flow rate:

Q = (0.0005 m³ / 300 s) / 0.00007854 m²

Calculating the flow rate:

Q = 0.00000167 m³/s

(iii) Hydraulic conductivity:

The hydraulic conductivity (K) can be calculated using Darcy's Law:

K = Q / (A * i)

Given the values we calculated:

Q = 0.00000167 m³/s

A = 0.00007854 m²

i = 0.45

Substituting the values into the formula:

K = 0.00000167 m³/s / (0.00007854 m² * 0.45)

Calculating the hydraulic conductivity:

K ≈ 0.000037 m/s

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The acceleration of the skateboarder is 2.33 m/s².

Initial velocity of the skateboarder (U) = 7 m/s

Time taken by the skateboarder ( t ) = 3 s

Final velocity of the skateboarder (V) = 0 m/s

Using the equation, V = U + a × t

= 0 = 7 + a × 3

= - 7 = 3 × a

= a = (- 7) / 3

= a = ( - 2.33 ) m/s²

The acceleration of the skateboarder was 2.33 m/s². The negative sign indicates that he was decelerating.

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If someone would like to lease state-owned lands for oil and gas production, they should negotiate with the appropriate government agency responsible for managing the lands.

In the United States, this agency is typically the Bureau of Land Management (BLM), which manages millions of acres of federal lands, including lands with potential for oil and gas development. The BLM offers competitive leasing programs that allow individuals and companies to bid on leasing rights for specific parcels of land. The leasing process typically involves submitting an application, conducting an environmental analysis, participating in a lease sale auction. Ultimately, negotiation and leasing of state-owned lands for oil and gas production is subject regulations and oversight by  government agency responsible for managing  lands.

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The event that is possible when you toss a number cube labelled 1 to 6 is getting a number less than 7.  

It is certain that you will get a number less than 7 if you roll a number cube with the numbers 1 through 6. There are six possible outcomes for this scenario (all the numbers from 1 to 6). The likelihood of "receiving less than 7" is therefore 6 / 6 or 1.

Generally speaking, a probability of 0 denotes an event's impossibility while a probability of 1 denotes an event's certainty of occurring.

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Disadvantage of nuclear power is . Nuclear power produces radioactive waste and creates a potential for disaster. This is nuclear pollution .

The generation of radioactive wastes such spent (used) reactor fuel, uranium mill tailings, and other radioactive wastes is a significant environmental hazard associated with nuclear power. Over millions of years, these substances may continue to be radioactive and hazardous to human health.

Low-enriched uranium fuel is used in nuclear power plants to generate electricity through a process known as fission, which is the splitting of uranium atoms in a nuclear reactor. Small, dense ceramic pellets used as uranium fuel are stored in protracted, vertical tubes. Bundles of this fuel are put within the reactor in bundles.

Smaller than a pencil eraser in size, a single uranium pellet has the same amount of energy in it as a ton of coal, three barrels of oil, or 17,000 cubic feet of natural gas. A single pellet of uranium fuel can generate heat for electricity production for up to five years. Yet since uranium is one of the most plentiful metals in the world, it can continue to fuel commercial nuclear power plants for many years to come.

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Answer:

C

Explanation:

Edge 2023

Answer:

They have mass is always true.

Answer:

“they have mass” because if they don’t have mass they can’t exert force even if they have speed if they have no mass they can’t do anything or exert force

Explanation:

Answer:

1299N

Explanation:

GIven data

Weight W= 1500N

Angle Ф= 30°

The applied force up the frictionless ramp is gotten by applying the formula below

F= WcosФ

substitute

F=1500 cos 30

F = 1500*0.8660

F= 1299N

Hence the applied force is 1299N

Answer: because there is no displacement or movement in the watchman's work. According to science when displacement or movement take place it is said to be work. Jul 9, 2020

Hope it helps!

The angular velocity is θ" = 0.302rad/s

Given data,

r = 100cos(2θ)

r = -200sin(2θ)θ"

For angular velocity,

\(v = \frac{dr}{dt} u^{r} +r\frac{dθ}{dt}\)

\(v = \sqrt{\frac{dr}{dt} } ^{2} + \sqrt\frac{rdθ}{dt} ^{2}\)

So, v = 20m/s

\(20 = \sqrt{} [-200sin(2θ)θ" + \sqrt{} [100cos(2θ)θ"\)\(]^{2}\)

\(400 = [-200sin(2*15)θ']^{2} + [100cos(2*15)θ']^{2}\)

On solving for angular velocity, we get

θ" = 0.302rad/s

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Answer:

0.8

Explanation:

Cosine is the adjacent over the hypotenuse. Using this we can solve.

cosC = A / H = 16 / 20 = 4 / 5 = 0.8

The potential energy of the crate with respect to the ground is 3×10⁴ J, and the mass of the crate is 153.1 kg.

This is the energy of a body by virtue of it position in the gravitationla field.

The potential energy of the crate with respect to the ground is the same as the amount of work needed to lift the crate to a height of 20m.

From the question,

Also,

To caluclate the mass of the crate, we use the formula below.

Formula:

Where:

From the question,

Given:

SUbstitute these values into equation 1

Hence, the Potential energy and the mass of the crate is 3×10⁴ J

and 153.1 kg respectively.

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Answer:

As its speed increases.......

The kinetic energy of an object increases as its speed increases. So, option B.

The type of energy that an object possesses as a result of its motion is called kinetic energy.

The kinetic energy of an object is described as the amount of effort required to accelerate a body of a specific mass from rest to its specified velocity.

The body keeps its kinetic energy after gaining it during acceleration, barring changes in speed.

When slowing down from its current pace to a condition of rest, the body expends the same amount of energy.

A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

The kinetic energy of the object,

KE = 1/mv²

where m is the mass and v is the speed of the object.

Since, the mass is a constant, the increase in speed can increase the kinetic energy of the object.

Hence,

The kinetic energy of an object increases as its speed increases.

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E=26.5mV/m=0.0265V/m is the electric field in an electromagnetic wave. As a result, S=9.32 x 10 W/m² represents the average rate at which this wave transfers energy across unit area per unit time.

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Answer:

The answer should be 0.825

Explanation:

I took like 20 mins to figure this out lol

Answer:

C

Explanation:

The distance that the pig moves up will be less than the distance that the strongman pulls down.

Explanation: The strongman is further from the fulcrum than the pig is, so the distance that he pulls down will be greater than the distance that the pig moves up.

The distance that the pig moves up will be less than the distance that the strongman pulls down. Hence, option (C) is correct.

The given problem is based on the work done by the applied force. When some magnitude of force is applied on any object, then there will be some obvious displacement of object. This is known as work done by the object. The expression for the work done by the object is,

w = Fd

here, F is the applied force and d is the displacement.

In the given problem, the applied force will be due to the weight of man and pig. So, the modified form of work done is,

work = Wd

W = work/d

here, W is the weight.

Clearly, more the weight, less will be the displacement and vice versa. So due to heavy weight of man, he will pull the pig easily. Such that the upward distance covered by pig will be less than the distance that the strongman pulls down.

Thus, we can conclude that the distance that the pig moves up will be less than the distance that the strongman pulls down. Hence, option (C) is correct.

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The length of the rubber band that the boy must use is 0.024 m or 24 mm.

To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:

where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.

Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.

We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):

where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:

k = (v² M) / (2 m)

We can now combine the two equations to solve for the length of the rubber band, L:

U = 1/2 k x²

U = 1/2 ((v² M) / (2 m)) (0.25 L)²

U = (v² M L²) / (32 m)

The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:

U = 1/2 M v²

(v² M L²) / (32 m) = 1/2 M v²

L = ((16 m v²) / (k M))

L = ((16 m v²) / ((v² M) / (2 m) M))

L = √(32 m^2 / M)

L = (0.032 M)

Substituting the given values, we get:

L = √(0.032 * 0.006)

L = 0.024 m

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Answer:

Comfortable, skimming workout clothes that are not baggy.

You also need white coloured clothes that reflect heat so that you don't get all hot and sweaty easily.

Shells are the orbits in which electrons move with high velocities. The number of shells in an element also indicates the Period number.

The nucleus is in the centre of the element. It holds the protons and neutrons.

Shells: Shells or orbits are circular paths around the nucleus in an atom in which the electrons revolve.

Nucleus: It is the center of an atom that contains protons and neutrons.

The difference between Shell and nucleus is-

1. Nucleus is primarily composed of both proton and neutron that is positively and negatively charged particles while the shell is composed of only electrons that are negatively charged particles.

2. The probability of finding an electron in the nucleus is negligible while the probability of finding an electron in shells is maximum. Electrons occupy different shells based on their energy levels.

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Answer:

remains the same

Explanation:

Momentum refers to the quantity of motion of a body. When any body of mass moves, it possess momentum. Numerically,

Momentum =  mass x velocity

i.e. momentum is the product of the mass x velocity

Momentum of a body is always conserved.

In the context, the skateboard has certain momentum before Freddy lands on it. After Freddy lands, the momentum of skateboard remains the same, there is no change in the momentum.

This is because, here the momentum is conserved. After Freddy lands on the skateboard, the total mass on the skateboard increases and so the velocity decreases making the momentum same before the landing.

Answer:

\(a=155.750\ m/s^2\)

Explanation:

It is given that,

A small rock is shoot at Dennis' neighbor's flowerpots. The rock travels a distance of 12.5 cm from the point at which he pulls it back to the point at which it leaves the slingshot.

Final velocity of the rock, v = 6.24 m/s

The initial velocity of the rock, u = 0 (as it was at rest)

Let a is the acceleration of the rock. It can be calculated using the equation of kinematics as follows :

\(v^2-u^2=2ad\\\\\text{Put u = 0 }\\\\v^2=2ad\\\\a=\dfrac{v^2}{2d}\\\\a=\dfrac{(6.24)^2}{2\times 12.5\times 10^{-2}}\\\\a=155.750\ m/s^2\)

So, the average acceleration of the rock is \(155.750\ m/s^2\).

Using the gravitational force of F= G(m1*m2/r^2)

m1= 5.97 x 10^24 kg (Earth)

m2= 1.99 x 10^30 kg (Sun)

r= 1.48 x 10^11 m

G is a known value, it is 6.672 x 10^-11

All units are proper. Therefore plug in the values and you get 3.16 x 10^22 N.

Let me know if I calculated this wrong and it is something else so I can delete this. Thank you. I don't want to make other students put down the wrong answer.

Answer:

\(\boxed {\boxed {\sf F_g \approx 3.62 *10^{22} \ N}}\)

Explanation:

We are asked to find the gravitational force between Earth and the Sun. Use the following formula:

\(F_g= \frac{Gm_1m_2}{r^2}\)

G is the universal gravitational constant. One mass (m₁) is the Earth and the other (m₂) is the Sun. r is the distance between the planets.

Substitute the values into the formula.

\(F_g = \frac{ (6.67*10^{-11} N*m^2/kg^2)(5.97*10^{24} \ kg)(1.99*10^{30} \ kg) }{ (1.48 *10^{11} \ m)^2}}\)

Multiply the numerator. The units of kilograms cancel.

\(F_g = \frac {7.9241601 *10^{44} \ N*m^2}{ (1.48 *10^{11} \ m)^2 }\)

Solve the exponent in the denominator.

\(F_g= \frac {7.9241601 *10^{44} \ N*m^2}{ 2.1904*10^{22} \ m^2}\)

Divide. The units of meters squared cancel.

\(F_g=3.61767718 *10^{22} \ N\)

The original values all have 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 7 in the thousandth place tells us to round the 1 up to a 2.

\(F_g \approx 3.62 *10^{22} \ N\)

The gravitational force between Earth and the Sun is approximately 3.62 *10²² Newtons.