Thirty newborn babies are used for a study where gender and height/length (in inches) is recorded. JMP Applet imo ? Oneway Analysis of Length By Gender DIE 23 22 Length 20 Gender Pooled Test Summary of Fit Rsquare Adj Rsquare Root Mean Square Error Mean of Response Observations (or Sum Wgts) 0.015817 -0.01933 1224745 20.95 30 1 Test M-F Assuming equal variances Difference -0.3000 t Ratio -0.67082 Assuming equal variances Difference 0.3000 t Ratio Sid En Dil 0.4472 DF Upper CL Dit 0.9358 Prob Lower CL Dil -1.5358 Prob > 1 Confidence 0.99 Prob -0.67082 28 0.5078 0.7461 0.2539 -1.5 -10 -05 00 05 10 15 Analysis of Variance Source DF Sum of Squares Mean Square F Ratio Prob>F Gender 1 0675000 0.67500 0.4500 0.5078 Error 28 42.000000 1.50000 C. Total 29 42.675000 Means for Oneway Anova Level Number Mean Std Error Lower 99% Upper 99% F 15 21.1000 0.31623 20.226 21.974 M 15 20 8000 0.31623 19.926 21.674 Std Error uses a pooled estimate of error variance Means and Std Deviations Level Number Mean Std Dev Std ErrMean Lower 99% Upper 99% F 15 21.1000 131203 0.33877 20.092 22.108 M 15 20 8000 113074 0.29196 19.931 21.669 vt Test M-F Assuming unequal variances Difference -6 3000 t Ratio Std Err Dif 0.4472 DF Upper CL DI 0.9377 Prob > Lower CL Dit -1,5377 Prob > Confidence 0.99 Prob
Answers
It seems that you have provided the output of a statistical analysis conducted in JMP Applet, where the goal was to test if there is a difference in length (in inches) between male and female newborn babies.
Based on the output, it appears that the study included 30 newborn babies, with 15 males and 15 females. The analysis conducted was a one-way analysis of variance (ANOVA) with gender as the independent variable and length as the dependent variable.
The ANOVA results show that the F-ratio is 0.45, with a corresponding p-value of 0.5078. This suggests that there is no significant difference in length between male and female newborns.
The output also includes means and standard deviations for each gender. The mean length for females is 21.1 inches with a standard deviation of 1.31 inches, while the mean length for males is 20.8 inches with a standard deviation of 1.13 inches.
Additionally, the output includes t-tests assuming equal and unequal variances. The results suggest that there is no significant difference in length between male and female newborns, regardless of whether the variances are assumed to be equal or unequal.
Click the below link, to learn more about JMP amplet analysis:
https://brainly.com/question/27189686
#SPJ11
Related Questions
Which of the following is monocotyledonous seed? / खालीलपैकी एकबीजपत्र असणारे बी कोणते ?
sunflower / सूर्यफूल
lentils / मसूर
beans / घेवडा
maize / मका
Answers
lentils is monocotyledonous
Students filled two beakers with 500 mL of water each. They placed three drops of live algae culture into each of the beakers, then used a dissolved oxygen sensor to measure the oxygen content of the water in each beaker. The students then stirred 5 mL of nitrogen-rich fertilizer into one of the beakers, and labeled the beaker A. Nothing was added to the second beaker, which the students labeled B. Both beakers were placed under a high-intensity light over a weekend. On Monday, the students measured the amount of oxygen in the water of each of the beakers. Which aspect of the watershed were these students trying to model?
A. The effect of fertilizer-contaminated surface water flowing as runoff into a waterway
B. How stagnant or non-flowing water can result in providing a habitat for living organisms such as algae
C. The inverse relationship between water, light, oxygen, and photosynthesis
D. How light and oxygen levels in water affect the growth of algae within a system over time
Answers
D. How light and oxygen levels in water affect the growth of algae within a system over time
What is the population density?
Answers
which of the following characteristics is associated with organisms that provide significant parental care to offspring?
Answers
The characteristic associated with organisms that provide significant parental care to offspring is that they typically have fewer offspring with higher survival rates.
This is because parental care requires a significant investment of time and energy, and organisms that engage in this behavior are typically more invested in the survival of their offspring. By providing care, parents can help their offspring to survive and increase their chances of successfully reproducing, thus ensuring the continuation of their genetic lineage. In contrast, organisms that produce large numbers of offspring with little or no parental care often have lower survival rates, but can increase their chances of passing on their genes by producing a large number of offspring. Therefore, the trade-off between quality versus quantity of offspring is an important consideration in understanding the evolution of parental care behaviors.
To know more about survival rates
brainly.com/question/31816400
#SPJ11
10
Which term refers to the loss of fertile soil from drying out?
erosion
desertification
depletion
overuse
Answers
Answer:It’s desertification, I’m taking the unit test right now.
Explanation:
Answer:
desertification
Explanation:
PLEASEEE HELP ASAP! BRAINLIST GETS 80 POINTS!!!!!!!!!!
04.02 Environmental Resources Lab Report
Instructions: For this lab, use the lab report to record your information. You will submit your completed lab report.
Note: If you cannot complete this lab as directed, please contact your instructor for assistance.
Name and Title:
Include your name, instructor's name, and date.
Introduction
To improve your soil, you should first know what you’re starting with. In this lab, you will sample local soil to determine its composition and pH range.
Materials
• Distilled water
• Metric ruler
• Small zipper storage bag
• Soil from the yard, garden, or other local source
• Jar with tightly fitting lid (tall and skinny would be best)
• Small digging tool
• pH strips (available at hardware and pool supply stores) or vinegar and baking soda
Pre-lab Questions
1. Describe soil particles (sand, silt, and clay) in term of size and texture.
2. If soil is too acidic, what substance is usually added? If soil is too alkaline, what substance is usually added?
3. Why are soil composition and pH important to know?
Hypothesis
Predict what type of soil you think is in your local area (mostly sand, silt, clay, or mixed) and if it more acidic, more alkaline, or neutral.
Procedure
Obtaining soil samples for your jar and resealable bag
1. Take your jar, resealable bag, and digging tool into your garden or yard. Use the digging tool to dig a hole 3–6 inches deep. Take your soil sample from the soil at this depth.
2. Place approximately one cup of soil into the resealable bag, squeeze the air out of the bag, and zip it shut (you will use this soil later in the lab).
3. Dig up additional soil and fill the jar to approximately 1/4 full of soil. Take everything back inside to your work area.
Note: To avoid making a mess, it is best to work on a covered surface (for example, a kitchen counter covered with old newspaper or plastic wrap).
4. Fill the remaining space in the jar with water, and screw the cap on tightly (see Figure 1, below).
5. Shake the jar so that the dirt is totally dispersed through the water (see Figure 2, below). Set down the jar and allow the shaken contents to settle completely (see Figure 3, below). Leave it undisturbed overnight while you test the texture and pH of the soil in your resealable bag.
Note: Do not pick up the jar. Doing so will begin to mix the contents again.
Figure 1 Figure 2 Figure 3
Fill jar 3/4 full of water and 1/4 full of soil. With the lid on tightly, shake the jar well until the soil and water have mixed thoroughly. Let the jar sit. Materials will begin to settle out and form layers.
Testing texture and pH of the soil in your resealable bag
1. While you wait for the soil and water sample to settle in the jar, you can test the texture of the sample in the resealable bag. First, remove a small amount and moisten it slightly to test the texture. Record your observations in the Data and Observations section.
a. Rough and gritty soil that barely sticks together is sand.
b. Loams (mixtures of clay, silt, and sand) feel medium-textured.
c. Smooth and sticky fine textures indicate clay.
2. Next, test the pH using one of the following methods:
a. If you have pH strips: To test with pH strips, place the soil sample in a small bowl or container and add a small amount of distilled water. Add just enough water to make the soil slightly liquid, like a milkshake consistency. Dip the pH strip in and compare it to the color identification provided with the test strips. Record your data in the Data and Observations section.
b. If you do not have pH strips: Use vinegar and baking soda instead. To do this, split the sample into two containers. Add a half cup of vinegar to the first sample of soil, mix gently, and watch to see if it bubbles or fizzes. If it does, it is alkaline. In the second container, add a half cup of distilled water to the soil and mix gently. Then add a half cup of baking soda. If there is a reaction of bubbles or fizzing, the soil is acidic. If neither sample has a reaction, the soil is neutral. Record your data in the Data and Observations section.
Testing soil sample in your jar
1. For the sample in the jar, wait until after the contents have settled and you can see several different-colored layers. In addition, you may see some material floating at the top of the water. You may also see that the water is still clouded with some particles.
2. Measure the total thickness of the soil in the jar after it settles. Record this measurement (in centimeters) in the data table.
3. Observe the settled dirt carefully. There should be distinct layers of soil. The bottom will be your sand layer (largest particles fall out first), then clay or silt, depending on the kind of soil you have. Carefully measure the thickness of any layers of soil seen in your jar. Record your measurements in centimeters (cm) in the data table. Also record the color of each layer.
Answers
What is the difference between Protostome and Deuterostome?
Answers
The main difference between Protostome and Deuterostome is in the development of the embryonic gut. Protostomes develop the mouth first while Deuterostomes develop the anus first.
Protostomes and Deuterostomes are two major groupings of animals that differ in their embryological development. Protostomes have an opening (blastopore) that becomes the mouth, and the anus forms later. Deuterostomes have an opening that becomes the anus and the mouth forms later.
Protostomes include animals such as insects, mollusks, and annelids. Examples of deuterostomes include echinoderms, chordates, and hemichordates.
In Protostomes, the first opening in the embryo, called the blastopore, develops into the mouth. The second opening that forms becomes the anus. In Deuterostomes, the blastopore develops into the anus and the second opening becomes the mouth.
Additionally, Protostomes have spiral cleavage while Deuterostomes have radial cleavage during embryonic development. Protostomes also have determinate cell fate, meaning that the fate of each cell is determined early on in development. Deuterostomes have indeterminate cell fate, meaning that cells can become any type of cell until a later stage of development.
To learn more about protosome:
https://brainly.com/question/823820#
#SPJ11
It's impossible for vegetarians to get all the nutrients they need.
O A.
True
OB.
False
Answers
Answer: A
Explanation: there is a variety of things they can eat. Being vegetarian would not be a thing if they could not survive.
Answer:
b. false
Explanation:
. what forced brother and sister mating in the birds? would you expect generations after this even to be more or less diverse? explain your reasoning.
Answers
Wiping of all the family on the island for four generations is the string reason for brother and sister mating in birds.
The behavioural sequester you would expect the generations following this to be more dissimilar. The concept of a species is sufficiently apparent in some situations. Animals can be categorised based on their outward appearance, such as humans, gigantic pandas, or sunflowers, without the help of a biologist.
When the species in question have distinct physical differences from one another, this system functions effectively. If you truly wanted your glasses, you probably wouldn't confuse a panda for a sunflower. Animals can be categorised based on their outward appearance, such as humans, gigantic pandas, or sunflowers, without the help of a biologist.
Learn more about mating in birds at
https://brainly.com/question/14377613
#SPJ4
Using the information you learned in the CRISPR interactive, match the following vocabulary with their respective definitions.
Column A
1.
Targeting:
2.
Binding:
3.
Cleaving:
4.
DNA Repair:
Column B
a. The Cas9 unwinds the DNA double helix to a location that perfectly matches a sequence of 20 nucleotides within the guide RNA. the DNA and matching RNA bind through complementary base pairing.
b. The Cas9-guide RNA complex is introduced into a cell, in which it randomly dissociates with the DNA.
c. Cells contain enzymes that repair double-stranded DNA breaks
d. This step causes the 3D structure to cut DNA strands at a site and upstream.
Answers
The complementary base pairing rule, which states that Adenine must always pair with Thymine and Guanine must always pair with Cytosine, holds the double helix shape of DNA together.
What is CRISPR?
Thousands of genes that can lead to illness disorders in our bodies have been found by researchers.
Small guide RNA first forms a complex with the protein CAS9 endonuclease. The Cas9/sgRNA complex that results from this binds the PAM sequence found in the target DNA. Cas9 unzips DNA upon interacting with the PAM sequence.
Therefore, the small guide RNA (sgRNA) in the CAS9 complex combines with the target DNA to form a hybrid. Cas9, which snips the target DNA, detects this hybridization.
Learn more about CRISPR, here:
https://brainly.com/question/29566768
#SPJ1
The thylakoid membrane contains a protein called atp synthase. As hydrogen ions pass through the protein, adp and a phosphate group are combined to form atp. What is the direct energy source, if any, for the movement of hydrogen ions and the formation of atp? a. The energy source is the high-energy electrons that accompany the hydrogen ions. B. The energy source is the concentration difference of hydrogen ions across the membrane. C. The energy source is a set of atp molecules that gather inside the thylakoid. D. There is no energy source; the process occurs without an energy input.
Answers
The energy source is the concentration difference of hydrogen ions across the membrane.
The photochemical and electron transport reactions of oxygenic photosynthesis occur at the thylakoid membrane. The lipid composition of the thylakoid membrane is highly conserved among oxygenic photosynthetic organisms, with two galactolipids, one sulfolipid, and one phospholipid.
The primary functions of thylakoids are to trap light energy and convert it into chemical energy forms such as ATP and NADPH. Water is oxidized and oxygen is released during this process. Inside chloroplasts and cyanobacteria, thylakoids are membrane-bound compartments. They are the site of photosynthesis's light-dependent reactions. Both stages of photosynthesis involve the chloroplast. The light reactions occur in the thylakoid.
To learn more about thylakoid membrane, here
https://brainly.com/question/9122983
#SPJ4
There are too many potassium ions inside a cell. As a result the cell membrane expands in bursts. Which problem was the cell most likely having
Answers
Answer:
The cell was unable to maintain a stable internal environment.
Your welcome ;D
Explanation:
whats the answer to this questgion
Answers
A random mutation caused an individual bacteria to be resistant to antibiotics. The bacteria survived the antibiotics and reproduced. Option B.
How do bacteria develop resistance to antibiotics?Bacteria can develop resistance to antibiotics through mutations in their DNA. These mutations can occur spontaneously or as a result of exposure to antibiotics or other stressors.
Individual bacteria with the mutation are able to survive the antibiotic treatment. Natural selection favors the mutated trait and mutated bacteria survive and produce more.
With time, the individual bacterium that cannot withstand the antibiotic dies off the population, leaving those that are resistant to the antibiotics.
More on antibiotic resistance can be found here: https://brainly.com/question/10868637
#SPJ1
how does comparing the skeletons of these animals provide support for the scientific theory of evolution
Answers
Comparing the skeletons of different animals provides compelling evidence that supports the scientific theory of evolution. By examining the anatomical structures and bone arrangements of various species.
Scientists can identify patterns that reflect common ancestry and gradual change over time. One way skeletons provide evidence for evolution is through the presence of homologous structures. Homologous structures are similar in form but may serve different functions in different organisms.
For instance, the pentadactyl limb structure, characterized by five digits, is found in a variety of vertebrates, including humans, bats, whales, and birds. This similarity suggests a common ancestor with a limb structure that has been modified for different purposes.
Learn more about species here:
https://brainly.com/question/9506161
#SPJ11
Would you expect the frequencies of the alleles for PTC tasting and non-tasting to remain constant for North America over the next 200 years? Use what you know about the Hardy-Weinberg equation and the five conditions.
Write your answer here.
And I konw the answer , I just want let you guys can find it. caus I use longtime to do this work. the answer is right there
- Yes, frequencies of the allele for PTC tasting and non-tasting should remain constant for North America over the next 200 years. because it meets all the requirements necessary for Hardy-Weinberg equilibrium.
We know that when a population is in Hardy-Weinberg equilibrium it is not evolving, and allele frequencies will stay the same across generations. there are 5 conditions for population is in Hardy-Weinberg equilibrium.They are- no mutation, no gene flow, infinite population size, no natural selection and random mating. we will see how this meets all the requirements.
No mutation- yes mutation rates of the allele are very low.
No gene flow- only large migrations can change the frequencies of allele.
Infinite population size- yes population is large.
No natural selection- there is no known natural selection of the allele.
Random mating - yes mating is random because people in North America will not mate on the basis of ability to tasting PTC.
So frequencies of the allele for PTC tasting and non-tasting should remain constant for North America over the next 200 years.
Answers
Answer:
The Hardy-Weinberg equilibrium is a principle that describes the genetic makeup of a population that is not evolving. When a population is in Hardy-Weinberg equilibrium, the frequencies of alleles and genotypes remain constant over time. This principle is based on five key conditions, which include no mutation, no gene flow, infinite population size, no natural selection, and random mating.
In the case of the PTC tasting and non-tasting alleles in North America, it is reasonable to assume that these conditions are being met. First, there is no evidence to suggest that the mutation rate of the allele for PTC tasting and non-tasting is high, and therefore, we can assume that this condition is met. Second, gene flow, which is the movement of alleles between populations, is not likely to have a significant impact on the frequencies of these alleles, given that North America is a large population and there are no significant barriers to migration within the continent.
Third, the population size of North America is indeed large, and so it can be assumed that the condition of an infinite population size is being met. Fourth, there is no known natural selection that would favor one allele over the other, and therefore, this condition is met as well. Lastly, random mating is expected to occur in North America, as individuals are likely to mate randomly without any preference for the ability to taste PTC.
Based on these five conditions, we can conclude that the frequencies of the allele for PTC tasting and non-tasting should remain constant for North America over the next 200 years, as the population is expected to be in Hardy-Weinberg equilibrium. This means that the proportion of individuals who can taste PTC versus those who cannot taste it is likely to remain constant, barring any unforeseen factors that would disrupt the equilibrium.
P.S Can I get brainliest for making a whole essay? haha
difference between pendulum clock and quartz watch.. plz give photo
Answers
Answer:
A pendulum clock is a mechanical device. It relies on a pendulum swinging at a steady pace, with energy to the pendulum provided by a spring. ... A quartz clock relies on the exactly repeating vibration of a thin sliver of quartz. This vibration creates an electrical current that controls the electronic display.
Explanation:
heres some photos
Use The image below to answer question I’m with appropriate vocabulary.
Explain what would happen to the abiotic and biotic components of this System if beavers were removed.
Answers
If beavers were removed from the ecosystem in the image, both abiotic and biotic components would have substantial effects on both abiotic and biotic components, these changes could lead to a loss of biodiversity and negatively impact the stability of the ecosystem.
In terms of abiotic components, water flow and sedimentation might change. Beavers build dams, which slow down water flow and create ponds, without the dams, water flow would increase, potentially causing erosion and altering the sediment composition in the area. For the biotic components, there would be a significant impact on the plants and animals in the ecosystem, the absence of beaver dams could result in the loss of wetland habitat, affecting plant species adapted to those conditions. Aquatic plants might decline, impacting the availability of food and shelter for various organisms.
The absence of beavers would also affect animals that rely on beaver-created habitats. Species like ducks, frogs, and fish that depend on the slow-moving water created by beaver dams might decline in number. Additionally, predators like wolves and bears that prey on beavers would need to find alternative food sources. In summary, removing beavers from the ecosystem would have substantial effects on both abiotic and biotic components. These changes could lead to a loss of biodiversity and negatively impact the stability of the ecosystem.
Learn more about abiotic components here:
https://brainly.com/question/13500413
#SPJ11
which of the following is not a property of conditioned muscles? group of answer choices they can store more glycogen. they rely less on glucose and more on fat breakdown for energy. they are resistant to lactate build-up. glycogen breakdown occurs more slowly. they contain more mitochondria.
Answers
The statement which is not a property of conditioned muscles is b. they rely less on glucose and more on fat breakdown for energy.
Muscles that have been regularly exercised and become conditioned demonstrate a variety of physiological changes that enhance their capacity for performance and endurance. Increased glycogen storage, the main source of energy for muscles during exercise, is one of these adaptations. Additionally, they are resistant to lactate buildup, which can lead to exhaustion and pain in the muscles.
There are more mitochondria, and they are in charge of generating energy within the muscle cells. faster depletion and more effective glycogen breakdown during exercise. However, conditioned muscles do not normally rely on fat breakdown for energy during exercise. Long-term exercise can cause the body to use fat as a source of energy, this is not a characteristic of conditioned muscles per se, but rather a result of the body's normal energy metabolism.
Complete question:
which of the following is not a property of conditioned muscles?
a. they can store more glycogen.
b. they rely less on glucose and more on fat breakdown for energy.
c. they are resistant to lactate build-up.
d. glycogen breakdown occurs more slowly. they contain more mitochondria.
Read more about conditioned muscles on:
https://brainly.com/question/2413871
#SPJ4
the deepest layer of cells in the epidermis is the cells of the
Answers
The deepest layer of cells in the epidermis is the cells of the Stratum Basale, which are attached to the basement membrane by hemidesmosomes.
Skin the uppermost layer of the body which protects the internal organs from infection, higher order injury etc. There are three layers of cells beneath the skin namely the epidermis, hypodermis and dermis. The epidermis is the thinnest layer and is present just below the skin.
The stratum Basale is also called as stratum germinativum. It is a single layer of cuboidal or columnar cells that rests on the basement membrane. In this portion the stem cells are located. Merkel cells are oval-shaped modified epidermal cells found in the stratum Basale. These cells perform several functions such as mechanoreceptors for light touch, sensory effects etc.
Learn more about stratum Basale at:
brainly.com/question/14085451
#SPJ4
(ii) Explain whether the nitrate ions are taken up by the root by diffusion, active transport or both
processes. Justify your answer.
Answers
Answer:
Only by active transport.
Explanation:
This is because diffussion is possible only with gases and the nitrate ions passes through nitrogen fixing bacterials known as azotobacta.
please help me out. thanks:)
Answers
Answer:
I belive the answer is b
a cell with a diploid number of 20 undergoes meiosis. this will produce _____ daughter cells
Answers
A cell with a diploid number of 20 undergoes meiosis. This will produce four daughter cells. Meiosis is a special type of cell division that generates haploid gametes for sexual reproduction in eukaryotes.
Chromosomes are duplicated and divided twice during meiosis, resulting in four daughter cells that each have half the number of chromosomes as the original cell. This halving of chromosome number is critical for sexual reproduction, as it allows for the combination of genetic information from two parents.
In meiosis, diploid cells divide to produce haploid cells. Diploid cells have two sets of chromosomes, whereas haploid cells have only one set of chromosomes. The process of meiosis in eukaryotes reduces the chromosome number from the diploid to the haploid number.
Learn more about chromosome
https://brainly.com/question/30077641
#SPJ11
producers and microorganisms are able to use sulfur easiest if it is in what form? question 4 options: sulfide sulfhydryl group hydrogen sulfide sulfate
Answers
Producers and microorganisms are able to use sulfur the easiest if it is in sulfate form.
Producers, microbes, and sulfateProducers and microorganisms are able to use sulfur the easiest if it is in the form of sulfate. Sulfate is a stable and readily available form of sulfur in many environments.
Producers, such as plants, and various microorganisms have the ability to take up sulfate and utilize it in metabolic processes. Sulfate can be converted into organic compounds containing sulfur through enzymatic reactions within these organisms.
While other forms of sulfur like sulfide, sulfhydryl groups, and hydrogen sulfide may also be utilized by specific microorganisms in different contexts, sulfate is generally the most easily accessible and commonly utilized form of sulfur in biological systems.
More on sulfates can be found here: https://brainly.com/question/31558225
#SPJ1
What would you expect to occur if you streaked 1/2 of an agar plate with S. epidermidis and the other half with Penicillium and then incubated for one week
Answers
**S. epidermidis** growth would be expected on one half of the agar plate, while **Penicillium** growth would appear on the other half after incubating for one week.
When streaking half of the agar plate with S. epidermidis, a type of bacteria, and the other half with Penicillium, a type of fungus, each organism will grow on its respective half. **Incubation** for one week provides ample time for both organisms to multiply and form colonies, making them easily visible. S. epidermidis will form small, round, and whitish colonies, whereas Penicillium will display fuzzy, blue-green growth. It is important to note that no interaction or inhibition between the two organisms will be expected if they are streaked on separate halves of the plate.
Know more about incubation medium of bacteria here:
https://brainly.com/question/30700756
#SPJ11
A scientist is studying a population of 100 lizards. Find the chi-square of AA=75 observed, Aa=15 observed, aa=10 observed
Answers
The chi-square value for the observed genotype frequencies for a population of 100 lizards is approximately 161.63.
To find the chi-square value for the observed values of the genotypes (AA = 75, Aa = 15, aa = 10) in a population of 100 lizards, we need to compare them with the expected values under a specific hypothesis.
First, we need to determine the expected genotype frequencies based on a specific hypothesis or assumption. Let's assume that the population is in Hardy-Weinberg equilibrium, which assumes random mating and no evolutionary forces at play. In that case, the expected genotype frequencies can be calculated based on the allele frequencies.
Let's assume that the allele frequencies are p and q, where p represents the frequency of the dominant allele (A) and q represents the frequency of the recessive allele (a). In a population in Hardy-Weinberg equilibrium, the expected genotype frequencies can be calculated as follows:
AA = p² * total population
Aa = 2pq * total population
aa = q² * total population
Since we don't have the allele frequencies, we cannot calculate the exact expected values. However, let's assume that the allele frequencies are p = 0.6 and q = 0.4.
Expected genotype frequencies:
AA = (0.6)² * 100 = 36
Aa = 2 * 0.6 * 0.4 * 100 = 48
aa = (0.4)² * 100 = 16
Now, we can calculate the chi-square value using the formula:
chi-square = Σ ((observed - expected)² / expected)
chi-square = ((75 - 36)² / 36) + ((15 - 48)² / 48) + ((10 - 16)² / 16)
chi-square = (39² / 36) + (33² / 48) + (6² / 16)
chi-square = 136.5 + 22.88 + 2.25
chi-square = 161.63
Therefore, the chi-square value for the observed genotype frequencies is approximately 161.63.
Learn more about chi-square
https://brainly.com/question/30355927
#SPJ4
The most abundant component of plasma is:
Select one:
O A. ions.
• B. proteins.
• C. gases.
O D. water.
Answers
Answer: D water
Explanation:
Plasma contains about 90 percent water, with 10 percent being made up of ions, proteins, dissolved gases, nutrient molecules, and wastes. The proteins in plasma include the antibody proteins, coagulation factors, and the proteins albumin and fibrinogen which maintain serum osmotic pressure.
What difference do you notice compared to the other the church bio molecules in nucleus acid ?
Answers
The most crucial macromolecules for maintaining life are nucleic acids. They contain instructions for a cell's proper operation as well as the genetic code for that cell.
Deoxyribonucleic acid (DNA) and Ribonucleic acid (RNA) are the two primary forms of nucleic acids. All living things, from single-celled bacteria to multicellular mammals, have DNA as their genetic makeup. It is located in the organelle, chloroplasts, and mitochondria as well as the nuclei of eukaryotes. Prokaryotes lack a membranous sheath around their DNA. A cell's genome is its entire genetic makeup, and genomics is the study of genomes. DNA and histone proteins combine to form a complex to create chromatin, the material that makes up eukaryotic chromosomes, in eukaryotic cells yet not in prokaryotes. There may be hundreds or thousands of genes on a chromosome. Many genes encode for the production of protein molecules, while some genes produce RNA. DNA manipulates the genes to turn on or turn off various biological processes.
Learn more about Nucleic acids
https://brainly.com/question/11309892
#SPJ9
WILL GIVE BRAINLIST!!!! What effects do weathering, erosion, and deposition have on agriculture in Texas?
Answers
Answer:
cause the soil to become less fertile therefore causing the loss of nutrients and farmers can no longer plant crops causing profits to drop.
Explanation:
Which of the following statements is MOST accurate: Group of answer choices Animals evolved during the Cambrian Explosion because the Earth was organized into a supercontinent called Pangea Animals evolved during the Cambrian Explosion because oxygen on Earth had become abundant Animals evolved during the Cambrian Explosion because the Earth had just recovered from an asteroid impact Animals evolved during the Cambrian Explosion because carbon dioxide on Earth had become abundant
Answers
Answer:
Animals evolved during the Cambrian Explosion because oxygen on Earth had become abundant.
Explanation:
Photosynthesis could be responsible for the rise in the amount of oxygen in the seas and atmosphere near the beginning of the Cambrian. This rise of oxygen concentration allowing the evolution of larger animals having complex respiratory and circulatory systems. So we can conclude that evolution in the physical and genetical characteristics of animals occur during the Cambrian Explosion.
Can anyone help me ?
