Thinking about the winter we missed out on this year. Calvin and his tiger go sledding down a snowy hill. There is friction between the snow and the sled, and there is air resistance. Looking at the entire time that they spend on the hill (from when they start from rest at the top of the hill until they reach the bottom moving fast), indicate whether each of the following quantities is positive, negative, or zero, by writing either, -, or 0 for the questions below. We take Calvin, the tiger, and the sled as our system.
a. The work done by the normal force that the snow exerts on the system?
b. The work is done by the frictional force that the snow exerts on the system?
c.The change in the kinetic energy of the system?
d.The change in the gravitational potential energy of the system?
e. The total work is done on the system?

The net force on the baseball is approximately -4 N (one significant figure).

We can use the formula:

Net force = Change in momentum / Time

The change in momentum of the baseball is:

Δp = final momentum - initial momentum

Δp = 0 - 4 kg.m/s

Δp = -4 kg.m/s

The time taken for the baseball to stop is 1 second.

Substituting these values in the formula, we get:

Net force = -4 kg.m/s / 1 s

Net force = -4 N

Therefore, the net force on the baseball is approximately -4 N (one significant figure). Note that the negative sign indicates that the force is in the opposite direction to the initial momentum of the baseball.

What is momentum?

It is defined as the product of an object's mass and velocity, and is represented by the symbol "p". Mathematically, momentum can be expressed as: p = m * v

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a) 12.1 Average.

B) It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.

A) Determine the average length and express the answer using the correct number of significant figures:

12.2+12.1+12=36.3/3 = 12.1 Average.

B)  Based on your average length calculation in part a, discuss the importance of recording measurements to the appropriate number of significant figures:

It is important to record measurements to the correct number of significant figures because otherwise, the integrity of the number is compromised.

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Answer:

Twice.

Explanation:

The momentum of an object is given by :

p = mv

Where

m is mass and v is the velocity

If the mass of the ball were doubled, m'=2m and v'=v=3 m/s

New momentum,

p'=m'v'

p'=2m × v

p'=2mv

or

p'=2p

So, the new momentum becomes twice the initial momentum.

Answer:

True. The two laws of thermal radiation state; 1) "Each square meter of a hotter object

Explanation:

The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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Explanation:

2 hr = 2×60 = 120 min

2 hr + 10 min = 120 + 10 =130 min

1 min = 60 seconds

130min = 130 × 60 = 7,800 seconds

2 hr 10 min = 7,800 seconds

Answer:

F = M v^2 / R = M w^2 R      where w represents the angular frequency

Only 1 / R causes a reduction in centripetal force when increased

(B)   is the answer

Option B. The radius of curvature causes a reduction in centripetal force with an increase in the magnitude.

Centripetal force is a force that acts on the object that moves in a circular motion and is directed towards the center of the circular moving path. The mathematical representation of centripetal force is -

Where Fc = the centripetal force,

m = mass of the object,

v = velocity

and r = radius.

From the given explanation above, The centripetal force and radius of curvature are inversely proportional to each other,

that is, Fc = 1/r.

Therefore, an increase in the radius of curvature leads to a reduction in the centripetal force.

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Answer:

Explanation:

Your numbers seem wonky, so I'll just assume that the initial displacement is a distance A (Amplitude) from the equilibrium position. Spring constant = k

Initial potential energy is

PE = ½kA²

As potential energy and kinetic energy are constantly exchanging in SHM,

the position x where half of the original spring potential exists is found where

½kx² = ½(½kA²)

    x² = ½A²

    x = (√0.5)A

    x ≈ 0.707A

just plug in your actual starting position A

With A = 5.2 cm

x = 3.67695... 3.7 cm

The electric field is -641.25 volt, potential energy is -1.76x 10⁻³ J.

What is electric field ?

The term "electric field" or "electrostatic field" refers to the area surrounding an electric charge where stress or an electric force occur. A significant amount of tension might be produced in the area if the charge is of a big magnitude. The letter E is used to denote the electric field. Newtons per coulomb, or volts per metre, is the SI unit for the electric field.

What is potential energy ?

Potential energy is energy that is preserved or stored in a material or an item. The item or substance's position, organization, or condition determines the amount of stored energy. Consider it as energy with the "potential" to accomplish work.

Va = kq1/r1 + Kq2/r2

Va = 9 x 10/0.05 (2.3 x 10⁻⁹ – 6x 10⁹)

Va = -666 volt

Vb = 9x10⁹ (2.3x10⁻⁹/.08 – 6x10⁻⁹/.06)

Vb = -641.25 volt

Work done by electric field from b to a

W e = q(Vb-Va)  

W e = 3x10⁻⁹ (-641.25+666)

W e = 74.25x10⁻⁹ J

W e = qEd = 30x 10⁻⁹x 3.2x10⁴x.63

W e = 6.05x10⁻⁴ J

W e = -qEd cos 45

W e = -30x10⁻⁹x3.2x10⁴x2.6 cos 45

W e = -1.76x 10⁻³ J

Therefore, electric field is -641.25 volt, potential energy is -1.76x 10⁻³ J.

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Answer:

c

Explanation:

Answer:\(4\ m/s^2\)

Explanation:

Given

mass of toy \(m=0.5\ kg\)

Force by first dog \(F_1=140\ N\)

Force by second dog is \(F_2=138\ N\)

Net force on the dog is

\(F_{net}=F_1-F_2=140-138\)

\(F_{net}=2\ N\)

and \(F_{net}=ma\)

\(a=\dfrac{F_{net}}{m}\)

\(a=\dfrac{2}{0.5}\)

\(a=4\ m/s^2\)

So, horizontal acceleration of the toy is \(4\ m/s^2\)

Answer:

a) d = 3.6 km

b) 0.024°

Explanation:

To see the top of a 1 m tall deer over the surface of a 6400 km radius perfect sphere, the angle subtended is

cosθ = 6 400 000 / (6 400 001)

θ = 0.0320293...°

d = Rtanθ = 6 400 000tan0.0320293

d = 3,577.708... m

5 ft = 1.524 m

tanθ = 1.524 / 3577.7

θ = 0.0244063...°

There are six half lives that have passed within 34,200 years. When we assume that we have some of the products present initially, then we overestimate the age of the sample.

The half life is the time taken to obtain only half of the number of atoms that were originally present in the radioactive material. We know that living things do contain the carbon- 14 isotope together with the carbon - 12 isotope in the substance. When the organism dies, the carbon - 14 which is radioactive begins to decay and its half life could be used to estimate the age of the sample as we know.

Given that after each half life, we have only half of the original amount that remains. We would have 1/64 of the original amount left after six half lives and this means that 34,200 years have passed.

If we  the daughter product of carbon-14 is present in the sample when it forms (even before any radioactive decay happens), then we would over estimate the  age of the sample.

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Answer:

You must travel at an average speed of 67.06 m/s to be on time to the lecture.

Explanation:

From the question, the total distance from your house to the science lecture is 75 miles.

Also, you get halfway there before you stop for a gas, that is, you have covered half of 75 miles, which 37.5 miles and you also have to cover 37.5 miles to get to the science lecture.

After filling up, you only have 15  minutes before the lecture starts,

To determine how fast you must drive to be on time to the lecture,

we will determine the average speed you need to travel.

From

Average speed = Distance / Time

Distance = 37.5 miles (Convert to meters)

(NOTE: 1 mile = 1609.344 meters)

Hence, 37.5 miles = 37.5 × 1609.344 miles = 60350.4 meters

∴ Distance = 60350.4 meters

Time = 15 minutes (Convert to seconds)

(NOTE: 1 minute = 60 seconds)

Hence, 15 minutes = 15 × 60 seconds = 900 seconds

Now, from

Average speed = Distance / Time

Average speed = 60350.4 m / 900 s

Average speed = 67.06 m/s

Hence, you must travel at an average speed of 67.06 m/s to be on time to the lecture.

Answer:

0.44m/s

Explanation:

drift velocity=I/nAq

diameter 12 gauge

wire=0.081inches=0.081*2.5=0.2025cm radius=0.10125cm area=pi*R^2 =20/8.5*10^22*3.14*0.10125^2*10^-4*1.6*10^-19*

V = 0.44m/s

The drift velocity of the electrons should be 0.44 mm/s.

Since the diameter is 0.081 in

So, the  radius = r = 0.081 inch/2

= 0.0405 inch

Now the conversion of inches to cm should be

= 0.0405*2.54

= 0.10287 cm

Now

area = π r2

= 3.14 * (0.10287)2

= 0.0332

Now the velocity should be

v = i/(nqA)

= 20/(8.5e22*1.60e-19*0.0332)

= 0.044 cm/s

= 0.44 mm/s

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Answer:

C

Explanation:

correct me if I'm wrong.

Answer:

A

Explanation:

i got it right on acellus

The difference between the manufacturer's claims and your findings is, the manufacturer is concerned about amount of fat in the meat while you are concerned about calories.

Your findings concluded that only fat can provide calories needed in the body, perhaps other classes of food or nutrients in the meat can provide calories as well.

In the manufacturer's claim there are about 3% fat in the lunch meat and doesn't necessary mean that all the calories needed is the 3% fat.

Thus, there are lots of difference between your findings and the manufacturer's claim. The manufacturer is concerned about amount of fat in the lunch meat while you are concerned about calories in the meat.

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Answer:

A. the motion of an object along a curved path

Answer:

The correct answer is the final momentum is zero but the final kinetic energy is positive.

Explanation:

Solution

Given that:

The momentum is zero because momentum is the sum of the mass * velocity for each component. momentum is conserved

The Kinetic energy (KE) is positive because kinetic energy is the total of the 1/2 *mass * velocity^2.

Whereas the velocity can be positive and negative since it is directed (this is what makes the momentum zero because on is positive and one is negative), the velocity squared will always be positive.

Thus adding together two positives will always be a positive number.

Answer: 1/gk

Explanation: 15(22/330kg) (330/330gk) = 1/gk

Answer:

Momentum is a term used in physics to describe an object's resistance to change its motion. It is a measure of an object's mass and velocity and can be mathematically represented by the equation p = mv, where p is momentum, m is mass, and v is velocity.

Momentum is a vector quantity, meaning it has both magnitude and direction. It can be thought of as the amount of motion an object possesses in a particular direction. For example, a large truck traveling at a high speed has more momentum than a small car traveling at a slower speed, even though they both may have the same mass.

In physics, momentum plays a crucial role in determining how objects will react when they collide. If two objects collide and have equal and opposite momentum, they will typically bounce off each other. However, if one object has much more momentum than the other, it is likely to push the other object aside and continue on its original path.

It is also important to note that momentum is conserved in isolated systems. This means that if two or more objects collide or interact with each other, the total momentum before the collision is equal to the total momentum after the collision.

In conclusion, momentum is a fundamental concept in physics that helps to describe and understand the motion of objects. It is a combination of an object's mass and velocity, and it determines how objects will interact when they collide.

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The glycerin index predicts the way certain foods affect​ the blood glucose.

The glycemic index is a numerical scale that ranks carbohydrates in foods based on how they affect blood glucose levels compared to a reference food, typically pure glucose  or white bread. Foods with a high glycerin index cause rapid increase in blood sugar levels, while foods with a low glycerin index result in a slower and more gradual increase.

The glycerin index is often used as a tool for managing blood sugar levels, particularly in individuals with diabetes. Foods with a lower glycerin index are generally considered healthier as they provide more sustained energy and have a lesser impact on blood sugar levels.

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The electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

The electric potential energy stored in a capacitor is given by the formula:

U = (1/2) * C * V^2

where U is the potential energy in Joules, C is the capacitance in Farads, and V is the voltage across the capacitor in Volts.

In this case, we are given that the capacitor stores 9.40 x 10^-10 C of charge at 50.0 V. However, we are not given the capacitance value. Therefore, we cannot calculate the potential energy directly using the above formula.

To find the capacitance value, we can use the formula:

C = Q / V

where Q is the charge stored in the capacitor and V is the voltage across the capacitor.

Substituting the given values, we get:

C = 9.40 x 10^-10 / 50.0

= 1.88 x 10^-11 F

Now we can use the formula for electric potential energy to find the energy stored in the capacitor:

U = (1/2) * 1.88 x 10^-11 * (50.0)^2

= 4.70 x 10^-8 J

Therefore, the electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

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The formula for calculating the speed of a wave is expressed as

Speed = frequency x wavelength

From the information given,

frequency = 0.25

wavelength = 6

By substituting these values into the formula,

Speed = 0.25 x 6

Speed = 1.5 m/s

The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.

The object and image distance formed by the lens is calculated by applying the following lens formula.

v + u = 40 ------- (1)

v/u = 3 ------------ (2)

v = 3u

Substitute v into equation (1);

3u + u = 40

4u = 40

u = 40/4

u = 10 cm

The image distance = 3u

= 3 x 10 cm

= 30 cm

Thus, the object distance is 10 cm and the image distance is 30 cm.

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Change in speed = (acceleration) x (time)

4 minutes = 240 seconds

Change in speed = (40 m/s²) x (240 seconds)

Change in speed = 9,600 m/s

What you're actually describing here is a car pulling 4 G's for 4 minutes, and ending up going 21,475 miles per hour.

The driver would definitely NOT get a speeding ticket, because nobody could catch him.

Also, his car would heat up and shoot flames from atmospheric friction.

(He could avoid this with some fancy steering, leave the atmosphere, and end up in low-Earth-orbit.)

Actually, I hope there's nobody in the car.  His experience wouldn't be pretty.

(a)The rifle exerts a force of 628 N on the bullet while it is in the barrel.

(b) (i)  There is no friction between the bullet and the barrel, there is no force of friction to consider.

    (ii) Just after it has left the barrel, the only force acting on the bullet would be the force of gravity pulling it downward.

(c) The rifle gives the bullet an acceleration of about 24885 g's.

(d) the bullet is in the barrel for 0.030 s.

What is Force?

Force is a physical quantity that describes the interaction between two objects, causing a change in motion. Specifically, it is an influence that can cause an object to accelerate, change direction, or deform. Force is defined as the product of mass and acceleration, according to Newton's second law of motion. Mathematically, force can be represented by the equation:

                              F = m*a

(a) To determine the force that the rifle exerts on the bullet while it is in the barrel, we need to use the equation for the work done by a constant force:

                                   W = Fd

where W is the work done, F is the force, and d is the distance over which the force is applied. We can rearrange this equation to solve for the force:

F = W/d

We know that the work done on the bullet is equal to the change in kinetic energy:

W = ΔK = (1/2)mv^2

where m is the mass of the bullet and v is its velocity. Plugging in the given values, we get:

W = (1/2)(0.00420 kg)(370 m/s)^2 = 283 J

The distance over which the force is applied is given as 45.0 cm = 0.45 m. So the force exerted by the rifle on the bullet is:

F = W/d = 283 J / 0.45 m = 628 N

Therefore, the rifle exerts a force of 628 N on the bullet while it is in the barrel.

(b) (i) The free-body diagram of the bullet while it is in the barrel would show two forces acting on it: the force of the rifle pushing it forward, and the force of gravity pulling it downward. Since there is no friction between the bullet and the barrel, there is no force of friction to consider.

(ii) Just after it has left the barrel, the only force acting on the bullet would be the force of gravity pulling it downward.

(c) We can calculate the acceleration of the bullet using the formula:

a = Δv/t

where Δv is the change in velocity and t is the time for which the acceleration occurs. We know that the initial velocity of the bullet is 370 m/s and that it starts from rest, so the change in velocity is:

Δv = 370 m/s

The distance over which the acceleration occurs is given as 45.0 cm = 0.45 m. Using the formula for distance traveled with constant acceleration, we can find the time for which the acceleration occurs:

d = (1/2)at^2

0.45 m = (1/2)a(t^2)

Solving for t, we get:

t = sqrt(0.9/a)

Plugging this into the equation for acceleration, we get:

a = Δv/t = 370 m/s / sqrt(0.9/a)

Solving for a, we get:

a = 2.44 x 10^5 m/s^2

To express this acceleration in units of g's, we can divide by the acceleration due to gravity:

a/g = 2.44 x 10^5 m/s^2 / 9.81 m/s^2 = 24885

Therefore, the rifle gives the bullet an acceleration of about 24885 g's.

(d) Using the same formula as before for distance traveled with constant acceleration, we can solve for the time the bullet is in the barrel:

d = (1/2)at^2

0.45 m = (1/2)(2.44 x 10^5 m/s^2)t^2

Solving for t, we get:

t = \(\sqrt{(0.00092)}\)s = 0.030 s

Therefore, the bullet is in the barrel for 0.030 s.

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The bullet is in the barrel for 7.05 x 10^-5 seconds. Acceleration can also be caused by changes in direction, such as when an object moves in a circular path.

What is Acceleration?

Acceleration is a fundamental concept in physics and plays an important role in understanding the motion of objects. It is used to describe the behavior of objects in a wide range of applications, from simple everyday situations such as cars accelerating and braking, to more complex phenomena such as the acceleration of particles in particle accelerators or the acceleration of celestial bodies in space.

(a) To find the force exerted by the rifle on the bullet, we can use the kinematic equation:

v^2 = u^2 + 2as

where v is the final velocity (muzzle velocity), u is the initial velocity (0 m/s), a is the acceleration, and s is the distance traveled (45.0 cm = 0.45 m).

Rearranging this equation to solve for acceleration:

a = (v^2 - u^2) / 2s

Plugging in the given values:

a = (1200 m/s)^2 / (2 x 0.45 m) = 3.20 x 10^6 m/s^2

The force exerted by the rifle on the bullet can be found using Newton's second law:

F = ma

where F is the force, m is the mass of the bullet (4.20 g = 0.00420 kg), and a is the acceleration we just calculated:

F = 0.00420 kg x 3.20 x 10^6 m/s^2 = 13,440 N

Therefore, the rifle exerts a force of 13,440 N on the bullet while it is in the barrel.

(b)

(i) Free-body diagram of the bullet while it is in the barrel:

The only force acting on the bullet while it is in the barrel is the force exerted by the rifle, which is directed to the right.

  |

  |

-->|  F

  |

  |

Once the bullet has left the barrel, it is subject to air resistance, which we will assume acts in the opposite direction to the velocity of the bullet. The force of gravity on the bullet is negligible for this problem.

  |

  |

<--|  F_air

  |

  |

(c) The acceleration given to the bullet can be expressed in terms of g's by dividing by the acceleration due to gravity, g:

a_g = a / g = (3.20 x 10^6 m/s^2) / 9.81 m/s^2 = 326,000 g's

Therefore, the rifle gives the bullet an acceleration of 326,000 g's.

(d) The time the bullet is in the barrel can be found using the kinematic equation:

s = ut + (1/2)at^2

where s is the distance traveled (0.45 m), u is the initial velocity (0 m/s), a is the acceleration we calculated earlier (3.20 x 10^6 m/s^2), and t is the time the bullet is in the barrel (which we want to find).

Rearranging and solving for t:

t = sqrt(2s/a) = sqrt(2 x 0.45 m / 3.20 x 10^6 m/s^2) = 7.05 x 10^-5 s

Therefore, the bullet is in the barrel for 7.05 x 10^-5 seconds.

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Answer:

2

Explanation:edu