These genes determine where the (answer) and the (answer) of the animal's going to be; the top, the bottom; the left, the right; the inside, the outside; where the eyes are going to be; where the legs are going to be; where the gut's going to be; how many fingers they're going to have.

Binocular rivalry is a condition resulting from the combination of two different images received by the two eyes.

Here correct answer is C

When this occurs, the visual cortex of the brain is unable to combine the two images, leaving only one of the images to be perceived either through suppression or alternation. During binocular rivalry, an observer experiences a back-and-forth switch between the two dissimilar images.

The alternations between the two images can last anywhere from seconds to minutes depending on the strength of the two images. The factors influencing the alternations between the images include individual viewing habits, attention and emotional state. People who suffer from binocular rivalry often experience confusion, disorientation and eyestrain.

This condition can be treated with vision therapy which focuses on strengthening weak eye muscles and developing better visual habits. It can help reduce the amount of time and intensity of binocular rivalry instances.

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It is true that  if genes A and B are so closely linked that the recombination frequency is 0 percent, only AB and ab gametes will be produced during meiosis.

A mature haploid male or female germ cell that can mate with a different sex to create a zygote during sexual reproduction.

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Answer:

physical earth and life science

Explanation:

Answer:

physical earth and life science

Explanation:

The correct type of stain that ought to be used is the  Giemsa stain. Option A

Giemsa stain is frequently employed in laboratories to find and identify parasites, particularly those found in blood samples. It is an essential stain that binds to the DNA and RNA of cells to create contrast and make microscopic organism identification simpler.

Giemsa stain is frequently used in laboratories for this reason because it is created expressly to reveal parasites as we have seen in this case here.

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Missing parts;

Which stain successfully revealed the parasite presence in Purna's blood sample?

A) Giemsa stain.

B) Gram stain.

C) Wright stain.

D) Crystal violet stain.

There is a standard antimicrobial procedure available from the centers for disease control and prevention (cdc) that can be used for all different microorganisms under any condition. False. One type of standard antimicrobial procedure cannot be used for all types of microbes.

CDC or center for disease control and prevention is the department of health and community services which is tasked with dealing with various diseases, conducting research, and publishing research results and instructions to the public. The CDC also has laboratory and epidemiological surveillance policies, the Center of Global Health, and work through state and local governments.

Antimicrobials are substances that have the ability to inhibit or kill microbial growth with relatively little toxicity to humans. Antimicrobials include antibiotics (to kill bacteria), antivirals, antiparasitics, and antifungals. Each antibiotic drug content has different abilities and functions and is specific to certain microbes. Therefore one type of standard antimicrobial procedure cannot be used for all types of microbes.

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An example of potentiation with probenecid (Benemid) is the combination of probenecid with certain antibiotics, such as penicillin or cephalosporins. Probenecid can increase the effectiveness and duration of action of these antibiotics by inhibiting their elimination from the body.

Probenecid is a medication commonly used to treat gout and increase the excretion of uric acid from the body. It works by blocking the renal tubular secretion of certain substances, including antibiotics like penicillin or cephalosporins. When probenecid is co-administered with these antibiotics, it inhibits their elimination by interfering with their active secretion into the urine.

As a result, the combination of probenecid with these antibiotics leads to higher and more sustained levels of the antibiotics in the bloodstream. This phenomenon is known as potentiation, where one drug enhances the effects or prolongs the action of another drug. In this case, probenecid potentiates the antibiotics by increasing their concentration and exposure in the body.

The potentiation effect of probenecid can be beneficial in certain situations. By increasing the concentration of antibiotics in the bloodstream, probenecid can enhance its effectiveness against bacterial infections, particularly those caused by organisms that are susceptible to the antibiotics being used. However, it is important to note that drug interactions can have both beneficial and adverse effects, and any combination therapy should be prescribed and monitored by healthcare professionals.

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The response of the dbms to a query is the Query result set.

The name for a response to a query which the DBMS provides to the application is a "query result set."

Data storage administration:You are spared the challenging process of specifying and programming actual physical data properties because the DBMS constructs and controls the intricate structures needed for data storage.

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To determine the allele frequencies, we can use the Hardy-Weinberg equation: pp2 + 2pq + qq = 1, where p is the frequency of the dominant allele (T) and q is the frequency of the recessive allele (t).

From the given information, we know that there are 700 students who are homozygous recessive (tt) and 100 who are homozygous dominant (TT). This means that the frequency of the recessive allele (q) is:

qq = 700/1000
qq = 0.7
q = √0.7
q = 0.84

Similarly, the frequency of the dominant allele (p) can be calculated as:

pp = 100/1000
pp = 0.1
p = √0.1
p = 0.316

Therefore, the allele frequencies for tongue rolling in this population are:
- Frequency of the recessive allele (t): 0.84
- Frequency of the dominant allele (T): 0.316

Given the data provided:

1. 700 students are homozygous recessive (tt)
2. 200 students are heterozygous (Tt)
3. 100 students are homozygous dominant (TT)

We will use the Hardy-Weinberg equation to determine the allele frequencies:

pp + 2pq + qq = 1

Where p is the frequency of the dominant allele (T) and q is the frequency of the recessive allele (t).

First, we'll find the frequency of each genotype:

1. Homozygous recessive (tt): 700 / 1,000 = 0.7
2. Heterozygous (Tt): 200 / 1,000 = 0.2
3. Homozygous dominant (TT): 100 / 1,000 = 0.1

Now, we will use the equation qq = homozygous recessive frequency to find q:

qq = 0.7
q = √0.7 ≈ 0.837

To find p, we can use the equation p + q = 1:

p = 1 - q
p = 1 - 0.837 ≈ 0.163

So, the allele frequencies for tongue rolling in this population are approximately:

1. Dominant allele (T): 16.3%
2. Recessive allele (t): 83.7%

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Answer:

C.

Explanation:

Empirical evidence is evidences obtained by direct observation, sensual perception, or direct measurement. It is then processed and useful data gathered and stored in a material form or documented to provide a record of the measurement.

With the aid of empirical evidence, it is possible for researchers to find answers to question regarding topics that can vastly impact everyday life.

With empirical evidence, it is possible to determine the effects of treatment in a study such as the invention of working car safety devices such as seat belts and airbags.

Answer:

your mom

Explanation:

dad

Answer:

Well, Shibuya City is located in the Tokyo Metropolis of Japan and since it is an urbanized area, it is an continental environment.

The average time range necessary for completing phase testing of drugs during clinical trials is approximately 6 months to 1 year.

The development and testing of new drugs involve a series of clinical trials, which are conducted in different phases to assess their safety, efficacy, and side effects. The duration of each phase can vary, but on average, the time required for completing phase testing falls within the range of 6 months to 1 year.

Clinical trials are typically divided into four phases: Phase 1, Phase 2, Phase 3, and Phase 4. Phase 1 trials focus on assessing the safety and dosage range of the drug in a small group of healthy volunteers. This phase usually takes several months to complete.

Phase 2 trials involve a larger group of patients and aim to evaluate the drug's effectiveness and further assess its safety. This phase can last from several months to a couple of years, depending on the complexity of the study and recruitment of participants.

Phase 3 trials are extensive and involve a larger population of patients to confirm the drug's effectiveness, monitor side effects, and compare it to existing treatments. These trials generally take several years to complete.

Phase 4 trials, also known as post-marketing surveillance, occur after the drug has been approved and released to the market. These trials continue to monitor the drug's safety and effectiveness in larger patient populations.

On average, the completion of phase testing during clinical trials for new drugs takes approximately 6 months to 1 year. However, it's important to note that the duration can vary depending on factors such as the complexity of the study, recruitment of participants, and regulatory requirements. Clinical trials play a critical role in ensuring the safety and efficacy of new drugs before they are made available to the public.

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Answer: Expectation is that 75% of offspring will have the dominant phenotype, 25% the recessive phenotype.

Explanation: Pp x Pp gives expected offspring genotypes PP (25%), Pp (50%), pp (25%).

If P is dominant, the expectation for phenotype ‘P’ = 75% and for phenotype ‘p’ = 25%

The distal clavicle and the acromioclavicular joint are assessed using holmblad method the acromioclavicular (AC) joint radiography series.

The patient can be seated or standing straight, with the backs of their shoulders resting on the image receptor, for an AP projection of their AC joints. In cases of suspected acromia-clavicular separation, weight-bearing views could be deceptive if the deltoid and trapezius muscles are very tense. Instead of holding the weights in your hands, you might be able to decrease the impact of this spasm by strapping them to your wrist.

The cross-body adduction test is the most accurate physical examination test for acromioclavicular joint pathology. The midshaft of the clavicle should be maneuvered during this examination, which evaluates the stability of the afflicted shoulder.

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The journal Gynecological Endocrinology in 2008 explores the possibility of hormone replacement therapy being carcinogenic, meaning it may increase the risk of developing cancer.

Replacement therapy refers to the use of medications or hormones to replace or supplement hormones that are naturally produced in the body. In the context of this question, it specifically refers to hormone replacement therapy (HRT) used in gynecology and endocrinology.

To determine if HRT is carcinogenic, researchers analyze various factors such as the type and duration of HRT, age of the patient, and other risk factors.

The study concludes that the plausibility of HRT being carcinogenic is still a subject of debate and requires further research.

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Answer: There are two categories of jawless fish: hagfish and lampreys. Hagfish usually feed on dead or dying fish. These fish can be found around the tunnels they dig in muddy bottoms, in moderate depths and cold waters. Scientists only know of about 20 species of hagfish worldwide.May 8, 2017

Sorry if it doesn't answer your sentence or question , i just thought about writing this..

Answer:

Although the question is pretty simple,the answer,I'm afraid, could occupy a whole volume of a book.

But very simply put the secondary sexual growth in males is under the influence of testosterone. Males also produce estrogen but in very small amounts,which makes the effect of estrogen very minimal and almost negligible.

Sexual growth in females is under the influence of estrogen and then progesterone.

In both cases,the physiological process is quite similar:

At puberty in males,the hypothalamus produces gonadotropin releasing hormones which causes the anterior pituitary lobe to produce leutinizing hormones(LH) and follicle stimulating hormones(FSH). LH acts on leydig cells in the seminiferous tubules of the testes to produce testosterone and FSH acts on the Sertoli cells in the seminiferous tubules of the testes to produce androgen binding proteins(ABP). Together testosterone and ABP cause sperm production.

At puberty in females, ,the hypothalamus produces gonadotropin releasing hormones which causes the anterior pituitary lobe to produce leutinizing hormones(LH) and follicle stimulating hormones(FSH). FSH causes growth of the primordial follicle into a mature Graafian follicle while LH presence causes exocytosis of the mature oocyte (ovulation) in about 48hours.

The proportion of the infant's total daily food energy that should come from each food group varies depending on the infant's individual needs.

In general , their are recommendations  and guidelines, and the specific needs of each infant may vary depending on factors such as age, weight, growth rate, and activity level.  Also,  infants should consume a diet that includes 28-42 grams of protein per day, 1-1.5 cups of cereal per day and  about 1-1.5 cups of fruit per day. Other foods such as dairy products, fats and oils, and sweets , as needed to meet the infant's energy needs.

Also, It is recommended that parents and caregivers consult with a healthcare professional to develop a personalized feeding plan for their infant.

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Answer: A dichotomous key is a tool that allows the user to determine the identity of items and organisms in the natural world. It is the most widely used form of classification in the biological sciences because it offers the user a quick and easy way of identifying unknown organisms.

Explanation:

answer:The vishnu schist is oldest that is 1.7 billion years old and the redwall schist is youngest. Explanation: The Vishnu schist is the uncovered rocks of the grand canyon vicinity they're formed on the basement location that underlines the bottom limestone. Which are accompanied by way of the Zoroaster granite which is an igneous-plutonic rocks intrusion and became later metamorphosed

Explanation:

Answer:

D

Explanation:

Index fossils are the basis for defining boundaries in the geologic time scale and for the correlation of strata. They also have a wide geographic distribution and a short range through time

Answer:

D

Explanation:

Mutations are changes that take place in the DNA sequence. There are different types of mutations and the given original and new DNA strands can help us identify different types of mutations. Therefore, the types of mutations are as follows:

Type of mutation: Deletion

The first set of DNA strands contains one less base in the new strand when compared to the original. A base "C" is missing in the new strand that is present in the original strand. It is also known as the deletion of the nucleotide. Therefore, the type of mutation is a deletion.

Type of mutation: Insertion

The second set of DNA strands contains one additional base in the new strand when compared to the original. A base "T" is present in the new strand that is not present in the original strand. It is also known as an insertion of the nucleotide. Therefore, the type of mutation is an insertion.

Type of mutation: Substitution

The third set of DNA strands contains one different base in the new strand when compared to the original. The base "A" in the original DNA strand is replaced by a base "G" in the new DNA strand. It is also known as a substitution mutation. Therefore, the type of mutation is a substitution.

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Answer:

You would not be able to prove that an atomic bomb was dropped on Hiroshima using the scientific method Because it is a historical event. You would not be able to prove that an atomic bomb was dropped on Hiroshima using the scientific method Because it is a historical event.

Answer: B

Explanation: Water molecules have an unequal charge making them more negitive than positive.

Answer:

B

Explanation:

Water molecules are polar, meaning they have a net partial negative charge.

Brainliest? If not it ok! ^w^

Answer:

Take in

Explanation:

During photosynthesis, plants take in carbon dioxide (CO2) and water (H2O) from the air and soil. This transforms the water into oxygen and the carbon dioxide into glucose. The plant then releases the oxygen back into the air, and stores energy within the glucose molecules.

If there are 2.91 gigabase pairs (2.91x10⁹base pairs) in the haploid human genome, then the number of:

A residues are 786.57 million bases,

T residues are 786.57 million bases,

C residues are 669.03 million bases,

G residues are 669.03 million bases.

Since the human genome is diploid, each somatic cell contains two copies of each chromosome, but gametes are haploid, meaning they contain only one copy of each chromosome.

Here, the haploid human genome contains a total of 2.91 gigabase pairs (2.91x10⁹base pairs).

Number of A residues = number of T residues and

Number of G residues = number of C residues

If A is 27%, then T is also 27%

G+C = (100-27-27)%

G+C = 46%

G = C = 23%

We can calculate the number of each type of base in a single gamete as follows:

Number of A residues = 27% x 2.91x10⁹ = 786,570,000

Number of T residues = 27% x 2.91x10⁹ = 786,570,000

Number of G residues = 23% x 2.91x10⁹ = 669,030,000

Number of C residues = 23% x 2.91x10⁹ = 669,030,000

Therefore the number of A residues is 786.57 million bases, the number of T residues is 786.57 million bases, the number of C residues is 669.03 million bases, and the number of G residues is 669.03 million bases

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On Ediacaran bedding planes all across the world, microbial mats are frequently discovered alongside macro- and trace fossils. As wrinkled surface textures on bedding planes or, less frequently, as preserved collections of small pyritized filaments covering macrofossil surfaces, mats can be identified. Due to its cracked and wrinkled look, the "elephant skin" texture of MISS is arguably the most identifiable kind. Thin sections cut through bedding planes can also be used to identify microbial mats. They can be recognized by the distinctive orientation of the sediment grains or, on rare occasions, by the presence of microfossils of the original bacteria. Jim Gerling postulated in 1999 that Australia's vast microbial mats may have been crucial to the preservation of Ediacaran macrofossils.

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