We need a sample size of at least 62 to detect the alternative hypothesis with power of at least 0.80 at a 5% significance level.
To answer this question, we need to use power analysis. Power is the probability of rejecting the null hypothesis when it is false. In this case, the null hypothesis is m = 0 and the alternative hypothesis is m > 0. We want to detect the alternative hypothesis with power of at least 0.80 at a 5% significance level.
Assuming that s is 20 and we want to detect the alternative m > 4, we can use the following formula to calculate the sample size:
n = (Zα/2 + Zβ)² * σ² / δ²
where:
- Zα/2 is the critical value for the significance level α/2 (α = 0.05, so Zα/2 = 1.96)
- Zβ is the critical value for the power (power = 0.80, so Zβ = 0.84)
- σ is the standard deviation (σ = 20)
- δ is the difference between the null hypothesis and the alternative hypothesis (δ = 4)
Substituting these values into the formula, we get:
n = (1.96 + 0.84)² * 20² / 4²
n = 61.61
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pls help me solve for length XY pls show how you got the answer
Answer:
XY = 4.75 cm
Step-by-step explanation:
Δ VXY and Δ VWZ are similar so the ratios of corresponding sides are equal, that is
\(\frac{XY}{WZ}\) = \(\frac{VX}{VW}\) , substitute values
\(\frac{XY}{2.5}\) = \(\frac{4.5+5}{5}\) = \(\frac{9.5}{5}\) ( cross- multiply )
5 XY = 23.75 ( divide both sides by 5 )
XY = 4.75 cm
2(x+3) < x + 6
how to solve this inequalities ?
Answer: X <0
Step-by-step explanation: 2(x+3)<x+6
Use the distributive property to multiply 2 by x+3.
2x+6<x+6
Subtract x from both sides.
2x+6−x<6
Combine 2x and −x to get x.
x+6<6
Subtract 6 from both sides.
x<6−6
Subtract 6 from 6 to get 0.
x<0
Using Laplace Transforms, find the solution of the initial value problem: d²y +9y =9. sin(t). U(t - 3), = y(0) = y'(0) = 0 dx²
The solution to the given initial value problem, obtained using Laplace transforms, is y(x) = 0. This means that the function y(x) is identically zero for all values of x.
To find the solution of the initial value problem using Laplace transforms for the equation d²y/dx² + 9y = 9sin(t)u(t - 3), where y(0) = y'(0) = 0, we can follow these steps:
Take the Laplace transform of the given differential equation.
Applying the Laplace transform to the equation d²y/dx² + 9y = 9sin(t)u(t - 3), we get:
s²Y(s) - sy(0) - y'(0) + 9Y(s) = 9 * (1/s² + 1/(s² + 1))
Since y(0) = 0 and y'(0) = 0, the Laplace transform simplifies to:
s²Y(s) + 9Y(s) = 9 * (1/s² + 1/(s² + 1))
Solve for Y(s).
Combining like terms, we have:
Y(s) * (s² + 9) = 9 * (1/s² + 1/(s² + 1))
Multiply through by (s² + 1)(s² + 9) to get rid of the denominators:
Y(s) * (s⁴ + 10s² + 9) = 9 * (s² + 1)
Simplifying further, we have:
Y(s) * (s⁴ + 10s² + 9) = 9s² + 9
Divide both sides by (s⁴ + 10s² + 9) to solve for Y(s):
Y(s) = (9s² + 9)/(s⁴ + 10s² + 9)
Partial fraction decomposition.
To proceed, we need to decompose the right side of the equation using partial fraction decomposition:
Y(s) = (9s² + 9)/(s⁴ + 10s² + 9) = A/(s² + 1) + B/(s² + 9)
Multiplying through by (s⁴ + 10s² + 9), we have:
9s² + 9 = A(s² + 9) + B(s² + 1)
Equating the coefficients of like powers of s, we get:
9 = 9A + B
0 = A + B
Solving these equations, we find:
A = 0
B = 0
Therefore, the decomposition becomes:
Y(s) = 0/(s² + 1) + 0/(s² + 9)
Inverse Laplace transform.
Taking the inverse Laplace transform of the decomposed terms, we find:
L^(-1){Y(s)} = L^(-1){0/(s² + 1)} + L^(-1){0/(s² + 9)}
The inverse Laplace transform of 0/(s² + 1) is 0.
The inverse Laplace transform of 0/(s² + 9) is 0.
Combining these terms, we have:
Y(x) = 0 + 0
Therefore, the solution to the initial value problem is:
y(x) = 0
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Find a value for x and a value for y so that 2x+3y=24 and 5x-2y=22
The values of x and y are 6 and 4, respectively. So, x = 6 and y = 4.
Given equations:
2x + 3y = 24, and
5x - 2y = 22
To find the values of x and y,
we have to solve the equations by using the elimination method.
Here's how:
Step 1:
Multiply equation (1) by 2 and equation (2) by 3.
4x + 6y = 48 (Equation 1 multiplied by 2)
15x - 6y = 66 (Equation 2 multiplied by 3)
Step 2: Add both equations to eliminate y,
4x + 6y = 48
15x - 6y = 66 ___________________________
19x = 114
Step 3: Divide both sides by 19.
x = 6
Step 4: Substitute the value of x in any of the given equations.
2x + 3y = 24
Putting the value of x, we get:
2 (6) + 3y = 24
Simplifying, we get:
12 + 3y = 24
Step 5: Solve for y,
3y = 24 - 12
y = 4
Thus, the values of x and y are 6 and 4, respectively. So, x = 6 and y = 4.
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24 less than z is less than 12.
Answer:
36
Step-by-step explanation:
24+12=36
.....................
Answer:
B. √16 × √6
C. √96
Step-by-step explanation:
4√6
4 can be written as a square root.
4 = √16
√16 × √6
The square roots are multiplied, they can be written under one whole square root.
√(16 × 6)
√96
Given K∼N(μ=0,σ2=1), i.e. K is Gaussian distributed, what’s the probability that the equation x2+2Kx+1=0 has real solutions?
Hint: The solution to the quadratic equation ax2+bx+c=0 where a, b and c are real constants and x is unknown, is x=−b±b2−4ac√2a.
P(|K| ≥ 1) = 1 - P(-1 ≤ K ≤ 1)
To find this probability, we can look up the values in a standard normal distribution table or use a calculator that provides the CDF of the standard normal distribution. The result will give us the probability that the quadratic equation has real solutions.
Using the quadratic formula you provided, x = (-2K ± sqrt((2K)^2 - 4(1)(1))) / (2(1)) simplifies to:
x = -K ± sqrt(K^2 - 1)
For the quadratic equation to have real solutions, the discriminant (K^2 - 1) must be greater than or equal to zero, since the square root of a negative number would result in imaginary solutions.
So, we need to find the range of values for K that satisfy the inequality K^2 - 1 ≥ 0.
Let's solve this inequality:
K^2 - 1 ≥ 0
Adding 1 to both sides:
K^2 ≥ 1
Taking the square root of both sides (note that K^2 is always positive):
|K| ≥ 1
This means that the absolute value of K must be greater than or equal to 1 for the quadratic equation to have real solutions.
Now, since K is Gaussian distributed with a mean of μ = 0 and variance of σ^2 = 1, we can calculate the probability using the standard normal distribution.
Using the properties of the standard normal distribution, the probability that K falls within the range |K| ≥ 1 is equal to 1 minus the cumulative distribution function (CDF) at 1 and -1:
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Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software, graph the function with a domain and viewpoint that reveal all the
Important aspects of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
F(x,y)=x³+y³-3x²-6y²-9x
local maximum value(s)=
local minimum value(s)=
saddle point(s)=
For the function F(x, y) = x³ + y³ - 3x² - 6y² - 9x , the local maximum value is 5 and the local minimum value is -3. The graph is discontinuous, so we cannot locate the saddle points.
What is a saddle point?In mathematics, a saddle point or minimax point is a point on the surface of the graph of a function where the slopes (derivatives) in orthogonal directions are all zero (a critical point), but which is not a local extremum of the function.
We have the following function -
F(x, y) = x³ + y³ - 3x² - 6y² - 9x
We will plot the 3 dimensional graph of this function. From the model it can be seen that, the local maximum value is 5 and the local minimum value is -3. Since the graph is discontinuous, we cannot locate the saddle points.
Therefore, for the function F(x, y) = x³ + y³ - 3x² - 6y² - 9x , the local maximum value is 5 and the local minimum value is -3. The graph is discontinuous, so we cannot locate the saddle points.
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The shape of a colony of bacteria on a Petri dish is circular. Find the approximate increase in its area if its radius increases from 40 mm to 47 mm The estimated change in area is □mm2
The approximate increase in area is 1915.86 mm^2.
The area of a circle is given by the formula A = πr^2, where r is the radius.
Initially, the radius is 40 mm, so the area of the colony is:
A1 = π(40)^2 = 1600π mm^2
After the radius increases to 47 mm, the new area of the colony is:
A2 = π(47)^2 = 2209π mm^2
The increase in area is then:
ΔA = A2 - A1 = (2209π - 1600π) mm^2
ΔA = 609π mm^2
Approximating π as 3.14, we get:
ΔA ≈ 1915.86 mm^2
Therefore, the approximate increase in area is 1915.86 mm^2.
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What are lines called in Riemann's spherical geometry?
O A. segments
O B. great circles
O C. diameters
O D. great lines
Answer:
B
Step-by-step explanation:
Great circles are the largest possible circles that can be drawn around a sphere and are the lines called in Riemann's spherical geometry.
Can you guys help meh pls
Suppose that 17 inches of wire costs 51 cents. At the same rate, how many inches of wire can be bought for 42 cents?
Element X decays radioactively with a half life of 15 minutes. If there are 400 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 87 grams?
Answer:
The time it'd take for the element to have 15 g of mass is approximately 68 min.
Step-by-step explanation:
The radioactive decay of a substance is given by the following formula:
Since the element has a half life of 12 minutes, this means that after this time the mass of the element will be half of it was originally, therefore:
Therefore the mass of the element is given by:
If the initial mass is 760 g and the final mass is 15 g, we have:
The time it'd take for the element to have 15 g of mass is approximately 68 min.
Step-by-step explanation:
Element X take 32.6 minutes to decay to 87 grams.
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
Element X decays radioactively with a half life of 15 minutes.
And, there are 400 grams of Element X.
Now, By the given information, we can formulate;
⇒ \(y = x (0.5)^{t/h}\)
Substitute all the values we get;
⇒ 400 = 87 × \((0.5)^{t/15}\)
⇒ 400 / 87 = \((0.5)^{t/15}\)
⇒ 4.6 = \((0.5)^{t/15}\)
Take log both side,
⇒ ln 4.6 = t/15 (ln 0.5)
⇒ 1.52 = t/15 x 0.7
⇒ t = 32.6 minutes
Thus, Element X take 32.6 minutes to decay to 87 grams.
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if their first three children have the disease, what is the probability that their fourth child will not
The probability of Bob and Joan's fourth child having sickle cell disease, given that their first three children are healthy, is 6.25%.
When Bob and Joan have children, each child has a 25% chance of inheriting two copies of the sickle cell gene and thus developing the disease, a 50% chance of inheriting one copy of the sickle cell gene and being a carrier like their parents, and a 25% chance of inheriting two copies of the normal gene and not carrying the disease.
To understand this probability calculation mathematically, we can use the laws of probability. We can define the probability of the fourth child inheriting the sickle cell gene as P(s), and the probability of the fourth child inheriting the normal gene as P(n).
Since Bob and Joan are each heterozygous carriers for the sickle cell gene, we know that P(s) = 0.25 (25%), and P(n) = 0.75 (75%). We can use the multiplication rule of probability to calculate the probability of their fourth child inheriting two copies of the sickle cell gene, which is:
P(sickle cell disease) = P(s) x P(s) = 0.25 x 0.25 = 0.0625 or 6.25%
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Complete Question:
Bob and Joan know from a blood test that they are each heterozygous (carriers) for the autosomal recessive gene that causes sickle cell disease. If their first three children are healthy, what is the probability that their fourth child will have the disease?
Combinaciones y permutaciones en la vida diaria
In real life, permutations and combinations can exist in the following examples -
the arrangement of peoples in a particular order.selection of food from the menu etWhat is the formula to find permutation?The formula to find the permutation is -
P(n, r) = n!/(n - r)!
Given is to investigate the real life problems on -
Combinations and permutations
Permutations and combinations in real life exist in a lot of different ways such as the arrangement of peoples in a particular order, selection of food from the menu etc.
Therefore, in real life, permutations and combinations can exist in the following examples -
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{QUESTION IN ENGLISH -
Combinations and permutations in daily life?
if AB, CB, DCE = (7x + 2) and ECB = ( x + 8), find the measure of DCE. Could anyone help me? I don’t know how to solve it.
Answer:
<DCE = 72°
Step-by-step explanation:
If lie AB is perpendicular to each other, then the sum of angle DCE and ECB will be equivalent to 90°.
Given
<DCE = 7x+2
<ECB = x+8
Hence
<DCE + < ECB = 90
7x+2 + x+8 = 90
7x+x+2+8 = 90
8x+10 = 90
8x = 90-10
8x = 80
x = 80/8
x = 10°
Since <DCE = 7x+2, substitute x= 10 into the expression
<DCE = 7(10)+2
<DCE = 70+2
<DCE = 72°
A car completes a journey in 10 minutes. For the first half of the
distance the speed was 60 km/h and for the second half the speed
was 40 km/h. How far is the journey?ans me I'll mark u as brilliant just hurry upp plzz guysss
Simplify the expression -4x(6x − 7).
Answer: -24x^2+28x
Step-by-step explanation: -4x*6x-(-4x)*7 to -24x^2+28x
What is 2(x - 9) = 10?
Answer:
x=14
Step-by-step explanation:
2 times x = 2x and 2 time 9 is 18 so the equation is 2x-18=10. then you add 18 to both sides and get 2x=28 then simplify to x=14
Answer:
x=14
Step-by-step explanation:
2(x-9)=10
Step one - Simplify both sides
(2)(x)+(2)(-9)=10 (distribute)
2x+-18=10
2x-18=10
Step two - Add 18 to both sides
2x-18+18=10+18
2x=28
Step three - Divide both sides by 2
2x÷2 = 28÷2
x= 14
Answer:
x=14
Solve and find the value of X : −0.17=(x−390)/390+7.2/390 [enter your answer with 3 decimals]
The value of x is approximately 369.186.
To solve the equation -0.17 = (x - 390) / 390 + 7.2 / 390 for x, we can simplify the equation and isolate x.
Given:
-0.17 = (x - 390) / 390 + 7.2 / 390
First, let's simplify the right side of the equation by finding a common denominator:
-0.17 = (x - 390 + 7.2) / 390
Combine like terms:
-0.17 = (x - 382.8) / 390
Multiply both sides of the equation by 390 to eliminate the fraction:
-0.17 * 390 = x - 382.8
-66.3 = x - 382.8
Add 382.8 to both sides of the equation:
-66.3 + 382.8 = x
316.5 = x
Therefore, the value of x is approximately 316.5 (rounded to three decimal places).
Note: There seems to be an error in the given equation. The correct equation should be -0.17 = (x - 390) / 390 + 7.2 / 390, not -0.17 = (x - 390) / 390 + 7.2 / 390.
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Find all real zeros of the function Y = -9x-1
Answer:
x=-1/9; -1/9; (-1/9,0)
(each one is a different way to write the answer)a
Step-by-step explanation:
Zeros of a function are when the y-value of a point on a graph is equal to 0. Plugging in 0 for y in this equation of the function we get 0=-9x-1, which we can solve by adding 9x to both sides of the equation to get 0+9x=-9x+9x-1, or 9x=-1, and divide both sides by 9 to get x=-1/9
Using the expression 10xy + 6, what are the
variables?
Pleasee huryyy!!
Answer:xy
Step-by-step explanation:
She must determine height of the clock tower using a 1.5 m transit instrument (calculations are done 1.5 m above level ground) from a distance 100 m from the tower she found the angle of elevation to be 19 degrees. How high is the clock tower from 1 decimal place?
Step-by-step explanation:
We can use trigonometry to solve this problem. Let's draw a diagram:
```
A - observer (1.5 m above ground)
B - base of the clock tower
C - top of the clock tower
D - intersection of AB and the horizontal ground
E - point on the ground directly below C
C
|
|
|
|
| x
|
|
|
-------------
|
|
|
|
|
|
|
|
|
B
|
|
|
|
|
|
|
|
|
|
|
A
```
We want to find the height of the clock tower, which is CE. We have the angle of elevation ACD, which is 19 degrees, and the distance AB, which is 100 m. We can use tangent to find CE:
tan(ACD) = CE / AB
tan(19) = CE / 100
CE = 100 * tan(19)
CE ≈ 34.5 m (rounded to 1 decimal place)
Therefore, the height of the clock tower is approximately 34.5 m.
A box of 200 baseball cards included 10 cards that featured the Los Angeles Dodgers.
1. What fraction of the cards featured the LA Dodgers. Use simplest form.
2. What is the amount as a decimal?
3. What percent of the cards featured the LA Dodgers?
Answer:
1. 1/20
2. 0.05
3. 5%
Step-by-step explanation:
Hope it helps :)
Have a good day/night
Brainliest pls?
Pls helppp i don’t get it
Answer:
its A correct me if im wrong in the comments
what is the volume of a cereal box that is 2in and 7in and 13in
The volume of the cereal box(rectangular prism) is 182 cubic in.
What is rectangular prism?
A rectangular prism is a three-dimensional shape that has six faces (two top and bottom and four side faces). All sides of the prism are rectangular in shape. So there are three pairs of identical faces. It is also called cuboid.
Given that the dimensions of the cereal box(rectangular prism) are 2in, 7in, 13in
volume=l× b× h( l= length, b=breadth ,h= height)
= 2×7×13
=182
hence the volume is 182 cubic in.
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Mr. Chen has a circular flower garden with a diameter of 5 feet. He put a fence around the
garden to keep rabbits from eating the flowers. About how much fencing did he use?
Answer:
15.7 ft
Step-by-step explanation:
circumference = pi * diameter
c = 3.14 * 5 ft
c = 15.7 ft
Answer: 15.7 ft
A bank loan processing system has three components with individual reliabilities as shown: R 1 = 0.82 R 2 = 0.991 R 3 = 0.98 What would be the reliability of the bank system above if each of the three components had a backup with a reliability of 0.80? How would the total reliability be different?
To calculate the reliability of the bank loan processing system with backup components, we can use the concept of series-parallel system reliability.
In the original system, the three components are connected in series. To calculate the overall reliability of the system, we multiply the reliabilities of the individual components:
R_system = R_1 * R_2 * R_3 = 0.82 * 0.991 * 0.98 ≈ 0.801
So, the reliability of the bank loan processing system without backup components is approximately 0.801.
Now, if each of the three components has a backup with a reliability of 0.80, we have a parallel configuration between the original components and their backups. In a parallel system, the overall reliability is calculated as 1 minus the product of the complement of individual reliabilities.
Let's calculate the reliability of each component with the backup:
R_1_with_backup = 1 - (1 - R_1) * (1 - 0.80) = 1 - (1 - 0.82) * (1 - 0.80) ≈ 0.984
R_2_with_backup = 1 - (1 - R_2) * (1 - 0.80) = 1 - (1 - 0.991) * (1 - 0.80) ≈ 0.9988
R_3_with_backup = 1 - (1 - R_3) * (1 - 0.80) = 1 - (1 - 0.98) * (1 - 0.80) ≈ 0.9992
Now, we calculate the overall reliability of the system with the backups:
R_system_with_backup = R_1_with_backup * R_2_with_backup * R_3_with_backup ≈ 0.984 * 0.9988 * 0.9992 ≈ 0.981
Therefore, the reliability of the bank loan processing system with backup components is approximately 0.981.
Comparing the two scenarios, we can see that introducing backup components with a reliability of 0.80 has improved the overall reliability of the system. The total reliability increased from 0.801 (without backups) to 0.981 (with backups). Having backup components in a parallel configuration provides redundancy and increases the system's ability to withstand failures, resulting in higher reliability.
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a man in a boat rowing from light house whose height is 200 meter.he takes 2minutes to change the angle of elevation top of light house from 60⁰ and 45⁰ find speed of boat
Answer:
The speed of the boat is approximately 0.704 m/s
Step-by-step explanation:
The time it takes the man in the boat to change the angle of elevation from 60° to 45°, t = 2 minutes = 120 seconds
The height of the light house = 200 m
Given that the angle of elevation is reducing, the direction of the man is away from the lighthouse
The initial distance of the man in the boat from the lighthouse = 200 m/(tan(60°)) = (200/√3) m
The final distance of the man in the boat from the lighthouse = 200 m/(tan(45°)) = 200 m
The distance traveled in 2 minutes, d = 200 m - (200/√3) m ≈ 84.53 m
The speed of the boat, v = d/t
∴ v = 84.53 m/(2 min × 60 s/min) ≈ 0.704 m/s
The speed of the boat, v ≈ 0.704 m/s.
Russia has
23,400 miles
of what?
A. continuous coast
lines
B. continuous
highways
C. continuous
mountain ranges