there are two bodies a of mass 5 kg at 40 degrees c temperature and b of mass 50 kg at 40 degrees c. the average speed of a molecule in body a and body b will be

Answer:

94600kgm/s

Explanation:

Linear momentum of a body can be calculated using the formula;

P = mv

Where;

P = linear momentum (Kgm/s)

m = mass of body (kg)

v = speed of the moving body (m/s)

According to the provided information in the question, m = 110kg, v = 860m/s

P = 110 × 860

P = 94600kgm/s

The angular momentum of the earth-moon system measured from the center of the earth is approximately 7.07 x 10^33 kg m^2/s. The angular momentum of the earth-moon system can be estimated by multiplying the moment of inertia of the system by the angular velocity.

The moment of inertia for a solid sphere is (2/5)mr^2, where m is the mass of the sphere and r is the radius.

For the earth, the moment of inertia is (2/5)m_eR_e^2, where R_e is the radius of the earth. For the moon, the moment of inertia is (2/5)m_mR_m^2, where m_m is the mass of the moon and R_m is the radius of the moon.

Assuming that both the earth and moon are rotating in the same sense, the angular velocity of the system can be calculated by dividing the angular displacement (2π radians) by the time it takes for one complete revolution, which is the sidereal month of about 27.32 days.

Using the values for the moment of inertia and angular velocity, the angular momentum of the earth-moon system can be estimated as:

L = (2/5)m_eR_e^2ω + (2/5)m_mR_m^2ω

where ω is the angular velocity. Plugging in the values and solving for L, we get:

L = (2/5)m_eR_e^2(2π/27.32 days)

L = (2/5)m_e(6.371 x 10^6 m)^2(2π/27.32 x 24 x 60 x 60 seconds)

L = 7.07 x 10^33 kg m^2/s

Therefore, the angular momentum of the earth-moon system measured from the center of the earth is approximately 7.07 x 10^33 kg m^2/s.

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Explanation:

Given data

velocity v= 25m/s

The time it takes to put on brake t= 0.3s

the distance covered when the  brake was put on is

v=s/t

s= v*t

s= 25*0.3s

s= 7.5m

hence the distance covered is 7.5m

Also the rate of decrease in aceleration is 5m/s^2

we can also calculate the distance covered at this rate

v^2=u^2+2as

25^2= 0+2*5*s

625=10s

divide both sides by 10

s=625/10

s= 62.5m

The total  distance covered between putting on the brakes and decelareation is  7.5+62.5= 70m

Given that the tree is 75m ahead, the car would not hit the tree

Answer:

Hey mate.....

Explanation:

This is ur answer......

Winds and currents in the Pacific flow predominantly from East to West. Above the equator Pacific Ocean trade winds blow from the northeast. Below the equator they blow from the southeast.

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The 46.4 kg wolf moving at a speed of 12.2 m/s has a kinetic energy of 3,456.98 J.

The amount of work done on an item and its acceleration following a moment of inertia caused by external forces are two aspects that affect the overall kinetic energy of an object.

The formula: gives the kinetic energy (KE) of an item.

KE = (1/2) × mass × velocity²

where velocity is measured in meters per second (m/s) and mass is measured in kilograms (kg).

Plugging in the following numbers will allow us to determine the wolf's kinetic energy:

KE = (1/2) × 46.4 kg × (12.2 m/s)²

= (1/2) × 46.4 kg × 148.84 m²/s²

= 3,456.98 joules (J)

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Given,

The volucme of Kayak, V₁=0.285 m³

The mass of the Kayak when the man is sitting in it, m₁=75 kg

The volume of the man, V₂=0.066 m³

The density of the man, d=1000 kg/m³

The mass of the man inside the Kayak is given by,

On substituting the known values,

The mass of the empty Kayak is,

Given that only half of the volume of the man is inside the Kayak when he is sitting in it. Half of the man's volume which is outside the Kayak will be considered in the total volume of the Kayak when he is sitting in it. Thus we have to subtract half of his volume, which is outside the Kayak, while we calculate the density of the Kayak.

Thus the density of the empty Kayak is

On substituting the known values,

Thus the density of the Kayak is 35.71 kg/m³

Answer:

A voltmeter device determines the electrical potential difference between two points in an electrical circuit. The voltmeter has high internal resistance because of which it does not allow current to pass through it. So, it is in parallel connection with the circuit component as it does not draw any current and also does not affect the net resistance of the circuit.

Explanation:

the force between the two wires if they are separated by 2.50 cm is 0.525 N.

Given that force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires and that a force of 0.750 N exists between wires that are 1.75 cm apart and that we are supposed to find the force between them if they are separated by 2.50 cm.

Let the initial force be F₁ and the initial distance be d₁.

Therefore, we can write the relationship between force and distance as;

F₁d₁ = F₂d₂

Where

;F₁ = 0.750 N (initial force)

d₁ = 1.75 cm (initial distance)

F₂ = ? (force at new distance)

d₂ = 2.50 cm (new distance)

Let us find F₂;F₁d₁ = F₂d₂F₂ = F₁d₁/d₂

Now substitute the values we know;

F₂ = (0.750 N x 1.75 cm) / 2.50 cmF₂ = 0.525 N

Therefore, the force between the two wires if they are separated by 2.50 cm is 0.525 N.

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Answer:

This is basically Simple Harmonic Motion - where the wave disturbance is in the same direction as the wave direction.

That describes (B).

note that y = A cos ω t          where the disturbance is y and ω the the angular frequency and is in the same direction as the disturbance y

This seems the make (D) a satisfactory answer

The projection of the disturbance y is perpendicular (sinusoidal) to the time axis, but the disturbance is still in the same direction as the wave motion

The wave generated by a spring is a transverse wave where, the particles oscillate in a direction perpendicular to the the wave motion.

Mechanical waves are energy transfer through a medium. Unlike electromagnetic waves, mechanical waves cannot transfer through vacuum.

There are two types of mechanical waves namely, transverse waves and longitudinal waves. Transverse waves are those in which the oscillation of particles or disturbance is created perpendicular to the wave motion.

In longitudinal waves, the particle motion or disturbance is created along the wave motion. The wave generated in a spring is transverse wave thus, the disturbance created by moving it up and down will be perpendicular to the wave motion.

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Answer:

E = 149.92 N/C

Explanation:

Given that,

The power emitted by a sinusoidal light is 60 W

Intensity is equal to the power per unit area. It can be given by :

\(I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{60}{4\pi \times (0.4)^2}\\\\I=29.84\ W/m^2\)

The relation between the amplitude of the electric field and the intensity is given by :

\(I=\dfrac{E_o^2c \epsilon_o}{2}\)

Here, \(E_o\) is the amplitude of the electric field

\(E_o=\sqrt{\dfrac{2I}{c\epsilon_o}} \\\\E_o=\sqrt{\dfrac{2\times 29.84}{3\times 10^8\times 8.85\times 10^{-12}}}\\E_o=149.92\ N/C\)

So, the amplitude of the electric field is 149.92 N/C.

The ball will reach the ground after 1.8 seconds.

We have a ball thrown directly downward.

We have to determine after what time interval does it strike the ground,

According to the question -

u = 8.55 m/s

S = 30.4 m

a = 9.8 m/\(s^{2}\)

Using the Second Equation of Motion -

x = ut + \(\frac{1}{2} at^{2}\)

Substituting the values -

30.4 = 8.55t + 4.9\(t^{2}\)

4.9\(t^{2}\) + 8.55t - 30.4 = 0

Solve this quadratic equation, you will get -

t = 1.8 seconds.

Hence, the ball will reach the ground after 1.8 seconds.

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Answer:

False.

Explanation:

An aurora is a natural electric phenomenon that creates bright and colorful light displays in the sky. These dramatic and colorful lights are created when electrically charged particles from solar winds enter the Earth's atmosphere and interact with gases in the atmosphere.

Resonance

The function of the auditory canal is to enhance the intensities of some frequency sounds by means of Resonance.

Resonance happens when an object's oscillations become more intense because they are matched by the vibrations of another object.

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Answer:

the fast carbon cycle follows the movement of carbon through living (biotic) components of an ecosystem. This occurs faster because life moves more quickly. The fast carbon cycle focuses primarily on the biosphere, while the slow carbon cycle is more involved with the hydrosphere, lithosphere and atmosphere.

Explanation:

Answer: B. Muscular fitness training increases muscle mass, which increases your metabolism

Answer:

Approximately \(1.04 \; {\rm J \cdot g^{-1} \cdot K^{-1}}\).

Explanation:

Multiply energy input by efficiency to find the useful energy output:

\(\begin{aligned}& (\text{useful out}\text{put}) \\ &= (\text{efficiency})\, (\text{energy in}\text{put}) \\ &= (87.5\%)\, (1560\; {\rm kJ}) \\&= (0.875)\, (1560\; {\rm kJ}) \\ &= 1365\; {\rm kJ}\end{aligned}\).

In other words, \(1365\; {\rm kJ}\) of energy was supplied to the air in the building.

The standard unit of energy is Joules (\({\rm J}\).) Apply unit conversion:

\(\begin{aligned}(1365\; {\rm kJ})\, \left(\frac{10000\; {\rm J}}{1\; {\rm kJ}}\right) = 1.365\times 10^{6}\; {\rm J}\end{aligned}\).

Let \(c\) denote the specific heat capacity of the air in this building. Let \(m\) denote the mass of the air.

Let \(Q\) denote the energy supplied to the air. Let \(\Delta T\) denote the change in temperature. The equation \(Q = c\, m\, \Delta T\) relates these quantities.

In this question, the change in the temperature of the air in this building is:

\(\Delta T = (22.1\; {\rm ^{\circ} C}) - (11.6\; {\rm ^{\circ} C}) = 10.5\; {\rm K}\).

Rearrange the equation \(Q = c\, m\, \Delta T\) to find specific heat capacity \(c\):

\(\begin{aligned}c &= \frac{Q}{m\, \Delta T} \\ &= \frac{1.365 \times 10^{6}\; {\rm J}}{(125\; {\rm kg})\, (10.5\; {\rm K})} \\ &\approx 1.04 \times 10^{3}\; {\rm J \cdot kg^{-1} \cdot K^{-1}}\end{aligned}\).

Radio waves are diffracted by large objects such as buildings, whereas light is not noticeably diffracted, because b) the wavelength of light is much smaller than the wavelength of radio waves.

The diffraction is the bending of waves around obstacles or through small openings, and the amount of diffraction is proportional to the size of the obstacle or opening and the wavelength of the wave. Since radio waves have much longer wavelengths than visible light, they are more easily diffracted by large objects such as buildings. On the other hand, visible light has a much smaller wavelength than radio waves, which makes it less prone to diffraction. Polarization and coherence are not directly related to diffraction.

Polarization refers to the direction of oscillation of the electromagnetic waves, while coherence refers to the consistency of phase between waves. Therefore, the correct answer is b) the wavelength of light is much smaller than the wavelength of radio waves. Radio waves are diffracted by large objects such as buildings, whereas light is not noticeably diffracted, because b) the wavelength of light is much smaller than the wavelength of radio waves.

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Letter A is the plane surface

Letter B is the incident ray

Letter C is the reflected ray.

The terms of the ray diagram is illustrated as follows;

(i) This arrow indicates the incident ray, which is known as the incoming ray.

(ii) This arrow indicates the normal, a perpendicular line to the plane of incidence.

(iii) This arrow indicates the reflected ray; the out going arrow.

(iv) This the angle of incident or incident angle.

(v) This is the reflected angle or angle of reflection.

Thus, based on the given letters, we can match them as follows;

Letter A is the plane surface (surface containing the incident, reflected rays)

Letter B is the incident ray

Letter C is the reflected ray.

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Answer:

B) is the answer

Explanation:

A) is 25 N

B) is 36N

C) is 30N

D)15N

Answer:

Solar panels have increased in efficiency over the past 20 years

Explanation:

Because if efficiency have increased other technologies will be discovered

Answer:

Solar panels have increased in efficiency over the past 20 years

Explanation:

Answer:  If there are no air resistance the hailstones would hit the earth at velocities near 350 m/s and melt before they hit the ground.

Explanation: Hope This Helps

Explanation:

Given parameters:-

To find:-

Solution:-

Here , we are provided frequency of electromagnetic wave and we have to find the wavelength of the wave. To find the wavelength we have to divide the speed of light by given frequency. therefore,

\(\tt\red{wavelength( \lambda)= \frac{speed(c)}{frequency(f)}}\)

\( \rightarrow \sf \: \lambda = \frac{3 \times {10}^{8} }{8.2 \times {10}^{14} } \\ \\ \rightarrow \sf \: \lambda = \frac{3 \times {10}^{8} \times {10}^{ - 14} }{8.2} \\ \\ \rightarrow \sf \: \lambda = 0.36 \times {10}^{6} \\ \\ \rightarrow \sf \: \lambda = 36 \times {10}^{4}m\)

Answer:

Plural cerebrums cerebra The largest part of the vertebrate brain, filling most of the skull and consisting of two cerebral hemispheres divided by a deep groove and joined by the corpus callosum, a transverse band of nerve fibers. The cerebrum processes complex sensory information and controls voluntary muscle activity.

Explanation:

A single converging lens cannot produce a real image that is inverted and is larger with respect to the object(c).

A single converging lens can produce both real and virtual images, and the characteristics of the image depend on the location of the object relative to the lens. When an object is located beyond the focal point of the lens, a real image is formed on the opposite side of the lens. The image is inverted and smaller than the object.

If the object is positioned between the focal point and the lens, a virtual image is formed on the same side as the object. The virtual image is upright and larger than the object.

However, a single converging lens cannot produce a real image that is inverted and larger than the object. This is because when the object is within the focal length of the lens, the image formed is virtual, upright, and larger than the object. So c is correct option.

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Answer:

The work is done by the force 100 NM.

Explanation:

=5kg * 2 m/s^2

=5* 2 N (kg*m/s^2=N)

=10N

Work done = force* distance

=10N* 10

= 100 NM

For an object of mass 5 kg accelerating at the rate of 2 m/s², then the work done by the force on the object will be 100 Nm.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Mass of the object, m = 5 kg

Acceleration, a = 2 m/s²

Distance, d = 10 m

W = f × d

W = m × a × d

W = 5 × 2 × 10

W = 100 Nm

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The de Broglie wavelength for a proton moving with a speed of 1.0 x 10⁶ m/s is approximately 6.63 x 10⁻⁹ meters.

The de Broglie wavelength (λ) of a particle is given by the equation:

λ = h / p

Where:

λ is the de Broglie wavelength

h is the Planck's constant (approximately 6.63 x 10⁻³⁴ joule-seconds)

p is the momentum of the particle

The momentum of a particle is given by:

p = mv

Where:

m is the mass of the particle

v is the velocity of the particle

In this case, we are dealing with a proton. The mass of a proton (m) is approximately 1.67 x 10⁻²⁷ kilograms.

Given the speed of the proton (v) as 1.0 x 10⁶ m/s, we can calculate the momentum (p):

p = mv = (1.67 x 10⁻²⁷ kg) x (1.0 x 10⁶ m/s) = 1.67 x 10⁻²¹ kg·m/s

Now, we can calculate the de Broglie wavelength (λ):

λ = h / p = (6.63 x 10⁻³⁴ J·s) / (1.67 x 10⁻²¹ kg·m/s) ≈ 6.63 x 10⁻⁹ meters.

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The acceleration of a bullet that leaves a 28-in rifle barrel at 2700 ft/s is 1.562 x 10⁶ m/s² and its time in the barrel is 0.0017s

a) How to determine the acceleration of the bullet

Converting inches to a foot

1 inch = 1/12 foot

28-in =  1/12 x 28 ft

28-in = 2.33ft

Therefore, the distance, s, covered by the bullet is 2.333ft

Using one of the equations of motion

2as = u² - v²

The initial velocity is 0

Where a = acceleration of the bullet

            s = distance

             u = initial velocity

             v = final velocity

a = v² - u² ÷ 2s

= (2700 ft/s)² - 0 ÷ 2 (2.333ft)

a = 1.562 x 10⁶ m/s²

b) How to determine the time of the bullet in the barrel

s = v² + u² ÷ 2

t = 2 ÷ (v² + u²)

t = 2 (2.333ft) ÷ (0 + 2700 ft/s)

t = 0.0017s

In summary, a bullet that leaves a 28-in rifle barrel at 2700 ft/s would have an acceleration of 1.562 x 10⁶ m/s², spending a time of 0.0017s in the barrel.

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Yes, ultraviolet light and irradiation can destroy riboflavin.

Riboflavin is a light-sensitive vitamin that can break down when exposed to light, particularly UV light. This is why milk and other products that are fortified with riboflavin are often packaged in opaque containers to protect the vitamin from light damage.

When ultraviolet (UV) radiation activates the vitamin B2 riboflavin, active oxygen is produced, which destroys cell membranes and stops the spread of pathogens like viruses, bacteria, and protozoa in all blood products.

However, some studies suggest that controlled exposure to UV light and riboflavin can be used to disinfect surfaces and water. In this process, called UV-C irradiation, the riboflavin helps to enhance the antimicrobial effects of the UV light.

Riboflavin can therefore be destroyed by radiation and UV light.

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The displacement of the small piece of the string at x = 0.360 m and t = 0.150 s is approximately -0.0198 m.

To determine the displacement of a small piece of the string at a specific position and time, use the equation for the transverse wave:

y(x, t) = A × sin(kx - ωt + φ)

where:

y(x, t) = displacement of the string at position x and time t,

A = amplitude of the wave,

k = wave number (k = 2π/λ, where λ is the wavelength),

ω = angular frequency (ω = 2πf, where f is the frequency),

φ = phase constant.

Given the values:

A = 0.0700 m (amplitude),

v = 8.00 m/s (wave speed),

λ = 0.320 m (wavelength),

x = 0.360 m (position),

t = 0.150 s (time).

First, calculate the wave number (k) using the wavelength:

k = 2π / λ = 2π / 0.320 ≈ 19.63 rad/m

Next, calculate the angular frequency (ω) using the wave speed and wavelength:

v = ω / k

ω = v × k = 8.00 × 19.63 ≈ 157.04 rad/s

Now plug the values into the equation to find the displacement at the given position and time:

y(0.360, 0.150) = 0.0700 × sin(19.63 × 0.360 - 157.04 × 0.150)

y(0.360, 0.150) ≈ 0.0700 × sin(7.087 - 23.556)

= 0.0700 × sin(-16.469)

= -0.0198

Therefore, the displacement of the small piece of the string at x = 0.360 m and t = 0.150 s is approximately -0.0198 m.

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