The probability of choosing a humbug is 3/5.
The measurement and study of uncertainty are topics covered in the mathematical field of probability. The likelihood or chance of an event happening is being studied. To put it another way, the probability is a measurement of the possibility that an event will occur.
Let T represent the overall quantity of candies in the jar. Then, we are aware of:
T = 4 + 3x + 6 + 2x = 10 + 5x
Picking an eclair has a 1/15 chance of happening. The jar contains 4 eclairs, so we can construct the following equation:
P(eclair) = 4/T = 1/15
Solving for T,
T = 60
Inputting this value of T into the formula for the number of humbugs yields the following results:
Number of humbugs = 3x + 6 = 3(10) + 6 = 36
The probability of choosing a humbug is:
P(humbug) = number of humbugs/T = 36/60 = 3/5
Therefore, the probability of choosing a humbug is 3/5.
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If a two sided test of hypothesis is conducted at a 0.05 level of significance and the test statistic resulting from the analysis is z-0.92. The conclusion is: O Reject the null hypothesis Fail to reject the null hypothesis Reject the alternative hypothesis
The correct conclusion in this case would be "Fail to reject the null hypothesis."
When conducting a hypothesis test, the null hypothesis is typically assumed to be true unless there is sufficient evidence to reject it in favor of the alternative hypothesis. In this scenario, with a two-sided test at a 0.05 level of significance, the critical value (or cutoff) for the test statistic would be ±1.96.
Since the test statistic of z-0.92 does not exceed the critical value of ±1.96, we do not have enough evidence to reject the null hypothesis. Therefore, the conclusion is to fail to reject the null hypothesis.
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During a very cold winter, water pipes sometimes burst due to water expanding when freezing. thawing producing pressure on the pipes. water contracting when freezing. the ground contracting when colder. none of the above
Answer:
THAWING producing pressure on Pipes
Step-by-step explanation:
As more water fills and freezes the pressure on the pipes also increases and it gets much denser causing it to burst
Find the mistake and show the correct steps and solution
Answer:
The mistake happens in the 4th line.
Step-by-step explanation:
The first 3 lines are correct until the 4th line which is 2=6x. This is wrong. If we go back a line to the third line, it is 22=-20+6x. The part that was wrong was that they subtracted 20 from 22 to get 2. We are supposed to add 20 to each side because the -20 is negative. So the 4th line should be 42=6x. Then, we know that 6 times 7 is 42, so x is equal to 7.
22 + 53x + x = -20 + 60x
22 + 54x = -20 + 60x
22 = -20 + 6x
42 = 6x
x = 7
answer all questions 9-13!!!!
Answer:
9) 3.7 in
10) 12 in²
11) 18 in³
12) V=432π cm³
TSA= 216π cm²
13)V=448π ft³
TSA=240π ft²
Step-by-step explanation:
9) Since all side of the trapezium are the same the height = perpendicular line which is 3.7 in
10) 3×4 (the quadrilateral at the bottom)
11)∵ A= Cross-sectional area× height
⇒A= Area of the trapezium × 4
∴ A=\(\frac{1}{2} \\\) (sum of the parallel sides) × 4
A=\(\frac{1}{2} \\\) (3+6) × 4
A= 18 in²
12) V=πr²h
V=π(6)²(12)
⇒V=432 cm³
TSA=2(πr²)+2πrh
TSA=2(π(6)²)+2π(6)(12)
⇒TSA=240π cm²
13. V=πr²h
V=π(8)²(7)
V=448π ft³
TSA=2(πr²)+2πrh
TSA=2(π(8)²)+2π(8)(7)
TSA=240π ft²
9) 3.7 in
10) 12 in²
11) 18 in³
12) V=432π cm³
TSA= 216π cm²
13)V=448π ft³
TSA=240π ft²
y = 2/5 x-3 in standard form fast please 30 points
Please help solve 5 and 6 and show work please
a. The actual area of the kitchen is 128 square feet.
b. the couch measures 1.25 inches across in the scale drawing.
How do we calculate?The scale is 1/4 inch = 2 feet,
meaning that in the drawing, each inch represents 8 feet (since 2 feet/0.25 inches = 8 feet/inch).
The kitchen in the drawing has an area of 2 square inches.
we apply the scale factor to find the actual area in square feet,
1 inch in the drawing = 8 feet in real life
So, 2 square inches in the drawing = 2 x 8 x 8 = 128 square feet in real life.
Hence, the actual area of the kitchen is 128 square feet.
we also apply the scale factor to find the couch measurement in the scale drawing,
1 inch in the drawing = 8 feet in real life
10 feet in real life = 10/8 = 1.25 inches in the drawing.
In conclusion, the couch measures 1.25 inches across in the scale drawing.
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In a class of 34 students,19 of them are girls.
What percentage of the class are girls?
Give your answer to 1 decimal place
Answer:
55.9%
Step-by-step explanation:
To find the percentage of girls in the class, we can use the following formula:
Percentage = (Number of girls / Total number of students) * 100
Number of girls = 19
Total number of students = 34
Percentage = (19 / 34) * 100
= 55.88235 % ≈ 55.9 % ( rounded off to one decimal place)
a fair coin is tossed at random 100 times. what is the approximate probability that the number of heads will exceed 60? what is the approximate probability that the number of heads will be at least 40 but less than 60?
Therefore ,the probability that the number of heads will exceed 60 is 0.0176
What is probability ?The number of outcomes that could occur is the basis for the response is known as probability .To this question the outcome in this case might be either head or tail. Therefore, there is a 50% chance that the result will be a head.
Here,
The fair coin is tossed at random 100 times.
So we have to find probability that the number of heads will exceed 60
Thus,
=> P(number of heads will exceed 60) = \(\frac{C^{100} _{1} }{C^{2} _{60}}\)
=> P(number of heads will exceed 60) = 0.01760010010885238
=> P(number of heads will exceed 60) = 0.0176
Therefore ,the probability that the number of heads will exceed 60 is 0.0176
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Please help me! 10 pts and brainliest! please
Solve for x.
Answer choices and triangle are in the image above, please be correct and thanks! Have a great day :)
Answer:
B is correct
Step-by-step explanation:
i think
pls help me. i need it
Answer:
Step-by-step explanation:
If a = 2+√3 , find the value of (a-1/a)^2
Answer:
1
Step-by-step explanation:
I dont get this at all
The equation of line that shows the relation between time and temperature is x + 2y = 8.
What is equation of line?A line's equation is an algebraic way of expressing the collection of points that make up a line in a coordinate system.
The many points that collectively make up a line on the coordinate axis are represented as a group of variables (x, y) to create an algebraic equation, also known as an equation of a line.
In the given graph,
A straight line is given which shows the relation between time and temperature.
To find the equation of line, which shows the relation between time and temperature.
Use formula of equation of line,
y - y₁= ((y₂ - y₁)/(x₂ - x₁)) (x- x₁)
Let 2 points on the graph (2, 3) and (4,2)
The equation of line,
y - 3 = ((2-3)/(4-2))(x-2)
y - 3 = (-1/2)(x - 2)
2y - 6 = - x + 2
x + 2y = 8
The required equation of line is x + 2y = 8.
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State if the three numbers can be the measures of the sides of a triangle.
1) 10,8,6
2) 6, 18, 12
3) 8, 1,7
4) 7, 2,7
Answer:
Step-by-step explanation:
1) Makes a triangle. 6+8>10 In fact this one makes a right triangle. Try it using a = 6 b = 8 c = 10
2) 6 + 12 should exceed the third side. If these two just equal the third side (as these two do) then no triangle is formed.
3) Same with this one 7 + 1 = 8. No triangle is formed. Just a straight line
4) This one is fine. It makes an isosceles triangle with 2 sides = to 7. Any 2 are bigger than the third.
8. Find the distance between M(-2, 3) and N(8,2). number 8 please
Answer:
The answer is \(\sqrt{x} 101\)
Step-by-step explanation:
Answer:
D.\(\sqrt{101}\)
Step-by-step explanation:
The formula is = \(\sqrt{(x2-x1)^{2}+(y2-y1)^{2}\)
So, x1=-2 ; y1=3; x2=8; y2=2
putting these values in the formula the result will be \(\sqrt{101}\)
Hope, this helps you.
Which is the lower temperature? (Assume temperatures to be exact numbers.) (a) 273
∘
C or 273
∘
F ? 273
∘
C 273∘F They are the same temperature. (b) 200
∘
C or 353
∘
F ? 200
∘
C 353
∘
F They are the same temperature.
The lower temperature is 200∘C for (a) and 353∘F for (b). In order to determine the lower temperature between two measurements given in different temperature scales, we need to convert them to a common scale.
The common scale we can use is the Kelvin scale, as it is an absolute temperature scale.
(a) To compare 273∘C and 273∘F, we need to convert them to Kelvin. The conversion formula for Celsius to Kelvin is K = C + 273.15, and for Fahrenheit to Kelvin, K = (F - 32) × 5/9 + 273.15.
- For 273∘C, we have K = 273 + 273.15 = 546.15K.
- For 273∘F, we have K = (273 - 32) × 5/9 + 273.15 ≈ 523.15K.
Since 523.15K is lower than 546.15K, the lower temperature is 273∘F.
(b) To compare 200∘C and 353∘F:
- For 200∘C, we have K = 200 + 273.15 = 473.15K.
- For 353∘F, we have K = (353 - 32) × 5/9 + 273.15 ≈ 423.15K.
Since 423.15K is lower than 473.15K, the lower temperature is 353∘F.
In summary, the lower temperature is 200∘C for (a) and 353∘F for (b).
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the standard error of the regression, se, is calculated by taking the square root of divided by .
The standard error of the regression (se) is calculated by taking the square root of the mean squared error (MSE) divided by the degrees of freedom (df).
The mean squared error (MSE) is calculated by summing the squared residuals (the differences between the actual observed values and the predicted values) and dividing by the number of observations minus the number of predictors (variables) in the regression model.
The formula for the mean squared error is:
MSE = Σ(residuals^2) / (n - k)
where Σ denotes the sum, residuals^2 represents the squared residuals, n is the number of observations, and k is the number of predictors in the regression model.
To calculate the standard error of the regression, se, we take the square root of the mean squared error divided by the degrees of freedom:
se = √(MSE / df)
The degrees of freedom (df) in a regression model is equal to the number of observations minus the number of predictors (k).
Therefore, the standard error of the regression, se, is calculated by taking the square root of the mean squared error divided by the degrees of freedom (df).
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A maintenance worker needs to wax a restaurant floor shaped like the image shown.
A six-sided figure. There is a horizontal base of 33 feet then another horizontal base below it of 19 feet. The longest side is to the right and is 37 feet. The top is 28 feet. There is a perpendicular from the vertex of the top to the first base of 33 that is labeled 14 feet.
If the wax cost $1.67 a square foot, how much will the wax cost to cover the floor?
$832.50
$1,300.10
$1,664.99
$2,600.19
PLS HURRY HAVE TO SUBMIT THIS IN A COUPLE OF MINUTES!
If the wax cost $1.67 a square foot, the cost of wax to cover the area of the floor is $1,664.99.
The correct option is C.
What is the total area of the floor?We can start by finding the area of the floor.
The floor is made up of a trapezoid and a rectangle.
The area of a trapezoid can be calculated as:
A = (b1 + b2)/2 * h
where b1 and b2 are the lengths of the bases and h is the height.
The trapezoid has a height of 14 feet and bases of 33 feet and (28 - 19) or 9 feet. So its area is:
A = (33 + 9)/2 * 14
A = 294 square feet
The rectangle has a base of 19 feet and a height of 37 feet. So its area is:
A = 19 * 37
A = 703 square feet
The total area of the figure is the sum of the areas of the trapezoid and triangle:
A = 294 + 703
A = 997 square feet
Finally, to find the cost of the wax, we multiply the area by the cost per square foot:
Cost = 997 * $1.67
Cost = $1664.99
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There are 20 triangles and 4 circles. What is the simplest ratio of circles to total shapes?
PLS HURRY HELP
Answer:
Im pretty sure its 5
Step-by-step explanation:
5:1 due to 20/4 would be 5. I can give you more of an explaination if needed.
Answer:
5 triangles to 4 circles.
Solve and explain it clearly. 1. Use the substitution method to show that the solution of T(n) = T(n-1) + n is O(n^ 2 ). 2. Use a recursion tree to determine a good asymptotic upper bound on the recurrence T(n) = 2T(n-1) + 1. Use the substitution method to verify your answer.
We can conclude that T(n) = O(n²) for the recurrence relation T(n) = T(n-1) + n. We can conclude that T(n) = O(2ⁿ) is a valid upper bound for the recurrence relation T(n) = 2T(n-1) + 1.
1. To show that the solution of T(n) = T(n-1) + n is O(n²), we can use the substitution method. Let's assume that T(n) = O(n²). This means there exists a constant c and a positive integer k such that T(n) ≤ cn² for all n ≥ k.
Using the substitution method:
T(n) = T(n-1) + n
≤ c(n-1)² + n (by the assumption T(n-1) ≤ c(n-1)²)
= cn² - 2cn + c + n
≤ cn² - cn + n (for large values of n)
Now, we need to find values of c and k such that cn² - cn + n ≤ cn² for all n ≥ k. Choosing c = 2 and k = 1, we have:
2n² - n + n ≤ 2n² for all n ≥ 1
Therefore, we can conclude that T(n) = O(n²) for the recurrence relation T(n) = T(n-1) + n.
2. For the recurrence relation T(n) = 2T(n-1) + 1, let's use a recursion tree to determine an asymptotic upper bound. Starting with T(0) as the root, each node has two child nodes corresponding to T(n-1). Each node also has a constant cost of 1.
The height of the recursion tree is n, and at each level, the cost doubles. Therefore, the total cost of all levels in the tree is 2⁰ + 2¹ + 2 + ... + 2⁽ⁿ⁻¹⁾ = 2ⁿ - 1.
Hence, the asymptotic upper bound for T(n) is O(2ⁿ), as the cost increases exponentially with respect to n. Using the substitution method to verify this answer, let's assume T(n) = O(2ⁿ). This means there exists a constant c and a positive integer k such that T(n) ≤ c * 2ⁿ for all n ≥ k.
Using the substitution method:
T(n) = 2T(n-1) + 1
≤ 2(c * 2⁽ⁿ⁻¹⁾) + 1 (by the assumption T(n-1) ≤ c * 2⁽ⁿ⁻¹⁾)
= 2cn + 1
≤ c * 2ⁿ for large values of n
Thus, we can conclude that T(n) = O(2ⁿ) is a valid upper bound for the recurrence relation T(n) = 2T(n-1) + 1.
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Last year, Marshall withdrew $8,000 from his RRSP under the Lifelong Learning Program to fund a one-year program at a community college. This year, he worked full-time but, he would like to pursue a university degree beginning next year. Marshall is wondering whether he can participate in the LLP again next year. What statement is true?
a) Provided he repays his LLP balance in full by the end of this year, Marshall can participate in the LLP again next year.
b) Marshall can only participate in the LLP once over his lifetime. However, his wife can make a LLP withdrawal from her RRSP on his behalf.
c) He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.
d) He can only participate in the LLP a second time if he repays his LLP balance in full and waits 5 years before he returns to school.
Marshall is wondering whether he can participate in the LLP again next year. The statement that is true is "He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.
The Lifelong Learning Plan is a program that helps Canadian residents finance their post-secondary education through their registered retirement savings plans (RRSP). If an individual is attending school full-time, they can withdraw up to $10,000 a year from their RRSP under the program, or up to $20,000 in total. There are certain rules that must be followed by an individual participating in the LLP. For example, withdrawals must be made within four years of enrolling in an eligible educational program, and repayments must begin within the same period.
Here are the statements: Provided he repays his LLP balance in full by the end of this year, Marshall can participate in the LLP again next year.Marshall can only participate in the LLP once over his lifetime. However, his wife can make a LLP withdrawal from her RRSP on his behalf. He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000. He can only participate in the LLP a second time if he repays his LLP balance in full and waits 5 years before he returns to school.The correct statement is: He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.
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Ethan Purchased A new cell phone for $75.00. The cost of the phone is included in his first months bill. His cell phone plan charges $0.06 for each minute used. If Ethan has $90.00 to spend on his first month bill, what is the maximum Number of minutes he can use?
Answer:
he had $90
he bought a phone for $75
90-75=15
he has $15 now
15÷0.06=1500÷6=250 minutes
I will give thanks, brainliest, and all the points on the questions if someone answers my unanswered questions. They are 50 points each.
What is the solution of this linear equation see photo
SOLUTIION
The given equations are
\(p+q+r=32,p-r=4,2p+q=36\)This further gives
Therefore the solutions are:
\(p=\frac{-q+36}{2},r=\frac{36-q}{2}-4\)From the option considering the value q=8, it follows
\(\begin{gathered} p=\frac{-8+36}{2} \\ p=14 \end{gathered}\)And
\(\begin{gathered} r=\frac{36-8}{2}-4 \\ r=14-4 \\ r=10 \end{gathered}\)Therefore the solution is
\((14,8,10)\)A group of 4 friends have a bag of 49 sweets. They divide the sweets equally between them. a) How many sweets does each friend get? b) How many sweets are left over
Answer:
a) Each friend gets 12 sweets
b) There is 1 sweet left
Step-by-step explanation:
When you divide 49 by 4 you will get 12 with a remainder 1.
49 ÷ 4 = 12 R1
The remainder is the left over while the total result is how much each friend gets.
Answer:
A) 12
B) 1
Step-by-step explanation:
49 cannot be divided equally among the 4 friends but 48 can be divided.
A) So,
48/4 = 12 sweets
Each friend gets 12 sweets
B) 1 sweet is left
Solve (x-2)(2x-1) = 0
Answer:
x = 2
x = 1/2
Step-by-step explanation:
To solve the given equation (x-2)(2x-1) = 0, we need to find the values of 'x' that make the left-hand side of the equation equal to zero. For this, we need to use the zero product property, which states that if the product of two factors is zero, then at least one of the factors must be zero.
Using the zero product property, we can set each factor equal to zero and solve for 'x'.
First factor: x - 2 = 0
Adding 2 to both sides, we get:
x = 2
Second factor: 2x - 1 = 0
Adding 1 to both sides, we get:
2x = 1
Dividing by 2 on both sides, we get:
x = 1/2
Therefore, the solutions to the given equation (x-2)(2x-1) = 0 are x = 2 and x = 1/2.
We can verify our solutions by plugging them back into the original equation and checking if the left-hand side equals zero.
When x = 2, we have:
(x-2)(2x-1) = (2-2)(2(2)-1) = 0, which is true.
When x = 1/2, we have:
(x-2)(2x-1) = (1/2-2)(2(1/2)-1) = (-3/2)(0) = 0, which is also true.
Therefore, our solutions are correct.
FYI, you could've also multiplied the polynomials to get a quadratic equation, though this is terribly inefficient for this case.
Answer:
In short, to solve the equation (x-2)(2x-1) = 0, we use the zero product property by setting each factor equal to zero and solving for x. The solutions are x = 2 and x = 1/2.
Step-by-step explanation:
The equation (x-2)(2x-1) = 0 can be solved by finding the values of x that make the left-hand side of the equation equal to zero.
To do this, we can use the zero product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero.
Therefore, we set each factor equal to zero and solve for x:
x-2 = 0 or 2x-1 = 0
Solving each equation for x, we get:
x = 2 or x = 1/2
So the solutions to the equation (x-2)(2x-1) = 0 are x = 2 and x = 1/2.
can someone please help me?
Answer:
b i think
Step-by-step explanation:
becuase 45f in total and for every hour it decreses 2f the anwser would be b but i may be wrong
A circle has a radius of 11 meters. What is the area of the circle?
Answer:
A≈380.13 m²
Step-by-step explanation:
looked it up
Answer:
A= 380.13 m²
Step-by-step explanation:
A=\(\pi r^{2}\)
A= \(\pi\)x\(11^{2}\)
A= 380.13
8 divided by 0.61 show me how you solved it
helpppp me please with this exercise
\(\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=6\\ \theta =80 \end{cases}\implies A=\cfrac{(80)\pi (6)^2}{360} \\\\\\ A=8\pi \implies A\approx 25.13~mi^2\)
Answer:
Step-by-step explanation:
PLS IT'S DUE!!
The longer leg of a 30⁰-60⁰-90⁰ triangle is 5√3 . Find the length of the hypotenuse.
explain how you got it.
Answer:
The answer is 10
Step-by-step explanation:
The longer leg of this triangle is √3 times longer than the shorter leg. Since the longer leg is 5√3, then the shorter leg will be 5. The hypotenuse is twice the size of the shorter leg, so 5*2 is 10.