There are no external force acting during collision of two object then which of the following statement is true?
a. the total momentum before the collision is always equal to the total momentum after the collision
b. both momentum and kinetic energy are conserved in the collision
c. the two objects must stick together
d. the speed of each object must remain the same before and after the collision
e. the momentum of ecah object must remain the same before and after the collision

This question involves the concept of Colomb's Law and electrostatic force.

The electrostatic force will be "0.2 N".

According to Colomb's Law, every charge exerts an electrostatic force on the other charge, which is directly proportional to the product of the magnitudes of both the charges and inversely proportional to the square of the distance between them.

\(F=\frac{kq_1q_2}{r^2}\)

where,

In case of +2 C charges:

Therefore,

\(0.1\ N = \frac{(9\ x\ 10^9\ N.m^2/C^2)(2\ C)(2\ C)}{r^2}\\\\r^2=\frac{(9\ x\ 10^9\ N.m^2/C^2)(2\ C)(2\ C)}{0.1\ N}\\\\r^2=3.6\ x\ 10^{11}\ m^2\)

Now, for the second case:

Therefore,

\(F=\frac{(9\ x\ 10^9\ N.m^2/C^2)(2\ C)(4\ C)}{3.6\ x\ 10^{11}\ m^2}\)

F = 0.2 N

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Explanation:

FALSE

The first periodic table of elements Mendeleev created contained 63 elements.

a) The isocost curve equation is G = (20000 - 100C)/500. b) The isocost curve equation is G = (30000 - 100c)/500. c) The isocost curve equation is G = (20000 - 100C)/375. d)  The isocost curve equation is G = (20000 - 120C)/500.

To draw the isocost curve showing the different combinations of gas and coal, we need to use the cost per unit values for coal and gas, as well as the given expenditure (TC) and the changes in expenditure or prices.

Let's denote the quantity of coal as C and the quantity of gas as G. The cost per unit of coal is 100, and the cost per unit of gas is 500.

(a) Initial expenditure (TC) of 20000:

To find the combinations of gas and coal that can be purchased with an initial expenditure of 20000, we can use the following isocost equation

TC = 100C + 500G

We can rearrange the equation to solve for G in terms of C

G = (TC - 100C) / 500

Now we can plot the isocost curve with TC = 20000 using the equation above.

(b) Expenditure (TC) increases by 50%

If the expenditure increases by 50%, the new expenditure (TC_new) becomes 1.5 × TC = 1.5 × 20000 = 30000.

We can use the same isocost equation as before, but with the new expenditure value:

TC_new = 100C + 500G

Rearranging the equation to solve for G

G = (TC_new - 100C) / 500

Now we can plot the isocost curve with TC_new = 30000.

(c) Gas price reduced by 25%:

If the gas price is reduced by 25%, the new cost per unit of gas (Gas_new) becomes 0.75 × 500 = 375.

We can use the original isocost equation, but with the new cost per unit value:

TC = 100C + 375G

Rearranging the equation to solve for G

G = (TC - 100C) / 375

Now we can plot the isocost curve with the reduced gas price.

(d) Coal price rises by 20%

If the coal price rises by 20%, the new cost per unit of coal (Coal_new) becomes 1.2 × 100 = 120.

We can use the original isocost equation, but with the new cost per unit value:

TC = 120C + 500G

Rearranging the equation to solve for G:

G = (TC - 120C) / 500

Now we can plot the isocost curve with the increased coal price.

By plotting these isocost curves on a graph with G on the y-axis and C on the x-axis, we can visualize the different combinations of gas and coal that can be purchased at the given expenditures or price changes.

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Answer:

60m/s

Explanation:

Given parameters:

Acceleration  = 2m/s²

Time  = 30s

Unknown:

Change in velocity  = ?

Solution:

Acceleration is the rate of change of velocity with time.

Mathematically;

         Acceleration  = \(\frac{Change in velocity }{Time }\)

Now,

 Change in velocity  = Acceleration x time

So,

  input the parameters and solve;

 Change in velocity  = 2 x 30  = 60m/s

The formulation of Kepler's laws of planetary motion relied on the data and observations of Tycho Brahe

Kepler's laws of planetary motion are as follows:

Tycho Brahe used a telescope to propose a model in which the planets orbit around the sun but the sun orbits the Earth in elliptical orbits. This provided a clear idea for Kepler about the position of planets.

Therefore, the formulation of Kepler's laws of planetary motion relied on the data and observations of Tycho Brahe

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The frequency of a sound wave affects the way our ears perceive sound:

1) A sound wave is created when an object vibrates and causes the molecules in the surrounding medium (such as air or water) to vibrate.

2) The frequency of a sound wave is the number of times that the object vibrates back and forth per second. This frequency is measured in hertz (Hz).

3) When a sound wave reaches our ears, it causes the eardrum to vibrate.

This vibration is then transmitted to the inner ear, where it is detected by hair cells in the cochlea.

4) The cochlea is a fluid-filled structure in the inner ear that contains hair cells that are sensitive to different frequencies of sound.

5) Hair cells in the cochlea that are closest to the entrance of the ear are most sensitive to high-frequency sounds, while hair cells at the other end of the cochlea are most sensitive to low-frequency sounds.

6) When a sound wave enters the ear, it causes the fluid in the cochlea to vibrate.

This vibration causes the hair cells that are sensitive to that frequency to bend.

7) The bending of the hair cells generates an electrical signal that is transmitted to the brain via the auditory nerve.

8) The brain then interprets the electrical signals from the hair cells as sound.

The frequency of the sound wave determines the pitch of the sound that we hear, with higher frequencies being perceived as high-pitched sounds and lower frequencies being perceived as low-pitched sounds.

In summary, the frequency of a sound wave determines which hair cells in the cochlea are activated, which in turn determines the pitch of the sound that we hear.

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The frequency of the photons emitted by hydrogen atoms when they undergo transitions from n = 5 to n = 3 is in the visible range.

The energy of a photon is given by the equation:
E = hf
where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon.
The energy difference between the n = 5 and n = 3 energy levels in a hydrogen atom is given by the Rydberg equation:
ΔE = RH (1/nf^2 - 1/ni^2)
where RH is the Rydberg constant (1.097 x 10^7 m^-1), nf is the final energy level (3), and ni is the initial energy level (5).
Plugging in the values gives us:
ΔE = (1.097 x 10^7 m^-1)(1/3^2 - 1/5^2) = 1.944 x 10^-18 J
Using the equation E = hf, we can solve for the frequency of the photon:
f = ΔE/h = (1.944 x 10^-18 J)/(6.626 x 10^-34 J*s) = 2.933 x 10^15 Hz

This frequency falls within the visible range of the electromagnetic spectrum (4 x 10^14 Hz to 7.5 x 10^14 Hz), so the correct answer is Visible.

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A) Oil B) Wood C) 0.02J D) 3g E) Gas

Answer:

stainless steel is the material which is non magnetic.

On a particular day the atmospheric pressure is 1. 02*100000. The density of mercury is 13600 kg/m3. Then the value of h indicated by the barometer is 0.7594 m.

On a particular day the atmospheric pressure is 1.02 * 100000. The density of mercury is 13600 kg/m³. We need to calculate the value of h indicated by the barometer.Let's first understand what is barometer. A barometer is an instrument that is used to measure atmospheric pressure, commonly used in weather forecasting and meteorology. There are two types of barometers: mercury and aneroid barometer.

A mercury barometer uses mercury which is placed in a long glass tube, where one end of the tube is closed and filled with the mercury, and the other end is exposed to the atmosphere. Due to the atmospheric pressure, mercury rises in the tube. The height of the mercury column indicates the atmospheric pressure. Let's apply this concept to solve the given question .h = (p / (ρ * g))where p = atmospheric pressure = 1.02 * 10^5 N/m²ρ = density of mercury = 13600 kg/m³g = acceleration due to gravity = 9.8 m/s²h = (1.02 × 10^5) / (13600 × 9.8)≈ 0.7594 m

Therefore, the value of h indicated by the barometer is 0.7594 m.

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Answer:

well a beach ball could be any size at all a bowling ball is usually the same size  the weight difference is inside of them inside the beach ball there's air although in a bowling ball there's cement or rock i don't know what they put inside the ball but anyway the bowling ball a lot higher density o it has more volume so the bowling ball is a lot heavier than just a beach ball

Explanation:

If a metal ball is suspended by a rod , the forces acting on the system are balanced so there is no motion observed in the system and this is because of the upward tension in the rod .

Option 1 says : the tension in the rod

The gravitational pull that is acting downwards direction and the tension in rod that is acting in a anti parallel direction to the gravitational pull . being on the same line of action and in opposite directions , these forces cancels each other out .

Option 2 says : the friction of rod

Friction acts in cases of contact forces like a drag or pull not in cases of non-contact forces like gravity , thus friction can't balance it .

Option 3 says : the electromagnetic force

There are no charges or magnets present in the system so the electromagnetic force is absent in this case Thus they cant balance the gravitational force.

Option 4 says : the strong force around the rod

The strong force around is not on the line of action of the gravitational pull so it cant balance it.

So out of all the forces only the tension present in the rod is able to balance the gravitational force

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Answer:

5000 N/m².

Explanation:

The following data were obtained from the question:

Density (d) = 1000 kg/m³

Acceleration due to gravity (g) = 10 N/kg

Height (h) = 50 cm = 50/100 = 0.5 m

Pressure (P) =.?

Pressure is related to density and height by the following equation:

P = dgh

Where

P is the pressure.

d is the density.

g is the acceleration due to gravity.

h is the height.

With the above formula, we can obtain the pressure at the bottom of the cup as follow:

P = dgh

P = 1000 x 10 x 0.5

P = 5000 N/m²

Therefore, the pressure at bottom of the cup is 5000 N/m².

The pump at the base of the drinking fountain needs to provide a gauge pressure of approximately 12.4 kPa.

The gauge pressure for the pump in the drinking fountain is determined by considering the height to which the water is lifted and the diameter of the supply pipe. The pressure can be calculated using the hydrostatic pressure formula: P = ρgh

where P is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the height of the water column.

In this case, the pump needs to lift the water about 1.1 m (from the base to the nozzle), and the diameter of the supply pipe is given. By substituting these values into the formula and considering the density of water, the gauge pressure required for the pump is approximately 12.4 kPa.

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a) The null and alternative hypotheses can be stated as follows:

H0: The mean body temperature of a healthy adult is 98.6 °F.

H1: The mean body temperature of a healthy adult is not 98.6 °F.

b) The appropriate significance level is given as 0.10, which corresponds to a 10% significance level.

c) To perform the hypothesis test, we can use the t-test since the population standard deviation is unknown. The test statistic can be calculated using the formula:

t = (sample mean - hypothesized mean) / (sample standard deviation / √n)

where the sample mean is 98.24 °F, the hypothesized mean is 98.6 °F, the sample standard deviation is 0.92 °F, and n is the sample size, which is 35 in this case.

Substituting these values into the formula, we get:

t = (98.24 - 98.6) / (0.92 / √35)

t = -0.36 / (0.92 / √35)

t = -0.36 / (0.92 / 5.92)

t ≈ -0.36 / 0.155

t ≈ -2.32 (rounded to two decimal places)

d) The test statistic is approximately -2.32.

e) To calculate the p-value, we need to determine the probability of obtaining a test statistic as extreme as -2.32 (in either tail) assuming the null hypothesis is true. Since we have a two-tailed test, we need to calculate the area under the t-distribution curve beyond -2.32 in the left tail and beyond 2.32 in the right tail.

Looking up the p-value corresponding to -2.32 (or the closest value) in the t-distribution table or using statistical software, we find that the p-value is approximately 0.0257.

Therefore, the p-value is approximately 0.0257 (rounded to four decimal places).

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Answer:

if it's combined forces then it would be 25N if it was an unbalanced force then it would be 15N

Answer:

áp dụng công thức í, mình thấy câu này có rắc rối gì đâu

The missing 4 million tons of matter are converted to energy, according to Einstein's equation \(E=mc^{2}\).

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Answer:

\(m=\frac{1}{3}\)

General Formulas and Concepts:

Pre-Algebra

Algebra I

Explanation:

Step 1: Define

Point (0, -1)

Point (3, 0)

Step 2: Find slope m

One of the effects that occurs to an object as it falls into a black hole is spaghettification, also known as the noodle effect.

As an object falls into a black hole, it experiences extreme tidal forces due to the black hole's immense gravitational pull. These forces cause the object to stretch and elongate in the direction of the black hole, while simultaneously compressing it in other directions, resembling a thin strand of spaghetti.

This stretching and compressing occurs because the gravitational force acting on the side of the object closest to the black hole is much stronger than the force acting on the far side.

As the object continues to fall, the tidal forces become so strong that they eventually tear the object apart. Spaghettification occurs at the event horizon for non-rotating black holes, but can happen outside the event horizon for rotating black holes due to their stronger gravitational effects.

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Answer:

θ = 17.67°

Explanation:

The grating equation can be used here to find the angle. The grating equation is given as follows:

\(m\lambda = dSin\ \theta\)

where,

m = order = 2

d = 3.88 x 10⁻⁶ m

λ = wavelength of light = 589 nm = 5.89 x 10⁻⁷ m

θ = angle = ?

Therefore, using these values in the equation, we get:

\((2)(5.89\ x\ 10^{-7}\ m) = (3.88\ x\ 10^{-6}\ m)Sin\theta \\Sin\theta = \frac{(2)(5.89\ x\ 10^{-7}\ m)}{(3.88\ x\ 10^{-6}\ m)}\\\\\theta = Sin^{-1}(0.3036)\)

θ = 17.67°

Answer:17.67

Explanation:

The frequency and period of the hummingbird's wing flutter are 80 Hz and 0.0125 s respectively.

It can be defined as the number of flutter per second. The period is the time taken to complete a flutter.

Given here,

Hummingbirds can flutter wings 4800 times /minute.

The frequency of the wing flutter,

\(f = \dfrac {4800}{60}\\\\ f = 80 \rm \ Hz \ (times/s)\)

Period of the wing flutter,

\(P = \dfrac 1f\)

Now put the value in the formula,

\(P = \dfrac 1{80}\\\\ P = 0.0125\rm\ s\)

Therefore, the frequency and period of the hummingbird's wing flutter are 80 Hz and 0.0125 s respectively.

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Answer:

A hummingbird can flutter its wings 4,800 times per minute.

What is the frequency of wing flutters per second?

80

flutters/second

What is the period for one wing flutter in seconds? Round your answer to two significant figures.

 0.013  seconds

Explanation:

Answer:

A physical property of matter is electric charge. It is caused by an imbalance in the number of protons and electrons in a material. Whether there are more protons than electrons in a substance, it is positively charged if there are more electrons than protons, it is negatively charged.

Explanation:

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Rod OA rotates counterclockwise with a constant angular velocity of ω (omega).

When a rigid object like rod OA rotates with a constant angular velocity, it means that it maintains a consistent rate of rotation in the counterclockwise direction. The angular velocity, denoted by ω, represents the rate of change of the object's angular displacement per unit of time. It is measured in radians per second (rad/s). In this case, the angular velocity of rod OA remains constant, indicating that it rotates at the same speed without any acceleration or deceleration. This steady rotation allows us to analyze the object's rotational motion and understand various aspects such as its angular position, angular velocity, and angular acceleration.

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When a fragment of bone containing carbon-14 isotopes of the element carbon is discovered during an archaeological dig, and it is estimated to be approximately 23,000 years old, one can calculate the proportion of the carbon-14 isotopes that remains.

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The medium for an ocean wave is the ocean water which involves movement on the water body.

This is defined as a substance or material that carries the wave. In the case of ocean waves, the medium is referred to the ocean water.

The medium is not transferred when a water wave moves on a lake as energy is transported but the water molecules aren't which is why lakes have water present in them.

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Answer:

electric circuit............

which grade

Answer: The answer is B) False

Explanation: There are only three muscle types in the exercise physiology.

Skeletal Muscle

Smooth Muscle

Cardiac Muscle