There are ________ mol of bromide ions in 0.700 L of a 0.400 M solution of AlBr

Answer:

The number of moles of solute present in 4.00 L of an 8.30 M solution​ is 33.2

Explanation:

The Molarity (M) or Molar Concentration is the number of moles of solute per liter of solution; in other words it is the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

\(Molarity=\frac{number of moles of solute}{volume}\)

Molarity is expressed in units (\(\frac{moles}{liter}\))  or M.

In this case:

Replacing:

\(8.30 M=\frac{number of moles of solute}{4 L}\)

Solving:

number of moles of solute= 8.30 M* 4 L= 8.30 \(\frac{moles}{liter}\) * 4 L

number of moles of solute =33.2

The number of moles of solute present in 4.00 L of an 8.30 M solution​ is 33.2

Answer:

33.2 is the answer

Explanation:

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Answer:

Evaporation

Explanation:

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Answer: H3(PO4) + 3 KOH= K3(PO4)+ 3 H2O

Explanation: With these numbers everything is balanced on each side.

The temperature inside the freezer is approximately -164°C.

To solve this problem, we can use the combined gas law equation:

\((P1V1)/T1 = (P2V2)/T2\)

where P is the pressure, V is the volume, and T is the temperature of the gas.

We know that the initial volume of the balloon is 145 mL and the final volume is 35 mL. We also know that the initial temperature is 25°C or 298 K, and we need to find the final temperature.

Assuming the pressure of the gas remains constant, we can rearrange the combined gas law equation to solve for the final temperature:

\(T2 = (P2V2/T1)(P1/V1)\)

Plugging in the values we know, we get:

\(T2 = (1 atm * 35 mL/298 K)(1 atm/145 mL) = 0.0808 atm/mL\)

Multiplying both sides by 298 K and dividing by 0.0808 atm/mL, we get:

T2 = 109.15 K or approximately -164°C

Therefore, the temperature inside the freezer is approximately -164°C.

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Answer:

Answer Below ↓

Explanation:

If the moving sand hits an obstacle, it stops due to the friction created by the contact and its kinetic energy is then transformed into thermal energy, or heat.

Answer:

1 kg = 1000 g

58.6=58,600g

Explanation:

Answer:

Solution given:

1:

1 mole of aluminum =26.98 gram

8 mole =26.98*8=215.84 gram

8.00 moles of aluminum =215.84grams.

2:

1 mole of aluminum chloride =133.34 grams

10.5 moles of aluminum chloride =133.34*10.5=1400.07 grams

10.5 moles of aluminum chloride =1400 grams.

#1

1mol.of Al=27g

8mol of Al=27(8)=216g

#2

Molar mass of AlCl3=133.5g/mol

1 mol of AlCl3=133.5g

10.5mol.of AlCl3=10.5(133.5)=1401.75g

The reason for the fourth measurement is that the solution is  saturated. Option C in the question.

According to the Beer Lambert's law, the absorbance of the solution is found to the proportional to the concentration of the solution. This implies that as the concentration of the solution increases, the absorbance of the solution also increases.

The absorbance is proportional to the concentration, and the pathlength of the cell where the measurement is taken.

We can now see from the table that the absorbance of the solution is largely affected by the concentration of the solution and not really the pathlength.

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Answer:

711.96 mL

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

P1 = 785.0 mmHg

P2 = 847.0 mmHg

V1 = 669.0 mL

V2 = ?

T1 = 17.0 °C = 17 + 273 = 290K

T2 = 60.0 °C = 60 + 273 = 333K

Using P1V1/T1 = P2V2/T2

785 × 669/290 = 847 × V2/333

525165/290 = 847 V2/333

1810.91 = 2.54 V2

V2 = 1810.91 ÷ 2.54

V2 = 711.96 mL

C2H4 is the molecular formula. When we multiply the empirical formula by the empirical mass ratio, we get the molecular formula.

Atoms from various elements are chemically mixed in a predetermined ratio to form a compound. A pure chemical compound known as an element is composed of only one type of atom. Composition. Different elements are found in compounds in fixed ratios organized in predetermined ways by chemical bonds.

A single sort of atom makes up the pure substances known as elements. Compounds are compounds made of multiple distinct kinds of elements combined chemically in predetermined ratios.

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Answer:

only molecules with polar bonds may have a permanent dipole moment.

Explanation:

Answer:

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How does work related to kinetic energy?

How are mass and velocity related in kinetic energy?

Explanation:

Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

Answer:

The second option

Explanation:

Answer:

A

Explanation:

common sense

Answer:

are you good at sailing A.

Answer:

Explanation:

Combined Gas Law

T2= T1P2V2/ (P1V1) = 348.15 X .5 X 3.4/(2 X 7.5) =39.46 K or -233.69C

The products of the alpha decay of radium-226 and the beta decay of carbon-14 are radon-222 and nitrogen-14, respectively.

The alpha decay of radium-226 results in the emission of an alpha particle, which is a helium nucleus consisting of two protons and two neutrons.

Therefore, the product of the alpha decay of radium-226 is radon-222:

Ra-226 → Rn-222 + alpha particle

On the other hand, In the case of carbon-14, beta minus decay occurs, in which a neutron is converted into a proton, and an electron and an antineutrino are emitted.

So carbon-14 becomes nitrogen-14:

C-14 → N-14 + beta particle

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--The complete Question is, What is the product of the alpha decay of radium-226 and the beta decay of carbon-14?--

Answer: In the Western United States and Canada, open range is rangeland where cattle roam freely regardless of land ownership. ... Land in open range that is designated as part of a "herd district" reverses liabilities, requiring an animal's owner to fence it in or otherwise keep it on the person's own property.

Explanation: Mark me as brainliest

Answer:

The two elements that most commonly fail to complete an octet are boron and aluminum; they both readily form compounds in which they have six valence electrons, rather than the usual eight predicted by the octet rule.

I think it will help you.

The difference between the products point on the reaction profile and the energy of the reactants is the reaction's activation energy. The change is negative

The energy change between the reactants and the products can be seen in a potential energy diagram or reaction profile.

When we examine the reaction profile, we see that the energy difference between the reactants and products indicates that the process is endothermic. Enthalpy is calculated by deducting the energy of the reactants from the energy of the products.

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The molar mass (formula weight) of carbon dioxide (CO2) is 44.01 g/mol.

At STP (Standard Temperature and Pressure), which is defined as 0°C (273.15 K) and 1 atm of pressure, 1 mole of any gas occupies 22.4 L of volume.

Now, we have 3.9 x 10^23 molecules of CO2:

- To find the number of moles, we divide the number of molecules by Avogadro's number:

n = N/Na = 3.9 x 10^23/6.022 x 10^23 = 0.648 moles

- To find the mass, we multiply the number of moles by the molar mass:

mass = n x M = 0.648 mol x 44.01 g/mol = 28.52 grams

Therefore, the mass of 3.9 x 10^23 molecules of carbon dioxide gas at STP is approximately 28.6 grams (option A).

Molality of C2H5OH is 1.1.27m.



What is Molality?

Molality is no.of moles present in One Kg solution .

Molality is represented by m

m= no.of moles/ weigt of solution in kg

Given is Molarity= 51.30M

molar mass of C2H5OH is 46g / mol , Density =0.9349g/ ml

Density=m/V

V = 107 ml

Molarity= no of moles/ Volume

51.5×46×107= x × 1000

weight of C2H5OH = 27.7g

molality = 27.7/1000××46

m= 1.27m

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1750mL

In order to get the required volume, we will use the dilution formula expressed as:

where:

C₁ and C₂ are the initial and final concentration respectively

V₁ and V₂ are the initial and final volume respectively

Given the following parameters:

C₁ = 500mg/L

C₂ = 100mg/L

V₁= 350mL

Required

V₂

Substitute the given parameters into the formula to have:

Hence the amount of water needed is 1750mL

1.25 moles of \(CO_{2}\) are required to react with 2.50 moles of \(NH_{3}\).

What are the moles?

Moles are a unit of measurement used in chemistry to express the amount of a substance. One mole of a substance is equal to its molecular weight expressed in grams. In other words, one mole of a substance contains 6.022 x \(10^{23}\) individual particles (atoms, molecules, or ions). The number of moles of a substance can be calculated by dividing its mass in grams by its molecular weight or by using the ideal gas law PV=nRT, where n is the number of moles.

The balanced chemical equation is:

\(2NH_{3}\)(g) + \(CO_{2}\)(g) → \((NH_{2})_{2}CO\)(aq) + \(H_{2}O\)(l)

From the balanced equation, we can see that 1 mole of \(CO_{2}\) reacts with 2 moles of \(NH_{3}\).

Therefore, to determine the moles of \(CO_{2}\) required to react with 2.50 moles of \(NH_{3}\), we need to use the mole ratio from the balanced equation:

2 \(NH_{3}\) : 1 \(CO_{2}\)

2.50 moles \(NH_{3}\) * (1 mole \(CO_{2}\) / 2 moles \(NH_{3}\)) = 1.25 moles \(CO_{2}\)

Therefore, 1.25 moles of \(CO_{2}\) are required to react with 2.50 moles of \(NH_{3}\).

What is molecular weight ?

Molecular weight, also known as molar mass, is the mass of one mole of a substance. It is expressed in units of grams per mole (g/mol). The molecular weight of a compound is determined by adding up the atomic weights of all the atoms in the molecule.

What is substance?

In chemistry, a substance is a form of matter that has constant chemical composition and characteristic properties. It may be an element or a compound made up of two or more elements chemically combined in a fixed proportion. Examples of substances include pure water, carbon dioxide gas, and sodium chloride (table salt).

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Answer:

Carbon And the number of protons

Here are some questions on Personal Care services on E2020 are:

An infection is the entrance and growth of dangerous microorganisms in the body that harm the host, such as bacteria, viruses, fungus, or parasites.

Infections can be systemic (affecting the entire body) or localized (affecting a particular area of the body), and they can be moderate to severe.

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0.65mol \(Alx_{2} (So_{4} )_{3}\) are produced during the reaction.

How many grams of Al2(SO4)3 are produced during the following reaction?

2 Al + 3 H2SO4 → Al2(SO4)3 + 3 H2

Molar mas:26.98 →341.15g/mol

All take 35g.

Moles of aluminum=35/26.98=1.29mol.

2mole of aluminum will give=1/2*1.29=0.65

Therefore, 0.65mol \(Alx_{2} (So_{4} )_{3}\).

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