The voltage in american household is 120 v. however, because we use a/c power, the voltage is oscillating between two maximums. what is the maximum or peak voltage required to produce an average voltage of 120 v?.

Given 16 kg of a radioactive sample with a certain half-life of 15 years:

To determine how much of the 16 kg radioactive sample is left after 60 years with a half-life of 15 years, we will use the following steps:

1. Calculate the number of half-lives that have passed: 60 years / 15 years per half-life = 4 half-lives
2. Calculate the remaining sample amount using the formula: remaining amount = initial amount * (1/2)^number of half-lives
3. Apply the formula: remaining amount = 16 kg * (1/2)^4 = 16 kg * 1/16 = 1 kg

After 60 years, 1 kg of the radioactive sample is left. The correct answer is D. 1kg.

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Answer: Thanks for the points!

Explanation:  The average amount of energy passing through a unit area per unit of time in a specified direction is called the intensity of the wave. As the amplitude of the sound wave increases, the intensity of the sound increases. Sounds with higher intensities are perceived to be louder.

Answer:

Amplitude

Explanation:

Answer:summer

Explanation:

Answer:

first day of summer

Explanation:

The momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of hockey player 1= 91.0-kg

(m₂) is the mass of hockey player 2=  91.0-kg

(u₁) is the velocity before collision of hockey player 1 = 5.50 m/s.

(u₂) is the velocity before the collision of hockey player 2=?

a)

Momentum before the collision;

\(\rm m_1u_1 + m_2u_2 \\\\ 91.0 \times 5.50 + 91.0 \times 8.1 \\\\ 1237.6 kg m/s^2\)

Momentum before the collision = 1237.6 kg m/s².

b)

The velocity of the two hockey players after the collision from the law of conservation of the momentum as:

Momentum before collision = Momentum after the collision

1237.6 kg m/s² = (m₁+m₂)V

1237.6 kg m/s² =(2 ×91.0-kg )V

V=6.8 m/sec.

Hence, momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

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Answer:

There is a 0% chance the daughter will have the disease (unless the husband is a carrier). There is a 50% chance she will be a carrier (assuming the husband is not a carrier).

Hope this helps :)

Explanation:

The magnitude of the radial force on the mass can be calculated using the formula:

Fr = mrω²

Where Fr is the magnitude of the radial force, m is the mass, r is the radius of the circular path, and ω is the angular speed.

In this case, we know that the mass is 4.00 kg and the angular speed is 5.00 rad/sec. To find the radius of the circular path, we can use the formula for linear speed:

v = ωr

Where v is the linear speed and r is the radius.

We know that the linear speed is 5.00 m/sec and the angular speed is 5.00 rad/sec, so we can plug these values in and solve for r:

5.00 m/sec = 5.00 rad/sec x r

r = 1.00 m

Now we can plug in the values for m, ω, and r into the formula for the magnitude of the radial force:

Fr = (4.00 kg) x (5.00 rad/sec)² x (1.00 m)

Fr = 100 N

Therefore, the magnitude of the radial force on the mass is 100 N.

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Answer:

Workdone is 5734.06Nm.

Explanation:

Given the following data;

Force applied = 125N

Angle = 35°

Distance = 56m

To find the workdone by the lawnmower, we would first of all find the horizontal component of the force applied.

\( Horizontal force, Fx = mgCosd\)

Where;

mg = weight = 125N

Substituting into the equation, we have;

\( Fx = 125 * Cos35\)

\( Fx = 125 * 0.8192\)

Fx = 102.39N

Workdone is given by the formula;

\( Workdone = force * distance\)

\( Workdone = 102.39 * 56\)

Workdone = 5734.06Nm

Therefore, the work done by the lawnmower is 5734.06Nm.

Answer:

acceleration = final velocity - initial velocity / time

V-U/T

Explanation:

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.

To plot the root loci, we determine the poles, the number of branches, the angles of departure and arrival, and the breakaway and break-in points. These parameters help us sketch the loci on the complex plane.

To plot the root loci of the given transfer function KG(S) = K s(s2+10s+29) with unity feedback, follow these steps:

Determine the open-loop transfer function: G(S) = KG(S) = K s(s2+10s+29).

Find the poles of the open-loop transfer function: Set the denominator equal to zero and solve for the values of s that make the denominator equal to zero. In this case, the poles are at s = 0, s = -5 + j2, and s = -5 - j2.

Determine the number of branches or asymptotes: The number of branches or asymptotes is equal to the number of poles minus the number of zeros. In this case, there are no zeros, so there will be three branches or asymptotes.

Determine the angles of departure and arrival: The angles of departure and arrival are the angles of the poles and zeros with respect to the complex plane. The angles of departure are given by φd = (2k+1)π/n, where k is an integer from 0 to n-1 and n is the number of branches. The angles of arrival are given by φa = φd + π.

Determine the breakaway and break-in points: The breakaway and break-in points are the locations where the root loci start or end. They can be found by setting the derivative of the characteristic equation equal to zero and solving for s.

Plot the root loci: Use the angles of departure and arrival, as well as the breakaway and break-in points, to plot the root loci on the complex plane.

The root locus is a graphical representation of how the poles of a system vary with changes in the gain K. It helps in analyzing the stability and transient response of a control system. By plotting the root loci, we can observe the movement of the poles as the gain K is varied.

In this case, the given transfer function KG(S) = K s(s2+10s+29) has a second-order polynomial in the denominator, resulting in a third-order system. The root loci will consist of curves in the complex plane.

To plot the root loci, we determine the poles, the number of branches, the angles of departure and arrival, and the breakaway and break-in points. These parameters help us sketch the loci on the complex plane.

It's important to note that the specific values of poles, branches, angles, and break points will depend on the transfer function provided in the problem. The step-by-step process outlined above should be followed to accurately plot the root loci for the given transfer function.

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The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.

Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.

Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:

∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du

The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.

Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.

Let us work through the steps:

Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x

Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du

Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.

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Answer:

X = A sin ω t      is the simplest equation for SH

V = ω A cos ω t   describes the velocity where    ω A is the maximum speed

cos ω t = 1/2       describes 1/2 the maximum speed

then ω t = 60 deg      (cos 60 = 1/2)

X = A sin 60   will then be the displacement at 1/2 the maximum speed

or X = .866 A = 3^1/2 / 2 A

At 0.866 displacement from the point of equilibrium, the speed of the SHO is half the maximum value.

Equilibrium is the state of such a system in which neither its internal heat state nor its state or motion tend to change over time. If a simple mechanical body experiences neither accelerometers nor angular acceleration, it is considered to be in equilibrium.

That state will last as long as it is not disturbed by an external factor. Equilibrium for a single particle occurs when the vector sum of the forces acting on the particle is zero.

X = A sin ω t    

V = ω A cos ω t, it describes the velocity.

Here,

ω A = maximum speed

cos ω t = 1/2      

then ω t = 60 deg      

∵ cos 60 = 1/2

X = A sin 60, then the displacement will be at half the maximum speed.

X = 0.866 A

= \(3^{1/2}\) / 2 A

= 0.866

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5 mins

Explanation:

because speed ÷ to distance since the distance is 5 miles the answer is 5mins if not it's 0.2 if the teacher incorrect it

Answer:

48.96V

Explanation:

Given parameters:

Resistance  = 68Ω

Current  = 0.72A

Unknown:

Voltage  = ?

Solution:

According to ohm's law;

           V = IR

V is the voltage

I is the current

R is the resistance

  Now insert the parameters and solve;

      V  = 68 x 0.72 = 48.96V

Initial position ( 4, 4 )

Add the displacements

d1 ( 2 , - 3 ) = ( 4 + 2 , 4 - 3 ) = ( 6 , 1 )

d2 ( -5,0 ) = ( 6 - 5, 1 + 0 ) = (1,1 )

d3 (1, 6 ) = ( 1 + 1 , 1 + 6 ) = ( 2 , 7 )

Final position (2, 7 )

Graph:

Answer:

B

Explanation:

There are a pair of forces acting on the 2 interacting objects

You're welcome <3

Answer:

Given,

initial velocity (u) = 2m/s

Mass (m) = 60kg

work (w) = 150j

final velocity (v) = ?

first of all, we have to find it's force

we know that,

w = f.d

or, f = w/d

or, f = 150j/2m

◇ f = 75N

Again, we have to find a

we know that,

f = m.a

or, a = f/m

or, a = 75N/60kg

◇ a = 1.25m/s^2

Now,

v = u+a.t

or, v = 2+ 1.25×1

◇ v = 3.25m/s

Answer:

Different ions of an element

Explanation:

From the options given, it is only the different ions of an element that can have different electrons.

This is because ions carry charge which could be positive or negative due to a deficit or excess of electrons.

A cation would be formed if there is a deficit of electrons and the atom becomes positively charged, and an anion would be formed if there is an excess of electrons and the atom becomes negatively charged.

For different ions of the same element, the electron number would vary and this would thus lead to each different ion carrying a greater or lesser charge than the other ions of the same element.

Different numbers of electrons occurs in different ions of an element.

Different isotopes of an element have the same number of number of protons and electrons but different number of neutrons.

Different ions of an element have different number of electrons.

For cations, such as;

Thus, we can conclude that different numbers of electrons occurs in different ions of an element.

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Answer:

Force = 80 kN

Explanation:

Given:

m = 1000 кг

S = 250 m

t = 2,5 с

__________

F -?

S = a·t² / 2     ⇒      a = 2·S / t²

F =m·a = 2·m·S / t²

F = 2·1000·250 / 2,5² = 80 000 N

This statement is partially correct. It takes less and less time to fuse heavier elements up to iron inside a high-mass star, but beyond iron, fusion requires energy instead of releasing energy and is not sustainable.

It takes less and less time to fuse heavier and heavier elements inside a high mass star. Iron is the most stably bonded atomic nucleus. When a stellar iron core collapses, large numbers of neutrinos are formed, and then: they immediately pass through the core and escape to space.

Higher mass stars will switch from helium to carbon burning and extend their lifetimes. Even higher mass stars will burn neon after carbon is used up. However, once iron is reached, fusion is halted since iron is so tightly bound that no energy can be extracted by fusion

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A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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The formula for calculating density is expressed as

Density = mass/volume

From the information given,

mass of empty pycnometer = 10.2

mass of the same pycnometer with an unknown liquid is 21.8.

Mass of unkown liquid = 21.8 - 10.2 = 11.6

volume of unknown liquid = 7

Thus,

Density = 11.6/7

Density = 1.7 g/ml

The magnitude of the charge on each plate is 3.56 × 10⁻⁶ C. Given,mass of the plastic ball, m = 6.79 × 10⁻³ kgCharge on the ball, q = +0.196 μC = +0.196 × 10⁻⁶ C

Equilibrium angle made by the thread with respect to vertical, θ = 30.0°Area of each plate, A = 0.01348 m²The electrostatic force acting on the ball is given as:F = qEwhere E is the electric field strength inside the capacitor.The electric field E inside a parallel plate capacitor is given as:E = σ/εwhere σ is the surface charge density and ε is the permittivity of the medium.The net force acting on the ball is given as:F = Tsinθwhere T is the tension in the thread.In equilibrium,F = Tsinθ = qEwhere Tcosθ = mg (gravitational force)Charge on each plateq = σATaking electric field and surface charge density equations,σ = εEσ = q/Aε = σ/Eε = q/EA = εEThus,σ = q/ECharge on each plate,q = σA = qEAE = σ/ε = q/(εA)Substituting values,3.56 × 10⁻⁶ C is the magnitude of the charge on each plate.

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Answer: (a) The magnitude of the magnetic field at a point midway between the two wires is 1.20 × 10⁻⁵ T and the direction of the magnetic field is out of the page.

(b) The magnitude of the magnetic field at a point that is 2.00 m below the point of part (a) is 2.93 × 10⁻⁷ T and the direction of the magnetic field is out of the page.

(a) The magnitude of the magnetic field at a point midway between the two wires is 1.20 × 10⁻⁵ T and the direction of the magnetic field is out of the page.  Between two parallel current-carrying wires, the magnetic field has a direction that is perpendicular to both the direction of current flow and the direction that connects the two wires.

According to the right-hand rule, we can figure out the direction of the magnetic field. The right-hand rule says that if you point your thumb in the direction of the current and curl your fingers, your fingers point in the direction of the magnetic field. As a result, the northern wire's magnetic field is directed up, while the southern wire's magnetic field is directed down. Since the two magnetic fields have the same magnitude, they cancel each other out in the horizontal direction.

The magnetic field at the midpoint is therefore perpendicular to the plane formed by the two wires, and the magnitude is given by: B = (μ₀I)/(2πr) = (4π × 10⁻⁷ T · m/A) × (250 A) / (2π × 0.600 m) = 1.20 × 10⁻⁵ T.

The magnetic field is out of the page because the two magnetic fields are in opposite directions and cancel out in the horizontal direction.

(b) The magnitude of the magnetic field at a point that is 2.00 m below the point of part (a) is 2.93 × 10⁻⁷ T and the direction of the magnetic field is out of the page.

The magnetic field at a point that is 2.00 m below the midpoint is required. The magnetic field is inversely proportional to the square of the distance from the wires.

Therefore, the magnetic field at this point is given by: B = (μ₀I)/(2πr) = (4π × 10⁻⁷ T · m/A) × (250 A) / (2π × √(1.20² + 2²) m) = 2.93 × 10⁻⁷ T. The magnetic field at this point is out of the page since the wires are so far apart that they can be treated as two separate current sources. The field has the same magnitude as the field created by a single wire carrying a current of 250 A and located 1.20 m away.

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a) The angular velocity of the wheel is (2π/60) rad/s.

b) The angle is 60 degrees in 10 seconds.

Given data:

(a) To find the angular velocity in radians per second, we need to convert the given rate from revolutions per minute (rev/min) to radians per second (rad/s).

We know that 1 revolution is equal to 2π radians. Therefore, the conversion factor is 2π rad/rev.

Angular velocity (ω) is given by:

ω = (2π rev/min) * (1 min/60 s)

Simplifying, we have:

ω = (2π/60) rad/s

The angular velocity of the wheel is (2π/60) rad/s.

(b)

To find the angle turned by the wheel in 10 seconds, we can use the formula:

θ = ω * t

where θ is the angle in radians, ω is the angular velocity in radians per second, and t is the time in seconds.

Substituting the values:

θ = (2π/60) rad/s * 10 s

Simplifying, we have:

θ = (2π/6) rad

To convert the angle to degrees, we know that 2π radians is equal to 360 degrees. Therefore, the conversion factor is 360 degrees / (2π radians).

Converting the angle to degrees:

θ = (2π/6) rad * (360 degrees / (2π radians))

Simplifying, we have:

θ = 60 degrees

Hence, the wheel turns through an angle of (2π/6) rad or 60 degrees in 10 seconds.

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When a 9.0 V battery is connected to a bulb and 0.1 A of current flows through it, the resistance of the bulb is 90 ohms.

When a 9.0 V battery is connected to a bulb and 0.1 A of current flows through the bulb, we can calculate the resistance of the bulb using Ohm's Law. Ohm's Law states that the current flowing through a conductor is directly proportional to the voltage applied across it and inversely proportional to its resistance.

To find the resistance, we can rearrange Ohm's Law equation (V = IR) to solve for R, where V is the voltage, I is the current, and R is the resistance.

First, let's plug in the given values:

V = 9.0 V (voltage)
I = 0.1 A (current)

Now, we can rearrange the equation to solve for R:

R = V / I

Substituting the given values:

R = 9.0 V / 0.1 A

Dividing 9.0 V by 0.1 A, we get:

R = 90 ohms

Therefore, the resistance of the bulb is 90 ohms.

In summary, when a 9.0 V battery is connected to a bulb and 0.1 A of current flows through it, the resistance of the bulb is 90 ohms.

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After considering the given data we come to the conclusion that the density of the mixture is 321 kg/m³ in SI units, under the condition that 400cm³ of alcohol of density 800kg/m³ is mixed with 600cm³ of water.

To evaluate the density of the mixture, we can apply the formula
Density = (alcohol mass + mass of water) / (volume of alcohol + volume of water)
It is known to us  that 400cm³ of alcohol of density 800kg/m³ is mixed with 600cm³ of water of density 1g/m³, we can evaluate the mass of alcohol and water as follows
Mass of alcohol = Volume of alcohol × Density of alcohol = 400cm³ × 800kg/m³ = 320000g
Mass of water = Volume of water × Density of water = 600cm³ × 1g/m³ = 600g
Total mass = Mass of alcohol + Mass of water = 320000g + 600g = 320600g
Total volume = Volume of alcohol + Volume of water = 400cm³ + 600cm³ = 1000cm³
Density = Total mass / Total volume
Density = 320600g / (1000cm³ × (1/1000) kg/cm³)
Density ≈ 321 kg/m³ in SI units.
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Rochelle is a chemist who mainly studies thermodynamics, so she is likely to research: b. the temperature required to melt a certain metal, c. the amount of heat produced by a certain reaction and d. how a new engine transforms thermal energy into work.

Thermal energy is a form of energy that results from the movement of particles in matter. It is the energy that is associated with the temperature of a substance and is proportional to the amount of heat it contains.

Thermal energy is a form of internal energy and is often used to describe the energy stored in a system due to the random motion of its constituent particles. Thermal energy can be transferred from one object to another through heat conduction, convection, and radiation.

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Answer:

Buoyant force exerted water​ =  0.196 Newton

Explanation:

Given:

Mass of sphere ball = 5 kg

Volume = 2 x 10⁻⁵

Find:

Buoyant force exerted water​

Computation:

Buoyant force exerted water​ = Gravity due to acceleration x volume of object x density of given liquid

Buoyant force exerted water​ = 9.8 x 2 x 10⁻⁵ x 1000

Buoyant force exerted water​ =  0.196 Newton

The correct terms that fills the box are;

(i) The incident ray

(ii) The normal

(iii) The reflected ray

(iv) The angle of incident

(v) The reflected angle

The terms of the ray diagram is illustrated as follows;

(i) This arrow indicates the incident ray, which is known as the incoming ray.

(ii) This arrow indicates the normal, a perpendicular line to the plane of incidence.

(iii) This arrow indicates the reflected ray; the out going arrow.

(iv) This the angle of incident or incident angle.

(v) This is the reflected angle or angle of reflection.

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