The value of Kp for the reaction,
2SO2(g)+O2(g)⇌2SO3(g) is 5.
What will be the partial pressure of O2 at equilibrium when equal moles of SO2 and SO2 are present at equilibrium?
0.5
0.3
0.2
0.1
Answers
0.2.
Explanation:
To determine the partial pressure of \(O_{2}\) at equilibrium when equal moles of \(SO_{2}\) and \(SO_{3}\) are present, we can use the expression for Kp:
Kp = [\(SO_{3}\)^2 / ([\(SO_{2}\)]^2 * [\(O_{2}\)])
Given that Kp = 5 and equal moles of \(SO_{2}\) and \(SO_{3}\) are present at equilibrium, let's denote their partial pressures as P_SO2 and P_SO3. Since stoichiometry is 2:1, we can denote the partial pressure of \(O_{2}\) as P_\(O_{2}\). Now, we can substitute the values in the Kp expression:
5 = (P_\(SO_{3}\))^2 / ((P_\(SO_{2}\))^2 * P_\(O_{2}\))
Since P_SO2 = P_SO3, we can simplify the equation as:
5 = P_\(SO_{2}\)^2 / (P_\(SO_{2}\)^2 * P_\(O_{2}\))
Dividing both sides by P_\(SO_{2}\)^2, we get:
5 = 1 / P_\(O_{2}\)
Now, we can solve for P_\(O_{2}\):
P_\(O_{2}\) = 1 / 5 = 0.2
So, the partial pressure of \(O_{2}\) at equilibrium when equal moles of \(SO_{2}\) and \(SO_{3}\) are present is 0.2.
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Related Questions
An ideal gas fills a balloon at a temperature of 227ºC and standard pressure. By what factor will the volume of the balloon change if the gas in the balloon is heated to 327ºC at standard pressure? Identify which gas law applies and show your work to receive full credit. Highlight the correct answer below. (2 points)
a. 227/327
b. 5/6
c. 6/5
d. 2/1
e. 327/227
Answers
Answer:
e. 327/227
Explanation:
This is the correct standard pressure.
EXERCISE 3: WHAT DOES pCO2 CHANGE? - When pCO
2
increases, the concentration of total CO
2
dissolved in water - When pCO
2
increases, the concentration of only CO
2
dissolved in water - When pCO
2
increases, the pH - Which form of dissolved CO
2
is most common in water? Ocean acidification is the decrease in pH due to increasing atmospheric CO
2
concentration.
2
. Choose the correct word option in the statements below: - An organism that needs CO
2
is likely to fare better / worse under ocean acidification. - An organism that needs HCO
3
- is likely to fare better/worse under ocean acidification. - An organism that needs CO
3
2−
is likely to fare better/worse under ocean acidification.
Answers
pCO2 is an important factor that affects various aspects of water chemistry and the impacts of ocean acidification. When pCO2 increases, the concentration of total CO2 dissolved in water also increases. This leads to changes in pH, which decreases due to increasing atmospheric CO2 concentration.
When pCO2 rises, the concentration of only CO2 dissolved in water increases. The dissolved CO2 forms carbonic acid, which contributes to the acidification of the ocean. This increase in CO2 affects the equilibrium between CO2, HCO3-, and CO3^2-, shifting it towards higher levels of dissolved CO2 and H+ ions, resulting in a lower pH.
In terms of the impacts of ocean acidification on different organisms, the effects can vary depending on their specific needs. An organism that requires CO2 is likely to fare better under ocean acidification since the increase in dissolved CO2 can provide them with a favorable environment. However, organisms that rely on HCO3- or CO3^2- may fare worse under ocean acidification, as the lower pH interferes with the availability of these carbonate ions, which are essential for shell formation and calcification in some marine organisms.
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Two moles of nitrogen gas are sealed in a 1L fixed-volume cylinder at 25 °C and 1 atmosphere of pressure. If the cylinder is heated to 1000 °C in an incinerator, what is the pressure inside of the cylinder?
Answers
To solve this question we need to use the combined gas law:
\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)sufix 1 reffears to the initial state and sufix 2 reffears to the final state. P is pressure, V volume and T temperature (in Kelvin). They are asking for the pressure at the final state (P2) and they give the initial conditions: P1= 1atm, V1=1L T1=25°C=298K and the final temperature T2=1000°C= 1273 K. They alse say that the Volume is fixed so V2=V1=1L. then we just have to substitute the values into the eqaution:
\(\frac{1atm_{}\times1L}{298K}=\frac{P_2\times1L}{1273K}\)Then solve P2. P2 = 4.272 atm
what is the drag force acting on a car with a resultant force of 600N when the engine is pushing it with a force of 11,000N
Answers
Answer:
10 400 N
Explanation:
A drag force is an oppositional or limiting force which must be overcome before an object must move wit a force. The lesser the drag force, the higher the probability that an object would move easily.
From the question give, the resultant force of the was is 600 N and force from the engine - 11 000 N.
Drag force = 11 000 - 600
= 10 400 N
The drag force on the car is 10 400 N.
This shows that the car would not move since the drag force (10 400 N) is far greater than the resultant force(600 N).
6.
Which best represents a particle containing 28 protons, 26 electrons, and 34 neutrons?
A Fe2-
B
54
2+
28N;
C%2Fe2-
DSNi2+
Answers
Answer:
Ni^2+
Explanation:
The following data were obtained from the question:
Proton = 28
Electron = 26
Neutron = 34
Next, we shall determine the atomic number of the element.
Atomic number of an element is simply defined as the number of protons in the atom of an element.
Thus,
Atomic number = proton number
Proton = 28
Atomic number = proton number = 28
Atomic number = 28
Therefore, the element is Nickel since no two elements have the same atomic number.
Finally, we shall determine the charge on the Nickel atom as follow:
Proton = 28
Electron = 26
Charge on atom =
Charge on atom = Proton – Electron
Charge on atom = 28 – 26
Charge on atom = +2
Therefore, we can represent the Particle as Ni^2+
1. Explain what happens to the train cars when the engine car begins moving to the left. In your response, describe the role played by magnetic force.
Answers
The train cars moves in the same direction when the engine car begins
moving to the left.
What is Law of magnetism?The law of magnetism states that like poles repel and unlike poles attract.
In substances which have magnetic field, they are known to attract each
other.
The engine and train car are highly magnetized which results in them
moving in the same direction when they are in close contact with one
another.
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WHAT ELEMENTS FROM PLACE THEORY AND GEOHERITAGE COULD BE USED IN THE CONSERVATION OF A NATURAL RESOURCE?
Answers
Elements from place theory and geoheritage can be used in the conservation of a natural resource. Place theory emphasizes the cultural and emotional connections between people and places, while geoheritage focuses on the geological and ecological values of an area. Incorporating these elements in conservation efforts can help raise awareness, foster a sense of belonging, and highlight the intrinsic value of the natural resource, leading to better stewardship and preservation.
Place theory recognizes that people develop a connection with specific places due to their cultural significance, history, and personal experiences. By incorporating place-based approaches in the conservation of a natural resource, such as highlighting the cultural and historical importance of the area, it can foster a sense of attachment and pride among local communities. This can lead to increased support and engagement in conservation initiatives.
Geoheritage, on the other hand, focuses on the geological and ecological values of a specific area. Understanding the geological processes, unique landforms, biodiversity, and ecological significance of a natural resource can provide a strong scientific foundation for its conservation. By emphasizing the geoheritage values, such as rare geological formations or endangered species habitats, conservation efforts can be targeted towards preserving these specific features.
By combining elements from place theory and geoheritage, conservation efforts can encompass both the cultural and scientific aspects of a natural resource. This holistic approach not only enhances the understanding and appreciation of the resource but also promotes sustainable management practices for its long-term conservation.
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What is the entropy change when 2.50 moles of CCl₂F₂ vaporizes at 25.0 °C? [∆H(vap) = 17.2 kJ/mol at 25.0 °C]
Answers
The entropy change when 2.50 moles of CCl₂F₂ vaporizes at 25.0 °C is approximately 0.0577 \(\frac{kJ}{(mol·K)}\).
How to calculate the entropy change (∆S) during the vaporization of CCl₂F₂ at a given temperature?To calculate the entropy change (∆S) when 2.50 moles of CCl₂F₂ vaporizes at 25.0 °C, we can use the equation:
∆S = \(\frac{\delta H(vap) }{ T}\)
where:
∆S is the entropy change
∆H(vap) is the enthalpy of vaporization
T is the temperature in Kelvin
First, let's convert the temperature from Celsius to Kelvin:
T = 25.0 °C + 273.15 = 298.15 K
Now we can calculate the entropy change:
∆S = 17.2 kJ/mol / 298.15 K
Since the given enthalpy of vaporization (∆H(vap)) is in kilojoules per mole (kJ/mol), the entropy change will also be in kilojoules per mole per Kelvin (kJ/(mol·K)).
∆S = 0.0577 kJ/(mol·K)
Therefore, the entropy change when 2.50 moles of CCl₂F₂ vaporizes at 25.0 °C is approximately 0.0577 kJ/(mol·K).
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Which of these 0.10 M solutions will have a pH lower than 7.00? I) KCN II) CH3NH21 III) Fe(NO3)3 (Note: CH3NH2I is the iodide salt of the methylammonium CH3NH3tion) 1. only I
2. only 11 3. only III 4. I and III 5. II and III
Answers
The solution that will have a pH lower than 7.00 is the one that is acidic which is option 2 (CH3NH2I).
To determine which of the given solutions is acidic, we need to look at the nature of the ions that will be formed when each compound dissolves in water.
I) KCN - When KCN dissolves in water, it forms the ions K+ and CN-. The CN- ion is the conjugate base of a weak acid (HCN), which means it can hydrolyze in water to produce OH- ions. This makes the solution basic and not acidic. Therefore, option 1 is incorrect.
II) CH3NH2I - This compound is the iodide salt of the weak base CH3NH3+. When it dissolves in water, it forms CH3NH3+ and I- ions. The CH3NH3+ ion is a weak acid and can hydrolyze to produce H+ ions, making the solution acidic. Therefore, option 2 is correct.
III) Fe(NO3)3 - When Fe(NO3)3 dissolves in water, it forms Fe3+ and NO3- ions. Neither of these ions can act as an acid or base, so the solution will not be acidic or basic. Therefore, option 3 is incorrect.
Therefore, the solution that will have a pH lower than 7.00 is only option 2 (CH3NH2I).
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how do i do this? it doesn’t make sense
Answers
Phosphate is any salt or ester of phosphoric acid with the chemical formula PO₄³-
According to this question, a chemical compound with the formula; FePO₄ was given. The iron ion has a 3+ charge and the phosphate ion has a 3- charge.
Charge of an ion can be estimated by finding the difference between the number of protons and electrons in the atom.
Phosphate is an ion with charge of -3, hence, it complements an iron ion with charge +3 to form a neutral compound.
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a) would you expect this compound to have any appreciable solubility in the aqueous layer? explain using a structural argument. (5 pts) b) propose a common organic solvent that would be most suitable for extraction of this compound from water. would it be the top or bottom layer and why? (5 pts)
Answers
The non-polar compound is likely to have limited solubility in the aqueous layer and could be extracted using a non-polar organic solvent like dichloromethane or diethyl ether
a) Based on structural arguments, this compound is likely to have limited solubility in the aqueous layer. The molecule appears to be non-polar, as it has mostly C-H and C-C bonds with very few polar functional groups. In contrast, water is a polar solvent that readily dissolves polar and ionic compounds due to its ability to interact with charged or polar molecules. Therefore, it is unlikely that this non-polar compound would dissolve significantly in the aqueous layer, and it is more likely to partition into an organic solvent.
b) A common organic solvent that would be most suitable for extraction of this compound from water is a non-polar solvent such as dichloromethane (CH2Cl2) or diethyl ether (Et2O). The compound is non-polar and would preferentially dissolve in a non-polar solvent rather than the polar aqueous layer. Therefore, the organic solvent would form the top layer in the separation funnel, and the compound could be extracted into it by shaking the mixture and allowing the layers to separate.
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Iron is extracted from its ore (hematite) in the blast furnace. Which gas is produced as a waste product?
Answers
Answer:
CO2
Explanation:
CO2 or carbon dioxide is produced when iron is extracted from its ore. Carbon monoxide Co is used as reducing agent in iron extraction. In this reaction iron ore is reduced to iron and CO is oxidized to CO2 or carbon dioxide which is released in the process. There extraction of iron is redox reaction.
What are examples of superalloys?
Answers
Examples of such alloys are Hastelloy, Inconel, Waspaloy, Rene alloys, Incoloy, MP98T, TMS alloys, and CMSX single crystal alloys. Superalloy development has relied heavily on both chemical and process innovations.
hope this helps
:))
Answer:
Hastelloy,Inconel,Waspaloy,Rene alloys,and CMSX single crystal alloys.
PLEASE HELP ME ASAPPPPP!!!!!!!!
Answers
Answer: time
Explanation: hi
When ice melts, it becomes liquid.
Which statement correctly compares ice and liquid water?
O A. Both liquid water and ice have definite shapes.
B. Particles of liquid water have more energy than particles of ice.
ОО ОО
C. Liquid water has a lower temperature than ice.
D. Ice has a definite volume, but liquid water does not.
Answers
Given what we know about the energy of particles in each state, we can confirm that the best comparison between water and ice is that particles of liquid water have more energy than particles of ice.
Why do water particles have more energy than ice?This is due to the heat they receive. In order for water to stay in a liquid state, it requires energy in the form of heat. This heat energy excites the particles in the water, causing movement and higher internal kinetic energy.Water becomes ice when it loses this energy and is no longer able to maintain a higher temperature.Therefore, we can confirm that since the heat required to keep water in a liquid state excites the particles and gives them more energy, the correct comparison would be to say that particles of liquid water have more energy than particles of ice, option B is correct.
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Answer:
b.
Explanation:
1. What is Chemistry?
Answers
Answer:
The definition of chemistry is a branch of science that deals with the form of properties of matter and substances or the interaction between individuals.
The following galvanic cell has a potential of 1.214 V at 25∘C:
Hg(l)|Hg2Br2(s)|Br−(0.10M)||MnO4−(0.10M),Mn2+(0.10M),H+(0.10M)|Pt(s)
Calculate the value of Ksp for Hg2Br2 at 25∘C.
Express your answer using one significant figure.
Answers
The value of Ksp for Hg2Br2 at 25∘C is 1.0 × 10^-12.
The given galvanic cell involves the reaction between Hg(l), Hg2Br2(s), Br−(0.10M), MnO4−(0.10M), Mn2+(0.10M), H+(0.10M), and Pt(s). The potential of the cell is given as 1.214 V at 25∘C.
To calculate the value of Ksp for Hg2Br2 at 25∘C, we can use the Nernst equation:
Ecell = E°cell - (0.0592/n) * log(Q)
Where Ecell is the cell potential, E°cell is the standard cell potential, n is the number of electrons transferred, and Q is the reaction quotient.
Since Hg2Br2 is a solid and its concentration does not appear in the reaction quotient, we can assume its activity is 1. Therefore, the reaction quotient simplifies to the concentrations of the other species involved in the cell:
Q = [Br−] / [MnO4−][Mn2+][H+]
By substituting the given concentrations and the calculated cell potential into the Nernst equation, we can solve for E°cell. Then, using the Nernst equation at equilibrium (Q = Ksp), we can solve for Ksp. In this case, the value of Ksp for Hg2Br2 at 25∘C is found to be 1.0 × 10^-12, rounded to one significant figure.
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A 35 L tank of oxygen is at 42°C with an internal pressure of 5000.mmHg. If the temperature changes to 88°C, what would the new pressure be ? the volume is held constant
Answers
Answer:
5730 mmHg.
Explanation:
The following data were obtained from the question:
Initial temperature (T1) = 42 °C.
Initial pressure (P1) = 5000 mmHg.
Final temperature (T2) = 88 °C.
Final pressure (P2) =.?
Next we shall convert celsius temperature,T(°C) to Kelvin temperature, T(K).
This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T1) = 42 °C.
Initial temperature (T1) = 42 °C + 273 = 315 K
Final temperature (T2) = 88 °C.
Final temperature (T2) = 88 °C + 273 = 361 K
Finally, we shall determine the new pressure.
Since the volume of the container is constant, the new pressure can be obtained as follow:
Initial temperature (T1) = 315 K.
Initial pressure (P1) = 5000 mmHg.
Final temperature (T2) = 361 K.
Final pressure (P2) =.?
P1/T1 = P2/T2
5000/315 = P2/361
Cross multiply
315 x P2 = 5000 x 361
Divide both side by 315
P2 = (5000 x 361) / 315
P2 = 5730.1 ≈ 5730 mmHg
Therefore, the new pressure is 5730 mmHg.
Compared to a solution with a ph value of 7, a solution with a thousand times greater hydronium ion concentration has a ph value of.
Answers
Answer:
pH = 4
Explanation:
pH is a base 10 logarithmic scale
1000 = 10^3
7 -3 = pH = 4
It is estimated that the total amount of oxygen (O₂) contained in BIFs is equivalent to 6.6% of the oxygen present in the modern atmosphere. This is quite impressive given that the atmosphere during Archaean and early Proterozoic times was largely devoid of oxygen! Therefore, this reflects the photosynthetic efficiency of the early biosphere, coupled with its operation over long periods of time. Knowing that the mass of the modern atmosphere is 5.01×10¹⁸ kg, of which 21% is oxygen, what is the mass (in kilograms) of oxygen contained within BIFs?
_____ ×10¹⁶ kg of O₂ contained in BIF deposits
Knowing that the molecular mass of O₂ is 32 g/ mole (0.032 kg/ mole ), how many moles of O₂ are contained within BIFs?
____ ×10¹⁸ moles of O₂ contained in BIF deposits
Now, let us think about iron (Fe). The total mass of BIF's globally is estimated at 5.0×10¹⁷ kg, wherein iron accounts for approximately 35% by mass. The atomic mass of iron is 55.8 g/mole(0.0558 kg/mole). What is the total mass of iron in BIFs in kilograms and moles?
_____ ×10¹⁷ kg of Fe contained in BIF deposits
_____ ×10¹⁸ moles of Fe contained in BIF deposits
Finally, take the values you have computed in units of moles, and express them as the molar ratio of iron (Fe) to oxygen (O₂) of BIFs. You can do this by dividing both sides of the ratio by the larger number (Fe in this case).
FeO₂=1 _____
Your calculated ratio above should fall between the Fe: O₂ molar ratios of both Hematite (1:0.75) and Magnetite (1:0.67). Which molar ratio is your calculated value closest to (meaning which iron component, Hematite or Magnetite, is the more dominate in BIFs)?
Answers
The calculated molar ratio of iron to oxygen in BIFs is 1.452.
Comparing this ratio to the molar ratios of Hematite (1:0.75) and Magnetite (1:0.67), we can see that the calculated value of 1.452 is closest to the Hematite molar ratio of 1:0.75. Therefore, Hematite is the more dominant iron component in BIFs.
To calculate the mass of oxygen contained within BIFs, we'll use the given information:
Total mass of the modern atmosphere = 5.01×10¹⁸ kg
Percentage of oxygen in the modern atmosphere = 21%
Mass of oxygen contained within the modern atmosphere = (5.01×10¹⁸ kg) × (0.21) = 1.051×10¹⁸ kg
Percentage of oxygen contained in BIFs = 6.6% (given)
Mass of oxygen contained within BIFs = (6.6% of 1.051×10¹⁸ kg) = 6.6/100 × 1.051×10¹⁸ kg = 6.9166×10¹⁶ kg
Therefore, the mass of oxygen contained within BIFs is 6.9166 × 10¹⁶ kg.
To calculate the number of moles of oxygen contained within BIFs, we'll use the molecular mass of O₂:
Molecular mass of O₂ = 0.032 kg/mole
Number of moles of oxygen contained within BIFs = (Mass of oxygen in BIFs) / (Molecular mass of O₂)
= (6.9166×10¹⁶ kg) / (0.032 kg/mole) = 2.1614375 × 10¹⁸ moles
Therefore, the number of moles of oxygen contained within BIFs is 2.1614375 × 10¹⁸ moles.
Next, let's calculate the mass of iron in BIFs:
Total mass of BIFs = 5.0×10¹⁷ kg
Percentage of iron in BIFs = 35%
Mass of iron contained within BIFs = (35% of 5.0×10¹⁷ kg) = 35/100 × 5.0×10¹⁷ kg = 1.75×10¹⁷ kg
To calculate the number of moles of iron contained within BIFs, we'll use the atomic mass of iron:
Atomic mass of iron = 0.0558 kg/mole
Number of moles of iron contained within BIFs = (Mass of iron in BIFs) / (Atomic mass of iron)
= (1.75×10¹⁷ kg) / (0.0558 kg/mole) = 3.1367419 × 10¹⁸ moles
Therefore, the number of moles of iron contained within BIFs is 3.1367419 × 10¹⁸ moles.
Finally, let's calculate the molar ratio of iron to oxygen in BIFs:
Molar ratio of iron to oxygen = (Number of moles of iron) / (Number of moles of oxygen)
= (3.1367419 × 10¹⁸ moles) / (2.1614375 × 10¹⁸ moles)
≈ 1.452
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A 165 pound man was involved in a car accident at 10 mph. His BAC was measured at the time at 0. 08, impossible. How much beer did he have?
Answers
2
He would have had a BAC of 0.07 on leaving the bar if he had drúnķ only two (2) b33rs.
What is the volume, in liters, of a 0.2 M solution containing 8.5 grams of AgNO3?
Answers
Answer:
0.25L or 250Ml
Explanation:
I am not that good but as far as my calculations this must be the answer
rank the following compounds in order of decreasing boiling point: kcl, co2, ch2o
Answers
The order of decreasing boiling point for these compounds is KCl > CH2O > CO2.
This is because KCl has ionic bonds, which are stronger than the covalent bonds found in CH2O and CO2. Stronger bonds require more energy to break, thus requiring a higher boiling point. Additionally, CH2O has dipole-dipole interactions which add to its boiling point, while CO2 has only weak London dispersion forces.
To rank the following compounds in order of decreasing boiling point: KCl, CO2, and CH2O, you need to consider the types of intermolecular forces present in each compound.
1. Identify the intermolecular forces present in each compound:
- KCl: Ionic bonding (between metal and non-metal)
- CO2: London dispersion forces (non-polar molecule)
- CH2O (formaldehyde): Dipole-dipole forces and London dispersion forces (polar molecule)
2. Compare the strengths of these intermolecular forces:
- Ionic bonding > Dipole-dipole forces > London dispersion forces
3. Rank the compounds based on the strengths of their intermolecular forces:
- KCl (Ionic bonding) > CH2O (Dipole-dipole forces) > CO2 (London dispersion forces)
So, the order of decreasing boiling point is: KCl > CH2O > CO2.
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in the following chemical reaction, which element is the reducing agent? 2 io₃⁻(aq) 12 h⁺(aq) 10 ag(s) 10 cl⁻(aq) → 10 agcl(s) i₂(s) 6h₂o(l) A. I B.Ag C.Ci D.H
Answers
In the given redox reaction, the element which is the reducing agent is silver as it is getting oxidized from zero to +1 by the gain of an electron.
Redox reactions comprise of two parts a reduced part and an oxidized part, which occur simultaneously . The part which is reduced gain electrons and hence there is a increase in oxidation state of the species.
While, the part which is oxidized looses electrons and hence there is a decrease in oxidation state of the species.During redox reactions, there is no net change in the number of electrons . Electrons which are given off in oxidation are used up in reduction.
The ion or molecule which accepts electrons is called as oxidizing agent while the ion or molecule which donates electrons is called as a reducing agent.
In the given equation silver is getting oxidized thus acting as a reducing agent.Thus, option B is correct.
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Bobby shot an arrow at a target 300 meters away, Bobby's longbow shoots
arrows at a speed of 75 m/s. How long did it take until the arrow hit the target?
Your newer
Answers
Answer:
3.5 seconds
Explanation:
because i found the answer
which reaction occurs at the anode of a lead-storage battery while it is in use to start a car
Answers
Answer: Oxidation happens at the anode and reduction happens at the cathode.
At the anode of a lead-storage battery while it is in use to start a car, the following reaction occurs: Pb(s) → Pb²⁺(aq) + 2e⁻.
In a lead-storage battery, the anode is the negative electrode where oxidation takes place during discharge. During the process of starting a car, the battery provides electrical energy to power the starter motor. At the anode, the reaction involves the oxidation of solid lead (Pb) to form lead ions (Pb²⁺) in an aqueous solution and release two electrons (2e⁻). This reaction is represented as:
Pb(s) → Pb²⁺(aq) + 2e⁻
The lead ions formed at the anode combine with sulfate ions (SO₄²⁻) from the electrolyte to form lead sulfate (PbSO₄) as a solid precipitate. This reaction occurs at the positive electrode, known as the cathode.
During the charging process, the reactions at the anode and cathode are reversed, and the lead sulfate is converted back to lead and lead dioxide, respectively, through a series of chemical reactions. This allows the battery to be recharged and ready for the next use.
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You are a NASCAR pit crew member. Your employer is leading the race with 15 laps to go. He just finished a pit stop and has 3.0 gallons of fuel in the tank. On the way out of the pits, he asks, “Am I going to have enough fuel to finish the race or am I going to have to make another pit stop?” You whip out your calculator and begin your calculations based on your knowledge of stoichiometry. Other information you know is:
C5H12 + O2 → CO2 + H2O
The car uses an average of 275.0 grams of O2 for each lap.
The formula for fuel is C5H12
The fuel has a density of 700 g/gal.
What do you tell the driver? Can he finish the race? Will he have fuel left over?
Answers
Answer:
When Darrell is radioed back he would be asked to “Go for it!”
Explanation:
Here we are given the fuel as C₅H₁₂, therefore the combustion reaction is given as
C₅H₁₂ + 8O₂ → 5CO₂ + H₂O
Mass of oxygen consumed on each lap = 300 g
Molar mass of oxygen gas O₂ = 32 g/mol
Number of moles of oxygen n 300 g of O₂ =
(300 g)/(32 g/mol) = 9.375 moles
For complete combustion, one mole of oxygen gas reacts with one mole C₅H₁₂, to form 5 moles of CO₂ and one mole of H₂O
Therefore 9.375 moles of oxygen ill combine with 9.375/8 or 1.172 moles of C₅H₁₂
Mass of 1.172 moles is given as
Mass = Number of moles × Molar mass
= 1.172 moles × 72.15 g/mole = 84.551 g
Therefore the mass of fuel to complete one lap = 84.551 g
However there are 25 gallons or 3.5 kg in the tank therefore we have
Number of laps the fuel in the tank can last = Mass of fuel in the tank/ Mass of fuel consumed per lap
= 3.5/84.551 = 41.395 laps.
Number of laps the fuel in the tank can last = 41.395 laps.
Since there are 20 laps left to complete, which is less than 41.395 laps left in the fuel tank of the vehicle, then Darrell would be asked to go for it.
Are the following chemical equations balanced or
Balanced / Onbalanced
.
CH4 + 4Cl2 → CCL + 2HCL
Balanced / Unbalanced
N2 + 3H2
2NH3
Balanced / Unbalanced
C3H2 + 302 + 3CO2 + 4H2O
+
Answers
Answer:
the first is unbalanced
because the number of hydrogen are not equal on both sides
the second one is balanced
because the number of nitrogen and hydrogen atoms are equal on both sides
and the third one seems to be incomplete
Give an example of a physical change in matter.
Answers
Answer:
Freezing or boiling water
Explain why a fluorescent light bulb is not as hot
as an incandescent light bulb.
Answers
Answer:
Fluorescent tubes do not get as hot as incandescent bulbs because they emit most of their energy as light. This means that they use energy very efficiently. One 18-watt fluorescent tube provides the same amount of light as a 75-watt incandescent bulb, and the fluorescent tube lasts ten times longer.
Explanation:
You can write about anything as long as you include at least one of these things
Particles in plasmas collide more often, but that does not necessarily give them higher temperature. Plasma particles have high kinetic energy (they move quickly). Plasma particles are far apart. The plasma in a fluorescent bulb has a low density.