The age of the universe is estimated to be approximately 13.7 billion years, making option (c) the correct answer. This age is derived from various cosmological observations and measurements.
To estimate the age of the universe:
1. Scientists use various methods, including observations and measurements, to gather data about the universe.
2. One important piece of evidence is the cosmic microwave background radiation, which is a faint glow left over from the early stages of the universe.
3. By studying this radiation, scientists can determine the expansion rate of the universe.
4. Another method involves measuring the ages of the oldest known celestial objects, such as globular clusters or white dwarf stars.
5. By analyzing the chemical composition, temperature, and other characteristics of these objects, scientists can estimate their age.
6. Combining these measurements and observations, scientists have determined that the age of the universe is approximately 13.7 billion years.
7. This value is widely accepted in the scientific community and is considered the best estimate based on current knowledge and understanding of the universe.
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An airplane accelerates at 200 m/s2 for 8 seconds from rest. What is the final velocity?
Answer:
\(\boxed{Final\:velocity\:(v)\:=\:1600m/s}\)
Explanation:
v = u + at
The body accelerates from rest, So initial velocity would be zero.
v = 0 + 200×8
v = 0 + 1600
v = 1600m/s
Hope it helps!<3
The major changes in the state of the universe that occurred immediately after the Big Bang were in ______ and ______.
what is the greatest distance you can be from base camp at the end of the third displacement regardless of direction
To determine the greatest distance you can be from the base camp at the end of the third displacement, regardless of direction, we need more specific information about the magnitudes and directions of the displacements.
Displacement is a vector quantity that has both magnitude and direction. The distance covered during multiple displacements depends on the individual magnitudes and directions of each displacement. Without specific values, it is not possible to determine the exact greatest distance from the base camp.
If you provide the magnitudes and directions of the three displacements, I can help you calculate the total distance and determine the maximum possible distance from the base camp at the end of the third displacement.
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a uniformly charged thin ring has radius 13.5 cm and total charge 21.5 nc . an electron is placed on the ring's axis a distance 27.0 cm from the center of the ring and is constrained to stay on the axis of the ring. the electron is then released from rest. you may want to review (page) . for related problemsolving tips and strategies, you may want to view a video tutor solution of a ring of charge. part a find the speed of the electron when it reaches the center of the ring.
The speed of the electron when it reaches the center of the ring (a uniformly charged thin ring has radius 13.5 cm and total charge 21.5 nc . an electron is placed on the ring's axis a distance 27.0 cm from the center of the ring and is constrained to stay on the axis of the ring. the electron is then released from rest. you may want to review) is 1.73 x 10⁷ m/s.
The electron will be drawn to the center of the ring, where there is no net force. The electron, however, has some kinetic energy and, due to inertia, crosses the center, but on the other side, it is further attracted to the center of the ring.
Potential V₀ = kQ/(r² + z²) \(^{1/2}\)
Potential at center of ring:
V = kQ/r
Where:
r = radius = 13.5 cm = 0.135 m
Q = the charge = 23.0 nC = 2.3 x 10⁻⁸C
z = the distance = 27.0 cm = 0.27 m.
Then by theorem of change of kinetic energy:
mv²/2 = e(V - V₀)
Where:
m = mass of electron
e = charge of electron
Hence,
v = [2e(V - V₀)/m]\(^{1/2}\)
V = (9 x 10⁹) (2.3 x 10⁻⁸)/0.315
= 657.14 V
V₀ = (9 x 10⁹) (2.3 x 10⁻⁸)/(0.315² + 0.27²)\(^{1/2}\)
= 446.38 v
So, the speed of the electron when it reaches the center of the ring:
v = [2 x (1.6 x 10¹⁹) (657.14 - 446.38)/(9.11 x 10³¹}\(^{1/2}\)
= 1.73 x 10⁷ m/s
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How do electric motors work?
A. They convert kinetic energy into electrical energy
B. They convert electrical energy into kinetic energy
C. They convert chemical energy from gasoline into kinetic energy
D. They convert mechanical energy into potential energy
Answer:
Option C
Explanation:
The answer is option C or "they convert chemical energy from gasoline into kinetic energy." Electric motors usually require a power source for example a car, you put gasoline in that car which is converted into kinetic energy which allows the motor to operate and run, (enabling you to drive the car) the kinetic energy is then used into you run out of gasoline.
Hope this helps.
1. E Boiling and condensation At the critical maximum nucleate boiling heat flux, the heating element may experiences a sudden temperature jump. 2. In Film Boiling the presence of a vapor film between the heater surface and the liquid is responsible for the low heat transfer rates in the film boiling region. 3. Condensation releases latent heat, which acts to cool the air. 4. The excess temperature, used in pool boiling problem is equal to Ts-Too. Answer with True or False
The first two statements are true. The last two statements are false.
1. At the critical maximum nucleate boiling heat flux, a sudden temperature jump can occur in a heating element. This phenomenon happens when the heat flux is at its maximum and the liquid near the heating surface transitions to a highly active boiling state. The sudden temperature jump is caused by the intense vapor generation and rapid heat transfer processes occurring at the surface.
2. Film boiling is a stage of boiling where a vapor film forms between the heater surface and the liquid. This vapor film acts as an insulating layer, leading to low heat transfer rates in the film boiling region. The vapor film reduces the contact between the heater surface and the liquid, hindering efficient heat transfer and resulting in lower overall heat transfer rates compared to other boiling regimes.
3. Condensation is the process in which a vapor or gas transforms into a liquid state. When condensation occurs, latent heat is released. However, contrary to the statement, the release of latent heat actually acts to heat the surroundings, not cool the air. This is because latent heat represents the energy released during the phase transition from gas to liquid, and it is transferred to the surrounding environment.
4. In pool boiling problems, the excess temperature is not equal to Ts - Too as stated. Instead, it is calculated as Ts - Tsub. Ts represents the surface temperature, and Tsub represents the saturation temperature of the liquid. The excess temperature is the temperature difference between the surface and the saturation temperature, which is used to characterize the heat transfer performance in pool boiling experiments or analyses.
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An objec with a mass of 7 kg accelerates 5m/s2 when an unknown force is applied to it.what is the magnitude of the unknown force?
Answer:
35 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 7 × 5
We have the final answer as
35 NHope this helps you
A scientist observes a geyser erupting. Which objects must be interacting beneath the surface? Select two options. Well spring magma groundwater unsaturated zone.
Well spring magma and groundwater must be interacting beneath the surface which is why they geyser is erupting.
A scientist observes a geyser erupting. The two objects that must be interacting beneath the surface are well spring magma and groundwater.
When a geyser is erupting, it involves the interaction of groundwater and well spring magma. The groundwater seeps into the earth's crust, where it gets heated by the well spring magma. Once the water reaches a certain temperature, it turns into steam and expands, causing pressure to build up. Eventually, this pressure forces the heated water and steam to the surface, resulting in the eruption of the geyser.
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please help I'm stuck on this question
Answer:
increase
decrease
Explanation:
using formula
Vt=mg/6πηr
so if m increases V increases
r is the denominator so if r increases V decreases
1. A boat initially moving at 10 m/s accelerates at 2 m/s2 for 10 s. What is the velocity of the boat after 10 seconds?
Answer:
5 m/s is the answer so yeah
Pendulum In this task, you’ll make a pendulum and analyze its swing. a hand holding a swinging pendulum shown in three positions Estimated time to complete: 20 minutes You will need these materials: goggles golf ball (or similar size ball) plastic sandwich bag tape hole punch or scissors 1 foot of string metal lid or pan Stay safe! Always wear your safety goggles. Part A Place the ball in the plastic bag, and twist the top so the ball is secure in the bag. Wrap the twisted portion with tape so it stays tight. Use the hole punch or scissors to poke a hole in the part of the bag that’s above the ball. Slip an end of the string through the hole, and tie a knot. This is your pendulum. Hold the loose end of the string still with one hand. With the other hand, raise the ball in an arc so that it’s almost level with the hand holding the string. With the string taut, let the ball go. What do you observe? Font Sizes Characters used: 0 / 15000 Part B Why did the pendulum stop swinging? Where did the energy go? Font Sizes Characters used: 0 / 15000 Part C Scientists have organized all forms of energy into two types—kinetic and potential. Kinetic energy is the energy of motion, and potential energy is stored energy. At the top of its swing, does the pendulum have kinetic or potential energy? Font Sizes Characters used: 0 / 15000 Part D At the bottom of its swing, does the pendulum have kinetic or potential energy? Font Sizes Characters used: 0 / 15000 Part E Think about the process of raising the pendulum to one side and letting it go. For this event, create a list of each form of energy associated with the pendulum as it cycles. Font Sizes Characters used: 0 / 15000 Part F How could you give the pendulum more energy? Font Sizes Characters used: 0 / 15000 Part G Now raise the pendulum and let it hit a metal lid or pan. When the ball strikes the lid, what forms of energy can you identify?
Answer:
A: Place the ball in the plastic bag, and twist the top so the ball is secure in the bag. Wrap the twisted portion with tape so it stays tight. Use the hole punch or scissors to poke a hole in the part of the bag that’s above the ball. Slip an end of the string through the hole, and tie a knot. This is your pendulum. Hold the loose end of the string still with one hand. With the other hand, raise the ball in an arc so that it’s almost level with the hand holding the string. With the string taut, let the ball go. What do you observe?
Mine was swaying perfectly fine. after a little bit it gradually started swinging slower until stopped.
B: Why did the pendulum stop swinging? Where did the energy go?
gravity was pulling it towards the ground, however the weight and momentum of the ball helped it keep swinging for a good while.
C: Scientists have organized all forms of energy into two types—kinetic and potential. Kinetic [THE ENERGY OF MOTION IN A BODY] energy is the energy of motion, and potential energy [THE STORED ENERGY IN AN OBJECT] is stored energy. At the top of its swing, does the pendulum have kinetic or potential energy?
when its at the very top of the swing it does have a very small amount of time until it starts going back down again but during that time it is potential energy
D: At the bottom of its swing, does the pendulum have kinetic or potential energy?
the pendulum still has kinetic energy when it is the closest to the ground since it is still swinging
E: Think about the process of raising the pendulum to one side and letting it go. For this event, create a list of each form of energy associated with the pendulum as it cycles.
when its in my hand: potential energy
when it starts swinging: kinetic energy
when its going upwards: kinetic energy
when it stops swinging: potential energy
F: How could you give the pendulum more energy?
one way you could possibly make it have more energy is if you make the string longer
G: Now raise the pendulum and let it hit a metal lid or pan. When the ball strikes the lid, what forms of energy can you identify?
I could hear sound energy when the two made contact but for the most part it was kinetic energy
Answer:
I could hear sound energy when the two made contact but for the most part it was kinetic energy
Explanation:
blood is tissue .how?
Answer:
Blood is both a tissue and a fluid. It is a tissue because it is a collection of similar specialized cells that serve particular functions. These cells are suspended in a liquid matrix (plasma), which makes the blood a fluid
Equipment such as chafing dishes, steam tables and heated cabinets designed to hold foods hot should at least keep food temperatures at _____ or hotter:
135°F (57°C)
140°F (60°C)
155°F (68°C)
165°F (74°C)
Equipment such as chafing dishes, steam tables and heated cabinets designed to hold foods hot should at least keep food temperatures at 140°F (60°C) or hotter. The correct answer is 140°F (60°C).
Food safety is a crucial aspect of any foodservice operation. Keeping hot correct food temperatures is essential in preventing the growth of harmful bacteria. The temperature range of 140°F (60°C) to 165°F (74°C) is considered the "danger zone" for hot foods, as this range allows bacteria to grow rapidly.
Therefore, equipment such as chafing dishes, steam tables, and heated cabinets designed to hold hot foods should maintain a minimum temperature of 140°F (60°C) or hotter.
This ensures that the food remains safe to eat and reduces the risk of foodborne illness. It is also important to check the temperature of the food regularly using a thermometer to ensure that it is being held at the correct temperature.
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what is angular velocity
Answer -:
rate of charge of angular displacement of a circular motion is called angular velocity it is denoted by omega ( ω ) . if particle trave△θ angluar displacement time then
\( \bold {average \: velocity \: } \: \bold{ \frac{angular \: displacement \: }{time} }\)
or
\( \omega \frac{ \triangle \theta}{ \triangle \: t} \)
if t is very small then instantaneous
\( \omega = \lim \: \frac{ \triangle \theta}{ \triangle \: t \: } \)
When we look at a book in the sunlight, what must happen to the light for our eyes to see the book?
Answer:
Sometimes you can see light from the Sun passing through clouds and the sunbeams appear as straight lines. After light has been reflected off an object, such as a tree or a book, it still travels in straight lines, but in a new direction.
Explanation:
scientists classify everything in the universe as either
Scientists classify everything in the universe as either matter or energy.
Matter refers to anything that has mass and takes up space, such as atoms, molecules, and objects made up of these particles. Energy, on the other hand, refers to the ability to do work or to cause changes in matter. Energy can take various forms, including kinetic energy, potential energy, thermal energy, electromagnetic radiation, and many others.
The distinction between matter and energy is a fundamental concept in physics and has important implications for our understanding of the physical world and the behavior of various systems, from subatomic particles to the entire universe.
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The complete question is :
Fill in the blanks:
Scientists classify everything in the universe as either______
Given that R1 is 13 Ω, R2 is 10 Ω, and R3 is 4 Ω, what is the current coming out of the 9-V battery? What is the power dissipation of each resistor?
what is 0.94kg divided by 2.4n
Answer:
0.39166666666
Explanation:
Write a paragraph comparing one bulb in series, two bulbs in series, and two bulbs in parallel.
What did you learn?
Answer:
Explanation:
The series circuit with two light bulbs will illuminate more than the series with one light bulb because two light bulbs will have more energy as compared to one light bulb.
Una Fuerza F Aplicada a un objeto de masa m1 produce Una Aceleracion De 3.00m/s^2 La Misma Fuerza Aplicada a un segundo objeto de masa m2 Produce una Aceleracion De 1.00m/s^2a) Cual Es El Valor de la relacion m1/m2? B) Si m1 y m2 se combinan en un objeto ¿Cual Es Su Aceleracion Bajo La Accion De La Fuerza F?
Answer:
(a) m1/m2 = 1/3
(b) a = 0.75m/s^2
Explanation:
You have the following relations:
For an object of mass m1:
\(F_1=m_1a_1=m_1(3.00m/s^2)\) (1)
For an object of mass m2:
\(F_2=m_2a_2=m_2(1.00m/s^2)\) (2)
(a) In order to calculate the quotient m1/m2 you use the fact that F1=F2=F.
You divide the equation (1) into the equation (2):
\(\frac{F_1}{F_2}=\frac{F}{F}=1=\frac{m_1(3.00m/s^2)}{m_2(1.00m/s^2)}\\\\1=3.00\frac{m_1}{m_2}\\\\\frac{m_1}{m_2}=\frac{1}{3}\)
The quotient m1/m2 = 1/3
(b) For the case of a mass of m1+m2, you have:
\(F=(m_1+m_2)a\) (3)
To find the values of the acceleration you divide the previous equation into the equation (2):
\(\frac{F}{F}=1=\frac{(m_1+m_2)a}{m_2(1.00)}\\\\1=\frac{m_1}{m_2}a+\frac{m_2}{m_2}a=\frac{1}{3}a+a\\\\1=\frac{4}{3}a\\\\a=\frac{3}{4}\)
The new acceleratio for an object of mass m1+m2 is 3/4m/s^2 = 0.75m/s^2
What is gravity force
The force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface.
Answer:
Gravity is the force that keeps everything on the ground instead of it floaating around!
Explanation:
Without gravity, you would be floating round in your house dodging floating objects.
Hope this brings you down to earth!
Have an amazing day!
PLEASE RATE AND MARK BRAINLIEST!! :)
a horizontal spring with stiffness 0.5 n/m has a relaxed length of 15 cm. a mass of 20 g is attached and you stretch the spring to a total length of 25 cm. the mass is then released from rest and moves with little friction. what is the speed of the mass at the moment when the spring returns to its relaxed length of 15 cm?
The speed of the mass when the spring returns to its relaxed length of 15 cm is 0.632 m/s.
1. First, we need to find the spring constant (k) and the mass (m). We are given k = 0.5 N/m and m = 20 g (which we need to convert to kg): m = 20/1000 = 0.02 kg.
2. Next, we need to determine the elongation (x) of the spring. We are given the initial length (25 cm) and the relaxed length (15 cm):
x = 25 cm - 15 cm = 10 cm (which we need to convert to meters):
x = 10/100 = 0.1 m.
3. Now, we can calculate the potential energy (PE) stored in the spring when it's stretched: PE = (1/2) * k * x^2 = (1/2) * 0.5 N/m * (0.1 m)^2 = 0.0025 J.
4. When the spring returns to its relaxed length, the potential energy will be converted into kinetic energy (KE): KE = (1/2) * m * v^2.
5. Since PE = KE, we can solve for the velocity (v) of the mass: 0.0025 J = (1/2) * 0.02 kg * v^2.
6. Solve for v: v^2 = (0.0025 J * 2) / 0.02 kg
v^2 = 0.25
v = √0.25 = 0.5 m/s.
The speed of the mass when the spring returns to its relaxed length of 15 cm is 0.632 m/s.
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Liquid X of volume 0.5m3 and density 900kgm-3 was mixed with liquid Y of volume 0.4m3 and density 800kgm-3. What was the density of the mixture?
Answer:
Density of the mixture = 855.56kgm-3
Explanation:
Density = Mass / Volume
Volume of Liquid X = 0.5m³
Density of Liquid X = 900kgm-3
Mass of Liquid X = Density × Volume
= 900kgm-3 × 0.5m³ = 450kg
Volume of Liquid Y = 0.4m³
Density of Liquid Y = 800kgm-3
Mass of Liquid Y = Density × Volume
= 800kgm-3 × 0.4m³= 320kg
As X and Y are mixed, we add their masses and volumes together:
Mass = 770kg
Volume = 0.9m³
Now we can find the density of the mixture:
Density = 770kg / 0.9m³ = 855.56kgm-3 (rounded to the 2nd decimal)
four electrons, a, b, c, and d, are fired into a region that has a uniform magnetic field pointing into the screen. the initial speeds of the electrons are equal, and their velocity vectors are indicated by red arrows in the figure. each electron will follow a trajectory that is bent by the magnetic force. four electrons and a proton entering a region of uniform magnetic field pointing into the screen. electron a enters the region from above and its velocity vector points straight down. electrons b and c enter from the right and their velocity vectors point left. electron d enters from below and its velocity vector points straight up. the proton enters from the left and its velocity vector points right. electron b's entry point is higher than the protons entrypoint, whereas electron c's entry point is lower. for which electrons is it possible for the magnetic force to bend the trajectory such that the electron exits the field at the point where the proton enters the field?
The linear velocity is v=0.810 m ×15.0 rad/s = 12.15 m/s.
What is velocity?Velocity is a vector quantity that measured the rate and direction of the change in an object position it is typically excelled in unit of meter per second velocity is equal to the distance traveled divided by the time it take to travel the distance velocity is also related to acceleration which is the rate of change of velocity.
(a) The linear velocity of the disc at the moment of release can be found by using the equation v=rω, where r is the radius of the circular arc, and ω is the angular velocity. Thus, the linear velocity is v=0.810 m ×15.0 rad/s = 12.15 m/s.
(b) The tangential acceleration of the disc at the moment of release can be found by using the equation at = rα, where r is the radius of the circular arc, and α is the angular acceleration. Since the angular acceleration is equal to the change in angular velocity divided by the time, the tangential acceleration is at = 0.810 m ×(15.0 rad/s)/(0.270 s) = \(55.9 m/s^{2}\)
(c) The centripetal acceleration of the disc at the moment of release can be found by using the equation ac = \(v^{2}\)/r, where v is the linear velocity, and r is the radius of the circular arc. Thus, the centripetal acceleration is ac = \((12.15 m/s^{2})\)/(0.810 m) = \(151.0 m/s^{2}\)
(d) The total acceleration of the disc at the moment of release can be found by adding the tangential and centripetal accelerations, thus a tot = at + ac = 55.9 \(m/s^{2}\) + 151.0 \(m/s^{2}\) = 206.9 \(m/s^{2}\)
(e) The angle of the total acceleration at the moment of release can be found by using the equation θ = \(tan^{-1}\)(at/ac), where at is the tangential acceleration, and ac is the centripetal acceleration. Thus, the angle of the total acceleration is θ = \(tan^{-1}\)(55.9 m/\(s^{2}\)/151.0 m/\(s^{2}\)) = 22.4°.
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How would you classify an EM wave with a frequency of 10^7 Hz?
Answer:
I think it is television and radio wave
The quadriceps tendon attaches to the tibia at a 30 degree angle 5 cm from the joint center at the knee. When an 80 N weight is attached to the ankle 28 cm from the knee joint, how much force is required of the quadriceps to maintain the leg in a horizontal position?
the force required of the quadriceps to maintain the leg in a horizontal position is 896 N.
In order to maintain the leg in a horizontal position, the force exerted by the quadriceps must be equal and opposite to the force exerted by the weight on the ankle.
To determine the force required of the quadriceps, we can use the principles of torque and moment arm.
First, we need to calculate the moment arm of the weight. The moment arm is the perpendicular distance between the weight and the joint center.
The moment arm of the weight = 28 cm
Next, we need to calculate the moment arm of the quadriceps. The moment arm of the quadriceps is the perpendicular distance between the line of action of the quadriceps force and the joint center.
We know that the quadriceps tendon attaches to the tibia at a 30 degree angle 5 cm from the joint center. Using trigonometry, we can calculate the moment arm of the quadriceps:
Sin 30 = opposite/hypotenuse
Opposite = Sin 30 x hypotenuse
Opposite = 0.5 x 5
Opposite = 2.5 cm
Therefore, the moment arm of the quadriceps = 2.5 cm
Now we can use the equation for torque:
Torque = force x moment arm
We know that the torque of the weight = torque of the quadriceps (since the leg is in equilibrium).
Torque of the weight = 80 N x 0.28 m = 22.4 Nm
Torque of the quadriceps = force x 0.025 m (converting 2.5 cm to meters)
Setting the torques equal to each other and solving for force:
Force x 0.025 m = 22.4 Nm
Force = 22.4 Nm / 0.025 m
Force = 896 N
Therefore, the force required of the quadriceps to maintain the leg in a horizontal position is 896 N.
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Calculate the force of attraction between a cation with a valence of +2 and an anion with a valence of -2, the centers of which are separated by a distance of 2.5 nm.
Then force of attraction between the cation and anion can be calculated using Coulomb's law: Force = -7.592 x 10^-9 N.
What is the attraction ?The attraction of visiting a new place is the opportunity to explore, discover and learn something new. Visiting a new place often involves immersing oneself in new cultures and customs, experiencing different foods and cuisines, and taking in breathtaking views. By exploring a new place, one can gain a greater understanding of the past and present, and appreciate the diversity of people, cultures, and landscapes. Travelling to a new place also offers the chance to make new friends, learn new skills and create lasting memories. Visiting a new place can be a thrilling, eye-opening experience, and the memories created will last forever.
Then force of attraction betweena the cation and anion can be calculated using Coulomb's law:
Force = k * (Q1 * Q2) / r2
where k is Coulomb's constant (8.99 x 10^9 N*m²/C²), Q1 and Q2 are the charges of the cation and anion (2 and -2 in this case), and r is the distance between the two particles (2.5 nm).
Force = 8.99 x 10^9 N*m²/C² * (2 * -2) / (2.5 x 10^-9 m)²
Force = -7.592 x 10^-9 N
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Then force of attraction between the cation and anion can be calculated using Coulomb's law: Force = \(-7.592 \times 10^{-9} N.\)
What is the attraction ?The attraction of visiting a new place is the opportunity to explore, discover and learn something new. Visiting a new place often involves immersing oneself in new cultures and customs, experiencing different foods and cuisines, and taking in breathtaking views. By exploring a new place, one can gain a greater understanding of the past and present, and appreciate the diversity of people, cultures, and landscapes. Travelling to a new place also offers the chance to make new friends, learn new skills and create lasting memories. Visiting a new place can be a thrilling, eye-opening experience, and the memories created will last forever.
Then force of attraction between a the cation and anion can be calculated using Coulomb's law:
\(Force = k \times (Q1 \times Q2) / r^2\)
where k is Coulomb's constant (\(8.99 \times 10^9 N\times m^2/C^2)\), Q1 and Q2 are the charges of the cation and anion (2 and -2 in this case), and r is the distance between the two particles (2.5 nm).
\(Force = 8.99 \times 10^9 N\times m^2/C^2 \times (2 \times -2) / (2.5 \times 10^{-9} m)^2\\Force = -7.592 x 10^{-9} N\)
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You and your friend are chosen to appear on a TV show where you dress up as sumo wrestlers and battle it out. In your gear, you have a mass of 156 kg, and your friend has a mass of 210 kg. Once the start bell is rung, you both charge at each other and collide near the center of the mat. According to the judges, you have a velocity of 3 m/s, and your friend had a velocity of 1.3 m/s. After the collision, you bounced back at a velocity of 3.8 m/s. What happened to your friend? Find his velocity and direction after the collision. (Assume you were moving in the positive direction before the collision.)
Your friend also bounced back with a velocity of 3.75 m/s.
What is the final velocity of your friend after collision?
The final velocity of your friend after the collision is calculated by applying the principle of conservation of linear momentum.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m is the massesu is the initial velocitiesv₁ is your final velocityv₂ is the final velocity of your friend( 156 x 3 ) + (210)(-1.3) = ( 156)(-3.8) + 210v₂
195 = -592.8 + 210v₂
210v₂ = 787.8
v₂ = 787.8 / 210
v₂ = 3.75 m/s
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A t-shirt cannon is fired into a crowd at a baseball game. The t-shirt with mass 0.17kg is fired, and the launcher (2.7kg) recoils at 1.7 m/s. Calculate the launch velocity of the t-shirt. Answer to 2 decimals
Answer:
Exactly 27 m/s
Explanation:
P=mv
P(cannon)=2.7*1.7
P(cannon)=4.59 kg*m/s
P(cannon)=P(tshirt)
4.59=0.17*v
v=27 m/s
How much thermal energy is absorbed when 145 g of water at 23ºC is heated until it boils and turns into vapour?
Answer:
the thermal energy absorbed is 46,893 J
Explanation:
Given;
mass of the water, m = 145 g = 0.145 kg
initial temperature of the water, t₁ = 23 ⁰C
final temperature of the water, t₂ = 100 ⁰C
specific heat capacity of water, c = 4,200 J/kg.⁰C
The thermal energy absorbed is calculated as;
H = mcΔt
H = 0.145 x 4,200 x (100 - 23)
H = 46,893J
Therefore, the thermal energy absorbed is 46,893J