the total mechanical energy of the system is the same when the ball is at the top and bottom of the vertical circle. use conservation of energy to write an expression for v2t in terms of v2b . your answer may also include m , g , and l .

Answer:

pic

Explanation:

The graph which best shows the velocity v of the quarter from when it is tossed up until it reaches the ground is attached in the answer.

Velocity is the time rate of change of displacement. The displacement and velocity both are vector quantities. They represent magnitude and direction as well.

A quarter is tossed up from the roof of a skyscraper and hits the sidewalk below.

The velocity will decrease with the time linearly.

The graph which best shows the velocity v of the quarter from when it is tossed up until it reaches the ground is attached in the solution.

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Answer:

80%

Explanation:

efficiency = (useful work out / total energy in) x  100

                = \(\frac{80}{100}\)  x 100

                =  80%

That Pacific Plate the Northern American Plate are separated from one another by San Andreas Fault. While a Northern American Plate is migrating the southwest and east, it Pacific Plate moves a north west.

A transform fault, the 1,200-kilometer-long the San Andreas fault zone forms a section of the boundary between both the Pacific or North American plates. It links the Mendocino fissure zone or the Cascade subduction junction to the north with the Pacific Plate Rise inside the Gulf of California.

Southwestern North America is home to the San Andreas Fault, a significant Earth's crustal fissure. From the northern end of a Gulf of California across western California in the United States, the fissure trends northwestward for further than 800 miles (1,300 km), heading out to sea into the Pacific Ocean not far from San Francirsco.

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Answer:

true, there are certain forms of bacteria in water that can cause permanent brain damage (although its rare) so further contamination of water can lead to higher chances of contracting serious illnesses caused by such bacteria.

The magnitude of the charge of the given moveable beads is 9.33 nC.

The tension in the string is calculated as follows;

Tcos45 = mg

where;

F = Tsin45

\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)

\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)

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The moral condition of the world today appears to be worse than it was in the antediluvian era.

The biblical account of the flood records that the world delved into apostasy in the days of Noah so much so that God regretted the fact that he created man. Some of the evils of the antediluvian world include; sodomy, drunkenness, lewdness and several forms of immorality.

We can see that these vices that led to the destruction of the world due to moral bankruptcy in the antediluvian era is still very much prevalent in our world today. The moral condition of the world today appears to be worse than it was in the antediluvian era.

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Answer:

The atomic nucleus is the small, dense region consisting of protons and [[]]s at the center of an atom

Explanation:

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Answer:

10778292789403987593790

Explanation:

I am a Cow'

Answer:I need the answer pls

Explanation:

I don't have one

Answer:

The answer is D, what the cell parts are.

Explanation:

Answer:

Yes, you would consider the mass × gravity at the centre of gravity of the object in question to cause a moment, hence it should be included in your resolution

Volume of rectangular block is 75.4 cm^3

Density of the rectangular block is 8.02 g/cm^3

Volume is simply defined as the space occupied within the boundaries of an object in three-dimensional space.

It is also known as the capacity of the object.

Volume of rectangular block = length× breadth× height

=2.9 cm × 2.6 cm × 10.0 cm

=75.4 cm^3

Density is defined as the substance's mass per unit of volume.

Mathematically ,density is defined as mass divided by volume.

Density of the block = Mass of block / volume of block

=605.0 g / 75.4 cm^3

=8.02 g/cm^3

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The velocity of the combined lump after the collision is 39.5 cm/s, which is the average velocity of the two lumps before the collision.

To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a system before a collision is equal to the total momentum of the system after the collision, provided there are no external horizontal forces acting on the system.

The momentum of an object is equal to its mass multiplied by its velocity. Therefore, we can calculate the total momentum of the system before the collision as:

Total momentum before collision = (0.50 g) × (-20.0 cm/s) + (70.0 g) × 40.0 cm/s

= -10.0 g·cm/s + 2800.0 g·cm/s

= 2790.0 g·cm/s

Since the two lumps stick together after the collision, their masses combine to form a single lump. Let's call the velocity of the combined lump after the collision "v". We can then calculate the total momentum of the system after the collision as:

Total momentum after collision = (0.50 g + 70.0 g) × v

= 70.50 g × v

According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore, we can equate these two expressions and solve for "v":

Total momentum before collision = Total momentum after collision

2790.0 g·cm/s = 70.50 g × v

v = 2790.0 g·cm/s ÷ 70.50 g

v = 39.5 cm/s

This result can be explained by the fact that, in the absence of external horizontal forces, the momentum of the system is conserved, and the total mass of the system remains constant.

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The average acceleration can be written as:

Then, for our case, we can find out the time taken by applying:

Then, the total time taken is equal to 6.5s

The work function of the metal is W₀ = hν₀

The electrons on and near the surface of the metal are expelled when light of continuous intensity and frequency that is greater than the threshold frequency falls on an electrode in a vacuum glass tube. For the sake of simplicity, assume that each photon releases one electron. Now that the light is consistent in intensity, the quantity of photons released and those that collide with the surface will likewise be constant, leading to a constant quantity of electrons released from the metal surface. But because they are at various speeds, the ejected electrons each have a varied amount of kinetic energy.

Therefore, from above we can said, that the minimum energy of an electron from the metal surface is known as work function.

W₀ = hν₀

In above equation, h is plank constant its value is 6.626 × 10⁻³⁴J-s and ν₀

is the frequency of incident radiation.

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The current flowing through the speaker  is 0.045 ampere.

The rate of electron passage in a conductor is known as electric current. The ampere is the electric current's SI unit. Electrons are little particles that are part of a substance's molecular structure.

The potential difference of the speaker = 9 V.

The resistance of the speaker = 200 Ω.

According to Ohm's law,

potential difference  = resistance × current flowing

Hence, the current flowing through the speaker =   potential difference ÷ resistance

= 9 V/200 Ω

= 0.045 Ampere.

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In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. ... In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels.

Answer:

because vibration waves are made by sound

Answer: Here you go, i hope this kinda helps.

Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".

Watson Assistant replies to user's questions based on a confidence score.

Sometimes the customer's question could be interpreted in two or three different ways.

For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:

Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?

Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.

At maximum height, velocity is zero and kinetic energy will be zero.

K.E(A) = 0

P.E(A) = mgh = 200 x 9.8 x 30 = 58,800 J

K.E(B) = P.E(A) - P.E(B)

K.E(B) = 58,800 J - (200 x 9.8 x 25)

K.E(B) = 58,800 J - 49,000 J

K.E(B) = 9,800 J

K.E = ¹/₂mv²

v² = 2K.E/m

v² = (2 x 9800)/(200)

v² = 98

v = √98

v = 9.9 m/s

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The third statement provides the best air-standard assumption.

Air-standard assumptions are a set of assumptions that are used to simplify the analysis of thermodynamic systems involving air. The assumptions are necessary to simplify the analysis of the system because air is made up of many different gases and the temperatures and pressures of the system can vary significantly.

An air-standard assumption is a simplifying assumption used to calculate the thermodynamic cycle of a working fluid. This assumption states that the working fluid is air, and that all processes are reversible and adiabatic, with no changes in air composition. The third statement satisfies all of these criteria, as the exhaust process is isentropic, meaning that no energy is added or subtracted, and the working fluid immediately goes back to the beginning of the cycle to start again.

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Answer:

False

Explanation:

We are given:

Mass of the rocket = 10 kg

Weight of the Rocket = 100 N

Upward thrust applied by the rocket = 400 N

Net upward force on the rocket:

We are given that gravity pulls the rocket with a force of 100 N

Also, the rocket applied a force of 400N against gravity

Net upward force = Upward thrust - Force applied by gravity

Net upward force = 400 - 100

Net upward force = 300 N

Upward Acceleration of the Rocket:

From newton's second law:

F = ma

replacing the variables

300 = 10 * a

a = 30 m/s²

The diagram below that shows a free-body diagram is the third option m

A free-body diagram shows all the forces acting on a single object. In this case, the object is m3. The forces acting on m3 are:

The force F1 exerted by m1. This force is directed to the left. The force F2 exerted by m2. This force is directed to the right.

The force F3 exerted by m3. This force is directed to the left.

The net force on m3 is zero, since the forces F1 and F2 are equal and opposite. This means that m3 is in equilibrium.

Diagram (a) shows the forces F1 and F2, but it does not show the force F3. This is incorrect, since F3 is also acting on m3. In conclusion,the correct option is C.

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The correct answer is (a) The electric field is zero and the electric potential is non-zero at the midpoint between the charges.

What is Electric Potential?

Electric potential, also known as voltage, is a scalar quantity that describes the amount of electric potential energy per unit charge that is present at a given point in space. It is a fundamental concept in electrostatics and is important in understanding the behavior of electric fields and electric charges.

The electric potential at a point in space is defined as the amount of work required per unit charge to move a small positive test charge from infinity to that point. It is measured in volts (V), which is equivalent to joules per coulomb.

At the midpoint between the two equal magnitude but opposite sign charges, the electric field vectors due to each charge are equal in magnitude but opposite in direction. Therefore, the net electric field at the midpoint is zero. However, the electric potential due to each charge is non-zero, and the total electric potential at the midpoint is the sum of the potentials due to each charge. Since the charges have equal magnitude but opposite signs, their potentials cancel each other out and the total electric potential at the midpoint is zero.

Therefore, the correct statement is that theThe correct answer is (a) The electric field is zero and the electric potential is non-zero at the midpoint between the charges.

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Answer:

1. carbon cycle: photosynthesis, respiration, decomposition, and absorption

2. nitrogen cycle: nitrification, denitrification, fixation, assimilation, and ammonification

3. weathering, erosion

Explanation:

i got it right in my lesson

Answer:

1. carbon cycle: photosynthesis, respiration, decomposition, and absorption

2. nitrogen cycle: nitrification, denitrification, fixation, assimilation, and ammonification

3. weathering, erosion

Explanation:

The work done on the box from y=0 to 6.0m is 120 J.

To calculate the work done on the box from y=0 to 6.0m, we need to find the area under the force vs. position graph over that interval.

First, we can find the work done from 0 m to 2 m. Since the force is constant at 40 N over this interval, the work done is simply:

W = F * d = 40 N * 2 m = 80 J

From 2 m to 6 m, the force is constant at -20 N, so the work done is:

W = F * d = (-20) N * 4 m = -80 J

Note that the negative sign indicates that the work is done by the box on the force (since the force is in the opposite direction of the displacement).

Therefore, the total work done on the box from y=0 to 6.0m is:

W_total = 80 J - 80 J = 0 J

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The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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(A) In the given situation, when the foam square and animal fur are rubbed together, the foam square becomes negatively charged, and the fur becomes positively charged. (B) The foam square become charged because electrons were added to it. option(A)

(A) This occurs due to the process of triboelectric charging, also known as contact electrification. The foam square and animal fur are both electrically neutral before they are rubbed together, meaning they have an equal number of protons (#p*) and electrons (#e). However, when the two objects are rubbed, the surface of the foam square and the fur come into contact, causing the transfer of electrons between them.

The final charge distribution can be summarized as follows:

Before: #p* = #e (Equal number of protons and electrons)

After: #p* = #e (Number of protons remains the same)

       #p* > #e (Excess of electrons on the foam square)

       #p* < #e (Deficit of electrons on the fur)  

(B) During the rubbing process, the foam square gains electrons from the fur, resulting in an excess of electrons on the foam square's surface. This accumulation of electrons gives the foam square a negative charge. Conversely, the fur loses electrons, resulting in a deficit of electrons and an overall positive charge on its surface.

The foam square becomes charged negatively because electrons are added to it during the rubbing process. It is important to note that the transfer of charge occurs through the exchange of electrons, not protons. The number of protons in the foam square and fur remains the same before and after the rubbing process, so #p* remains unchanged. option(A)

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