The total cost C dollars, that a shop charges to print T shirts C = 45 + 7n , is the number of shirts ordered. Coach Dell paid 206 fo order T the track team, How Tshirts did Coach Dell order?

Answer:

c. m∠2 = m∠5

Step-by-step explanation:

We can check 1 by 1 and find the false one.

For answer A, measures 2 and 4 are vertical angles, which means they are equal, so that's not false.

For answer b, measures 4 and 8 are corresponding angles, since X and Y are parallel, so that's also not false.

For answer c, measures 2 and 5 are supplementary to each other, and since the transversal is not perpendicular to X nor Y, they are not equal, therefore, this is false, making that the answer.

For answer d, measure 2 and 6 are corresponding angles, so that's also not false.

Therefore, the answer must be c.

Answer:

3/4 x 2/5 => NO

2/5 x 5/6 => NO

1/10 x 1/5 => NO

1/2 x 3/5 => YES

Step-by-step explanation:

3/4 x 2/5 = 6/20 => NO

2/5 x 5/6 = 10/30 => NO

1/10 x 1/5 = 1/50 => NO

1/2 x 3/5 = 3/10 -> YES

The amount left in the can is an illustration of subtraction or differences

There are 2 quarts of water left in the watering can

The given parameters are:

Content = 8 quarts

Used = 6 quarts

To calculate the amount of water left, we use:

Content = Used + Left

Substitute known values

8 = 6+ Left

Subtract 6 from both sides

Left = 2

Hence, there are 2 quarts of water left in the watering can

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There were 357 dogs that were sold that day.

What is least squares regression line?

The line that best matches a linear connection between two variables in data is called a least-squares regression line because it minimizes the vertical distance between the data points and the regression line.

The given equation is,

y = 0.6p + 10.0

The residual for the day when 520 people attended was 35.

So, p = 520.

Plug 520 in the above equation, we get

y = 0.6(520) + 10.0

y = 312 + 10

y = 322

As, people attended was 35

So,

y = 322 + 35

y = 357

Hence, there are 357 dogs are sold that day.

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The takt time for the given system, where the total time per shift is 430 minutes, there is one shift, workers have two 18-minute breaks, and 40 minutes for lunch, and the daily demand is 356 units, is 1.21 minutes per cycle.

Takt time is calculated by dividing the available production time by the customer demand. In this case, the available production time is the total time per shift minus the break and lunch times.

Total time per shift = 430 minutes

Break time = 2 breaks * 18 minutes = 36 minutes

Lunch time = 40 minutes

Available production time = Total time per shift - Break time - Lunch time

= 430 minutes - 36 minutes - 40 minutes

= 354 minutes

To calculate the takt time, we divide the available production time by the daily demand:

Takt time = Available production time / Daily demand

= 354 minutes / 356 units

≈ 0.9944 minutes per unit

Rounding the takt time to 2 decimal places, we get approximately 1.21 minutes per cycle.

Therefore, the takt time for the given system is 1.21 minutes per cycle.

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The integral of sec(y) dy from zero to one-sixth of pi is equal to the natural logarithm of the square root of 3 times 64 raised to a certain power.

To evaluate the integral ∫ sec(y) dy from zero to one-sixth of pi, we can use the trigonometric identity that the integral of sec(y) dy is equal to the natural logarithm of the absolute value of the secant of y plus the tangent of y.

Integrating sec(y) dy gives us ln|sec(y) + tan(y)|. Evaluating the integral from zero to one-sixth of pi, we substitute the upper and lower limits of integration into the expression and subtract the result at the lower limit from the result at the upper limit.

ln|sec(π/6) + tan(π/6)| - ln|sec(0) + tan(0)|

Simplifying this expression, we know that sec(π/6) = √3/2 and tan(π/6) = 1/√3. Additionally, sec(0) = 1 and tan(0) = 0.

ln|√3/2 + 1/√3| - ln|1 + 0|

ln|√3 + 1| - ln|1|

ln|√3 + 1|

Therefore, the integral ∫ sec(y) dy from zero to one-sixth of pi is equal to the natural logarithm of the square root of 3 plus 1, or ln(√3 + 1).

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Answer:

36

because 2x3= 6

6x6 is 36

Therefore, the probability that one of the randomly selected 100 machined parts will be defective is approximately 0.096, which is equivalent to 9.6% (option b).

Given that 10% of the lot is defective, we can assume that the probability of selecting a defective machined part is also 10%.

To find the probability that one of the randomly selected 100 machined parts will be defective, we can use the complement rule. The complement of this event is that none of the 100 machined parts are defective.

The probability of none of the 100 machined parts being defective can be calculated as:

P(None defective) = (1 - Probability of defective)^Number of parts

P(None defective) = (1 - 0.10)^100

P(None defective) ≈ 0.904

Since we are interested in the probability that one of the machined parts will be defective, we can use the complement rule:

P(At least one defective) = 1 - P(None defective)

P(At least one defective) = 1 - 0.904

P(At least one defective) ≈ 0.096

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The value of dy=1.200

To compute δy and dy for \(y = 2x - x^2\)  at x = 2 and δx = -0.6, we can use the following formulas:

δy ≈ f'(x) δx

dy ≈ f'(x) dx

where f'(x) is the derivative of f(x) with respect to x.

First, we can find f'(x) by taking the derivative of y with respect to x:

\(f(x) = 2x - x^2\)

f'(x) = 2 - 2x

Substituting x = 2, we get:

f'(2) = 2 - 2(2) = -2

Using δy ≈ f'(x) δx and substituting x = 2 and δx = -0.6, we have:

δy ≈ f'(2) δx = (-2)(-0.6) = 1.2

Therefore, δy ≈ 1.2.

Using dy ≈ f'(x) dx and substituting x = 2 and dx = δx = -0.6, we have:

dy ≈ f'(2) δx = (-2)(-0.6) = 1.2

Therefore, dy ≈ 1.2.

Rounding to three decimal places, we have:

δy ≈ 1.200 and dy ≈ 1.200

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The probability that the athlete is either a football player or a basketball player is 93%.

What is probability?

Football players= 51%

Basketball players= 43%

Both football and basketball= 1%

Probability = Football players + Basketball players

- Both football and basketball

Probability= 51% + 43% -  1%

Probability= 93%

Inconclusion The probability that the athlete is either a football player or a basketball player is 93%.

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For a chi-square goodness-of-fit test, we can use variables of nominal level and ordinal level.

For a chi-square decency of-fit test, we can utilize the accompanying variable sorts:

Niveau nominal: a variable that has no inherent order or numerical value and is made up of categories or labels. Models incorporate orientation (male/female) or eye tone (blue/brown/green).

Standard level: a category of a natural order or ranking for a variable. Even though the categories are in a relative order, their differences might not be the same. Models incorporate rating scales (e.g., Likert scale: firmly deviate/dissent/impartial/concur/emphatically concur) or instructive accomplishment levels (e.g., secondary school recognition/four year certification/graduate degree).

In this manner, for a chi-square decency of-fit test, we can utilize factors of ostensible level and ordinal level.

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The relationship between x and y is a strong negative relationship.

For this question, we need to determine the correlation coefficient,

Thus,

The correlation coefficient

= (21 - 5*6)/ \(\sqrt{9 * 10}\)

= -0.948

The above answer is too close to -1. Therefore correlation coefficient is a strong negative.

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The direction in which the maximum rate of change occurs for the function f(x, y) = 3xsin(xy) at the point (4, 1) is given by the unit vector u ≈ <-0.0475, 0.9986>, gradient vector, rounded to 4 decimal places.

To find the direction of the maximum rate of change for the function f(x, y) = 3xsin(xy) at the point (4, 1), we first need to find the gradient vector, which is given by the partial derivatives of f with respect to x and y.
Compute the partial derivatives.
∂f/∂x = 3sin(xy) + 3xycos(xy)
∂f/∂y = 3x^2cos(xy)
Evaluate the partial derivatives at the point (4, 1).
∂f/∂x(4, 1) = 3sin(4) + 12cos(4) = -1.7175
∂f/∂y(4, 1) = 3(4^2)cos(4) = 36.1080
Form the gradient vector.
Grad f(x, y) = <-1.7175, 36.1080>
Find the magnitude of the gradient vector.
||Grad f(x, y)|| = √((-1.7175)^2 + (36.1080)^2) = 36.1581
Normalize the gradient vector to find the unit vector.
u = Grad f(x, y) / ||Grad f(x, y)||
u = <-1.7175/36.1581, 36.1080/36.1581>
u ≈ <-0.0475, 0.9986>

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95% confidence that the sample mean for the bio/total carbon ratio of blended fuels will fall within the interval is 0.9390 ± 0.002696, which is (0.9364, 0.9416).

We can use the formula for the margin of error for a 95% confidence interval for the population mean, given by:

the margin of error = 1.96 × standard deviation / √(sample size)

where the standard deviation of the sampling distribution of the sample mean is given by:

standard deviation = population standard deviation / sqrt(sample size)

Substituting the given values, we have:

standard deviation = 0.0080 / √(34) = 0.001375

margin of error = 1.96 × 0.001375 = 0.002696

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The question is -

Concerns about climate change and CO2 reduction have initiated the commercial production of blends of biodiesel (e.g., from renewable sources) and petrodiesel (from fossil fuel). Random samples of 34 blended fuels are tested in a lab to ascertain the bio/total carbon ratio.

If the true mean is .9390 with a standard deviation of .0080, within what interval will 95 percent of the sample mean to fall? (Round your answers to 4 decimal places.)

The total perimeter will be 4x^+17 and length be 22.76 cm

As per the data given in the questions,

We have, the shape of the sandwich be rectangular.

We know that, perimeter of the rectangle can be determined by using formula: 2(l+b),

where, l = length of the rectangle

and, b = breadth of the rectangle

The expression for the perimeter of the sandwich would be:

2 (2x^2 + 9) + 2 (2x^2 + 8)

= 4x^2 + 26

Now for finding the length of the crust,

we will put the value of x=1.2,

So, the value of the approximate length of the crust would be:

=4x^2 + 26

= 4 * 1.2^2 + 26

= 22.76 centimetres.

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Answer:

1

Step-by-step explanation:

-6 + 1 = -5

Answer:

yes it is.....................

Step-by-step explanation:

9.5 = 19/2

So it is a rational number (and so is not irrational)

We need to find the inequality that represents how the $55 I have can be spent in the fair.

The required inequality is \(12+1.75x\leq55\), and the possible number of rides is \(24\).

Admission cost = $12

Cost of each ride = $1.75

Let \(x\) be the number of rides taken.

Total cash = $55

So, the inequality will be \(12+1.75x\leq55\)

Solving the inequality

\(1.75x\leq55-12\\\Rightarrow x\leq\dfrac{55-12}{1.75}\\\Rightarrow x\leq 24.57\)

So, the maximum number of rides taken can be \(24\).

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9 cubed = 729

6 cubed = 216

729 - 216 = 513

To calculate the gain on the sale of the office furniture, we need to determine the asset's book value and compare it to the sale price.

First, let's calculate the accumulated depreciation on the furniture. The furniture was purchased on January 1, 2014, and the straight-line depreciation method is used over 10 years with a salvage value of $80,200.

Depreciation per year = (Cost - Salvage Value) / Useful Life

Depreciation per year = ($746,800 - $80,200) / 10 years

Depreciation per year = $66,160

Next, we need to calculate the accumulated depreciation for the period from January 1, 2014, to May 1, 2021 (the date of the sale). This is approximately 7.33 years.

Accumulated Depreciation = Depreciation per year × Years

Accumulated Depreciation = $66,160 × 7.33 years

Accumulated Depreciation = $484,444.80

Now, we can calculate the book value of the furniture:

Book Value = Cost - Accumulated Depreciation

Book Value = $746,800 - $484,444.80

Book Value = $262,355.20

Finally, we can calculate the gain on the sale:

Gain on Sale = Sale Price - Book Value

Gain on Sale = $300,000 - $262,355.20

Gain on Sale = $37,644.80

Therefore, the gain that should be recognized on the sale of the office furniture is approximately $37,644.80.

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The gain that should be recognized on the sale of the office furniture is $84,080.

The gain is calculated by subtracting the equipment's book value from the sale price. This gain will be reported on the company's income statement. Here is how to calculate the gain:First, find the equipment's book value using the straight-line method of depreciation.

Straight-line depreciation is calculated by taking the difference between the equipment's original cost and its salvage value, and then dividing it by the number of years the equipment is used. The annual depreciation expense is then multiplied by the number of years the equipment is used to find the equipment's book value at the end of its useful life.

For this question, the book value of the equipment at the time of sale is:Cost of equipment: $746,800Salvage value: $80,200Depreciable cost: $746,800 - $80,200 = $666,600Annual depreciation: $666,600 ÷ 10 years = $66,660Book value at the end of 2020: $666,600 - ($66,660 x 7) = $156,420

Next, subtract the equipment's book value from the sale price to find the gain:Sale price: $300,000Book value: $156,420Gain: $143,580Finally, round the gain to the nearest dollar:$143,580 ≈ $143,580.00So the gain that should be recognized on the sale of the office furniture is $84,080.

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Answer:

Hey homie I had trouble with this one too, the answer is 3.67%

Step-by-step explanation:

Basically this is a combination which means your looking for P(2 favorites) which is written as (2C2)(48C8)/(50C10).

This is using factorials so if you don't know those yet I would look it up but it's just simplified as 3.67%

Answer:One is 2 feet and one is 4 feet

Step-by-step explanation:

No, molar mass is a constant and does not depend on pressure or temperature.

Molar mass is a physical property of a substance and is the mass of one mole of a given substance. It is a constant value that represents the amount of grams of a substance that contains 022 x 1023 atoms or molecules. Since molar mass is a constant, it does not depend on pressure or temperature. Pressure and temperature can affect the physical and chemical properties of a substance, but they do not have an effect on the molar mass. The molar mass of a substance can be useful in determining molecular and empirical formulas, as well as calculating densities and molar concentrations.

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Answer:

m [ slope ] = 8/3

Step-by-step explanation:

What is the slope of the line that passes through the points (5, 1) and (2, -7)?

m = ∆y / ∆x

m = y₂ – y₁ / x₂ – x₁

| (5, 1) → (x₁, y₁) | (2, -7) → (x₂, y₂) |

[each coordinate will correspond (directly go to) to the variables shown]

m = (-7) – (1) / (2) – (5)

m = -8 / -3

m = 8 / 3

This means that this line has a rise of 8 and a run of 3.

Up 8 and right 3 proportionally, it would touch the opposite corners of a plane that was 8 by 3 units.

Slope can be thought of as the steepness of a line, the greater the slope, the greater the steepness.

These points are generally known as cartesian coordinates.

____________

Once you have the slope, you can back track from one of the coordinates to find the equation of the line.

Just multiply the slope by the x of either coordinate, make it opposite, and then add that to the y of that coordinate to get b [the y-intercept; where it crosses the y axis, x is always 0]

Since (2, -7) is closer to the y axis than (5, 1) it is more convenient.

In (2, -7), 2 is the x variable and -7 is the y variable.

-mx + y = (-8/3)(2) + (-7) = -16/3 + (-21/3)

21/3 is the same as 7 [so it will have a common denominator].

-16 + -21 / 3 = -37/3 = b

Thus this line has an equation of

y = mx + b

↓ ↓

y = 8/3x – 37/3.

__________________________

Or you can refer to point slope which is what is taught:

y – y₁ = m(x – x₁).

You can tell that there are some similarities to this and the slope formula.

m = ( y₂ – y₁ / x₂ – x₁ ) →

m × ( x₂ – x₁ ) =

( y₂ – y₁ / x₂ – x₁ ) × ( x₂ – x₁ )

[multiply the denominator by both sides]

m ( x₂ – x₁ ) = y₂ – y₁

[x₂, and y₂ can just be x and y since you only need the initial coordinate and slope, because the second coordinate can be anything along that line]

m ( x – x₁ ) = y – y₁ →

y – y₁ = m(x – x₁)

[symmetric property of equality]

if a = b, b = a.

The y-intercept represents the starting profit before tutoring any hours. To find her profit for 9 hours, use the linear equation and plug in 9 for hours.

Part A: The independent variable is the number of hours Elizabeth tutors, and the dependent variable is the profit she makes each month.
Explanation: The profit depends on the number of hours she works.
Part B: To determine the slope of the line, you need to find the change in profit per change in hours (Δprofit/Δhours). The slope represents the rate at which Elizabeth's profit changes as she works more hours.
Explanation: The slope shows the relationship between hours worked and profit earned.
Part C: The y-intercept is the point where the line crosses the y-axis. This represents the profit Elizabeth makes when she works 0 hours.
Explanation: The y-intercept shows her starting profit before she works any hours.
Part D: To find her profit when she tutors for 9 hours, plug in 9 for the independent variable (hours) in the linear equation representing the line and solve for the dependent variable (profit).
Explanation: Using the equation, we can calculate her profit based on the number of hours she works.

Summary: The independent variable is hours tutored, and the dependent variable is the profit. The slope represents the rate of profit change per hour worked. The y-intercept represents the starting profit before tutoring any hours. To find her profit for 9 hours, use the linear equation and plug in 9 for hours.

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Answer:

3h+7/h

Step-by-step explanation:

the parenthesis in g(4+h) is saying that is x. plug in 4+h in the x and evaluate.

so you would get 3(4+h)-5. distribute the 3 and get 12+3h-5. combine like terms to get 3h+7!

then it's just over h because you can't simplify anymore. so the real answer is 3h+7/h!!

Answer: >3 and >7

Step-by-step explanation: