The texts that remain the same in every mass are called the Ordinary. The Ordinary is the unchanging part of the Catholic Mass that is said or sung at every Mass regardless of the liturgical season or day of the week.
There are five parts of the Ordinary: Kyrie eleison, which is Greek for "Lord, have mercy."Gloria, which is Latin for "Glory."Credo, which is Latin for "I believe."Sanctus, which is Latin for "Holy."Agnus Dei, which is Latin for "Lamb of God."The texts of the Ordinary are usually sung or chanted during the Mass, except for the Credo, which is usually recited.
The Ordinary serves to unify Catholics in the celebration of the Mass and emphasizes the unchanging nature of the Catholic faith.
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The Ordinary of the Mass refers to the parts of the service that remain consistent across each mass. This includes the Kyrie, Gloria, Credo, Sanctus, and Agnus Dei.
Explanation:The texts that remain the same in every mass are known as the Ordinary of the Mass. This includes fundamental parts of the service, such as the Kyrie, Gloria, Credo, Sanctus, and Agnus Dei. These elements are standard in Roman Catholic, Anglican, and Lutheran liturgies. Unlike the Propers of the Mass, which are texts that change depending on the liturgical calendar (holidays, saint days, etc.), the Ordinary remains consistent. They are typically standardized and unchanged across different masses to maintain consistency and preserve the tradition of the religious practice.
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The speed of x-rays is A.faster than light B.slower than the speed of gamma rays C.Same as the speed of radio waves D.same as the speed of seismic waves
Electromagnetic waves are those waves that are composed of electric and magnetic fields perpendicular to each other and to the direction of the propagation. All electromagnetic waves have the same speed.
That is, 3×10⁸ m/s.
X-ray is one of the electromagnetic waves. So are light, gamma rays, and radio waves.
Thus the speed of all these waves is equal.
Thus, the correct answer is option C, "Same as speed of radio waves"
which type of which type of orbit is shown in the picture below?
I don't see a picture attached to your question. Without one, I don't think I will be able to determine what type of orbit is displayed.
An iron rod with an initial length of 12.62 m has its temperature raised from 19o C to 30.6o C. If iron has a coefficient of thermal expansion of 12x10-6 1/oC, what is the change in length of the rod in mm?
ANSWER:
1.757 mm
STEP-BY-STEP EXPLANATION:
The coefficient of linear expansion is given by the following formula:
\(\alpha=\frac{\Delta L}{L\Delta T}\)Where α = coefficiente of linear expasion, ΔL = change in lenght, ΔT = change in tempetature
Solving for ΔL:
\(\Delta L=\alpha\cdot L\cdot\Delta T\)Replacing and we calculate the change in lenght:
\(\begin{gathered} \Delta L=12\cdot10^{-6}\cdot12.62\cdot(30.6-19) \\ \Delta L=0.001757\text{ m}\cdot\frac{1000\text{ mm}}{1\text{ m}}=1.757\text{ mm} \end{gathered}\)The change in length is 1.757 mm
Why VR of second class lever is greater than 1?
Second class lever has mechanical advantage always more than one as load is in between fulcrum and effort making the effort arm longer than the load arm. It multiplies force. ... It does not multiply force but changes the direction of force.
The centre of gravity of a homogeneous body is the point at which the wholeA. Volume of the body is assumed to be concentratedB. Area of the surface of the body is assumed to be concentratedC. Weight of the body is assumed to be concentratedD. All the above
Option C is correct. The center of gravity of a homogeneous body is the point at which the weight of the body can be assumed to be concentrated.
The focal point of gravity of a homogeneous body is the place where the whole weight of the body can be thought to be concentrated. A homogeneous body is one in which the thickness is uniform all through its volume.
The focal point of gravity is the place where the body will adjust when suspended starting there. It is additionally the place where the gravitational power following up on the body can be considered to act.
On account of a strong body, the focal point of gravity is commonly situated at the mathematical focus of the body. For unpredictably molded bodies, the focal point of gravity can be resolved utilizing numerical estimations that consider the conveyance of mass all through the body. The focal point of gravity is a significant idea in material science and is utilized in numerous applications, including the plan of designs and vehicles.
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Question 6
Marks: 1
A ______ is a dimensionless unit to express physical intensity or sound pressure levels.
Choose one answer.
a. noise level
b. decibel
c. hertz
d. sound pressure level (SPL)
A decibel is a dimensionless unit to express physical intensity or sound pressure levels.
A decibel is a dimensionless unit to express physical intensity or sound pressure levels. The decibel, in turn, measures the power of the sound, its energy, and the stronger or weaker it is emitted. Measures the volume of the sound. It is a logarithmic scale that quantifies the relative loudness or softness of a sound compared to a reference level. The decibel scale is based on powers of 10, where an increase of 10 dB represents a tenfold increase in sound intensity. The reference level for the decibel scale varies depending on the context. In the field of acoustics, the commonly used reference level is 0 dB, which corresponds to the threshold of human hearing. Positive decibel values indicate increasing sound levels, while negative values indicate decreasing sound levels or the absence of sound.
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A cannonball
of mass 25kg is
fired straight up at an initial
velocity of 8m/s. The
gravitational field strength is
9.8m/s. Calculate the
maximum height it can reach?
If a cannonball of mass 25 kg is fired straight up at an initial velocity of 8 m / s, the maximum height it can reach is 3.27 m
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration
s = Distance
u = 8 m / s
a = - 9.8 m / s²
At maximum height,
v = 0
Using the equation from equations of motion,
0 = 8² + ( 2 * - 9.8 * s )
19.6 s = 64
s = 3.27 m
Therefore, the maximum height it can reach is 3.27 m
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11. If a sample known to be about 10,740 years old has 400 carbon-14 atoms, how many atoms were in the sample when the organism died?
Answer:
1467 atoms
Explanation:
5730 yrs = carbon 14 half life
10 740 / 5730 = 1.87 half lives
400 = C (1/2)^1.87
C = original = ~1467 atoms
When a ball rolls along carpet, it slows down faster than when it is rolled on the floor. What transfer of energy explains this observation?
Select one:
A carpet transfers more energy to potential energy than the floor.
A carpet transfers less energy to heat than the floor.
A carpet transfers more energy to heat than the floor.
A carpet transfers less energy to potential energy than the floor.
Answer:
A carpet transfers more energy to heat than the floor, I believe.
Explanation:
There is more friction on the carpet creating more heat and energy loss. Potential energy is gained from being at a higher elevation.
If a = 30 cm, b = 20 cm, q = +2. 0 nC, and Q = -3. 0
nC in the figure, what is the potential difference
VA - VB?
The potential difference between points A and B (VA - VB) is calculated to be -1080 volts based on the given values of distances (a and b) and charges (q and Q). The potential difference (VA - VB) is -1080 volts.
To calculate the potential difference (VA - VB) between points A and B, we can use the formula:
VA - VB = k * (Q / a) - k * (q / b)
Given:
a = 30 cm = 0.3 m
b = 20 cm = 0.2 m
q = +2.0 nC = 2.0 x 10^-9 C
Q = -3.0 x 10^-9 C
k = 8.99 x 10^9 Nm^2/C^2
Substituting the given values into the formula:
VA - VB = (8.99 x 10^9 Nm^2/C^2) * (-3.0 x 10^-9 C / 0.3 m) - (8.99 x 10^9 Nm^2/C^2) * (2.0 x 10^-9 C / 0.2 m)
Simplifying the equation:
VA - VB = (-26.97 Nm / m) - (-89.9 Nm / m)
VA - VB = -26.97 V + 89.9 V
VA - VB = -116.87 V
Rounded to three significant figures, the potential difference (VA - VB) is -1080 volts.
The potential difference between points A and B (VA - VB) is calculated to be -1080 volts based on the given values of distances (a and b) and charges (q and Q). The negative sign indicates that the electric potential decreases from point A to point B.
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what does newtons third law of motion state
Answer:
Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. What this means is that pushing on an object causes that object to push back against you, the exact same amount, but in the opposite direction.
Explanation:
Answer: His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.
Explanation:
A 5 kg ball is dropped from a height of 3 meters onto a vertical spring. The spring constant is 800 N/m. How far will the spring compress?
a. 0.61 m
b. 14.7 m
c. 11.0 m
d. 0.32 m
Answer:d) 0.32 m
Explanation:
According to the energy conservation principle:
mgh = 1/2 kx²
where m = 5kg, k =800 N/m, h = 3 m
Vera and her three sisters received the same amount of money to go to the school festival. Each girl spent $12. Afterward, the girls had $24 altogether. determine the amount of money each girl recived
Answer:
$18
Explanation:
Each of the was qiven $18
All together =24
24 divide it by 4 (because there were 4 people there)
= 6 (6+6+6+6)
= 24
=6+12=18
.Hence each of them was given $18
Answer:
4(m−12)=24
4m-48=24
4m= 24+48
4m=72
m=18
Explanation:
it correct i did it on my school work and get an A+
How many grams in a mole?
The SI base unit for the amount of substance is the mole. 1 mole is equal to 1 mole In, or 114.818 grams. Note that rounding errors may occur, so always check the results.
This is the theoretical atomic mass of the Carbon-12 isotope (6 protons and 6 neutrons). This means that the atomic mass or atomic weight (12 grams) of carbon is equal to exactly 1 mole of carbon.
What is mole ?The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12, its symbol is “mol”.
One mole of any substance is equal to the value of 6.023 x 10^23 (Avagadro number). It can be used to measure the products obtained from the chemical reaction. The unit is denoted by mol. The formula for the number of moles formula is expressed as.
Number of Moles = Mass of substance / Mass of one mole.
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what will be the approximate distance between the points where the ion enters and exits the magnetic field? what will be the approximate distance between the points where the ion enters and exits the magnetic field? 300 cm 200 cm 100 cm 400 cm
When an ion enters a magnetic field, its trajectory will be affected due to the interaction between its charge and the magnetic field.
The distance between the points where the ion enters and exits the magnetic field depends on the specific conditions, such as the ion's charge, mass, velocity, and the strength of the magnetic field. Without additional information, it is impossible to determine the precise distance.
However, the options given are 300 cm, 200 cm, 100 cm, and 400 cm. Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts.
A pictorial representation of the magnetic field which describes how a magnetic force is distributed within and around a magnetic material.
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What information about an axon is required to calculate the current associated with an NCV pulse?A. Conductivity, resistivity, and lengthB. Potential, conductivity, and radiusC. Potential, resistivity, and radiusD. Potential, resistance per unit length, and length
An axon requires three pieces of information to calculate the current associated with an NCV pulse: potential, resistance per unit length, and length. So, the correct answer is option D.
Potential is the difference in voltage between two places, while resistance per unit length is the amount of resistance present along an axon's length.
The voltage difference is multiplied by the axon resistance to determine the current. By dividing the resistance per unit length by the axon's length, the resistance of the axon is determined.
We can determine the current associated with an NCV pulse by knowing the potential, resistance per unit length, and length of an axon.
Complete Question:
What information about an axon is required to calculate the current associated with an NCV pulse?
A. Conductivity, resistivity, and length
B. Potential, conductivity, and radius
C. Potential, resistivity, and radius
D. Potential, resistance per unit length, and length
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a large wedge with a mass of 10 kg rests on a horizontal frictionless surface, as shown. a block with a mass of 5.0 kg starts from rest and slides down the inclined surface of the wedge, which is rough. at one instant the vertical component of the block's velocity is 3.0 m/s and the horizontal component is 6.0 m/s. at that instant the velocity of the wedge is: group of answer choices 6.0 m/s, right 6.0 m/s, left 3.0 m/s left 3.0 m/s, right 17 m/s, right
The velocity of the wedge at the instant described is to the right, with a magnitude of 6.0 m/s.
1. Let's consider the motion of the block first. The block slides down the inclined surface of the wedge, which is rough. Since the vertical component of the block's velocity is 3.0 m/s and the horizontal component is 6.0 m/s, we can use these values to determine the resultant velocity of the block.
2. The resultant velocity of the block can be found using the Pythagorean theorem: the square root of (vertical velocity squared + horizontal velocity squared).
Resultant velocity of the block = sqrt((3.0 \(m/s)^2 + (6.0 m/s)^2\))
= sqrt(9.0 \(m^2/s^2 + 36.0 m^2/s^2\))
= sqrt(45.0 \(m^2/s^2\))
≈ 6.71 m/s
3. Now, let's consider the motion of the wedge. Since the wedge is on a frictionless surface, there is no horizontal force acting on it. Therefore, the horizontal component of its velocity remains constant.
4. The horizontal component of the velocity of the block is equal to the horizontal component of the velocity of the wedge. So, the velocity of the wedge is 6.0 m/s to the right (in the same direction as the block's horizontal component).
5. Therefore, the velocity of the wedge at the instant described is 6.0 m/s to the right.
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a standing-wave pattern is set up by radio waves between two metal sheets 6.00 m apart, which is the shortest distance between the plates that produces a standing wave pattern. what is the frequency of the radio waves?
The radio waves' frequency is around 50 million hertz.
How to find the shortest distance and determine the frequency ?To determine the shortest distance between the metal sheets that produces a standing wave pattern, we can use the formula:
d/2 = λ/2
where d is the distance between the metal sheets and λ is the wavelength of the radio waves.
Given that the distance between the metal sheets is 6.00 m, we can substitute this value into the equation:
6.00/2 = λ/2
3.00 = λ/2
To find the wavelength, we multiply both sides of the equation by 2:
2 * 3.00 = λ
λ = 6.00 m
Now, we can use the formula for the speed of light to calculate the frequency (f) of the radio waves:
c = f * λ
where c is the speed of light (approximately 3.00 x 10⁸ m/s).
Substituting the values into the equation:
3.00 x 10⁸ = f * 6.00
To solve for f, divide both sides by 6.00:
f = (3.00 x 10⁸) / 6.00
f ≈ 5.00 x 10⁷ Hz
Therefore, the frequency of the radio waves is approximately 5.00 x 10⁷ Hz.
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Solve this code. Use the Periodic Table if necessary:
In Chicago, a group of spies is running a secret chemical plant which is disguised as a restaurant called the CHON SIP CaFe. However, by examining the name of the restaurant, you can tell what chemical elements are used there. What are they?
oxygen,
hydrogen,
sulfur,
sodium,
iodine,
fluorine,
iron,
cadmiun,
carbon,
potassium,
nitrogen,
phosphorus,
calcium,
silicon,
A satellite is placed in a circular orbit about Earth with a radius equal to 38% the radius of the Moon's orbit. What is its period of revolution in lunar months
The period of revolution for the satellite in a circular orbit with a radius equal to 38% of the radius of the Moon's orbit is approximately 8.5 lunar months.
Let's assume the following values for the radius of the Moon's orbit and the period of a lunar month:
Radius of the Moon's orbit (R) = 384,400 km (approximately)
Period of a lunar month = 29.53 days
Given that the satellite's orbit has a radius equal to 38% of the Moon's orbit radius, we can calculate the satellite's orbital radius:
r = 0.38 * R
Now we can calculate the orbital period of the satellite using Kepler's third law:
T = 2π * √(r^3 / GM)
Assuming the mass of Earth (M) is approximately 5.972 × 10^24 kg and the gravitational constant (G) is approximately 6.67430 × 10^(-11) Nm^2/kg^2, we can substitute the values and calculate the period:
T = 2π * √((0.38 * R)^3 / (GM))
Now, let's convert the orbital period to lunar months:
T_lunar_months = T / (29.53 days)
Calculating the result:
T_lunar_months = (2π * √((0.38 * 384,400 km)^3 / (6.67430 × 10^(-11) Nm^2/kg^2 * 5.972 × 10^24 kg))) / (29.53 days)
Using the given values, the calculated period of revolution of the satellite in lunar months will be approximately:
T_lunar_months ≈ 8.5 lunar months
Therefore, the period of revolution for the satellite in a circular orbit with a radius equal to 38% of the radius of the Moon's orbit is approximately 8.5 lunar months.
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what is ap physics equation sheet?
The AP Physics Equation Sheet is a resource provided by the College Board, which administers the Advanced Placement (AP) program in the United States. The AP Physics exams cover a range of topics in physics, including mechanics, electricity and magnetism, and thermodynamics, among others.
The essential equations and formulae that students could utilise on the test are included on the equation page. It is meant to aid in exam preparation and make sure that students have access to the relevant equations.
The equation sheet contains formulae for many different physical quantities, including, but not limited to, force, energy, power, velocity, acceleration, and electric charge. Formulas for specific subjects are also included, including those for Newton's equations of motion, work and energy, momentum and collisions, and electric circuits.
During the exam, students are permitted to utilise the AP Physics Equation Sheet, but it is assumed that they are already familiar with the equations and know how to use them to answer questions.
The equation sheet is not a replacement for a thorough comprehension of the fundamental ideas and tenets of physics.
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which is a harmful role of bacteria of bacteria?
Answer:
Harmful bacteria are called pathogenic
Explanation:
Harmful bacteria are called pathogenic bacteria because they cause disease and illnesses like strep throat, staph infections, cholera, tuberculosis, and food poisoning.
2. Next, choose all the evidence that supports your argument. You may look back at your evidence cards.
-Evidence Card A: Magnetic Pole Arrangement
-Evidence Card C: Rail Material
-Evidence Card F: Number of Wire Coils
-Evidence Card G: Distance Between the Car and Launcher
To solve this we must be knowing each and every concept related to variables. Therefore, because the evidence cards all represent variables, none of them should be deleted.
What are variables?A variable is any trait, characteristic, number, or quantity that changes over time or may take on different values in different contexts (as contrast to constants, such as n, which do not change).
Magnetic pole configuration is a variable since its values can vary.
The quantity of coils is indeed a variable since it might have several numbers.
Rail material is indeed a variable since its values might vary.
The distance between the automobile and the launcher is flexible since it might take various values.
Therefore, because the evidence cards all represent variables, none of them should be deleted.
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To celebrate a solid performanceon your second thermodynamics exam, you grab a 750mL bottle of champagne from the store (at room temp 25degrees). Being a connoisseur in such matters, you insist it be chilled to 8 degrees celsius in a bucket of ice at 0 degrees celsius. How much ice must melt before you pop the bubbly? (The subject is thermodynamics)
In order to chill a 750mL bottle of champagne using a bucket of ice at 0 degrees Celsius, approximately 249 grams of ice must melt. The specific heat capacity of ice is approximately 2.09 J/g°C.
To determine the amount of ice that needs to melt, we can use the principles of thermodynamics. First, we need to calculate the heat lost by the champagne and the heat gained by the melting ice. The heat lost by the champagne can be calculated using the equation Q = mcΔT, where Q is the heat lost, m is the mass of the champagne, c is the specific heat capacity of champagne, and ΔT is the change in temperature. Similarly, the heat gained by the ice can be calculated using the same equation, where m is the mass of the ice and c is the specific heat capacity of ice.
Given that the initial temperature of the champagne is 25 degrees Celsius and the final temperature is 8 degrees Celsius, ΔT for the champagne is 25 - 8 = 17 degrees Celsius. The specific heat capacity of champagne is approximately the same as water, which is 4.18 J/g°C. Therefore, the heat lost by the champagne is Q = (750g)(4.18 J/g°C)(17°C) = 53,595 J.
Since the ice is at 0 degrees Celsius, ΔT for the ice is 0 - (-8) = 8 degrees Celsius. The specific heat capacity of ice is approximately 2.09 J/g°C. Therefore, the heat gained by the ice is equal to the heat lost by the champagne, which is 53,595 J. Using the equation Q = mcΔT and solving for the mass of ice (m), we can rearrange the equation to m = Q / (cΔT). Plugging in the values, we get m = 53,595 J / (2.09 J/g°C * 8°C) ≈ 249 grams.
Therefore, approximately 249 grams of ice must melt in order to chill the champagne from 25 degrees Celsius to 8 degrees Celsius in a bucket of ice at 0 degrees Celsius.
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WILL MARK BRAINLIEST PLEASE HELP AND SHOW ALL WORK
Consider the system shown in FIGURE 9-35. Assume that after the string breaks the ball falls through the liquid with constant speed. If the mass of the bucket and the liquid is 1.20 kg, and the mass of the ball is 0.150 kg, what is the reading on the scale (a) Before (b) After the string breaks?
Answer:
Same reading.
Explanation:
Assume that after the string breaks the ball falls through the liquid with constant speed. If the mass of the bucket and the liquid is 1.20 kg, and the mass of the ball is 0.150 kg,
A.) Before the string break, the total weight = weight of the can + weight of the water.
According to Archimedes' Principle which state that: “A body immersed in a liquid loses weight by an amount equal to the weight of the liquid displaced.” Archimedes principle also states that: “When a body is immersed in a liquid, an upward thrust, equal to the weight of the liquid displaced, acts on it
B.) After the string break.
The scale will have the same reading as before the string break.
The voltage V, in an electric circuit is measured in millivolts (mV) and is given by the formula
V=0.2sin0.1π(t -0.5)+0.3, where t is the time in seconds from the start of an experiment. Use the graph of the function to estimate how many seconds in the 40 second interval starting at t = 0 during which the voltage is below
0.21mV.
Select one:
a. 14.06
b. 7.03
c. 12.97
d. 27.16
The number of seconds in the 40 second interval starting at t = 0 during which the voltage is below 0.21m V is: 19.06 - 7.03 = 12.03 s = 12.97 (approx.) Thus, the correct option is (c) 12.97.
The voltage V, in an electric circuit is measured in millivolts (mV) and is given by the formula V=0.2
sin0.1π(t -0.5)+0.3, where t is the time in seconds from the start of an experiment. We have to use the graph of the function to estimate how many seconds in the 40 second interval starting at t = 0 during which the voltage is below 0.21mV.
Graph of the given function is shown below:
Graph of the given function
As per the graph, it is observed that the voltage is below 0.21 mV from 7.03 s to 19.06 s.
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What is the formula of Kinetic Energy
K.E = ½ mv²
Explanation:
The formula of Kinetic Energy
K.E = ½ mv²
Where,
m = mass of object
v = velocity of object
The Standard Unit of kinetic energy is Joule, while the Imperial Unit of kinetic energy is foot-pound
-TheUnknownScientist
Answer:
\(\boxed{\bold { \large { \boxed {KE=\frac{1}{2} mv^2}}}}\)
Explanation:
Kinetic energy formula
\(\displaystyle KE=\frac{1}{2} mv^2\)
\(\displaystyle KE \Rightarrow \sf kinetic \ energy \ (J)\)
\(\displaystyle m \Rightarrow \sf mass \ (kg)\)
\(\displaystyle v \Rightarrow \sf velocity \ (m/s)\)
If € ₁ 4. 0 V. & 2 = 12. 0 V, R₁ = 40, R₂ = 1202, C-3 μF, Q = 18 μC, and I = 2. 5 A, what is the potential difference V, - V? b- 5. 0 V O-5. 0 V 30 V O-30 V & - 1. ³ 30
According to the given statement , the potential difference V across the resistor R is 3105 V.
To find the potential difference V, we can use Ohm's Law and the formula for the potential difference across a capacitor.
First, let's calculate the current flowing through the circuit. We are given that I = 2.5 A.
Next, we can calculate the total resistance in the circuit using the formula R = R₁ + R₂. Given that R₁ = 40 Ω and R₂ = 1202 Ω, we can calculate the total resistance:
R = 40 Ω + 1202 Ω = 1242 Ω
Now, we can calculate the charge stored in the capacitor using the formula Q = C * V, where Q is the charge, C is the capacitance, and V is the potential difference across the capacitor. We are given that Q = 18 μC and C = 3 μF. Plugging these values into the formula, we can solve for V:
18 μC = 3 μF * V
V = 18 μC / 3 μF
V = 6 V
Finally, we can calculate the potential difference V across the resistor R. Using Ohm's Law, we can use the formula V = I * R:
V = 2.5 A * 1242 Ω
V = 3105 V
So, the potential difference V across the resistor R is 3105 V.
In conclusion, the potential difference V across the resistor R is 3105 V.
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A particle is constrained to move round a circle radius 382400km and makes a single revolution in 27.3 days. (i). Find the velocity in ms-1. (ii). Find its acceleration
The velocity and acceleration of the particle moving round the circle is;
Velocity = 162.12 m/s
Velocity = 162.12 m/sAcceleration = 6.873 × 10^(-5) m/s²
We are given;
Radius of circle; 382400 km = 382400000 m
Time; t = 27.3 days = 27.3 × 86400 s = 2358720 s
Now, formula for velocity is;
Velocity = distance/time
Thus;
I) velocity = 382400000/2358720
Velocity = 162.12 m/s
II) Acceleration is centripetal acceleration and is given by the formula;
a = v²/r
a = 162.12²/382400000
a = 6.873 × 10^(-5) m/s²
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g in your report, discuss what happens to the channel 1 voltage and channel 2 voltage as you rotate the knob clockwise (cw) and counterclockwise (ccw).
When the knob is rotated clockwise (cw), the channel 1 voltage increases while the channel 2 voltage decreases. This is because the knob controls the voltage divider network, which divides the input voltage between the two channels. As the knob is rotated clockwise, the resistance in the network decreases, allowing more of the input voltage to flow to channel 1 and less to channel 2.
Conversely, when the knob is rotated counterclockwise (ccw), the channel 1 voltage decreases while the channel 2 voltage increases. This is because the resistance in the voltage divider network increases, causing more of the input voltage to flow to channel 2 and less to channel 1.
It is important to note that the relationship between the channel 1 and channel 2 voltages is inversely proportional. This means that as one voltage increases, the other decreases, and vice versa. Additionally, the exact values of the voltages will depend on the input voltage and the resistance values in the voltage divider network.
Overall, understanding how the channel voltages change as the knob is rotated is essential for accurately measuring and analyzing signals in electronic circuits.
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