Answer:
T(K) = 373.15 K
Explanation:
The kelvin is the base unit of temperature in the International System of Units (SI). The symbol used to express temperature in kelvins is K.
The temperature of zero kelvins is called the absolute zero. It is considered to be the lowest possible temperature, although nothing has reached it. The absolute zero (0K) is - 273.15 degrees Celsius.
This is the equation we can use to solve this question:
\(T(K) = T(C) + 273.15\)
We have 100*C.
\(T(C) = 100 C\)
\(T(K) = 100C + 273.15\)
\(T(K) = 373.15 K\)
Green plants use light from the Sun to drive photosynthesis, a chemical reaction in which liquid water and carbon dioxide gas form aqueous glucose C6H12O6 and oxygen O2 gas. Calculate the moles of water needed to produce 0.500mol of glucose. Be sure your answer has a unit symbol, if necessary, and round it to 3 significant digits.
In order to find the answer we need to set the equation up first, so the reaction for photosynthesis is:
6 CO2 + 6 H2O + energy -> C6H12O6 + 6 O2
Now by checking the molar ratio between water and glucose we see that for every 6 moles of H2O we will end up having 1 mol of C6H12O6, so we have a 6:1 molar ratio, now in order to produce 0.500 we will find out by doing the following calculation:
6 H2O = 1 C6H12O6
x H2O = 0.500 C6H12O6
x = 3.00 moles of H2O are needed to produce 0.500 moles of glucose
How many moles at of a gas will occupy 2.5 L at STP?
We need to answer the question with steps of that method.
Explanation:
Volume of gas = 2.50 L
Temperature = 273 K
Pressure = 1 atm
Moles of gas = ?
Solution:
PV = nRT
n = PV/RT
n = 1 atm× 2.50 L / 0.0821 atm. L. K⁻¹.mol⁻¹ . 273 K
n = 2.5 atm. L /22.4 atm. L. mol⁻¹
n = 0.112 mol
what is burning considered ?
7th grade science help me pleaseee
co2,nacl,hcl are all classified as what
Answer:
co2 oxide,nacl salt ,hcl acid
The kinetic energy distributions of particles of a gas at 20 °C and at 60 °C is shown below.
Which one of the statements relating to these distributions is correct?
(a) At 20 °C the average kinetic energy of the particles is higher than at 60 °C.
(b) At 20 °C there are no particles with a high kinetic energy.
(c) At 60 °C there are no particles with a low kinetic energy.
(d) At 60 °C there are more particles with higher kinetic energy than at 20 °C.
Answer:
(a) At 20 °C the average kinetic energy of the particles is higher than at 60 °C.
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if you run the acetylation reaction (part 1) using the exact amounts described in the procedure, what is the limiting reagent?
A limiting reagent is one that is completely consumed during a reaction, hence restricting the product's yield. Compared to the limiting reagent, the other reactant(s) are present in excess.
The amount of product that could be produced based on the molar ratios is known as the theoretical yield. The amount that was actually retrieved is divided by the theoretical yield to determine the percent yield. For this amount to be expressed as a percentage, multiply it by 100.
What is Acetylation Reaction ?Acetylation is an organic esterification reaction using acetic acid in organic chemistry. It gives a chemical molecule an acetyl group. These substances are known as acetate esters or just acetates. The opposing reaction, deacetylation, involves removing an acetyl group from a chemical molecule.
Deacetylation is the removal of an acetyl group from an organic chemical molecule, whereas acetylation is the introduction of an acetyl functional group (acetoxy group, CH3CO) into an organic chemical compound, specifically the substitution of the acetyl group for a hydrogen atom.
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In the equation shown, what are the reactants?
2H2+O2 --> 2H2O
Answer:
the hydrogen and the oxygen are the reactants while the H20(water) formed is the product
Physical properties like hardness, melting point, and boiling point depend on
Answer:
depend on nature of matter
Answer:
It depends on the temperature and how the molecules react
If you were to take the temperature of fire, what particles would you be taking the temperature of?
The particles move faster as their kinetic energy increases with rising temperature, leading to higher collision and diffusion rates. The particles gain kinetic energy as the temperature rises, which causes them to vibrate more quickly.
What is kinetic energy?An object's kinetic energy is the energy it has as a result of motion. Applying force is necessary if we wish to accelerate an object. We have to put forth work to apply a force. After the job is finished, the object will be travelling at a new, constant speed because energy has been transferred to it.
We use the aforementioned logic to get the kinetic energy and start by determining the work done, W, by a force, F, in a straightforward example. Consider a force parallel to a surface pushing a box with mass mm through a distance d along that surface.
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Measurements of the heights of various plants in an experiment are called
Answer:
Option 1 Data
Answer:
data
Explanation:
that is the answer
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What are the three components of soil texture?
Hurry please help!
Answer: sand, silt, and clay.
a reaction has a rate law of rate = (1.25 m⁻²s⁻¹)[a][b]². what concentration of [b] would give the reaction a rate of 0.0891 m/s if the concentration of [a] is 0.250 m?
The reaction has a rate law of the rate = (1.25 m⁻²s⁻¹)[A][B]². The concentration of [B] will give the reaction of rate of 0.0891 m/s if the concentration of [A] is 0.250 M is [B] is 0.52 M.
The concentration of [A] = 0.250
The Rate = (1.25 m⁻²s⁻¹)[A][B]²
By solving the equation , we get :
0.0857 = 1.25 [A] [B]²
0.0857 = 1.25 × 0.250 × [B]²
0.0857 = 0.3125 [B]²
[B]² = 0.27424
[B] = 0.52 M
Thus, the concentration of the [B] is 0.52 M with the reaction has a rate law of rate = (1.25 m⁻²s⁻¹)[A][B]².
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Plants cells also gain energy through cellular respiration.
True or false?
Answer:
true
Explanation:
Which of the following combinations will NOT result in a precipitate, according to
solubility rules?
The combination of ammonium chloride and sodium hydroxide will not give a precipitate. Option A
What is a precipitate?The solubility rules gives us the idea of the kind of combination of reactants that would lead to the formation of a precipitate. We can now apply that knowledge in this question.
These regulations are founded on the idea of solubility, or a substance's capacity to dissolve in a solvent, typically water.
These solubility rules provide a quick and easy way to predict the solubility of many ionic compounds in water.
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Which of the following is a strong acid?
A. Sulphuric acid
B. Acetic acid
C. Tartaric acid
D. Lactic acid
A strong acid is A. Sulphuric acid.
What is strong acidStrong acids are those that completely dissociate in water, meaning that they fully break apart into their individual ions.
Sulphuric acid (H2SO4) is a strong acid because it completely dissociates in water to form 2 hydrogen ions (H+) and 1 sulfate ion (SO42-).
On the other hand, acetic acid (CH3COOH), tartaric acid (C4H6O6), and lactic acid (C3H6O3) are all weak acids because they only partially dissociate in water.
This means that they do not fully break apart into their individual ions, and instead remain mostly in their original form. Therefore, the correct answer is A. Sulphuric acid.
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You need to calculate the enthalpy change (AHO) of the reaction A + B → C.How can the enthalpies given for the reaction steps below be combined to give the overall change in enthalpy?
Answer:
Explanation:
The question requires us to determine a proper equation to calculate the enthalpy change for the following reaction:
\(A+B\rightarrow C\)Considering the generic reactions and their associated enthalpy change given:
\(\begin{gathered} Reaction\text{ }1:A+B\rightarrow D\text{ }\Delta H_1^° \\ Reaction\text{ }2:C+\frac{1}{2}B\rightarrow D\text{ }\Delta H_2^° \end{gathered}\)According to Hess' Law, enthalpy is a function of state, which means it does not depend on the path by which reactants are converted to products. Using this definition, we can rearrange the reactions 1 and 2 given (and apply all the changes required to their associated enthalpy change) in order to obtain the required reaction, and then calculate the enthalpy change of the final reaction considering the rearranged enthalpies of reactions 1 and 2.
Our final objective is to obtain a chemical equation that presents 1 mol of reactants A and B on the left side, and 1 mol of product C on the right side.
First, let's guarantee that we will have product C by multiplying reaction 2 by -1:
\(Reaction\text{ 2}\times(-1):D\rightarrow C+\frac{1}{2}B\text{ }\Delta H_2^°=-\Delta H_2^°\)Next, we need to make sure that
Using the equation: 3 NO2(g)H2O-->2 HNO3(aq)+ NO (g)If you start with 10.0 g of NO2(g) and 30.0 g of H2O0):a. What is the limiting reagent for this reaction?b. How many grams of nitric acid can be produced? (theoretical yield)
Answer:
a. The limiting reagent is NO2.
b. 126g of nitric acid can be produced.
Explanation:
1st) It is necessary to write the balanced equation:
\(3NO_2+H_2O\text{ }\rightarrow2HNO_3\text{ + NO}\)From the balanced equation we know that 3 moles of NO2 (3x46g= 138g) react with 1 mol of water (18g/mol) to produce 2 moles of nitric acid (2x63g= 126g) and 1 mol of NO (30g/mol).
2nd) To calculate the limiting reagent it is necessary to use the given values and the stoichiometry of the balanced equation:
\(\begin{gathered} 138gNO_2-18gH_2O \\ 10.0gNO_2-x=\frac{10.0gNO_2\cdot18gH_2O}{138gNO_2} \\ x=1.30gH_2O \end{gathered}\)The 10.0g of NO2 will need 1.30g of H2O to react.
\(\begin{gathered} 18gH_2O-138gNO_2 \\ 30.0gH_2O-x=\frac{30.0gH_2O\cdot138gNO_2}{18gH_2O} \\ x=230gNO_2 \end{gathered}\)The 30.0g of H2O will need 230g of NO2 to react.
So, as we only have 10.0g of NO2 and 30.0g of H2O, the limiting reagent will be NO2.
3rd) Now, to calculate the theorical yield, we need to use the stoichiometry of the balanced equation using the limiting reagent:
1 mol of H2O produces 2 moles of nitric acid. With the molar mass of nitric acid (63g/mol), we can calculate the grams.
\(2\text{moles}\cdot(\frac{63g}{1\text{mol}})=126g\)
Finally, 126g of nitric acid will be produced if the reaction is 100% efficient (theoretical yield).
Additional Information needed: 1 eV = 1.6•10-19 j
1.) What is the wavelength of a photon absorbed by an electron that gained 1.89 electron-volts, or ev, upon perfect absorption of the photon?
2.) An electron initially in the orbital n = 2 that gained 1.89 eV can be found in what orbital after gaining that much energy?
3.) How many moles of photons contain 5,000 J of energy if every photon has a wavelength of 400 nm?
1) The wavelength of the photon is 6.5 * 10^ -7 m
2) The final level is n =2
3) The number of photons is 1 * 10^ 22
What is the wavelength?Recall that we must first convert the energy to joules as follows;
1 eV = 1.6 * 10^ -19 J
1.89 eV = 1.89 eV * 1.6 * 10^ -19 J/ 1 eV
= 3.024 * 10^ -19 J
Again;
E = hc/λ
E = energy
h = Plank's constant
c = speed of light
λ = wavelength
3.024 * 10^ -19 J = 6.6 * 10^ -34 * 3 * 10^ 8/λ
λ = 6.6 * 10^ -34 * 3 * 10^ 8/3.024 * 10^ -19 J
= 6.5 * 10^ -7 m
2)
Now we have;
E = -RH (1/\(n_{2} ^{2}\) - 1/\(n_{1} ^{2}\))
RH = Rydberg constant
Initial level = 2
Final level = x
Energy = 1.89 eV or 3.024 * 10^ -19 J
3.024 * 10^ -19 = - 2.18 * 10^ -18 (1/x^2 - 1/4)
3.024 * 10^ -19 /2.18 * 10^ -18 = 1/4 - 1/x^2
0.139 = 1/4 - 1/x^2
0.139 = 0.25 - 1/x^2
0.139 - 0.25 = - 1/x^2
-0.111 = - 1/x^2
0.111 = 1/x^2
x^2 = 9
x = 3
3) Let us find the energy from;
E = 6.6 * 10^ -34 * 3 * 10^ 8/400 * 10^-9
E = 0.0495 * 10^- 17 J
E = 4.95 * 10^ -19 J
Then;
5,000 J = n4.95 * 10^ -19 J
n = 5,000 J/4.95 * 10^ -19 J
= 1 * 10^ 22
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Particles of the substance have the most kinetic energy when the substance is(a)_______. The part of the graph that represents where the substance has the least amount of potential energy is labeled(b)_______.
multiple choice answers available.
(a)
1. A gas
2. A solid
3. Melting
4. vaporizing
(b)
1. Solid
2. Vaporizing
3. melting
4.liquid
5.gas
Answer: 1- gas 2- solid
Explanation:
how many atoms are in hydrogen
Answer:6.02
Explanation:
Answer:
there are about 6 atoms in hydrogen
What is the isotope name of the element that has 9 neutrons?
1)Beryllium-4
2 ) Beryllium-9
3) Fluorine-9
4) Fluorine-19
5)Not enough information to tell
We do not have enough information to deduce the isotope that would have nine neutrons. Option 5
What is the neutron?The atom is composed of subatomic particles. The subatomic particles that are in the atom are such that we have the electrons that are negatively charged, the protons that are positively charged and the neutrons that are uncharged.
Now, we know that the number of neutrons is obtained as the difference between the mass number and the atomic number of the atom. In this case, we only have the mass numbers and not the atomic numbers thus we do not have sufficient information.
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15. If I make 94.8 L of O2, how many grams of H2O did I start with? (Show ALL work)
Answer:
double
Explanation:
.
Copper used in electric wires comes in two flavors (isotopes): Cu-63 and Cu-65. Cu-63 has an atomic mass of 62.9298 amu and an abundance of 69.09%. The other isotope, Cu-65, has an abundance of 30.91%. The average atomic mass between these two isotopes is 63.546 amu.
Calculate the actual atomic mass of Cu-65.
Copper used in electric wires comes in two flavors (isotopes): Cu-63 and Cu-65. Cu-63 has an atomic mass of 62.9298 amu and an abundance of 69.09%. The other isotope, Cu-65, has an abundance of 30.91%. The average atomic mass between these two isotopes is 63.546 amu is 64.93 amu.
Average atomic mass = sum of masses of isotopes multiply by % of abundance
Cu - 63, mass = 62.9298 amu, % abundance = 69.09 %
Cu - 65, mass m2 = ? % abundance = 30.91 %
average atomic mass = 63.546 amu
average atomic mass = ( 62.9298 × 0.6909 ) + ( m2 × 0.3091 )
63.546 = ( 62.9298 × 0.6909 ) + ( m2 × 0.3091 )
m2 = 64.93 amu
Thus, Copper used in electric wires comes in two flavors (isotopes): Cu-63 and Cu-65. Cu-63 has an atomic mass of 62.9298 amu and an abundance of 69.09%. The other isotope, Cu-65, has an abundance of 30.91%. The average atomic mass between these two isotopes is 63.546 amu is 64.93 amu.
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2. How many of valence electrons do the elements in column 4 have? Are these elements very reactive?
Explain your answer.
Answer:
4
Explanation:
Elements in group 14 have 4 valence electrons. Meaning that to achieve a stable octet they need to either gain or lose 4 electrons in total.
5. If all the particles in a material are made up of
several smaller particles, and every larger particle
is identical, is the material a pure substance or
not? Explain your reasoning.
Answer:
No. Because a pure substance, no matter if an element, compound, it can only contain one kind of particle .
Explanation:
6. What is the molecular formula for this compound? The compound's empirical formula and
molar mass is given. CH20, 120g/mol
Explanation:
A compound's empirical formula tells you the smallest whole number ratio ,The molar mass tells you what the total mass of one mole
which of the following is a pure compound A. ethanol B. petrol C. steel D. tap water
Answer:
D. tap water
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Answer: ethanol
Explanation: as it is a pure compound and can sometimes be a mixture while all the rest are mixtures.
What is the difference between bulk and particle scale?
Someone please help!!
Answer:
Particle density is the volumetric mass of the solid soil. It differs from bulk density because the volume used does not include pore spaces. Particle density represents the average density of all the minerals composing the soil.
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flower position - S, dominant - tip if the stem, recessive - side of the stem, Parent 1 SS; Parent 2 ss
free/attached earlobe - L, dominant - attached earlobe, recessive - free earlobe, Parent 1 Ll ; Parent 2 LL
widow's peak - P, dominant - no widow's peak, recessive - have a widow's peak, Parent 1 Pp; Parent 2 PP
All of the progeny of two flowers with genotype Ss will have tips of the stem flowers.
In the event where one parent (genotype Pp) has a widow's peak and the other parent (genotype pp) does not, what is the likelihood that the child will also have a widow's peak?Every of their descendants will have a 50% chance of inheriting a widow's peak (dominant trait) and a 50% chance of not receiving a widow's peak if one parent has a widow's peak and the other parent does not (genotype Pp) (recessive trait).
What proportion of their children will have flowers on the side of the stem if two Ss genotype flowers are crossed?25% of the progeny of two flowers with genotype Ss will have blossoms on the side of the stalk (recessive trait).
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