The table shows the results of a survey of 150 students.


Use the table to find the probability of a student participating


in each sport.


1. Football


2. Tennis

Answer:

20

Step-by-step explanation:

3x+15=4x-5

3x+15-15=4x-5-15

Answer:

The answer is 112

Step-by-step explanation:

first you add 48 together twice to get 96 which represents 6 hours. Then you divide 48 by 3 to get 16. So you add 16 to 96 which represents 2 hours giving you a total of 112 tons of flour for 8 hours.

The the function to estimate the average age of employee of a company is A(s)=0.285s + 59  , then the average age of employee in 2003 is 65.27 and in 2009 is 66.98

To estimate the average age of an employee in 2003, we need to find the value of A(s) when s = 22  ;

because the number of years between 2003 and 1981 is = 22 years ;

So , A(22) = 0.285×22 + 59 = 65.27  ;

The average age of an employee in 2003 is approximately 65.27.

To estimate the average age of an employee in 2009,

we need to find the value of A(s) when s = 28

because the number of years between 2009 and 1981 is = 28 years ;

So , A(28) = 0.285×28 + 59 = 66.98  ;

The Average age of employee in 2009 is approximately 71.48.

The given question is incomplete , the complete question is

The function​ A(s) given by ​A(s)=0.285s + 59  can be used to estimate the average age of employee of a company in the year 1981 to 2009. Let​ A(s) be the average age of an​ employee, and "s" be the number of year since​ 1981; that​ is, s=0 for 1981 and s=9 for 1990. What is the average age of the employee in 2003 and in​ 2009 ?

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40°

Step-by-step explanation:

 ∠ACB = ∠DCE ( vertically opposite angle )

Now...

a + 90° + 50° = 180° ( the sum of interior angle of triangle is 180° )

a + 140° = 180°

a = 180° - 140°

a = 40°

hence the value of a is 40°

Answer:

C D F

Step-by-step explanation:

Taking -40/2, we know our answer must be -20.

Testing each answer choice proves this.

A= 40*1/2, which is equal to 40/2, which is 20.

B= -40*-1/2, again, equaling 20.

C= 40/-2. Since one of our terms is negative, this one is -20.

D= 40*-1/2, again, -20.

E= -1/40*2. This would equal -2/40, using fraction multiplication.

F= -40*1/2, Which is the exact same thing the original question asks.

Thus, our final answer is C, D, and F.

Answer:

100$

Step-by-step explanation:

he profit from 1 popcorn=0.85$

from 200=170$

170$-70$=100

Answer:

d. p - 15 = 49

Step-by-step explanation:

p = original price

The price was reduced by 15 dollars.

The new price is p - 15.

The new price is 49.

p - 15 = 49

Answer: d. p - 15 = 49

For the given parallelogram, the diagonals AC and BD intersect at point E. That means;

Substitute for the given values and we'll have;

Divide both sides by -3 and you'll have;

Note that line segment BD is made up of;

Therefore, the answer is option B

The required solution of the given expression 5y+9<+4 is y < -1.

Given that,
To determine the graph solution of expression 5y+9<+4.

Inequality can be defined as the relation of the equation containing the symbol of ( ≤, ≥, <, >) instead of the equal sign in an equation.

Here,
5y + 9 < +4
Simplifying,
5y + 9 < +4
Adding both sides by -9
5y < -5
divide both sides by 5
y < -1

Thus, the required solution of the given expression 5y+9<+4 is y < -1.

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Answer:

3%

Step-by-step explanation:

Apply distributive property as shown on all products-

All equations need to be distributed equally

x=3%

As shown, this should be what you do...

It's fine if you don't, but a little birdie said you should, just sayin'...

1300x+1200(x+0.02)=99

Rearrange

2500x+24=99

2500=75

\(75/100\\Properties\)

\(3/100\\Prioritized(mathematically)\)

When a thesis test is being performed for a population mean, the probability of a type II error isn't dependent on the sample mean. Option B is the right answer.

A type II error occurs when a null thesis isn't rejected despite it being incorrect. It's worth noting that the threat of making a type II error is affected by several factors, including the sample size, the true population mean, the position of significance, and the variability of the data.

As a result, the larger the sample size, the lower the threat of making a type IIerror.The true population mean also has an impact on the liability of a type II error. As the difference between the true mean and the hypothecated mean grows, the threat of a type II error decreases.

The position of significance is also pivotal in determining the threat of a type II error. As the significance position increases, the threat of a type II error decreases.

So, the correct answer is B

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When the null hypothesis is rejected in error it is a type II error. Hence the correct answer is A.

A Type II error occurs when the null hypothesis is incorrectly rejected. In other words, a Type II error happens when we fail to reject the null hypothesis even though it is actually false.

Option B refers to rejecting the research hypothesis in error, which is a Type I error. Type I error occurs when the null hypothesis is true, but we mistakenly reject it.

Option C refers to study underpower, which means the study lacks sufficient sample size or statistical power to detect a true effect if it exists. This is not directly related to Type II error.

Option D refers to study blinding, which is a method to minimize bias in research. However, it is not specifically related to Type II error.

Option E refers to accepting the research hypothesis in error, which is again a Type I error.

Therefore, the correct description of a Type II error is "A. The null hypothesis is rejected in error."

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Answer:

672 had dark hair, 592 had blond hair, and 48 had red hair

Step-by-step explanation:

To solve this problem, we need to first find the total number of people for each hair color based on the given ratio.

Let's start by finding the common factor that we can use to scale the ratio up to the total number of people, which is 1,312:

42 + 37 + 3 = 82

We can then divide 1,312 by 82 to get the scaling factor:

1,312 ÷ 82 = 16

This means that for every 16 people, there are 42 with dark hair, 37 with blond hair, and 3 with red hair.

To find the actual number of people with each hair color in the town meeting, we can multiply the scaling factor by the number of people for each hair color in the ratio:

Dark-haired people: 42 × 16 = 672

Blond-haired people: 37 × 16 = 592

Red-haired people: 3 × 16 = 48

Therefore, there are 672 people with dark hair, 592 people with blond hair, and 48 people with red hair at the town meeting.

43.9 + x = 49.65

Subtract 43.9 from both sides:

49.65 - 43.9 = 5.75

The missing number is 5

Answer:

1 × 2.4 = 2.4

10 × 2.4 = 24

100 × 2.4 = 240

1,000 × 2.4 =2400

Step-by-step explanation:

Answer:

1*2.4=2.4

10*2.4=24

100*2.4=240

1,000*2.4=2400

Step-by-step explanation:

You may see a pattern, as each answer is pushed up a digit from where it used to be. That is because the multiple is increased by 10, causing it to be that way.

Answer:

35/10000 or if you want it simplified 7/2000

Answer: 7/2000

Step-by-step explanation:

Step 1: Write down 0.0035 divided by 1:

0.0035/1

Step 2: Multiply both top and bottom by 10000 (because there are 4 digits after the decimal point so that is 10000

Step 3: Simplify the Fraction

FINAL ANSWER: 7/2000

~Hope this helped :)

Since ∠1 and ∠3 are vertical angles, they are congruent. Therefore, ∠1 is also 105°.

Angles have the same measure, so if we have information about the relationships between ∠1 and other angles (such as vertical angles, corresponding angles, alternate interior angles, etc.), we can determine the congruent angles.

There are two other angles that are congruent to ∠1. These are:

∠2, since they are alternate interior angles and the lines are parallel. Therefore, ∠2 is also 105°.

∠4, since they are corresponding angles and the lines are parallel. Therefore, ∠4 is also 105°.

So, the list of all angles congruent to ∠1 when ∠3 is 105° is:

∠1 = 105°

∠2 = 105°

∠4 = 105°

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Answer:

56 feet

Step-by-step explanation:

This is a trigonometry problem. It makes use of tangent. You can take the tangent of an angle and it will equal the side opposite divided by the side adjacent that isn't the hypotenuse.

In this case the angle is 35 degrees.

Tangent of the angle = opposite/ adjacent side

Tan(35) = (x)/(80)

Tan(35) = 0.7 so

(0.7)= (X)/(80)

Using algebra each side can be multiplied by 80.

(80)(.7)=X

56=x

X is in feet, so X is equal to 56 feet.

Hope this helps!

Answer:

If it is a conjunction that uses the word and, the solution must work in both inequalities and the solution is in the overlap region of the graph. If it is a disjunction that uses the word or, the solution must work in either one of the equations.

Step-by-step explanation:

1.

Original function

Left 3 units. Horizontal move is applied directly to the variable

Up 2 units. Vertical move is applied to whole function

reflect obout the y-axis, we change the sign of the variable, then

then right option is B

2.

then -f(x) is -y

then change the value of -y

So the point must be on the graph of -f(x) is

Then right option is D

Answer:

38feet 4.4 inches. .. ..........

Answer:

7.1

Step-by-step explanation: i took the quiz

Answer:

\({ \sf{ \sqrt{r} = \sqrt{(x {}^{2} + {y}^{2} ) } }}\)

Step-by-step explanation:

General equation:

\({ \bf{ {x}^{2} + {y}^{2} + 2ax + 2by + c = 0}} \\ \)

but a and b are 0:

\({ \bf{ {x}^{2} + {y}^{2} = {r}^{2} }} \\ { \bf{ \sqrt{ {x}^{2} + {y}^{2} } = \sqrt{r} }}\)

The probability of all 4 computers being good was 45.62%, the probability of 3 being good and 1 being defective was 4.58%, and the probability of 2 being good and 2 being defective was 2.29%.

1. The probability that all 4 are good is 90/100 x 89/99 x 88/98 x 87/97 = 0.4562, or 45.62%.

2. The probability that 3 are good and 1 is defective is 90/100 x 89/99 x 88/98 x 10/97 = 0.0458, or 4.58%.

3. The probability that 2 are good and 2 are defective is 90/100 x 89/99 x 10/98 x 10/97 = 0.0229, or 2.29%.

For the first problem, we can use the formula P(A) = n(A)/n(T), which is the probability of an event A occurring. In this case, P(A) = n(A)/n(T) = 4/100 = 0.04. This gives us the result of 0.4562, or 45.62%.

For the second problem, we use the same formula P(A) = n(A)/n(T), which is the probability of an event A occurring. In this case, P(A) = n(A)/n(T) = 3/100 = 0.03. This gives us the result of 0.0458, or 4.58%.

For the third problem, we use the same formula P(A) = n(A)/n(T), which is the probability of an event A occurring. In this case, P(A) = n(A)/n(T) = 2/100 = 0.02 ,then the probability of the next event, which is 89/99, then the probability of the next event, which is 10/98, then the probability of the last event, which is 10/97. This gives us the result of 0.0229, or 2.29%.

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The\(PH\) of the mixture of 0.100 M \(MNO\) and 0.100 M \(HCIO\)is approximately 2.66.

To find the pH of a mixture of two acids, to consider their dissociation constants (Kₐ) and the resulting concentrations of the hydronium ions (\(H3O\)⁺) in the solution.

Let's start with nitrous acid (\(HNO\)₂):

Kₐ for \(HNO\)₂ = 4.6×10²−4

Concentration of HNO₂ = 0.100 M

Assuming x is the concentration of \(H3O\)⁺ ions formed from the dissociation of \(HNO2\), we can set up an equilibrium expression for the dissociation of HNO₂ as follows:

\(KA\) = [\(H3O\)⁺][\(NO2\)⁻] / [\(HNO2\)]

Since nitrous acid is a weak acid, we can assume that the concentration of H₃O⁺ ions from the dissociation of HNO₂ is much smaller than the initial concentration of HNO₂. Thus, we can approximate [HNO₂] ≈ 0.100 M.

Now, let's consider hypochlorous acid :

Kₐ for \(HCIO\) = 3.0×10²−8

Concentration of \(HCIO\) = 0.100 M

Assuming y is the concentration of H₃O⁺ ions formed from the dissociation of \(HCIO\),  set up an equilibrium expression for the dissociation of as follows:

\(KA\) = [\(H3O\)⁺][\(CIO\)⁻] / [\(HCIO\)]

Since hypochlorous acid is a weak acid, approximate  ≈ 0.100 M.

The total concentration of \(H3O\)⁺ ions in the mixture is the sum of the concentrations from the dissociation of \(HNO2\) and \(HCIO\), so [H₃O⁺] = x + y.

To solve for x and y,  to consider the equilibrium expressions for both acids:

For \(HNO2\)₂:

\(KA\) = [\(H3O\)⁺][\(NO2\)⁻] / [\(HNO2\)]

4.6×10²−4 = x × [\(NO2\)⁻] / 0.100

For \(HCIO\):

\(KA\)= [\(H3O\)⁺][\(CIO\)⁻] / [\(HCIO\)]

3.0×10²−8 = y × [\(CIO\)⁻] / 0.100

Since both\(HNO2\)and \(HCIO\) dissociate independently, the concentrations of the respective anions are equal to the concentrations of the respective acids that dissociated. Thus, [\(NO2\)⁻] = x and [\(CIO\)⁻] = y.

Now, we can solve the equations simultaneously:

4.6×10²−4 = x ×x / 0.100

3.0×10²−8 = y × y / 0.100

Simplifying the equations:

4.6×10²−4 = x² / 0.100

3.0×10²−8 = y² / 0.100

Multiplying both sides by 0.100:

4.6×10²−5 = x²

3.0×10²−9 = y²

Taking the square root:

x ≈ 2.14×10²−3

y ≈ 5.48×10²−5

Since the concentration of ions in the mixture is the sum of x and y:

[\(H3O\)⁺] = 2.14×10²−3 + 5.48×10²−5 ≈ 2.20×10²−3

Finally,  calculate the  of the solution using the equation:

\(PH\) = -log[\(H3O\)⁺]

\(PH\)= -log(2.20×10²−3) ≈ 2.66

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