The sum total of all the energy of all the molecules in an object is called its
internal energy
When capillary effects, the effects of external magnetic, electric, and other fields are absent, a substance has internal energy, which is a property or state function in thermodynamics. Like any other state function, the value of the energy is determined by the state of the substance rather than the techniques used to get there. According to the first law of thermodynamics, work is equal to the change in internal energy when a system changes state as a result of a process in which only work is involved.
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help please I need this as quick as posible!!!
Momentum is exploited in many different sports and games. Write a brief essay on the uses of momentum collisions in a particular sport or game. Be sure to discuss the importance of mass and velocity in your example.
Increase in mass and velocity, increases the momentum of a rugby player and a player with more momentum will be difficult to stop and he be of advantage to his team.
Which sports uses momentum?Momentum is important in sport, particularly contact sports where collisions are involved. For example rugby, the more momentum a rugby player has the harder it is to stop him.
Momentum is defined as the product of mass and velocity.
P = mv
where;
m is mass of the playerv is the velocity of the playerP is the momentum of the playerThe massive a player is, the more momentum he will have and also the greater the velocity of the player, the more momentum the player will have.
Thus, increase in mass and velocity, increases the momentum of a rugby player and a player with more momentum will be difficult to stop and he be of advantage to his team.
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Why can't scientists see inside an atom?
Answer:
Because they don't have a telescope to magnify so close
Explanation:
Hope it works for you :)
Answer:
scientists can't see inside a atom because the atoms cant be seen by anything hope it help :)
Explanation:
Pressure waves cause fluid located in the cochlea to be set in motion, causing vibration in the _________, which in turn activates the auditory receptors.
In the air, pressure waves that propagate as sound. If the sound reaches the ear, it passes through the auditory tube, where it is amplified by the eardrum and ossicles. Finally, the organ of Corti in the cochlea detects these noises and transmits them to the brain via nerve impulses.
How Pressure affect cochlea.The fluid in the cochlea vibrates as a result of pressure waves traveling from the stapes to the oval window. Depending on the sound frequency, these vibrations move the thin basilar membrane that is connected to the organ of corti, activating the hair cell receptors. Additionally, sound first passes through the auditory tube from the outer ear to the tympanic membrane or eardrum. However, the middle ear, not the inner ear, is where the ossicles are found not of the oval window, but transfer vibrations to the oval window.
Ear structure?The various tissues and structures that make up the ears aid in the processing of sound that is heard in the environment. Learn about the inner and outer ear, eardrum, eustachian tube, cochlea, and semicircular canals as well as how they work.
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In a study of momentum during collisions, a student threw an egg at a large sheet of cloth that was suspended from a line and observed that the egg did not break during the collision. A second egg, thrown with similar force at a suspended concrete block, did break on impact. Why did the first egg survive the collision while the second egg did not survive?.
From the law of conservation of momentum, the first egg did not break because it forward momentum is transferred to the cloth while the second egg broke, the block exerts an opposite force equal to the momentum of the egg on the egg.
MomentumMomentum is the product of the mass of an object and its velocity of motion.
The law of conservation of momentum states that the momentum of an isolated system of colliding bodies is conserved.
When an egg is thrown on a large sheet of cloth suspended, the egg does not break because the momentum of the egg is transferred to the cloth as it is depressed.
However, a second egg, thrown with similar force at a suspended concrete block, did break on impact because the block does not move forward, instead it exerts an equal but opposite force on the egg resulting in the egg breaking.
Therefore, from the law of conservation of momentum, the first egg did not break because it forward momentum is transferred to the cloth while the second egg broke, the block exerts an opposite force equal to the momentum of the egg on the egg.
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Which energy conversion is taking place as the blades of the windmills rotate?
The energy conversion that is taking place as the blades of the windmills rotate is known as kinetic energy conversion.
Kinetic energy is the energy of motion and it is created when a body moves. In the case of windmills, the blades capture the energy of the wind, which is converted into mechanical energy and then into electricity.
When the blades of the windmill rotate, the wind passes through them and transfers its kinetic energy to the blades. This kinetic energy is then converted into rotational energy and is used to turn the rotor inside the windmill. The rotor is connected to a generator, which converts the rotational energy into electrical energy. This electricity is then used to power various electrical systems.
In summary, where the kinetic energy of the wind is converted into mechanical energy and then into electrical energy.
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Which type of waves give scientists information about the structure of Earth's interior layers?
Answer:
Seismic waves
Think of earthquakes :)
Draw a series circuit with a 12 v battery and a current of 2 amps and 3 light bulbs a drawing
The equivalent resistance in the given series circuit is 18 Ω.
Ohm's law, Which states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them.
To calculate the equivalent resistance in a series circuit, we can simply add up the resistance of each component in the circuit. In the given series circuit with a 12 V battery, a current of 2 amps, and 3 light bulbs, each having the same resistance, the equivalent resistance can be calculated as follows:
R_eq = R_1 + R_2 + R_3
Since each light bulb has the same resistance, we can represent the equivalent resistance as:
R_eq = 3 × R
where R is the resistance of each light bulb.
To find the value of R, we need to use Ohm's law, which states that the voltage drop across a resistor is directly proportional to the resistance of the resistor and the current flowing through it. In the given circuit, the voltage drop across each light bulb is 12 V (the voltage of the battery), and the current flowing through each light bulb is 2 A. Therefore, we can calculate the resistance of each light bulb as follows:
R = V / I
R = 12 V / 2 A
R = 6 Ω
Substituting this value of R in the equation for equivalent resistance, we get:
R_eq = 3 × 6 Ω
R_eq = 18 Ω
Therefore, the equivalent resistance in the given series circuit is 18 Ω.
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The figure below illustrates an Atwood's machine. Let the masses of blocks A and B be 4.00 kg and 2.00 kg, respectively, the moment of inertia of the wheel about its axis be 0.100 kg⋅m2 and the radius of the wheel be 0.500 m.
a) Find the linear acceleration of block A and block B if there is no slipping between the cord and the surface of the wheel
b) Find the tension in right side of the cord if there is no slipping between the cord and the surface of the wheel
c) Find the tension in left side of the cord if there is no slipping between the cord and the surface of the wheel.
a) To find the linear acceleration of block A and block B in the Atwood's machine, we can use the equations of motion and torque. Since there is no slipping between the cord and the surface of the wheel, the angular acceleration of the wheel can be related to the linear accelerations of the blocks.
Let's assume that block A is moving downwards and block B is moving upwards. The net force on block A is the tension in the left side of the cord (T_left) minus the weight of block A (m_A * g), and the net force on block B is the tension in the right side of the cord (T_right) minus the weight of block B (m_B * g). We can set up the equations of motion for both blocks:
For block A:
m_A * a_A = T_left - m_A * g (1)
For block B:
m_B * a_B = T_right - m_B * g (2)
The torque equation for the wheel is given by:
I * α = (T_right - T_left) * r (3)
Where I is the moment of inertia of the wheel, α is the angular acceleration of the wheel, and r is the radius of the wheel.
Since there is no slipping, the linear acceleration of both blocks is equal to the acceleration of the wheel, which can be expressed as r * α. Substituting this into equations (1) and (2), and substituting the expression for α in equation (3), we can solve for the linear accelerations:
For block A:
m_A * a_A = T_left - m_A * g
a_A = (T_left - m_A * g) / m_A (4)
For block B:
m_B * a_B = T_right - m_B * g
a_B = (T_right - m_B * g) / m_B (5)
From equation (3):
I * (a_A / r) = (T_right - T_left) * r
T_right - T_left = (I * a_A) / r^2 (6)
b) To find the tension in the right side of the cord (T_right), we can use equation (6) derived above. Rearranging the equation, we have:
T_right = T_left + (I * a_A) / r^2 (7)
Substitute the values of T_left, I, a_A, and r into equation (7) to calculate the tension in the right side of the cord.
c) Similarly, to find the tension in the left side of the cord (T_left), we can use equation (6) derived above. Rearranging the equation, we have:
T_left = T_right - (I * a_A) / r^2 (8)
Substitute the values of T_right, I, a_A, and r into equation (8) to calculate the tension in the left side of the cord.
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select all that apply. in response to a specific stimulus, autonomic reflex arcs can trigger to help maintain homeostasis.
Internal organs unconsciously react to environmental changes as a result of reflexes, particularly autonomic reflexes, which help control homeostasis.
Why are reflexes important to maintaining homeostasis?Remember from the first module the importance of homeostasis. Reflexes help the body recognize changes and respond appropriately in order to maintain homeostasis. Reflexes happen unconsciously and automatically for a reason. Can you imagine how your life would be if you had to be conscious of the temperature of the environment you had just entered and then make conscious adjustments to maintain your internal temperature within the normal range? To comprehend how reflexes function, we will examine the basic components of a reflex arc and how they interact to produce the desired effect.There are many different ways to classify reflexes, but for the purposes of this discussion, we'll focus on two of them: somatic reflexes, which regulate skeletal muscle, and autonomic reflexes, which regulate smooth muscle, cardiac muscle, glands, and other body parts.To Learn more About reflexes refer to:
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Light can be described in terms of wavelength, or as consisting of small packets of energy called? ions. photons. electrons. pulsars.
Light consisting of small packets of energy called photons
Even though light mostly behaves like a wave, it can also be claimed that it is composed of tiny energy packets called photons. Despite being light and thin, photons are always energetic. The energy of a photon changes with wavelength; longer wavelengths have less energy than shorter ones. Red photons, for instance, have lower energy than blue ones.
Scientists believed that electromagnetic radiation was only made up of waves up until about 1900. Then, Max Planck and others found that some metals and other materials release electrons when exposed to light while studying the photoelectric effect. They believed that more electrons would be released from the metal as brightness or intensity rose.
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If the hydrogen peroxide is heated to 60°C first, the catalase doesn't
work. why?
Answer:
The ideal temperature of catalase activity is 66.6 degrees Celsius, so a temperature between 60 degrees and 70 degrees should most likely release the most oxygen during the reaction.
Explanation:
A body is thrown upwards vertically with a velocity of 60m/s. Calculate it’s velocity the height attained after 3 seconds the maximum height attained
The velocity of the body will be 30.6 m/s.
The object's highest vertical point during its trajectory is at its maximum height. Before it reaches the highest point, the item is flying upward; once it reaches that point, it is falling.
The velocity of the body is 60 m/s when thrown vertically upwards.
The maximum height attained by the body after 3 seconds.
Then, the initial velocity of the body is :
u = 60 m/s
t = 3 seconds
Then, using the equation of motion:
v = u - gt , the negative sign indicates that the body is moving opposite to gravity.
Therefore,
v = 60 - (9.8)(3)
v = 60 - 29.4
v = 30.6 m/s
Hence, the final velocity of the body when thrown upwards before it comes to stop is 30.6 m/s.
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What is the variable unit for acceleration,gravity and height
Answer:
HLW ITS JESS BREGOLI
YOUR ANSWER IS HERE
At different points on Earth's surface, the free fall acceleration ranges from 9.764 m/s2 to 9.834 m/s2[2] depending on altitude and latitude, with a conventional standard value of exactly 9.80665 m/s2 (approximately 32.17405 ft/s2). Locations of significant variation from this value are known as gravity anomalies.
Explanation:
HOPE IT MAY HELP YOU !!
you charge a 2.0-cm-radius metal sphere with −13 nc of charge. at what distance from the surface of the sphere is there a force of 8.3 × 10−6 n on a charge of ?
To find the distance from the surface of the sphere where there is a force of 8.3 × 10−6 N on a charge, we can use Coulomb's Law:
F = kq₁q₂/r²
Where F is the force, k is Coulomb's constant (9.0 × 10⁹ N·m²/C²), q₁ and q₂ are the charges, and r is the distance between the charges.
The distance from the surface of the sphere where there is a force of 8.3 × 10⁻⁶ N on a charge q is 3.75 × 10⁷ m √(q).
We can rearrange the equation to solve for r:
r = √(kq₁q₂/F)
Plugging in the given values:
r = √((9.0 × 10⁹ N·m²/C²)(-13 × 10⁹ C)(q)/(8.3 × 10⁻⁶ N))
r = √((9.0 × 10⁹ N·m²/C²)(-13 × 10⁹ C)(q)/(8.3 × 10⁻⁶ N))
r = √((-1.17 × 10¹⁴ N·m²/C)(q)/(8.3 × 10⁻⁶ N))
r = √((-1.17 × 10¹⁴ N·m²/C)(q)/(8.3 × 10⁻⁶ N))
r = √((-1.17 × 10¹⁴ N·m²/C)(q)/(8.3 × 10⁻⁶ N))
r = √((-1.41 × 10²⁰ N·m²/C²)(q))
r = √((-1.41 × 10²⁰ N·m²/C²)(q))
r = 3.75 × 10⁷ m √(q)
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The sputnik one satellite orbiting earth mass equals 5.98×10 to the 24th power kilograms in a circle of radius 6.96×10 to the six power meters what was its orbital velocity
Answer:
7572 m/s
Explanation:
The force between two masses separated by a distance r is given as:
\(F=G\frac{m_1m_2}{r^2}\)
Where F is the attractive force between 2 masses, m1 and m2, r is the distance between the centres of the masses and G is the universal gravitation constant, which is \(6.674*10^-11 Nm^2/kg^2\)
The mass of the earth (\(m_1\)) is far greater than the mass of the sputnik (\(m_2\)). Therefore \(m_1m_2=m_1\). The mass of the sputnik is neglected, therefore:
\(F=G\frac{m_1}{r^2}=\frac{(6.674*10^{-11})(5.98*10^{24})}{(6.96*10^6)^2} = 8.2389N\)
But F is actually centripetal acceleration, a = v²/r
\(8.2389 = v^2 / 6.96*10^6\\v=7572m/s\)
Compare and contrast the eye and a camera. What parts of the camera correspond to the iris, the retina, and the cornea of the eye?
The eye and a camera share similarities in the way they capture images. However, they also differ in several ways such as the eye is capable of adjusting to different lighting conditions and focusing on objects at different distances, whereas a camera requires manual adjustments to achieve the same effects.
The iris in the eye corresponds to the aperture in a camera. The aperture controls the amount of light that enters the camera, just as the iris controls the amount of light that enters the eye. Both the iris and aperture can be adjusted to let in more or less light depending on the situation.
The retina in the eye corresponds to the image sensor in a camera. The retina converts the light that enters the eye into electrical signals that are sent to the brain, allowing us to see. Similarly, the image sensor in a camera converts the light that enters the camera into digital signals that are stored on memory cards.
The cornea in the eye corresponds to the camera lens. The cornea helps to focus light onto the retina, just as the lens of a camera helps to focus light onto the image sensor. Both the cornea and the camera lens can be adjusted to change the focus of the image.
Overall, while there are similarities between the eye and a camera, there are also several differences in the way they function. The eye is a complex organ that is capable of adjusting to different lighting conditions and focusing on objects at different distances, whereas a camera requires manual adjustments to achieve the same effects.
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what is meant by tyndall effect? in point wise with example.
Answer:
scattering of light
Explanation:
is the scattering of light as a light beam passes through a colloid. The individual suspension particles scatter and reflect light, making the beam visible. ...
A car of mass of 1200 kg is driven around a corner of a radius of 45m at 15 ms-1
.
(a) Calculate the acceleration of the car.
(b) Calculate the centripetal force acting on the car.
(c) Explain how the centripetal force is being produced.
Explanation:
w = v/r
= 15/ 45 = 1/3 rads-¹
a = w²r
= 1/9 • 45 = 5 ms-²
F = mv²/r
= 1200• 15• 15/45
= 6000N
The car, when rounding the curve, is pulled towards the center by the friction between it's wheels and the road.
which component acts a platform on which an application software runs.
Answer:
System software acts as a platform on which an application software program runs.
I need help with this
1)Hypothesis: what you expect
2)Aim:To determine
3) Apparatus/material
4)Variables
Controlled: Keep constant
Manipulated-Change this
Reporting -What you expect to change
5) Expected results
6) Limitations
7)Source of errors
8)Precaution
Answer:
Explanation
What exactly do you need? More context to this problem would help me in helping you!
What is the maximum instantaneous power dissipated by a 2.5 −hp pump connected to a 240−Vrms ac power source?
What is the maximum current passing through the pump?
The maximum current passing through the pump is approximately 11 amperes.
To find the maximum instantaneous power dissipated by a 2.5-hp pump connected to a 240-Vrms AC power source, follow these steps:
1. Convert the horsepower (hp) to watts (W): 1 hp is equal to 746 watts, so 2.5 hp × 746 W/hp = 1865 W.
2. Determine the maximum power: For an AC power source, the maximum power is √2 times the RMS power. So, the maximum power = 1865 W × √2 ≈ 2637.4 W.
The maximum instantaneous power dissipated by the pump is approximately 2637.4 watts.
To find the maximum current passing through the pump:
1. Use the formula: Power (P) = Voltage (V) × Current (I).
2. Rearrange the formula to solve for current: I = P / V.
3. Calculate the maximum current: I = 2637.4 W / 240 V ≈ 11 A.
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If you were in a high-speed spaceship traveling away from Earth at a speed close to that of light, you would measure your resting pulse to be
Answer:measurements: if frequency is doubled, time between flashes it cut in half
constant speed: yes because they will still be equally spaced
accelerated: no because they will not be equally space intervals
Explanation:
How wide is the central diffraction peak on a screen 2.40 m behind a 0.0328- mm -wide slit illuminated by 588- nm light
The width of the central diffraction peak is 0.0754 m.
What is central diffraction:
It is distance between the 1st order minima from the center of the screen on both sides of the center.
The first diffraction minimum from the center is given as:
y = L*λ / awhere
y is the location of first minimum diffraction.
Distance of screen from slit (L) = 2.40 m
Width of the slit (a) = 0.0328 mm = 0.0328 × 10⁻³ m
Wavelength of light (λ) = 588 nm = 588 × 10⁻⁹ m
Width of central diffraction peak is,
W = 2*y = (2* L*λ ) / aNow, plug in the values given and solve for width 'W'.
This gives,
W = 2 * 2.40 * 588 × 10⁻⁹ / ( 0.0328 × 10⁻³ )
W = 0.0860 m
Therefore,
The width of the central diffraction peak is 0.0754 m.
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Marking as brainliest last attempt
(ZOOM IN THE PHOTO)
write a paragraph about the topic : bullying in schools
Answer:
Bullying in the schools has negative effects on individual students and on the school climate as a whole. Bullying can cause long-term problems for both the victims of bullying and the bullies themselves. To explore the effects of bullying on adolescents, we will define bullying, identify the characteristics of bullies and victims, outline the extent and consequences of bullying, and present resources for further information and assistance.
Bullying is any behavior that is initiated by one or more students against a victim or victims that causes physical or psychological intimidation. Bullying behaviors can be classified as either direct (such as teasing, threatening, hitting, or stealing) or indirect (such as rumor spreading or social isolation). Boys typically employed direct methods of bullying, while girls tend to use in direct methods. Either way, behaviors must occur repeatedly overtime to be classified as bullying.
Characteristics of Bullies and Victims
There are specific behaviors that bullies tend to exhibit. The bullies often need to feel powerful and in control. They may feel no remorse when they inflict injury and suffering on others. Bullies tend to defy authority and are likely to break school rules. They seem to have little anxiety and appear to possess high self-esteem. Students who come from homes characterized by physical punishment tend to be more likely to exhibit these types of behaviors.
Victims also tend to exhibit specific characteristics. They are often anxious, insecure, cautious, and have low self-esteem. Victims tend to be socially isolated, and may lack social skills and friends. Because they tend to be weaker than their peers, either physically or socially, victims rarely retaliate against bullies. Students who have close ties with their parents/guardians or who have overprotective parents/guardians are more likely to be victimized by bullies.
Thermal insulators have _____.
A. high specific heat
B. high kinetic energy
C. lots of air pockets
D. low latent heat
E. strong molecular bonds
Answer:
The correct answer to the following question will be Option A (High specific heat).
Explanation:
A thermal or heat insulator has been used to help avoid heat from travelling from one location to the another.
Specific heat seems to be important unless you consider whether the temperature including its insulator becomes evolving. Whether it has a high specific heat, it will take more energy just to increase the temperature, as well as it can also allow somewhat when it happens to come to insulating material, and therefore heat transaction or energy transactions are often influenced by a temperature gradient.Other given choices are not related to the given scenario. So that Option A seems to be the right answer.
I used up all my tries for part a and I'm honestly stuck. I know it has something to do with the conservation of energy but I can't figure it out :(
a. Find d, the initial displacement of the spring-block system (in cm).
b. Find the speed of the block when it reaches the equilibrium position. (in m/s)
c. How fast is the block moving when it reaches a position 4.00 cm to the left of its equilibrium position?
d. Assuming friction not negligible, find the coefficient of kinetic friction between the block and the surface if the block-spring system compresses 0.300 cm from the equilibrium position before stopping and moving back to the right?
Using the equation of motion:
1/2mv^2 = 1/2kx^2
where
m is the mass of the block,
v is the velocity
x is the displacement from the equilibrium position
we can find the initial displacement, d.
b. To find the speed of the block when it reaches the equilibrium position, we can use the conservation of mechanical energy.The total mechanical energy of the system is the sum of the kinetic energy and potential energy.
Initial Potential energy = 1/2kd^2
Final kinetic energy = 1/2mv^2
so,
v=sqrt(2*(1/2kd^2))/m
c. The speed of the block when it reaches a position 4.00 cm to the left of its equilibrium position will be the same as when it reaches the equilibrium position. Because the speed will be at its maximum at the equilibrium position.d. To find the coefficient of kinetic friction between the block and the surface, we can use the work-energy theorem, which states that the work done on an object is equal to the change in kinetic energy of the object.Work done = change in kinetic energy
The work done by friction is equal to the force of friction multiplied by the distance over which the force acts.
Friction force = friction coefficient * normal force
Friction force = friction coefficient * m * g
work done = friction force * distance
By putting the value of friction force and work done we can find the coefficient of kinetic friction.
Hooke's Law
Hooke's Law states that the force (F) required to extend or compress a spring by some distance x is proportional to that distance. Mathematically, it is represented as F = kx, where k is the spring constant and is unique to the spring. This relationship is only valid for small displacements, and assumes that the spring is not stretched beyond its elastic limit.
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this si a 2 part question84) A shock absorber is designed to quickly damp out the oscillations that a car would otherwise make because it is suspended on springs. (a) Find the period of oscillation of a 1610-kg car that is suspended by springs that make an effective force constant of 5.75×104 N/m. (b) Find the damping constant b that will reduce the amplitude of oscillations of this car by a factor of 5.00 within a time equal to half the period of oscillation.
Given data
*The given mass of the car is m = 1610 kg
*The given effective force constant is k = 5.75 × 10^4 N/m
(a)
The formula for the period of oscillation of a 1610 kg car is given as
\(T=2\pi\sqrt[]{\frac{m}{k}}\)Substitute the known values in the above expression as
\(\begin{gathered} T=2\times3.14\times\sqrt[]{\frac{1610}{5.75\times10^4}} \\ =1.05\text{ s} \end{gathered}\)Hence, the time period of oscillation of a 1610 kg car is T = 1.05 s
(b)
As from the given data, the amplitude of the oscillation of the car decreases by a factor of 5.00. Then, the expression for the amplitude of the oscillation, and the damping constant (b) is calculated as
\(A=A_0e^{-\frac{bt}{2m}}\)Substitute the known values in the above expression as
\(\begin{gathered} \frac{A_0}{5.0}=A_0e^{-\frac{bt}{2m}} \\ bt=2m\ln (5.0)_{} \\ b(\frac{T}{2})=2m\ln (5.0) \\ b=\frac{4m\ln (5.0)}{T} \\ =\frac{4\times1610\times\ln (5.0)}{1.05} \\ =9871.2\text{ kg/s} \end{gathered}\)Hence, the damping constant is b = 9871.2 kg/s
A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110.0 m.
Determine the acceleration of the car.
Answer: a = 8.10 m/s^2
Explanation:
The car starts at rest, so:
V0= 0m/s
t= 5.21m/s
S = 110.0 m
Using one of the five uniformly accelerated motion formulas
S= V0t + 1/2 at^2
but V0 = 0 m/s
S = 1/2 at^2
a= 2S/ t^2
a = 2(110m)/ (5.21 s)^2
a = 8.10 m/s^2
What is the change in momentum of a 50. kg
woman goes from running at 8.0 m/s to 0.0
m/s?
Answer:
400 kg-m/s
Explanation:
Given that,
Mass of the woman, m = 50 kg
Initial velocity, u = 8 m/s
Final velocity, v = 0 m/s
We need to find the change in momentum of the woman. It can be given by :
\(\Delta p=m(v-u)\\\\=50\times (8-0)\\\\=400\ kg-m/s\)
So, the change in momentum is 400 kg-m/s.
say something random cuz i already answered my own question
Answer:
The experimental setup, with car 1 is at the top of a ramp and car 2 at the bottom of the ramp is explained below in details.
Explanation:
The meter pole should be located at the opening location of car second at the bottom of the ramp so that it regulates the portion of car second that will finish up the most distant away from the bottom of the ramp.
So, I think now you got your answer which is absolutely correct and it will help you.
Answer:
hello my good friend
Explanation: