the strongest reducing agents (oxidation reactions) are the strongest oxidizing agents (reducing reaction) are located where in the pt table

The incorrect statement regarding the reaction between aqueous solutions of aluminum nitrate, Al(NO3)3, and ammonium carbonate, (NH4)2CO3, which form a precipitate of aluminum carbonate, Al2(CO3)3 is If 0.5 mole of (NH4)2CO3 react with sufficient Al(NO3)3, 3 moles of Al2(CO3)3 will be formed. Option C.

A chemical equation is a description of the chemical reaction that takes place. It contains the formulae of the reactants and products separated by an arrow. The arrow indicates the direction of the reaction. The stoichiometric coefficients in the equation represent the number of moles of each substance involved in the reaction.

Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in a chemical reaction. It's important to keep in mind that the law of conservation of mass applies to chemical reactions. This means that the number of atoms of each element present in the reactants must equal the number of atoms of that element present in the products. Thus, stoichiometry plays a significant role in determining how much product is formed from a given amount of reactant and vice versa. Option C.

More on aqueous solutions: https://brainly.com/question/31271307

#SPJ11

So, from the cell notation:

Species oxidized: Mg(s)

Species reduced: Cu²⁺(aq)

Oxidizing agent: Cu²⁺(aq) (copper ions)

Reducing agent: Mg(s) (magnesium)

In the given cell notation: Mg(s)∣Mg²⁺(aq)∥Cu²⁺(aq)∣Cu(s)

The species on the left side of the double vertical line (∥) represents the anode, where oxidation occurs. The species on the right side represents the cathode, where reduction occurs.

Species oxidized: Mg(s) (the solid magnesium)

Species reduced: Cu²⁺(aq) (the aqueous copper ions)

Oxidizing agent: Cu²⁺(aq) (copper ions) - It accepts electrons from the magnesium, causing it to be reduced.

Reducing agent: Mg(s) (magnesium) - It loses electrons, causing it to be oxidized.

Learn more about Cell notation from the link given below.

https://brainly.com/question/26547891

#SPJ4

The value of ΔG at 298 K for a reaction mixture containing 1.9 atm N2, 1.6 atm H2, and 0.65 atm, the answer is (a) -3.86 × 10^3.

NH3 can be calculated using the equation:

ΔG = ΔG° + RT ln(Q)

where ΔG is the standard Gibbs free energy change, ΔG° is the standard Gibbs free energy change at standard conditions, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.

In this case, we are given ΔG° as -33.3 kJ/mol. To calculate Q, we need to use the partial pressures of the gases in the reaction mixture. The reaction stoichiometry tells us that the ratio of the partial pressures of N2, H2, and NH3 is 1:3:2. Therefore, we can write:

Q = (P(NH3))^2 / (P(N2) * P(H2)^3)

Plugging in the given values of P(N2) = 1.9 atm, P(H2) = 1.6 atm, and P(NH3) = 0.65 atm, we can calculate Q. Then, using the value of R = 8.314 J/(mol·K) and the temperature T = 298 K, we can substitute these values into the equation and solve for ΔG.

The calculated value of ΔG at 298 K for the given reaction mixture is approximately -3.86 × 10^3 J/mol. This value is equivalent to -3.86 kJ/mol. Therefore, the answer is (a) -3.86 × 10^3.

To learn more about Haber Process here brainly.com/question/30928282

#SPJ11

The joint in the human body which is similar to the chicken wing joint is elbow joint. There is some similarities in the arm joint movement of chicken and humans.

Joints are the connecting parts for bones. Thus two bones are connected by joints. The skeletal system is a web of different living tissues that gives the human body its structure and protects organs.

Additionally, it is where blood cells are created. Due to their similar evolutionary history as vertebrates, chicken wings are homologous to the upper limb of humans; that is, they share many of the same features.

In order to connect the shape of muscles, bones, and joints to their function, we can analyze a chicken wing. The structure, tissues and some movements of elbow joint of humans is similar to that of chicken wing joint.

To find more about joints, refer the link below:

https://brainly.com/question/15093622

#SPJ1

Answer:

170. g C₇H₅(NO₂)₃

General Formulas and Concepts:

Chemistry - Stoichiometry

Explanation:

Step 1: Define

RxN:   C₇H₈ (l) + 3HNO₃ (aq) → C₇H₅(NO₂)₃ (s) + 3H₂O (l)

Given:   69.0 g C₇H₈ (Toluene)

Step 2: Identify Conversions

Molar Mass of C - 12.01 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of C₇H₈ - 7(12.01) + 8(1.01) = 92.15 g/mol

Molar Mass of C₇H₅(NO₂)₃ - 7(12.01) + 5(1.01) + 3(14.01) + 6(16.00) = 227.15 g/mol

Step 3: Stoichiometry

\(69.0 \ g \ C_7H_8(\frac{1 \ mol \ C_7H_8}{92.15 \ g \ C_7H_8} )(\frac{1 \ mol \ C_7H_5(NO_2)_3}{1 \ mol \ C_7H_8} )(\frac{227.15 \ g \ C_7H_5(NO_2)_3}{1 \ mol \ C_7H_5(NO_2)_3} )\) = 170.085 g C₇H₅(NO₂)₃

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

170.085 g C₇H₅(NO₂)₃ ≈ 170. g C₇H₅(NO₂)₃

Answer:

True. Heating may convert some matter into another substance, but the Law of Conservation of Mass states that matter may not be destroyed.

Explanation:

the answer is C

we know that particles of gases are most loosely packed amongst the three state of matters and have tendency to occupy the maximum volume as the density of gases is minimum if we compare it with the density of solids and liquid.

When we decrease the volume of container, the particles of gas become important as the gas occupies more space or can say volume in the given (smaller) container.

The relative volume occupied by the gas increase on decreasing the volume of container.

To know more about gases:

brainly.com/question/1369730

#SPJ4

Answer:its c

Explanation:Oxidized: loses electrons...

Fe+2 gains electrons

C starts at +2, and ends at +4, it lost 2 electrons.

O starts at -2, ends at -2

215 grams of AlCl₃ is equal to 1,61 moles of AlCl₃. The relative molecular mass of the compound AlCl₃ is 133.5 grams/mol.

The mole is one of the basic units used to indicate the amount of substance in the international system of units. The equation for calculating moles is mol = mass / relative atomic mass. To find out the mol of AlCl₃ you can use the following steps

Step 1: Calculate the relative molecular mass for the compound AlCl₃.

Mr AlCl₃ = ( Ar Al × ∑Al ) + ( Ar Cl × ∑Cl)

              = ( 27 gam/mol × 1) + ( 35,5 gram/mol × 3)

              = 27 gram/mol + 106,5 gram/mol

             = 133,5 grams/mol

Step 2: Calculate the moles of the compound AlCl₃.

n AlCl₃ = mass AlCl₃ ÷ relative molecular mass AlCl₃

            = 215 grams ÷ 133,5 grams/mol

            = 1,61 mol

Learn more about relative molecular mass here: https://brainly.com/question/28128443

#SPJ1

The picture that correctly shows the path of the reflected light ray is: Picture A.

A ray diagram can be defined as the graphical representation of the possible paths that a light wave takes from one point (source) to another.

Basically, some of the phenomenon and properties associated with light ray include the following:

A reflected light ray completely bounces off a surface and as such, light wave do not pass through the surface as illustrated in Picture A.

Read more on reflected light here: https://brainly.com/question/14320820

A) To determine the atomic number of the metal that crystallizes in a body-centered cubic arrangement, we can use the formula:

Density = (2 * Atomic Mass) / (a^3 * Avogadro's Number)

where 'a' is the edge length of the cubic unit cell.

Given that the density is 0.9710 g/cm^3 and the atomic radius is 185.5 pm (1 pm = 10^-12 m), we can find the edge length 'a' using the relationship:

a = 4 * r / sqrt(3)

where 'r' is the atomic radius.

Substituting the given values, we find:

a = (4 * 185.5 pm) / sqrt(3) = 339.83 pm

Next, we can calculate the atomic mass:

Density = (2 * Atomic Mass) / (a^3 * Avogadro's Number)

Solving for the atomic mass:

Atomic Mass = (Density * a^3 * Avogadro's Number) / 2

Substituting the values:

Atomic Mass = (0.9710 g/cm^3 * (339.83 pm)^3 * 6.022 x 10^23) / 2 = 94.9 g/mol

The atomic number of the element can be determined by looking up the element with the closest atomic mass value of 94.9 g/mol, which is Technetium (Tc) with an atomic number of 43.

B) To calculate the density of Cesium (Cs), we can use a similar approach as in part A.

Given that the atomic radius is 267.2 pm, we can find the edge length 'a' of the body-centered cubic (BCC) unit cell:

a = 4 * r / sqrt(3) = (4 * 267.2 pm) / sqrt(3) = 489.75 pm

Next, we can calculate the density:

Density = (2 * Atomic Mass) / (a^3 * Avogadro's Number)

Solving for the density:

Density = (2 * Atomic Mass) / (489.75 pm)^3 * 6.022 x 10^23) = 1.93 g/cm^3

Therefore, the density of Cesium (Cs) is approximately 1.93 g/cm^3.

C) To find the radius of one atom of lead (Pb), we can use the relationship between density, atomic mass, and atomic radius.

Given that the density is 11.35 g/cm^3, we can calculate the molar volume:

Molar Volume = Atomic Mass / Density

Solving for the atomic mass:

Atomic Mass = Molar Volume * Density

Molar Volume can be calculated using the formula for the volume of a face-centered cubic (FCC) structure:

Molar Volume = (4 * Atomic Radius^3) / (3 * sqrt(2))

Substituting the values:

11.35 g/cm^3 = (4 * (Atomic Radius)^3) / (3 * sqrt(2)) * (10^-12 m)^3 * 6.022 x 10^23

Simplifying the equation and solving for the atomic radius:

Atomic Radius = (11.35 g/cm^3 * 3 * sqrt(2) / (4 * 6.022 x 10^23))^1/3 * (10^12 pm) = 175.8 pm

Therefore, the radius of one atom of lead (Pb) is approximately 175.8 pm.

Learn more about atomic number here:

https://brainly.com/question/16858932

#SPJ11

Answer:

376.56

Explanation:

using the formula q=mcΔT, where m=15g, C=4.18J/g°C and ΔT=6.0°C

The reaction energy (Q) for the reaction p + 3.1H → 2.1H + 2.1H is approximately 17.33 megaelectron volts (MeV).

To calculate the reaction energy, we need to determine the mass difference between the reactants and products and convert it into energy using Einstein's mass-energy equivalence equation (E = mc^2).

The atomic masses of the particles involved are as follows:

p (proton) = 1.007276 amu (atomic mass unit)

H (hydrogen) = 1.007825 amu

Given the reaction:

p + 3.1H → 2.1H + 2.1H

Reactant mass:

1 p + 3.1 H = 1.007276 amu + (3.1 × 1.007825 amu)

= 1.007276 amu + 3.1287 amu

= 4.135976 amu

Product mass:

2.1 H + 2.1 H = (2.1 × 1.007825 amu) + (2.1 × 1.007825 amu)

= 4.2169265 amu + 4.2169265 amu

= 8.433853 amu

Mass difference (Δm):

Δm = (product mass) - (reactant mass)

= 8.433853 amu - 4.135976 amu

= 4.297877 amu

Converting amu to kilograms:

1 amu = 1.66053906660 × 10^-27 kg

4.297877 amu = 4.297877 × 1.66053906660 × 10^-27 kg

= 7.13790964751 × 10^-27 kg

Converting mass difference to energy:

E = Δmc^2

= (7.13790964751 × 10^-27 kg) × (3.0 × 10^8 m/s)^2

= 6.42511868276 × 10^-11 J

Converting energy to megaelectron volts (MeV):

1 MeV = 1.60218 × 10^-13 J

Q = (6.42511868276 × 10^-11 J) / (1.60218 × 10^-13 J/MeV)

≈ 17.33 MeV

The reaction energy (Q) for the reaction p + 3.1H → 2.1H + 2.1H is approximately 17.33 megaelectron volts (MeV). This calculation is based on the mass difference between the reactants and products, using Einstein's mass-energy equivalence equation. The reaction releases energy in the form of MeV, indicating an exothermic process where the products have a lower mass than the reactants.

To know more about energy ,visit:

https://brainly.com/question/13881533

#SPJ11

Answer:

Ba, Ca, Mn, Ni

Explanation:

Each solution has a concentration of 7.625 x 103 m, 3.8125 x 104 m, and 1.90625 x 105 m, respectively.

Dilution is the process of lowering a sample's concentration by incorporating more solvent, according to its definition. The following is the dilution formula.

C₁V₁ = C₂V₂

where C1 is the sample's initial concentration.

V1 is the initial sample volume.

After dilution, the ultimate concentration is C2.

After dilution, the ultimate total volume is V2.

Calculate the concentration of the diluted solution by entering the numbers into the formula.

first common answer

C₁V₁ = C₂V₂

0. 1525 m(5.00 ml) = C₂(100.0 ml) (100.0 ml)

C₂ = 7.625 x 10⁻³ m

Second common solution

C₁V₁ = C₂V₂

7.625 x 10⁻³ m(5.00 ml) = C₂ (100.0 ml)

C₂ = 3.8125 x 10⁻⁴ m

Third accepted option

C₁V₁ = C₂V₂

3.8125 x 10⁻⁴ m(5.00 ml) = C₂(100.0 ml) (100.0 ml)

C₂ = 1.90625 x 10⁻⁵ m

To learn more about dilution Visit:

brainly.com/question/1615979

#SPJ4

Answer:

20 liters of 50% solution and 80 liters of 25% solution

Explanation:

Let x litres be the amount of 50% solution to be used.

Since the amount of 25% solution used is 20 liters less than 5 times the amount of 50% solution used, then the 25% solution would be (5x -20) litres.

Therefore, 50x + 25(5x-20) = 30(x + 5x-20)

50x + 125x - 500 = 30x + 150x - 6 00

175x - 500 = 180x - 600

Collecting like terms

180x - 175x = 600 - 500

5x = 100

x = 20

Therefore, volume of 50% solution needed = 20 litres

Volume of 25% solution needed = (5 * 20) - 20 = 80 litres

20 liters of 50% solution and 80 liters of 25% solution

Answer:

1. mercury.

2. suspensions.

3.iodine is the solute and alcohol is the solvent.

4. A element.

If the stock ampicillin solution is 10 mg/mL, the stock solution should be added to 50 mL of lb broth for a final concentration of 100 ug/mL ampicillin would be 0.505 mL

When making experimental solutions, a volume of a stock solution with a certain concentration is added to the diluted solution to increase its concentration. This following formula can be used to determine the stock solution's volume:

                                    Cstock x Vstock = Cfinal x Vfinal

Take note that the value Vfinal represents the total volume of the solution (the volume of the stock plus the volume of the medium for bacterial growth).

Thus, the stock solution should be added would be:

(10 mg/mL) x (X) = (0.1 mg/mL) x (50 mL + X)

X = 0.505 mL ampicillin stock solution

To learn more about dilute solution, click here:

https://brainly.com/question/16926361

#SPJ4

Answer:

dont know sorry

Explanation:

i dont get it

Answer:Does alcohol really burn off when cooking? what are the possible substitutions for alcohol in recipes?

Explanation:

The longer you cook, the more alcohol cooks out, but you have to cook food for about 3 hours to fully erase all traces of alcohol. A study from the U.S. Department of Agriculture's Nutrient Data lab confirmed this and added that food baked or simmered in alcohol for 15 minutes still retains 40 percent of the alcohol.

Answer:

B.  George Washington

Explanation:

On April 30, 1789, George Washington, standing on the balcony of Federal Hall on Wall Street in New York, took his oath of office as the first President of the United States

hope it helps

#carry on learning

Answer:

The answers are B and D

The transformation you described involves the reaction of TsCl (p-toluenesulfonyl chloride) with pyridine in the presence of CF3COOH (trifluoroacetic acid) to form CF3COONa (sodium trifluoroacetate) and the desired products.

Here is a proposed curved-arrow mechanism for this transformation:

Step 1: Activation of TsCl

TsCl reacts with pyridine to form a sulfonium ion intermediate.

markdown

Copy code

    TsCl + pyridine ⟶ Ts+ + Cl- + pyridine

Step 2: Nucleophilic attack by CF3COOH

The activated Ts+ intermediate undergoes nucleophilic attack by CF3COOH.

objectivec

Copy code

    Ts+ + CF3COOH ⟶ Ts-CF3COOH

Step 3: Rearrangement and elimination

The Ts-CF3COOH intermediate rearranges to form an anhydride intermediate, followed by elimination of HCl to generate the desired product.

objectivec

Copy code

    Ts-CF3COOH ⟶ CF3COOTs + HCl

Step 4: Formation of sodium trifluoroacetate

The product CF3COOTs reacts with sodium hydroxide (NaOH) to form the final product, CF3COONa.

objectivec

Copy code

    CF3COOTs + NaOH ⟶ CF3COONa + TsOH

Overall, the complete curved-arrow mechanism for the transformation is as follows:

objectivec

Copy code

    TsCl + pyridine ⟶ Ts+ + Cl- + pyridine

    Ts+ + CF3COOH ⟶ Ts-CF3COOH

    Ts-CF3COOH ⟶ CF3COOTs + HCl

    CF3COOTs + NaOH ⟶ CF3COONa + TsOH

Please note that this mechanism is proposed based on the given reactants and products, and additional experimental conditions or factors may influence the reaction pathway.

know more about pyridine here

https://brainly.com/question/28250277#

#SPJ11

Answer:

a state of matter created when particles, called bosons, are cooled to near absolute zero (-273.15 degrees Celsius, or -460 degrees Fahrenheit).

Explanation:

hope this helps

pls mark brainliest

The fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

Fugacity is a measure of the escaping tendency of a component in a mixture, which is defined as the pressure that the component would have if it obeyed ideal gas laws. It is used as a correction factor in the calculation of equilibrium constants and thermodynamic properties such as chemical potential. Here we need to determine the fugacity in atm for pure ethane at 310 K and 20.4 atm and the change in the chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm. So, using the formula of fugacity: f = P.exp(Δu/RT) Where P is the pressure of the system, R is the gas constant, T is the temperature of the system, Δu is the change in chemical potential of the system.  Δu = RT ln (f / P)The chemical potential at the initial state can be calculated using the ideal gas equation as: PV = nRT    

=>  P

= nRT/V

=> 20.4 atm

= nRT/V

=> n/V

= 20.4/RT The chemical potential of the system at the initial state is:

Δu1 = RT ln (f/P)

= RT ln (f/20.4) Also, we know that for a pure substance,

Δu = Δg. So,

Δg1 = Δu1 The change in pressure is 24 atm – 20.4 atm

= 3.6 atm At the second state, the pressure is 24 atm.

Using the ideal gas equation, n/V = 24/RT The chemical potential of the system at the second state is: Δu2 = RT ln (f/24) = RT ln (f/24) The change in chemical potential is Δu2 – Δu1 The change in chemical potential is

Δu2 – Δu1 = RT ln (f/24) – RT ln (f/20.4)

= RT ln [(f/24)/(f/20.4)]

= RT ln (20.4/24)

= - 0.0911 RT Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is:

f = P.exp(Δu/RT)

=> f

= 20.4 exp (-Δu1/RT)

=> f

= 20.4 exp (-Δg1/RT) And, the change in the chemical potential between this state and a second state of ethane where the temperature is constant but pressure is 24 atm is -0.0911RT. Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

To know more about chemical potential visit:-

https://brainly.com/question/31100203

#SPJ11

Explanation:

P1V1 = P2V2

(100.7 kPa)(0.75 L) = (99.8 kPa)V2

V2 = (100.7 kPa)(0.75 L)/(99.8 kPa)

= 0.757 L

Answer:

Explanation:

Cu(s) + 2Ag+  ======> Cu^(2+) + Ag(s)

Notice what happened. Silver started out as an ion. It took on 2 electrons that were donated by the copper.

The silver then became a solid ppte. This equation wil take on much more meaning when you take up oxidation and reduction. Until then, you need only know who gave up elections and who took them up.