The speed of the sports car is 23.02 ft/s. To calculate the speed of the sports car, we need to use the formula:
v = √(rho * g * sin(theta))
where v is the speed of the car, rho is the radius of curvature, g is the acceleration due to gravity (which is approximately 32.2 ft/\(s^2\)), and theta is the angle of elevation of the car's wheels relative to the horizontal.
The angle of elevation can be found using the following formula:
theta = arctan(v / √(rho² + h²))
where h is the height of the car above the ground.
Substituting the given values, we get:
v = √(500² * 32.2 / sin(30))
v = 23.02 ft/s
Therefore, the speed of the sports car is 23.02 ft/s.
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Full Question ;
The sport car is traveling along a 30∘ banked road having a radius of curvature of P = 150 m. If the coefficient of static friction between the tire and the road is μs=0.2, determine the maximum safe speed so no slipping occurs. neglect the size of the car.
Which describes refraction?
the reflection of light as it passes through a substance
the focusing of light as it passes through a substance
the emission of light as it passes through a substance
the bending of light as it passes through a substance
Answer:
A
Explanation:
Image result for Which describes refraction? the reflection of light as it passes through a substance the focusing of light as it passes through a substance the emission of light as it passes through a substance the bending of light as it passes through a substance
When electromagnetic radiation, in the form of visible light, travels from one substance or medium into another, the light waves may undergo a phenomenon known as refraction, which is manifested by a bending or change in direction of the light.
help asap please, hope you can read it
Answer:
Wire length, current value, and potential difference certainly belong to the continuous category.
Perhaps, eye color would be the 4'th value because of the continuity involved
the maximum force a thin string can support without breaking is 50n. a 3kg mass is suspended from the string. the largest acceleration that can be given to the mass without breaking the string is most nearly
The largest acceleration that can be given to the mass without breaking the string is most nearly 6.86 m/s².
To determine the largest acceleration for the 3kg mass suspended by the thin string without breaking it, you need to consider the maximum force the string can support, which is 50N. Start by calculating the gravitational force acting on the mass (weight) using the formula F = mg, where F is the force, m is the mass (3kg), and g is the acceleration due to gravity (approximately 9.81 m/s²).
F = 3kg × 9.81 m/s² ≈ 29.43N
Since the string can support a maximum force of 50N, subtract the gravitational force to find the additional force it can handle without breaking:
50N - 29.43N ≈ 20.57N
Now, calculate the largest acceleration using Newton's second law, F = ma, where F is the additional force, m is the mass (3kg), and a is the acceleration:
20.57N = 3kg × a
Solve for a:
a ≈ 20.57N / 3kg ≈ 6.86 m/s
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B. Period
A. Frequency
2. Which of the following is the speed of a wave traveling with a wavelength A, frequency f, and period Ta
A.v=
B.V=
C. v = A'f
D.V=fT
E.v=4
Which of the following statements is true about transverse waves?
The, speed of the wave is A'f.
The number of complete oscillations made by a wave during a time interval of one second is defined as the frequency of the wave.
The time period of a wave is the time taken by a wave to complete one oscillation. It is the reciprocal of frequency of the wave.
The expression for speed of the wave is given by,
v = fλ
where f is the frequency and λ is the wavelength of the wave.
Here, the wavelength of the wave, λ = A'
Therefore, speed of the wave,
v = A'f
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which products rely on the ability of ionic compounds to conduct electricity? check all that apply.
1. papers
2. cell phones
3. soaps
4. glazed pottery
5. remote control toys
In recent years it has been possible to buy a 1. 0 F capacitor. This is an enormously large amount of capacitance. Suppose you want to build a 1. 1 Hz oscillator with a 1. 0 F capacitor. You have a spool of 0. 25-mm-diameter wire and a 4. 0-cm-diameter plastic cylinder.
How long must your inductor be if you wrap it with 2 layers of closely spaced turns?
An oscillator is an electronic device that produces an electrical signal at a specific frequency. A capacitor is an electrical component that stores electrical energy. In recent years, it has become possible to purchase a 1.0 F capacitor. This is an incredibly large amount of capacitance.
Suppose you want to build a 1.1 Hz oscillator using a 1.0 F capacitor and a spool of 0.25-mm-diameter wire and a 4.0-cm-diameter plastic cylinder. We can calculate the required inductance value using the formula:f = 1/2π√(L*C)Where f is the desired frequency, L is the inductance value, and C is the capacitance value. Substituting the given values:
\(f = 1.1 HzC = 1.0 F\)
Plugging these values into the formula and solving for L:
1.1 Hz = 1/2π√(L*1.0 F)2π*1.1 Hz = √(L*1.0 F)6.88 Hz2 = L*1.0 F6.88 H/ F = LL = 6.88 H
\(1.1 Hz = 1/2π√(L*1.0 F)2π*1.1 Hz = √(L*1.0 F)6.88 Hz2 = L*1.0 F6.88 H/ F = LL = 6.88 H\)We need to wrap this inductance value with two layers of closely spaced turns around the plastic cylinder.
The inner diameter of the cylinder is equal to the diameter of the wire, which is 0.25 mm or 0.00025 m. Therefore:d = 0.00025 mThe outer diameter of the cylinder is 4.0 cm or 0.04 m. Therefore:D = 0.04 mPlugging these values into the formula for A:
\(A = (π/4)(0.04² - 0.00025²)A = 0.001257 m²\)
Plugging these values into the formula for L:
\(L = µn²A/lSolving for l:l = µn²A/L\)
Plugging in the given values:
\(µ = 4π x 10^-7 H/mn = 2\)
(since we want two layers)
\(A = 0.001257 m²L = 6.88 Hl = (4π x 10^-7 H/m)(2²)(0.001257 m²)/(6.88 H)l ≈ 0.0015 m\) or 1.5 mm
Therefore, the length of the inductor should be approximately 1.5 mm.
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This is the question
Answer:
B
Explanation:
If opposing forces acting on an object are equal, the net force is
N. (Enter your answer in the numerical form)
help me please
Answer:
0 N
Explanation:
suppose, you push a box with 5 N, and another person pushes the box on the opposite side of the box with 5 N, the net force (resultant ) is 0 N, the box will not move if it wasn't moving
hope this helps
a ball is thrown vertically upward with a velocity of 20m/s from the top of a multistory building. the height of the point where the ball is thrown is 25 m from the ground. then find a. how height will the ball rise?
B how long will it be before the ball hip the ground?
A ball is thrown vertically upward with a velocity of 20m/s from the top of a multistory building. The height of the point where the ball is thrown is 25 m from the ground. The height will the ball rise is 20m. 5s long will it be before the ball hip the ground.
What is velocity ?The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.
A. for solving how high will ball go , velocity at the top point will be 0 this gives ,
s = v² - u² / 2a
= 0 - 20² / -2 × 10
= 20m
B. Time to reach maximum height can be obtained from v = u + at
0 = 20 + ( − 10 ) t
t = 2s
s = ut + 0.5at²
= 20 ( 2 ) + 0.5 ( −10 ) ( 2 )²
= 20m
Therefore, the total distance for maximum height is 45 m
s = ut + 0.5at²
45 = 0 + 0.5 ( 10 ) ( t )²
t = 3s
Then,
Total time = 3+2
= 5s
Thus, A ball is thrown vertically upward with a velocity of 20m/s from the top of a multistory building.The height will the ball rise is 20m. 5s long will it be before the ball hip the ground.
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A skier starts from rest at the top of a 45.0 m hill, coasts down a 30 slope into a valley and continues up to the top of a 40.0 m hill. Both
hill heights are measured from the valley floor. Assume the skier puts no effort into the motion (they simply coast) and there is no friction.
How fast will the skier be moving on the top of the 40.0 m hill?
Round your answer to the nearest hundredth.
The speed at the bottom of the valley is 29.7 m/s. The speed at the top of the second hill is 9.9 m/s. The results are independent of the angle of the hills.
What is speed?Speed of an object can be defined as the total distance covered in a given period of time. It is a scalar quantity because it has only the magnitude and no direction. The SI unit of speed is meter per second (m/s).
Since, there is no frictional force involved we can apply the law of conservation of energy, and the total mechanical energy of a system remains conserved under the action of conservative forces like the gravitational forces.
Total energy = KE + PE
where, KE is Kinetic Energy and PE is Potential Energy
At the top of the hill, KE will be 0 since the skier is at rest, so all the energy is potential energy:
PE = mgh
where,
m is the mass of the skier
g is the acceleration of gravity
h = 45.0 m is the height of the hill
At the bottom, there is only the kinetic energy:
KE = 1/2 mv²
where, v is the speed of the skier at the bottom of the hill
Since the total energy is conserved, then:
KE = PE
1/2 mv² = mgh
v = \(\sqrt{mgh}\)
v = \(\sqrt{2gh\\}\)
v = \(\sqrt{(2)(9.8)(45)}\)
v = 29.7 m/s
The height of the second hill is h' = 40.0 m
Applying the conservation of energy, the kinetic energy at the bottom will be converted to potential energy and remaining kinetic energy for the second hill:
let the speed of the skier at the top of second hill be v', then
1/2 mv² = mgh' + 1/2 mv'²
mgh = mgh' + 1/2 mv'²
v' = \(\sqrt{2g(h-h')}\)
v = \(\sqrt{(2)(9.8)(45-40)}\)
v = 9.8 m/s
We can clearly see in the above results that the results are independent of the angle of the hills.
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Your question is incomplete, most probably the complete question is:
A skier starts from rest at the top of a 45.0-m-high hill, skis down a 30° incline into a valley, and continues up a 40.0-m-high hill. The heights of both hills are measured from the valley floor. Assume that you can neglect friction and the effect of the ski poles. How fast is the skier moving at the bottom of the valley? What is the skier’s speed at the top of the next hill? Do the angles of the hills affect your answers?
1 A. Graph the data below for a bicycle ride.
B. Use the graph to determine how far the biker has traveled at 12 minutes.
Answer:
A: i cant show the graph i did
B: The biker would have gone 3.6 km in 12 minuets
Explanation:
What is the answer? I am trying to do some exercise
Answer:
fourth quadrant.
Explanation:
First, let us see how many 2 pi radians are there in 40 pi /7. The answer is found by dividing 40 pi / 7 by 2 pi
\(\frac{40\pi}{7}\div2\pi=\frac{40\pi}{7}\times\frac{1}{2\pi}\)\(=\frac{40\pi}{7}\times\frac{1}{2\pi}=\frac{20}{7}=2R6\)Meaning ( 40 pi / 7 ) / ( 2pi ) = 2 Remainder 6
Meaning there are 2 complete revolutions in ( 40 pi / 7 ).
How about the revolution that is incomplete?
Now,
\(\frac{40\pi}{7}-2(2\pi)=\frac{40}{7}\pi-4\pi\)\(=\frac{12}{7}\pi\)\(=1.71\pi\)Which if we plot, looks like
Meaning that 40 pi / 7 lies in the fourth quadrant.
When you drop a penny off the roof of a building, it takes 16 seconds to reach
the ground. How high is the roof?
Answer:
Explanation:
I'll do this in both meters and feet, since you don't specify which you need. Since we are only dealing in the y-dimension:
Δx = ???
a = -9.8 m/s/s
v₀ = 0
t = 16 sec
In the equation:
Δx = v₀t + \(\frac{1}{2}at^2\) we fill in accordingly:
Δx = \(0(16)+\frac{1}{2}(-9.8)(16)^2\) which simplifies to
Δx = \(\frac{1}{2}(-9.8)(256)\) so
Δx = -1300 m. Now in feet, it's the same equation but the acceleration is -32 ft/s/s:
Δx = \(\frac{1}{2}(-32)(256)\) which is
Δx = -4100 ft (the negative signs here just indicate direction: the penny is this distance below the point from which it was dropped. So, obviously, to answer the question regarding the height of the building, you would say it was 1300 m high or 4100 feet high. The negative would be significant if we were asked instead "How far did the penny fall?" which would be the same answer to a slightly different question.)
A swimmer is moving at a speed of 2.0 meters per second. How long will it take for the swimmer to go 100 meters?
A) 20 seconds
B) 50 seconds
C) 100 seconds
D) 200 seconds
The swimmer will take 50 seconds to go 100 meters. So, the correct answer is B) 50 seconds.
To determine how long it will take for a swimmer moving at a speed of 2.0 meters per second to go 100 meters, you can use the formula time = distance/speed.
1: Identify the given values - distance (100 meters) and speed (2.0 meters per second).
2: Use the formula time = distance/speed to find the time it takes to cover 100 meters.
3: Plug in the values: time = 100 meters / 2.0 meters per second.
4: Calculate the time: time = 50 seconds.
So, B is the correct option.
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If a single lens forms a virtual image, we can conclude that:.
If a single lens forms a virtual image, we can conclude that:
The lens being used is a diverging lens, and the object is placed within the focal length of the lens.
In this situation, light rays diverge after passing through the lens, making it impossible for them to converge at a single point on the other side of the lens.
As a result, the image appears to originate from a point behind the lens, creating a virtual image.
The virtual image produced is upright and magnified, meaning it appears larger than the original object.
Since the image is not formed by the actual convergence of light rays, it cannot be projected onto a screen, and can only be observed by looking through the lens.
In summary, when a single lens forms a virtual image, we can conclude that the lens is diverging, the object is placed within the lens's focal length, and the resulting image is upright, magnified, and cannot be projected onto a screen.
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This fossil snake and this living rat both have a structure in their skull called the quadrate bone. What best explains why both species have a quadrate bone?
The snake and rat both share the same ancestor population that had a quadrate bone, which was inherited from an ancestor population.
What is a homo-logous structure?A homo-logous structure is a trait that may or not have the same function but has a common evolutionary origin.
A homo-logous structure can be used to trace the evolutionary relationships between species.
Conversely, an analogous structure has the same function but it does not reflect an evolutionary origin.
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What is the deceleration of a truck that takes 8.5 seconds to decrease its velocity from 35 m/s to 5 m/s?
Answer:
It will decelerate at the rate of \(3.52\ m/s^2\).
Explanation:
Initial speed of the truck, u = 35 m/s
Final speed, v = 5 m/s
Time, t = 8.5 s
We need to find the deceleration of the truck. As the speed is becoming less, it means it will decelerate. It can be calculated as follows :
\(a=\dfrac{v-u}{t}\\\\a=\dfrac{5-35}{8.5}\\\\a=-3.52\ m/s^2\)
So, it will decelerate at the rate of \(3.52\ m/s^2\).
4.10n is applied to accelerate a 1.80kg box from rest to 3.90m/s. how long does it take? a force of 4.10n is applied to accelerate a 1.80kg box from rest to 3.90m/s. how long does it take
It takes approximately 1.71 seconds for the box to accelerate from rest to a velocity of 3.90 m/s for the force of 4.10N is applied to accelerate a 1.80kg box from rest to 3.90m/s.
To find the time it takes for the box to accelerate from rest to 3.90 m/s with a force of 4.10 N, we can use Newton's second law of motion:
F = ma
Where:
F = force (4.10 N)
m = mass of the box (1.80 kg)
a = acceleration
t = time
From the equation, we can rearrange it to solve for acceleration:
a = F / m
Substituting the given values:
a = 4.10 N / 1.80 kg
a ≈ 2.28 m/s²
Now, we can use the kinematic equation to find the time it takes for the box to reach a velocity of 3.90 m/s:
v = u + at
Where:
v = final velocity (3.90 m/s)
u = initial velocity (0 m/s, as the box starts from rest)
a = acceleration (2.28 m/s²)
t = time
Rearranging the equation to solve for time (t):
t = (v - u) / a
Substituting the given values:
t = (3.90 m/s - 0 m/s) / 2.28 m/s²
t ≈ 1.71 s
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The question is -
A force of 4.10N is applied to accelerate a 1.80kg box from rest to 3.90m/s. How long does it take?
Escriba la cantidad que representan los siguientes expresiones, dada en
notación cientifica.
a) 7.1 x 10
6) 2.3 x 103
C) 1.56 10
d) 4. 19. 4. 104
Answer:
Comencemos con la primera:
si tenemos algo como:
7.1*10^n
Simplemente lo que tenemos que hacer es:
si n es positivo, movemos n veces el punto para la derecha, si no tenemos dígitos, completamos con ceros.
si n es negativo, movemos n veces el punto a la izquierda.
a) 7.1*10
aca tenemos n = 1
entonces movemos una vez el punto a la derecha:
7.1*10 = 71. = 71
b) 2.3*10^3
aca n = 3, entonces movemos el punto 3 veces a la derecha:
2.3*10^3 = 23__.
Tenemos dos huecos ahí, los cuales serán completados con ceros, entonces:
2.3*10^3 = 2,300. = 2,300
c) 1.56*10
n = 1, entonces movemos el punto una vez a la derecha:
1.56*10 = 15.6
d) 4.10^4
acá tenemos n = 4
entonces movemos el punto 4 veces a la derecha, recordar que debemos completar con ceros:
4.10^4 = 40,000. = 40,000
Which city is known as the richest square mile on earth?.
Answer:
Central City is the county seat and the most populous municipality of Gilpin County. The city is a historic mining settlement founded in 1859 during the Pike's Peak Gold Rush and came to be known as the "Richest Square Mile on Earth".
The half life of a material is 100 years. If you have 1000g, how much will remain after 500 years?
While examining a piston crown that has vertical cracks through the edges of the piston's combustion chamber bowl, Technician A suggests the piston crown was not getting properly cooled due to low mass airflow in the combustion chamber during the valve overlap period. Technician B suggests the cracks were caused by inadequate cooling by the oil cooler nozzles. Who is correct?
When examining a piston crown that has vertical cracks through the edges of the piston's combustion chamber bowl, Technician A suggests the piston crown was not getting properly cooled due to low mass airflow in the combustion chamber during the valve overlap period. The correct suggestion is Technician A because the piston crown to not get properly cooled and thus causes cracks
While examining a piston crown that has vertical cracks through the edges of the piston's combustion chamber bowl, it was found that the technician A suggested that the piston crown was not getting properly cooled due to low mass airflow in the combustion chamber during the valve overlap period. While technician B suggests the cracks were caused by inadequate cooling by the oil cooler nozzles.
In this situation, technician A is correct. During valve overlap, a low-mass airflow occurs, which leads to an increased temperature of the combustion chamber. This causes the piston crown to not get properly cooled and thus causes cracks. Therefore, technician A's suggestion is correct.
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_____ is the amount of energy given off by a star each second. A. Magnitude B. Luminosity C. Visible light D. Invisible light
Answer:
B. Luminosity
Explanation:
The luminosity of a star is a measure of its brightness.
Have a good day and stay safe!
you are in the middle of a large field. you walk in a straight line for 100 m, then turn left and walk 100 m more in a straight line before stopping. when you stop, you are 100 m from your starting point. by how many degress did you tur
The correct answer is E) This is impossible. You cannot walk 200m and be only 100m away from where you started. To determine the number of degrees you turned, we can use basic geometry.
You started in the middle of a field and walked 100m in a straight line. This forms a right triangle, where one side is the distance you walked (100m) and the other side is the distance from the starting point to the final position (100m).
Since the triangle is a right triangle, we can use the Pythagorean theorem to find the length of the hypotenuse, which represents the distance you are from the starting point.
Using the Pythagorean theorem:
\(c^2 = a^2 + b^2\)
\(c^2 = 100^2 + 100^2\)
\(c^2 = 20000\)
c = √20000
c ≈ 141.42 m
From this, we can see that the distance from the starting point is approximately 141.42m, not 100m. Therefore, the given situation is impossible.
The correct answer is E) This is impossible. You cannot walk 200m and be only 100m away from where you started.
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Full Question ;
You are in the middle of a large field. You walk in a straight line for 100m, then turn left and walk 100m more in start line before stopping. When you stop, you are 100m from the starting point.By how many degrees did you turn?
A) 90
B) 120
C) 30
D) 180
E) This is impossible. You cannot walk 200m and be the only 100m away from where you started.
elbow flexion: angular velocity of 2 radians/s. movement took 0.5 s. what was the change in position in degrees?
The change in position in degrees will be 57.30°
angular velocity = change in angular rotation / change in time
given
angular velocity = 2 rad/s
time = 0.5 seconds
change in position = angular velocity * change in time
= 2 * 0.5 = 1 rad
1 radian = 180 / π = 57.30 °
The change in position in degrees will be 57.30°
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1 1.3.3 Test (CST): Marketing and
Question 19 of 20
What does the Federal Reserve help regulate?
A. Music
B. Clothing
C. Food
D. The economy
The Federal Reserve helps to regulate the economy of the United States. So, the correct option is D.
What is meant by marketing ?Marketing is defined as the activities done for promoting the products through creating offers and communicating to the customers.
Here,
The Federal Reserve of the United state is functioning as a Central Bank, such that they are maintaining the financial aspects of the system.
The Federal Reserve has a great role in regulating the financial system and at the same time, the establishing of the monetary policies.
The primary functions of the Federal Reserve includes the functions of maintaining the banking operations and reliable payments for the system.
Hence,
The Federal Reserve helps to regulate the economy of the United States.
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The density of solid copper is 8960 kg/m3.
The density of molten copper is 7900 kg/m3.
Explain this difference in density by referring to the particle model and the arrangement of
atoms in the two states. (2)
Explanation:
The density of a solid copper is 8960kg/m^3 while the density of a molten copper is 7900kg/m^3 this is due to the difference in the state of matter, the solid copper is in solid state while the molten copper is in form of a liquid. In the solid copper atoms are tightly pack while they atom are not tightly packed.
Blank is a good way to for me to see where I am going while
dribbling
Answer:
???
Explanation:
ACTIVITY 4
Applying the equation learned, answer the following problems:
1. A bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s. What is its momentum? p = m/s. What Is Its Momentum?
Given:
Find:
Formula:
Solution:
2. A skateboard is rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s. What is its mass?
Given:
Find:
Formula:
Solution:
3. A pitcher throws a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s. What is its velocity?
Given:
Find:
Formula:
Solution:
Subject Is Science
Good Perfect Complete=Brainlist
Copy Wrong Incomplete=Report
Good Luck Answer Brainly Users:-)
Answer:
1) 10 kg-m/s
2) 2 kg
3) 20 m/s
Explanation:
The momentum of an object can be calculated using the equation:
\(\large\boxed{p=mv}\)
where:
p is momentum (measured in kilogram meters per second).m is mass (measured in kilograms).v is the velocity (measured in meters per second).\(\hrulefill\)
Question 1For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.
Given values:
m = 4.0 kgv = 2.5 m/sSubstitute the given values into the momentum formula and solve for p:
\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)
\(p=10\;\text{kg m/s}\)
Therefore, the momentum of the bowling ball is 10 kg-m/s.
\(\hrulefill\)
Question 2For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.
Given values:
p = 6.0 kg-m/sv = 3.0 m/sAs we want to find mass, rearrange the momentum formula to isolate m:
\(\large\boxed{m=\dfrac{p}{v}}\)
Substitute the given values into the formula and solve for m:
\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)
\(m=2\;\text{kg}\)
Therefore, the mass of the skateboard is 2 kg.
\(\hrulefill\)
Question 3For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.
Given values:
p = 10 kg-m/sm = 0.5 kgAs we want to find velocity, rearrange the momentum formula to isolate v:
\(\large\boxed{v=\dfrac{p}{m}}\)
Substitute the given values into the formula and solve for v:
\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)
\(v=20\;\text{m/s}\)
Therefore, the velocity of the baseball is 20 m/s.
Given the densities of five objects: 2.00 grams/cm^3, 3.00 grams/cm^3, 4.00 grams/cm^3, 5.00 grams/cm^3, and 6.00 grams/cm^3. How many of these objects would float in water? A)1 B)2 C)3 D)4 E)0
Givne densities are,
\(\begin{gathered} \rho_1=2\text{ g/}cm^3 \\ \rho_2=3\text{ g/}cm^3 \\ \rho_3=4\text{ g/}cm^3 \\ \rho_4=5\text{ g/}cm^3 \end{gathered}\)The density of water is ρ=1 g/cm³.
Any object will float if the denisty of the object is less than the density of water, if the density of object is greater than the dnesity of water, then the object sink in the water.
In the given case, all the objects have density greater than the density of water. Therefore, all the objects will sink in the water.
Thus, option E is corret, no object will flot on the water.